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• Creating Objects

  - by user1424667

  I have a general coding standard question. Is it bad practice to initialize and create an object in multiple methods depending on the outcome of a users choice. So for example if the user quits a poker game, create the poker hand with the cards the user has received, even if < 5, and if the user played till the end create object to show completed hand to show outcome of the game. The key is that the object will only be created once in actuality, there are just different paths and parameters is will receive depending on if the user folded, or played on to the showdown.

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• How to change the state of a singleton in runtime

  - by user34401

  Consider I am going to write a simple file based logger AppLogger to be used in my apps, ideally it should be a singleton so I can call it via public class AppLogger { public static String file = ".."; public void logToFile() { // Write to file } public static log(String s) { AppLogger.getInstance().logToFile(s); } } And to use it AppLogger::log("This is a log statement"); The problem is, what is the best time I should provide the value of file since it is a just a singleton? Or how to refactor the above code (or skip using singleton) so I can customize the log file path? (Assume I don't need to write to multiple at the same time) p.s. I know I can use library e.g. log4j, but consider it is just a design question, how to refactor the code above?

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• How can I be certain that my code is flawless? [duplicate]

  - by David

  This question already has an answer here: Theoretically bug-free programs 5 answers I have just completed an exercise from my textbook which wanted me to write a program to check if a number is prime or not. I have tested it and seems to work fine, but how can I be certain that it will work for every prime number? public boolean isPrime(int n) { int divisor = 2; int limit = n-1 ; if (n == 2) { return true; } else { int mod = 0; while (divisor <= limit) { mod = n % divisor; if (mod == 0) { return false; } divisor++; } if (mod > 0) { return true; } } return false; } Note that this question is not a duplicate of Theoretically Bug Free Programs because that question asks about whether one can write bug free programs in the face of the the limitative results such as Turing's proof of the incomputability of halting, Rice's theorem and Godel's incompleteness theorems. This question asks how a program can be shown to be bug free.

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• Climbing boxes in box2D

  - by Rothens

  I've just stepped into the world of Box2D with libgdx. I've already made a stack of boxes: They are dropped randomly ontop of each other. What I'd like to achieve is to make a character, that could freely climb on the boxes, (He can grip on the boxes anywhere, not just on the side/top of a box) but his weight affects the stack as well, so the boxes could fall down. My google-fu failed me... Is there any way to make this possible?

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• Having trouble with pathfinding

