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  • jQuery add class is not working

    - by user1269625
    Hey ya'll I have this code here and it suppose to add the class name "cboxElement" $(".wpcart_gallery a:first").addClass("cboxElement"); but it does not work. I have the proper Jquery file in my header, I have surrounded this in jQuery('document').ready(function($){......}); and it works for all my other Jquery but the add class call. here is what I am trying to add the class to... <div class="wpcart_gallery" style="text-align:center; padding-top:5px;"> <a class="thickbox" href="DSC_0037.jpg" rev="DSC_0037.jpg"></a> </div> Anybody know why this isnt working? I am new to jquery this is also in wordpress hence the jQuery('document')

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  • How would I UPDATE these table entries with SQL and PHP?

    - by CT
    I am working on an Asset Database problem. I enter assets into a database. Every object is an asset and has variables within the asset table. An object is also a type of asset. In this example the type is server. Here is the Query to retrieve all necessary data: SELECT asset.id ,asset.company ,asset.location ,asset.purchaseDate ,asset.purchaseOrder ,asset.value ,asset.type ,asset.notes ,server.manufacturer ,server.model ,server.serialNumber ,server.esc ,server.warranty ,server.user ,server.prevUser ,server.cpu ,server.memory ,server.hardDrive FROM asset LEFT JOIN server ON server.id = asset.id WHERE asset.id = '$id' I then assign all results into single php variables. How would I write a query/script to update an asset?

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  • ruby send vs __send__

    - by jaydel
    I understand the concept of some_instance.send but I'm trying to figure out why you can call this both ways? The Ruby Koans imply that there is some reason beyond providing lots of different ways to do the same thing and I'm wrestling with figuring this out. Here are the two examples of usage more concretely class Foo def bar? true end end foo = Foo.new foo.send(:bar?) foo.send(:bar?) Anyone have any idea about this? thanks in advance!

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  • How do you printf an unsigned long long int?

    - by superjoe30
    #include <stdio.h>int main() { unsigned long long int num = 285212672; //FYI: fits in 29 bits int normalInt = 5; printf("My number is %d bytes wide and its value is %ul. A normal number is %d.\n", sizeof(num), num, normalInt); return 0;} Output: My number is 8 bytes wide and its value is 285212672l. A normal number is 0. I assume this unexpected result is from printing the unsigned long long int. How do you printf an unsigned long long int?

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  • in C# sharp, how you pronounce 'T?'

    - by plinth
    How do you pronounce 'bool?', 'int?' and their ilk? I've been mulling over options like "nullable of T", "T hook", "T huh", "T what" and "T" with a rising inflection. I'm not particularly satisfied with these as they seem either cumbersome or affected or both.

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  • LINQ to SQL: ExecuteQuery not working when performing a parameterized query.

    - by ajbeaven
    I have a weird problem with ExecuteQuery in that it isn't working when performing a parameterized query. The following returns 1 record: db.ExecuteQuery<Member>(@"SELECT * FROM Member INNER JOIN aspnet_Users ON Member.user_id = aspnet_Users.UserId WHERE [aspnet_Users].[UserName] = 'Marina2'"); However, the parameterized version returns no results: db.ExecuteQuery<Member>(@"SELECT * FROM Member INNER JOIN aspnet_Users ON Member.user_id = aspnet_Users.UserId WHERE [aspnet_Users].[UserName] = '{0}'", "Marina2"); What am I doing wrong?

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  • Cygwin bash syntax error - but script run perfectly well in Ubuntu

    - by Michael Mao
    #!/bin/bash if test "$#" == "4"; then echo "$*"; else echo "args-error" >&2; fi; This little code snippet troubles me a lot when I tried to run it on both Ubuntu and Cygwin. Ubuntu runs bash version 4.0+ whereas Cygwin runs 3.2.49; But I reckon version collision shall not be the cause of this, this code runs well under fedora 10 which is also using bash version 3.+ So basically I am wondering if there is a way to code my script once and for all so there are not to have this awful issue later on. Many thanks in advance.

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  • Does Java need tuples?

    - by Yuval A
    This question got me re-thinking about something that always bothered me: Does Java need tuples? Do you feel the lack of them in your day-to-day work? Do you think tuples would simplify otherwise complex data structures you find yourself implementing?

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  • In SQL, what's the difference between count(column) and count(*)?

    - by Bill the Lizard
    I have the following query: select column_name, count(column_name) from table group by column_name having count(column_name) > 1; What would be the difference if I replaced all calls to count(column_name) to count(*)? This question was inspired by a previous one. Edit: To clarify the accepted answer (and maybe my question), using count(*) in this case returns an extra row in the result that contains a null and the count of null values in the column.

