Search Results

Search found 1472 results on 59 pages for 'harry len'.

Page 5/59 | < Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >

  • finding a solution to a giving maze txt.file

    - by alberto
    how can i fix this program, the problem is when it print out the coordinate it give me a 7 for the start and finish, i would appreciated you help, thanks start = (len(data)) finish = (len(data)) pos= [] for i in range(len(pos)): for j in range(len(pos[i])): if pos[i][j] == "S": start=(i,j) elif pos[i][j] == "F": finish=(i,j) print "S found in",start, print "\nF found in",finish,"\n"

    Read the article

  • ProgressBar isn't updating

    - by Nuru Salihu
    I have a progressbar that that is show progress returned by the backgroundworker do_dowork event like below . if (ftpSourceFilePath.Scheme == Uri.UriSchemeFtp) { FtpWebRequest objRequest = (FtpWebRequest)FtpWebRequest.Create(ftpSourceFilePath); NetworkCredential objCredential = new NetworkCredential(userName, password); objRequest.Credentials = objCredential; objRequest.Method = WebRequestMethods.Ftp.DownloadFile; FtpWebResponse objResponse = (FtpWebResponse)objRequest.GetResponse(); StreamReader objReader = new StreamReader(objResponse.GetResponseStream()); int len = 0; int iProgressPercentage = 0; FileStream objFS = new FileStream((cd+"\\VolareUpdate.rar"), FileMode.Create, FileAccess.Write, FileShare.Read); while ((len = objReader.BaseStream.Read(buffer, 0, buffer.Length)) > 0) { objFS.Write(buffer, 0, len); iRunningByteTotal += len; double dIndex = (double)(iRunningByteTotal); double dTotal = (double)buffer.Length; double dProgressPercentage = (dIndex / dTotal); iProgressPercentage = (int)(dProgressPercentage); if (iProgressPercentage > 100) { iProgressPercentage = 100; } bw.ReportProgress(iProgressPercentage); } } However, my progressbar does not update. While searching , i was told the UI thread is being blocked and then i thought may be passing the progress outside the loop will do the trick. then i change to this if (ftpSourceFilePath.Scheme == Uri.UriSchemeFtp) { FtpWebRequest objRequest = (FtpWebRequest)FtpWebRequest.Create(ftpSourceFilePath); NetworkCredential objCredential = new NetworkCredential(userName, password); objRequest.Credentials = objCredential; objRequest.Method = WebRequestMethods.Ftp.DownloadFile; FtpWebResponse objResponse = (FtpWebResponse)objRequest.GetResponse(); StreamReader objReader = new StreamReader(objResponse.GetResponseStream()); int len = 0; int iProgressPercentage = 0; FileStream objFS = new FileStream((cd+"\\VolareUpdate.rar"), FileMode.Create, FileAccess.Write, FileShare.Read); while ((len = objReader.BaseStream.Read(buffer, 0, buffer.Length)) > 0) { objFS.Write(buffer, 0, len); iRunningByteTotal += len; double dIndex = (double)(iRunningByteTotal); double dTotal = (double)buffer.Length; double dProgressPercentage = (dIndex / dTotal); iProgressPercentage = (int)(dProgressPercentage); if (iProgressPercentage > 100) { iProgressPercentage = 100; } // System.Threading.Thread.Sleep(2000); iProgressPercentage++; // SetText("F", true); } bw.ReportProgress(iProgressPercentage); progressBar.Refresh(); } However still didn't help. When i put break point in my workerprogresschanged event, it show the progressbar.value however does not update. I tried progressbar.update(0, i also tried sleeping the thread for a while in the loop still didn't help. Please any suggestion/help would be appreciated .

    Read the article

  • Web hosting providers for businesses (with offsite backups, disaster recovery options, etc.) [closed]

    - by Harry Muscle
    Possible Duplicate: How to find web hosting that meets my requirements? I'm wondering if anyone can point me in the direction of a couple of web hosting providers that are geared towards businesses. By this I mean providers that make it easy to create daily off site backups, are aware that websites require disaster recovery options and have these in place or are able to assist with them, etc. We currently have about a dozen sites with various providers, however, I've been asked to consolidate all of these into one provider and create a full disaster recovery plan. Unfortunately it seems like most providers are geared towards average users that don't require all these extra bells and whistles that businesses need. For example, HostGator, which is a very popular and well reviewed provider, doesn't even allow you to schedule full backups, they have to be manually requested via cPanel and then downloaded once available. If anyone can point out a couple companies that might be able to help with these sorts of things that would be much appreciated. Thanks, Harry P.S. I should also add that we are hoping to stay away from having to manage our own server, we're hoping for a fully managed solution like what HostGator would offer for example.

