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  • find elements of a varchar in another varchar

    - by Luca Romagnoli
    hi, i have a varchar field with the content like these: a,b,c,d e,d,a,c b,q,d,e i need to do a query that select only the rows with the field that has elements equals with an input string. ex input: c,a rows selected: a,b,c,d e,d,a,c is possible without use the OR (field like '%a%' OR field like '%c%') ? thanks

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  • PHP/SQL/Wordpress: Group a user list by alphabet

    - by rayne
    I want to create a (fairly big) Wordpress user index with the users categorized alphabetically, like this: A Amy Adam B Bernard Bianca and so on. I've created a custom Wordpress query which works fine for this, except for one problem: It also displays "empty" letters, letters where there aren't any users whose name begins with that letter. I'd be glad if you could help me fix this code so that it only displays the letter if there's actually a user with a name of that letter :) I've tried my luck by checking how many results there are for that letter, but somehow that's not working. (FYI, I use the user photo plugin and only want to show users in the list who have an approved picture, hence the stuff in the SQL query). <?php $alphabet = range('A', 'Z'); foreach ($alphabet as $letter) { $user_count = $wpdb->get_results("SELECT COUNT(*) FROM wp_users WHERE display_name LIKE '".$letter."%' ORDER BY display_name ASC"); if ($user_count > 0) { $user_row = $wpdb->get_results("SELECT wp_users.user_login, wp_users.display_name FROM wp_users, wp_usermeta WHERE wp_users.display_name LIKE '".$letter."%' AND wp_usermeta.meta_key = 'userphoto_approvalstatus' AND wp_usermeta.meta_value = '2' AND wp_usermeta.user_id = wp_users.ID ORDER BY wp_users.display_name ASC"); echo '<li class="letter">'.$letter.''; echo '<ul>'; foreach ($user_row as $user) { echo '<li><a href="/author/'.$user->user_login.'">'.$user->display_name.'</a></li>'; } echo '</ul></li>'; } } ?> Thanks in advance!

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  • cakephp and SQL_CALC_FOUND_ROWS

    - by Lizard
    I am trying to add the SQL_CALC_FOUND_ROWS into a query (Please note this isn't for pagination) please note I am trying to add this to a cakePHP query the code I currently have is below: return $this->find('all', array( 'conditions' => $conditions, 'fields'=>array('SQL_CALC_FOUND_ROWS','Category.*','COUNT(`Entity`.`id`) as `entity_count`'), 'joins' => array('LEFT JOIN `entities` AS Entity ON `Entity`.`category_id` = `Category`.`id`'), 'group' => '`Category`.`id`', 'order' => $sort, 'limit'=>$params['limit'], 'offset'=>$params['start'], 'contain' => array('Domain' => array('fields' => array('title'))) )); Note the 'fields'=>array('SQL_CALC_FOUND_ROWS',' this obviously doesn't work as It tries to apply the SQL_CALC_FOUND_ROWS to the table e.g. SELECTCategory.SQL_CALC_FOUND_ROWS, Is there anyway of doing this? Any help would be greatly appreciated, thanks.

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  • relational database: how to design this table

    - by donpal
    I'm a database newbie designing a database. I'll use SO to ask my question because it's easier to ask it on something that you can see already, but it's not the same, it will just help me understand the right approach. As you can see, there are many questions here and each can have many answers. How should I store the answers in a table? Should I store all the answers in the SAME table with a unique id (make it the key) and just a new field for the question id? What if there are 100,000 answers like there is here? Do I still store them in 1 table? What keys should I use to minimize search time when I want to search for the answers of a specific question? The database is both read and write if that makes any difference in this case.

