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  • PHP: Collect all variables passed to a function as array?

    - by Industrial
    Hi everybody, I was thinking about the possibility of accessing all the variables that are passed into an function, and merge them into an array. (Without passing variables into an array from the beginning) Pseudo-code: // Call function newFunction('one', 'two', 'three' ) ;// All values are interpreted as a one rray in some way // Function layout newFunction( ) { // $functionvariables = array( All passed variables) foreach ($functionvariable as $k => $v) { // Do stuff } }

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  • Force result for empty() test on an object

    - by hsz
    Hello ! Simple class for example: class Foo { protected $_bar; public function setBar( $value ) { $this->_bar = $value; } } And here is the question: $obj = new Foo(); var_dump( empty( $obj ) ); // true $obj->setBar( 'foobar' ); var_dump( empty( $obj ) ); // false Is it possible to change class's behaviour with testing it with empty() function so it will returns true when object is not filled with data ? I know about magic function __isset( $name ) but it is called only when we test specific field like: empty( $obj->someField ); but not when test whole object.

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  • Php read directory file

    - by kwek-kwek
    I have a script that goes through a directory that has 3 images $imglist=''; $img_folder = "path to my image"; //use the directory class $imgs = dir($img_folder); //read all files from the directory, checks if are images and ads them to a list while ($file = $imgs->read()) { if (eregi("gif", $file) || eregi("jpg", $file) || eregi("png", $file)) $imglist .= "$file "; } closedir($imgs->handle); //put all images into an array $imglist = explode(" ", $imglist); //display image foreach($imglist as $image) { echo '<img src="'.$img_folder.$image.'">'; } but the problem that I am having is it display a 4th img with no image.. yet I only have 3 image in that folder.

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  • How to convert a PHP object to a string?

    - by Rohan
    I get this error: Catchable fatal error: Object of class stdClass could not be converted to string So, my question is, how do I convert an object to a string in PHP? I don't want to serialize it though. Just a note: the code I use works in PHP 4, but not in PHP 5 Thanks!

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  • Easy way to apply a function to an array

    - by alex
    I am aware of array_walk() and array_map(). However when using the former like so (on an old project) it failed array_walk($_POST, 'mysql_real_escape_string'); Warning: mysql_real_escape_string() expects parameter 2 to be resource, string given. So I went with this slightly more ugly version foreach($_POST as $key => $value) { $_POST[$key] = mysql_real_escape_string($value); } So why didn't the first way work? What is the best way to map values of an array to a function?

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  • PHP oop build array

    - by Industrial
    Hi! If I would need to build up an array with OOP based PHP, would this be the proper way to do it? class MyClass { $array = array(); function addElement($value) { $this->array[] = $value; } function fetch() { $return = $this->memcached->getMulti($this->array); return $return; } } PHP file where it will be used: <?php $this->myClass->addElement('key1'); $this->myClass->addElement('key1'); $this->myClass->addElement('key1'); $var = $this->myClass->fetch(); Thanks a lot

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  • ctype_alpha but allow spaces(php)

    - by helloo
    I was wondering if one can allow spaces in a textfield when checking it with ctype_alpha. Since ctype_alpha only allows alphabetical letters, I don't know how to let the user enter space in the field. I did try using ctype_space but that didn't work. I simply want the user to be able to type only alphabets and they have a choice to include spaces if they "wish." I hope I will not have to use regexp as I am very new to all of this and hope to learn it at a later date. Below is some of the code...Thank you. elseif (!ctype_alpha($fname)) { echo "Your name may only contain alphabetical letters"; }

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  • PHP: Iterate through folders and display HTML contends

    - by Mestika
    Hi, I’m currently trying to develop a method to get a overview of all my different web templates I’ve created and (legally) downloaded over the years. I thought about a displaying them like Wordpress is previewing it’s templates view a small preview windows, displaying the concrete file with styles and everything. How to divide them into rows and columns and create AJAX modal window open on preview and pagination and so on I believe I can manage, but it is the concept itself about iterate over several folders then find all index.htm / index.html pages and displaying them. I’ve not worked very much with directories in PHP and the only references and code stumps I’ve found so far is just to list all the files in a certain directory like, what it contains. I would be really grateful if someone knew about a script, a function, snippet or just could get me a nudge in the right direction to create such a (probably simple) preview function. Sincere Mestika

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  • Framework or CMS for php web development?