    Read the article

  • Iptables blocking mysql port 3306

    - by valmar
    I got a Tomcat server running a web application that must access a mysql server via Hibernate on the same machine. So, I added a rule for port 3306 to my iptables script but tomcat cannot connect to the mysql server for some reason. I need to reset all iptables rules - Then tomcat can connect to the mysql server again. All the other iptables rules work perfectly though. What's wrong? Here is my script: iptables -A INPUT -m conntrack --ctstate ESTABLISHED,RELATED -j ACCEPT iptables -A INPUT -p tcp --dport 24 -j ACCEPT iptables -A INPUT -p tcp --dport 80 -j ACCEPT iptables -A OUTPUT -p tcp --dport 80 -j ACCEPT iptables -A INPUT -p tcp -s localhost --dport 8009 -m state --state ESTABLISHED -j ACCEPT iptables -A OUTPUT -p tcp -d localhost --dport 8009 -j ACCEPT iptables -A INPUT -p tcp -s localhost --dport 3306 -j ACCEPT iptables -A OUTPUT -p tcp -d localhost --dport 3306 -j ACCEPT iptables -A INPUT -p tcp --dport 443 -j ACCEPT iptables -A OUTPUT -p tcp --dport 443 -j ACCEPT iptables -A INPUT -p tcp --dport 25 -m state --state ESTABLISHED -j ACCEPT iptables -A OUTPUT -p tcp --dport 25 -j ACCEPT iptables -A INPUT -p tcp --dport 587 -m state --state ESTABLISHED -j ACCEPT iptables -A OUTPUT -p tcp --dport 587 -j ACCEPT iptables -A INPUT -p tcp --dport 465 -m state --state ESTABLISHED -j ACCEPT iptables -A OUTPUT -p tcp --dport 465 -j ACCEPT iptables -A INPUT -p tcp --dport 110 -m state --state ESTABLISHED -j ACCEPT iptables -A OUTPUT -p tcp --dport 110 -j ACCEPT iptables -A INPUT -p tcp --dport 995 -m state --state ESTABLISHED -j ACCEPT iptables -A OUTPUT -p tcp --dport 995 -j ACCEPT iptables -A INPUT -p tcp --dport 143 -m state --state ESTABLISHED -j ACCEPT iptables -A OUTPUT -p tcp --dport 143 -j ACCEPT iptables -A INPUT -p tcp --dport 993 -m state --state ESTABLISHED -j ACCEPT iptables -A OUTPUT -p tcp --dport 993 -j ACCEPT iptables -A INPUT -j DROP My /etc/hosts file: # nameserver config # IPv4 127.0.0.1 localhost 46.4.7.93 mydomain.com 46.4.7.93 Ubuntu-1004-lucid-64-minimal 46.4.7.93 horst # IPv6 ::1 ip6-localhost ip6-loopback fe00::0 ip6-localnet ff00::0 ip6-mcastprefix ff02::1 ip6-allnodes ff02::2 ip6-allrouters ff02::3 ip6-allhosts Having a look into the iptables logs, gives me this: Jun 22 16:52:43 Ubuntu-1004-lucid-64-minimal kernel: [ 435.111780] denied-input IN=lo OUT= MAC=00:00:00:00:00:00:00:00:00:00:00:00:08:00 SRC=127.0.0.1 DST=127.0.0.1 LEN=60 TOS=0x00 PREC=0x00 TTL=64 ID=52432 DF PROTO=TCP SPT=56108 DPT=8009 WINDOW=32792 RES=0x00 SYN URGP=0 Jun 22 16:52:46 Ubuntu-1004-lucid-64-minimal kernel: [ 438.110555] denied-input IN=lo OUT= MAC=00:00:00:00:00:00:00:00:00:00:00:00:08:00 SRC=127.0.0.1 DST=127.0.0.1 LEN=60 TOS=0x00 PREC=0x00 TTL=64 ID=52433 DF PROTO=TCP SPT=56108 DPT=8009 WINDOW=32792 RES=0x00 SYN URGP=0 Jun 22 16:52:46 Ubuntu-1004-lucid-64-minimal kernel: [ 438.231954] denied-input IN=lo OUT= MAC=00:00:00:00:00:00:00:00:00:00:00:00:08:00 SRC=127.0.0.1 DST=127.0.0.1 LEN=60 TOS=0x00 PREC=0x00 TTL=64 ID=48020 DF PROTO=TCP SPT=56109 DPT=8009 WINDOW=32792 RES=0x00 SYN URGP=0 Jun 22 16:52:49 Ubuntu-1004-lucid-64-minimal kernel: [ 441.229778] denied-input IN=lo OUT= MAC=00:00:00:00:00:00:00:00:00:00:00:00:08:00 SRC=127.0.0.1 DST=127.0.0.1 LEN=60 TOS=0x00 PREC=0x00 TTL=64 ID=48021 DF PROTO=TCP SPT=56109 DPT=8009 WINDOW=32792 RES=0x00 SYN URGP=0 Jun 22 16:53:57 Ubuntu-1004-lucid-64-minimal kernel: [ 508.731839] denied-input IN=eth0 OUT= MAC=6c:62:6d:85:bf:0e:00:26:88:75:dc:01:08:00 SRC=78.92.97.67 DST=46.4.7.93 LEN=64 TOS=0x00 PREC=0x00 TTL=122 ID=23053 DF PROTO=TCP SPT=1672 DPT=445 WINDOW=65535 RES=0x00 SYN URGP=0 Jun 22 16:53:59 Ubuntu-1004-lucid-64-minimal kernel: [ 511.625038] denied-input IN=eth0 OUT= MAC=6c:62:6d:85:bf:0e:00:26:88:75:dc:01:08:00 SRC=78.92.97.67 DST=46.4.7.93 LEN=64 TOS=0x00 PREC=0x00 TTL=122 ID=23547 DF PROTO=TCP SPT=1672 DPT=445 WINDOW=65535 RES=0x00 SYN URGP=0 Jun 22 16:54:22 Ubuntu-1004-lucid-64-minimal kernel: [ 533.981995] denied-input IN=eth0 OUT= MAC=6c:62:6d:85:bf:0e:00:26:88:75:dc:01:08:00 SRC=27.254.39.16 DST=46.4.7.93 LEN=48 TOS=0x00 PREC=0x00 TTL=117 ID=6549 PROTO=TCP SPT=6005 DPT=33796 WINDOW=64240 RES=0x00 ACK SYN URGP=0 Jun 22 16:54:44 Ubuntu-1004-lucid-64-minimal kernel: [ 556.297038] denied-input IN=eth0 OUT= MAC=6c:62:6d:85:bf:0e:00:26:88:75:dc:01:08:00 SRC=94.78.93.41 DST=46.4.7.93 LEN=40 TOS=0x00 PREC=0x00 TTL=52 ID=7712 PROTO=TCP SPT=57598 DPT=445 WINDOW=512 RES=0x00 SYN URGP=0

