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  • More issues with IntelliJ 9.0.1 "Hello World" in Scala - Predef version 5.0 vs 4.1

    - by Alex R
    Any ideas what could cause this? Scala signature Predef has wrong version Expected 5.0 found: 4.1 in .... scala-library.jar I tried both versions 2.7.6 and 2.8 RC1 of scala-*.jar, the result was the same. JDK is 1.6.u20. UPDATE Today uninstalled IntelliJ 9.0.1, and installed 9.0.2 Early Availability, with the 4/14 stable version of the Scala plug-in. Then I setup a project from scratch through the wizards: new project from scratch JDK is 1.6.u20 accept the default (project) instead of global / module accept the download of Scala 2.8.0beta1 into project's lib folder Created a new class: object hello { def main(args: Array[String]) { println("hello: " + args); } } For my efforts, I now have a brand-new error :) Here it is: Scalac internal error: class java.lang.ClassNotFoundException [java.net.URLClassLoader$1.run(URLClassLoader.java:202), java.security.AccessController.doPrivileged(Native Method), java.net.URLClassLoader.findClass(URLClassLoader.java:190), java.lang.ClassLoader.loadClass(ClassLoader.java:307), sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:301), java.lang.ClassLoader.loadClass(ClassLoader.java:248), java.lang.Class.forName0(Native Method), java.lang.Class.forName(Class.java:169), org.jetbrains.plugins.scala.compiler.rt.ScalacRunner.main(ScalacRunner.java:72)] Thanks

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  • Is it possible to override List accessors in Grails domain classes?

    - by Ali G
    If I have a List in a Grails domain class, is there a way to override the addX() and removeX() accessors to it? In the following example, I'd expect MyObject.addThing(String) to be called twice. In fact, the output is: Adding thing: thing 2 class MyObject { static hasMany = [things: String] List things = [] void addThing(String newThing) { println "Adding thing: ${newThing}" things << newThing } } class BootStrap { def init = { servletContext -> MyObject o = new MyObject().save() o.things << 'thing 1' o.addThing('thing 2') } def destroy = { } }

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  • How can I get the post text to be beside the avatar and not below it?

    - by William
    So I'm trying to create a forum with avatars, but right now the text is going below the avatars and not beside them. How can I fix this? Here is the CSS: .postbox{ text-align: left; margin: auto; background-color: #dbfef8; border: 1px solid #82FFCD; width: 100%; margin-top: 10px; } .postfooter{ width: 100%; border-top: 1px solid #82FFCD; } .postheader{ width: 100%; border-bottom: 1px solid #82FFCD; } .posttext{ width: 70%; text-align: left; border: 1px solid #82FFCD; } .postavi{ width: 20%; text-align: left; border: 1px solid #82FFCD; } and here is the html: <div class="postbox"><div class="postheader"> <b><span>CyanPrime!!~::##Admin##::~</span></b> </div> <div class="postavi"><img src="http://prime.programming-designs.com/test_forum/images/avatars/hacker.png" alt="hacker"/></div><div class="posttext">Let's test the Hacker Avatar.</div> <div class="postfooter"> [<a href="http://prime.programming-designs.com/test_forum/viewthread.php?thread=25">Reply</a>] 0 posts omitted. </div> </div>

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  • Proper use of Q_OBJECT?

    - by Jen
    If I derive my class from QObject (or a subclass), the Qt documentation says that I have to put the Q_OBJECT macro into my class declaration. It also ways I need to "run the meta-object compiler" for my class. I have no idea how to do this. Is this something I need to add to the .pro file? Do I need to edit the makefile? This seems overly complicated for a simple derived class. I'm using Qt Creator.

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  • Android Application is unexpectedly stopped error when button is clicked

    - by user1794499
    Hi there I'm totally new to Android development and I'm working in my android application my application includes a forum where users can post, comment and have their discussion there.... So I'm working in the interface but I get error when I click on the button I directs me to the signup page can somebody please help me with this error this is the code of the mainuserinterface.java for the mainuserinterface.xml file where the button resides. and the signupform.class is the java file for the next activity triggered when the button is clicked the error I receive is the application is unexpectedly stopped.. Hope I make it clear for you guys package com.mohammed.watzIslam; import android.app.Activity; import android.content.Intent; import android.os.Bundle; import android.view.View; import android.widget.Button; public class mainuserinterface extends Activity { @Override protected void onCreate(Bundle savedInstanceState) { // TODO Auto-generated method stub super.onCreate(savedInstanceState); setContentView(R.layout.mainuserinterface); // this is the button where I receive errors when I click Button forum = (Button) findViewById(R.id.next); forum.setOnClickListener(new View.OnClickListener() { public void onClick(View view){ Intent myIntent = new Intent (view.getContext(), signupform.class); startActivityForResult (myIntent, 0); } }); //these two button still not directing to any next activity yet Button button1 = (Button) findViewById(R.id.next); forum.setOnClickListener(new View.OnClickListener() { public void onClick(View view){ Intent myIntent1 = new Intent (view.getContext(), signupform.class); startActivityForResult (myIntent1, 0); } }); Button button2 = (Button) findViewById(R.id.next); forum.setOnClickListener(new View.OnClickListener() { public void onClick(View view){ Intent myIntent2 = new Intent (view.getContext(), signupform.class); startActivityForResult (myIntent2, 0); } }); } }

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  • Review my ASP.NET Authentication code.

