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  • How to properly test Hibernate length restriction?

    - by Cesar
    I have a POJO mapped with Hibernate for persistence. In my mapping I specify the following: <class name="ExpertiseArea"> <id name="id" type="string"> <generator class="assigned" /> </id> <version name="version" column="VERSION" unsaved-value="null" /> <property name="name" type="string" unique="true" not-null="true" length="100" /> ... </class> And I want to test that if I set a name longer than 100 characters, the change won't be persisted. I have a DAO where I save the entity with the following code: public T makePersistent(T entity){ transaction = getSession().beginTransaction(); transaction.begin(); try{ getSession().saveOrUpdate(entity); transaction.commit(); }catch(HibernateException e){ logger.debug(e.getMessage()); transaction.rollback(); } return entity; } Actually the code above is from a GenericDAO which all my DAOs inherit from. Then I created the following test: public void testNameLengthMustBe100orLess(){ ExpertiseArea ea = new ExpertiseArea( "1234567890" + "1234567890" + "1234567890" + "1234567890" + "1234567890" + "1234567890" + "1234567890" + "1234567890" + "1234567890" + "1234567890"); assertTrue("Name should be 100 characters long", ea.getName().length() == 100); ead.makePersistent(ea); List<ExpertiseArea> result = ead.findAll(); assertEquals("Size must be 1", result.size(),1); ea.setName(ea.getName()+"1234567890"); ead.makePersistent(ea); ExpertiseArea retrieved = ead.findById(ea.getId(), false); assertTrue("Both objects should be equal", retrieved.equals(ea)); assertTrue("Name should be 100 characters long", (retrieved.getName().length() == 100)); } The object is persisted ok. Then I set a name longer than 100 characters and try to save the changes, which fails: 14:12:14,608 INFO StringType:162 - could not bind value '12345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890' to parameter: 2; data exception: string data, right truncation 14:12:14,611 WARN JDBCExceptionReporter:100 - SQL Error: -3401, SQLState: 22001 14:12:14,611 ERROR JDBCExceptionReporter:101 - data exception: string data, right truncation 14:12:14,614 ERROR AbstractFlushingEventListener:324 - Could not synchronize database state with session org.hibernate.exception.DataException: could not update: [com.exp.model.ExpertiseArea#33BA7E09-3A79-4C9D-888B-4263314076AF] //Stack trace 14:12:14,615 DEBUG GenericDAO:87 - could not update: [com.exp.model.ExpertiseArea#33BA7E09-3A79-4C9D-888B-4263314076AF] 14:12:14,616 DEBUG JDBCTransaction:186 - rollback 14:12:14,616 DEBUG JDBCTransaction:197 - rolled back JDBC Connection That's expected behavior. However when I retrieve the persisted object to check if its name is still 100 characters long, the test fails. The way I see it, the retrieved object should have a name that is 100 characters long, given that the attempted update failed. The last assertion fails because the name is 110 characters long now, as if the ea instance was indeed updated. What am I doing wrong here?

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  • No exception, no error, still i dont recieve the json object from my http post

    - by user2978538
    My source code: final Thread t = new Thread() { public void run() { Looper.prepare(); HttpClient client = new DefaultHttpClient(); HttpConnectionParams.setConnectionTimeout(client.getParams(), 10000); HttpResponse response; JSONObject obj = new JSONObject(); try { HttpPost post = new HttpPost("http://pc.dyndns-office.com/mobile.asp"); obj.put("Model", ReadIn1); obj.put("Product", ReadIn2); obj.put("Manufacturer", ReadIn3); obj.put("RELEASE", ReadIn4); obj.put("SERIAL", ReadIn5); obj.put("ID", ReadIn6); obj.put("ANDROID_ID", ReadIn7); obj.put("Language", ReadIn8); obj.put("BOARD", ReadIn9); obj.put("BOOTLOADER", ReadIn10); obj.put("BRAND", ReadIn11); obj.put("CPU_API", ReadIn12); obj.put("DISPLAY", ReadIn13); obj.put("FINGERPRINT", ReadIn14); obj.put("HARDWARE", ReadIn15); obj.put("UUID", ReadIn16); StringEntity se = new StringEntity(obj.toString()); se.setContentType(new BasicHeader(HTTP.CONTENT_TYPE, "application/json")); post.setEntity(se); post.setHeader("host", "http://pc.dyndns-office.com/mobile.asp"); response = client.execute(post); if (response != null) { InputStream in = response.getEntity().getContent(); } } catch (Exception e) { e.printStackTrace(); } Looper.loop(); } }; t.start(); } } i want to send an Json object to a Website. As far as I can see, I set the header, but still I get this exception, can someone help me? (I'm using Android-Studio) __ Edit: i don't get any exceptions anymore, but still i do not receive the json packet. When i manually call the website i get a log file entry. Does anyone know, what's wrong? Edit2: When i debug i get as response "HTTP/1.1 400 bad request" i'm sure its not an permission problem. Any ideas?

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  • SQLite3 table not accepting INSERT INTO statements. The table is created, and so is the database, but nothing is passed into it

    - by user1460029
    <?php try { //open the database $db = new PDO('sqlite:music.db'); $db->exec("DELETE from Music;"); $db->exec("INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('Whatd I Say', 'Ray Charles', '1956');" . "INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('Smells Like Teen Spirit.', 'Nirvana', '1991');" . "INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('Hey Jude', 'The Beatles', '1968');" . "INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('Johnny B. Goode', 'Chuck Berry', '1958');" . "INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('Good Vibrations', 'The Beach Boys', '1966');" . "INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('Respect', 'Aretha Franklin', '1967');" . "INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('Whats Going On', 'Marvin Gaye', '1971');" . "INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('Imagine', 'John Lennon', '1971');" . "INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('(I Cant Get No) Satisfaction', 'Rolling Stones', '1965');" . "INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('Like A Rolling Stone', 'Bob Dylan', '1965');"); //now output the data to a simple html table... //example of specifier --> WHERE First=\'Josh\'; <-- print "<table border=1>"; print "<tr><td>Title</td><td>Author</td><td>Y.O.P.</td></tr>"; $result = $db->query('SELECT * FROM Music '); foreach($result as $row) { print "<td>".$row['Title']."</td>"; print "<td>".$row['Author']."</td>"; print "<td>".$row['ReleaseDate']."</td></tr>"; } print "</table>"; $db = NULL; } catch(PDOException $e) { print 'Exception : '.$e->getMessage(); } ?> I am not sure why nothing is being inserted into the table. The file 'music.db' exists in the right path. For the record, I can only use SQlite3, no SQL allowed. PHP is allowed, so is SQLite3.