    Read the article

  • My IIS server won't serve SSL sites to some browsers

    - by sbleon
    (Update: This is now cross-posted at http://stackoverflow.com/questions/3355000. This is the more appropriate forum, but StackOverflow gets a lot more traffic.) I've got an IIS 6.0 server that won't serve pages over SSL to some browsers. In Webkit-based browsers on OS X 10.6, I can't load pages at all. In MSIE 8 on Windows XP SP3, I can load pages, but it will sometimes hang downloading images or sending POSTs. Working: Firefox 3.6 (OS X + Windows) Chrome (Windows) Partially Working: MSIE 8 (works sometimes, but hangs up, especially on POSTs) Not Working: Chrome 5 (OS X) Safari 5 (OS X) Mobile Safari (iOS 4) On OS X (the easiest platform for me to test on), Chrome and Firefox both negotiate the same TLS Cipher, but Chrome hangs on or after the post-negotiation handshake. Chrome packet capture (via ssldump): 1 1 0.0485 (0.0485) C>S Handshake ClientHello Version 3.1 cipher suites Unknown value 0xc00a Unknown value 0xc009 Unknown value 0xc007 Unknown value 0xc008 Unknown value 0xc013 Unknown value 0xc014 Unknown value 0xc011 Unknown value 0xc012 Unknown value 0xc004 Unknown value 0xc005 Unknown value 0xc002 Unknown value 0xc003 Unknown value 0xc00e Unknown value 0xc00f Unknown value 0xc00c Unknown value 0xc00d Unknown value 0x2f TLS_RSA_WITH_RC4_128_SHA TLS_RSA_WITH_RC4_128_MD5 Unknown value 0x35 TLS_RSA_WITH_3DES_EDE_CBC_SHA Unknown value 0x32 Unknown value 0x33 Unknown value 0x38 Unknown value 0x39 TLS_DHE_RSA_WITH_3DES_EDE_CBC_SHA TLS_DHE_DSS_WITH_3DES_EDE_CBC_SHA compression methods NULL 1 2 0.3106 (0.2620) S>C Handshake ServerHello Version 3.1 session_id[32]= bb 0e 00 00 7a 7e 07 50 5e 78 48 cf 43 5a f7 4d d2 ed 72 8f ff 1d 9e 74 66 74 03 b3 bb 92 8d eb cipherSuite TLS_RSA_WITH_RC4_128_MD5 compressionMethod NULL Certificate ServerHelloDone 1 3 0.3196 (0.0090) C>S Handshake ClientKeyExchange 1 4 0.3197 (0.0000) C>S ChangeCipherSpec 1 5 0.3197 (0.0000) C>S Handshake [hang, no more data transmitted] Firefox packet capture: 1 1 0.0485 (0.0485) C>S Handshake ClientHello Version 3.1 resume [32]= 14 03 00 00 4e 28 de aa da 7a 25 87 25 32 f3 a7 ae 4c 2d a0 e4 57 cc dd d7 0e d7 82 19 f7 8f b9 cipher suites Unknown value 0xff Unknown value 0xc00a Unknown value 0xc014 Unknown value 0x88 Unknown value 0x87 Unknown value 0x39 Unknown value 0x38 Unknown value 0xc00f Unknown value 0xc005 Unknown value 0x84 Unknown value 0x35 Unknown value 0xc007 Unknown value 0xc009 Unknown value 0xc011 Unknown value 0xc013 Unknown value 0x45 Unknown value 0x44 Unknown value 0x33 Unknown value 0x32 Unknown value 0xc00c Unknown value 0xc00e Unknown value 0xc002 Unknown value 0xc004 Unknown value 0x96 Unknown value 0x41 TLS_RSA_WITH_RC4_128_MD5 TLS_RSA_WITH_RC4_128_SHA Unknown value 0x2f Unknown value 0xc008 Unknown value 0xc012 TLS_DHE_RSA_WITH_3DES_EDE_CBC_SHA TLS_DHE_DSS_WITH_3DES_EDE_CBC_SHA Unknown value 0xc00d Unknown value 0xc003 Unknown value 0xfeff TLS_RSA_WITH_3DES_EDE_CBC_SHA compression methods NULL 1 2 0.0983 (0.0497) S>C Handshake ServerHello Version 3.1 session_id[32]= 14 03 00 00 4e 28 de aa da 7a 25 87 25 32 f3 a7 ae 4c 2d a0 e4 57 cc dd d7 0e d7 82 19 f7 8f b9 cipherSuite TLS_RSA_WITH_RC4_128_MD5 compressionMethod NULL 1 3 0.0983 (0.0000) S>C ChangeCipherSpec 1 4 0.0983 (0.0000) S>C Handshake 1 5 0.1019 (0.0035) C>S ChangeCipherSpec 1 6 0.1019 (0.0000) C>S Handshake 1 7 0.1019 (0.0000) C>S application_data 1 8 0.2460 (0.1440) S>C application_data 1 9 0.3108 (0.0648) S>C application_data 1 10 0.3650 (0.0542) S>C application_data 1 11 0.4188 (0.0537) S>C application_data 1 12 0.4580 (0.0392) S>C application_data 1 13 0.4831 (0.0251) S>C application_data [etc] Update: Here's a Wireshark capture from the server end. What's going on with those two much-delayed RST packets? Is that just IIS terminating what it perceives as a non-responsive connection? 19 10.129450 67.249.xxx.xxx 10.100.xxx.xx TCP 50653 > https [SYN] Seq=0 Win=65535 Len=0 MSS=1460 WS=3 TSV=699250189 TSER=0 20 10.129517 10.100.xxx.xx 67.249.xxx.xxx TCP https > 50653 [SYN, ACK] Seq=0 Ack=1 Win=16384 Len=0 MSS=1460 WS=0 TSV=0 TSER=0 21 10.168596 67.249.xxx.xxx 10.100.xxx.xx TCP 50653 > https [ACK] Seq=1 Ack=1 Win=524280 Len=0 TSV=699250189 TSER=0 22 10.172950 67.249.xxx.xxx 10.100.xxx.xx TLSv1 Client Hello 23 10.173267 10.100.xxx.xx 67.249.xxx.xxx TCP [TCP segment of a reassembled PDU] 24 10.173297 10.100.xxx.xx 67.249.xxx.xxx TCP [TCP segment of a reassembled PDU] 25 10.385180 67.249.xxx.xxx 10.100.xxx.xx TCP 50653 > https [ACK] Seq=148 Ack=2897 Win=524280 Len=0 TSV=699250191 TSER=163006 26 10.385235 10.100.xxx.xx 67.249.xxx.xxx TLSv1 Server Hello, Certificate, Server Hello Done 27 10.424682 67.249.xxx.xxx 10.100.xxx.xx TCP 50653 > https [ACK] Seq=148 Ack=4215 Win=524280 Len=0 TSV=699250192 TSER=163008 28 10.435245 67.249.xxx.xxx 10.100.xxx.xx TLSv1 Client Key Exchange 29 10.438522 67.249.xxx.xxx 10.100.xxx.xx TLSv1 Change Cipher Spec 30 10.438553 10.100.xxx.xx 67.249.xxx.xxx TCP https > 50653 [ACK] Seq=4215 Ack=421 Win=65115 Len=0 TSV=163008 TSER=699250192 31 10.449036 67.249.xxx.xxx 10.100.xxx.xx TLSv1 Encrypted Handshake Message 32 10.580652 10.100.xxx.xx 67.249.xxx.xxx TCP https > 50653 [ACK] Seq=4215 Ack=458 Win=65078 Len=0 TSV=163010 TSER=699250192 7312 57.315338 10.100.xxx.xx 67.249.xxx.xxx TCP https > 50644 [RST, ACK] Seq=1 Ack=1 Win=0 Len=0 19531 142.316425 10.100.xxx.xx 67.249.xxx.xxx TCP https > 50653 [RST, ACK] Seq=4215 Ack=458 Win=0 Len=0

