Search Results

Search found 30341 results on 1214 pages for 'mysql gui tools'.

Page 460/1214 | < Previous Page | 456 457 458 459 460 461 462 463 464 465 466 467  | Next Page >

  • Need Advice on building the database. all in one table or split?

    - by Ibrahim Azhar Armar
    hello, i am developing an application for a real-estate company. the problem i am facing is about implementing the database. however i am just confused on which way to adopt i would appreciate if you could help me out in reasoning the database implementation. here is my situation. a) i have to store the property details in the database. b) the properties have approximately 4-5 categories to which it will belong for ex : resedential, commnercial, industrial etc. c) now the categories have sub-categories. for example. a residential category will have sub category such as. Apartment / Independent House / Villa / Farm House/ Studio Apartment etc. and hence same way commercial and industrial or agricultural will too have sub-categories. d) each sub-categories will have to store the different values. like a resident will have features like Bedrooms/ kitchens / Hall / bathroom etc. the features depends on the sub categories. for an example on how i would want to implement my application you can have a look at this site. http://www.magicbricks.com/bricks/postProperty.html i could possibly think of the solution like this. a) create four to five tables depending upon the categories which will be existing(the problem is categories might increase in the future). b) create different tables for all the features, location, price, description and merge the common property table into one. for example all the property will have the common entity such as location, total area, etc. what would you advice for me given the current situation. thank you

    Read the article

  • What groupware/collaboration system to choose?

    - by Ivan
    I am looking for a good (stable enough, intuitive enough, and the more technologically modern and advanced - the better) free PHP-based online groupware/collaboration system. 100% UTF-8 is a requirement. OOP-style code is an advantage. And collaborative mindmapping would be a cool feature to have. The team is of ~20 people. Any suggestions?

    Read the article

  • Getting Phing's dbdeploy task to automatically rollback on delta error

    - by Gordon
    I am using Phing's dbdeploy task to manage my database schema. This is working fine, as long as there is no errors in the queries of my delta files. However, if there is an error, dbdeploy will just run the delta files up to the query with the error and then abort. This causes me some frustration, because I have to manually rollback the entry in the changelog table then. If I don't, dbdeploy will assume the migration was successful on a subsequent try. So the question is, is there any way to get dbdeploy use transactions or can you suggest any other way to have phing rollback automatically when an error occurs? Note: I'm not that proficient with Phing, so if this involves writing a custom task, any example code or a url with further information is highly appreciated. Thanks

    Read the article

  • Can't find my.cnf file so I can enable InnoDB - is there another way?

    - by Jared
    Hey all, I am trying to Magento running on a share server, and am having difficulty. When I look at the engines in PHPmyAdmin, I get InnoDB DISABLED. So I look in /etc/, and there is no my.cnf file. There is a ftpquota and a .boxtrapper file, but nothing else. I know I can probably create a new one, but this is a server that hosts a lot of sites. I'm afraid I will mess someone up. So is there a way to maybe create a my.cnf file that only enable InnoDB and doesn't effect anything else? Or is there another way to enable it?

