Finding the left-most and right-most points of a list. std::find_if the right way to go?
- by Tom
Hi,
I have a list of Point objects, (each one with x,y properties) and would like to find the left-most and right-most points. I've been trying to do it with find_if, but i'm not sure its the way to go, because i can't seem to pass a comparator instance. Is find_if the way to go? Seems not. So, is there an algorithm in <algorithm> to achieve this?
Thanks in advance.
#include <iostream>
#include <list>
#include <algorithm>
using namespace std;
typedef struct Point{
float x;
float y;
} Point;
bool left(Point& p1,Point& p2)
{
return p1.x < p2.x;
}
int main(){
Point p1 ={-1,0};
Point p2 ={1,0};
Point p3 ={5,0};
Point p4 ={7,0};
list <Point> points;
points.push_back(p1);
points.push_back(p2);
points.push_back(p3);
points.push_back(p4);
//Should return an interator to p1.
find_if(points.begin(),points.end(),left);
return 0;
}