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  • cuda/thrust: Trying to sort_by_key 2.8GB of data in 6GB of gpu RAM throws bad_alloc

    - by Sven K
    I have just started using thrust and one of the biggest issues I have so far is that there seems to be no documentation as to how much memory operations require. So I am not sure why the code below is throwing bad_alloc when trying to sort (before the sorting I still have 50% of GPU memory available, and I have 70GB of RAM available on the CPU)--can anyone shed some light on this? #include <thrust/device_vector.h> #include <thrust/sort.h> #include <thrust/random.h> void initialize_data(thrust::device_vector<uint64_t>& data) { thrust::fill(data.begin(), data.end(), 10); } #define BUFFERS 3 int main(void) { size_t N = 120 * 1024 * 1024; char line[256]; try { std::cout << "device_vector" << std::endl; typedef thrust::device_vector<uint64_t> vec64_t; // Each buffer is 900MB vec64_t c[3] = {vec64_t(N), vec64_t(N), vec64_t(N)}; initialize_data(c[0]); initialize_data(c[1]); initialize_data(c[2]); std::cout << "initialize_data finished... Press enter"; std::cin.getline(line, 0); // nvidia-smi reports 48% memory usage at this point (2959MB of // 6143MB) std::cout << "sort_by_key col 0" << std::endl; // throws bad_alloc thrust::sort_by_key(c[0].begin(), c[0].end(), thrust::make_zip_iterator(thrust::make_tuple(c[1].begin(), c[2].begin()))); std::cout << "sort_by_key col 1" << std::endl; thrust::sort_by_key(c[1].begin(), c[1].end(), thrust::make_zip_iterator(thrust::make_tuple(c[0].begin(), c[2].begin()))); } catch(thrust::system_error &e) { std::cerr << "Error: " << e.what() << std::endl; exit(-1); } return 0; }

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  • Rails Google Maps integration Javascript problem

    - by JZ
    I'm working on Rails 3.0.0.beta2, following Advanced Rails Recipes "Recipe #32, Mark locations on a Google Map" and I hit a road block: I do not see a google map. My @adds view uses @adds.to_json to connect the google maps api with my model. My database contains "latitude" "longitude", as floating points. And the entire project can be accessed at github. Can you see where I'm not connecting the to_json output with the javascript correctly? Can you see other glairing errors in my javascript? Thanks in advance! My application.js file: function initialize() { if (GBrowserIsCompatible() && typeof adds != 'undefined') { var map = new GMap2(document.getElementById("map")); map.setCenter(new GLatLng(37.4419, -122.1419), 13); map.addControl(new GLargeMapControl()); function createMarker(latlng, add) { var marker = new GMarker(latlng); var html="<strong>"+add.first_name+"</strong><br />"+add.address; GEvent.addListener(marker,"click", function() { map.openInfoWindowHtml(latlng, html); }); return marker; } var bounds = new GLatLngBounds; for (var i = 0; i < adds.length; i++) { var latlng=new GLatLng(adds[i].latitude,adds[i].longitude) bounds.extend(latlng); map.addOverlay(createMarker(latlng, adds[i])); } map.setCenter(bounds.getCenter(),map.getBoundsZoomLevel(bounds)); } } window.onload=initialize; window.onunload=GUnload; Layouts/adds.html.erb: <script src="http://maps.google.com/maps?file=api&amp;v=2&amp;sensor=true_or_false&amp;key=ABQIAAAAeH4ThRuftWNHlwYdvcK1QBTJQa0g3IQ9GZqIMmInSLzwtGDKaBQvZChl_y5OHf0juslJRNx7TbxK3Q" type="text/javascript"></script> <% if @adds -%> <script type="text/javascript"> var maps = <%= @adds.to_json %>; </script> <% end -%>

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  • How can I make these images download on a seperate thread?

    - by Andy Barlow
    Hello!! I have the following code running on my Android device. It works great and displays my list items wonderfully. It's also clever in the fact it only downloads the data when it's needed by the ArrayAdapter. However, whilst the download of the thumbnail is occurring, the entire list stalls and you cannot scroll until it's finished downloading. Is there any way of threading this so it'll still scroll happily, maybe show a place holder for the downloading image, finish the download, and then show? Any help with this would be really apreciated. Thank-you kindly. Andy Barlow private class CatalogAdapter extends ArrayAdapter { private ArrayList<SingleQueueResult> items; //Must research what this actually does! public CatalogAdapter(Context context, int textViewResourceId, ArrayList<SingleQueueResult> items) { super(context, textViewResourceId, items); this.items = items; } /** This overrides the getview of the ArrayAdapter. It should send back our new custom rows for the list */ @Override public View getView(int position, View convertView, ViewGroup parent) { View v = convertView; if (v == null) { LayoutInflater vi = (LayoutInflater)getSystemService(Context.LAYOUT_INFLATER_SERVICE); v = vi.inflate(R.layout.mylists_rows, null); } final SingleQueueResult result = items.get(position); // Sets the text inside the rows as they are scrolled by! if (result != null) { TextView title = (TextView)v.findViewById(R.id.mylist_title); TextView format = (TextView)v.findViewById(R.id.mylist_format); title.setText(result.getTitle()); format.setText(result.getThumbnail()); // Download Images ImageView myImageView = (ImageView)v.findViewById(R.id.mylist_thumbnail); downloadImage(result.getThumbnail(), myImageView); } return v; } } // This should run in a seperate thread public void downloadImage(String imageUrl, ImageView myImageView) { try { url = new URL(imageUrl); URLConnection conn = url.openConnection(); conn.connect(); InputStream is = conn.getInputStream(); BufferedInputStream bis = new BufferedInputStream(is); Bitmap bm = BitmapFactory.decodeStream(bis); bis.close(); is.close(); myImageView.setImageBitmap(bm); } catch (IOException e) { /* Reset to Default image on any error. */ //this.myImageView.setImageDrawable(getResources().getDrawable(R.drawable.default)); } }

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  • HttpSession problem in Google App Engine/J

    - by Tahir Akram
    I am writting a Twitter web app by using Twitter4J on GAE/J. I am saving Twitter and Request Token objects in session so that to be used after call back. I have two servlets. IndexServlet sets session and HomeServlet get from session (hits on call back by twitter oAuth). If I comment out session handling lines in both servlets then call backs works fine. Please suggest any workaround. I am sharing my code here. IndexServlet.java Twitter twitter = new Twitter(); twitter.setOAuthConsumer("<masked>", "<masked>"); RequestToken requestToken = null; try { requestToken = twitter.getOAuthRequestToken(); log.info("OAuth token has been taken"); } catch (TwitterException e) { log.warning(e.toString()); } HttpSession session = request.getSession(); if (session.getAttribute("twitter")==null){ session.setAttribute("twitter", twitter); out.println("-----------------------------> session is set"); } if (session.getAttribute("token")==null){ session.setAttribute("token", requestToken); out.println("-----------------------------> session is set"); } String authUrl = requestToken.getAuthorizationURL(); HomeServlet.java HttpSession session = request.getSession(); twitter = (Twitter)session.getAttribute("twitter"); r = (RequestToken)session.getAttribute("token"); twitter.setOAuthAccessToken(r.getAccessToken()); twitter.updateStatus("Hello World!"); Exception javax.servlet.ServletException: java.lang.ArrayStoreException: [Ljava.lang.String; at com.google.apphosting.runtime.jetty.AppVersionHandlerMap.handle(AppVersionHandlerMap.java:239) at org.mortbay.jetty.handler.HandlerWrapper.handle(HandlerWrapper.java:139) at org.mortbay.jetty.Server.handle(Server.java:313) at org.mortbay.jetty.HttpConnection.handleRequest(HttpConnection.java:506) at org.mortbay.jetty.HttpConnection$RequestHandler.headerComplete(HttpConnection.java:830) at com.google.apphosting.runtime.jetty.RpcRequestParser.parseAvailable(RpcRequestParser.java:76) at org.mortbay.jetty.HttpConnection.handle(HttpConnection.java:381) at com.google.apphosting.runtime.jetty.JettyServletEngineAdapter.serviceRequest(JettyServletEngineAdapter.java:139) at com.google.apphosting.runtime.JavaRuntime.handleRequest(JavaRuntime.java:235) at com.google.apphosting.base.RuntimePb$EvaluationRuntime$6.handleBlockingRequest(RuntimePb.java:4950) at com.google.apphosting.base.RuntimePb$EvaluationRuntime$6.handleBlockingRequest(RuntimePb.java:4948) at com.google.net.rpc.impl.BlockingApplicationHandler.handleRequest(BlockingApplicationHandler.java:24) at com.google.net.rpc.impl.RpcUtil.runRpcInApplication(RpcUtil.java:359) at com.google.net.rpc.impl.Server$2.run(Server.java:823) at com.google.tracing.LocalTraceSpanRunnable.run(LocalTraceSpanRunnable.java:56)