  - by user2144536

  I'm trying to implement pathfinding in a game I'm programming using this method. I'm implementing it with recursion but some of the values after the immediate circle of tiles around the player are way off. For some reason I cannot find the problem with it. This is a screen cap of the problem: The pathfinding values are displayed in the center of every tile. Clipped blocks are displayed with the value of 'c' because the values were too high and were covering up the next value. The red circle is the first value that is incorrect. The code below is the recursive method. //tileX is the coordinates of the current tile, val is the current pathfinding value, used[][] is a boolean //array to keep track of which tiles' values have already been assigned public void pathFind(int tileX, int tileY, int val, boolean[][] used) { //increment pathfinding value int curVal = val + 1; //set current tile to true if it hasn't been already used[tileX][tileY] = true; //booleans to know which tiles the recursive call needs to be used on boolean topLeftUsed = false, topUsed = false, topRightUsed = false, leftUsed = false, rightUsed = false, botomLeftUsed = false, botomUsed = false, botomRightUsed = false; //set value of top left tile if necessary if(tileX - 1 >= 0 && tileY - 1 >= 0) { //isClipped(int x, int y) returns true if the coordinates givin are in a tile that can't be walked through (IE walls) //occupied[][] is an array that keeps track of which tiles have an enemy in them // //if the tile is not clipped and not occupied set the pathfinding value if(isClipped((tileX - 1) * 50 + 25, (tileY - 1) * 50 + 25) == false && occupied[tileX - 1][tileY - 1] == false && !(used[tileX - 1][tileY - 1])) { pathFindingValues[tileX - 1][tileY - 1] = curVal; topLeftUsed = true; used[tileX - 1][tileY - 1] = true; } //if it is occupied set it to an arbitrary high number so enemies find alternate routes if the best is clogged if(occupied[tileX - 1][tileY - 1] == true) pathFindingValues[tileX - 1][tileY - 1] = 1000000000; //if it is clipped set it to an arbitrary higher number so enemies don't travel through walls if(isClipped((tileX - 1) * 50 + 25, (tileY - 1) * 50 + 25) == true) pathFindingValues[tileX - 1][tileY - 1] = 2000000000; } //top middle if(tileY - 1 >= 0 ) { if(isClipped(tileX * 50 + 25, (tileY - 1) * 50 + 25) == false && occupied[tileX][tileY - 1] == false && !(used[tileX][tileY - 1])) { pathFindingValues[tileX][tileY - 1] = curVal; topUsed = true; used[tileX][tileY - 1] = true; } if(occupied[tileX][tileY - 1] == true) pathFindingValues[tileX][tileY - 1] = 1000000000; if(isClipped(tileX * 50 + 25, (tileY - 1) * 50 + 25) == true) pathFindingValues[tileX][tileY - 1] = 2000000000; } //top right if(tileX + 1 <= used.length && tileY - 1 >= 0) { if(isClipped((tileX + 1) * 50 + 25, (tileY - 1) * 50 + 25) == false && occupied[tileX + 1][tileY - 1] == false && !(used[tileX + 1][tileY - 1])) { pathFindingValues[tileX + 1][tileY - 1] = curVal; topRightUsed = true; used[tileX + 1][tileY - 1] = true; } if(occupied[tileX + 1][tileY - 1] == true) pathFindingValues[tileX + 1][tileY - 1] = 1000000000; if(isClipped((tileX + 1) * 50 + 25, (tileY - 1) * 50 + 25) == true) pathFindingValues[tileX + 1][tileY - 1] = 2000000000; } //left if(tileX - 1 >= 0) { if(isClipped((tileX - 1) * 50 + 25, (tileY) * 50 + 25) == false && occupied[tileX - 1][tileY] == false && !(used[tileX - 1][tileY])) { pathFindingValues[tileX - 1][tileY] = curVal; leftUsed = true; used[tileX - 1][tileY] = true; } if(occupied[tileX - 1][tileY] == true) pathFindingValues[tileX - 1][tileY] = 1000000000; if(isClipped((tileX - 1) * 50 + 25, (tileY) * 50 + 25) == true) pathFindingValues[tileX - 1][tileY] = 2000000000; } //right if(tileX + 1 <= used.length) { if(isClipped((tileX + 1) * 50 + 25, (tileY) * 50 + 25) == false && occupied[tileX + 1][tileY] == false && !(used[tileX + 1][tileY])) { pathFindingValues[tileX + 1][tileY] = curVal; rightUsed = true; used[tileX + 1][tileY] = true; } if(occupied[tileX + 1][tileY] == true) pathFindingValues[tileX + 1][tileY] = 1000000000; if(isClipped((tileX + 1) * 50 + 25, (tileY) * 50 + 25) == true) pathFindingValues[tileX + 1][tileY] = 2000000000; } //botom left if(tileX - 1 >= 0 && tileY + 1 <= used[0].length) { if(isClipped((tileX - 1) * 50 + 25, (tileY + 1) * 50 + 25) == false && occupied[tileX - 1][tileY + 1] == false && !(used[tileX - 1][tileY + 1])) { pathFindingValues[tileX - 1][tileY + 1] = curVal; botomLeftUsed = true; used[tileX - 1][tileY + 1] = true; } if(occupied[tileX - 1][tileY + 1] == true) pathFindingValues[tileX - 1][tileY + 1] = 1000000000; if(isClipped((tileX - 1) * 50 + 25, (tileY + 1) * 50 + 25) == true) pathFindingValues[tileX - 1][tileY + 1] = 2000000000; } //botom middle if(tileY + 1 <= used[0].length) { if(isClipped((tileX) * 50 + 25, (tileY + 1) * 50 + 25) == false && occupied[tileX][tileY + 1] == false && !(used[tileX][tileY + 1])) { pathFindingValues[tileX][tileY + 1] = curVal; botomUsed = true; used[tileX][tileY + 1] = true; } if(occupied[tileX][tileY + 1] == true) pathFindingValues[tileX][tileY + 1] = 1000000000; if(isClipped((tileX) * 50 + 25, (tileY + 1) * 50 + 25) == true) pathFindingValues[tileX][tileY + 1] = 2000000000; } //botom right if(tileX + 1 <= used.length && tileY + 1 <= used[0].length) { if(isClipped((tileX + 1) * 50 + 25, (tileY + 1) * 50 + 25) == false && occupied[tileX + 1][tileY + 1] == false && !(used[tileX + 1][tileY + 1])) { pathFindingValues[tileX + 1][tileY + 1] = curVal; botomRightUsed = true; used[tileX + 1][tileY + 1] = true; } if(occupied[tileX + 1][tileY + 1] == true) pathFindingValues[tileX + 1][tileY + 1] = 1000000000; if(isClipped((tileX + 1) * 50 + 25, (tileY + 1) * 50 + 25) == true) pathFindingValues[tileX + 1][tileY + 1] = 2000000000; } //call the method on the tiles that need it if(tileX - 1 >= 0 && tileY - 1 >= 0 && topLeftUsed) pathFind(tileX - 1, tileY - 1, curVal, used); if(tileY - 1 >= 0 && topUsed) pathFind(tileX , tileY - 1, curVal, used); if(tileX + 1 <= used.length && tileY - 1 >= 0 && topRightUsed) pathFind(tileX + 1, tileY - 1, curVal, used); if(tileX - 1 >= 0 && leftUsed) pathFind(tileX - 1, tileY, curVal, used); if(tileX + 1 <= used.length && rightUsed) pathFind(tileX + 1, tileY, curVal, used); if(tileX - 1 >= 0 && tileY + 1 <= used[0].length && botomLeftUsed) pathFind(tileX - 1, tileY + 1, curVal, used); if(tileY + 1 <= used[0].length && botomUsed) pathFind(tileX, tileY + 1, curVal, used); if(tileX + 1 <= used.length && tileY + 1 <= used[0].length && botomRightUsed) pathFind(tileX + 1, tileY + 1, curVal, used); }

