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  • SQLite is the CASE statement expensive?

    - by galford13x
    I'm wondering if using a CASE statement in SQLite (or other SQL engines) to replace data is not advised. For example lets say I have a query. SELECT Users, CASE WHEN Active = 0 THEN 'Inactive' WHEN Active = 1 THEN 'Active' WHEN Active = 2 THEN 'Processing' ELSE 'ERROR' AS Active FROM UsersTable; When is it better to create a reference table and perform a JOIN. In this case I would create a Table 'ActiveStatesTable' with ActiveID, ActiveDescription and perform the JOIN.

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  • How to sort output of "s3cmd ls"

    - by dba.in.ua
    Amazon "s3cmd ls" takes like this output: 2010-02-20 21:01 1458414588 s3://file.tgz.00 2010-02-20 21:10 1458414527 s3://file.tgz.01 2010-02-20 22:01 1458414588 s3://file.tgz.00 2010-02-20 23:10 1458414527 s3://file.tgz.01 2010-02-20 23:20 1458414588 s3://file.tgz.02 How to select all files of archive, ending at 0 ... X, with the latest date of fileset ? Bash, regexp ? Thanx!

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  • mysql count, distinct, join? COnfusion

    - by calum
    hello i have 2 tables: tblItems ID | orderID | productID 1 1 2 2 1 2 3 2 1 4 3 2 tblProducts productID | productName 1 ABC 2 DEF im attempting to find the most popular Product based on whats in "tblItems", and display the product Name and the number of times it appears in the tblItems table. i can get mysql to count up the total like: $sql="SELECT COUNT(productID) AS CountProductID FROM tblItems"; but i can't figure out how to join the products table on..if i try LEFT JOIN the query goes horribly wrong hopefully thats not too confusing..thankss

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  • Linq to DataTable without enumerating fields

    - by Luciano
    Hi, i´m trying to query a DataTable object without specifying the fields, like this : var linqdata = from ItemA in ItemData.AsEnumerable() select ItemA but the returning type is System.Data.EnumerableRowCollection<System.Data.DataRow> and I need the following returning type System.Data.EnumerableRowCollection<<object,object>> (like the standard anonymous type) Any idea? Thanks

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  • Rails offen lost connection to oracle database

    - by qichunren
    I sometimes got this error from my log/production.log file: #<ActiveRecord::StatementInvalid: OCIError: ORA-03114: not connected to ORACLE: select decode(table_name,upper(table_name),lower(table_name),table_name) name from all_tables where owner = sys_context('userenv','session_user')>, How to solve this? How to rescue this and reconnect to oracle database?

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  • Django debug error

    - by Hulk
    I have the following in my model: class info(models.Model): add = models.CharField(max_length=255) name = models.CharField(max_length=255) An in the views when i say info_l = info.objects.filter(id=1) logging.debug(info_l.name) i get an error saying name doesnt exist at debug statement. 'QuerySet' object has no attribute 'name' 1.How can this be resolved. 2.Also how to query for only one field instead of selecting all like select name from info.

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  • how to get LIKE clause to work in asp.net and mssql

    - by anoob836
    Hi, I am doing a really simple query in asp.net but after I inserted the LIKE clause it stops working. Example: String sql = " SELECT * FROM Products WHERE ID = @MYID AND Name LIKE '%@MYNAME%' "; SqlCommand command = new SqlCommand(sql, cn); If I removed the LIKE it works. Hence I am thinking its to do with the '' quotes? Thanks

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  • Why decimal behave differently?

    - by haansi
    Hello, I am doing this small exercise. declare @No decimal(38,5); set @No=12345678910111213.14151; select @No*1000/1000,@No/1000*1000,@No; Results are: 12345678910111213.141510 12345678910111213.141000 12345678910111213.14151 Why are the results of first 2 selects different when mathematically it should be same?

