Search Results

Search found 18238 results on 730 pages for 'python gui'.

Page 456/730 | < Previous Page | 452 453 454 455 456 457 458 459 460 461 462 463  | Next Page >

  • Django ModelForm Imagefield Upload

    - by Wei Xu
    I am pretty new to Django and I met a problem in handling image upload using ModelForm. My model is as following: class Project(models.Model): name = models.CharField(max_length=100) description = models.CharField(max_length=2000) startDate = models.DateField(auto_now_add=True) photo = models.ImageField(upload_to="projectimg/", null=True, blank=True) And the modelform is as following: class AddProjectForm(ModelForm): class Meta: model = Project widgets = { 'description': Textarea(attrs={'cols': 80, 'rows': 50}), } fields = ['name', 'description', 'photo'] And the View function is: def addProject(request, template_name): if request.method == 'POST': addprojectform = AddProjectForm(request.POST,request.FILES) print addprojectform if addprojectform.is_valid(): newproject = addprojectform.save(commit=False) print newproject print request.FILES newproject.photo = request.FILES['photo'] newproject.save() print newproject.photo else: addprojectform = AddProjectForm() newProposalNum = projectProposal.objects.filter(solved=False).count() return render(request, template_name, {'addprojectform':addprojectform, 'newProposalNum':newProposalNum}) the template is: <form class="bs-example form-horizontal" method="post" action="">{% csrf_token %} <h2>Project Name</h2><br> {{ addprojectform.name }}<br> <h2>Project Description</h2> {{ addprojectform.description }}<br> <h2>Image Upload</h2><br> {{ addprojectform.photo }}<br> <input type="submit" class="btn btn-success" value="Add Project"> </form> Can anyone help me or could you give an example of image uploading? Thank you!

    Read the article

  • default model field attribute in Django

    - by Rosarch
    I have a Django model: @staticmethod def getdefault(): print "getdefault called" return cPickle.dumps(set()) _applies_to = models.TextField(db_index=True, default=getdefault) For some reason, getdefault() is never called, even as I construct instances of this model and save them to the database. This seems to contradict the Django documentation: Field.default The default value for the field. This can be a value or a callable object. If callable it will be called every time a new object is created. Am I doing something wrong? Update: Originally, I had this, but then I switched to the above version to debug: _applies_to = models.TextField(db_index=True, default=cPickle.dumps(set())) I'm not sure why that wouldn't work.

    Read the article

  • django threadedcomments

    - by Patrick
    Hi folks, I would like to setup a comment systems on my site, using django threadedcomments, and I follow all the steps in the Tutorial, however, I get the following error: No module named newforms.util I am not sure what causing this issue, here is my configuration: #settings.py INSTALLED_APPS = ( 'django.contrib.admin', 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'myproject.myapp', 'threadedcomments', ) #urls.py from django.conf import settings from django.conf.urls.defaults import * from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', (r'^admin/', include(admin.site.urls)), (r'^threadedcomments/', include('threadedcomments.urls')), ) Please let me know if there is another better choice for commenting, as long as the comment system is flexible and able to do lot of customization, as well as threadedcomment, of coz, integrating with Rating, I am happy to use the other one. Thanks guys.

    Read the article

  • UDP security and identifying incoming data.

    - by Charles
    I have been creating an application using UDP for transmitting and receiving information. The problem I am running into is security. Right now I am using the IP/socketid in determining what data belongs to whom. However, I have been reading about how people could simply spoof their IP, then just send data as a specific IP. So this seems to be the wrong way to do it (insecure). So how else am I suppose to identify what data belongs to what users? For instance you have 10 users connected, all have specific data. The server would need to match the user data to this data we received. The only way I can see to do this is to use some sort of client/server key system and encrypt the data. I am curious as to how other applications (or games, since that's what this application is) make sure their data is genuine. Also there is the fact that encryption takes much longer to process than unencrypted. Although I am not sure by how much it will affect performance. Any information would be appreciated. Thanks.

    Read the article

  • Can Django be used for web services?

    - by alex
    My friend said, "Pylons is so much better for web services." My other friend said, "You can modify Django in a way to do exactly whatever you like." In Django, what is necessary to be modified (urls.py? models classes? settings?) in order to do "web services" with APIs and REST and versioning, etc etc.?

    Read the article

  • Doing a count over a filter query efficiently in django

    - by apple_pie
    Hello, Django newbie here, I need to do a count over a certain filter in a django model. If I do it like so: my_model.objects.filter(...).count() I'm guessing it does the SQL query that retrieves all the rows and only afterwards does the count. To my knowledge it's much more efficient to do the count without retrieving those rows like so "SELECT COUNT(*) FROM ...". Is there a way to do so in django?

    Read the article

  • slicing arrays in numpy/scipy

    - by user248237
    I have an array like: a = array([[1,2,3],[3,4,5],[4,5,6]]) what's the most efficient way to slice out a 1x2 array out of this that has only the first two columns of "a"? I.e., array([[2,3],[4,5],[5,6]]) in this case. thanks.

    Read the article

  • Finding out event that called a CGI script

    - by Acorn
    What I want is to be able to make my CGI script do different things depending on what action initiated the calling of the script. For example, if one button is pressed, a database is cleared. If another button is pressed, a form is submitted and that data is added to the database. Should I be doing something like adding the name of the form/button to the end of the POST data submitted in jQuery and then .poping it off in the script? Or is there some other data that's already sent in the POST that I could get from FieldStorage that would give me the information I need to decide what the script should do when it's called? And what if I wasn't using javascript? Would I have to have a hidden field that gets submitted with the name of the form/button? Or is it best to use a different target script for each button on a page?