    Read the article

  • Failing to install activerecord-jdbcmysql-adapter gem

    - by Phil Sturgeon
    I am trying to follow the basic "Create a blog in 20 minutes" Rails screencast but have hit a stumbling block already. When I try to rake db:migrate I get errors about the gem activerecord-jdbcmysql-adapter not being installed. When I try to install it, I am told it doesn't exist. If I try to simply gem install mysql I get all sorts of madness appearing. I am running this on Mac OS X 10.6.2 and my installation was all done through gem. My basic setup works (Hello world!). Here is the error log: $ rake db:migrate (in /Users/xxxx/Sites/blog) rake aborted! Please install the jdbcmysql adapter: gem install activerecord-jdbcmysql-adapter (no such file to load -- active_record/connection_adapters/jdbcmysql_adapter) (See full trace by running task with --trace) $ sudo gem install activerecord-jdbcmysql-adapter ERROR: could not find gem activerecord-jdbcmysql-adapter locally or in a repository $ sudo gem install mysql Password: Building native extensions. This could take a while... ERROR: Error installing mysql: ERROR: Failed to build gem native extension. /opt/local/bin/ruby extconf.rb checking for mysql_query() in -lmysqlclient... no checking for main() in -lm... yes checking for mysql_query() in -lmysqlclient... no checking for main() in -lz... yes checking for mysql_query() in -lmysqlclient... no checking for main() in -lsocket... no checking for mysql_query() in -lmysqlclient... no checking for main() in -lnsl... no checking for mysql_query() in -lmysqlclient... no checking for main() in -lmygcc... no checking for mysql_query() in -lmysqlclient... no * extconf.rb failed * Could not create Makefile due to some reason, probably lack of necessary libraries and/or headers. Check the mkmf.log file for more details. You may need configuration options. Provided configuration options: --with-opt-dir --without-opt-dir --with-opt-include --without-opt-include=${opt-dir}/include --with-opt-lib --without-opt-lib=${opt-dir}/lib --with-make-prog --without-make-prog --srcdir=. --curdir --ruby=/opt/local/bin/ruby --with-mysql-config --without-mysql-config --with-mysql-dir --without-mysql-dir --with-mysql-include --without-mysql-include=${mysql-dir}/include --with-mysql-lib --without-mysql-lib=${mysql-dir}/lib --with-mysqlclientlib --without-mysqlclientlib --with-mlib --without-mlib --with-mysqlclientlib --without-mysqlclientlib --with-zlib --without-zlib --with-mysqlclientlib --without-mysqlclientlib --with-socketlib --without-socketlib --with-mysqlclientlib --without-mysqlclientlib --with-nsllib --without-nsllib --with-mysqlclientlib --without-mysqlclientlib --with-mygcclib --without-mygcclib --with-mysqlclientlib --without-mysqlclientlib Gem files will remain installed in /opt/local/lib/ruby/gems/1.8/gems/mysql-2.8.1 for inspection. Results logged to /opt/local/lib/ruby/gems/1.8/gems/mysql-2.8.1/ext/mysql_api/gem_make.out

    Read the article

  • Update multiple rows with known keys without inserting new rows if nonexistent keys are found

    - by Kirzilla
    Hello, Let's imagine that we have table items... table: items item_id INT PRIMARY AUTO_INCREMENT title VARCHAR(255) views INT Let's imagine that it is filled with something like (1, item-1, 10), (2, item-2, 10), (3, item-3, 15) I want to make multi update view for this items from data taken from this array [item_id] = [views] '1' => '50', '2' => '60', '3' => '70', '5' => '10' IMPORTANT! Please note that we have item_id=5 in array, but we don't have item_id=5 in database. I can use INSERT ... ON DUPLICATE KEY UPDATE, but this way image_id=5 will be inserted into talbe items. How to avoid inserting new key? I just want item_id=5 be skipped because it is not in table. Of course, before execution I can select existing keys from items table; then compare with keys in array; delete nonexistent keys and perform INSERT ... ON DUPLICATE KEY UPDATE. But maybe there is some more elegant solutions? Thank you.

    Read the article

  • Are there code reviews in opensource projects? If so, what tools are used to do this?

    - by monksy
    I know there is a big push for code reviews in commercial development. However, are code reviews used in open source software or is based on trust? If so, then how are they performed? [Is it a delayed commit, "a pre commit environment", is there a tool that allows for the patch to be sent to another dev]? Are there any projects that use code reviews? From my understanding the linux kernel is mostly based around trust of the commitor. MySQL was based on the main author's approval and the performance impact.