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  • Getting my string value from my form into my class( not another form)

    - by jovany
    Hello all, I have a question regarding the some data which is being transfered from one form to my class. It's not going quite the way i'd like to , so I figured maybe there is someone who could help me. This is my code in my class Public Class DrawableTextBox Inherits Drawable Dim i_testString As Integer Private s_InsertLabel As String Private drawFont As Font Public Sub New(ByVal fore_color As Color, ByVal fill_color As Color, Optional ByVal line_width As Integer = 0, Optional ByVal new_x1 As Integer = 0, Optional ByVal new_y1 As Integer = 0, Optional ByVal new_x2 As Integer = 1, Optional ByVal new_y2 As Integer = 1) MyBase.New(fore_color, fill_color, line_width) X1 = new_x1 Y1 = new_y1 X2 = new_x2 Y2 = new_y2 Trace.WriteLine(s_InsertLabel) End Sub Friend WriteOnly Property _textBox() As String Set(ByVal Value As String) s_InsertLabel = Value Trace.WriteLine(s_InsertLabel) End Set End Property ' Draw the object on this Graphics surface. Public Overrides Sub Draw(ByVal gr As System.Drawing.Graphics) ' Make a Rectangle representing this rectangle. Dim rect As Rectangle = GetBounds() ' Fill the rectangle as usual. Dim fill_brush As New SolidBrush(FillColor) gr.FillRectangle(fill_brush, rect) fill_brush.Dispose() ' See if we're selected. If IsSelected Then ' Draw the rectangle highlighted. Dim highlight_pen As New Pen(Color.Yellow, LineWidth) gr.DrawRectangle(highlight_pen, rect) highlight_pen.Dispose() ' Draw grab handles. Trace.WriteLine("drawing the lines for my textbox") DrawGrabHandle(gr, X1, Y1) DrawGrabHandle(gr, X1, Y2) DrawGrabHandle(gr, X2, Y2) DrawGrabHandle(gr, X2, Y1) Else 'TextBox() Dim fg_pen As New Pen(Color.Red, LineWidth) 'Dim fontSize As Single = 0.1 + ((Y2 - Y1) / 2) Dim fontSize As Single = 20 Try Dim drawFont As New Font("Arial", fontSize, FontStyle.Bold) Trace.WriteLine(s_InsertLabel) gr.DrawString(s_InsertLabel, drawFont, Brushes.Brown, X1, Y1) Catch ex As ArgumentException End Try gr.DrawRectangle(Pens.Azure, rect) ' gr.DrawRectangle(fg_pen, rect) fg_pen.Dispose() End If End Sub Public Function GetValueString(ByVal ValueType As String) Return ValueType End Function ' Return the object's bounding rectangle. Public Overrides Function GetBounds() As System.Drawing.Rectangle Return New Rectangle( _ Min(X1, X2), _ Min(Y1, Y2), _ Abs(100), _ Abs(30)) Trace.WriteLine("don't forget to make variables in GetBounds DrawableTextbox") End Function ' Return True if this point is on the object. Public Overrides Function IsAt(ByVal x As Integer, ByVal y As Integer) As Boolean Return (x >= Min(X1, X2)) AndAlso _ (x <= Max(X1, X2)) AndAlso _ (y >= Min(Y1, Y2)) AndAlso _ (y <= Max(Y1, Y2)) End Function ' Move the second point. Public Overrides Sub NewPoint(ByVal x As Integer, ByVal y As Integer) X2 = x Y2 = y End Sub ' Return True if the object is empty (e.g. a zero-length line). Public Overrides Function IsEmpty() As Boolean Return (X1 = X2) AndAlso (Y1 = Y2) End Function End Class I've got a form with a textbox( form1) in which the text is being inserted and passed through a buttonclick (al via properties). As you can see I've placed several traces and in the property of the class my trace works fine , however if I look in my Draw function it is already gone. And I get a blank trace. Does anyone know what's happening here. thanks in advance. (forgive me I'm new )

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  • Is Java assert broken?

    - by BlairHippo
    While poking around the questions, I recently discovered the assert keyword in Java. At first, I was excited. Something useful I didn't already know! A more efficient way for me to check the validity of input parameters! Yay learning! But then I took a closer look, and my enthusiasm was not so much "tempered" as "snuffed-out completely" by one simple fact: you can turn assertions off.* This sounds like a nightmare. If I'm asserting that I don't want the code to keep going if the input listOfStuff is null, why on earth would I want that assertion ignored? It sounds like if I'm debugging a piece of production code and suspect that listOfStuff may have been erroneously passed a null but don't see any logfile evidence of that assertion being triggered, I can't trust that listOfStuff actually got sent a valid value; I also have to account for the possibility that assertions may have been turned off entirely. And this assumes that I'm the one debugging the code. Somebody unfamiliar with assertions might see that and assume (quite reasonably) that if the assertion message doesn't appear in the log, listOfStuff couldn't be the problem. If your first encounter with assert was in the wild, would it even occur to you that it could be turned-off entirely? It's not like there's a command-line option that lets you disable try/catch blocks, after all. All of which brings me to my question (and this is a question, not an excuse for a rant! I promise!): What am I missing? Is there some nuance that renders Java's implementation of assert far more useful than I'm giving it credit for? Is the ability to enable/disable it from the command line actually incredibly valuable in some contexts? Am I misconceptualizing it somehow when I envision using it in production code in lieu of statements like if (listOfStuff == null) barf();? I just feel like there's something important here that I'm not getting. *Okay, technically speaking, they're actually off by default; you have to go out of your way to turn them on. But still, you can knock them out entirely.