    Read the article

  • My IIS server won't serve SSL sites to some browsers

    - by sbleon
    (Update: This is now cross-posted at http://stackoverflow.com/questions/3355000. This is the more appropriate forum, but StackOverflow gets a lot more traffic.) I've got an IIS 6.0 server that won't serve pages over SSL to some browsers. In Webkit-based browsers on OS X 10.6, I can't load pages at all. In MSIE 8 on Windows XP SP3, I can load pages, but it will sometimes hang downloading images or sending POSTs. Working: Firefox 3.6 (OS X + Windows) Chrome (Windows) Partially Working: MSIE 8 (works sometimes, but hangs up, especially on POSTs) Not Working: Chrome 5 (OS X) Safari 5 (OS X) Mobile Safari (iOS 4) On OS X (the easiest platform for me to test on), Chrome and Firefox both negotiate the same TLS Cipher, but Chrome hangs on or after the post-negotiation handshake. Chrome packet capture (via ssldump): 1 1 0.0485 (0.0485) C>S Handshake ClientHello Version 3.1 cipher suites Unknown value 0xc00a Unknown value 0xc009 Unknown value 0xc007 Unknown value 0xc008 Unknown value 0xc013 Unknown value 0xc014 Unknown value 0xc011 Unknown value 0xc012 Unknown value 0xc004 Unknown value 0xc005 Unknown value 0xc002 Unknown value 0xc003 Unknown value 0xc00e Unknown value 0xc00f Unknown value 0xc00c Unknown value 0xc00d Unknown value 0x2f TLS_RSA_WITH_RC4_128_SHA TLS_RSA_WITH_RC4_128_MD5 Unknown value 0x35 TLS_RSA_WITH_3DES_EDE_CBC_SHA Unknown value 0x32 Unknown value 0x33 Unknown value 0x38 Unknown value 0x39 TLS_DHE_RSA_WITH_3DES_EDE_CBC_SHA TLS_DHE_DSS_WITH_3DES_EDE_CBC_SHA compression methods NULL 1 2 0.3106 (0.2620) S>C Handshake ServerHello Version 3.1 session_id[32]= bb 0e 00 00 7a 7e 07 50 5e 78 48 cf 43 5a f7 4d d2 ed 72 8f ff 1d 9e 74 66 74 03 b3 bb 92 8d eb cipherSuite TLS_RSA_WITH_RC4_128_MD5 compressionMethod NULL Certificate ServerHelloDone 1 3 0.3196 (0.0090) C>S Handshake ClientKeyExchange 1 4 0.3197 (0.0000) C>S ChangeCipherSpec 1 5 0.3197 (0.0000) C>S Handshake [hang, no more data transmitted] Firefox packet capture: 1 1 0.0485 (0.0485) C>S Handshake ClientHello Version 3.1 resume [32]= 14 03 00 00 4e 28 de aa da 7a 25 87 25 32 f3 a7 ae 4c 2d a0 e4 57 cc dd d7 0e d7 82 19 f7 8f b9 cipher suites Unknown value 0xff Unknown value 0xc00a Unknown value 0xc014 Unknown value 0x88 Unknown value 0x87 Unknown value 0x39 Unknown value 0x38 Unknown value 0xc00f Unknown value 0xc005 Unknown value 0x84 Unknown value 0x35 Unknown value 0xc007 Unknown value 0xc009 Unknown value 0xc011 Unknown value 0xc013 Unknown value 0x45 Unknown value 0x44 Unknown value 0x33 Unknown value 0x32 Unknown value 0xc00c Unknown value 0xc00e Unknown value 0xc002 Unknown value 0xc004 Unknown value 0x96 Unknown value 0x41 TLS_RSA_WITH_RC4_128_MD5 TLS_RSA_WITH_RC4_128_SHA Unknown value 0x2f Unknown value 0xc008 Unknown value 0xc012 TLS_DHE_RSA_WITH_3DES_EDE_CBC_SHA TLS_DHE_DSS_WITH_3DES_EDE_CBC_SHA Unknown value 0xc00d Unknown value 0xc003 Unknown value 0xfeff TLS_RSA_WITH_3DES_EDE_CBC_SHA compression methods NULL 1 2 0.0983 (0.0497) S>C Handshake ServerHello Version 3.1 session_id[32]= 14 03 00 00 4e 28 de aa da 7a 25 87 25 32 f3 a7 ae 4c 2d a0 e4 57 cc dd d7 0e d7 82 19 f7 8f b9 cipherSuite TLS_RSA_WITH_RC4_128_MD5 compressionMethod NULL 1 3 0.0983 (0.0000) S>C ChangeCipherSpec 1 4 0.0983 (0.0000) S>C Handshake 1 5 0.1019 (0.0035) C>S ChangeCipherSpec 1 6 0.1019 (0.0000) C>S Handshake 1 7 0.1019 (0.0000) C>S application_data 1 8 0.2460 (0.1440) S>C application_data 1 9 0.3108 (0.0648) S>C application_data 1 10 0.3650 (0.0542) S>C application_data 1 11 0.4188 (0.0537) S>C application_data 1 12 0.4580 (0.0392) S>C application_data 1 13 0.4831 (0.0251) S>C application_data [etc] Update: Here's a Wireshark capture from the server end. What's going on with those two much-delayed RST packets? Is that just IIS terminating what it perceives as a non-responsive connection? 19 10.129450 67.249.xxx.xxx 10.100.xxx.xx TCP 50653 > https [SYN] Seq=0 Win=65535 Len=0 MSS=1460 WS=3 TSV=699250189 TSER=0 20 10.129517 10.100.xxx.xx 67.249.xxx.xxx TCP https > 50653 [SYN, ACK] Seq=0 Ack=1 Win=16384 Len=0 MSS=1460 WS=0 TSV=0 TSER=0 21 10.168596 67.249.xxx.xxx 10.100.xxx.xx TCP 50653 > https [ACK] Seq=1 Ack=1 Win=524280 Len=0 TSV=699250189 TSER=0 22 10.172950 67.249.xxx.xxx 10.100.xxx.xx TLSv1 Client Hello 23 10.173267 10.100.xxx.xx 67.249.xxx.xxx TCP [TCP segment of a reassembled PDU] 24 10.173297 10.100.xxx.xx 67.249.xxx.xxx TCP [TCP segment of a reassembled PDU] 25 10.385180 67.249.xxx.xxx 10.100.xxx.xx TCP 50653 > https [ACK] Seq=148 Ack=2897 Win=524280 Len=0 TSV=699250191 TSER=163006 26 10.385235 10.100.xxx.xx 67.249.xxx.xxx TLSv1 Server Hello, Certificate, Server Hello Done 27 10.424682 67.249.xxx.xxx 10.100.xxx.xx TCP 50653 > https [ACK] Seq=148 Ack=4215 Win=524280 Len=0 TSV=699250192 TSER=163008 28 10.435245 67.249.xxx.xxx 10.100.xxx.xx TLSv1 Client Key Exchange 29 10.438522 67.249.xxx.xxx 10.100.xxx.xx TLSv1 Change Cipher Spec 30 10.438553 10.100.xxx.xx 67.249.xxx.xxx TCP https > 50653 [ACK] Seq=4215 Ack=421 Win=65115 Len=0 TSV=163008 TSER=699250192 31 10.449036 67.249.xxx.xxx 10.100.xxx.xx TLSv1 Encrypted Handshake Message 32 10.580652 10.100.xxx.xx 67.249.xxx.xxx TCP https > 50653 [ACK] Seq=4215 Ack=458 Win=65078 Len=0 TSV=163010 TSER=699250192 7312 57.315338 10.100.xxx.xx 67.249.xxx.xxx TCP https > 50644 [RST, ACK] Seq=1 Ack=1 Win=0 Len=0 19531 142.316425 10.100.xxx.xx 67.249.xxx.xxx TCP https > 50653 [RST, ACK] Seq=4215 Ack=458 Win=0 Len=0