    Read the article

  • Join 2 children tables with a parent tables without duplicated

    - by user1847866
    Problem I have 3 tables: People, Phones and Emails. Each person has an UNIQUE ID, and each person can have multiple numbers or multiple emails. Simplified it looks like this: +---------+----------+ | ID | Name | +---------+----------+ | 5000003 | Amy | | 5000004 | George | | 5000005 | John | | 5000008 | Steven | | 8000009 | Ashley | +---------+----------+ +---------+-----------------+ | ID | Number | +---------+-----------------+ | 5000005 | 5551234 | | 5000005 | 5154324 | | 5000008 | 2487312 | | 8000009 | 7134584 | | 5000008 | 8451384 | +---------+-----------------+ +---------+------------------------------+ | ID | Email | +---------+------------------------------+ | 5000005 | [email protected] | | 5000005 | [email protected] | | 5000008 | [email protected] | | 5000008 | [email protected] | | 5000008 | [email protected] | | 8000009 | [email protected] | | 5000004 | [email protected] | +---------+------------------------------+ I am trying to joining them together without duplicates. It works great, when I try to join only Emails with People or only Phones with People. SELECT People.Name, People.ID, Phones.Number FROM People LEFT OUTER JOIN Phones ON People.ID=Phones.ID ORDER BY Name, ID, Number; +----------+---------+-----------------+ | Name | ID | Number | +----------+---------+-----------------+ | Steven | 5000008 | 8451384 | | Steven | 5000008 | 24887312 | | John | 5000005 | 5551234 | | John | 5000005 | 5154324 | | George | 5000004 | NULL | | Ashley | 8000009 | 7134584 | | Amy | 5000003 | NULL | +----------+---------+-----------------+ SELECT People.Name, People.ID, Emails.Email FROM People LEFT OUTER JOIN Emails ON People.ID=Emails.ID ORDER BY Name, ID, Email; +----------+---------+------------------------------+ | Name | ID | Email | +----------+---------+------------------------------+ | Steven | 5000008 | [email protected] | | Steven | 5000008 | [email protected] | | Steven | 5000008 | [email protected] | | John | 5000005 | [email protected] | | John | 5000005 | [email protected] | | George | 5000004 | [email protected] | | Ashley | 8000009 | [email protected] | | Amy | 5000003 | NULL | +----------+---------+------------------------------+ However, when I try to join Emails and Phones on People - I get this: SELECT People.Name, People.ID, Phones.Number, Emails.Email FROM People LEFT OUTER JOIN Phones ON People.ID = Phones.ID LEFT OUTER JOIN Emails ON People.ID = Emails.ID ORDER BY Name, ID, Number, Email; +----------+---------+-----------------+------------------------------+ | Name | ID | Number | Email | +----------+---------+-----------------+------------------------------+ | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | John | 5000005 | 5551234 | [email protected] | | John | 5000005 | 5551234 | [email protected] | | John | 5000005 | 5154324 | [email protected] | | John | 5000005 | 5154324 | [email protected] | | George | 5000004 | NULL | [email protected] | | Ashley | 8000009 | 7134584 | [email protected] | | Amy | 5000003 | NULL | NULL | +----------+---------+-----------------+------------------------------+ What happens is - if a Person has 2 numbers, all his emails are shown twice (They can not be sorted! which means they can not be removed by @last) What I want: Bottom line, playing with the @last, I want to end up with somethig like this, but @last won't work if I don't arrange ORDER columns in the righ way - and this seems like a big problem..Orderin the email column. Because seen from the example above: Steven has 2 phone number and 3 emails. The JOIN Emails with Numbers happens with each email - thus duplicated values that can not be sorted (SORT BY does not work on them). **THIS IS WHAT I WANT** +----------+---------+-----------------+------------------------------+ | Name | ID | Number | Email | +----------+---------+-----------------+------------------------------+ | Steven | 5000008 | 8451384 | [email protected] | | | | 24887312 | [email protected] | | | | | [email protected] | | John | 5000005 | 5551234 | [email protected] | | | | 5154324 | [email protected] | | George | 5000004 | NULL | [email protected] | | Ashley | 8000009 | 7134584 | [email protected] | | Amy | 5000003 | NULL | NULL | +----------+---------+-----------------+------------------------------+ Now I'm told that it's best to keep emails and number in separated tables because one can have many emails. So if it's such a common thing to do, what isn't there a simple solution? I'd be happy with a PHP Solution aswell. What I know how to do by now that satisfies it, but is not as pretty. If I do it with GROUP_CONTACT I geat a satisfactory result, but it doesn't look as pretty: I can't put a "Email type = work" next to it. SELECT People.Ime, GROUP_CONCAT(DISTINCT Phones.Number), GROUP_CONCAT(DISTINCT Emails.Email) FROM People LEFT OUTER JOIN Phones ON People.ID=Phones.ID LEFT OUTER JOIN Emails ON People.ID=Emails.ID GROUP BY Name; +----------+----------------------------------------------+---------------------------------------------------------------------+ | Name | GROUP_CONCAT(DISTINCT Phones.Number) | GROUP_CONCAT(DISTINCT Emails.Email) | +----------+----------------------------------------------+---------------------------------------------------------------------+ | Steven | 8451384,24887312 | [email protected],[email protected],[email protected] | | John | 5551234,5154324 | [email protected],[email protected] | | George | NULL | [email protected] | | Ashley | 7134584 | [email protected] | | Amy | NULL | NULL | +----------+----------------------------------------------+---------------------------------------------------------------------+