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  • Use an Array to Cycle Through a MySQL Where Statement

    - by Ryan
    I'm trying to create a loop that will output multiple where statements for a MySQL query. Ultimately, my goal is to end up with these four separate Where statements: `fruit` = '1' AND `vegetables` = '1' `fruit` = '1' AND `vegetables` = '2' `fruit` = '2' AND `vegetables` = '1' `fruit` = '2' AND `vegetables` = '2' My theoretical code is pasted below: <?php $columnnames = array('fruit','vegetables'); $column1 = array('1','2'); $column2 = array('1','2'); $where = ''; $column1inc =0; $column2inc =0; while( $column1inc <= count($column1) ) { if( !empty( $where ) ) $where .= ' AND '; $where = "`".$columnnames[0]."` = "; $where .= "'".$column1[$column1inc]."'"; while( $column2inc <= count($column2) ) { if( !empty( $where ) ) $where .= ' AND '; $where .= "`".$columnnames[1]."` = "; $where .= "'".$column2[$column2inc]."'"; echo $where."\n"; $column2inc++; } $column1inc++; } ?> When I run this code, I get the following output: `fruit` = '1' AND `vegetables` = '1' `fruit` = '1' AND `vegetables` = '1' AND `vegetables` = '2' `fruit` = '1' AND `vegetables` = '1' AND `vegetables` = '2' AND `vegetables` = '' Does anyone see what I am doing incorrectly? Thanks.

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  • Ruby does 'elseif' still exist

    - by catchmikey
    I'm just learning ROR and I came across the if / else statements. I also came across 'elseif' but my text editor (textmate) doesn't pick it up as a keyword, not does the program run properly. if name == 'Chris' puts 'What a lovely name.' elseif name == 'Katy' puts 'What a lovely name!' end I'm using the book, Learn to Program, which was written several years ago. I was wondering if the 'elseif' was changed because when I simply use 'else' it seems to function properly

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  • Passing a comparator syntax help in Java

    - by Crystal
    I've tried this a couple ways, the first is have a class that implements comparator at the bottom of the following code. When I try to pass the comparat in sortListByLastName, I get a constructor not found error and I am not sure why import java.util.*; public class OrganizeThis implements WhoDoneIt { /** Add a person to the organizer @param p A person object */ public void add(Person p) { staff.put(p.getEmail(), p); //System.out.println("Person " + p + "added"); } /** * Remove a Person from the organizer. * * @param email The email of the person to be removed. */ public void remove(String email) { staff.remove(email); } /** * Remove all contacts from the organizer. * */ public void empty() { staff.clear(); } /** * Find the person stored in the organizer with the email address. * Note, each person will have a unique email address. * * @param email The person email address you are looking for. * */ public Person findByEmail(String email) { Person aPerson = staff.get(email); return aPerson; } /** * Find all persons stored in the organizer with the same last name. * Note, there can be multiple persons with the same last name. * * @param lastName The last name of the persons your are looking for. * */ public Person[] find(String lastName) { ArrayList<Person> names = new ArrayList<Person>(); for (Person s : staff.values()) { if (s.getLastName() == lastName) { names.add(s); } } // Convert ArrayList back to Array Person nameArray[] = new Person[names.size()]; names.toArray(nameArray); return nameArray; } /** * Return all the contact from the orgnizer in * an array sorted by last name. * * @return An array of Person objects. * */ public Person[] getSortedListByLastName() { PersonLastNameComparator comp = new PersonLastNameComparator(); Map<String, Person> sorted = new TreeMap<String, Person>(comp); ArrayList<Person> sortedArrayList = new ArrayList<Person>(); for (Person s: sorted.values()) { sortedArrayList.add(s); } Person sortedArray[] = new Person[sortedArrayList.size()]; sortedArrayList.toArray(sortedArray); return sortedArray; } private Map<String, Person> staff = new HashMap<String, Person>(); public static void main(String[] args) { OrganizeThis testObj = new OrganizeThis(); Person person1 = new Person("J", "W", "111-222-3333", "[email protected]"); Person person2 = new Person("K", "W", "345-678-9999", "[email protected]"); Person person3 = new Person("Phoebe", "Wang", "322-111-3333", "[email protected]"); Person person4 = new Person("Nermal", "Johnson", "322-342-5555", "[email protected]"); Person person5 = new Person("Apple", "Banana", "123-456-1111", "[email protected]"); testObj.add(person1); testObj.add(person2); testObj.add(person3); testObj.add(person4); testObj.add(person5); System.out.println(testObj.findByEmail("[email protected]")); System.out.println("------------" + '\n'); Person a[] = testObj.find("W"); for (Person p : a) System.out.println(p); System.out.println("------------" + '\n'); a = testObj.find("W"); for (Person p : a) System.out.println(p); System.out.println("SORTED" + '\n'); a = testObj.getSortedListByLastName(); for (Person b : a) { System.out.println(b); } System.out.println(testObj.getAuthor()); } } class PersonLastNameComparator implements Comparator<Person> { public int compare(Person a, Person b) { return a.getLastName().compareTo(b.getLastName()); } } And then when I tried doing it by creating an anonymous inner class, I also get a constructor TreeMap cannot find symbol error. Any thoughts? inner class method: public Person[] getSortedListByLastName() { //PersonLastNameComparator comp = new PersonLastNameComparator(); Map<String, Person> sorted = new TreeMap<String, Person>(new Comparator<Person>() { public int compare(Person a, Person b) { return a.getLastName().compareTo(b.getLastName()); } }); ArrayList<Person> sortedArrayList = new ArrayList<Person>(); for (Person s: sorted.values()) { sortedArrayList.add(s); } Person sortedArray[] = new Person[sortedArrayList.size()]; sortedArrayList.toArray(sortedArray); return sortedArray; }