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  • Pentaho - Reporting Tool - Is the .prpt file (report template file) contains datasource information

    - by Yatendra Goel
    I am new Pentaho Reporting Tool. I have the following question: When I created a report using Pentaho Report Designer, it output a report file having .prpt extension. After that I found an example on internet where the following code were used to display the report in html format:| protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { ResourceManager manager = new ResourceManager(); manager.registerDefaults(); String reportPath = "file:" + this.getServletContext().getRealPath("sampleReport.prpt"); try { Resource res = manager.createDirectly(new URL(reportPath), MasterReport.class); MasterReport report = (MasterReport) res.getResource(); HtmlReportUtil.createStreamHTML(report, response.getOutputStream()); } catch (Exception e) { e.printStackTrace(); } } And the report got printed successfully. So as we haven't specified any datasource information here, I think that the .prpt file contains that information in it. If that's true than Isn't Jasper is better Reporting tool than Pentaho because when we display Jasper reports, we have to provide datasource details also so in that way our report is flexible and is not bound to any particular database.

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  • .Net framework 2.0 Configuration Tool

    - by Cédric Boivin
    I recently installed windows 7, visual studio 2008, and .net framework 3.5. With these installed, I was unable to find the .net framework configuration tool. It should be located in %windir%\Microsoft.net\framework\v2.0.507727\ with the file name mscorcfg.msc The only place I found something similar is in %windir%\Microsoft.net\framework\v1.0.3705 where there are files named mscormmc.cfg and mscormmc.dll Any idea where to get the configuration tool?

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  • Best practices to store CreditCard information into DataBase

    - by Garis Suero
    In my country the online payments are not an old thing, the first time i saw a web application taking payments directly to a local bank account was last year. So, Im a newbie coding web payment system. My question is, what are the best practices to store creditcard information into the database... I have many ideas: encrypting the creditcard, database security restriction, etc. What have you done?

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  • Rows dropping when I try to join data from two tables

    - by blcArmadillo
    I have a fairly simple query I'm try to write. If I run the following query: SELECT parts.id, parts.type_id FROM parts WHERE parts.type_id=1 OR parts.type_id=2 OR parts.type_id=4 ORDER BY parts.type_id; I get all the rows I expect to be returned. Now when I try to grab the parent_unit from another table with the following query six rows suddenly drop out of the result: SELECT parts.id, parts.type_id, sp.parent_unit FROM parts, serialized_parts sp WHERE (parts.type_id=1 OR parts.type_id=2 OR parts.type_id=4) AND sp.parts_id = parts.id ORDER BY parts.type_id In the past I've never really dealt with ORs in my queries so maybe I'm just doing it wrong. That said I'm guessing it's just a simple mistake. Let me know if you need sample data and I'll post some. Thanks.

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  • recursive function to get all the child categories

    - by user253530
    Here is what I'm trying to do: - i need a function that when passed as an argument an ID (for a category of things) will provide all the subcategories and the sub-sub categories and sub-sub-sub..etc. - i was thinking to use a recursive function since i don't know the number of subcategories their sub-subcategories and so on so here is what i've tried to do so far function categoryChild($id) { $s = "SELECT * FROM PLD_CATEGORY WHERE PARENT_ID = $id"; $r = mysql_query($s); if(mysql_num_rows($r) > 0) { while($row = mysql_fetch_array($r)) echo $row['ID'].",".categoryChild($row['ID']); } else { $row = mysql_fetch_array($r); return $row['ID']; } } If i use return instead of echo, i won't get the same result. I need some help in order to fix this or rewrite it from scratch

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  • SQL: Gather right hand values from a join

    - by Max Williams
    Let's say a question has many tags, via a join table called taggings. I do a join thus: SELECT DISTINCT `questions`.id FROM `questions` LEFT OUTER JOIN `taggings` ON `taggings`.taggable_id = `questions`.id LEFT OUTER JOIN `tags` ON `tags`.id = `taggings`.tag_id I want to order the results according to a particular tag name, eg 'piano', so that piano is at the top, then by all the other tags in alphabetical order. Currently i'm using this order clause: ORDER BY (tags.name = 'piano') desc, tags.name Which is going completely wrong - the first results i get back aren't even tagged with 'piano' at all. I think my problem is that i need to group the tag names somehow and do my ordering test against that: i think that doing it against the straight tags.name isn't working due to the structure of the resultant join table (it does work if i just do a simple select on the tags table) but i can't get my head around how to fix it. grateful for any advice, max

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  • Architectural advice on connecting multiple diverse sites into a single community.

