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  • Cannot Resize DIV to anything smaller than maximum width

    - by MxmastaMills
    Quick CSS Question. I cannot seem to figure out a very simple CSS/HTML problem. Here's a JSFiddle. http://jsfiddle.net/BmM6t/ Basically, these two divs are not resizing to anything less than 100% width: <div id="main_pic" class="main_div"> THIS IS WHERE THE MAIN PIC WILL GO. </div> <div id="signin" class="main_div"> SIGN IN TO THE SITE! <form> <label for="name">EMAIL/USERNAME:</label> <input type="text" name="name" id="name"> <label for="email">PASSWORD:</label> <input type="text" name="email" id="email"> <br /> <input type="submit" value="Let's Play!"> </form> </div> You'll see that the two divs with class main_div actually take up the entire width of the screen for some reason (you can see that if you inspect the element) even though their widths are clearly written. When you try to change the width of one of the main_div's it changes the width but if you inspect the element, it just changes the width of the object and adds padding around it to make sure it still takes up the entire width of the screen. I'm sure it's some little error I've made but I can't find it. Thanks for the help!

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  • Get parent function

    - by Morgoth
    Is there a way to find what function called the current function? So for example: def first(): second() def second(): # print out here what function called this one Any ideas?

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  • Setting Android webview initialScale prevents proper zooming

    - by Ryan
    Need: I want a webview to automatically be sized to fit the width of that particular page. I have Googled this and found several different suggestions. Most of them work. But then each of them effects zooming in / zooming out. What I'm looking for is a solution that accomplishes both. The webview is initially set to fill the screen, but then it allows the user to zoom in (with pinching) and zoom out. What I've Tried: mainView.getSettings().setLoadWithOverviewMode(true); mainView.getSettings().setUseWideViewPort(false); mainView.setScrollBarStyle(WebView.SCROLLBARS_OUTSIDE_OVERLAY); mainView.getSettings().setBuiltInZoomControls(true); mainView.getSettings().setSupportZoom(true); I have also tried setting mainView.setInitialScale(various percentages) Again, I have tried these in different orders, including some, not including others. Currently, if I use the above code and setInitialScale(65), it loads initially fine but then once you zoom in, you cannot zoom all the way back out. Does anyone know of the best practice to set initial scale to fit screen but fully allow zooming out and in? Why I Need It: I'm using a ViewFlipper in my Android app to load several webviews simultaneously. I have a touch sensor that allows sliding from left to right to switch between different webviews. The practical purpose of this is to show a grocery store's ads and allow the user to slide from page to page. The problem is that the API feed I'm using basically only allows me to load a URL for each page. So I have to use webviews.

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  • recursion resulting in extra unwanted data

    - by spacerace
    I'm writing a module to handle dice rolling. Given x die of y sides, I'm trying to come up with a list of all potential roll combinations. This code assumes 3 die, each with 3 sides labeled 1, 2, and 3. (I realize I'm using "magic numbers" but this is just an attempt to simplify and get the base code working.) int[] set = { 1, 1, 1 }; list = diceroll.recurse(0,0, list, set); ... public ArrayList<Integer> recurse(int index, int i, ArrayList<Integer> list, int[] set){ if(index < 3){ // System.out.print("\n(looping on "+index+")\n"); for(int k=1;k<=3;k++){ // System.out.print("setting i"+index+" to "+k+" "); set[index] = k; dump(set); recurse(index+1, i, list, set); } } return list; } (dump() is a simple method to just display the contents of list[]. The variable i is not used at the moment.) What I'm attempting to do is increment a list[index] by one, stepping through the entire length of the list and incrementing as I go. This is my "best attempt" code. Here is the output: Bold output is what I'm looking for. I can't figure out how to get rid of the rest. (This is assuming three dice, each with 3 sides. Using recursion so I can scale it up to any x dice with y sides.) [1][1][1] [1][1][1] [1][1][1] [1][1][2] [1][1][3] [1][2][3] [1][2][1] [1][2][2] [1][2][3] [1][3][3] [1][3][1] [1][3][2] [1][3][3] [2][3][3] [2][1][3] [2][1][1] [2][1][2] [2][1][3] [2][2][3] [2][2][1] [2][2][2] [2][2][3] [2][3][3] [2][3][1] [2][3][2] [2][3][3] [3][3][3] [3][1][3] [3][1][1] [3][1][2] [3][1][3] [3][2][3] [3][2][1] [3][2][2] [3][2][3] [3][3][3] [3][3][1] [3][3][2] [3][3][3] I apologize for the formatting, best I could come up with. Any help would be greatly appreciated. (This method was actually stemmed to use the data for something quite trivial, but has turned into a personal challenge. :) edit: If there is another approach to solving this problem I'd be all ears, but I'd also like to solve my current problem and successfully use recursion for something useful.