    Read the article

  • How to include a dynamic page contents into a template ?

    - by Ankit
    Hi All, I have to include a dynamic page content into my template, Say I have a left panel which gets the data dynamically through a view. Now, I have to include this left panel into all my pages but I do not want to duplicate the code for all the pages. Is there any way, I can write a single script and include it in all my templates to display the left panel in all my pages? Thanks in advance.

    Read the article

  • Django: how to create sites dynamically?

    - by Leandro Ardissone
    Hi, I need to create an application for the company where I can create sites dynamically. For example, I need an admin interface (Django's admin is enough) where I can setup a new site and add some settings to it. Each site must hold a domain (domains can be manually added to apache conf, but if Django can handle it too would be awesome). Each site must be independent of the others, I mean, I shouldn't be able to see the data content of other sites but I can share same applications/models. I've seen the Django's Sites framework, but I'm not sure if it's possible to implement that way. Should I use Sites framework or create a new app that can handle sites better? What do you think?

    Read the article

  • programs hangs during socket interaction

    - by herrturtur
    I have two programs, sendfile.py and recvfile.py that are supposed to interact to send a file across the network. They communicate over TCP sockets. The communication is supposed to go something like this: sender =====filename=====> receiver sender <===== 'ok' ======= receiver or sender <===== 'no' ======= receiver if ok: sender ====== file ======> receiver I've got The sender and receiver code is here: Sender: import sys from jmm_sockets import * if len(sys.argv) != 4: print "Usage:", sys.argv[0], "<host> <port> <filename>" sys.exit(1) s = getClientSocket(sys.argv[1], int(sys.argv[2])) try: f = open(sys.argv[3]) except IOError, msg: print "couldn't open file" sys.exit(1) # send filename s.send(sys.argv[3]) # receive 'ok' buffer = None response = str() while 1: buffer = s.recv(1) if buffer == '': break else: response = response + buffer if response == 'ok': print 'receiver acknowledged receipt of filename' # send file s.send(f.read()) elif response == 'no': print "receiver doesn't want the file" # cleanup f.close() s.close() Receiver: from jmm_sockets import * s = getServerSocket(None, 16001) conn, addr = s.accept() buffer = None filename = str() # receive filename while 1: buffer = conn.recv(1) if buffer == '': break else: filename = filename + buffer print "sender wants to send", filename, "is that ok?" user_choice = raw_input("ok/no: ") if user_choice == 'ok': # send ok conn.send('ok') #receive file data = str() while 1: buffer = conn.recv(1) if buffer=='': break else: data = data + buffer print data else: conn.send('no') conn.close() I'm sure I'm missing something here in the sorts of a deadlock, but don't know what it is.

    Read the article

  • Setting custom SQL in django admin

    - by eugene y
    I'm trying to set up a proxy model in django admin. It will represent a subset of the original model. The code from models.py: class MyManager(models.Manager): def get_query_set(self): return super(MyManager, self).get_query_set().filter(some_column='value') class MyModel(OrigModel): objects = MyManager() class Meta: proxy = True Now instead of filter() I need to use a complex SELECT statement with JOINS. What's the proper way to inject it wholly to the custom manager?

    Read the article

  • Django template context not working with imported class

    - by Andy Hume
    I'm using Django's templating on appengine, and am having a problem whereby a class I'm importing from another package is not correctly being made available to the template context. Broadly speaking, this is the code. The prop1 is not available in the template in the first example below, but is in the second. MyClass is identical in both cases. This does not work: from module import MyClass context = MyClass() self.response.out.write(template.render(path, context)) This does: class MyClass(object): def __init__(self): self.prop1 = "prop1" context = MyClass() self.response.out.write(template.render(path, context)) If I log the context in the above code I get: <module.MyClass object at 0x107b1e450> when it's imported, and: <__main__.MyClass object at 0x103759390> when it's defined in the same file. Any clues as to what might cause this kind of behaviour?

    Read the article

  • PHP CURL sending POST to Django app issue

    - by Felipe Pelá
    This code in PHP sends a HTTP POST to a Django app using CURL lib. I need that this code sends POST but redirect to the page in the same submit. Like a simple form does. The PHP Code: $c = curl_init(); curl_setopt($c, CURLOPT_FOLLOWLOCATION, true); curl_setopt($c, CURLOPT_URL, "http://www.xxx.com"); curl_setopt($c, CURLOPT_POST, true); curl_setopt($c, CURLOPT_POSTFIELDS, 'Var='.$var); curl_exec($c); curl_close ($c); In this case, the PHP is sending the HTTP POST, but is not redirecting to the page. He is printing the result. My URL still .php and not a django/url/ I need be redirected to the django URL with the Post like a simple form in HTML does. Any Idea? Thanks.

    Read the article

  • Why will this for loop not return one field from list rather than the list?

    - by Dick Eshelman
    import csv """sample row = 10/6/2010,73.42,74.43,72.9,74.15,2993500""" filename_in = 'c:/python27/scripts/fiverows.csv' reader = csv.reader(open(filename_in, "rb"), dialect="excel", delimiter="\t", quoting =csv.QUOTE_MINIMAL) for row in reader: for item in row: print 'row = ',row print 'item = ', item When you run this script and print the row you get the sample row returned in [] as a list. When you print the item you get the sample row as an unquoted string. Why do I not get each field ie, (10/6/2010), (73.42), etc. returned as an item? How do I return a single item?

    Read the article

< Previous Page | 452 453 454 455 456 457 458 459 460 461 462 463  | Next Page >