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  • HttpClient response handler always returns closed stream

    - by Alex Ciminian
    I'm new to Java development so please bear with me. Also, I hope I'm not the champion of tl;dr :). I'm using HttpClient to make requests over Http (duh!) and I'd gotten it to work for a simple servlet that receives an URL as a query string parameter. I realized that my code could use some refactoring, so I decided to make my own HttpResponseHandler, to clean up the code, make it reusable and improve exception handling. I currently have something like this: public class HttpResponseHandler implements ResponseHandler<InputStream>{ public InputStream handleResponse(HttpResponse response) throws ClientProtocolException, IOException { int statusCode = response.getStatusLine().getStatusCode(); InputStream in = null; if (statusCode != HttpStatus.SC_OK) { throw new HttpResponseException(statusCode, null); } else { HttpEntity entity = response.getEntity(); if (entity != null) { in = entity.getContent(); // This works // for (int i;(i = in.read()) >= 0;) System.out.print((char)i); } } return in; } } And in the method where I make the actual request: HttpClient httpclient = new DefaultHttpClient(); HttpGet httpget = new HttpGet(target); ResponseHandler<InputStream> httpResponseHandler = new HttpResponseHandler(); try { InputStream in = httpclient.execute(httpget, httpResponseHandler); // This doesn't work // for (int i;(i = in.read()) >= 0;) System.out.print((char)i); return in; } catch (HttpResponseException e) { throw new HttpResponseException(e.getStatusCode(), null); } The problem is that the input stream returned from the handler is closed. I don't have any idea why, but I've checked it with the prints in my code (and no, I haven't used them both at the same time :). While the first print works, the other one gives a closed stream error. I need InputStreams, because all my other methods expect an InputStream and not a String. Also, I want to be able to retrieve images (or maybe other types of files), not just text files. I can work around this pretty easily by giving up on the response handler (I have a working implementation that doesn't use it), but I'm pretty curious about the following: Why does it do what it does? How do I open the stream, if something closes it? What's the right way to do this, anyway :)? I've checked the docs and I couldn't find anything useful regarding this issue. To save you a bit of Googling, here's the Javadoc and here's the HttpClient tutorial (Section 1.1.8 - Response handlers). Thanks, Alex

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  • How to call Ajax to run a PHP file while maintaining PHP & Javascript variables.

    - by Umar
    Hi Stackoverflowers. I'm using the Facebook php-sdk to get the users name and friends, right now the loading friends part takes about +3 seconds so I wanted to do it via Ajax, e.g. so the document can load and jQuery then calls an external PHP script which loads the friends (their names and their profile pictures). So to do this I did: $(document).ready(function() { var loadUrl = "http://localhost/fb/getFriends.php" ; $("#friends") .html("Hold on, your friends are loading!") .load(loadUrl); }); But I get a PHP error: Fatal error: Call to a member function api() on a non-object If I do this in the same PHP file (so I don't use Ajax at all to call it) it works fine. Now I think I understand the reason this is happening, but I don't know how to fix it. In my main index.php file I have a bunch of init and session code e.g. FB.init({ appId : '<?php echo $facebook->getAppId(); ?>', session : <?php echo json_encode($session); ?>, // don't refetch the session when PHP already has it status : true, // check login status cookie : true, // enable cookies to allow the server to access the session xfbml : true // parse XFBML }); So I'm just wondering what is the best way to treat my new separate PHP file getFriends.php in a way where it has access to all PHP/JavaScript session data/variables? If you haven't used the Facebook php-sdk I'll quickly explain what I mean: Lets say I have index.php and getUsername.php, from index.php I want to retrieve the getUsername.php file via Ajax using .load. Now the problem is getUsername.php needs to access PHP session data/Javascript Init functions which were created in index.php, so I'm thinking of ways to solve this (I'm new to PHP so sorry if this sounds silly) but I'm thinking maybe I could do a POST in jQuery Ajax and post the session data? Or maybe I could create a PHP class, so something like: class getUsername extends index{} /*Yes I'm a newbie*/ If you have a look at the php-sdk example.php link posted at the top maybe you'd better understand what variables exactly need to be accessed from a new file. Also on a different note, I'm using PHP to work out page rendering times and it seems that fetching the users name alone : // Session based API call. if ($session) { try { $uid = $facebook->getUser(); $me = $facebook->api('/me'); } catch (FacebookApiException $e) { error_log($e); } } Can take a good 4 seconds, is this normal? Once I get the users details is it good to cache it or something? -Speed isn't as important right now, for now I'm just trying to figure out this Ajax-separating php files thing. Woah this is a long post. Thanks very much for your time.

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  • <li> titles and descriptions align across top

    - by AMC
    Not quite sure how to go about describing what it is I'm trying to achieve, so I have some screenshots.. Basically, I'd like the <h2>s all have their top edges align, as well as the <p>'s. What I currently have: What I would like to have: index.html <div id="services"> <p><span>Services</span></p> <ul> <li><h2>Identity and Logo Design</h2><p>Nulla et diam risus. Praesent vestibulum augue non purus tincidunt placerat. Sed in orci leo. Duis dignissim nibh vitae lacus placerat et posuere</p></li> <li><h2>Branding</h2><p>Nulla et diam risus. Praesent vestibulum augue non purus tincidunt placerat. Sed in orci leo. Duis dignissim nibh vitae lacus placerat et posuere</p></li> <li><h2>Web Design and Development</h2><p>Nulla et diam risus. Praesent vestibulum augue non purus tincidunt placerat. Sed in orci leo. Duis dignissim nibh vitae lacus placerat et posuere</p></li> <li><h2>Social Media</h2><p>Nulla et diam risus. Praesent vestibulum augue non purus tincidunt placerat. Sed in orci leo. Duis dignissim nibh vitae lacus placerat et posuere</p></li> </ul> <div class="next"> <a href="#"><img src="img/next.png" alt="Click for more information" /></a> </div><!-- end next --> </div><!-- end services --> style.css #services { border-top: 1px solid #202020; padding-bottom: 60px; padding-top: 40px; } #services p span { font-family: nevis-webfont; font-size: 112.5%; font-weight: normal; letter-spacing: 1px; text-transform: uppercase; } #services ul li { display: inline-block; padding-left: 100px; width: 160px; } #services ul li:first-child { padding-left: 0px; } #services ul li h2 { padding-top: 20px; text-align: center; } #services .next { float: right }

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  • Not able to delete list which dynamically created with jquery.

    - by shin
    I have two html here. The first one is dynamically generated by php and second one is just html to test. I also have the following jquery. When I click a cross with class delete in the second ones(plain html), it works nicely. However when I click a cross in the first ones, it does not work. It redirect me to the home page with # at the end. I am hoping someone point out what I am doing wrong. Thank in advance. HTML First part (dyanmicall generated) <ul style="display: block;" id="message"> <li class="41"> <span class="user"><strong>shin</strong></span> <span class="msg"> delete this as well</span> <span class="date">2010-01-15 07:47:31</span> <a href="#" id="41" class="delete">x</a> <div class="clear"></div></li> <li class="40"> <span class="user"><strong>shin</strong></span> <span class="msg"> delete me as well</span> <span class="date">2010-01-14 16:01:44</span> <a href="#" id="40" class="delete">x</a> <div class="clear"></div></li> ... ...</ul> Second part which is plain html <ul id="another"> <li><a href="#">you can't delete me</a></li> <li><a href="#" class="delete">delete this</a></li> <li><a href="#" class="delete">delete this</a></li> </ul> Here is jquery $(".delete").click(function(event) { event.preventDefault(); loading.fadeIn(); var commentContainer = $(this).parent(); var id = $(this).attr("id"); // var string = 'id='+ id ; $.ajax({ type: "POST", url: "index.php/admin/messages/changestatus/"+id, // data: string, cache: false, success: function(){ commentContainer.slideUp('slow', function() {$(this).remove();}); loading.fadeOut(); } }); return false; }); I am using CodeIgniter by the way.