    Read the article

  • mixed declarations and codes

    - by gcc
    When I compile function with "gcc -o dene -Wall -ansi -pedantic-errors dene.c",gcc emits no error.(can you look a line which starts with char ....,in if loop,) static void remove_negation(char *s,char *s1) { char **cmainp=malloc(sizeof(char*)*1); int len=0;int d=0; int i=0; cmainp[0]=malloc(sizeof(char)*300); len=strlen(s); for(i=0;i<len;++i) { if(s[i]=='-') if(i==0 || s[i-1]==',') /*look*/ {char *p=malloc(sizeof(char)*3); /*look*/ ++i; p[0]=s[i]; p[1]='\0'; strcat(s1,","); strcat(s1,p); free(p); continue; } cmainp[0][d]=s[i]; ++d; } cmainp[0][d+1]='\0'; strcpy(cmainp[0],s); free(cmainp[0]); } But,when compile above function being reformatted with gcc,gcc emits that error "dene.c:10: error: ISO C90 forbids mixed declarations and code" static void remove_negation(char *s,char *s1) { char **cmainp=malloc(sizeof(char*)*1); /*look*/ cmainp[0]=malloc(sizeof(char)*300); /*look*/ int len=0;int d=0; int i=0; len=strlen(s); for(i=0;i<len;++i) { if(s[i]=='-') if(i==0 || s[i-1]==',') {char *p=malloc(sizeof(char)*3); ++i; p[0]=s[i]; p[1]='\0'; strcat(s1,","); strcat(s1,p); free(p); continue; } cmainp[0][d]=s[i]; ++d; } cmainp[0][d+1]='\0'; strcpy(cmainp[0],s); free(cmainp[0]); } And last one,gcc emits following errors dene.c:16: error: expected expression before ‘char’ dene.c:20: error: ‘p1’ undeclared (first use in this function) dene.c:20: error: (Each undeclared identifier is reported only once dene.c:20: error: for each function it appears in.) static void remove_negation(char *s,char *s1) { char **cmainp=malloc(sizeof(char*)*1); /*look*/ cmainp[0]=malloc(sizeof(char)*300); /*look*/ int len=0;int d=0; int i=0; len=strlen(s); for(i=0;i<len;++i) { if(s[i]=='-') /*look*/ char *p=malloc(sizeof(char)*3); /*look*/ if(i==0 || s[i-1]==',') { ++i; p[0]=s[i]; p[1]='\0'; strcat(s1,","); strcat(s1,p); free(p); continue; } cmainp[0][d]=s[i]; ++d; } cmainp[0][d+1]='\0'; strcpy(cmainp[0],s); free(cmainp[0]); } question is why there are differences between them.

    Read the article

  • Urban Turtle is such an awesome product !

    - by Vincent Grondin
    Mario Cardinal, the host of the Visual Studio Talk Show, is quite happy these days. He works with the Urban Turtle team and they received significant support from Microsoft. Brian Harry, who is the Product Unit Manager for Team Foundation Server, has published an outstanding blog post about Urban Turtle that says: "...awesome Scrum experience for TFS.” You can read Brian Harry's blog post at the following URL: http://urbanturtle.com/awesome.

    Read the article

  • Learning Python and trying to get first two letters and last two letters of a string.

    - by Sergio Tapia
    Here's my code: # B. both_ends # Given a string s, return a string made of the first 2 # and the last 2 chars of the original string, # so 'spring' yields 'spng'. However, if the string length # is less than 2, return instead the empty string. def both_ends(s): if len(s) <= 2: return "" else: return s[0] + s[1] + s[len(s)-2] + s[len(s-1)] # +++your code here+++ return Unfortunately my program doesn't run. :( I'm sure I'm overlooking something since I'm a newbie with Python. Here's the error: > Traceback (most recent call last): File "C:\Users\Sergio\Desktop\google-python-exercises\google-python-exercises\basic\string1.py", line 120, in <module> main() File "C:\Users\Sergio\Desktop\google-python-exercises\google-python-exercises\basic\string1.py", line 97, in main test(both_ends('spring'), 'spng') File "C:\Users\Sergio\Desktop\google-python-exercises\google-python-exercises\basic\string1.py", line 44, in both_ends return s[0] + s[1] + s[len(s)-2] + s[len(s-1)] TypeError: unsupported operand type(s) for -: 'str' and 'int' Thanks for the help guys. :D

    Read the article

  • What Am I Missing? : iPhone Objective-C NSInputStream initWithData

    - by gabe
    I'm creating an NSInputStream from an NSData object but once created the stream reports NO for hasBytesAvailable: NSData* data = [outputStream propertyForKey: NSStreamDataWrittenToMemoryStreamKey]; NSLog(@"creating stream with data 0x%x length %d", [data bytes], [data length]); NSInputStream *insrm = [[NSInputStream alloc] initWithData:data]; [insrm open]; uint8_t* buf = NULL; NSUInteger len; BOOL result = [insrm getBuffer:&buf length:&len]; BOOL hasbytes = [insrm hasBytesAvailable]; NSLog(@"getBuffer:%d hasBytes:%d", result, hasbytes); NSLog(@"created inputstream data %d len %d", buf, len); Log: [26797:20b] creating stream with data 0x7050000 length 34672 [26797:20b] getBuffer:0 hasBytes:0 [26797:20b] created inputstream data 0 len 0 What am I missing here?