    - by Aleksandar
    Hi SO, I've been given a task to connect multiple sites of the same client into a single network. So i would like to hear an architectural advice on connecting these sites into a single community. These sites include: 1. Invision Power Board Forum (the most important site) 2. 3 custom made cms-s (changes to code allowable) 3. 1 drupal site 4. 3-4 wordpress blogs Requirements are as follows: 1. Connecting all users of all sites into a single administrable entity. With permissions changing ability, users banning etc. 2. Later on, based on this implementation I have to implement "facebook like" chat, which will be available to all users regardless of place of login. I have few ideas on my mind on how to go with this, but would like to hear some people with more experience and expertize than my self. Cheers!

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  • php smart learner

    - by rajesh1984
    Is there a possibility to create a html or a php page that will count redirects? I mean, let's say you have a page with a link in it. I want the page to count how many times the link is clicked per ip adress or username. The counting would be reported into a log file or text document.

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  • How to evaluate query by DBMS?

    - by Kevinniceguy
    Sorry...I mean what question will be for this query? SELECT SUM(price) FROM Room r, Hotel h WHERE r.hotelNo = h.hotelNo and hotelName = 'Paris Hilton' and roomNo NOT IN (SELECT roomNo FROM Booking b, Hotel h WHERE (dateFrom <= CURRENT_DATE AND dateTo >= CURRENT_DATE) AND b.hotelNo = h.hotelNo AND hotelName = 'Paris Hilton');

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  • How to get an hierarchical php structure from a db table, in php array, or JSON

    - by daniel
    Hi guys, can you please help me. How to get an hierarchical php structure from a db table, in php array, or JSON, but with the following format: [{ "attributes" : {"id" : "111"}, "data" : "Some node title", "children" : [ { "attributes" : { "id" : "555"}, "data" : "A sub node title here" } ], "state" : "open" }, { "attributes" : {"id" : "222"}, "data" : "Other main node", "children" : [ { "attributes" : { "id" : "666"}, "data" : "Another sub node" } ], "state" : "open" }] My SQL table contains the fields: ID, PARENT, ORDER, TITLE Can you please help me with this? I'm going crazy trying to get this. Many thanks in advance. Daniel

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  • jQuery Datatables throws error when dynamically created row headers