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• How can I perform sentiment analysis on extracted text from online sources?

  - by aniket69

  I'm working on extracting the sentiment from YouTube comments, blogs, news content, Facebook wall posts, and Twitter feeds. I'm looking for an automated way to do this: the two third-party solutions I've found have been AlchemyAPI and RapidMiner. Are these the best way to approach this project, or should I be using something else? Is there a more efficient way to approach sentiment analysis? What techniques have worked for you in a project like this?

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• Can I install an Ubuntu app from remote laptop?

  - by Voidcode

  Is their a way to push/send and ubuntu-app/deb-file to be install on my Ubuntu laptop? Usecase... Laptop 1. I find an app, I need to install! But I´am not at home. I just push it to my other laptop to be install.. Laptop 2. I am now at home. My laptop 2 view an dialog asking to install the app I send from laptop 1. Can this be do?.. SSH? Question-update Can it be done so it open Ubuntu Software Center and then laptop2-user only need to write their password and press ok? for non-tec users.. like my father...

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• More smaller maps among which player can travel

  - by davidv

  I am developing 2d game, where maps are tile based, small about 20x20 tiles and player can travel between a lot of maps (in my game rooms) like this. The maps are connected sometimes verticaly and sometimes horizontaly and together they make one big cave. Should I create a class where one 2d array holds all the maps (another 2d arrays), or is there any other way? Whats the most efficient way to create them in this class? Thank you for your help.

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• BigDecimal.floatValue versus Float.valueOf

  - by Frank

  Has anybody ever come across this: System.out.println("value of: " + Float.valueOf("3.0f")); // ok, prints 3.0 System.out.println(new BigDecimal("3.0f").floatValue()); // NumberFormatException I would argue that the lack of consistency here is a bug, where BigDecimal(String) doesn't follow the same spec as Float.valueOf() (I checked the JDK doc). I'm using a library that forces me to go through BigDecimal, but it can happen that I have to send "3.0f" there. Is there a known workaround (BigDecimal is inaccessible in a library).

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• JEE project(s) to show prospective employers

  - by My code has no bugs

  I'm studying JEE and want to get employed doing JEE work in the near future. From reading this website and various others, I now know that many employers value a github profile with code samples, projects and the like. Since I want to get hired doing JEE stuff, what kind of projects can I work on to eventually place on github showing prospective employers? Is there any (non-nonsense) project(s) which uses the JEE stack I can work on ?

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• How to store a list of Objects that might change in future?

  - by Amogh Talpallikar

  I have set of Objects of the same class which have different values of their attributes. and I need to find the best match from a function under given scenarios out of these objects. In future these objects might increase as well. Quite similar to the way we have Color class in awt. we have some static color objects in the class with diff rgb values. But in my case say, I need to chose the suitable color out of these static ones based on certain criteria. So should I keep them in an arrayList or enum or keep them as static vars as in case of Colors. because I will need to parse through all of them and decide upon the best match. so I need them in some sort of collection. But in future if I need to add another type I will have to modify the class and add another list.add(object) call for this one and then it will violate the open-close principle. How should I go about it ?

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• Android Array Lag?

  - by Mike

  I am making a platform game for Android. It is sort of a tile based game. I added bullets and enemies with AI and a bunch of tile types. I created a simple map with no Enemies. Everything was running well and smooth until I shot a bunch of bullets randomly everywhere. A couple of hundreds of bullets later, the FPS lowered. I made a test to find out if the bullets were the problem so I made another simple map with just a tile to stand on and left it for a while. Minutes later, I played around with it a bit to check if the FPS changed and it didnt. I reloaded the same map and shot a lot of bullets. Minutes later, the FPS was visibly lower even after the number of bullets were zero. Points to note: Programmed FPS is 30 Tested on a Samsung Galaxy Y and Samsung Galaxy W Any tile, enemy, bullet that is off screen is not drawn to prevent lag Bullets collide with Tiles (if they dont collide with in 450 frames, they are removed from the array) I used List bullets = new ListArray(); I used bullets.add(new Bullet(x, y, params...)); I used for(...){ if(...){ bullets.remove(i); } } Code for bullet: private void drawBullets(Canvas canvas) { for (int i = 0; i < bullets.size(); i++) { Bullet b = bullets.get(i); b.update(canvas); //updates physics if (b.t > blm) { //if the bullet is past its expiry bullets.remove(i); i--; } else { if (svx((b.x)) > 0 && svx(b.x) < width && svy((b.y)) > 0 && svy(b.y) < height) { // if bullet is not off screen b.draw(canvas); // draw the bullet } } } } I tried searching for solutions and references but I have no luck. I'm guessing that the lag has something to do with the Array and the Bullets or Classes that I've loaded? I'm not sure! Someone please help! Thanks in advance! :)

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• Move Camera Freely Around Object While Looking at It

  - by Alex_Hyzer_Kenoyer

  I've got a 3D model loaded (a planet) and I have a camera that I want to allow the user to move freely around it. I have no problem getting the camera to orbit the planet around either the x or y axis. My problem is when I try to move the camera on a different axis I have no idea how to go about doing it. I am using OpenGL on Android with the libGDX library. I want the camera to orbit the planet in the direction that the user swipes their finger on the screen.

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• Derby 10.9.1.0 released

  - by kah

  Earlier today, the release of Apache Derby 10.9.1.0 was announced. In addition to the usual chunk of bug fixes, this release includes the following new features: NATIVE authentication, a new authentication mechanism with better support for managing credentials. See this section of the developer's guide for an introduction. JDBC 4.1 escape syntax completes Derby's support for JDBC 4.1. Allow multi-column subqueries in EXISTS predicates (SQL:2003 Feature T501, Enhanced EXISTS predicate) to support auto-generated SQL from some persistence frameworks. Download it now and try it out!

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• Use decorator and factory together to extend objects?

  - by TheClue

  I'm new to OOP and design pattern. I've a simple app that handles the generation of Tables, Columns (that belong to Table), Rows (that belong to Column) and Values (that belong to Rows). Each of these object can have a collection of Property, which is in turn defined as an enum. They are all interfaces: I used factories to get concrete instances of these products, depending on circumnstances. Now I'm facing the problem of extending these classes. Let's say I need another product called "SpecialTable" which in turn has some special properties or new methods like 'getSomethingSpecial' or an extended set of Property. The only way is to extend/specialize all my elements (ie. build a SpecialTableFactory, a SpecialTable interface and a SpecialTableImpl concrete)? What to do if, let's say, I plan to use standard methods like addRow(Column column, String name) that doesn't need to be specialized? I don't like the idea to inherit factories and interfaces, but since SpecialTable has more methods than Table i guess it cannot share the same factory. Am I wrong? Another question: if I need to define product properties at run time (a Table that is upgraded to SpecialTable at runtime), i guess i should use a decorator. Is it possible (and how) to combine both factory and decorator design? Is it better to use a State or Strategy pattern, instead?

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• How do I implement a "sliding out of / into" effect on a settings menu similar to that in Angry Birds?

  - by VictorB

  I'm trying to implement a settings menu component similar to that in Angry Birds - a button control that makes an options menu slide out of it and back into it when clicked on. I use scene2d.ui to build the UI components: a Button in a Table to implement the button control, a Table to implement the options menu, and a Stack to lay these out one on top of the other and at this moment I have the following behavior: When the user hits the button control for the first time, then the alpha of the table component is set to 1; When the user hits the button control the second time, then the alpha of the table component is set to 0; And so on. Any ideas how I can get the sliding out of and into effect on user clicks with libgdx? Similar to what Angry Birds provides. Maybe using the TweenEngine, actions, interpolations, combinations of these? Thanks in advance.

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• How to choose between Tell don't Ask and Command Query Separation?

  - by Dakotah North

  The principle Tell Don't Ask says: you should endeavor to tell objects what you want them to do; do not ask them questions about their state, make a decision, and then tell them what to do. The problem is that, as the caller, you should not be making decisions based on the state of the called object that result in you then changing the state of the object. The logic you are implementing is probably the called object’s responsibility, not yours. For you to make decisions outside the object violates its encapsulation. A simple example of "Tell, don't Ask" is Widget w = ...; if (w.getParent() != null) { Panel parent = w.getParent(); parent.remove(w); } and the tell version is ... Widget w = ...; w.removeFromParent(); But what if I need to know the result from the removeFromParent method? My first reaction was just to change the removeFromParent to return a boolean denoting if the parent was removed or not. But then I came across Command Query Separation Pattern which says NOT to do this. It states that every method should either be a command that performs an action, or a query that returns data to the caller, but not both. In other words, asking a question should not change the answer. More formally, methods should return a value only if they are referentially transparent and hence possess no side effects. Are these two really at odds with each other and how do I choose between the two? Do I go with the Pragmatic Programmer or Bertrand Meyer on this?

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• how to avoid or minimise use of check/conditional statement?

  - by Muneeb Nasir

  I have scenario, where i got stream and i need to check for some value. if i got my any new value i have to store it in any of data structure. well it seems very easy, i can place conditional statement if-else or can use contain method of set/map to check either received is new or not. but the problem is checking will effect my application performance, in stream i'll receive hundreds for value in second, if i start checking each and every value i received than for sure it effect performance. Any body can suggest me any mechanism or algorithm that solve my issue. either by bypassing checks or atleast minimize them?

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• which is better performance, using a disposable local variable or reusing a global one?

  - by petervaz

  This is for an android game. Suppose I have a function that is called several times for second and do some calculations involving an arraylist (or any other complex objects for what matter). Which approach would be preffered? local: private void doStuff(){ ArrayList<Type> XList = new ArrayList<Type>(); // do stuff with list } global: private ArrayList<Type> XList = new ArrayList<Type>(); private void doStuff(){ XList.clear(); // do stuff with list }

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• New Interoperability Solutions for SQL Server 2012

  - by The Official Microsoft IIS Site

  I am excited to share some great news about how we are opening up the SQL Server data platform even further with expanded interoperability support through new tools that allow customers to modernize their infrastructure while maximizing existing investments and extending virtually any data anywhere. The SQL Server team today introduced several tools that enable interoperability with SQL Server 2012. These tools help developers to build secure, highly available and high performance applications for...(read more)

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• Bukkit send a custom placed name plate?

  - by HcgRandon

  Hello i have been working on a part of my plugin that has waypoints allowing the user to create delete etc. I got to thinking after using and seeing a couple of the disguse plugins. That maybe i could create a command toggle that would show the user where the waypoints they have are! I know how to do all of this i just have no idea how to display a nameplate to the client. I know its possible because disguisecraft does it i tried looking though their code but couldent find much... I belive to get this effect i need to send packets to the client if someone can direct me to a list of bukkit packets or even a solution to sending the client a custom located nameplate that would be fantastic! Thanks in advanced.

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• Do threads delete themselves?

  - by Prog

  Let's say I was working on a Swing application. Most of it is run on the EDT using SwingUtilities.invokeLater() inside the main method, because I heard (please correct me if I'm wrong) that that's what you need to do with Swing. However, some parts of it shouldn't run on the EDT. These parts are parts that take long to complete (I assume that this is because long tasks on the EDT will interfere with GUI stuff the EDT should be doing, and thus these kinds of tasks should be run on parallel, on a different thread. Is this assumption correct?) To do this, when I need to perform a task that takes long to complete and thus can't be run on the EDT like the rest of the program, I create a new thread and run that task inside it. My question is: When the run() method of that new thread finishes, aka the thread finished it's job. Does it delete itself? Or does it keep existing in the memory?