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  • retrieving information from web service calls

    - by Monte Chan
    Hi all, I am trying to retrieve information from a web service call. The following is what I have so far. In my text view, it is showing Map {item=anyType{key=TestKey; value=2;}; item=anyType{key=TestField; value=adsfasd; };} When I ran that in the debugger, I can see the information above in the variable, tempvar. But the question is, how do I retrieve the information (i.e. the actual values of "key" and "value" in each of the array positions)? Yes, I know there is a lot going on in onCreate and I will fix it later. Thanks in advance, Monte My codes are as follows, import java.util.Vector; import android.app.Activity; import android.os.Bundle; import android.widget.TextView; import org.ksoap2.SoapEnvelope; import org.ksoap2.serialization.SoapObject; import org.ksoap2.serialization.SoapSerializationEnvelope; import org.ksoap2.transport.AndroidHttpTransport; public class ViewHitUpActivity extends Activity { private static final String SOAP_ACTION = "test_function"; private static final String METHOD_NAME = "test_function"; private static final String NAMESPACE = "http://www.monteandjanicechan.com/"; private static final String URL = "http://www.monteandjanicechan.com/ws/test_ws.cfc?wsdl"; // private Object resultRequestSOAP = null; private TextView tv; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME); tv = (TextView)findViewById(R.id.people_view); //SoapObject request.addProperty("test_item", "1"); SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); envelope.setOutputSoapObject(request); AndroidHttpTransport androidHttpTransport = new AndroidHttpTransport(URL); try { androidHttpTransport.call(SOAP_ACTION, envelope); /* resultRequestSOAP = envelope.getResponse(); Vector tempResult = (Vector) resultRequestSOAP("test_functionReturn"); */ SoapObject resultsRequestSOAP = (SoapObject) envelope.bodyIn; Vector tempResult = (Vector) resultsRequestSOAP.getProperty("test_functionReturn"); int testsize = tempResult.size(); // SoapObject test = (SoapObject) tempResult.get(0); //String[] results = (String[]) resultRequestSOAP; Object tempvar = tempResult.elementAt(1); tv.setText(tempvar.toString()); } catch (Exception aE) { aE.printStackTrace (); tv.setText(aE.getClass().getName() + ": " + aE.getMessage()); } } }

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  • Form value not passed to Seam bean after a4j reRender

    - by Casper
    I'm making a webapp in Seam but ran into a problem I can't seem to fix. I have a JSF form where the customer can select a reservation type through a combobox. Based on the selected value, other form components gets rendered. For example: the customer selects Hours as reservation type, a panelGroup gets rendered where the customer can select a start- and an end hour. But if the customer would select 'part of the day' as reservation type, a selectOneMenu gets rendered where the customer can select a part of the day (morning, afternoon, evening) The rerendering well but the values of the components with a rendered conditional won't get passed to the bean. They stay null values. This is the code i'm talking about: <h:panelGrid columns="2"> <h:outputText value="Reservation Type" /> <h:selectOneMenu value="#{selectedPeriodPart}"> <s:selectItems value="#{productManager.getAvailableDayPartsSpot()}" var="daypart" label="#{daypart.label}"></s:selectItems> <s:convertEnum /> <a4j:support ajaxSingle="true" event="onchange" action="#" reRender="spot"></a4j:support> </h:selectOneMenu> <h:outputText id="date_spot" value="Date" /> <a4j:outputPanel id="calendar_spot" layout="block"> <rich:calendar value="#{reservation.reservationPeriod.startDate}" locale="en" cellWidth="24px" cellHeight="22px" style="width:200px" /> </a4j:outputPanel> <h:outputText rendered="#{selectedPeriodPart eq 'DAY_PART'}" value="Daypart" /> <h:selectOneMenu value="#{selectedDaypart}" rendered="#{selectedPeriodPart eq 'DAY_PART'}"> <f:selectItem id="si_morning" itemLabel="Morning (6:00 - 12:00)" itemValue="morning" /> <f:selectItem id="si_afternoon" itemLabel="Afternoon (12:00 - 18:00)" itemValue="afternoon" /> <f:selectItem id="si_evening" itemLabel="Evening (18:00 - 00:00)" itemValue="evening" /> </h:selectOneMenu> <h:outputText rendered="#{selectedPeriodPart eq 'HOURS'}" value="Hours" /> <h:panelGroup id="hours_spot" rendered="#{selectedPeriodPart eq 'HOURS'}"> <ui:include src="/includes/reservation/select_hours.xhtml" /> </h:panelGroup> </h:panelGrid> </s:div></code> Note: The calendar value do get passed back to the bean but the value of this piece of code doesn't (it does if you remove the rendered conditional):

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  • How hard programming is? Really. [closed]

    - by Bubba88
    Hi! The question is about your perception of programming activity. How hard/exacting this task is? There is much buzz about programming nowadays, people say that programmers are smart, very technical and abstract at a time, know much about world, psychology etc.. They say, that programmers got really powerful brain thing, cause there is much to keep in consideration simultaneously again with much information folded into each other associatively (up 10 levels of folding they say))) Still, there are some terms to specify at our own.. So that is the question: What do you think about programming in general? Is it hard? Is it 'for everyone' or for the particular kind of people only? How much non-CS background do you need to program (just to program, really; enterprise applications for example)? How long is the learning curve? (again, for programming in general) And another bunch of random questions: - If you were not to like/love programming, would that be a serious trouble bothering your current employment? - If you were to start from the beginning, would you chose that direction this time? - What other areas (jobs or maybe hobbies) are comparable to programming in the way they can explode someone's lovely brain? - Is 'non turing-complete programming' (SQL, XML, etc.) comparable to what we do or is it really way easier, less requiring, cheap and akin to cooking :)? Well, the essence is: How would you describe programming activity WRT to its difficulty? Or, on the other hand: Did you ever catch yourself thinking at some point: OMG, it's sooo hard! I don't know how would I ever program, even carried away this way and doing programming just for fun? It's very interesting to know your opinion, your'e the programmers after all. I mean much people must be exaggerating/speculating about the thing they do not really know about. But that musn't be the case here on SO :) P.S.: I'll try my best to update this post later, and you please edit it too. At least I'll get decent English in my question text :)

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  • Component must be a valid peer (when i remove frame.add(Component);)