    - by Niels Bosma
    I have had some problems with authentication in ASP.NET. I'm not used most of the built in authentication in .NET. I gotten some complaints from users using Internet Explorer (any version - may affect other browsers as well) that the login process proceeds but when redirected they aren't authenticated and are bounced back to loginpage (pages that require authentication check if logged in and if not redirect back to loginpage). Can this be a cookie problem? Do I need to check if cookies are enabled by the user? What's the best way to build authentication if you have a custom member table and don't want to use ASP.NET login controls? Here my current code: using System; using System.Linq; using MyCompany; using System.Web; using System.Web.Security; using MyCompany.DAL; using MyCompany.Globalization; using MyCompany.DAL.Logs; using MyCompany.Logging; namespace MyCompany { public class Auth { public class AuthException : Exception { public int StatusCode = 0; public AuthException(string message, int statusCode) : base(message) { StatusCode = statusCode; } } public class EmptyEmailException : AuthException { public EmptyEmailException() : base(Language.RES_ERROR_LOGIN_CLIENT_EMPTY_EMAIL, 6) { } } public class EmptyPasswordException : AuthException { public EmptyPasswordException() : base(Language.RES_ERROR_LOGIN_CLIENT_EMPTY_PASSWORD, 7) { } } public class WrongEmailException : AuthException { public WrongEmailException() : base(Language.RES_ERROR_LOGIN_CLIENT_WRONG_EMAIL, 2) { } } public class WrongPasswordException : AuthException { public WrongPasswordException() : base(Language.RES_ERROR_LOGIN_CLIENT_WRONG_PASSWORD, 3) { } } public class InactiveAccountException : AuthException { public InactiveAccountException() : base(Language.RES_ERROR_LOGIN_CLIENT_INACTIVE_ACCOUNT, 5) { } } public class EmailNotValidatedException : AuthException { public EmailNotValidatedException() : base(Language.RES_ERROR_LOGIN_CLIENT_EMAIL_NOT_VALIDATED, 4) { } } private readonly string CLIENT_KEY = "9A751E0D-816F-4A92-9185-559D38661F77"; private readonly string CLIENT_USER_KEY = "0CE2F700-1375-4B0F-8400-06A01CED2658"; public Client Client { get { if(!IsAuthenticated) return null; if(HttpContext.Current.Items[CLIENT_KEY]==null) { HttpContext.Current.Items[CLIENT_KEY] = ClientMethods.Get<Client>((Guid)ClientId); } return (Client)HttpContext.Current.Items[CLIENT_KEY]; } } public ClientUser ClientUser { get { if (!IsAuthenticated) return null; if (HttpContext.Current.Items[CLIENT_USER_KEY] == null) { HttpContext.Current.Items[CLIENT_USER_KEY] = ClientUserMethods.GetByClientId((Guid)ClientId); } return (ClientUser)HttpContext.Current.Items[CLIENT_USER_KEY]; } } public Boolean IsAuthenticated { get; set; } public Guid? ClientId { get { if (!IsAuthenticated) return null; return (Guid)HttpContext.Current.Session["ClientId"]; } } public Guid? ClientUserId { get { if (!IsAuthenticated) return null; return ClientUser.Id; } } public int ClientTypeId { get { if (!IsAuthenticated) return 0; return Client.ClientTypeId; } } public Auth() { if (HttpContext.Current.User.Identity.IsAuthenticated) { IsAuthenticated = true; } } public void RequireClientOfType(params int[] types) { if (!(IsAuthenticated && types.Contains(ClientTypeId))) { HttpContext.Current.Response.Redirect((new UrlFactory(false)).GetHomeUrl(), true); } } public void Logout() { Logout(true); } public void Logout(Boolean redirect) { FormsAuthentication.SignOut(); IsAuthenticated = false; HttpContext.Current.Session["ClientId"] = null; HttpContext.Current.Items[CLIENT_KEY] = null; HttpContext.Current.Items[CLIENT_USER_KEY] = null; if(redirect) HttpContext.Current.Response.Redirect((new UrlFactory(false)).GetHomeUrl(), true); } public void Login(string email, string password, bool autoLogin) { Logout(false); email = email.Trim().ToLower(); password = password.Trim(); int status = 1; LoginAttemptLog log = new LoginAttemptLog { AutoLogin = autoLogin, Email = email, Password = password }; try { if (string.IsNullOrEmpty(email)) throw new EmptyEmailException(); if (string.IsNullOrEmpty(password)) throw new EmptyPasswordException(); ClientUser clientUser = ClientUserMethods.GetByEmailExcludingProspects(email); if (clientUser == null) throw new WrongEmailException(); if (!clientUser.Password.Equals(password)) throw new WrongPasswordException(); Client client = clientUser.Client; if (!(bool)client.PreRegCheck) throw new EmailNotValidatedException(); if (!(bool)client.Active || client.DeleteFlag.Equals("y")) throw new InactiveAccountException(); FormsAuthentication.SetAuthCookie(client.Id.ToString(), true); HttpContext.Current.Session["ClientId"] = client.Id; log.KeyId = client.Id; log.KeyEntityId = ClientMethods.GetEntityId(client.ClientTypeId); } catch (AuthException ax) { status = ax.StatusCode; log.Success = status == 1; log.Status = status; } finally { LogRecorder.Record(log); } } } }