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  • how to do this problem?

    - by Sachin Tendulkar
    Write an iterative program that finds the largest number of McNuggets that cannot be bought in exact quantity. Your program should print the answer in the following format (where the correct number is provided in place of n): "Largest number of McNuggets that cannot be bought in exact quantity: n"

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  • Printing values of all fields in C++ structure

    - by Zhinkaas
    Say a simple structure struct abc { int a; char b; } I got some value in a variable defined as its structure and now I want to print below a = [some value] b = [some character] What is the best way to achieve this for an arbitrary structure without having to write a dump...(...) function for each of the structure I encounter?

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  • How to display a page in my browser with python code that is run locally on my computer with "GAE" S

    - by brilliant
    When I run this code on my computer with the help of "Google App Engine SDK", it displays (in my browser) the HTML code of the Google home page: from google.appengine.api import urlfetch url = "http://www.google.com/" result = urlfetch.fetch(url) print result.content How can I make it display the page itself? I mean I want to see that page in my browser the way it would normally be seen by any user of the internet.

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  • Output error in comparing characters from two strings

    - by Andrew Martin
    I'm stuck with my a piece of code I'm creating. My IDE is Eclipse and when I use its debugging feature, to trace what's happening on each line, it outputs perfectly. However, when I click the "run" project, it just outputs a blank screen: public static void compareInterests(Client[] clientDetails) { int interests = 0; for (int p = 0; p < numberOfClients; p++) { for (int q = 0; q < numberOfClients; q++) { String a = clientDetails[p].getClientInterests(); String b = clientDetails[q].getClientInterests(); int count = 0; while (count < a.length()) { if (a.charAt(count) == b.charAt(count)) interests++; count++; } if ((interests >= 3) && (clientDetails[p].getClientName() != clientDetails[q].getClientName())) System.out.print (clientDetails[p].getClientName() + " is compatible with " + clientDetails[q].getClientName()); interests = 0; } } } The code is designed to import an object array which contains information on a client's name and a client's interests. The client's interests are stored in the format "01010", where each 1 means they are interested in that activity, each 0 means they are not. My code compares each character of every client's string with every other client's string and outputs the results for all client's that don't have the same name and have three or more interests in common. When I run this code through Java's debugger, it outputs fine - but when I click run project or compile, I just get a blank screen. Any ideas?

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  • How to get attributes from parent?

    - by bribon
    Hi all, Let's say we have these classes: class Foo(object): _bar = "" def __init__(self): self.bar = "hello" def getBar(self): return self._bar def setBar(self, bar): self._bar = bar def getAttributes(self): for attr in self.__dict__: print attr bar = property(getBar, setBar) class Child(Foo): def __init__(self): super(Child, self).__init__() self.a = "" self.b = "" if I do something like: child = Child() child.getAttributes() I get all the attributes from parent and child. How could I get the attributes only from the parent? Thanks in advance!

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  • rb plugin the hot key not working

    - by Bunny Rabbit
    def activate(self,shell): self.shell = shell self.action = gtk.Action ('foo','bar','baz',None) self.activate_id = self.action.connect ('activate', self.call_bk_fn,self.shell) self.action_group = gtk.ActionGroup ('hot_key_action_group') self.action_group.add_action_with_accel (self.action, "<control>E") uim = shell.get_ui_manager () uim.insert_action_group (self.action_group, 0) uim.ensure_update () def call_bk_fn(self,shell): print('hello world') i am using the above code in a plugin for rhythmbox ,and here i am trying to register the key ctr+e so that the call_bk_fn gets called whenever the key combination is pressed , but its not working why is that so ?

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  • Collision between 2 objects of the same class

    - by user1826033
    Okay, so I have an enemy class(With rotation, position, texture and so on). I spawn a few enemies on the screen, they move around, but they overlap each other. So I tried to do a collision check between two enemies of the same class. But no matter what method I try, it isn't quite working. The best thing I tried was: foreach (Enemy enemy1 in enemies) { enemy1Pos = new Vector2(enemy1.position.X, enemy1.position.Y) foreach (Enemy enemy2 in enemies) { enemy2Pos = new Vector2(enemy2.position.X, enemy2.position.Y) if (Vector2.Distance(enemy2Pos, enemy1Pos) < 200) { enemy1Pos += new Vector2((float)(enemy1.Speed * Math.Cos(enemy1.Rotation)), (float)(enemy1.Speed * Math.Sin(enemy1.Rotation))); } } } This is not to exact code, so it might have some mistakes in it. Anyway when i implemented this solution, the enemies were not overlapping so everything was fine on that part. But, they were always moving to the right side of the screen. I've also looked up flocking etc, but I would like to know, how can I detect collision between 2 objects of the same class?