    Read the article

  • Python beginner, strange output problem

    - by Protean
    I'm having a weird problem with the following piece of code. from math import sqrt def Permute(array): result1 = [] result2 = [] if len(array) <= 1: return array for subarray in Permute(array[1:]): for i in range(len(array)): temp1 = subarray[:i]+array[0]+subarray[i:] temp2 = [0] for num in range(len(array)-1): temp2[0] += (sqrt(pow((temp1[num+1][1][0]-temp1[num][1][0]),2) + pow((temp1[num+1][1][1]-temp1[num][1][1]),2))) result1.append(temp1+temp2) return result1 a = [['A',[50,1]]] b = [['B',[1,1]]] c = [['C',[100,1]]] array = [a,b,c] result1 = Permute(array) for i in range(len(result1)): print (result1[i]) print (len(result1)) What it does is find all the permutations of the points abc and then returns them along with the sum of the distances between each ordered point. It does this; however, it also seems to report a strange additional value, 99. I figure that the 99 is coming from the computation of the distance between point a and c but I don't understand why it is appearing in the final output as it does.

    Read the article

  • SQL MIN in Sub query causes huge delay

    - by Spencer
    I have a SQL query that I'm trying to debug. It works fine for small sets of data, but in large sets of data, this particular part of it causes it to take 45-50 seconds instead of being sub second in speed. This subquery is one of the select items in a larger query. I'm basically trying to figure out when the earliest work date is that fits in the same category as the current row we are looking at (from table dr) ISNULL(CONVERT(varchar(25),(SELECT MIN(drsd.DateWorked) FROM [TableName] drsd WHERE drsd.UserID = dr.UserID AND drsd.Val1 = dr.Val1 OR (((drsd.Val2 = dr.Val2 AND LEN(dr.Val2) > 0) AND (drsd.Val3 = dr.Val3 AND LEN(dr.Val3) > 0) AND (drsd.Val4 = dr.Val4 AND LEN(dr.Val4) > 0)) OR (drsd.Val5 = dr.Val5 AND LEN(dr.Val5) > 0) OR ((drsd.Val6 = dr.Val6 AND LEN(dr.Val6) > 0) AND (drsd.Val7 = dr.Val7 AND LEN(dr.Val2) > 0))))), '') AS WorkStartDate, This winds up executing a key lookup some 18 million times on a table that has 346,000 records. I've tried creating an index on it, but haven't had any success. Also, selecting a max value in this same query is sub second in time, as it doesn't have to execute very many times at all. Any suggestions of a different approach to try? Thanks!

    Read the article

  • Lisp Style question label local functions or not?

    - by Andrew Myers
    I was wondering if there is a standard practice regarding the use of labels in Lisp. I've been messing around with a Lisp implementation of the algorithm described in the first answer here http://stackoverflow.com/questions/352203/generating-permutations-lazily My current version uses labels to break out portions of functionality. (defun next-permutation (pmute) (declare (vector pmute)) (let ((len (length pmute))) (if (> len 2) (labels ((get-pivot () (do ((pivot (1- len) (1- pivot))) ((or (= pivot 0) (< (aref pmute (1- pivot)) (aref pmute pivot))) pivot))) (get-swap (pivot) (let ((swp (1- len))) (loop for i from (1- len) downto pivot do (if (or (and (> (aref pmute i) (aref pmute (1- pivot))) (< (aref pmute i) (aref pmute swp))) (< (aref pmute swp) (aref pmute (1- pivot)))) (setf swp i))) swp)) (next (swp pivot) (rotatef (aref pmute (1- pivot)) (aref pmute swp)) (reverse-vector pmute pivot (1- len)))) (let ((piv (get-pivot))) (if (> piv 0) (next (get-swap piv) piv) nil)))))) Since each label is only called once I was wondering if this is considered bad practice since the only reason to do it in this case is for aesthetic reasons. I would argue that the current version with labels is clearer but that may go against common wisdom that I'm not aware of, being new to Lisp.

    Read the article

  • C# PInvoke VerQueryValue returns back OutOfMemoryException?

    - by Bopha
    Hi, Below is the code sample which I got from online resource but it's suppose to work with fullframework, but when I try to build it using C# smart device, it throws exception saying it's out of memory. Does anybody know how can I fix it to use on compact? the out of memory exception when I make the second call to VerQueryValue which is the last one. thanks, [DllImport("coredll.dll")] public static extern bool VerQueryValue(byte[] buffer, string subblock, out IntPtr blockbuffer, out uint len); [DllImport("coredll.dll")] public static extern bool VerQueryValue(byte[] pBlock, string pSubBlock, out string pValue, out uint len); // private static void GetAssemblyVersion() { string filename = @"\Windows\MyLibrary.dll"; if (File.Exists(filename)) { try { int handle = 0; Int32 size = 0; size = GetFileVersionInfoSize(filename, out handle); if (size > 0) { bool retValue; byte[] buffer = new byte[size]; retValue = GetFileVersionInfo(filename, handle, size, buffer); if (retValue == true) { bool success = false; IntPtr blockbuffer = IntPtr.Zero; uint len = 0; //success = VerQueryValue(buffer, "\\", out blockbuffer, out len); success = VerQueryValue(buffer, @"\VarFileInfo\Translation", out blockbuffer, out len); if(success) { int p = (int)blockbuffer; //Reads a 16-bit signed integer from unmanaged memory int j = Marshal.ReadInt16((IntPtr)p); p += 2; //Reads a 16-bit signed integer from unmanaged memory int k = Marshal.ReadInt16((IntPtr)p); string sb = string.Format("{0:X4}{1:X4}", j, k); string spv = @"\StringFileInfo\" + sb + @"\ProductVersion"; string versionInfo; VerQueryValue(buffer, spv, out versionInfo, out len); } } } } catch (Exception err) { string error = err.Message; } } }

    Read the article

  • GZIP Java vs .NET

    - by Jim Jones
    Using the following Java code to compress/decompress bytes[] to/from GZIP. First text bytes to gzip bytes: public static byte[] fromByteToGByte(byte[] bytes) { ByteArrayOutputStream baos = null; try { ByteArrayInputStream bais = new ByteArrayInputStream(bytes); baos = new ByteArrayOutputStream(); GZIPOutputStream gzos = new GZIPOutputStream(baos); byte[] buffer = new byte[1024]; int len; while((len = bais.read(buffer)) >= 0) { gzos.write(buffer, 0, len); } gzos.close(); baos.close(); } catch (IOException e) { e.printStackTrace(); } return(baos.toByteArray()); } Then the method that goes the other way compressed bytes to uncompressed bytes: public static byte[] fromGByteToByte(byte[] gbytes) { ByteArrayOutputStream baos = null; ByteArrayInputStream bais = new ByteArrayInputStream(gbytes); try { baos = new ByteArrayOutputStream(); GZIPInputStream gzis = new GZIPInputStream(bais); byte[] bytes = new byte[1024]; int len; while((len = gzis.read(bytes)) > 0) { baos.write(bytes, 0, len); } } catch (IOException e) { e.printStackTrace(); } return(baos.toByteArray()); } Think there is any effect since I'm not writing out to a gzip file? Also I noticed that in the standard C# function that BitConverter reads the first four bytes and then the MemoryStream Write function is called with a start point of 4 and a length of input buffer length - 4. So is that effect the validity of the header? Jim

    Read the article

  • going reverse in a for loop?