    - by rocknroll
    Hi all, I am a C++,Unix developer who has never dabbled in web development apart from creating simple HTML pages. I am going to change that and develop a website at a personal level soon. I am going to use php,mysql on a linux machine. In this regard I am browsing through relevant literature. The language isn't a problem but reading about CMS's and frameworks is confusing. And since I am new to web development, the number of CMS's and Frameworks are overwhelming. ? My question is do I need to have knowledge of one or more CMS' and/or Frameworks like Drupal,Joomla,Zend,Wordpress etc. If yes which is the best open source CMS' and/or Framework suggested for a newbie. ?? If the answer to the above question is yes, does the choice changes if one delves into the realms of commercial web development? Note:- I will be developing on a Linux machine, using open source tools. Thanks in advance

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  • Make a router like zend

    - by Vahan
    I have a url http://*.com/branch/module/view/id/1/cat/2/etc/3. It becomes. array ( 'module'=>'branch', 'controller'=>'module', 'action'=>'view' ); next I need to get the params. Ihave this array. /*function getNextSegments($n,$segments) { return array_slice ( $q = $this->segments, $n + 1 ); } $params = getNextSegments(3); */ array ( 0 => 'id', 1 => '1', 2 => 'cat', 3 => '2', 4 => 'etc', 5 => '3' );//params And i wanna convert it to this one: array ( 'id'=1, 'cat'=2, 'etc'=3, ); How i can do this using php function. I know I can do using for or foreach, but I think php has such function , but i cant find it :(. Thank you. class A { protected function combine($params) { $count = count ( $params ); $returnArray = array (); for($i = 0; $i < $count; $i += 2) { $g = $i % 2; if ($g == 0 or $g > 0) { if (isset ( $params [$i] ) and isset ( $params [$i + 1] )) $returnArray [$params [$i]] = $params [$i + 1]; } } return $returnArray; } } This works normaly. If anybody has better login for this please help. Thank you again.

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  • What is the efficient way to make a permission system?

    - by WEBProject
    Currently im just using something like: in the DB Table: access: home,register,login and then in each page: if(!Functions::has_rights('content')) { Functions::noAccess(); } is there more efficient way to do it, php & MySQL? i may want to gain access even to several parts a page, for example: user can read a page, but doesnt comment to it, and I dont want to build a separate system to each module. Thanks in advanced, Tal.

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  • An efficient way to store view counts for objects?

    - by Nick Brooks
    I maintain an application where users are able to store images, and then share them. The system is powered by MongoDB at the back end. Most of the image depiction pages are cached as flat HTML files, but I can run some code just before loading the file. I've decided to implement a view count for the system. I am wondering what is the best storage place for that. It should be like Memcached but it should save the viewcounts every hour or so, so even if our server has to be restarted we won't lose the view counts. What is the best solution for that (preferably with a PHP extension as a client)?

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  • php joomla session lifetime settings

    - by jtanmay
    I have searched through the google and also joomla forums but didn't got what exactly I was looking for. My main purpose is to set the joomla session live for ever. Many forums says its not good to keep a higher value (security issues) but I don't want to consider that right now. My question is : What if I set the session lifetime value to "0" (Zero), will the session be active for ever? or the user will NOT be able to login completely? Thanks, Tanmay

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  • What is the below code

    - by Priyanka
    Hello, I am getting an issue wherein I am using FCKEditor, and once I type in something, in the source of FCKEditor, something like below is getting iserted automatically. <input type="hidden" id="gwProxy" /><!--Session data--><input type="hidden" id="jsProxy" /> <div id="refHTML">&nbsp;</div> Some hidden tag is getting inserted, which isnot getting diplayed here in my question. Can anyone tell me about this. Thanks in Advance

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  • Why won't my PHP script work?

    - by sadicool
    I have a script that reports the following error: Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'admin'@'localhost' (using password: YES) in C:\wamp\www\bits\includes\connect.inc.php on line 10 Notice: Undefined variable: l_error in C:\wamp\www\bits\includes\connect.inc.php on line 12 Notice: Undefined variable: l_cannotconnecttodatabase in C:\wamp\www\bits\includes\connect.inc.php on line 12 Why would this be?

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  • Php compatibility question

    - by Undgerman
    I am trying to run cimyadmin(http://cimyadmin.net/) but i am getting a lot of helper depreciation errors and after looking around the web for answers i am convinced its a php issue.Is there a way to run php 5.0.2 or earlier but not less than php 5 code on latest distributions of php.

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