    - by JM4
    I am using the Datatables jquery plugin for one of my projects. For one in particular, the number of columns can vary based on how many children a consumer has (yes I realize normalization and proper technique would insert on another row but it is a client requirement). Datatables must be set up as such: <table> <thead> <tr> <th></th> </tr> </thead> <tbody> <tr> <td></td> </tr> </tbody> </table> my script starts out as: <table cellpadding="0" cellspacing="0" border="0" class="display" id="sortable"> <thead> <tr> <th>parent name</th> <th>parent phone</th> <?php try { $db->beginTransaction(); $stmt = $db->prepare("SELECT max(num_deps) FROM (SELECT count(a.id) as num_deps FROM children a INNER JOIN parents b USING(id) WHERE a.id !=0 GROUP BY a.id) x"); $stmt->execute(); $rows = $stmt->fetchAll(); for($i=1; $i<=$rows[0][0]; $i++) { echo " <th>Child Name ".$i."</th> <th>Date of Birth ".$i."</th> "; } $db->commit(); } catch (PDOException $e) { echo "<p align='center'>There was a system error. Please contact administration.<br>".$e->getMessage()."</p><br />"; } ?> </tr> </thead> In this manner, the final column headers can be 1 or 50 spots long. However, with this dynamic code in place, datatables throws the following error: ""DataTables warning (table id = 'datatable'): Cannot reinitialise DataTable. To retrieve the DataTables object for this table, please pass either no arguments to the dataTable() function, or set bRetrive to true. Alternativly, to destroy old table and create a new one...ETC."' Yes I have set "bRetrieve" : true in the javascript above and that does not do the trick. If I remove the code above, the file "works" fine but it leaves off the necessary columns for my table. Any ideas? Displaying JS <script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jqueryui/1.8.6/jquery-ui.min.js"></script> <script type="text/javascript" src="../media/js/jquery.dataTables.min.js"></script> <script type="text/javascript" src="../media/js/TableTools/TableTools.js"></script> <script type="text/javascript" src="../media/ZeroClipboard/ZeroClipboard.js"></script> <script type="text/javascript"> $(document).ready(function() { TableToolsInit.sSwfPath = "../media/swf/ZeroClipboard.swf"; oTable = $('#sortable').dataTable({ "bRetrieve": true, "bProcessing": true, "sScrollX": "100%", "sScrollXInner": "110%", "bScrollCollapse": true, "bJQueryUI": true, "sPaginationType": "full_numbers", "sDom": 'T<"clear"><"fg-toolbar ui-widget-header ui-corner-tl ui-corner-tr ui-helper-clearfix"lfr>t<"fg-toolbar ui-widget-header ui-corner-bl ui-corner-br ui-helper-clearfix"ip>' }); }); </script> </head> TOP piece of HTML <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Home</title> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <link rel="stylesheet" type="text/css" href="style.css" /> <link rel="stylesheet" type="text/css" href="default.css" /> <script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jquery/1.4.3/jquery.min.js"></script> <style type="text/css" title="currentStyle"> @import "TableTools.css"; @import "demo_table_jui.css"; @import "jquery-ui-1.8.4.custom.css"; </style> <script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jqueryui/1.8.6/jquery-ui.min.js"></script> <script type="text/javascript" src="js/jquery.dataTables.min.js"></script> <script type="text/javascript" src="js/TableTools/TableTools.js"></script> <script type="text/javascript" src="ZeroClipboard/ZeroClipboard.js"></script> <script type="text/javascript"> $(document).ready(function() { TableToolsInit.sSwfPath = "ZeroClipboard.swf"; oTable = $('#sortable').dataTable({ "bRetrieve": true, "bProcessing": true, "sScrollX": "100%", "sScrollXInner": "110%", "bScrollCollapse": true, "bJQueryUI": true, "sPaginationType": "full_numbers", "sDom": 'T<"clear"><"fg-toolbar ui-widget-header ui-corner-tl ui-corner-tr ui-helper-clearfix"lfr>t<"fg-toolbar ui-widget-header ui-corner-bl ui-corner-br ui-helper-clearfix"ip>' }); }); </script> </head> <body bgcolor="#e0e0e0"> <div class="main"> <div class="body"> <div class="body_resize"> <div class="liquid-round"> <div class="top"><span><h2>Details</h2></span></div> <div class="center-content"> <div style="overflow-x:hidden; min-height:400px; max-height:600px; overflow-y:auto;"> <div class="demo_jui"><br /> <table cellpadding="0" cellspacing="0" border="0" class="display" width="100%" id="sortable"> <thead> <tr> <th>First Name</th> <th>MI</th> <th>Last Name</th> <th>Street Address</th> <th>City</th> <th>State</th> <th>Zip</th> <th>DOB</th> <th>Gender</th> <th>Spouse Name</th> <th>Spouse Date of Birth</th> <!-- this part is generated with the php, when removed, datatables works just fine with the rest of the page --> <th>Dependent Child Name 1</th> <th>Dependent Date of Birth 1</th> <th>Dependent Child Name 2</th> <th>Dependent Date of Birth 2</th> <th>Dependent Child Name 3</th> <th>Dependent Date of Birth 3</th> <th>Dependent Child Name 4</th> <th>Dependent Date of Birth 4</th> <th>Dependent Child Name 5</th> <th>Dependent Date of Birth 5</th> <th>Dependent Child Name 6</th> <th>Dependent Date of Birth 6</th> <th>Dependent Child Name 7</th> <th>Dependent Date of Birth 7</th> </tr> </thead> <tbody> <tr> ... UPDATE REGARDING COMMENTS/ANSWERS I have received a number of responses indicating the number of headers may not match the field count in the body. As I mention below, eliminating the php script below altogether would eliminate 5+ fields in the header and without question throw the count match off balance. This DOES NOT however cause an error and in fact "resolves" the issue in that datatables functions properly (even though there is NO header record for 5+ fields in the body.