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• Common Substring of two strings

  - by Chander Shivdasani

  This particular interview-question stumped me: Given two Strings S1 and S2. Find the longest Substring which is a Prefix of S1 and suffix of S2. Through Google, I came across the following solution, but didnt quite understand what it was doing. public String findLongestSubstring(String s1, String s2) { List<Integer> occurs = new ArrayList<>(); for (int i = 0; i < s1.length(); i++) { if (s1.charAt(i) == s2.charAt(s2.length()-1)) { occurs.add(i); } } Collections.reverse(occurs); for(int index : occurs) { boolean equals = true; for(int i = index; i >= 0; i--) { if (s1.charAt(index-i) != s2.charAt(s2.length() - i - 1)) { equals = false; break; } } if(equals) { return s1.substring(0,index+1); } } return null; }

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• How to run around another football player

  - by Lumis

  I have finished a simple 2D one-on-one indoor football Android game. The thing that it seemed so simple to me, a human being, turned out to be difficult for a computer: how to go around the opponent … At the moment the game logic of the computer player is that if it hits into the human player will step back few points on the pixel greed and then try again to go towards the ball. The problem is if the human player is in-between then the computer player will oscillate in one place, which does not look very nice and the human opponent can use this weakness to control the game. You can see this in the photo – at the moment the computer will go along the red line indefinitely. I tried few ideas but it proved not easy to do it when both the human player and the ball are constantly moving so at each step computer would change directions and “oscillate” again. Once when the computer player reaches the ball it will kick it with certain amount of random strength and direction towards the human’s goal. The question here is how to formulate the logic of going around the ever moving human opponent and how to translate it into the co-ordinate system and frame by frame animation… any suggestions welcome.

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• Multidimensional multiple-choice knapsack problem: find a feasible solution

  - by Onheiron

  My assignment is to use local search heuristics to solve the Multidimensional multiple-choice knapsack problem, but to do so I first need to find a feasible solution to start with. Here is an example problem with what I tried so far. Problem R1 R2 R3 RESOUCES : 8 8 8 GROUPS: G1: 11.0 3 2 2 12.0 1 1 3 G2: 20.0 1 1 3 5.0 2 3 2 G3: 10.0 2 2 3 30.0 1 1 3 Sorting strategies To find a starting feasible solution for my local search I decided to ignore maximization of gains and just try to fit the resources requirements. I decided to sort the choices (strategies) in each group by comparing their "distance" from the multidimensional space origin, thus calculating SQRT(R1^2 + R2^2 + ... + RN^2). I felt like this was a keen solution as it somehow privileged those choices with resouce usages closer to each other (e.g. R1:2 R2:2 R3:2 < R1:1 R2:2 R3:3) even if the total sum is the same. Doing so and selecting the best choice from each group proved sufficent to find a feasible solution for many[30] different benchmark problems, but of course I knew it was just luck. So I came up with the problem presented above which sorts like this: R1 R2 R3 RESOUCES : 8 8 8 GROUPS: G1: 12.0 1 1 3 < select this 11.0 3 2 2 G2: 20.0 1 1 3 < select this 5.0 2 3 2 G3: 30.0 1 1 3 < select this 10.0 2 2 3 And it is not feasible because the resources consmption is R1:3, R2:3, R3:9. The easy solution is to pick one of the second best choices in group 1 or 2, so I'll need some kind of iteration (local search[?]) to find the starting feasible solution for my local search solution. Here are the options I came up with Option 1: iterate choices I tried to find a way to iterate all the choices with a specific order, something like G1 G2 G3 1 1 1 2 1 1 1 2 1 1 1 2 2 2 1 ... believeng that feasible solutions won't be that far away from the unfeasible one I start with and thus the number of iterations will keep quite low. Does this make any sense? If yes, how can I iterate the choices (grouped combinations) of each group keeping "as near as possibile" to the previous iteration? Option 2: Change the comparation term I tried to think how to find a better variable to sort the choices on. I thought at a measure of how "precious" a resource is based on supply and demand, so that an higer demand of a more precious resource will push you down the list, but this didn't help at all. Also I thought there probably isn't gonna be such a comparsion variable which assures me a feasible solution at first strike. I there such a variable? If not, is there a better sorting criteria anyways? Option 3: implement any known sub-optimal fast solving algorithm Unfortunately I could not find any of such algorithms online. Any suggestion?

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