    Read the article

  • python simpleftpserver module ftp

    - by iamrohitbanga
    i need a simple implementation of ftp that i can setup quickly for some experiments. is there an equivalent of python -m SimpleHTTPServer for ftp. Google sarch didn't help. i just need a simple implentation of ftp that is easy to setup. (so i don't have to go through the installation trouble for a lot of PC's).

    Read the article

  • Database design for very large amount of data

    - by Hossein
    Hi, I am working on a project, involving large amount of data from the delicious website.The data available is at files are "Date,UserId,Url,Tags" (for each bookmark). I normalized my database to a 3NF, and because of the nature of the queries that we wanted to use In combination I came down to 6 tables....The design looks fine, however, now a large amount of data is in the database, most of the queries needs to "join" at least 2 tables together to get the answer, sometimes 3 or 4. At first, we didn't have any performance issues, because for testing matters we haven't had added too much data in the database. No that we have a lot of data, simply joining extremely large tables does take a lot of time and for our project which has to be real-time is a disaster.I was wondering how big companies solve these issues.Looks like normalizing tables just adds complexity, but how does the big company handle large amounts of data in their databases, don't they do the normalization? thanks

    Read the article

  • Comparing fields of one table to other fields of another table

    - by chupinette
    Hello! I have a function called add_item which actually inserts values in a field item_name of temporary table called temp having fields temp_id and item_name. I have another table calleed item which consists of fields item_id, item_name, price. I have another table called quotation which consists of fields q_id, item_id,item_name,price. Now I cant figure out how do i compare the item_name from temp to the field item_name from item. And then, insert the values of item in quoatation table. Can anyone guide me please?

    Read the article

  • &ldquo;Napa&rdquo; Development Tools for SharePoint 2013 and Office 2013

    - by Sahil Malik
    SharePoint 2010 Training: more information One of the biggest issues in getting started with SharePoint development are the 2091097 steps you need to go through, and the heavy duty machine you need to invest in, to create a development environment for a SharePoint and Office developer. This is not unlike the fact that creating and running a production SharePoint farm can be extremely time-consuming. In my latest code-magazine article, I describe how you can use the “Napa” Development Tools for SharePoint 2013 and Office 2013. These are also described in my latest book, “SharePoint 2013 - Planet of the Apps”, which is now available on Lulu.com Read full article ....