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  • Trouble setting IE8 browser mode to IE7

    - by deostroll
    Inspite of putting the following meta tag I am not getting the expected result: <meta http-equiv="X-UA-Compatible" content="IE=EmulateIE7" > I open the developer tool window. In the same bar where the menu appears there is an item called Browser Mode: it still shows IE 8 by default. Even doing document.documentMode in the console window shows "8". Am I doing anything wrong?

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  • Invalid parameter number: number of bound variables does not match number of tokens

    - by Alex
    I have a table: 'objects' with few columns: object_id:int, object_type:int, object_status:int, object_lati:float, object_long:float My query is : $stmt = $db->query('SELECT o.object_id, o.object_type, o.object_status, o.object_lati, o.object_long FROM objects o WHERE o.object_id = 1'); $res = $stmt->fetch(); Pdo throw error: SQLSTATE[HY093]: Invalid parameter number: number of bound variables does not match number of tokens When i remove column object_lati or object_long query is work fine.

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  • SQL: Need to SUM on results that meet a HAVING statement

    - by Wasauce
    I have a table where we record per user values like money_spent, money_spent_on_candy and the date. So the columns in this table (let's call it MoneyTable) would be: UserId Money_Spent Money_Spent_On_Candy Date My goal is to SUM the total amount of money_spent -- but only for those users where they have spent more than 10% of their total money spent for the date range on candy. What would that query be? I know how to select the Users that have this -- and then I can output the data and sum that by hand but I would like to do this in one single query. Here would be the query to pull the sum of Spend per user for only the users that have spent 10% of their money on candy. SELECT UserId, SUM(Money_Spent), SUM(Money_Spent_On_Candy) / SUM(Money_Spent) AS PercentCandySpend FROM MoneyTable WHERE DATE >= '2010-01-01' HAVING PercentCandySpend > 0.1;

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  • SQL Replace Into question

    - by Matt
    With Replace Into, if I have two fields. FirstName LastName. The table has John Smith in it, if I was to run REPLACE INTO tblNames (FirstName, LastName) VALUES (John, Jones) Would that replace Smith with Jones, or create a new name? What determines if its an Update or and Insert?

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  • Query Not Working

    - by John
    Hello, The simple query below is not working. Any idea why? When I echo the three variables, the correct values are returned, so I know I have variables. Thanks in advance, John $comment = $_POST['comment']; $uid = $_POST['uid']; $subid = $_POST['submissionid']; echo $comment; echo $uid; echo $subid; mysql_connect("mysqlv12", "username", "password") or die(mysql_error()); mysql_select_db("database") or die(mysql_error()); $query = sprintf("INSERT INTO comment VALUES (NULL, '%s', '%s', '%s', NULL, NULL)", $uid, $subid, $comment); mysql_query($query);

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  • Peer review maatkits mk-parallel-dump and mk-parallel-restore usage?

    - by Brent
    Hiya Im trying to make use of maatkit as a means of dumping a database and then restoring to another database. For dumps: mk-parallel-dump --user abc --password xyz --databases $db --base-dir /tmp/dump For restore: mk-parallel-restore --create-databases --user abc --password xyz --database devdb /tmp/dump My question is, is my logic and understanding correct, and would it be ok to do it like this. Kind Regards Brent

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