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  • Python: Run a progess bar and work simultaneously?

    - by DanielTA
    I want to know how to run a progress bar and some other work simultaneously, then when the work is done, stop the progress bar in Python (2.7.x) import sys, time def progress_bar(): while True: for c in ['-','\\','|','/']: sys.stdout.write('\r' + "Working " + c) sys.stdout.flush() time.sleep(0.2) def work(): *doing hard work* How would I be able to do something like: progress_bar() #run in background? work() *stop progress bar* print "\nThe work is done!"

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  • Write failed, errno 0

    - by EpsilonVector
    I have a client server situation in which I receive data using read(socket, char_buf, BUF_SIZE) and then try to write it into a log file using write(filefd, char_buf, strlen(char_buf)) Strangely enough this fails (write returns -1), and yet the errno is set to 0, and I can print the message, AND the log file descriptor works (I write to it before and after this command). What's going on?? (Working on Linux kernel 2.4 (homework))

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  • Unicode symbols coming wrong

    - by robert
    Obviously, there must be something stupid i'm doing. The unicode chart for subscripts and superscripts says #00B2 is superscript 2, but i get scrambled output. 0078 is x, but I get N, and 0120 is x. Am i reading wrong manual? EDIT $x = '&#0078;'; print html_entity_decode($x, ENT_NOQUOTES, 'UTF-8') . "\n";

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  • Drawing animation

    - by HHHH
    I'm creating a simple app where when the user presses a button, a series of lines will be drawn on the screen and the user will be able to see these lines drawn in real time (almost like an animation). My code looks something like this (has been simplified): UIGraphicsBeginImageContext(CGSizeMake(300,300)); CGContextRef context = UIGraphicsGetCurrentContext(); for (int i = 0; i < 100; i++ ) { CGContextMoveToPoint(context, i, i); CGContextAddLineToPoint(context, i+20, i+20); CGContextSetStrokeColorWithColor(context, [[UIColor blackColor] CGColor]); CGContextStrokePath(context); } UIImage *newImage = UIGraphicsGetImageFromCurrentImageContext(); UIGraphicsEndImageContext(); My problem is that: 1) As soon as the user presses the button, the UIThread blocks until the drawing is done. 2) I can't get the lines to be drawn on the screen one at a time - I've tried setting the UIImage directly inside the loop and also tried setting a layer content inside the loop. How do I get around these problems?

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  • Converting Numpy Lstsq residual value to R^2

    - by whatnick
    I am performing a least squares regression as below (univariate). I would like to express the significance of the result in terms of R^2. Numpy returns a value of unscaled residual, what would be a sensible way of normalizing this. field_clean,back_clean = rid_zeros(backscatter,field_data) num_vals = len(field_clean) x = field_clean[:,row:row+1] y = 10*log10(back_clean) A = hstack([x, ones((num_vals,1))]) soln = lstsq(A, y ) m, c = soln [0] residues = soln [1] print residues

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  • word after the space NSlog

    - by DD007
    I am new bie to xcode may be question is silly but I am lagging with my home work. In a file I want to read a specific character after the string. I want to read all the character after the space. ex: asasasasasas wewewewewewe qwqwqwqwqwqw xyz_ 22 aaaaaaaaaaa bbbbbbbbbbb ccccccccccccccc ddddddddddddd fgfgfgfgfgfgfg ererererererer abc_ 12 bbbbbbbbbb dddddddd jkjkjkjkjkjkjk lalallalalalal everything is fine .. but i want to print after "xyz_ 22" as aaaaaaa then bbbb ccc

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  • related to list and file handling?

    - by kaushik
    i have file with contents in list form such as [1,'ab','fgf','ssd'] [2,'eb','ghf','hhsd'] [3,'ag','rtf','ssfdd'] i want to read that file line by line using f.readline and assign thn to a list so as to use it is the prog as a list for using list properties tried like k=[ ] k=f.readline() print k[1] i xpected a result to show 2nd element in the list in first line but it showed the first bit and gave o/p as '1' how to get the xpected output.. please suggest

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