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  • Why do I get Detached Entity exception when upgrading Spring Boot 1.1.4 to 1.1.5

    - by mmeany
    On updating Spring Boot from 1.1.4 to 1.1.5 a simple web application started generating detached entity exceptions. Specifically, a post authentication inteceptor that bumped number of visits was causing the problem. A quick check of loaded dependencies showed that Spring Data has been updated from 1.6.1 to 1.6.2 and a further check of the change log shows a couple of issues relating to optimistic locking, version fields and JPA issues that have been fixed. Well I am using a version field and it starts out as Null following recommendation to not set in the specification. I have produced a very simple test scenario where I get detached entity exceptions if the version field starts as null or zero. If I create an entity with version 1 however then I do not get these exceptions. Is this expected behaviour or is there still something amiss? Below is the test scenario I have for this condition. In the scenario the service layer that has been annotated @Transactional. Each test case makes multiple calls to the service layer - the tests are working with detached entities as this is the scenario I am working with in the full blown application. The test case comprises four tests: Test 1 - versionNullCausesAnExceptionOnUpdate() In this test the version field in the detached object is Null. This is how I would usually create the object prior to passing to the service. This test fails with a Detached Entity exception. I would have expected this test to pass. If there is a flaw in the test then the rest of the scenario is probably moot. Test 2 - versionZeroCausesExceptionOnUpdate() In this test I have set the version to value Long(0L). This is an edge case test and included because I found reference to Zero values being used for version field in the Spring Data change log. This test fails with a Detached Entity exception. Of interest simply because the following two tests pass leaving this as an anomaly. Test 3 - versionOneDoesNotCausesExceptionOnUpdate() In this test the version field is set to value Long(1L). Not something I would usually do, but considering the notes in the Spring Data change log I decided to give it a go. This test passes. Would not usually set the version field, but this looks like a work-around until I figure out why the first test is failing. Test 4 - versionOneDoesNotCausesExceptionWithMultipleUpdates() Encouraged by the result of test 3 I pushed the scenario a step further and perform multiple updates on the entity that started life with a version of Long(1L). This test passes. Reinforcement that this may be a useable work-around. The entity: package com.mvmlabs.domain; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.GenerationType; import javax.persistence.Id; import javax.persistence.Table; import javax.persistence.Version; @Entity @Table(name="user_details") public class User { @Id @GeneratedValue(strategy=GenerationType.AUTO) private Long id; @Version private Long version; @Column(nullable = false, unique = true) private String username; @Column(nullable = false) private Integer numberOfVisits; public Long getId() { return id; } public void setId(Long id) { this.id = id; } public Long getVersion() { return version; } public void setVersion(Long version) { this.version = version; } public Integer getNumberOfVisits() { return numberOfVisits == null ? 0 : numberOfVisits; } public void setNumberOfVisits(Integer numberOfVisits) { this.numberOfVisits = numberOfVisits; } public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } } The repository: package com.mvmlabs.dao; import org.springframework.data.repository.CrudRepository; import com.mvmlabs.domain.User; public interface UserDao extends CrudRepository<User, Long>{ } The service interface: package com.mvmlabs.service; import com.mvmlabs.domain.User; public interface UserService { User save(User user); User loadUser(Long id); User registerVisit(User user); } The service implementation: package com.mvmlabs.service; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.stereotype.Service; import org.springframework.transaction.annotation.Propagation; import org.springframework.transaction.annotation.Transactional; import org.springframework.transaction.support.TransactionSynchronizationManager; import com.mvmlabs.dao.UserDao; import com.mvmlabs.domain.User; @Service @Transactional(propagation=Propagation.REQUIRED, readOnly=false) public class UserServiceJpaImpl implements UserService { @Autowired private UserDao userDao; @Transactional(readOnly=true) @Override public User loadUser(Long id) { return