    Read the article

  • UTF-8 character encoding battles json_encode()

    - by Dave Jarvis
    Quest I am looking to fetch rows that have accented characters. The encoding for the column (NAME) is latin1_swedish_ci. The Code The following query returns Abord â Plouffe using phpMyAdmin: SELECT C.NAME FROM CITY C WHERE C.REGION_ID=10 AND C.NAME_LOWERCASE LIKE '%abor%' ORDER BY C.NAME LIMIT 30 The following displays expected values (function is called db_fetch_all( $result )): while( $row = mysql_fetch_assoc( $result ) ) { foreach( $row as $value ) { echo $value . " "; $value = utf8_encode( $value ); echo $value . " "; } $r[] = $row; } The displayed values: 5482 5482 Abord â Plouffe Abord â Plouffe The array is then encoded using json_encode: $rows = db_fetch_all( $result ); echo json_encode( $rows ); Problem The web browser receives the following value: {"ID":"5482","NAME":null} Instead of: {"ID":"5482","NAME":"Abord â Plouffe"} (Or the encoded equivalent.) Question The documentation states that json_encode() works on UTF-8. I can see the values being encoded from LATIN1 to UTF-8. After the call to json_encode(), however, the value becomes null. How do I make json_encode() encode the UTF-8 values properly? One possible solution is to use the Zend Framework, but I'd rather not if it can be avoided.

    Read the article

  • Python MySQLdb placeholders syntax

    - by ensnare
    I'd like to use placeholders as seen in this example: cursor.execute (""" UPDATE animal SET name = %s WHERE name = %s """, ("snake", "turtle")) Except I'd like to have the query be its own variable as I need to insert a query into multiple databases, as in: query = """UPDATE animal SET name = %s WHERE name = %s """, ("snake", "turtle")) cursor.execute(query) cursor2.execute(query) cursor3.execute(query) What would be the proper syntax for doing something like this?

    Read the article

  • PHP throws 'Allowed memory exhausted' errors while migrating data in Drupal.

    - by Stan
    I'm trying to setup a tiny sandbox on a local machine to play around with Drupal. I created a few CCK types; in order to create a few nodes I wrote the following script: chdir('C:\..\drupal'); require_once '.\includes\bootstrap.inc'; drupal_bootstrap(DRUPAL_BOOTSTRAP_FULL); module_load_include('inc', 'node', 'node.pages'); $node = array('type' => 'my_type'); $link = mysql_connect(..); mysql_select_db('my_db'); $query_bldg = ' SELECT stuff FROM table LIMIT 10 '; $result = mysql_query($query_bldg); while ($row = mysql_fetch_object($result)) { $form_state = array(); $form_state['values']['name'] = 'admin'; $form_state['values']['status'] = 1; $form_state['values']['op'] = t('Save'); $form_state['values']['title'] = $row->val_a; $form_state['values']['my_field'][0]['value'] = $row->val_b; ## About another dozen or so of similar assignments... drupal_execute('node_form', $form_state, (object)$node); } Here are a few relevant lines from php_errors.log: [12-Jun-2010 05:02:47] PHP Notice: Undefined index: REMOTE_ADDR in C:\..\drupal\includes\bootstrap.inc on line 1299 [12-Jun-2010 05:02:47] PHP Notice: Undefined index: REMOTE_ADDR in C:\..\drupal\includes\bootstrap.inc on line 1299 [12-Jun-2010 05:02:47] PHP Warning: session_start(): Cannot send session cookie - headers already sent by (output started at C:\..\drupal\includes\bootstrap.inc:1299) in C:\..\drupal\includes\bootstrap.inc on line 1143 [12-Jun-2010 05:02:47] PHP Warning: session_start(): Cannot send session cache limiter - headers already sent (output started at C:\..\drupal\includes\bootstrap.inc:1299) in C:\..\drupal\includes\bootstrap.inc on line 1143 [12-Jun-2010 05:02:47] PHP Warning: Cannot modify header information - headers already sent by (output started at C:\..\drupal\includes\bootstrap.inc:1299) in C:\..\drupal\includes\bootstrap.inc on line 709 [12-Jun-2010 05:02:47] PHP Warning: Cannot modify header information - headers already sent by (output started at C:\..\drupal\includes\bootstrap.inc:1299) in C:\..\drupal\includes\bootstrap.inc on line 710 [12-Jun-2010 05:02:47] PHP Warning: Cannot modify header information - headers already sent by (output started at C:\..\drupal\includes\bootstrap.inc:1299) in C:\..\drupal\includes\bootstrap.inc on line 711 [12-Jun-2010 05:02:47] PHP Warning: Cannot modify header information - headers already sent by (output started at C:\..\drupal\includes\bootstrap.inc:1299) in C:\..\drupal\includes\bootstrap.inc on line 712 [12-Jun-2010 05:02:47] PHP Notice: Undefined index: REMOTE_ADDR in C:\..\drupal\includes\bootstrap.inc on line 1299 [12-Jun-2010 05:02:48] PHP Fatal error: Allowed memory size of 239075328 bytes exhau sted (tried to allocate 261904 bytes) in C:\..\drupal\includes\form.inc on line 488 [12-Jun-2010 05:03:22] PHP Fatal error: Allowed memory size of 239075328 bytes exhausted (tried to allocate 261904 bytes) in C:\..\drupal\includes\form.inc on line 488 [12-Jun-2010 05:04:34] PHP Fatal error: Allowed memory size of 262144 bytes exhausted (tried to allocate 261904 bytes) in Unknown on line 0 At this point any action php takes results in the last error shown above. I tried increasing the value of memory_limit in php.ini before the final Fatal error which obviously didn't help. How can the error be eliminated? Am I on a correct path to migrating data into Drupal or should the cck tables be operated on directly? Windows XP PHP 5.3.2 VC6 Apache 2.2