    - by sil3nt
    Hello there, Basically i got this for loop and i want the number inputed (eg. 123) to be printed out in reverse, so "321". so far it works fine and prints out the correct order when the for loop is for(i = 0; i<len ; i++) but i get an error when i try to print it in reverse?. Whats going wrong? #include <stdio.h> #include <string.h> void cnvrter(char *number); int main(){ char number[80]; printf("enter a number "); gets(number); cnvrter(number); return 0; } void cnvrter(char *number){ char tmp[80]; int i = 0,len = 0; int cnvrtd_digit = 0; len = strlen(number); printf("\nsize of input %d\n",len); for(i = len; i>len ; i--){ if ( ( number[i] >= '0' ) && ( number[i]<='9' ) ){ tmp[0] = number[i]; sscanf(tmp,"%d",&cnvrtd_digit); } printf("%d\n",cnvrtd_digit); } }

    Read the article

  • convert an int to list of individual digitals more faster?

    - by user478514
    All, I want define an int(987654321) <= [9, 8, 7, 6, 5, 4, 3, 2, 1] convertor, if the length of int number < 9, for example 10 the list will be [0,0,0,0,0,0,0,1,0] , and if the length 9, for example 9987654321 , the list will be [9, 9, 8, 7, 6, 5, 4, 3, 2, 1] >>> i 987654321 >>> l [9, 8, 7, 6, 5, 4, 3, 2, 1] >>> z = [0]*(len(unit) - len(str(l))) >>> z.extend(l) >>> l = z >>> unit [100000000, 10000000, 1000000, 100000, 10000, 1000, 100, 10, 1] >>> sum([x*y for x,y in zip(l, unit)]) 987654321 >>> int("".join([str(x) for x in l])) 987654321 >>> l1 = [int(x) for x in str(i)] >>> z = [0]*(len(unit) - len(str(l1))) >>> z.extend(l1) >>> l1 = z >>> l1 [9, 8, 7, 6, 5, 4, 3, 2, 1] >>> a = [i//x for x in unit] >>> b = [a[x] - a[x-1]*10 for x in range(9)] >>> if len(b) = len(a): b[0] = a[0] # fix the a[-1] issue >>> b [9, 8, 7, 6, 5, 4, 3, 2, 1] I tested above solutions but found those may not faster/simple enough than I want and may have a length related bug inside, anyone may share me a better solution for this kinds convertion? Thanks!

    Read the article

  • So, I guess I can't use "&&" in the Python if conditional. What should I use in this case? Any help?

    - by Sergio Tapia
    Here's my code: # F. front_back # Consider dividing a string into two halves. # If the length is even, the front and back halves are the same length. # If the length is odd, we'll say that the extra char goes in the front half. # e.g. 'abcde', the front half is 'abc', the back half 'de'. # Given 2 strings, a and b, return a string of the form # a-front + b-front + a-back + b-back def front_back(a, b): # +++your code here+++ if len(a) % 2 == 0 && len(b) % 2 == 0: return a[:(len(a)/2)] + b[:(len(b)/2)] + a[(len(a)/2):] + b[(len(b)/2):] else: #todo! Not yet done. :P return I'm getting an error in the IF conditional. What am I doing wrong? Edit: I meant no arrogance here. Someone edited my question title to make it sound douchy. I was genuinely confused about what to use, didn't think 'and' would be a keyword. Please don't downvote as other newbies might be confused about it as well.

    Read the article

  • Best way to determine surface normal for a group of pixels?

    - by Paul Renton
    One of my current endeavors is creating a 2D destructible terrain engine for iOS Cocos2D (See https://github.com/crebstar/PWNDestructibleTerrain ). It is in an infant stages no doubt, but I have made significant progress since starting a couple weeks ago. However, I have run into a bit of a performance road block with calculating surface normals. Note: For my destructible terrain engine, an alpha of 0 is considered to not be solid ground. The method posted below works just great given small rectangles, such as n < 30. Anything above 30 causes a dip in the frame rate. If you approach 100x100 then you might as well read a book while the sprite attempts to traverse the terrain. At the moment this is the best I can come up with for altering the angle on a sprite as it roams across terrain (to get the angle for a sprite's orientation just take dot product of 100 * normal * (1,0) vector). -(CGPoint)getAverageSurfaceNormalAt:(CGPoint)pt withRect:(CGRect)area { float avgX = 0; float avgY = 0; ccColor4B color = ccc4(0, 0, 0, 0); CGPoint normal; float len; for (int w = area.size.width; w >= -area.size.width; w--) { for (int h = area.size.height; h >= -area.size.height; h--) { CGPoint pixPt = ccp(w + pt.x, h + pt.y); if ([self pixelAt:pixPt colorCache:&color]) { if (color.a != 0) { avgX -= w; avgY -= h; } // end inner if } // end outer if } // end inner for } // end outer for len = sqrtf(avgX * avgX + avgY * avgY); if (len == 0) { normal = ccp(avgX, avgY); } else { normal = ccp(avgX/len, avgY/len); } // end if return normal; } // end get My problem is I have sprites that require larger rectangles in order for their movement to look realistic. I considered doing a cache of all surface normals, but this lead to issues of knowing when to recalculate the surface normals and these calculations also being quite expensive (also how large should the blocks be?). Another smaller issue is I don't know how to properly treat the case when length is = 0. So I am stuck... Any advice from the community would be greatly appreciated! Is my method the best possible one? Or should I rethink the algorithm? I am new to game development and always looking to learn new tips and tricks.

    Read the article

  • C Programming - My program is good enough for my assignment but I know its not good

    - by Joe
    Hi there I'm just starting an assignment for uni and it's raised a question for me. I don't understand how to return a string from a function without having a memory leak. char* trim(char* line) { int start = 0; int end = strlen(line) - 1; /* find the start position of the string */ while(isspace(line[start]) != 0) { start++; } //printf("start is %d\n", start); /* find the position end of the string */ while(isspace(line[end]) != 0) { end--; } //printf("end is %d\n", end); /* calculate string length and add 1 for the sentinel */ int len = end - start + 2; /* initialise char array to len and read in characters */ int i; char* trimmed = calloc(sizeof(char), len); for(i = 0; i < (len - 1); i++) { trimmed[i] = line[start + i]; } trimmed[len - 1] = '\0'; return trimmed; } as you can see I am returning a pointer to char which is an array. I found that if I tried to make the 'trimmed' array by something like: char trimmed[len]; then the compiler would throw up a message saying that a constant was expected on this line. I assume this meant that for some reason you can't use variables as the array length when initialising an array, although something tells me that can't be right. So instead I made my array by allocating some memory to a char pointer. I understand that this function is probably waaaaay sub-optimal for what it is trying to do, but what I really want to know is: 1. Can you normally initialise an array using a variable to declare the length like: char trimmed[len]; ? 2. If I had an array that was of that type (char trimmed[]) would it have the same return type as a pointer to char (ie char*). 3. If I make my array by callocing some memory and allocating it to a char pointer, how do I free this memory. It seems to me that once I have returned this array, I can't access it to free it as it is a local variable. Many thanks in advance Joe

    Read the article

  • Strange behavior of std::cout &operator<<...