userDao.findOne(id); } @Override public User registerVisit(User user) { user.setNumberOfVisits(user.getNumberOfVisits() + 1); return userDao.save(user); } @Override public User save(User user) { return userDao.save(user); } } The application class: package com.mvmlabs; import org.springframework.boot.SpringApplication; import org.springframework.boot.autoconfigure.EnableAutoConfiguration; import org.springframework.context.annotation.ComponentScan; import org.springframework.context.annotation.Configuration; @Configuration @ComponentScan @EnableAutoConfiguration public class Application { public static void main(String[] args) { SpringApplication.run(Application.class, args); } } The POM: <?xml version="1.0" encoding="UTF-8"?> <project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd"> <modelVersion>4.0.0</modelVersion> <groupId>com.mvmlabs</groupId> <artifactId>jpa-issue</artifactId> <version>0.0.1-SNAPSHOT</version> <packaging>jar</packaging> <name>spring-boot-jpa-issue</name> <description>JPA Issue between spring boot 1.1.4 and 1.1.5</description> <parent> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-starter-parent</artifactId> <version>1.1.5.RELEASE</version> <relativePath /> <!-- lookup parent from repository --> </parent> <dependencies> <dependency> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-starter-data-jpa</artifactId> </dependency> <dependency> <groupId>org.hsqldb</groupId> <artifactId>hsqldb</artifactId> <scope>runtime</scope> </dependency> <dependency> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-starter-test</artifactId> <scope>test</scope> </dependency> </dependencies> <properties> <project.build.sourceEncoding>UTF-8</project.build.sourceEncoding> <start-class>com.mvmlabs.Application</start-class> <java.version>1.7</java.version> </properties> <build> <plugins> <plugin> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-maven-plugin</artifactId> </plugin> </plugins> </build> </project> The application properties: spring.jpa.hibernate.ddl-auto: create spring.jpa.hibernate.naming_strategy: org.hibernate.cfg.ImprovedNamingStrategy spring.jpa.database: HSQL spring.jpa.show-sql: true spring.datasource.url=jdbc:hsqldb:file:./target/testdb spring.datasource.username=sa spring.datasource.password= spring.datasource.driverClassName=org.hsqldb.jdbcDriver The test case: package com.mvmlabs; import org.junit.Assert; import org.junit.Test; import org.junit.runner.RunWith; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.boot.test.SpringApplicationConfiguration; import org.springframework.test.context.junit4.SpringJUnit4ClassRunner; import com.mvmlabs.domain.User; import com.mvmlabs.service.UserService; @RunWith(SpringJUnit4ClassRunner.class) @SpringApplicationConfiguration(classes = Application.class) public class ApplicationTests { @Autowired UserService userService; @Test public void versionNullCausesAnExceptionOnUpdate() throws Exception { User user = new User(); user.setUsername("Version Null"); user.setNumberOfVisits(0); user.setVersion(null); user = userService.save(user); user = userService.registerVisit(user); Assert.assertEquals(new Integer(1), user.getNumberOfVisits()); Assert.assertEquals(new Long(1L), user.getVersion()); } @Test public void versionZeroCausesExceptionOnUpdate() throws Exception { User user = new User(); user.setUsername("Version Zero"); user.setNumberOfVisits(0); user.setVersion(0L); user = userService.save(user); user = userService.registerVisit(user); Assert.assertEquals(new Integer(1), user.getNumberOfVisits()); Assert.assertEquals(new Long(1L), user.getVersion()); } @Test public void versionOneDoesNotCausesExceptionOnUpdate() throws Exception { User user = new User(); user.setUsername("Version One"); user.setNumberOfVisits(0); user.setVersion(1L); user = userService.save(user); user = userService.registerVisit(user); Assert.assertEquals(new Integer(1), user.getNumberOfVisits()); Assert.assertEquals(new Long(2L), user.getVersion()); } @Test public void versionOneDoesNotCausesExceptionWithMultipleUpdates() throws Exception { User user = new User(); user.setUsername("Version One Multiple"); user.setNumberOfVisits(0); user.setVersion(1L); user = userService.save(user); user = userService.registerVisit(user); user = userService.registerVisit(user); user = userService.registerVisit(user); Assert.assertEquals(new Integer(3), user.getNumberOfVisits()); Assert.assertEquals(new Long(4L), user.getVersion()); } } The first two tests fail with detached entity exception. The last two tests pass as expected. Now change Spring Boot version to 1.1.4 and rerun, all tests pass. Are my expectations wrong? Edit: This code saved to GitHub at https://github.com/mmeany/spring-boot-detached-entity-issue