    Read the article

  • A rails migration that specifies the distance between two months..?

    - by Trip
    I would like to make two drop downs. a start time, and an end time. Specifically, I only need months. I would like to, for example, choose January, and then March, and then have the database read that it is the these two months plus February. Is there any out of the box migration that could work? I'm guessing.. script/generate migration AddMonthsToClass beginDate:datetime #through endDate:datetime I apologize ahead of time if my question sounds retarded! Sorry! :D

    Read the article

  • Drupal db_query error need help

    - by Gobi
    Hi drupal pals, im using drupal 6.15 and doing my first project in drupal . i got an issue while running the below query with db_query i have drupal,delhi keywords in column 'tag' with table name tagging. db_query(SELECT * FROM {tagging} WHERE tag LIKE '%drup%') wont retrieve the correct output. it show null but the query modified like this, db_query(SELECT * FROM {tagging} WHERE tag LIKE 'drup%') retrieve "drupal" as output finally i used the php core mysql_query mysql_query(SELECT * FROM tagging WHERE tag LIKE '%drup%') it retrieve the exact n correct output "drupal" . is any one have solution , Thanxs, Gobi

    Read the article

  • What is wrong with this WHERE clause?

    - by Victor
    Is there a reason why this query doesn't work? The following query will work if I just exclude the WHERE clause. I need to know what is wrong with it. I know the given values of $key exists in the table, so why doesn't this work? $q = "SELECT * WHERE t1.project=$key FROM project_technologies AS t1 JOIN languages AS t2 ON t1.language = t2.key"; Table's have the following fields: project_technologies - key - project - language languages - key - name

    Read the article

  • Relational database queestion with php.

    - by Oliver Bayes-Shelton
    Hi, Not really a coding question more a little help with my idea of a Relational database. If I have 3 tables in a SQL database. In my php script I basically query the companies which are in industry "a" and then insert a row into a seperate table with their details such as companyId , companyName etc is that a type of Relational database ? I have explained it in a simple way so we don't get confused what I am trying to say.

    Read the article

  • A little bit of Ajax goes a long way

    - by Holland
    ..except when you're having problems. My problem is this: I have a hierarchical list of categories stored in a database which I wish to output in a dropdown list. The hierarchy comes into place when the subcategories are to be displayed, which are dependent on a parent id (which equals out to the first seven or so main categories listed). My thoughts are relatively simple: when the user clicks the dynamically allocated list of main categories, they are clicking on an option tag. For each option tag, an id (i.e., the parent) is listed in the value attribute, as well as an argument which is sent to a Javascript function which then uses AJAX to get the data via PHP and sends it to my 'javascript.php' file. The file then does magic, and populates the subcategory list, which is dependent on the main category selected. I believe I have the idea down, it's just that I'm implementing the solution improperly, for some reason. Here's what I have so far: from javascript.php <script type="text/javascript" src=<?=JPATH_BASE.DS.'includes'.DS.'jquery.js';?>> var ajax = { ajax.sendAjaxData = function(method, url, dataTitle, ajaxData) { $.ajax({ type: 'post', url: "C:/wamp/www/patention/components/com_adsmanagar/views/edit/tmpl/javascript.php", data: { 'data' : ajaxData }, success: function(result){ // we have the response alert("Your request was successful." + result); }, error: function(e){ alert('Error: ' + e); } }); } ajax.printSubCategoriesOnClick = function(parent) { alert("hello world!"); ajax.sendAjaxData('post', 'javascript.php', 'data' parent); <?php $categories = $this->formData->getCategories($_POST['data']); ?> ajax.printSubCategories(<?=$categories;?>); } ajax.printSubCategories = function(categories) { var select = document.getElementById("subcategories"); for (var i = 0; i < categories.length; i++) { var opt = document.createElement("option"); opt.text = categories['name']; opt.value = categories['id']; } } } </script> the function used to populate the form data function populateCategories($parent, FormData $formData) { $categories = $formData->getCategories($parent); echo "<pre>"; print_r($categories); echo "</pre>"; foreach($categories as $section => $row){ ?> <option value=<?=$row['id'];?> onclick="ajax.printSubCategoriesOnClick(<?=$row['id']?>)"> <? echo $row['name']; ?> </option> <?php } } The problem is that when I try to do a print_r on my $_POST variable, nothing shows up. I also receive an "undefined index" error (which refers to the key I set for the data type). I'm thinking that for some reason, the data is being sent to my form.php file, or my default.php file which includes both the form.php and javascript.php files via a function. Is there something specific that I'm missing here? Just looking up basic AJAX syntax (via jQuery) hasn't helped out, unfortunately.

    Read the article

  • Can preventing directory listings in WordPress upload folders cause Google ranking drops when they cause 403 errors in Webmaster Tools?

    - by Kelly
    I recently moved to a new host that blocks crawling to my uploads folders but (hopefully) allows the files in the folder to be crawled. I now show many 403 errors for each folder in the uploads folder in my Webmaster Tools. For example, http://www.rewardcharts4kids.com/wp-content/uploads/2013/07/ shows a 403 error. For example, I can access this file: http://www.rewardcharts4kids.com/wp-content/uploads/2013/07/lunch-box-notes.jpg but I cannot access the folder it is in. My rankings went down after I moved to this host and I am wondering if: this could be the reason. is this how files/folders are supposed to be set up?

    Read the article

  • Database design in blogging systems

    - by Peter
    As a learning exercise I'm trying to put myself a blogging system. The goal is to code something that will let me create multiple blogs, like blogger.com or wordpress.com, but much simplified. I would like to ask you, what do you think is best database design for this type of script. Is it better to have one big table, containing posts from all blogs of all users (like friendfeed) or would it be better to create separate table for each blog's posts? Big thanks in advance for your help, Peter.

    Read the article

< Previous Page | 456 457 458 459 460 461 462 463 464 465 466 467  | Next Page >