    - by themoondothshine
    Hey ppl, I came across something weird today, and I was wondering if any of you here could explain what's happening... Here's a sample: #include <iostream> #include <cassert> using namespace std; #define REQUIRE_STRING(s) assert(s != 0) #define REQUIRE_STRING_LEN(s, n) assert(s != 0 || n == 0) class String { public: String(const char *str, size_t len) : __data(__construct(str, len)), __len(len) {} ~String() { __destroy(__data); } const char *toString() const { return const_cast<const char *>(__data); } String &toUpper() { REQUIRE_STRING_LEN(__data, __len); char *it = __data; while(it < __data + __len) { if(*it >= 'a' && *it <= 'z') *it -= 32; ++it; } return *this; } String &toLower() { REQUIRE_STRING_LEN(__data, __len); char *it = __data; while(it < __data + __len) { if(*it >= 'A' && *it <= 'Z') *it += 32; ++it; } return *this; } private: char *__data; size_t __len; protected: static char *__construct(const char *str, size_t len) { REQUIRE_STRING_LEN(str, len); char *data = new char[len]; std::copy(str, str + len, data); return data; } static void __destroy(char *data) { REQUIRE_STRING(data); delete[] data; } }; int main() { String s("Hello world!", __builtin_strlen("Hello world!")); cout << s.toLower().toString() << endl; cout << s.toUpper().toString() << endl; cout << s.toLower().toString() << endl << s.toUpper().toString() << endl; return 0; } Now, I had expected the output to be: hello world! HELLO WORLD! hello world! HELLO WORLD! but instead I got this: hello world! HELLO WORLD! hello world! hello world! I can't really understand why the second toUpper didn't have any effect.

    Read the article

  • How is the MTU is 65535 in UDP but ethernet does not allow frame size more than 1500 bytes

    - by nikku
    I am using a fast ethernet of 100 Mbps, whose frame size is less than 1500 bytes (1472 bytes for payload as per my textbook). In that, I was able to send and receive a UDP packet of message size 65507 bytes, which means the packet size was 65507 + 20 (IP Header) + 8 (UDP Header) = 65535. If the frame's payload size itself is maximum of 1472 bytes (as per my textbook), how can the packet size of IP be greater than that which here is 65535? I used sender code as char buffer[100000]; for (int i = 1; i < 100000; i++) { int len = send (socket_id, buffer, i); printf("%d\n", len); } Receiver code as while (len = recv (socket_id, buffer, 100000)) { printf("%d\n". len); } I observed that send returns -1 on i > 65507 and recv prints or receives a packet of maximum of length 65507.

    Read the article

  • Shorewall log question.

    - by Shikoru
    I have been getting various attempts to connect to ports on my shorewall firewall. The ports that I keep seeing connection attempts at are tcp 44444, tcp 44446, udp 55555 and every now and then some slight variation. I ran "netstat -a" and did not see anything listening on those ports. Is this something that I should be worried about or is it just some rouge computers out there? I have noticed alot of the ip addresses are from Spain and Mexico. May 25 18:39:35 Takkun kernel: [62516.626514] Shorewall:net2fw:DROP:IN=eth0 OUT= MAC=00:d0:b7:65:d4:13:34:ef:xx:xx:xx:81:08:00 SRC=200.124.9.113 DST=72.xxx.xxx.xxx LEN=48 TOS=0x00 PREC=0x00 TTL=112 ID=51796 DF PROTO=TCP SPT=2071 DPT=44446 WINDOW=16384 RES=0x00 SYN URGP=0 May 25 18:39:52 Takkun kernel: [62535.433285] Shorewall:net2fw:DROP:IN=eth0 OUT= MAC=00:d0:b7:65:d4:13:34:ef:xx:xx:xx:81:08:00 SRC=72.50.95.174 DST=72.xxx.xxx.xxx LEN=90 TOS=0x00 PREC=0x00 TTL=105 ID=31130 PROTO=UDP SPT=59505 DPT=55555 LEN=70 May 25 18:40:05 Takkun kernel: [62548.963413] Shorewall:net2fw:DROP:IN=eth0 OUT= MAC=00:d0:b7:65:d4:13:34:ef:xx:xx:xx:81:08:00 SRC=77.12.37.1 DST=72.xxx.xxx.xxx LEN=90 TOS=0x00 PREC=0x00 TTL=108 ID=9585 PROTO=UDP SPT=20401 DPT=55555 LEN=70 That is the jist of what im seeing.

    Read the article

  • How is the MTU is 65535 in UDP but ethernet does not allow frame size more than 1500 bytes

    - by nikku
    I am using a fast ethernet of 100 Mbps, whose frame size is less than 1500 bytes (1472 bytes for payload as per my textbook). In that, I was able to send and receive a UDP packet of message size 65507 bytes, which means the packet size was 65507 + 20 (IP Header) + 8 (UDP Header) = 65535. If the frame's payload size itself is maximum of 1472 bytes (as per my textbook), how can the packet size of IP be greater than that which here is 65535? I used sender code as char buffer[100000]; for (int i = 1; i < 100000; i++) { int len = send (socket_id, buffer, i); printf("%d\n", len); } Receiver code as while (len = recv (socket_id, buffer, 100000)) { printf("%d\n". len); } I observed that send returns -1 on i > 65507 and recv prints or receives a packet of maximum of length 65507.

    Read the article

  • Which GPO is making my Domain Controller my clients' DNS server?

    - by Harry Muscle
    I maintain a small domain (about 20 clients) and we need to make some changes to the DNS server that's being used by the clients. All the clients have been hard coded to use the domain controller as their DNS. Since these are new machines, and I never changed their DNS settings, I'm guessing there must be a GPO that's causing them to use the domain controller as their DNS. Since we don't have any GPO other than the default one yet, it's got to be the default GPO, however, I have looked through all the GPO settings and none of them refer to anything related to DNS. So I'm wondering if there's anything else that might be causing this. Any help or advice is highly appreciated. Thanks, Harry

    Read the article

< Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >