Is there any way to pass an anonymous array as an argument in C++?
- by Jeremy Friesner
Hi all,
I'd like to be able to declare an array as a function argument in C++, as shown in the example code below (which doesn't compile). Is there any way to do this (other than declaring the array separately beforehand)?
#include <stdio.h>
static void PrintArray(int arrayLen, const int * array)
{
for (int i=0; i<arrayLen; i++) printf("%i -> %i\n", i, array[i]);
}
int main(int, char **)
{
PrintArray(5, {5,6,7,8,9} ); // doesn't compile
return 0;
}