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  • How to make if loop in grails?

    - by user3569696
    I'm beginner in Grails, please help. I have this in my gsp <div class="right66"> <g:select class="time_pick" name="pick_day" placeholder="" from="${['Dani', 'Sati', 'Minute']}" valueMessagePrefix="book.category"/> </div> In translation: Dani=Days, Sati= Hours, Minute= Minutes. I need to save data in minutes but User have privilege to choose will his input be in minutes, days or hours. So i have to do if loop. I now how if loop works but i don't know how to wite it in grails. I was thinking something like this: n=1 if(params.type=Dani){ n= 3600 }else if(params.type=Sati) { n=60 } def minute=params.minute*n but how to call that choosen input "Dani"? I can't write Params.type=Dani. Does if loop go in controller in my case?

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  • How to change out-of-focus text selection color in Xcode?

    - by Jackson
    Okay, I'll bite. I've got really pleasant code/window colors set up in Xcode. Ordinarily, my selection color is very visible. When I am doing a project search and iterating through the results, however, the results list stays in focus and the found text remains out of focus, using a different background color. This color is extremely hard to detect, especially when the text is embedded in a larger code block and the view is shifting around as it scrolls to the results. Here's an example: Left side is in focus (just normal selection), right side is out of focus (during project find) Often it takes a few seconds to find where the heck the selected text is. Unless I'm just missing it, Xcode seems to offer no way to change this particular selection color. Interestingly, it also doesn't seem to follow the selection color from the Appearance panel. Does anyone know a way to change this color or force it to be more visible, short of changing my entire color scheme around?

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  • When to use or not use symbols in PHP

    - by brett
    I'm reading a PHP book where the author says that symbols should be avoided except when it's valid to use them. Very informative stuff, if he could only elaborate or give code examples but he doesn't. Can someone from the experienced PHP bunch give me an example of what these symbols are, and when it makes sense to use them or not. I'm looking for a code example that I can wrap my head around since I don't quite get it in plain English. Code is more plain English to me.

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  • Prolog check if

    - by NickLee
    I'm creating a text adventure game on SWI-Prolog and I want to include (some kind of) dialogs. What I have so far is: dialog1(1):- nl,write('blah blah'),nl write('a: this is answer a'),nl, write('b: this is answer b'),nl. a:- write('respond to answer a'),nl. b:- write('respond to answer b'),nl. That's pretty much the first dialog. Now I want to create a second dialog similar to the first one. dialog1(2):- nl,write('blah blah'),nl, write('a: this is answer a'),nl, write('b: this is answer b'),nl. a:- write('respond to answer a'),nl. b:- write('respond to answer b'),nl. How can I check if the dialog is the first or the second one? I want to do that because when the user types a., I need the right answer a to be shown. I thought I could use something like a(1):- write('respond to answer a'),nl. b(1):- write('respond to answer b'),nl. /* and on the second dialog*/ a(2):- write('respond to answer a'),nl. b(2):- write('respond to answer b'),nl. But still, if the user is on dialog 2 and he types a(1),the first answer will appear.

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  • C#: Easy access to the member of a singleton ICollection<> ?

    - by Rosarch
    I have an ICollection that I know will only ever have one member. Currently, I loop through it, knowing the loop will only ever run once, to grab the value. Is there a cleaner way to do this? I could alter the persistentState object to return single values, but that would complicate the rest of the interface. It's grabbing data from XML, and for the most part ICollections are appropriate. // worldMapLinks ensured to be a singleton ICollection<IDictionary<string, string>> worldMapLinks = persistentState.GetAllOfType("worldMapLink"); string levelName = ""; //worldMapLinks.GetEnumerator().Current['filePath']; // this loop will only run once foreach (IDictionary<string, string> dict in worldMapLinks) // hacky hack hack hack { levelName = dict["filePath"]; } // proceed with levelName loadLevel(levelName); Here is another example of the same issue: // meta will be a singleton ICollection<IDictionary<string, string>> meta = persistentState.GetAllOfType("meta"); foreach (IDictionary<string, string> dict in meta) // this loop should only run once. HACKS. { currentLevelName = dict["name"]; currentLevelCaption = dict["teaserCaption"]; } Yet another example: private Vector2 startPositionOfKV(ICollection<IDictionary<string, string>> dicts) { Vector2 result = new Vector2(); foreach (IDictionary<string, string> dict in dicts) // this loop will only ever run once { result.X = Single.Parse(dict["x"]); result.Y = Single.Parse(dict["y"]); } return result; }

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  • php : echo"", print(), printf()

    - by marc-andre menard
    Is there a better way to output data to html page with PHP ? if i like to make a div with some var in php i will write something like that print ('<div>'.$var.'</div>); or echo "'<div>'.$var.'</div>'"; what is the PROPER way to do that ? or a better way, fill a $tempvar and print it once? like that: $tempvar = '<div>'.$var.'</div>' print ($tempvar); in fact, in real life, the var will be fill with much more !

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  • Understanding syntax in c#

    - by user279521
    I am hoping someone can help me understand what is going on in the code line below: Table t = (Table)Page.FindControl("Panel1").FindControl("tbl"); I understand Page.FindControl("Panel1").FindControl("tbl"); Why is there a (Table) before the Page.FindControl?

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  • How to change the value of None in Python?

    - by michael
    I'm currently reading chapter 5.8 of Dive Into Python and Mark Pilgrim says: There are no constants in Python. Everything can be changed if you try hard enough. This fits with one of the core principles of Python: bad behavior should be discouraged but not banned. If you really want to change the value of None, you can do it, but don't come running to me when your code is impossible to debug. I tried this in the interpreter None = "bad" I get a SyntaxError: assignment to None Just out of curiosity how do you change None?

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  • Why is my variable uninitialized in a separate if test?

    - by user2932733
    For the first run, I need to use dates that are six months prior to the last MySQL date $row_recent[0]. For all of the runs after 1, I am using a previous variable to store the previous date and then decrease the date by 6 months. I have confirmed that the first if test produces the expected result. (MySQL date - 6 Months). However, the second if test outputs $startdate6m as the PHP default due to $previous_6m being uninitialized. Any idea why it won't recognize $previous_6m = $initial6m? <?php while ($run_number < 15) { $run_number++; if($run_number == 1){ if ($month <= 06){ $year6m = date("Y", strtotime($row_recent[0]))-1; $month6m = str_pad((12-(6-date("m", strtotime($row_recent[0])))), 2, "0", STR_PAD_LEFT); $startdate6m = "'".$year6m."-".$month6m."-01'"; $end_date = $startdate6m; $initial6m = $startdate6m; } else{ $year6m = date("Y", strtotime($row_recent[0])); $month6m = str_pad(date("m", strtotime($row_recent[0]))-6, 2, "0", STR_PAD_LEFT); $startdate6m = "'".$year6m."-".$month6m."-01'"; $end_date = $startdate6m; $initial6m = $startdate6m; } } $previous_6m = $initial6m; if($run_number > 1){ # 6 Month # Decrement date by 6 months $month6m = date("m", strtotime($previous_6m)); if ($month6m <= 06){ $year6m = date("Y", strtotime($previous_6m))-1; $month6m = str_pad((12-(6-date("m", strtotime($previous_6m)))), 2, "0", STR_PAD_LEFT); $startdate6m = "'".$year6m."-".$month6m."-01'"; $end_date = $startdate6m; } else{ $year6m = date("Y", strtotime($previous_6m)); $month6m = str_pad(date("m", strtotime($previous_6m))-6, 2, "0", STR_PAD_LEFT); $startdate6m = "'".$year6m."-".$month6m."-01'"; $end_date = $startdate6m; } } $previous_6m = $startdate6m; } ?>

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