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  • List all avilable ResourceBundle Files

    - by shay
    Hello all , i am using ResourceBundle and i want to give the user an option to select a language for the GUI. i want to get a list of all resource files that are under a specific package. i don't know what resource i will have since this application based on plug-ins is there an option to ask from java to search all available resources under a package ? (if no i guess the plug-in should give all available local for it) thank you all

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  • SHBrowseForFolder, But With Textbox to Navigate

    - by Emtucifor
    I found all the code I need to make SHBrowseForFolder work in my application. But I hate that it forces you to do everything in the little folder window, without a text box to navigate by typing. In Windows, I know I commonly see a different folder browse dialog that does let me type folder names and use the other regular navigation keys to get around to select the desired folder (backspace, "..", Enter, and so on). Is there a different API call for that?

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  • Multiline values in dropdown (ComboBox)

    - by Vladimir Kuzin
    Is there are any libraries to make ComboBox to select multiline options when expanded. I am looking something similar to Combobox in ExtJS except values have to appear when user clicks down arrow, like in normal dropdown. Does someone know if its possible to do something like that with ExtJS? Because their own community and support sure doesn’t (http://www.extjs.com/forum/showthread.php?t=94079)

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  • Copy Field and Methods

    - by javaguy
    I am new to java. I was wondering if there is a tool to copy fields and method easily. E.g if I have private String foo; // with getter/setters I should be able to select foo and type bar car in a textbox and the tool should generate fields bar and car with their getter/setters.

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  • Robust LINQ to XML query for sibling key-value pairs

    - by awshepard
    (First post, please be gentle!) I am just learning about LINQ to XML in all its glory and frailty, trying to hack it to do what I want to do: Given an XML file like this - <list> <!-- random data, keys, values, etc.--> <key>FIRST_WANTED_KEY</key> <value>FIRST_WANTED_VALUE</value> <key>SECOND_WANTED_KEY</key> <value>SECOND_WANTED_VALUE</value> <!-- wanted because it's first --> <key>SECOND_WANTED_KEY</key> <value>UNWANTED_VALUE</value> <!-- not wanted because it's second --> <!-- nonexistent <key>THIRD_WANTED_KEY</key> --> <!-- nonexistent <value>THIRD_WANTED_VALUE</value> --> <!-- more stuff--> </list> I want to extract the values of a set of known "wanted keys" in a robust fashion, i.e. if SECOND_WANTED_KEY appears twice, I only want SECOND_WANTED_VALUE, not UNWANTED_VALUE. Additionally, THIRD_WANTED_KEY may or may not appear, so the query should be able to handle that as well. I can assume that FIRST_WANTED_KEY will appear before other keys, but can't assume anything about the order of the other keys - if a key appears twice, its values aren't important, I only want the first one. An anonymous data type consisting of strings is fine. My attempt has centered around something along these lines: var z = from y in x.Descendants() where y.Value == "FIRST_WANTED_KEY" select new { first_wanted_value = ((XElement)y.NextNode).Value, //... } My question is what should that ... be? I've tried, for instance, (ugly, I know) second_wanted_value = ((XElement)y.ElementsAfterSelf() .Where(w => w.Value=="SECOND_WANTED_KEY") .FirstOrDefault().NextNode).Value which should hopefully allow the key to be anywhere, or non-existent, but that hasn't worked out, since .NextNode on a null XElement doesn't seem to work. I've also tried to add in a .Select(t => { if (t==null) return new XElement("SECOND_WANTED_KEY",""); else return t; }) clause in after the where, but that hasn't worked either. I'm open to suggestions, (constructive) criticism, links, references, or suggestions of phrases to Google for, etc. I've done a fair share of Googling and checking around S.O., so any help would be appreciated. Thanks!

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  • Eclipselink read complex oject model in an ordered way

    - by Raven
    Hi, I need to read a complex model in an ordered way with eclipselink. The order is mandantory because it is a huge database and I want to have an output of a small portion of the database in a jface tableview. Trying to reorder it in the loading/quering thread takes too long and ordering it in the LabelProvider blocks the UI thread too much time, so I thought if Eclipselink could be used that way, that the database will order it, it might give me the performance I need. Unfortunately the object model can not be changed :-( The model is something like: @SuppressWarnings("serial") @Entity public class Thing implements Serializable { @Id @GeneratedValue(strategy = GenerationType.TABLE) private int id; private String name; @OneToMany(cascade=CascadeType.ALL) @PrivateOwned private List<Property> properties = new ArrayList<Property>(); ... // getter and setter following here } public class Property implements Serializable { @Id @GeneratedValue(strategy = GenerationType.TABLE) private int id; @OneToOne private Item item; private String value; ... // getter and setter following here } public class Item implements Serializable { @Id @GeneratedValue(strategy = GenerationType.TABLE) private int id; private String name; .... // getter and setter following here } // Code end In the table view the y-axis is more or less created with the query Query q = em.createQuery("SELECT m FROM Thing m ORDER BY m.name ASC"); using the "name" attribute from the Thing objects as label. In the table view the x-axis is more or less created with the query Query q = em.createQuery("SELECT m FROM Item m ORDER BY m.name ASC"); using the "name" attribute from the Item objects as label. Each cell has the value Things.getProperties().get[x].getValue() Unfortunately the list "properties" is not ordered, so the combination of cell value and x-axis column number (x) is not necessarily correct. Therefore I need to order the list "properties" in the same way as I ordered the labeling of the x-axis. And exactly this is the thing I dont know how it is done. So querying for the Thing objects should return the list "properties" "ORDER BY name ASC" but of the "Item"s objects. My ideas are something like having a query with two JOINs. Joing Things with Property and with Item but somehow I was unable to get it to work yet. Thank you for your help and your ideas to solve this riddle.

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  • Simulating MySQL's ORDER BY FIELD() in Postgresql

    - by Peer Allan
    Hello all, Just trying out Postgresql for the first time, coming from MySQL. In our Rails application we have a couple of locations with SQL like so: SELECT * FROM `currency_codes` ORDER BY FIELD(code, 'GBP', 'EUR', 'BBD', 'AUD', 'CAD', 'USD') DESC, name ASC It didn't take long to discover that this is not supported/allowed in Postgresql. Does anyone know how to simulate this behaviour in Postgres or do we have to pull to sorting out into the code? Thanks Peer

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  • Selecting a user-defined scalar function that takes as a parameter another field

    - by ghills
    I have a table a with a list of id's, and a user-defined function foo(id) that takes the id and returns a VARCHAR(20). What I am trying to do is: SELECT id, foo(id) AS 'text field' FROM a However, instead of calling the function for each ID number, like I desired, the text comes back the same for every row. I have tested the foo() function manually with the returned ID's and it does not have that problem, so I realize I must not understand something about the evaluation of the query.

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  • set radio button in jquery dialog

    - by RememberME
    I have the following if/else on another form and it works perfectly. I've now put it on a form which shows as a jquery dialog. Every alert along the way shows the correct assignment, but when the dialog opens, neither button is selected. $("#create-company").click(function() { alert($('#primary_company').val().length); if ($('#primary_company').val().length > 0) { alert("if secondary"); $('#secondary').attr('checked', 'true'); var id = $("input:radio[name='companyType']:checked").attr('id'); alert(id); } else { alert("else primary"); $('#primary').attr('checked', 'true'); $('#sec').hide(); var id = $("input:radio[name='companyType']:checked").attr('id'); alert(id); } var id = $("input:radio[name='companyType']:checked").attr('id'); alert(id); $('#popupCreateCompany').dialog('open'); }); Dialog: $('#popupCreateCompany').dialog( { autoOpen: false, modal: true, buttons: { 'Add': function() { var dialog = $(this); var form = dialog.find('input:text, select'); $.post('/company/post', $(form).serialize(), function(data) { if (data.Result == "success") { var id = $("input:radio[name='companyType']:checked").attr('id'); if (id == "primary") { $('#company').append($('<option></option>').val(data.company_id).html(data.company_name).attr("selected", true)); $('#primary_company').append($('<option></option>').val(data.company_id).html(data.company_name).attr("selected", true)); $('#company_id').append($('<option></option>').val(data.company_id).html(data.company_name).attr("selected", true)); } else { $('#company_id').append($('<option></option>').val(data.company_id).html(data.company_name)); } dialog.dialog('close'); alert("Company " + data.company_name + " successfully added."); } else { alert(data.Result); }; }, "json") }, 'Cancel': function() { $(this).dialog('close'); } } }); Radio buttons: <label>Company Type:</label> <label for="primary"><input onclick="javascript: $('#sec').hide('slow');$('#primary_company').find('option:first').attr('selected','selected');" type="radio" name="companyType" id="primary" />Primary</label> <label for="secondary"><input onclick="javascript: $('#sec').show('slow');" type="radio" name="companyType" id="secondary" />Subsidiary</label> <div id="sec"> <fieldset> <label for="primary_company">Primary Company:</label> <%= Html.DropDownList("primary_company", Model.SelectPrimaryCompanies, "** Select Primary Company **") %> </fieldset> </div>

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  • How to use second level cache for lazy loaded collections in Hibernate?

    - by Chandru
    Let's say I have two entities, Employee and Skill. Every employee has a set of skills. Now when I load the skills lazily through the Employee instances the cache is not used for skills in different instances of Employee. Let's Consider the following data set. Employee - 1 : Java, PHP Employee - 2 : Java, PHP When I load Employee - 2 after Employee - 1, I do not want hibernate to hit the database to get the skills and instead use the Skill instances already available in cache. Is this possible? If so how? Hibernate Configuration <session-factory> <property name="hibernate.connection.driver_class">com.mysql.jdbc.Driver</property> <property name="hibernate.connection.password">pass</property> <property name="hibernate.connection.url">jdbc:mysql://localhost/cache</property> <property name="hibernate.connection.username">root</property> <property name="hibernate.dialect">org.hibernate.dialect.MySQLInnoDBDialect</property> <property name="hibernate.cache.use_second_level_cache">true</property> <property name="hibernate.cache.use_query_cache">true</property> <property name="hibernate.cache.provider_class">net.sf.ehcache.hibernate.EhCacheProvider</property> <property name="hibernate.hbm2ddl.auto">update</property> <property name="hibernate.show_sql">true</property> <mapping class="org.cache.models.Employee" /> <mapping class="org.cache.models.Skill" /> </session-factory> The Entities with imports, getters and setters Removed @Entity @Table(name = "employee") @Cache(usage = CacheConcurrencyStrategy.READ_WRITE) public class Employee { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) private int id; private String name; public Employee() { } @ManyToMany @JoinTable(name = "employee_skills", joinColumns = @JoinColumn(name = "employee_id"), inverseJoinColumns = @JoinColumn(name = "skill_id")) @Cache(usage = CacheConcurrencyStrategy.READ_WRITE) private List<Skill> skills; } @Entity @Table(name = "skill") @Cache(usage = CacheConcurrencyStrategy.READ_WRITE) public class Skill { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) private int id; private String name; } SQL for Loading the Second Employee and his Skills Hibernate: select employee0_.id as id0_0_, employee0_.name as name0_0_ from employee employee0_ where employee0_.id=? Hibernate: select skills0_.employee_id as employee1_1_, skills0_.skill_id as skill2_1_, skill1_.id as id1_0_, skill1_.name as name1_0_ from employee_skills skills0_ left outer join skill skill1_ on skills0_.skill_id=skill1_.id where skills0_.employee_id=? In that I specifically want to avoid the second query as the first one is unavoidable anyway.

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  • Show the focused div only bookmarklet

    - by ideotop
    I'm searching to select a text from a div, then click on a bookmarklet that remove all html parts in the body except the div where the text is selected maybe jquery can help with something like : javascript:var%20s=document.createElement('script');s.setAttribute('src',%20'http://jquery.com/src/jquery-latest.js');document.body.appendChild(s);s.onload=function(){/*the code*/};void(s);

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  • Help writing database queries for derby?

    - by outsyncof
    I have a database containing multiple tables (Person, Parents, etc) Person table has certain attributes particularly ssn, countryofbirth and currentcountry. Parents table has ssn, and fathersbirthcountry I'm trying to output the SSNs of all people who have the same countryofbirth as their fathersbirthcountry and also have same currentcountry as fathersbirthcountry. SELECT Person.ssn FROM Person, Parents WHERE fathersbirthcountry = countryofbirth AND currentcountry = fathersbirthcountry; the above doesn't seem to be working, could anyone please help me out?

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  • jsTree Selecte most nested node

    - by niao
    Greetings, I just started to use jsTree and I have a question for you guys. How can I select only the most nested node - the node which doesn't have any children. additionally, when this node is selected, I would like to submit my form which contains the jsTree. How can I then access selected node?

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  • Fixing Unicode Oops

    - by Mez
    It seems that we have managed to insert into our database 2 unicode characters for each of the unicode characters we want, For example, for the unicde char 0x3CBC, we've inserted the unicode equivalents for each of it's components (0xC383 AND 0xC2BC) Can anyone think of a simple solution for fixing this? I've come up with something like SELECT replace(name, CONCAT(0xC3,0x83,0xc2,0xbc), CONCAT(0xc3,0xbc)) FROM lang For the above, but don't want to have to do this for every unicode character!

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  • Problem connecting to postgres with Kohana 3 database module on OS X Snow Leopard

    - by Bart Gottschalk
    Environment: Mac OS X 10.6 Snow Leopard PHP 5.3 Kohana 3.0.4 When I try to configure and use a connection to a postgresql database on localhost I get the following error: ErrorException [ Warning ]: mysql_connect(): [2002] No such file or directory (trying to connect via unix:///var/mysql/mysql.sock) Here is the configuration of the database in /modules/database/config/database.php (note the third instance named 'pgsqltest') return array ( 'default' => array ( 'type' => 'mysql', 'connection' => array( /** * The following options are available for MySQL: * * string hostname * string username * string password * boolean persistent * string database * * Ports and sockets may be appended to the hostname. */ 'hostname' => 'localhost', 'username' => FALSE, 'password' => FALSE, 'persistent' => FALSE, 'database' => 'kohana', ), 'table_prefix' => '', 'charset' => 'utf8', 'caching' => FALSE, 'profiling' => TRUE, ), 'alternate' => array( 'type' => 'pdo', 'connection' => array( /** * The following options are available for PDO: * * string dsn * string username * string password * boolean persistent * string identifier */ 'dsn' => 'mysql:host=localhost;dbname=kohana', 'username' => 'root', 'password' => 'r00tdb', 'persistent' => FALSE, ), 'table_prefix' => '', 'charset' => 'utf8', 'caching' => FALSE, 'profiling' => TRUE, ), 'pgsqltest' => array( 'type' => 'pdo', 'connection' => array( /** * The following options are available for PDO: * * string dsn * string username * string password * boolean persistent * string identifier */ 'dsn' => 'mysql:host=localhost;dbname=pgsqltest', 'username' => 'postgres', 'password' => 'dev1234', 'persistent' => FALSE, ), 'table_prefix' => '', 'charset' => 'utf8', 'caching' => FALSE, 'profiling' => TRUE, ), ); And here is the code to create the database instance, create a query and execute the query: $pgsqltest_db = Database::instance('pgsqltest'); $query = DB::query(Database::SELECT, 'SELECT * FROM test')->execute(); I'm continuing to research a solution for this error but thought I'd ask to see if someone else has already found a solution. Any ideas are welcome. One other note is that I know my build of PHP can access this postgresql db since I'm able to manage the db using phpPgAdmin. But I have yet to determine what phpPgAdmin is doing differently to connect to the db than what Kohana 3 is attempting. Bart

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