    - by boyd
    i have this code here for creating and drawing array of pixels into an image import javax.swing.JFrame; import java.awt.Canvas; import java.awt.Graphics; import java.awt.image.BufferStrategy; import java.awt.image.BufferedImage; import java.awt.image.DataBufferInt; public class test extends Canvas implements Runnable{ private static final long serialVersionUID = 1L; public static int WIDTH = 800; public static int HEIGHT = 600; public boolean running=true; public int[] pixels; public BufferedImage img; public static JFrame frame; private Thread thread; public static void main(String[] arg) { test wind = new test(); frame = new JFrame("WINDOW"); frame.add(wind); frame.setVisible(true); frame.setSize(WIDTH, HEIGHT); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); wind.init(); } public void init(){ thread=new Thread(this); thread.start(); img=new BufferedImage(WIDTH, HEIGHT,BufferedImage.TYPE_INT_RGB); pixels=((DataBufferInt)img.getRaster().getDataBuffer()).getData(); } public void run(){ while(running){ render(); try { thread.sleep(55); } catch (InterruptedException e) { e.printStackTrace(); } } } public void render(){ BufferStrategy bs=this.getBufferStrategy(); if(bs==null){ createBufferStrategy(4); return; } drawRect(0,0,150,150); Graphics g= bs.getDrawGraphics(); g.drawImage(img, 0, 0, WIDTH, HEIGHT, null); g.dispose(); bs.show(); } private void drawRect(int x, int y, int w, int h) { for(int i=x;i<w;i++) for(int j=x;j<h;j++) pixels[i+j*WIDTH]=346346; } } Why i get "Component must be a valid peer" error when i remove the line: frame.add(wind); Why I want to remove it? Because I want to create a frame using a class object(from another file) and use the code Window myWindow= new Window() to do exactly the same thing BTW: who knows Java and understands what i wrote please send me a message with your skype or yahoo messenger id.I want to cooperate with you for a project (graphics engine for games)

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  • Implementing rounded corners on slide down navigation menu

    - by Nick
    I am working on the slide down menu you can see here. I have rounded corners on both ul#navigation and ul.subnavigation. When the submenu slides down it is possible to see the border at the bottom of ul.subnavigation overlap with the content of ul#navigation, when I would like it to slide down smoothly, without the 'flicker'. I am aware that this issue is caused by the rounded corners. I need ul.subnavigation to cover the rounded corners at the bottom of ul#navigation when the menu drops down, without seeing the double border-bottom issue. I hope this is clear! Code is below. Thanks, Nick HTML <ul id="navigation"> <li class="dropdown"><a href="#">menu</a> <ul class="sub_navigation"> <li><a href="#">home</a></li> <li><a href="#">help</a></li> <li><a href="#">disable tips</a></li> </ul> </li> </ul> JQUERY $('.dropdown').hover(function() { $(this).find('.sub_navigation').slideToggle(); });? CSS ul#navigation, ul.sub_navigation { margin:0; padding:0; list-style-type:none; min-width:100px; background-color: white; font-size:15px; font-family: Trebuchet MS; text-align: center; -khtml-border-radius: 0 0 5px 5px; -moz-border-radius: 0 0 5px 5px; -webkit-border-radius: 0 0 5px 5px; border-radius: 0 0 5px 5px; border:1px black solid; border-top:none; } ul.sub_navigation { margin-left:-1px; position: absolute; top:28px; } ul#navigation { float:left; position:absolute; top:0; } ul#navigation li { float:left; min-width:100px; } ul.sub_navigation { position:absolute; display:none; } ul.sub_navigation li { clear:both; } a, a:active, a:visited { display:block; padding:7px; }

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  • Is it possible to gzip and upload this string to Amazon S3 without ever being written to disk?

    - by BigJoe714
    I know this is probably possible using Streams, but I wasn't sure the correct syntax. I would like to pass a string to the Save method and have it gzip the string and upload it to Amazon S3 without ever being written to disk. The current method inefficiently reads/writes to disk in between. The S3 PutObjectRequest has a constructor with InputStream input as an option. import java.io.*; import java.util.zip.GZIPOutputStream; import com.amazonaws.auth.PropertiesCredentials; import com.amazonaws.services.s3.AmazonS3; import com.amazonaws.services.s3.AmazonS3Client; import com.amazonaws.services.s3.model.PutObjectRequest; public class FileStore { public static void Save(String data) throws IOException { File file = File.createTempFile("filemaster-", ".htm"); file.deleteOnExit(); Writer writer = new OutputStreamWriter(new FileOutputStream(file)); writer.write(data); writer.flush(); writer.close(); String zippedFilename = gzipFile(file.getAbsolutePath()); File zippedFile = new File(zippedFilename); zippedFile.deleteOnExit(); AmazonS3 s3 = new AmazonS3Client(new PropertiesCredentials( new FileInputStream("AwsCredentials.properties"))); String bucketName = "mybucket"; String key = "test/" + zippedFile.getName(); s3.putObject(new PutObjectRequest(bucketName, key, zippedFile)); } public static String gzipFile(String filename) throws IOException { try { // Create the GZIP output stream String outFilename = filename + ".gz"; GZIPOutputStream out = new GZIPOutputStream(new FileOutputStream(outFilename)); // Open the input file FileInputStream in = new FileInputStream(filename); // Transfer bytes from the input file to the GZIP output stream byte[] buf = new byte[1024]; int len; while ((len = in.read(buf)) > 0) { out.write(buf, 0, len); } in.close(); // Complete the GZIP file out.finish(); out.close(); return outFilename; } catch (IOException e) { throw e; } } }

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  • Different positions in ViewPager

    - by Kalai Selvan.G
    In my Application am using ViewPager to swipe the images,which comes through webservice as URL. Everything goes smoothly,the problem is while swiping myself getting the position as collapsed one.. Swipe left-right: positions are 1,2,3,4,5,etc.. if i stops swiping at 5th pos and started to Swipe from right-left: positions are 2,1...why this happens? I need to catch the position of the imageURL to find out the ID of the specific image and so i need to download and set it as wallpaper.. Normally while we swipe from right-left,the positions should decrease like 4,3,2,1. Also in debugger mode i got some start position,end position,last position with different values.. Any Clue about ViewPager. Here is my code: public class ImagePagerActivity extends BaseActivity { private ViewPager pager; private DisplayImageOptions options; public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.ac_image_pager); Bundle bundle = getIntent().getExtras(); String[] imageUrls = bundle.getStringArray(Extra.IMAGES); int pagerPosition = bundle.getInt(Extra.IMAGE_POSITION, 0); options = new DisplayImageOptions.Builder() .showImageForEmptyUrl(R.drawable.image_for_empty_url) .cacheOnDisc() .decodingType(DecodingType.MEMORY_SAVING) .build(); pager = (ViewPager) findViewById(R.id.pager); pager.setAdapter(new ImagePagerAdapter(imageUrls)); pager.setCurrentItem(pagerPosition); } private class ImagePagerAdapter extends PagerAdapter { private String[] images; private LayoutInflater inflater; ImagePagerAdapter(String[] images) { this.images = images; inflater = getLayoutInflater(); } @Override public void destroyItem(View container, int position, Object object) { ((ViewPager) container).removeView((View) object); } @Override public void finishUpdate(View container) { } @Override public int getCount() { return images.length; } @Override public Object instantiateItem(View view, int position) { final FrameLayout imageLayout = (FrameLayout) inflater.inflate(R.layout.item_pager_image, null); final ImageView imageView = (ImageView) imageLayout.findViewById(R.id.image); final ProgressBar spinner = (ProgressBar) imageLayout.findViewById(R.id.loading); imageLoader.displayImage(images[position], imageView, options, new ImageLoadingListener() { public void onLoadingStarted() { spinner.setVisibility(View.VISIBLE); } public void onLoadingFailed() { spinner.setVisibility(View.GONE); imageView.setImageResource(android.R.drawable.ic_delete); } public void onLoadingComplete() { spinner.setVisibility(View.GONE); } }); ((ViewPager) view).addView(imageLayout, 0); return imageLayout; } @Override public boolean isViewFromObject(View view, Object object) { return view.equals(object); } @Override public void restoreState(Parcelable state, ClassLoader loader) { } @Override public Parcelable saveState() { return null; } @Override public void startUpdate(View container) { } } }

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  • Qt vs .NET - a few comparisons [closed]

    - by Pirate for Profit
    Event Handling In Qt the event handling system you just emit signals when something cool happens and then catch them in slots, for instance emit valueChanged(int percent, bool something); and void MyCatcherObj::valueChanged(int p, bool ok){} blocking them and disconnecting them when needed, doing it across threads... once you get the hang of it, it just seems a lot more natural and intuitive than the way the .NET event handling is set up (you know, object sender, CustomEventArgs e). And I'm not just talking about syntax, because in the end the .NET delegate crap is the bomb. I'm also talking about in more than just reflection (because, yes, .NET obviously has much stronger reflection capabilities). I'm talking about in the way the system feels to a human being. Qt wins hands down i m o. Basically, the footprints make more sense and you can visualize the project easier without the clunky event handling system. I wish I could it explain it better. The only thing is, I do love some of the ease of C# compared to C++ and .NET's assembly architecture. That is a big bonus for modular projects, which are a PITA to do in C++. Database Ease of Doing Crap Also what about datasets and database manipulations. I think .net wins here but I'm not sure. Threading/Conccurency How do you guys think of the threading? In .NET, all I've ever done is make like a list of master worker threads with locks. I like QConcurrentFramework, you don't worry about locks or anything, and with the ease of the signal slot system across threads it's nice to get notified about the progress of things. Memory Usage Also what do you think of the overall memory usage comparison. Is the .NET garbage collector pretty on the ball and quick compared to the instantaneous nature of native memory management? Or does it just let programs leak up a storm and lag the computer then clean it up when it's about to really lag? However, I am a n00b who doesn't know what I'm talking about, please school me on the subject.

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  • Issue with parsed text with HTMLCleaner - spaces at the begining of text

    - by ansol90
    Im able to get text using HTMLCleaner from website. The problem is that when I set the text to a TextView it shows the beginning of the text with a big space on it. Here is the screenshot of what im talking about. I have tried android:gravity but nothing happened. Please help. Here is my Code: private class SiteParser extends AsyncTask<String, Void, String> { protected String doInBackground(String... arg) { String output = null; try { HtmlHelper hh = new HtmlHelper(new URL(arg[0])); List<TagNode> news = hh.getnewsByClass("TextoPrint"); for (Iterator<TagNode> iterator = newss.iterator(); iterator .hasNext();) { TagNode divElement = (TagNode) iterator.next(); output = divElement.getText().toString(); } } catch (Exception e) { e.printStackTrace(); } return output; } protected void onPostExecute(String output) { Bundle bundle=new Bundle(); bundle.putString("body",output); Intent mainIntent = new Intent(act, MyView.class); mainIntent.putExtras(bundle); startActivity(mainIntent); act.finish(); } } public class HtmlHelper { TagNode rootNode; public HtmlHelper(URL htmlPage) throws IOException, XPatherException { HtmlCleaner cleaner = new HtmlCleaner(); rootNode = cleaner.clean(htmlPage); } List<TagNode> getnewsByClass(String Classname){ List<TagNode> newsList = new ArrayList<TagNode>(); TagNode divElements[] = rootNode.getElementsByName("div", true); for (int i = 0; divElements != null && i < divElements.length; i++) { String classType = divElements[i].getAttributeByName("id"); if (classType != null && classType.equals(Classname)) { newsList.add(divElements[i]); } } return newsList; } }

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  • Active Directory validate service account and user accounts

    - by Padur
    Hello folks I have an issue here, I guess you all know what is AD service account and why it is used for, if not please see the below description ? SSL-Explorer requires a dedicated Active Directory account to use for authenticating AD users. This account serves as a link to your Active Directory database. If the Service Account is not found on your AD database then the SSL-Explorer service will not start. Well I have Active Directory service account details and user submitted login/password details.In the code below I validated service account by giving MEMBER_GRPUP and adminPassword and I check whether the user exists in Active Directory by submitting samaaccountname but my question here is how do I validate the password submitted for that user? I am not sure how to do this, I appreciate if anybody has any suggestions on this. Thanks for your time. public boolean validateUserFromActiveDirectory(String userId) { final String MEMBER_GROUP = "CN=asdadasd,OU=asdasdasd Accounts,OU=adasdas,OU=asdasdas,DC=asdasdas,DC=asdasdas,DC=adasdasd,DC=asdasdasd"; String employeeNumber = ""; final String LDAP_INIT_CTX = "com.sun.jndi.ldap.LdapCtxFactory"; final String LDAP_URL = "ldap://xx-ssssssss.eee.eee.eeeee.eeeee:636"; final String MY_ATTRS[] = { "employeeNumber" }; String adminPassword = "somepassword"; String securityProtocol = "ssl"; boolean isValidUser = false; try { Hashtable env = new Hashtable(); env.put(Context.INITIAL_CONTEXT_FACTORY, LDAP_INIT_CTX); env.put(Context.PROVIDER_URL, LDAP_URL); env.put(Context.SECURITY_AUTHENTICATION, "simple"); env.put(Context.REFERRAL, "follow"); env.put(Context.SECURITY_PRINCIPAL, MEMBER_GROUP); env.put(Context.SECURITY_CREDENTIALS, adminPassword); env.put(Context.SECURITY_PROTOCOL, securityProtocol); //C:\Documents and Settings\yourusername\Local Settings\Temp File tf = File.createTempFile("adentTruststore", ".jks"); tf.deleteOnExit(); byte buffer[] = new byte[0x1000]; ClassLoader cl = JNDI.class.getClassLoader(); InputStream in = cl.getResourceAsStream( "someTruststore.jks"); FileOutputStream out = new FileOutputStream(tf); int cnt; while ((cnt = in.read(buffer)) != -1) out.write(buffer, 0, cnt); in.close(); out.close(); System.setProperty("javax.net.ssl.trustStore", tf .getAbsolutePath()); DirContext context = new InitialLdapContext(env, null); SearchControls searchControls = new SearchControls(); searchControls.setSearchScope(SearchControls.SUBTREE_SCOPE); NamingEnumeration results = context.search( "XX=ent,XX=abc,XX=aaaaa,XX=aaaa", "(sAMAccountName=" + userId + ")", searchControls); if (results != null && results.hasMore()) { //some logic } } } catch (Exception e) { e.printStackTrace(); } return isValidUser; }

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  • How do access a secure website within a sharepoint webpart?

    - by Bill
    How do access a secure website within a sharepoint webpart? The following code works fine as a console application but if you run it in a webpart, you will get a access violation WebRequest request = WebRequest.Create("https://somesecuresite.com"); WebResponse firstResponse = null; try { firstResponse = request.GetResponse(); } catch (WebException ex) { writer.WriteLine("Error: " + ex.ToString()); return; } if you access a non secure site, it also works. Any ideas? Error: System.Net.WebException: The underlying connection was closed: An unexpected error occurred on a receive. --- System.AccessViolationException: Attempted to read or write protected memory. This is often an indication that other memory is corrupt. at System.Net.UnsafeNclNativeMethods.NativePKI.CertVerifyCertificateChainPolicy(IntPtr policy, SafeFreeCertChain chainContext, ChainPolicyParameter& cpp, ChainPolicyStatus& ps) at System.Net.PolicyWrapper.VerifyChainPolicy(SafeFreeCertChain chainContext, ChainPolicyParameter& cpp) at System.Net.Security.SecureChannel.VerifyRemoteCertificate(RemoteCertValidationCallback remoteCertValidationCallback) at System.Net.Security.SslState.CompleteHandshake() at System.Net.Security.SslState.CheckCompletionBeforeNextReceive(ProtocolToken message, AsyncProtocolRequest asyncRequest) at System.Net.Security.SslState.StartSendBlob(Byte[] incoming, Int32 count, AsyncProtocolRequest asyncRequest) at System.Net.Security.SslState.ProcessReceivedBlob(Byte[] buffer, Int32 count, AsyncProtocolRequest asyncRequest) at System.Net.Security.SslState.StartReadFrame(Byte[] buffer, Int32 readBytes, AsyncProtocolRequest asyncRequest) at System.Net.Security.SslState.StartReceiveBlob(Byte[] buffer, AsyncProtocolRequest asyncRequest) at System.Net.Security.SslState.CheckCompletionBeforeNextReceive(ProtocolToken message, AsyncProtocolRequest asyncRequest) at System.Net.Security.SslState.StartSendBlob(Byte[] incoming, Int32 count, AsyncProtocolRequest asyncRequest) at System.Net.Security.SslState.ProcessReceivedBlob(Byte[] buffer, Int32 count, AsyncProtocolRequest asyncRequest) at System.Net.Security.SslState.StartReadFrame(Byte[] buffer, Int32 readBytes, AsyncProtocolRequest asyncRequest) at System.Net.Security.SslState.StartReceiveBlob(Byte[] buffer, AsyncProtocolRequest asyncRequest) at System.Net.Security.SslState.CheckCompletionBeforeNextReceive(ProtocolToken message, AsyncProtocolRequest asyncRequest) at System.Net.Security.SslState.StartSendBlob(Byte[] incoming, Int32 count, AsyncProtocolRequest asyncRequest) at System.Net.Security.SslState.ProcessReceivedBlob(Byte[] buffer, Int32 count, AsyncProtocolRequest asyncRequest) at System.Net.Security.SslState.StartReadFrame(Byte[] buffer, Int32 readBytes, AsyncProtocolRequest asyncRequest) at System.Net.Security.SslState.StartReceiveBlob(Byte[] buffer, AsyncProtocolRequest asyncRequest) at System.Net.Security.SslState.CheckCompletionBeforeNextReceive(ProtocolToken message, AsyncProtocolRequest asyncRequest) at System.Net.Security.SslState.StartSendBlob(Byte[] incoming, Int32 count, AsyncProtocolRequest asyncRequest) at System.Net.Security.SslState.ForceAuthentication(Boolean receiveFirst, Byte[] buffer, AsyncProtocolRequest asyncRequest) at System.Net.Security.SslState.ProcessAuthentication(LazyAsyncResult lazyResult) at System.Net.TlsStream.CallProcessAuthentication(Object state) at System.Threading.ExecutionContext.runTryCode(Object userData) at System.Runtime.CompilerServices.RuntimeHelpers.ExecuteCodeWithGuaranteedCleanup(TryCode code, CleanupCode backoutCode, Object userData) at System.Threading.ExecutionContext.RunInternal(ExecutionContext executionContext, ContextCallback callback, Object state) at System.Threading.ExecutionContext.Run(ExecutionContext executionContext, ContextCallback callback, Object state) at System.Net.TlsStream.ProcessAuthentication(LazyAsyncResult result) at System.Net.TlsStream.Write(Byte[] buffer, Int32 offset, Int32 size) at System.Net.PooledStream.Write(Byte[] buffer, Int32 offset, Int32 size) at System.Net.ConnectStream.WriteHeaders(Boolean async) --- End of inner exception stack trace --- at System.Net.HttpWebRequest.GetResponse()

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  • Invalid character in a Base-64 string when Concatenating and Url encoding a string

    - by Rob
    I’m trying to write some encryption code that is passed through a Url. For the sake of the issue I’ve excluded the actual encryption of the data and just shown the code causing the problem. I take a salt value, convert it to a byte array and then convert that to a base64 string. This string I concatenate to another base64 string (which was previously a byte array). These two base64 strings are then Url encoded. Here’s my code... using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Security.Cryptography; using System.IO; using System.Web; class RHEncryption { private static readonly Encoding ASCII_ENCODING = new System.Text.ASCIIEncoding(); private static readonly string SECRET_KEY = "akey"; private static string md5(string text) { return BitConverter.ToString(new MD5CryptoServiceProvider().ComputeHash(ASCII_ENCODING.GetBytes(text))).Replace("-", "").ToLower(); } public string UrlEncodedData; public RHEncryption() { // encryption object RijndaelManaged aes192 = new RijndaelManaged(); aes192.KeySize = 192; aes192.BlockSize = 192; aes192.Mode = CipherMode.CBC; aes192.Key = ASCII_ENCODING.GetBytes(md5(SECRET_KEY)); aes192.GenerateIV(); // convert Ivector to base64 for sending string base64IV = Convert.ToBase64String(aes192.IV); // salt value string s = "maryhadalittlelamb"; string salt = s.Substring(0, 8); // convert to byte array // and base64 for sending byte[] saltBytes = ASCII_ENCODING.GetBytes(salt.TrimEnd('\0')); string base64Salt = Convert.ToBase64String(saltBytes); //url encode concatenated base64 strings UrlEncodedData = HttpUtility.UrlEncode(base64Salt + base64IV, ASCII_ENCODING); } public string UrlDecodedData() { // decode the url encode string string s = HttpUtility.UrlDecode(UrlEncodedData, ASCII_ENCODING); // convert back from base64 byte[] base64DecodedBytes = null; try { base64DecodedBytes = Convert.FromBase64String(s); } catch (FormatException e) { Console.WriteLine(e.Message.ToString()); Console.ReadLine(); } return s; } } If I then call the UrlDecodedData method I get a “Invalid character in a Base-64 string” exception. This is generated because the base64Salt variable contains an invalid character (I’m guessing a line termination) but I can’t seem to strip it off.

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