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  • Is it possible to change the model name in the django admin site?

    - by luc
    Hello, I am translating a django app and I would like to translate also the homepage of the django admin site. On this page are listed the application names and the model class names. I would like to translate the model class name but I don't find how to give a user-friendly name for a model class. Does anybody know how to do that?

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  • How to change UIBarButtonItem Title - iPhone SDK

    - by user340226
    Hi Can anyone help me in that I am only trying to change the Title on an UIBarButtonItem from a different class. My code is: -(IBAction)spanishPush { SafetyTalks *bbiTitle= [[SafetyTalks alloc]init]; bbiTitle.bbiOpenPopOver.title = @"Spanish"; } SafetyTalks = the class I am trying to reference bbiOpenPopOver = the UIBarButtonItem. I can change the Title when in the SafetyTalks class by simple: bbiOpenPopOver.title = @"Talk Topics"; but cannot do it when I am out of that class. Please help. Andy

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  • Default template arguments for function templates

    - by Arman
    Why are default template arguments only allowed on class templates? Why can't we define a default type in a member function template? For example: struct mycclass { template<class T=int> void mymember(T* vec) { // ... } }; Instead, C++ forces that default template arguments are only allowed on a class template.

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  • How do I use a different image for each JQuery UI Slider handle

    - by Tom
    I'm using a JQuery UI slider which has two handles (a.k.a range slider). I know how to style the first handle: .ui-slider-horizontal .ui-slider-handle {background: white url(http://stackoverflow.com/content/img/so/vote-arrow-down.png) no-repeat scroll 50% 50%;} But how do I style the second handle differently? Using Firebug I can see Jquery does not uniquely identify each handle: <div id="hourlyRateSlider" class="ui-slider ui-slider-horizontal ui-widget ui-widget-content ui-corner-all"> <div class="ui-slider-range ui-widget-header" style="left: 26%; width: 46%;"/> <a class="ui-slider-handle ui-state-default ui-corner-all" href="#" style="left: 26%;"/> <a class="ui-slider-handle ui-state-default ui-corner-all" href="#" style="left: 72%;"/> </div> So I imagine I have to use either a CSS child selector which could be cross-browser problematic. Or I could use some JQuery trickery to add a CSS class to the second handle? Anyone done this in a neat way before?

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  • jQuery fadein fadeout divs over set interval

    - by theDawckta
    I want to fadeOut the first div in a collection and then fadeIn the next div. The fade in out would trigger at a set time. The number of items in the collection is 1 to n. Here is an example of the html; <div class="contentPanel"> <div class="content"> <div style="border: solid 2px black; text-align: center"> This is first content </div> </div> <div class="content"> <div style="border: solid 2px black; text-align: center"> This is second content </div> </div> <div class="content"> <div style="border: solid 2px black; text-align: center"> This is third content </div> </div> </div> So on page load the first "content" class would be visible, after x amount of time, the current "content" would fadeout and the next "content" would fade in. When it got to the nth "content" it would start over, fadeout the nth "content" and fadein the first "content". This behavior would loop continuously.

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  • Grails efficient hasMany-Relationship in View

    - by Jan
    Hi folks, I'm saving contacts (email, mobile phone, ICQ, AIM etc.) for people like this: class Person { static hasMany = { contacts: Contact } } class Contact { String code ContactType type } class ContactType { String name } In my view, I've written some Templates for displaying each contact with a select-box for the contact-type and a textfield for the code, spiced up with some JavaScript for adding and deleting. My question is: Is there an easy and elegant way to update the data similar to personInstance.properties = params or do I have to read out all the fields, deleting removed, updating changed and adding new ones?

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  • C# dictionary uniqueness for sibling classes using IEquatable<T>

    - by anthony
    I would like to store insances of two classes in a dictionary structure and use IEquatable to determine uniqueness of these instances. Both of these classes share an (abstract) base class. Consider the following classes: abstract class Foo { ... } class SubFoo1 : Foo { ... } class SubFoo2 : Foo { ... } The dictionary will be delcared: Dictionary<Foo, Bar> Which classes should be declared as IEquatable? And what should the generic type T be for those declarations? Is this even possible?

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  • Testing a method that sends e-mail without sending the mail

    - by SnOrfus
    I have a method like public abstract class Base { public void MethodUnderTest(); } public class ClassUnderTest : Base { public override MethodUnderTest() { if(condition) { IMail mail = new Mail() { /* ... */ }; IMailer mailer = new Mailer() { /* ... */ } mailer.Send(mail); } else { /* ... */ } } } I have unit tests for this method, and the mail gets sent to myself, so it's not terrible (better than no test) but I'd prefer not to send the mail. The problem I have is that I don't want test specific code in the class (ie. if (testMode) return; instead of sending the mail) I don't know lots about DI, but I considered passing a mock IMailer into MethodUnderTest except that it overrides the base class, and no other class that derives from Base needs an IMailer object (I don't want to force implementers of Base to take an unnecessary IMailer in MethodUnderTest) What else can I do? (note: IMail and IMailer are part of an external library for sending e-mail. It's written in house, so I can modify it all I like if necessary, though I can't see a need to in this situation)

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  • No EJB receiver available for handling [appName:,modulename:HelloWorldSessionBean,distinctname:]

    - by zoit
    I'm trying to develop my first EJB with an Example I found, I have the next mistake: Exception in thread "main" java.lang.IllegalStateException: No EJB receiver available for handling [appName:,modulename:HelloWorldSessionBean,distinctname:] combination for invocation context org.jboss.ejb.client.EJBClientInvocationContext@41408b80 at org.jboss.ejb.client.EJBClientContext.requireEJBReceiver(EJBClientContext.java:584) at org.jboss.ejb.client.ReceiverInterceptor.handleInvocation(ReceiverInterceptor.java:119) at org.jboss.ejb.client.EJBClientInvocationContext.sendRequest(EJBClientInvocationContext.java:181) at org.jboss.ejb.client.EJBInvocationHandler.doInvoke(EJBInvocationHandler.java:136) at org.jboss.ejb.client.EJBInvocationHandler.doInvoke(EJBInvocationHandler.java:121) at org.jboss.ejb.client.EJBInvocationHandler.invoke(EJBInvocationHandler.java:104) at $Proxy0.sayHello(Unknown Source) at com.ibytecode.client.EJBApplicationClient.main(EJBApplicationClient.java:16) I use JBOSS 7.1, and the code is this: HelloWorld.java package com.ibytecode.business; import javax.ejb.Remote; @Remote public interface HelloWorld { public String sayHello(); } HelloWorldBean.java package com.ibytecode.businesslogic; import com.ibytecode.business.HelloWorld; import javax.ejb.Stateless; /** * Session Bean implementation class HelloWorldBean */ @Stateless public class HelloWorldBean implements HelloWorld { /** * Default constructor. */ public HelloWorldBean() { } public String sayHello() { return "Hello World !!!"; } } EJBApplicationClient.java: package com.ibytecode.client; import javax.naming.Context; import javax.naming.NamingException; import com.ibytecode.business.HelloWorld; import com.ibytecode.businesslogic.HelloWorldBean; import com.ibytecode.clientutility.ClientUtility; public class EJBApplicationClient { public static void main(String[] args) { // TODO Auto-generated method stub HelloWorld bean = doLookup(); System.out.println(bean.sayHello()); // 4. Call business logic } private static HelloWorld doLookup() { Context context = null; HelloWorld bean = null; try { // 1. Obtaining Context context = ClientUtility.getInitialContext(); // 2. Generate JNDI Lookup name String lookupName = getLookupName(); // 3. Lookup and cast bean = (HelloWorld) context.lookup(lookupName); } catch (NamingException e) { e.printStackTrace(); } return bean; } private static String getLookupName() { /* The app name is the EAR name of the deployed EJB without .ear suffix. Since we haven't deployed the application as a .ear, the app name for us will be an empty string */ String appName = ""; /* The module name is the JAR name of the deployed EJB without the .jar suffix. */ String moduleName = "HelloWorldSessionBean"; /*AS7 allows each deployment to have an (optional) distinct name. This can be an empty string if distinct name is not specified. */ String distinctName = ""; // The EJB bean implementation class name String beanName = HelloWorldBean.class.getSimpleName(); // Fully qualified remote interface name final String interfaceName = HelloWorld.class.getName(); // Create a look up string name String name = "ejb:" + appName + "/" + moduleName + "/" + distinctName + "/" + beanName + "!" + interfaceName; return name; } } ClientUtility.java package com.ibytecode.clientutility; import java.util.Properties; import javax.naming.Context; import javax.naming.InitialContext; import javax.naming.NamingException; public class ClientUtility { private static Context initialContext; private static final String PKG_INTERFACES = "org.jboss.ejb.client.naming"; public static Context getInitialContext() throws NamingException { if (initialContext == null) { Properties properties = new Properties(); properties.put("jboss.naming.client.ejb.context", true); properties.put(Context.URL_PKG_PREFIXES, PKG_INTERFACES); initialContext = new InitialContext(properties); } return initialContext; } } properties.file: remote.connectionprovider.create.options.org.xnio.Options.SSL_ENABLED=false remote.connections=default remote.connection.default.host=localhost remote.connection.default.port = 4447 remote.connection.default.connect.options.org.xnio.Options.SASL_POLICY_NOANONYMOUS=false This is what I have. Why I have this?. Thanks so much. Regards

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  • Flex: How to resize DisplayObject to fit panel in Flex application

    - by ohm
    I am trying to attach some of my actionscript class, inherited from Sprite, to my Flex application by attaching it to a UIComponent, then add UIComponent to a panel. However, the size of my Sprite class appears to be larger than the panel. So, I try to resize it using DisplayObject.scale property, but I need to know the size of my container. Since I try to make my code reusable, I figure that I should let my Sprite class handle the resize by getting it via its parent property (let's say, I can resize it by set this.scaleX = this.parent.Width/this.width or something like this) However, my Sprite class's parent, which is the UIComponent, has width/height of 0. So, my question is: 1) Is there any better way to resize DisplayObject class to fit its container when attached to Flex object? 2) If you know, why my UIComponent's size remain 0 and my DisplayObject still appears at its full size? Here's my code, using Flash Builder 4: private var loader:Loader = new Loader(); private function testLoader():void { var urlRequest:URLRequest = new URLRequest("http://localhost/welcome.png"); loader.load(urlRequest); loader.contentLoaderInfo.addEventListener(Event.COMPLETE,onLoaderLoadComplete); } private function onLoaderLoadComplete(e:Event):void { loader.contentLoaderInfo.removeEventListener(Event.COMPLETE,onLoaderLoadComplete); var ui : UIComponent = new UIComponent(); ui.addChild(loader); panelTest.addElement(ui); trace("ui.width = " + ui.width); trace("ui.height = " + ui.height); trace("loader.width = " + loader.width); trace("loader.height = " + loader.height); trace("panelTest.width = " + panelTest.width); trace("panelTest.height = " + panelTest.height); } And this is the result when run: ui.width = 0 ui.height = 0 loader.width = 571 loader.height = 411 panelTest.width = 480 panelTest.height = 320

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  • Is this a valid XPath expression?

    - by sid_com
    Is this xpath a valid XPath expression? (It does what it should ). #!/usr/bin/env perl use strict; use warnings; use 5.012; use XML::LibXML; my $string =<<EOS; <result> <cd> <artists> <artist class="1">Pumkinsingers</artist> <artist class="2">Max and Moritz</artist> </artists> <title>Hello, Hello</title> </cd> <cd> <artists> <artist class="3">Green Trees</artist> <artist class="4">The Leons</artist> </artists> <title>The Shield</title> </cd> </result> EOS #/ my $parser = XML::LibXML->new(); my $doc = $parser->load_xml( string => $string ); my $root = $doc->documentElement; my $xpath = '/result/cd[artists[artist[@class="2"]]]/title'; my @nodes = $root->findnodes( $xpath ); for my $node ( @nodes ) { say $node->textContent; }

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  • servlet-mapping for Wordpress on Tomcat using Quercus

    - by Jeremy
    I have a web app running in Tomcat and I'm trying to add a Wordpress blog to it using Quercus. It works if I hit a .php file in my blog, but links to my articles are structured like http://myapp.com/blog/2011/01/my-first-post/ which don't work. Below is my web.xml: <welcome-file-list> <welcome-file>index.do</welcome-file> <welcome-file>index.php</welcome-file> </welcome-file-list> <context-param> <param-name>contextConfigLocation</param-name> <param-value>/WEB-INF/myapp-service.xml</param-value> </context-param> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> <servlet> <servlet-name>myapp</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>myapp</servlet-name> <url-pattern>*.do</url-pattern> </servlet-mapping> <servlet> <servlet-name>Quercus Servlet</servlet-name> <servlet-class>com.caucho.quercus.servlet.QuercusServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>Quercus Servlet</servlet-name> <url-pattern>*.php</url-pattern> </servlet-mapping> I've tried many combos of url-pattern such as /blog, /blog/*, etc. I can't get anything to work. Any help is appreciated. Thanks!

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  • extending django usermodel

    - by imran-glt
    Hi i am trying to create a signup form for my django app. for this i have extended the user model. This is my Forms.py from contact.models import register from django import forms from django.contrib import auth class registerForm(forms.ModelForm): class Meta: model=register fields = ('latitude', 'longitude', 'status') class Meta: model = auth.models.User # this gives me the User fields fields = ('username', 'first_name', 'last_name', 'email') and this is my model.py from django.db import models from django.contrib.auth.models import User STATUS_CHOICES = ( ('Online', 'Online.'), ('Busy', 'Busy.'), ('AppearOffline', 'AppearOffline.'),) class register(models.Model): user = models.ForeignKey('auth.User', unique = True) latitude = models.DecimalField(max_digits=8, decimal_places=6) longitude = models.DecimalField(max_digits=8, decimal_places=6) status = models.CharField(max_length=8,choices=STATUS_CHOICES, blank= True, null=True) i dont know where i am making a mistake. the users passwords are not accepted at the login and the latitude and logitude are not saved against the created user user. i am fiarly new to django and dont know what to do any body have any solution .?

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  • Can I add round cornres to HtmlPanelGrid in code or in page? If yes - how?

    - by Elena
    Hi all! I have a task - add round corners to HtmlPanelGrid. Now I am trying to do it with css (using 4 images for each corner - that css create our designer). I load css and try to do this in my code: this.grid = new HtmlPanelGrid(); this.grid.setStyleClass("toplist,toplist-top"); But no changes I could see in my page. I tried to load css and use it with tags, but it also didnt work and created one more problem - my jsf didn't reload and redisplay: <div class="toplist"> <div class="toplist-top"><h2>Top 10 List</h2></div> <div class="toplist-bg"> <div class="toplist-cont"> <rich:tab label="Top-List" id="screenTop"> <h:panelGrid id="topListTable" binding="#{chartBean.topListTable}" /> </rich:tab> <a4j:support event="onclick" reRender="menuSection" actionListener="#{chartBean.doChangeTab}" /> </div> </div> <div class="toplist-bottom"></div> </div> I am interesting of adding round corners to topListTable in the code. How can I do it? I load my css as: <link href="#{facesContext.externalContext.requestContextPath}/css/stylesheet.css" rel="styleSheet" type="text/css"/> If anybody knows, how can I add corners to the panelGrid. Sorry for stupid question, but I am newborn in jsf and richfaces, and I want to solve this task right Thanks!

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  • Calling "Base-Getter" in Overriding Getter of Property

    - by scherand
    I have a base class "Parent" like this: using System; using System.Collections.Generic; using System.Text; namespace ConsoleApplication1 { class Parent { private int parentVirtualInt = -1; public virtual int VirtualProperty { get { return parentVirtualInt; } set { if(parentVirtualInt != value) { parentVirtualInt = value; } } } } } and a child class like this: using System; using System.Collections.Generic; using System.Text; namespace ConsoleApplication1 { class Child : Parent { public override int VirtualProperty { get { if(base.VirtualProperty > 0) { throw new ApplicationException("Dummy Ex"); } return base.VirtualProperty; } set { if(base.VirtualProperty != value) { base.VirtualProperty = value; } } } } } Note that the getter in Child is calling the getter of Parent (or at least this is what I intend). I now use the "Child" class by instantiating it, assigning a value (let's say 4) to its VirtualProperty and then reading the property again. Child c = new Child(); c.VirtualProperty = 4; Console.Out.WriteLine("Child.VirtualProperty: " + c.VirtualProperty); When I run this, I obviously get an ApplicationException saying "Dummy Ex". But if I set a breakpoint on the line if(base.VirtualProperty > 0) in Child and check the value of base.VirtualProperty (by hovering the mouse over it) before the exception can be thrown (I assume(d)), I already get the Exception. From this I convey that the statement base.VirtualProperty in the "Child-Getter calls itself"; kind of. What I would like to achieve is the same behavior I get when I change the definition of parentVirutalInt (in Parent) to protected and use base.parentVirtualInt in the Getter of Child instead of base.VirtualProperty. And I don't yet see why this is not working. Can anybody shed some light on this? I feel that overridden properties behave differently than overridden methods? By the way: I am doing something very similar with subclassing a class I do not have any control over (this is the main reason why my "workaround" is not an option). Kind regards

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  • MVC - Calling Controller Methods

    - by JT703
    Hello, My application is following the MVC design pattern. The problem I keep running into is needing to call methods inside a Controller class from outside that Controller class (ex. A View class wants to call a Controller method, or a Manager class wants to call a Controller method). Is calling Controller methods in this way allowed in MVC? If it's allowed, what's the proper way to do it? According to the version of MVC that I am following (there seems to be so many different versions out there), the View knows of the Model, and the Controller knows of the View. Doing it this way, I can't access the controller. Here's the best site I've found and the one describing the version of MVC I'm following: http://leepoint.net/notes-java/GUI/structure/40mvc.html. The Main Program code block really shows how this works. Thanks for any answers.

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  • How to add image in ListView android

    - by Wawan Den Frastøtende
    i would like to add images on my list view, and i have this code package com.wilis.appmysql; import android.app.ListActivity; import android.content.Intent; import android.os.Bundle; //import android.util.Log; import android.view.View; import android.widget.ArrayAdapter; import android.widget.ListView; import android.widget.Toast; public class menulayanan extends ListActivity { /** Called when the activity is first created. */ public void onCreate(Bundle icicle) { super.onCreate(icicle); // Create an array of Strings, that will be put to our ListActivity String[] menulayanan = new String[] { "Berita Terbaru", "Info Item", "Customer Service", "Help","Exit"}; //Menset nilai array ke dalam list adapater sehingga data pada array akan dimunculkan dalam list this.setListAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1,menulayanan)); } @Override /**method ini akan mengoveride method onListItemClick yang ada pada class List Activity * method ini akan dipanggil apabilai ada salah satu item dari list menu yang dipilih */ protected void onListItemClick(ListView l, View v, int position, long id) { super.onListItemClick(l, v, position, id); // Get the item that was clicked // Menangkap nilai text yang dklik Object o = this.getListAdapter().getItem(position); String pilihan = o.toString(); // Menampilkan hasil pilihan menu dalam bentuk Toast tampilkanPilihan(pilihan); } /** * Tampilkan Activity sesuai dengan menu yang dipilih * */ protected void tampilkanPilihan(String pilihan) { try { //Intent digunakan untuk sebagai pengenal suatu activity Intent i = null; if (pilihan.equals("Berita Terbaru")) { i = new Intent(this, PraBayar.class); } else if (pilihan.equals("Info Item")) { i = new Intent(this, PascaBayar.class); } else if (pilihan.equals("Customer Service")) { i = new Intent(this, CustomerService.class); } else if (pilihan.equals("Help")) { i = new Intent(this, Help.class); } else if (pilihan.equals("Exit")) { finish(); } else { Toast.makeText(this,"Anda Memilih: " + pilihan + " , Actionnya belum dibuat", Toast.LENGTH_LONG).show(); } startActivity(i); } catch (Exception e) { e.printStackTrace(); } } } and i want to add different image per list, so i mean is i want to add a.png to "Berita Terbaru", b.png to "Info Item", c.png "Customer Service" , so how to do it? i was very confused about this, thanks before...

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  • Problem using Hibernate Projections

    - by Lucas
    Hello! I'm using Richfaces + HibernateQuery to create a data list. I'm trying to use Hibernate Projections to group my query result. Here is the code: final DetachedCriteria criteria = DetachedCriteria .forClass(Class.class, "c") .setProjection(Projections.projectionList() .add(Projections.groupProperty("c.id"))); ... in the .xhtml file i have the following code: <rich:dataTable width="100%" id="dataTable" value="#{myBean.dataModel}" var="row"> <f:facet name="header"> <rich:columnGroup> ...... </rich:columnGroup> </f:facet> <h:column> <h:outputText value="#{row.id}"/> </h:column> <h:column> <h:outputText value="#{row.name}"/> </h:column> But when i run the page it gives me the following error: Error: value="#{row.id}": The class 'java.lang.Long' does not have the property 'id'. If i take out the Projection from the code it works correctly, but it doesn't group the result. So, which mistake could be happening here? EDIT: Here is the full criteria: final DetachedCriteria criteria = DetachedCriteria.forClass(Class.class, "c"); criteria.setFetchMode("e.zzzzz", FetchMode.JOIN); criteria.createAlias("e.aaaaaaaa", "aa"); criteria.add(Restrictions.ilike("aa.information", "informations....")); criteria.setProjection(Projections.distinct(Projections.projectionList() .add(Projections.groupProperty("e.id").as("e.id")))); getDao().findByCriteria(criteria); if i take the "setProjection" line it works fine. I don't understand why it gives that error putting that line.

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