Search Results

Search found 1472 results on 59 pages for 'harry len'.

Page 4/59 | < Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >

• Why do UInt16 arrays seem to add faster than int arrays?

  - by scraimer

  It seems that C# is faster at adding two arrays of UInt16[] than it is at adding two arrays of int[]. This makes no sense to me, since I would have assumed the arrays would be word-aligned, and thus int[] would require less work from the CPU, no? I ran the test-code below, and got the following results: Int for 1000 took 9896625613 tick (4227 msec) UInt16 for 1000 took 6297688551 tick (2689 msec) The test code does the following: Creates two arrays named a and b, once. Fills them with random data, once. Starts a stopwatch. Adds a and b, item-by-item. This is done 1000 times. Stops the stopwatch. Reports how long it took. This is done for int[] a, b and for UInt16 a,b. And every time I run the code, the tests for the UInt16 arrays take 30%-50% less time than the int arrays. Can you explain this to me? Here's the code, if you want to try if for yourself: public static UInt16[] GenerateRandomDataUInt16(int length) { UInt16[] noise = new UInt16[length]; Random random = new Random((int)DateTime.Now.Ticks); for (int i = 0; i < length; ++i) { noise[i] = (UInt16)random.Next(); } return noise; } public static int[] GenerateRandomDataInt(int length) { int[] noise = new int[length]; Random random = new Random((int)DateTime.Now.Ticks); for (int i = 0; i < length; ++i) { noise[i] = (int)random.Next(); } return noise; } public static int[] AddInt(int[] a, int[] b) { int len = a.Length; int[] result = new int[len]; for (int i = 0; i < len; ++i) { result[i] = (int)(a[i] + b[i]); } return result; } public static UInt16[] AddUInt16(UInt16[] a, UInt16[] b) { int len = a.Length; UInt16[] result = new UInt16[len]; for (int i = 0; i < len; ++i) { result[i] = (ushort)(a[i] + b[i]); } return result; } public static void Main() { int count = 1000; int len = 128 * 6000; int[] aInt = GenerateRandomDataInt(len); int[] bInt = GenerateRandomDataInt(len); Stopwatch s = new Stopwatch(); s.Start(); for (int i=0; i<count; ++i) { int[] resultInt = AddInt(aInt, bInt); } s.Stop(); Console.WriteLine("Int for " + count + " took " + s.ElapsedTicks + " tick (" + s.ElapsedMilliseconds + " msec)"); UInt16[] aUInt16 = GenerateRandomDataUInt16(len); UInt16[] bUInt16 = GenerateRandomDataUInt16(len); s = new Stopwatch(); s.Start(); for (int i=0; i<count; ++i) { UInt16[] resultUInt16 = AddUInt16(aUInt16, bUInt16); } s.Stop(); Console.WriteLine("UInt16 for " + count + " took " + s.ElapsedTicks + " tick (" + s.ElapsedMilliseconds + " msec)"); }

  Read the article

• Java CORBA Client Disconnects Immediately

  - by Benny

  I have built a Java CORBA application that subscribes to an event server. The application narrows and logs on just fine, but as soon as an event is sent to the client, it breaks with the error below. Please advise. 2010/04/25!13.00.00!E00555!enserver!EventServiceIF_i.cpp!655!PID(7390)!enserver - e._info=system exception, ID 'IDL:omg.org/CORBA/TRANSIENT:1.0' TAO exception, minor code = 54410093 (invocation connect failed; ECONNRESET), completed = NO EDIT: Please note, this only happens when running on some machines. It works on some, but not others. Even on the same platform (I've tried Windows XP/7 and CentOS linux) Some work, some don't... Here is the WireShark output...looks like the working PC is much more interactive with the network compared to the non-working PC. Working PC No. Time Source Destination Protocol Info 62 28.837255 10.10.10.209 10.10.10.250 TCP 50169 > 23120 [SYN] Seq=0 Win=8192 Len=0 MSS=1260 WS=8 63 28.907068 fe80::5de0:8d21:937e:c649 ff02::1:3 LLMNR Standard query A isatap 64 28.907166 10.10.10.209 224.0.0.252 LLMNR Standard query A isatap 65 29.107259 10.10.10.209 10.255.255.255 NBNS Name query NB ISATAP<00> 66 29.227000 10.10.10.250 10.10.10.209 TCP 23120 > 50169 [SYN, ACK] Seq=0 Ack=1 Win=32768 Len=0 MSS=1260 WS=0 67 29.227032 10.10.10.209 10.10.10.250 TCP 50169 > 23120 [ACK] Seq=1 Ack=1 Win=66560 Len=0 68 29.238063 10.10.10.209 10.10.10.250 GIOP GIOP 1.1 Request s=326 id=5 (two-way): op=logon 69 29.291765 10.10.10.250 10.10.10.209 GIOP GIOP 1.1 Reply s=420 id=5: No Exception 70 29.301395 10.10.10.209 10.10.10.250 GIOP GIOP 1.1 Request s=369 id=6 (two-way): op=registerEventStat 71 29.348275 10.10.10.250 10.10.10.209 GIOP GIOP 1.1 Reply s=60 id=6: No Exception 72 29.405250 10.10.10.209 10.10.10.250 TCP 50170 > telnet [SYN] Seq=0 Win=8192 Len=0 MSS=1260 WS=8 73 29.446055 10.10.10.250 10.10.10.209 TCP telnet > 50170 [SYN, ACK] Seq=0 Ack=1 Win=32768 Len=0 MSS=1260 WS=0 74 29.446128 10.10.10.209 10.10.10.250 TCP 50170 > telnet [ACK] Seq=1 Ack=1 Win=66560 Len=0 75 29.452021 10.10.10.209 10.10.10.250 TELNET Telnet Data ... 76 29.483537 10.10.10.250 10.10.10.209 TELNET Telnet Data ... 77 29.483651 10.10.10.209 10.10.10.250 TELNET Telnet Data ... 78 29.523463 10.10.10.250 10.10.10.209 TCP telnet > 50170 [ACK] Seq=4 Ack=5 Win=32768 Len=0 79 29.554954 10.10.10.209 10.10.10.250 TCP 50169 > 23120 [ACK] Seq=720 Ack=505 Win=66048 Len=0 Non-working PC No. Time Source Destination Protocol Info 1 0.000000 10.10.10.209 10.10.10.250 TCP 64161 > 23120 [SYN] Seq=0 Win=8192 Len=0 MSS=1260 WS=8 2 2.999847 10.10.10.209 10.10.10.250 TCP 64161 > 23120 [SYN] Seq=0 Win=8192 Len=0 MSS=1260 WS=8 3 4.540773 Cisco_3c:78:00 Cisco-Li_55:87:72 ARP Who has 10.0.0.1? Tell 10.10.10.209 4 4.540843 Cisco-Li_55:87:72 Cisco_3c:78:00 ARP 10.0.0.1 is at 00:1a:70:55:87:72 5 8.992284 10.10.10.209 10.10.10.250 TCP 64161 > 23120 [SYN] Seq=0 Win=8192 Len=0 MSS=1260

  Read the article

• [Wireless LAN]hostapd is giving error whwn running in target board

  - by Renjith G

  hi, I got the following error when i tried to run the hostapd command in my target board. Any idea about this? /etc # hostapd -dd hostapd.conf Configuration file: hostapd.conf madwifi_set_iface_flags: dev_up=0 madwifi_set_privacy: enabled=0 BSS count 1, BSSID mask ff:ff:ff:ff:ff:ff (0 bits) Flushing old station entries madwifi_sta_deauth: addr=ff:ff:ff:ff:ff:ff reason_code=3 ioctl[IEEE80211_IOCTL_SETMLME]: Invalid argument madwifi_sta_deauth: Failed to deauth STA (addr ff:ff:ff:ff:ff:ff reason 3) Could not connect to kernel driver. Deauthenticate all stations madwifi_sta_deauth: addr=ff:ff:ff:ff:ff:ff reason_code=2 ioctl[IEEE80211_IOCTL_SETMLME]: Invalid argument madwifi_sta_deauth: Failed to deauth STA (addr ff:ff:ff:ff:ff:ff reason 2) madwifi_set_privacy: enabled=0 madwifi_del_key: addr=00:00:00:00:00:00 key_idx=0 madwifi_del_key: addr=00:00:00:00:00:00 key_idx=1 madwifi_del_key: addr=00:00:00:00:00:00 key_idx=2 madwifi_del_key: addr=00:00:00:00:00:00 key_idx=3 Using interface ath0 with hwaddr 00:0b:6b:33:8c:30 and ssid '"RG_WLAN Testing Renjith G"' SSID - hexdump_ascii(len=27): 22 52 47 5f 57 4c 41 4e 20 54 65 73 74 69 6e 67 "RG_WLAN Testing 20 52 65 6e 6a 69 74 68 20 47 22 Renjith G" PSK (ASCII passphrase) - hexdump_ascii(len=12): 6d 79 70 61 73 73 70 68 72 61 73 65 mypassphrase PSK (from passphrase) - hexdump(len=32): 70 6f a6 92 da 9c a8 3b ff 36 85 76 f3 11 9c 5e 5d 4a 4b 79 f4 4e 18 f6 b1 b8 09 af 6c 9c 6c 21 madwifi_set_ieee8021x: enabled=1 madwifi_configure_wpa: group key cipher=1 madwifi_configure_wpa: pairwise key ciphers=0xa madwifi_configure_wpa: key management algorithms=0x2 madwifi_configure_wpa: rsn capabilities=0x0 madwifi_configure_wpa: enable WPA=0x1 WPA: group state machine entering state GTK_INIT (VLAN-ID 0) GMK - hexdump(len=32): [REMOVED] GTK - hexdump(len=32): [REMOVED] WPA: group state machine entering state SETKEYSDONE (VLAN-ID 0) madwifi_set_key: alg=TKIP addr=00:00:00:00:00:00 key_idx=1 madwifi_set_privacy: enabled=1 madwifi_set_iface_flags: dev_up=1 ath0: Setup of interface done. l2_packet_receive - recvfrom: Network is down Wireless event: cmd=0x8b1a len=40 Register Fail Register Fail WPA: group state machine entering state SETKEYS (VLAN-ID 0) GMK - hexdump(len=32): [REMOVED] GTK - hexdump(len=32): [REMOVED] wpa_group_setkeys: GKeyDoneStations=0 WPA: group state machine entering state SETKEYSDONE (VLAN-ID 0) madwifi_set_key: alg=TKIP addr=00:00:00:00:00:00 key_idx=2 Signal 2 received - terminating Flushing old station entries madwifi_sta_deauth: addr=ff:ff:ff:ff:ff:ff reason_code=3 ioctl[IEEE80211_IOCTL_SETMLME]: Invalid argument madwifi_sta_deauth: Failed to deauth STA (addr ff:ff:ff:ff:ff:ff reason 3) Could not connect to kernel driver. Deauthenticate all stations madwifi_sta_deauth: addr=ff:ff:ff:ff:ff:ff reason_code=2 ioctl[IEEE80211_IOCTL_SETMLME]: Invalid argument madwifi_sta_deauth: Failed to deauth STA (addr ff:ff:ff:ff:ff:ff reason 2) madwifi_set_privacy: enabled=0 madwifi_set_ieee8021x: enabled=0 madwifi_set_iface_flags: dev_up=0

  Read the article

• So, I guess I can't use "&&" in the Python if conditional. Any help?

  - by Sergio Tapia

  Here's my code: # F. front_back # Consider dividing a string into two halves. # If the length is even, the front and back halves are the same length. # If the length is odd, we'll say that the extra char goes in the front half. # e.g. 'abcde', the front half is 'abc', the back half 'de'. # Given 2 strings, a and b, return a string of the form # a-front + b-front + a-back + b-back def front_back(a, b): # +++your code here+++ if len(a) % 2 == 0 && len(b) % 2 == 0: return a[:(len(a)/2)] + b[:(len(b)/2)] + a[(len(a)/2):] + b[(len(b)/2):] else: #todo! Not yet done. :P return I'm getting an error in the IF conditional. What am I doing wrong?

  Read the article

• c++ function overloading, making fwrite/fread act like PHP versions

  - by Newbie

  I'm used to the PHP fwrite/fread parameter orders, and i want to make them the same in C++ too. I want it to work with char and string types, and also any data type i put in it (only if length is defined). I am total noob on c++, this is what i made so far: size_t fwrite(FILE *fp, const std::string buf, const size_t len = SIZE_MAX){ if(len == SIZE_MAX){ return fwrite(buf.c_str(), 1, buf.length(), fp); }else{ return fwrite(buf.c_str(), 1, len, fp); } } size_t fwrite(FILE *fp, const void *buf, const size_t len = SIZE_MAX){ if(len == SIZE_MAX){ return fwrite((const char *)buf, 1, strlen((const char *)buf), fp); }else{ return fwrite(buf, 1, len, fp); } } Should this work just fine? And how should this be done if i wanted to do it the absolutely best possible way?

  Read the article

• why can't I use "&&" in python to mean 'and'?

  - by Sergio Tapia

  Here's my code: # F. front_back # Consider dividing a string into two halves. # If the length is even, the front and back halves are the same length. # If the length is odd, we'll say that the extra char goes in the front half. # e.g. 'abcde', the front half is 'abc', the back half 'de'. # Given 2 strings, a and b, return a string of the form # a-front + b-front + a-back + b-back def front_back(a, b): # +++your code here+++ if len(a) % 2 == 0 && len(b) % 2 == 0: return a[:(len(a)/2)] + b[:(len(b)/2)] + a[(len(a)/2):] + b[(len(b)/2):] else: #todo! Not yet done. :P return I'm getting an error in the IF conditional. What am I doing wrong?

  Read the article

• Initializing a char array through passed pointer segfaults

  - by Bitgarden

  Ie., why does the following work: char* char_array(size_t size){ return new char[size]; } int main(){ const char* foo = "foo"; size_t len = strlen(foo); char* bar=char_array(len); memset(bar, 0, len+1); } But the following segfaults: void char_array(char* out, size_t size){ out= new char[size]; } int main(){ const char* foo = "foo"; size_t len = strlen(foo); char* bar; char_array(bar, len); memset(bar, 0, len+1); }

  Read the article

• c permutation of a number

  - by Pkp

  I am writing a program for magic box. As the only way around it is brute force, I wrote a program to compute permutations of a given array using bells algorithm. I wrote in the lines similar to http://programminggeeks.com/c-code-for-permutation/. It does work for array of 3 and 4. It does not work for an arryay of 8 numbers (1,2,3,4,5,6,7,8). I see that the combination 1 2 3 4 5 6 7 8 gets repeated couple of times. Also there are other combinations that gets repeated. I see that certain combinations don't get displayed even. So could someone tell me what is wrong in the program below. Code: include<stdio.h> int len,numperm=1,count=0; display(int a[]){ int i; for(i=0;i<len;i++) printf("%d ",a[i]); printf("\n"); count++; } swap(int *a,int *b){ int temp; temp=*a; *a=*b; *b=temp; } no_of_perm(){ int x; for(x=1;x<=len;x++) numperm=numperm*x; } perm(int a[]){ int x,y; while(count < numperm){ for(x=0;x<len-1;x++){ swap(&a[x],&a[x+1]); display(a); } swap(&a[0],&a[1]); display(a); for(y=len-1;y>0;y--){ swap(&a[y],&a[y-1]); display(a); } swap(&a[len-1],&a[len-2]); display(a); } } main(int argc, char *argv[]){ if(argc<2){ printf("Error\n"); exit(0); } int i,*a=malloc(sizeof(int)*atoi(argv[1])); len=atoi(argv[1]); for(i=0;i<len;i++) a[i]=i+1; no_of_perm(); perm(a); }

  Read the article

• segmentation fault using BaseCode encryption

  - by Natasha Thapa

  i took the code from the links below to encrypt and decrypt a text but i get segmentation fault when trying to run this any ideas?? http://etutorials.org/Programming/secure+programming/Chapter+4.+Symmetric+Cryptography+Fundamentals/4.5+Performing+Base64+Encoding/ http://etutorials.org/Programming/secure+programming/Chapter+4.+Symmetric+Cryptography+Fundamentals/4.6+Performing+Base64+Decoding/ #include <stdlib.h> #include <string.h> #include <stdio.h> static char b64revtb[256] = { -3, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, /*0-15*/ -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, /*16-31*/ -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, 62, -1, -1, -1, 63, /*32-47*/ 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, -1, -1, -1, -2, -1, -1, /*48-63*/ -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, /*64-79*/ 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, -1, -1, -1, -1, -1, /*80-95*/ -1, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, /*96-111*/ 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, -1, -1, -1, -1, -1, /*112-127*/ -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, /*128-143*/ -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, /*144-159*/ -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, /*160-175*/ -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, /*176-191*/ -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, /*192-207*/ -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, /*208-223*/ -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, /*224-239*/ -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1 /*240-255*/ }; unsigned char *spc_base64_encode( unsigned char *input , size_t len , int wrap ) ; unsigned char *spc_base64_decode(unsigned char *buf, size_t *len, int strict, int *err); static unsigned int raw_base64_decode(unsigned char *in, unsigned char *out, int strict, int *err); unsigned char *tmbuf = NULL; static char tmpbuffer[] ={0}; int main(void) { memset( tmpbuffer, NULL, sizeof( tmpbuffer ) ); sprintf( tmpbuffer, "%s:%s" , "username", "password" ); tmbuf = spc_base64_encode( (unsigned char *)tmpbuffer , strlen( tmpbuffer ), 0 ); printf(" The text %s has been encrytped to %s \n", tmpbuffer, tmbuf ); unsigned char *decrypt = NULL; int strict; int *err; decrypt = spc_base64_decode( tmbuf , strlen( tmbuf ), 0, err ); printf(" The text %s has been decrytped to %s \n", tmbuf , decrypt); } static char b64table[64] = "ABCDEFGHIJKLMNOPQRSTUVWXYZ" "abcdefghijklmnopqrstuvwxyz" "0123456789+/"; /* Accepts a binary buffer with an associated size. * Returns a base64 encoded, NULL-terminated string. */ unsigned char *spc_base64_encode(unsigned char *input, size_t len, int wrap) { unsigned char *output, *p; size_t i = 0, mod = len % 3, toalloc; toalloc = (len / 3) * 4 + (3 - mod) % 3 + 1; if (wrap) { toalloc += len / 57; if (len % 57) toalloc++; } p = output = (unsigned char *)malloc(((len / 3) + (mod ? 1 : 0)) * 4 + 1); if (!p) return 0; while (i < len - mod) { *p++ = b64table[input[i++] >> 2]; *p++ = b64table[((input[i - 1] << 4) | (input[i] >> 4)) & 0x3f]; *p++ = b64table[((input[i] << 2) | (input[i + 1] >> 6)) & 0x3f]; *p++ = b64table[input[i + 1] & 0x3f]; i += 2; if (wrap && !(i % 57)) *p++ = '\n'; } if (!mod) { if (wrap && i % 57) *p++ = '\n'; *p = 0; return output; } else { *p++ = b64table[input[i++] >> 2]; *p++ = b64table[((input[i - 1] << 4) | (input[i] >> 4)) & 0x3f]; if (mod = = 1) { *p++ = '='; *p++ = '='; if (wrap) *p++ = '\n'; *p = 0; return output; } else { *p++ = b64table[(input[i] << 2) & 0x3f]; *p++ = '='; if (wrap) *p++ = '\n'; *p = 0; return output; } } } static unsigned int raw_base64_decode(unsigned char *in, unsigned char *out, int strict, int *err) { unsigned int result = 0, x; unsigned char buf[3], *p = in, pad = 0; *err = 0; while (!pad) { switch ((x = b64revtb[*p++])) { case -3: /* NULL TERMINATOR */ if (((p - 1) - in) % 4) *err = 1; return result; case -2: /* PADDING CHARACTER. INVALID HERE */ if (((p - 1) - in) % 4 < 2) { *err = 1; return result; } else if (((p - 1) - in) % 4 == 2) { /* Make sure there's appropriate padding */ if (*p != '=') { *err = 1; return result; } buf[2] = 0; pad = 2; result++; break; } else { pad = 1; result += 2; break; } case -1: if (strict) { *err = 2; return result; } break; default: switch (((p - 1) - in) % 4) { case 0: buf[0] = x << 2; break; case 1: buf[0] |= (x >> 4); buf[1] = x << 4; break; case 2: buf[1] |= (x >> 2); buf[2] = x << 6; break; case 3: buf[2] |= x; result += 3; for (x = 0; x < 3 - pad; x++) *out++ = buf[x]; break; } break; } } for (x = 0; x < 3 - pad; x++) *out++ = buf[x]; return result; } /* If err is non-zero on exit, then there was an incorrect padding error. We * allocate enough space for all circumstances, but when there is padding, or * there are characters outside the character set in the string (which we are * supposed to ignore), then we end up allocating too much space. You can * realloc() to the correct length if you wish. */ unsigned char *spc_base64_decode(unsigned char *buf, size_t *len, int strict, int *err) { unsigned char *outbuf; outbuf = (unsigned char *)malloc(3 * (strlen(buf) / 4 + 1)); if (!outbuf) { *err = -3; *len = 0; return 0; } *len = raw_base64_decode(buf, outbuf, strict, err); if (*err) { free(outbuf); *len = 0; outbuf = 0; } return outbuf; }

  Read the article

• Project Euler 17: (Iron)Python

  - by Ben Griswold

  In my attempt to learn (Iron)Python out in the open, here’s my solution for Project Euler Problem 17.  As always, any feedback is welcome. # Euler 17 # http://projecteuler.net/index.php?section=problems&id=17 # If the numbers 1 to 5 are written out in words: # one, two, three, four, five, then there are # 3 + 3 + 5 + 4 + 4 = 19 letters used in total. # If all the numbers from 1 to 1000 (one thousand) # inclusive were written out in words, how many letters # would be used? # # NOTE: Do not count spaces or hyphens. For example, 342 # (three hundred and forty-two) contains 23 letters and # 115 (one hundred and fifteen) contains 20 letters. The # use of "and" when writing out numbers is in compliance # with British usage. import time start = time.time() def to_word(n): h = { 1 : "one", 2 : "two", 3 : "three", 4 : "four", 5 : "five", 6 : "six", 7 : "seven", 8 : "eight", 9 : "nine", 10 : "ten", 11 : "eleven", 12 : "twelve", 13 : "thirteen", 14 : "fourteen", 15 : "fifteen", 16 : "sixteen", 17 : "seventeen", 18 : "eighteen", 19 : "nineteen", 20 : "twenty", 30 : "thirty", 40 : "forty", 50 : "fifty", 60 : "sixty", 70 : "seventy", 80 : "eighty", 90 : "ninety", 100 : "hundred", 1000 : "thousand" } word = "" # Reverse the numbers so position (ones, tens, # hundreds,...) can be easily determined a = [int(x) for x in str(n)[::-1]] # Thousands position if (len(a) == 4 and a[3] != 0): # This can only be one thousand based # on the problem/method constraints word = h[a[3]] + " thousand " # Hundreds position if (len(a) >= 3 and a[2] != 0): word += h[a[2]] + " hundred" # Add "and" string if the tens or ones # position is occupied with a non-zero value. # Note: routine is broken up this way for [my] clarity. if (len(a) >= 2 and a[1] != 0): # catch 10 - 99 word += " and" elif len(a) >= 1 and a[0] != 0: # catch 1 - 9 word += " and" # Tens and ones position tens_position_value = 99 if (len(a) >= 2 and a[1] != 0): # Calculate the tens position value per the # first and second element in array # e.g. (8 * 10) + 1 = 81 tens_position_value = int(a[1]) * 10 + a[0] if tens_position_value <= 20: # If the tens position value is 20 or less # there's an entry in the hash. Use it and there's # no need to consider the ones position word += " " + h[tens_position_value] else: # Determine the tens position word by # dividing by 10 first. E.g. 8 * 10 = h[80] # We will pick up the ones position word later in # the next part of the routine word += " " + h[(a[1] * 10)] if (len(a) >= 1 and a[0] != 0 and tens_position_value > 20): # Deal with ones position where tens position is # greater than 20 or we have a single digit number word += " " + h[a[0]] # Trim the empty spaces off both ends of the string return word.replace(" ","") def to_word_length(n): return len(to_word(n)) print sum([to_word_length(i) for i in xrange(1,1001)]) print "Elapsed Time:", (time.time() - start) * 1000, "millisecs" a=raw_input('Press return to continue')

  Read the article

• Web Hosting Backup/Disaster Recovery Plan - Which Company?

  - by Harry Muscle

  I've been asked to look after consolidating all of our various company websites onto one host and also provide a disaster recover plan in case the chosen host goes down/out of business/etc. We're most likely going to go with HostGator as our chosen host, however, I'm not sure who to pick for our backup host. HostGator uses cPanel and has the functionality to provide regular full (ie: including configuration) backups of all the sites we host. Ideally I'm looking for a solution where we can provide these backups to another company and within a short period of time they restore all the sites onto their servers and we're back up and running. The whole disaster recover process has to be fairly straight forward from the point of view of what we need to do in case I am unavailable to assist in the disaster recovery process and no one else overly technical is available to assist (ie: take these backup files, send them to this company, and ask them to do this). Any suggestions on which company would be a good choice for this backup solution would be highly appreciated. Thanks, Harry

  Read the article

• how to insert multiple characters into a string in C [closed]

  - by John Li

  I wish to insert some characters into a string in C: Example: char string[20] = "20120910T090000"; I want to make it something like "2012-09-10-T-0900-00" My code so far: void append(char subject[],char insert[], int pos) { char buf[100]; strncpy(buf, subject, pos); int len = strlen(buf); strcpy(buf+len, insert); len += strlen(insert); strcpy(buf+len, subject+pos); strcpy(subject, buf); } When I call this the first time I get: 2012-0910T090000 However when I call it a second time I get: 2012-0910T090000-10T090000 Any help is appreciated

  Read the article

• Why do ICMP Redirct Host happen?

  - by El Barto

  I'm setting up a Debian box as a router for 4 subnets. For that I have defined 4 virtual interfaces on the NIC where the LAN is connected (eth1). eth1 Link encap:Ethernet HWaddr 94:0c:6d:82:0d:98 inet addr:10.1.1.1 Bcast:10.1.1.255 Mask:255.255.255.0 inet6 addr: fe80::960c:6dff:fe82:d98/64 Scope:Link UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:6026521 errors:0 dropped:0 overruns:0 frame:0 TX packets:35331299 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:673201397 (642.0 MiB) TX bytes:177276932 (169.0 MiB) Interrupt:19 Base address:0x6000 eth1:0 Link encap:Ethernet HWaddr 94:0c:6d:82:0d:98 inet addr:10.1.2.1 Bcast:10.1.2.255 Mask:255.255.255.0 UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 Interrupt:19 Base address:0x6000 eth1:1 Link encap:Ethernet HWaddr 94:0c:6d:82:0d:98 inet addr:10.1.3.1 Bcast:10.1.3.255 Mask:255.255.255.0 UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 Interrupt:19 Base address:0x6000 eth1:2 Link encap:Ethernet HWaddr 94:0c:6d:82:0d:98 inet addr:10.1.4.1 Bcast:10.1.4.255 Mask:255.255.255.0 UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 Interrupt:19 Base address:0x6000 eth2 Link encap:Ethernet HWaddr 6c:f0:49:a4:47:38 inet addr:192.168.1.10 Bcast:192.168.1.255 Mask:255.255.255.0 inet6 addr: fe80::6ef0:49ff:fea4:4738/64 Scope:Link UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:199809345 errors:0 dropped:0 overruns:0 frame:0 TX packets:158362936 errors:0 dropped:0 overruns:0 carrier:1 collisions:0 txqueuelen:1000 RX bytes:3656983762 (3.4 GiB) TX bytes:1715848473 (1.5 GiB) Interrupt:27 eth3 Link encap:Ethernet HWaddr 94:0c:6d:82:c8:72 inet addr:192.168.2.5 Bcast:192.168.2.255 Mask:255.255.255.0 inet6 addr: fe80::960c:6dff:fe82:c872/64 Scope:Link UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:110814 errors:0 dropped:0 overruns:0 frame:0 TX packets:73386 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:16044901 (15.3 MiB) TX bytes:42125647 (40.1 MiB) Interrupt:20 Base address:0x2000 lo Link encap:Local Loopback inet addr:127.0.0.1 Mask:255.0.0.0 inet6 addr: ::1/128 Scope:Host UP LOOPBACK RUNNING MTU:16436 Metric:1 RX packets:22351 errors:0 dropped:0 overruns:0 frame:0 TX packets:22351 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:0 RX bytes:2625143 (2.5 MiB) TX bytes:2625143 (2.5 MiB) tun0 Link encap:UNSPEC HWaddr 00-00-00-00-00-00-00-00-00-00-00-00-00-00-00-00 inet addr:10.8.0.1 P-t-P:10.8.0.2 Mask:255.255.255.255 UP POINTOPOINT RUNNING NOARP MULTICAST MTU:1500 Metric:1 RX packets:41358924 errors:0 dropped:0 overruns:0 frame:0 TX packets:23116350 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:100 RX bytes:3065505744 (2.8 GiB) TX bytes:1324358330 (1.2 GiB) I have two other computers connected to this network. One has IP 10.1.1.12 (subnet mask 255.255.255.0) and the other one 10.1.2.20 (subnet mask 255.255.255.0). I want to be able to reach 10.1.1.12 from 10.1.2.20. Since packet forwarding is enabled in the router and the policy of the FORWARD chain is ACCEPT (and there are no other rules), I understand that there should be no problem to ping from 10.1.2.20 to 10.1.1.12 going through the router. However, this is what I get: $ ping -c15 10.1.1.12 PING 10.1.1.12 (10.1.1.12): 56 data bytes Request timeout for icmp_seq 0 92 bytes from router2.mydomain.com (10.1.2.1): Redirect Host(New addr: 10.1.1.12) Vr HL TOS Len ID Flg off TTL Pro cks Src Dst 4 5 00 0054 81d4 0 0000 3f 01 e2b3 10.1.2.20 10.1.1.12 Request timeout for icmp_seq 1 92 bytes from router2.mydomain.com (10.1.2.1): Redirect Host(New addr: 10.1.1.12) Vr HL TOS Len ID Flg off TTL Pro cks Src Dst 4 5 00 0054 899b 0 0000 3f 01 daec 10.1.2.20 10.1.1.12 Request timeout for icmp_seq 2 92 bytes from router2.mydomain.com (10.1.2.1): Redirect Host(New addr: 10.1.1.12) Vr HL TOS Len ID Flg off TTL Pro cks Src Dst 4 5 00 0054 78fe 0 0000 3f 01 eb89 10.1.2.20 10.1.1.12 Request timeout for icmp_seq 3 92 bytes from router2.mydomain.com (10.1.2.1): Redirect Host(New addr: 10.1.1.12) Vr HL TOS Len ID Flg off TTL Pro cks Src Dst 4 5 00 0054 14b8 0 0000 3f 01 4fd0 10.1.2.20 10.1.1.12 Request timeout for icmp_seq 4 92 bytes from router2.mydomain.com (10.1.2.1): Redirect Host(New addr: 10.1.1.12) Vr HL TOS Len ID Flg off TTL Pro cks Src Dst 4 5 00 0054 8ef7 0 0000 3f 01 d590 10.1.2.20 10.1.1.12 Request timeout for icmp_seq 5 92 bytes from router2.mydomain.com (10.1.2.1): Redirect Host(New addr: 10.1.1.12) Vr HL TOS Len ID Flg off TTL Pro cks Src Dst 4 5 00 0054 ec9d 0 0000 3f 01 77ea 10.1.2.20 10.1.1.12 Request timeout for icmp_seq 6 92 bytes from router2.mydomain.com (10.1.2.1): Redirect Host(New addr: 10.1.1.12) Vr HL TOS Len ID Flg off TTL Pro cks Src Dst 4 5 00 0054 70e6 0 0000 3f 01 f3a1 10.1.2.20 10.1.1.12 Request timeout for icmp_seq 7 92 bytes from router2.mydomain.com (10.1.2.1): Redirect Host(New addr: 10.1.1.12) Vr HL TOS Len ID Flg off TTL Pro cks Src Dst 4 5 00 0054 b0d2 0 0000 3f 01 b3b5 10.1.2.20 10.1.1.12 Request timeout for icmp_seq 8 92 bytes from router2.mydomain.com (10.1.2.1): Redirect Host(New addr: 10.1.1.12) Vr HL TOS Len ID Flg off TTL Pro cks Src Dst 4 5 00 0054 f8b4 0 0000 3f 01 6bd3 10.1.2.20 10.1.1.12 Request timeout for icmp_seq 9 Request timeout for icmp_seq 10 92 bytes from router2.mydomain.com (10.1.2.1): Redirect Host(New addr: 10.1.1.12) Vr HL TOS Len ID Flg off TTL Pro cks Src Dst 4 5 00 0054 1c95 0 0000 3f 01 47f3 10.1.2.20 10.1.1.12 Request timeout for icmp_seq 11 Request timeout for icmp_seq 12 Request timeout for icmp_seq 13 92 bytes from router2.mydomain.com (10.1.2.1): Redirect Host(New addr: 10.1.1.12) Vr HL TOS Len ID Flg off TTL Pro cks Src Dst 4 5 00 0054 62bc 0 0000 3f 01 01cc 10.1.2.20 10.1.1.12 Why does this happen? From what I've read the Redirect Host response has something to do with the fact that the two hosts are in the same network and there being a shorter route (or so I understood). They are in fact in the same physical network, but why would there be a better route if they are not on the same subnet (they can't see each other)? What am I missing? Some extra info you might want to see: # route -n Kernel IP routing table Destination Gateway Genmask Flags Metric Ref Use Iface 10.8.0.2 0.0.0.0 255.255.255.255 UH 0 0 0 tun0 127.0.0.1 0.0.0.0 255.255.255.255 UH 0 0 0 lo 192.168.2.0 0.0.0.0 255.255.255.0 U 0 0 0 eth3 10.8.0.0 10.8.0.2 255.255.255.0 UG 0 0 0 tun0 192.168.1.0 0.0.0.0 255.255.255.0 U 1 0 0 eth2 10.1.4.0 0.0.0.0 255.255.255.0 U 0 0 0 eth1 10.1.1.0 0.0.0.0 255.255.255.0 U 0 0 0 eth1 10.1.2.0 0.0.0.0 255.255.255.0 U 0 0 0 eth1 10.1.3.0 0.0.0.0 255.255.255.0 U 0 0 0 eth1 0.0.0.0 192.168.1.1 0.0.0.0 UG 0 0 0 eth2 0.0.0.0 192.168.2.1 0.0.0.0 UG 100 0 0 eth3 # iptables -L -n Chain INPUT (policy ACCEPT) target prot opt source destination Chain FORWARD (policy ACCEPT) target prot opt source destination Chain OUTPUT (policy ACCEPT) target prot opt source destination # iptables -L -n -t nat Chain PREROUTING (policy ACCEPT) target prot opt source destination Chain POSTROUTING (policy ACCEPT) target prot opt source destination MASQUERADE all -- !10.0.0.0/8 10.0.0.0/8 MASQUERADE all -- 10.0.0.0/8 !10.0.0.0/8 Chain OUTPUT (policy ACCEPT) target prot opt source destination

  Read the article

• Why do ICMP Redirect Host happen?

  - by El Barto

  I'm setting up a Debian box as a router for 4 subnets. For that I have defined 4 virtual interfaces on the NIC where the LAN is connected (eth1). eth1 Link encap:Ethernet HWaddr 94:0c:6d:82:0d:98 inet addr:10.1.1.1 Bcast:10.1.1.255 Mask:255.255.255.0 inet6 addr: fe80::960c:6dff:fe82:d98/64 Scope:Link UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:6026521 errors:0 dropped:0 overruns:0 frame:0 TX packets:35331299 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:673201397 (642.0 MiB) TX bytes:177276932 (169.0 MiB) Interrupt:19 Base address:0x6000 eth1:0 Link encap:Ethernet HWaddr 94:0c:6d:82:0d:98 inet addr:10.1.2.1 Bcast:10.1.2.255 Mask:255.255.255.0 UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 Interrupt:19 Base address:0x6000 eth1:1 Link encap:Ethernet HWaddr 94:0c:6d:82:0d:98 inet addr:10.1.3.1 Bcast:10.1.3.255 Mask:255.255.255.0 UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 Interrupt:19 Base address:0x6000 eth1:2 Link encap:Ethernet HWaddr 94:0c:6d:82:0d:98 inet addr:10.1.4.1 Bcast:10.1.4.255 Mask:255.255.255.0 UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 Interrupt:19 Base address:0x6000 eth2 Link encap:Ethernet HWaddr 6c:f0:49:a4:47:38 inet addr:192.168.1.10 Bcast:192.168.1.255 Mask:255.255.255.0 inet6 addr: fe80::6ef0:49ff:fea4:4738/64 Scope:Link UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:199809345 errors:0 dropped:0 overruns:0 frame:0 TX packets:158362936 errors:0 dropped:0 overruns:0 carrier:1 collisions:0 txqueuelen:1000 RX bytes:3656983762 (3.4 GiB) TX bytes:1715848473 (1.5 GiB) Interrupt:27 eth3 Link encap:Ethernet HWaddr 94:0c:6d:82:c8:72 inet addr:192.168.2.5 Bcast:192.168.2.255 Mask:255.255.255.0 inet6 addr: fe80::960c:6dff:fe82:c872/64 Scope:Link UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:110814 errors:0 dropped:0 overruns:0 frame:0 TX packets:73386 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:16044901 (15.3 MiB) TX bytes:42125647 (40.1 MiB) Interrupt:20 Base address:0x2000 lo Link encap:Local Loopback inet addr:127.0.0.1 Mask:255.0.0.0 inet6 addr: ::1/128 Scope:Host UP LOOPBACK RUNNING MTU:16436 Metric:1 RX packets:22351 errors:0 dropped:0 overruns:0 frame:0 TX packets:22351 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:0 RX bytes:2625143 (2.5 MiB) TX bytes:2625143 (2.5 MiB) tun0 Link encap:UNSPEC HWaddr 00-00-00-00-00-00-00-00-00-00-00-00-00-00-00-00 inet addr:10.8.0.1 P-t-P:10.8.0.2 Mask:255.255.255.255 UP POINTOPOINT RUNNING NOARP MULTICAST MTU:1500 Metric:1 RX packets:41358924 errors:0 dropped:0 overruns:0 frame:0 TX packets:23116350 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:100 RX bytes:3065505744 (2.8 GiB) TX bytes:1324358330 (1.2 GiB) I have two other computers connected to this network. One has IP 10.1.1.12 (subnet mask 255.255.255.0) and the other one 10.1.2.20 (subnet mask 255.255.255.0). I want to be able to reach 10.1.1.12 from 10.1.2.20. Since packet forwarding is enabled in the router and the policy of the FORWARD chain is ACCEPT (and there are no other rules), I understand that there should be no problem to ping from 10.1.2.20 to 10.1.1.12 going through the router. However, this is what I get: $ ping -c15 10.1.1.12 PING 10.1.1.12 (10.1.1.12): 56 data bytes Request timeout for icmp_seq 0 92 bytes from router2.mydomain.com (10.1.2.1): Redirect Host(New addr: 10.1.1.12) Vr HL TOS Len ID Flg off TTL Pro cks Src Dst 4 5 00 0054 81d4 0 0000 3f 01 e2b3 10.1.2.20 10.1.1.12 Request timeout for icmp_seq 1 92 bytes from router2.mydomain.com (10.1.2.1): Redirect Host(New addr: 10.1.1.12) Vr HL TOS Len ID Flg off TTL Pro cks Src Dst 4 5 00 0054 899b 0 0000 3f 01 daec 10.1.2.20 10.1.1.12 Request timeout for icmp_seq 2 92 bytes from router2.mydomain.com (10.1.2.1): Redirect Host(New addr: 10.1.1.12) Vr HL TOS Len ID Flg off TTL Pro cks Src Dst 4 5 00 0054 78fe 0 0000 3f 01 eb89 10.1.2.20 10.1.1.12 Request timeout for icmp_seq 3 92 bytes from router2.mydomain.com (10.1.2.1): Redirect Host(New addr: 10.1.1.12) Vr HL TOS Len ID Flg off TTL Pro cks Src Dst 4 5 00 0054 14b8 0 0000 3f 01 4fd0 10.1.2.20 10.1.1.12 Request timeout for icmp_seq 4 92 bytes from router2.mydomain.com (10.1.2.1): Redirect Host(New addr: 10.1.1.12) Vr HL TOS Len ID Flg off TTL Pro cks Src Dst 4 5 00 0054 8ef7 0 0000 3f 01 d590 10.1.2.20 10.1.1.12 Request timeout for icmp_seq 5 92 bytes from router2.mydomain.com (10.1.2.1): Redirect Host(New addr: 10.1.1.12) Vr HL TOS Len ID Flg off TTL Pro cks Src Dst 4 5 00 0054 ec9d 0 0000 3f 01 77ea 10.1.2.20 10.1.1.12 Request timeout for icmp_seq 6 92 bytes from router2.mydomain.com (10.1.2.1): Redirect Host(New addr: 10.1.1.12) Vr HL TOS Len ID Flg off TTL Pro cks Src Dst 4 5 00 0054 70e6 0 0000 3f 01 f3a1 10.1.2.20 10.1.1.12 Request timeout for icmp_seq 7 92 bytes from router2.mydomain.com (10.1.2.1): Redirect Host(New addr: 10.1.1.12) Vr HL TOS Len ID Flg off TTL Pro cks Src Dst 4 5 00 0054 b0d2 0 0000 3f 01 b3b5 10.1.2.20 10.1.1.12 Request timeout for icmp_seq 8 92 bytes from router2.mydomain.com (10.1.2.1): Redirect Host(New addr: 10.1.1.12) Vr HL TOS Len ID Flg off TTL Pro cks Src Dst 4 5 00 0054 f8b4 0 0000 3f 01 6bd3 10.1.2.20 10.1.1.12 Request timeout for icmp_seq 9 Request timeout for icmp_seq 10 92 bytes from router2.mydomain.com (10.1.2.1): Redirect Host(New addr: 10.1.1.12) Vr HL TOS Len ID Flg off TTL Pro cks Src Dst 4 5 00 0054 1c95 0 0000 3f 01 47f3 10.1.2.20 10.1.1.12 Request timeout for icmp_seq 11 Request timeout for icmp_seq 12 Request timeout for icmp_seq 13 92 bytes from router2.mydomain.com (10.1.2.1): Redirect Host(New addr: 10.1.1.12) Vr HL TOS Len ID Flg off TTL Pro cks Src Dst 4 5 00 0054 62bc 0 0000 3f 01 01cc 10.1.2.20 10.1.1.12 Why does this happen? From what I've read the Redirect Host response has something to do with the fact that the two hosts are in the same network and there being a shorter route (or so I understood). They are in fact in the same physical network, but why would there be a better route if they are not on the same subnet (they can't see each other)? What am I missing? Some extra info you might want to see: # route -n Kernel IP routing table Destination Gateway Genmask Flags Metric Ref Use Iface 10.8.0.2 0.0.0.0 255.255.255.255 UH 0 0 0 tun0 127.0.0.1 0.0.0.0 255.255.255.255 UH 0 0 0 lo 192.168.2.0 0.0.0.0 255.255.255.0 U 0 0 0 eth3 10.8.0.0 10.8.0.2 255.255.255.0 UG 0 0 0 tun0 192.168.1.0 0.0.0.0 255.255.255.0 U 1 0 0 eth2 10.1.4.0 0.0.0.0 255.255.255.0 U 0 0 0 eth1 10.1.1.0 0.0.0.0 255.255.255.0 U 0 0 0 eth1 10.1.2.0 0.0.0.0 255.255.255.0 U 0 0 0 eth1 10.1.3.0 0.0.0.0 255.255.255.0 U 0 0 0 eth1 0.0.0.0 192.168.1.1 0.0.0.0 UG 0 0 0 eth2 0.0.0.0 192.168.2.1 0.0.0.0 UG 100 0 0 eth3 # iptables -L -n Chain INPUT (policy ACCEPT) target prot opt source destination Chain FORWARD (policy ACCEPT) target prot opt source destination Chain OUTPUT (policy ACCEPT) target prot opt source destination # iptables -L -n -t nat Chain PREROUTING (policy ACCEPT) target prot opt source destination Chain POSTROUTING (policy ACCEPT) target prot opt source destination MASQUERADE all -- !10.0.0.0/8 10.0.0.0/8 MASQUERADE all -- 10.0.0.0/8 !10.0.0.0/8 Chain OUTPUT (policy ACCEPT) target prot opt source destination

  Read the article

• Optimization of Function with Dictionary and Zip()

  - by eWizardII

  Hello, I have the following function: def filetxt(): word_freq = {} lvl1 = [] lvl2 = [] total_t = 0 users = 0 text = [] for l in range(0,500): # Open File if os.path.exists("C:/Twitter/json/user_" + str(l) + ".json") == True: with open("C:/Twitter/json/user_" + str(l) + ".json", "r") as f: text_f = json.load(f) users = users + 1 for i in range(len(text_f)): text.append(text_f[str(i)]['text']) total_t = total_t + 1 else: pass # Filter occ = 0 import string for i in range(len(text)): s = text[i] # Sample string a = re.findall(r'(RT)',s) b = re.findall(r'(@)',s) occ = len(a) + len(b) + occ s = s.encode('utf-8') out = s.translate(string.maketrans("",""), string.punctuation) # Create Wordlist/Dictionary word_list = text[i].lower().split(None) for word in word_list: word_freq[word] = word_freq.get(word, 0) + 1 keys = word_freq.keys() numbo = range(1,len(keys)+1) WList = ', '.join(keys) NList = str(numbo).strip('[]') WList = WList.split(", ") NList = NList.split(", ") W2N = dict(zip(WList, NList)) for k in range (0,len(word_list)): word_list[k] = W2N[word_list[k]] for i in range (0,len(word_list)-1): lvl1.append(word_list[i]) lvl2.append(word_list[i+1]) I have used the profiler to find that it seems the greatest CPU time is spent on the zip() function and the join and split parts of the code, I'm looking to see if there is any way I have overlooked that I could potentially clean up the code to make it more optimized, since the greatest lag seems to be in how I am working with the dictionaries and the zip() function. Any help would be appreciated thanks!

  Read the article

• Images won't load if they are of high size

  - by Fahim Parkar

  I have created web-application using JSF 2.0 and mysql. I am storing images in DB using MEDIUMBLOB. When I try to load image, I am able to see those images. However if the image size is big (1 MB or more), I can see half or 3/4th image on the browser. Any idea how to overcome this issue? Do I need to set any variable in JSF or MySQL? I know I should have saved the images over disk instead of DB, however this was client requirement. Client wanted to backup data and provide it to someone else and client don't want to backup DB and images also. Edit 1 Do I need to set any variables on mysql like query_cache. Edit 2 When I download same image and put below code it works perfectly. <h:graphicImage value="images/myImage4.png" width="50%" /> Edit 3 code is as below. <h:graphicImage value="DisplayImage?mainID=drawing" /> DisplayImage.java String imgLen = rs1.getString(1); int len = imgLen.length(); byte[] rb = new byte[len]; InputStream readImg = rs1.getBinaryStream(1); InputStream inputStream = readImg; int index = readImg.read(rb, 0, len); response.reset(); response.setHeader("Content-Length", String.valueOf(len)); response.setHeader("Content-disposition", "inline;filename=/file.png"); response.setContentType("image/png"); response.getOutputStream().write(rb, 0, len); response.getOutputStream().flush(); When I print len I get value as len=1548432

  Read the article

• [Wireless LAN]hostapd is giving error whwn running in target board

  - by Renjith G

  hi, I got the following error when i tried to run the hostapd command in my target board. Any idea about this? /etc # hostapd -dd hostapd.conf Configuration file: hostapd.conf madwifi_set_iface_flags: dev_up=0 madwifi_set_privacy: enabled=0 BSS count 1, BSSID mask ff:ff:ff:ff:ff:ff (0 bits) Flushing old station entries madwifi_sta_deauth: addr=ff:ff:ff:ff:ff:ff reason_code=3 ioctl[IEEE80211_IOCTL_SETMLME]: Invalid argument madwifi_sta_deauth: Failed to deauth STA (addr ff:ff:ff:ff:ff:ff reason 3) Could not connect to kernel driver. Deauthenticate all stations madwifi_sta_deauth: addr=ff:ff:ff:ff:ff:ff reason_code=2 ioctl[IEEE80211_IOCTL_SETMLME]: Invalid argument madwifi_sta_deauth: Failed to deauth STA (addr ff:ff:ff:ff:ff:ff reason 2) madwifi_set_privacy: enabled=0 madwifi_del_key: addr=00:00:00:00:00:00 key_idx=0 madwifi_del_key: addr=00:00:00:00:00:00 key_idx=1 madwifi_del_key: addr=00:00:00:00:00:00 key_idx=2 madwifi_del_key: addr=00:00:00:00:00:00 key_idx=3 Using interface ath0 with hwaddr 00:0b:6b:33:8c:30 and ssid '"RG_WLAN Testing Renjith G"' SSID - hexdump_ascii(len=27): 22 52 47 5f 57 4c 41 4e 20 54 65 73 74 69 6e 67 "RG_WLAN Testing 20 52 65 6e 6a 69 74 68 20 47 22 Renjith G" PSK (ASCII passphrase) - hexdump_ascii(len=12): 6d 79 70 61 73 73 70 68 72 61 73 65 mypassphrase PSK (from passphrase) - hexdump(len=32): 70 6f a6 92 da 9c a8 3b ff 36 85 76 f3 11 9c 5e 5d 4a 4b 79 f4 4e 18 f6 b1 b8 09 af 6c 9c 6c 21 madwifi_set_ieee8021x: enabled=1 madwifi_configure_wpa: group key cipher=1 madwifi_configure_wpa: pairwise key ciphers=0xa madwifi_configure_wpa: key management algorithms=0x2 madwifi_configure_wpa: rsn capabilities=0x0 madwifi_configure_wpa: enable WPA=0x1 WPA: group state machine entering state GTK_INIT (VLAN-ID 0) GMK - hexdump(len=32): [REMOVED] GTK - hexdump(len=32): [REMOVED] WPA: group state machine entering state SETKEYSDONE (VLAN-ID 0) madwifi_set_key: alg=TKIP addr=00:00:00:00:00:00 key_idx=1 madwifi_set_privacy: enabled=1 madwifi_set_iface_flags: dev_up=1 ath0: Setup of interface done. l2_packet_receive - recvfrom: Network is down Wireless event: cmd=0x8b1a len=40 Register Fail Register Fail WPA: group state machine entering state SETKEYS (VLAN-ID 0) GMK - hexdump(len=32): [REMOVED] GTK - hexdump(len=32): [REMOVED] wpa_group_setkeys: GKeyDoneStations=0 WPA: group state machine entering state SETKEYSDONE (VLAN-ID 0) madwifi_set_key: alg=TKIP addr=00:00:00:00:00:00 key_idx=2 Signal 2 received - terminating Flushing old station entries madwifi_sta_deauth: addr=ff:ff:ff:ff:ff:ff reason_code=3 ioctl[IEEE80211_IOCTL_SETMLME]: Invalid argument madwifi_sta_deauth: Failed to deauth STA (addr ff:ff:ff:ff:ff:ff reason 3) Could not connect to kernel driver. Deauthenticate all stations madwifi_sta_deauth: addr=ff:ff:ff:ff:ff:ff reason_code=2 ioctl[IEEE80211_IOCTL_SETMLME]: Invalid argument madwifi_sta_deauth: Failed to deauth STA (addr ff:ff:ff:ff:ff:ff reason 2) madwifi_set_privacy: enabled=0 madwifi_set_ieee8021x: enabled=0 madwifi_set_iface_flags: dev_up=0

  Read the article

• Excel VBA - How to copy/transpose multiple columns record into individual single row

  - by larry

  I'm working on data migration, need some help on doing a macro to copy/transpose multiple columns record into individual single row. There are also a "tag" in the first row, which indicates the columns that should not be included in the copy/transpose. From: Tag x Name Jan Feb Mar Apr Larry 2 20 34 56 Harry 3 45 77 88 Marry 5 66 44 33 To: Larry Jan 2 Larry Feb 20 Larry Apr 56 Harry Jan 3 Harry Feb 45 Harry Apr 88 Marry Jan 5 Marry Feb 66 Marry Apr 33 The "Mar" data was omitted due to there's a tag (X) above it. The data might be near hundred columns (few years), and some of the months need to be omitted. Any expert able to help on this? I had been spending whole day cracking my head on this. Worse come to worse I might have to manually copy and paste, that would probably took me a decade.

  Read the article

• Linux - Only first virtual interface can ping external gateway

  - by husvar

  I created 3 virtual interfaces with different mac addresses all linked to the same physical interface. I see that they successfully arp for the gw and they can ping (the request is coming in the packet capture in wireshark). However the ping utility does not count the responses. Does anyone knows the issue? I am running Ubuntu 14.04 in a VmWare. root@ubuntu:~# ip link sh 1: lo: <LOOPBACK,UP,LOWER_UP> mtu 65536 qdisc noqueue state UNKNOWN mode DEFAULT group default link/loopback 00:00:00:00:00:00 brd 00:00:00:00:00:00 2: eth0: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qdisc pfifo_fast state UP mode DEFAULT group default qlen 1000 link/ether 00:0c:29:bc:fc:8b brd ff:ff:ff:ff:ff:ff root@ubuntu:~# ip addr sh 1: lo: <LOOPBACK,UP,LOWER_UP> mtu 65536 qdisc noqueue state UNKNOWN group default link/loopback 00:00:00:00:00:00 brd 00:00:00:00:00:00 inet 127.0.0.1/8 scope host lo valid_lft forever preferred_lft forever inet6 ::1/128 scope host valid_lft forever preferred_lft forever 2: eth0: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qdisc pfifo_fast state UP group default qlen 1000 link/ether 00:0c:29:bc:fc:8b brd ff:ff:ff:ff:ff:ff inet6 fe80::20c:29ff:febc:fc8b/64 scope link valid_lft forever preferred_lft forever root@ubuntu:~# ip route sh root@ubuntu:~# ip link add link eth0 eth0.1 addr 00:00:00:00:00:11 type macvlan root@ubuntu:~# ip link add link eth0 eth0.2 addr 00:00:00:00:00:22 type macvlan root@ubuntu:~# ip link add link eth0 eth0.3 addr 00:00:00:00:00:33 type macvlan root@ubuntu:~# ip -4 link sh 1: lo: <LOOPBACK,UP,LOWER_UP> mtu 65536 qdisc noqueue state UNKNOWN mode DEFAULT group default link/loopback 00:00:00:00:00:00 brd 00:00:00:00:00:00 2: eth0: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qdisc pfifo_fast state UP mode DEFAULT group default qlen 1000 link/ether 00:0c:29:bc:fc:8b brd ff:ff:ff:ff:ff:ff 18: eth0.1@eth0: <BROADCAST,MULTICAST> mtu 1500 qdisc noop state DOWN mode DEFAULT group default link/ether 00:00:00:00:00:11 brd ff:ff:ff:ff:ff:ff 19: eth0.2@eth0: <BROADCAST,MULTICAST> mtu 1500 qdisc noop state DOWN mode DEFAULT group default link/ether 00:00:00:00:00:22 brd ff:ff:ff:ff:ff:ff 20: eth0.3@eth0: <BROADCAST,MULTICAST> mtu 1500 qdisc noop state DOWN mode DEFAULT group default link/ether 00:00:00:00:00:33 brd ff:ff:ff:ff:ff:ff root@ubuntu:~# ip -4 addr sh 1: lo: <LOOPBACK,UP,LOWER_UP> mtu 65536 qdisc noqueue state UNKNOWN group default inet 127.0.0.1/8 scope host lo valid_lft forever preferred_lft forever root@ubuntu:~# ip -4 route sh root@ubuntu:~# dhclient -v eth0.1 Internet Systems Consortium DHCP Client 4.2.4 Copyright 2004-2012 Internet Systems Consortium. All rights reserved. For info, please visit https://www.isc.org/software/dhcp/ Listening on LPF/eth0.1/00:00:00:00:00:11 Sending on LPF/eth0.1/00:00:00:00:00:11 Sending on Socket/fallback DHCPDISCOVER on eth0.1 to 255.255.255.255 port 67 interval 3 (xid=0x568eac05) DHCPREQUEST of 192.168.1.145 on eth0.1 to 255.255.255.255 port 67 (xid=0x568eac05) DHCPOFFER of 192.168.1.145 from 192.168.1.254 DHCPACK of 192.168.1.145 from 192.168.1.254 bound to 192.168.1.145 -- renewal in 1473 seconds. root@ubuntu:~# dhclient -v eth0.2 Internet Systems Consortium DHCP Client 4.2.4 Copyright 2004-2012 Internet Systems Consortium. All rights reserved. For info, please visit https://www.isc.org/software/dhcp/ Listening on LPF/eth0.2/00:00:00:00:00:22 Sending on LPF/eth0.2/00:00:00:00:00:22 Sending on Socket/fallback DHCPDISCOVER on eth0.2 to 255.255.255.255 port 67 interval 3 (xid=0x21e3114e) DHCPREQUEST of 192.168.1.146 on eth0.2 to 255.255.255.255 port 67 (xid=0x21e3114e) DHCPOFFER of 192.168.1.146 from 192.168.1.254 DHCPACK of 192.168.1.146 from 192.168.1.254 bound to 192.168.1.146 -- renewal in 1366 seconds. root@ubuntu:~# dhclient -v eth0.3 Internet Systems Consortium DHCP Client 4.2.4 Copyright 2004-2012 Internet Systems Consortium. All rights reserved. For info, please visit https://www.isc.org/software/dhcp/ Listening on LPF/eth0.3/00:00:00:00:00:33 Sending on LPF/eth0.3/00:00:00:00:00:33 Sending on Socket/fallback DHCPDISCOVER on eth0.3 to 255.255.255.255 port 67 interval 3 (xid=0x11dc5f03) DHCPREQUEST of 192.168.1.147 on eth0.3 to 255.255.255.255 port 67 (xid=0x11dc5f03) DHCPOFFER of 192.168.1.147 from 192.168.1.254 DHCPACK of 192.168.1.147 from 192.168.1.254 bound to 192.168.1.147 -- renewal in 1657 seconds. root@ubuntu:~# ip -4 link sh 1: lo: <LOOPBACK,UP,LOWER_UP> mtu 65536 qdisc noqueue state UNKNOWN mode DEFAULT group default link/loopback 00:00:00:00:00:00 brd 00:00:00:00:00:00 2: eth0: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qdisc pfifo_fast state UP mode DEFAULT group default qlen 1000 link/ether 00:0c:29:bc:fc:8b brd ff:ff:ff:ff:ff:ff 18: eth0.1@eth0: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qdisc noqueue state UNKNOWN mode DEFAULT group default link/ether 00:00:00:00:00:11 brd ff:ff:ff:ff:ff:ff 19: eth0.2@eth0: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qdisc noqueue state UNKNOWN mode DEFAULT group default link/ether 00:00:00:00:00:22 brd ff:ff:ff:ff:ff:ff 20: eth0.3@eth0: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qdisc noqueue state UNKNOWN mode DEFAULT group default link/ether 00:00:00:00:00:33 brd ff:ff:ff:ff:ff:ff root@ubuntu:~# ip -4 addr sh 1: lo: <LOOPBACK,UP,LOWER_UP> mtu 65536 qdisc noqueue state UNKNOWN group default inet 127.0.0.1/8 scope host lo valid_lft forever preferred_lft forever 18: eth0.1@eth0: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qdisc noqueue state UNKNOWN group default inet 192.168.1.145/24 brd 192.168.1.255 scope global eth0.1 valid_lft forever preferred_lft forever 19: eth0.2@eth0: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qdisc noqueue state UNKNOWN group default inet 192.168.1.146/24 brd 192.168.1.255 scope global eth0.2 valid_lft forever preferred_lft forever 20: eth0.3@eth0: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qdisc noqueue state UNKNOWN group default inet 192.168.1.147/24 brd 192.168.1.255 scope global eth0.3 valid_lft forever preferred_lft forever root@ubuntu:~# ip -4 route sh default via 192.168.1.254 dev eth0.1 192.168.1.0/24 dev eth0.1 proto kernel scope link src 192.168.1.145 192.168.1.0/24 dev eth0.2 proto kernel scope link src 192.168.1.146 192.168.1.0/24 dev eth0.3 proto kernel scope link src 192.168.1.147 root@ubuntu:~# arping -c 5 -I eth0.1 192.168.1.254 ARPING 192.168.1.254 from 192.168.1.145 eth0.1 Unicast reply from 192.168.1.254 [58:98:35:57:a0:70] 6.936ms Unicast reply from 192.168.1.254 [58:98:35:57:a0:70] 2.986ms Unicast reply from 192.168.1.254 [58:98:35:57:a0:70] 0.654ms Unicast reply from 192.168.1.254 [58:98:35:57:a0:70] 5.137ms Unicast reply from 192.168.1.254 [58:98:35:57:a0:70] 2.426ms Sent 5 probes (1 broadcast(s)) Received 5 response(s) root@ubuntu:~# arping -c 5 -I eth0.2 192.168.1.254 ARPING 192.168.1.254 from 192.168.1.146 eth0.2 Unicast reply from 192.168.1.254 [58:98:35:57:a0:70] 5.665ms Unicast reply from 192.168.1.254 [58:98:35:57:a0:70] 3.753ms Unicast reply from 192.168.1.254 [58:98:35:57:a0:70] 16.500ms Unicast reply from 192.168.1.254 [58:98:35:57:a0:70] 3.287ms Unicast reply from 192.168.1.254 [58:98:35:57:a0:70] 32.438ms Sent 5 probes (1 broadcast(s)) Received 5 response(s) root@ubuntu:~# arping -c 5 -I eth0.3 192.168.1.254 ARPING 192.168.1.254 from 192.168.1.147 eth0.3 Unicast reply from 192.168.1.254 [58:98:35:57:a0:70] 4.422ms Unicast reply from 192.168.1.254 [58:98:35:57:a0:70] 2.429ms Unicast reply from 192.168.1.254 [58:98:35:57:a0:70] 2.321ms Unicast reply from 192.168.1.254 [58:98:35:57:a0:70] 40.423ms Unicast reply from 192.168.1.254 [58:98:35:57:a0:70] 2.268ms Sent 5 probes (1 broadcast(s)) Received 5 response(s) root@ubuntu:~# tcpdump -n -i eth0.1 -v & [1] 5317 root@ubuntu:~# ping -c5 -q -I eth0.1 192.168.1.254 PING 192.168.1.254 (192.168.1.254) from 192.168.1.145 eth0.1: 56(84) bytes of data. tcpdump: listening on eth0.1, link-type EN10MB (Ethernet), capture size 65535 bytes 13:18:37.612558 IP (tos 0x0, ttl 64, id 2595, offset 0, flags [DF], proto ICMP (1), length 84) 192.168.1.145 > 192.168.1.254: ICMP echo request, id 5318, seq 2, length 64 13:18:37.618864 IP (tos 0x68, ttl 64, id 14493, offset 0, flags [none], proto ICMP (1), length 84) 192.168.1.254 > 192.168.1.145: ICMP echo reply, id 5318, seq 2, length 64 13:18:37.743650 ARP, Ethernet (len 6), IPv4 (len 4), Request who-has 192.168.1.87 tell 192.168.1.86, length 46 13:18:38.134997 IP (tos 0x0, ttl 128, id 23547, offset 0, flags [none], proto UDP (17), length 229) 192.168.1.86.138 > 192.168.1.255.138: NBT UDP PACKET(138) 13:18:38.614580 IP (tos 0x0, ttl 64, id 2596, offset 0, flags [DF], proto ICMP (1), length 84) 192.168.1.145 > 192.168.1.254: ICMP echo request, id 5318, seq 3, length 64 13:18:38.793479 IP (tos 0x68, ttl 64, id 14495, offset 0, flags [none], proto ICMP (1), length 84) 192.168.1.254 > 192.168.1.145: ICMP echo reply, id 5318, seq 3, length 64 13:18:39.151282 IP6 (class 0x68, hlim 255, next-header ICMPv6 (58) payload length: 32) fe80::5a98:35ff:fe57:e070 > ff02::1:ff6b:e9b4: [icmp6 sum ok] ICMP6, neighbor solicitation, length 32, who has 2001:818:d812:da00:8ae3:abff:fe6b:e9b4 source link-address option (1), length 8 (1): 58:98:35:57:a0:70 13:18:39.615612 IP (tos 0x0, ttl 64, id 2597, offset 0, flags [DF], proto ICMP (1), length 84) 192.168.1.145 > 192.168.1.254: ICMP echo request, id 5318, seq 4, length 64 13:18:39.746981 IP (tos 0x68, ttl 64, id 14496, offset 0, flags [none], proto ICMP (1), length 84) 192.168.1.254 > 192.168.1.145: ICMP echo reply, id 5318, seq 4, length 64 --- 192.168.1.254 ping statistics --- 5 packets transmitted, 5 received, 0% packet loss, time 4008ms rtt min/avg/max/mdev = 2.793/67.810/178.934/73.108 ms root@ubuntu:~# killall tcpdump >> /dev/null 2>&1 9 packets captured 12 packets received by filter 0 packets dropped by kernel [1]+ Done tcpdump -n -i eth0.1 -v root@ubuntu:~# tcpdump -n -i eth0.2 -v & [1] 5320 root@ubuntu:~# ping -c5 -q -I eth0.2 192.168.1.254 PING 192.168.1.254 (192.168.1.254) from 192.168.1.146 eth0.2: 56(84) bytes of data. tcpdump: listening on eth0.2, link-type EN10MB (Ethernet), capture size 65535 bytes 13:18:41.536874 ARP, Ethernet (len 6), IPv4 (len 4), Reply 192.168.1.254 is-at 58:98:35:57:a0:70, length 46 13:18:41.536933 IP (tos 0x0, ttl 64, id 2599, offset 0, flags [DF], proto ICMP (1), length 84) 192.168.1.146 > 192.168.1.254: ICMP echo request, id 5321, seq 1, length 64 13:18:41.539255 IP (tos 0x68, ttl 64, id 14507, offset 0, flags [none], proto ICMP (1), length 84) 192.168.1.254 > 192.168.1.146: ICMP echo reply, id 5321, seq 1, length 64 13:18:42.127715 ARP, Ethernet (len 6), IPv4 (len 4), Request who-has 192.168.1.87 tell 192.168.1.86, length 46 13:18:42.511725 IP (tos 0x0, ttl 64, id 2600, offset 0, flags [DF], proto ICMP (1), length 84) 192.168.1.146 > 192.168.1.254: ICMP echo request, id 5321, seq 2, length 64 13:18:42.514385 IP (tos 0x68, ttl 64, id 14527, offset 0, flags [none], proto ICMP (1), length 84) 192.168.1.254 > 192.168.1.146: ICMP echo reply, id 5321, seq 2, length 64 13:18:42.743856 ARP, Ethernet (len 6), IPv4 (len 4), Request who-has 192.168.1.87 tell 192.168.1.86, length 46 13:18:43.511727 IP (tos 0x0, ttl 64, id 2601, offset 0, flags [DF], proto ICMP (1), length 84) 192.168.1.146 > 192.168.1.254: ICMP echo request, id 5321, seq 3, length 64 13:18:43.513768 IP (tos 0x68, ttl 64, id 14528, offset 0, flags [none], proto ICMP (1), length 84) 192.168.1.254 > 192.168.1.146: ICMP echo reply, id 5321, seq 3, length 64 13:18:43.637598 IP (tos 0x0, ttl 128, id 23551, offset 0, flags [none], proto UDP (17), length 225) 192.168.1.86.17500 > 255.255.255.255.17500: UDP, length 197 13:18:43.641185 IP (tos 0x0, ttl 128, id 23552, offset 0, flags [none], proto UDP (17), length 225) 192.168.1.86.17500 > 192.168.1.255.17500: UDP, length 197 13:18:43.641201 IP (tos 0x0, ttl 128, id 23553, offset 0, flags [none], proto UDP (17), length 225) 192.168.1.86.17500 > 255.255.255.255.17500: UDP, length 197 13:18:43.743890 ARP, Ethernet (len 6), IPv4 (len 4), Request who-has 192.168.1.87 tell 192.168.1.86, length 46 13:18:44.510758 IP (tos 0x0, ttl 64, id 2602, offset 0, flags [DF], proto ICMP (1), length 84) 192.168.1.146 > 192.168.1.254: ICMP echo request, id 5321, seq 4, length 64 13:18:44.512892 IP (tos 0x68, ttl 64, id 14538, offset 0, flags [none], proto ICMP (1), length 84) 192.168.1.254 > 192.168.1.146: ICMP echo reply, id 5321, seq 4, length 64 13:18:45.510794 IP (tos 0x0, ttl 64, id 2603, offset 0, flags [DF], proto ICMP (1), length 84) 192.168.1.146 > 192.168.1.254: ICMP echo request, id 5321, seq 5, length 64 13:18:45.519701 IP (tos 0x68, ttl 64, id 14539, offset 0, flags [none], proto ICMP (1), length 84) 192.168.1.254 > 192.168.1.146: ICMP echo reply, id 5321, seq 5, length 64 13:18:49.287554 IP6 (class 0x68, hlim 255, next-header ICMPv6 (58) payload length: 32) fe80::5a98:35ff:fe57:e070 > ff02::1:ff6b:e9b4: [icmp6 sum ok] ICMP6, neighbor solicitation, length 32, who has 2001:818:d812:da00:8ae3:abff:fe6b:e9b4 source link-address option (1), length 8 (1): 58:98:35:57:a0:70 13:18:50.013463 IP (tos 0x0, ttl 255, id 50737, offset 0, flags [DF], proto UDP (17), length 73) 192.168.1.146.5353 > 224.0.0.251.5353: 0 [2q] PTR (QM)? _ipps._tcp.local. PTR (QM)? _ipp._tcp.local. (45) 13:18:50.218874 IP6 (class 0x68, hlim 255, next-header ICMPv6 (58) payload length: 32) fe80::5a98:35ff:fe57:e070 > ff02::1:ff6b:e9b4: [icmp6 sum ok] ICMP6, neighbor solicitation, length 32, who has 2001:818:d812:da00:8ae3:abff:fe6b:e9b4 source link-address option (1), length 8 (1): 58:98:35:57:a0:70 13:18:51.129961 IP6 (class 0x68, hlim 255, next-header ICMPv6 (58) payload length: 32) fe80::5a98:35ff:fe57:e070 > ff02::1:ff6b:e9b4: [icmp6 sum ok] ICMP6, neighbor solicitation, length 32, who has 2001:818:d812:da00:8ae3:abff:fe6b:e9b4 source link-address option (1), length 8 (1): 58:98:35:57:a0:70 13:18:52.197074 IP6 (hlim 255, next-header UDP (17) payload length: 53) 2001:818:d812:da00:200:ff:fe00:22.5353 > ff02::fb.5353: [udp sum ok] 0 [2q] PTR (QM)? _ipps._tcp.local. PTR (QM)? _ipp._tcp.local. (45) 13:18:54.128240 ARP, Ethernet (len 6), IPv4 (len 4), Request who-has 192.168.1.87 tell 192.168.1.86, length 46 --- 192.168.1.254 ping statistics --- 5 packets transmitted, 0 received, 100% packet loss, time 4000ms root@ubuntu:~# killall tcpdump >> /dev/null 2>&1 13:18:54.657731 IP6 (class 0x68, hlim 255, next-header ICMPv6 (58) payload length: 32) fe80::5a98:35ff:fe57:e070 > ff02::1:ff6b:e9b4: [icmp6 sum ok] ICMP6, neighbor solicitation, length 32, who has 2001:818:d812:da00:8ae3:abff:fe6b:e9b4 source link-address option (1), length 8 (1): 58:98:35:57:a0:70 13:18:54.743174 ARP, Ethernet (len 6), IPv4 (len 4), Request who-has 192.168.1.87 tell 192.168.1.86, length 46 25 packets captured 26 packets received by filter 0 packets dropped by kernel [1]+ Done tcpdump -n -i eth0.2 -v root@ubuntu:~# tcpdump -n -i eth0.3 icmp & [1] 5324 root@ubuntu:~# ping -c5 -q -I eth0.3 192.168.1.254 PING 192.168.1.254 (192.168.1.254) from 192.168.1.147 eth0.3: 56(84) bytes of data. tcpdump: verbose output suppressed, use -v or -vv for full protocol decode listening on eth0.3, link-type EN10MB (Ethernet), capture size 65535 bytes 13:18:56.373434 IP 192.168.1.147 > 192.168.1.254: ICMP echo request, id 5325, seq 1, length 64 13:18:57.372116 IP 192.168.1.147 > 192.168.1.254: ICMP echo request, id 5325, seq 2, length 64 13:18:57.381263 IP 192.168.1.254 > 192.168.1.147: ICMP echo reply, id 5325, seq 2, length 64 13:18:58.371141 IP 192.168.1.147 > 192.168.1.254: ICMP echo request, id 5325, seq 3, length 64 13:18:58.373275 IP 192.168.1.254 > 192.168.1.147: ICMP echo reply, id 5325, seq 3, length 64 13:18:59.371165 IP 192.168.1.147 > 192.168.1.254: ICMP echo request, id 5325, seq 4, length 64 13:18:59.373259 IP 192.168.1.254 > 192.168.1.147: ICMP echo reply, id 5325, seq 4, length 64 13:19:00.371211 IP 192.168.1.147 > 192.168.1.254: ICMP echo request, id 5325, seq 5, length 64 13:19:00.373278 IP 192.168.1.254 > 192.168.1.147: ICMP echo reply, id 5325, seq 5, length 64 --- 192.168.1.254 ping statistics --- 5 packets transmitted, 1 received, 80% packet loss, time 4001ms rtt min/avg/max/mdev = 13.666/13.666/13.666/0.000 ms root@ubuntu:~# killall tcpdump >> /dev/null 2>&1 9 packets captured 10 packets received by filter 0 packets dropped by kernel [1]+ Done tcpdump -n -i eth0.3 icmp root@ubuntu:~# arp -n Address HWtype HWaddress Flags Mask Iface 192.168.1.254 ether 58:98:35:57:a0:70 C eth0.1 192.168.1.254 ether 58:98:35:57:a0:70 C eth0.2 192.168.1.254 ether 58:98:35:57:a0:70 C eth0.3

  Read the article

• How to deal with arrays of data in cookies

  - by peter

  Hi all, I want to store data in a cookie and I am not exactly sure how I will go about it. The data is the UserName, and Password values for the users that are logging into a website, e.g. sometime like this UserName = bob, Password=Passw0rd1 UserName = harry, Password=BLANK UserName = george, Password=R0jjd6s What this means is that bob and george logged into the site and chose to have their password remembered, but harry chose for his password not to be remembered. So on the login dialog a dropdown will be present with all the usernames in it 'bob', 'harry', 'george'. If they select the username bob the password will automatically be filled in, etc. So how does that information need to be stored in the cookie? Like it is above, or does it have to be, UserName1 = bob, Password1=Passw0rd1 UserName2 = harry, Password2=BLANK UserName3 = george, Password3=R0jjd6s Are the username and password values actually stored in the same cookie, or is each piece of data separate? Any information would be good.

  Read the article

• Python Expand Tabs Length Calculation

  - by Mithrill

  I'm confused by how the length of a string is calculated when expandtabs is used. I thought expandtabs replaces tabs with the appropriate number of spaces (with the default number of spaces per tab being 8). However, when I ran the commands using strings of varying lengths and varying numbers of tabs, the length calculation was different than I thought it would be (i.e., each tab didn't always result in the string length being increased by 8 for each instance of "/t"). Below is a detailed script output with comments explaining what I thought should be the result of the command executed above. Would someone please explain the how the length is calculated when expand tabs is used? IDLE 2.6.5 >>> s = '\t' >>> print len(s) 1 >>> #the length of the string without expandtabs was one (1 tab counted as a single space), as expected. >>> print len(s.expandtabs()) 8 >>> #the length of the string with expandtabs was eight (1 tab counted as eight spaces). >>> s = '\t\t' >>> print len(s) 2 >>> #the length of the string without expandtabs was 2 (2 tabs, each counted as a single space). >>> print len(s.expandtabs()) 16 >>> #the length of the string with expandtabs was 16 (2 tabs counted as 8 spaces each). >>> s = 'abc\tabc' >>> print len(s) 7 >>> #the length of the string without expandtabs was seven (6 characters and 1 tab counted as a single space). >>> print len(s.expandtabs()) 11 >>> #the length of the string with expandtabs was NOT 14 (6 characters and one 8 space tabs). >>> s = 'abc\tabc\tabc' >>> print len(s) 11 >>> #the length of the string without expandtabs was 11 (9 characters and 2 tabs counted as a single space). >>> print len(s.expandtabs()) 19 >>> #the length of the string with expandtabs was NOT 25 (9 characters and two 8 space tabs). >>>

  Read the article

• T-SQL String Functions: difference between using Left/Right and Substring and strange behaviour

  - by TheObserver

  I am using SQL Server 2008 & 2005 (Express). I'm trying to extract part of an alpha numeric string from a varchar field. RIGHT(str_field,3) yields null values but substring(str_field, len(str_field)-2, len(str_field)) gives the right value. left(str_field,7) gives the expected values. What gives? I would have thought that RIGHT(str_field,3) and substring(str_field, len(str_field)-2, len(str_field)) are equivalent expressions.

  Read the article

• ruby restrict attr_accessor in subclass

  - by Arivarasan

  I want restrict the access of superclass's method in subclass class Parent attr_accessor :first_name, :last_name def initialize(first_name, last_name) @first_name, @last_name = first_name, last_name end def full_name @first_name + " " + @last_name end end class Son < Parent attr_accessor :first_name def initialize(parent, first_name) @first_name = first_name @last_name = parent.last_name end def full_name @first_name + " " + @last_name end end p = Parent.new("Bharat", "Chipli") puts p.full_name s = Son.new(p, "Harry") s.last_name= "Smith" puts s.full_name here i am getting son's full name as "Harry Smith", but i want "Harry Chipli"

  Read the article

• Why my shell program wont open the file got as argument in function "cat"

  - by anna karenina

  I included the code below, sorry to bother you with so much code. Argument parsing is ok, i checked it out with watches. I've put some printfs to check out where the problem may be and it seems that it wont open the file cat receives as argument. i called from shell like "cat -b file" #include <stdio.h> #include <stdlib.h> #include <unistd.h> #include <string.h> #define TRUE 0 #define FALSE 1 void yes(int argc, char *argv[]); int cat(int argc, char *argv[]); //#include "cat.h" //#include "yes.h" //#include"tee.h" char buf[50],c[10], *p2,*p, *pch; int count; char *matrix[20]; void yes(int argc, char *argv[]) { int i; // if (argc >= 2 && *argv[1] == '-') // { //printf("ERROR!"); //} //if (argc == 1) // { while (1) if (puts("y") == EOF) { perror("yes"); exit(FALSE); } // } while (1) for (i = 1; i < argc; i++) if (fputs(argv[i], stdout) == EOF || putchar(i == argc - 1 ? '\n' : ' ') == EOF) { perror("yes"); exit(FALSE); } //exit(TRUE); } int main(int argc, char *argv[]) { //p=(char *)malloc(sizeof(char)*50); do { fprintf (stderr, "$ "); fgets (buf,50,stdin); p=buf; fprintf (stderr, "Comanda primita de la tastatura: "); fputs (buf, stderr); int i=0,j=0; //strcpy(p,buf); strcpy(c,"\0"); while (buf[i] == ' ') { i++; p++; } if (buf[i] == '#') fprintf (stderr, "Nici o comanda, ci e un comentariu!\n"); else { j=0; while (buf[i] != ' ' && buf[i] != '\n') { i++; j++; } strncpy (c,p,j); fprintf (stderr, "%s\n",c); if (strcmp (c,"yes") == 0) { p2 = p+j+1; pch = strtok (p2," "); count = 0; while (pch != NULL) { //printf ("%s\n",pch); matrix[count] = strdup(pch); pch = strtok (NULL, " "); count++; } yes(count, matrix); fprintf (stderr, "Aici se va executa comanda yes\n"); } else if (strcmp (c,"cat") == 0) { p2 = p+j+1; pch = strtok (p2," "); count = 0; while (pch != NULL) { //printf ("%s\n",pch); matrix[count] = strdup(pch); pch = strtok (NULL, " "); count++; } cat(count,matrix); fprintf (stderr, "Aici se va executa comanda cat \n"); } else if (strcmp (c,"tee") == 0) { //tee(); fprintf(stderr, "Aici se va executa comanda tee\n"); } fprintf (stderr, "Aici se va executa comanda basename\n"); strcpy(buf,"\0"); } } while (strcmp(c, "exit") != 0); fprintf (stderr, "Terminat corect!\n"); return 0; } int cat(int argc, char *argv[]) { int c ; opterr = 0 ; optind = 0 ; char number = 0; char squeeze = 0; char marker = 0; fprintf(stderr,"SALUT< SUNT IN FUNCTIZE>\n"); while ((c = getopt (argc, argv, "bnsE")) != -1) switch (c) { case 'b' : number = 1; break; case 'n' : number = 2; break; case 'm' : marker = 1; break; case 's' : squeeze = 1; break; case 'E' : marker = 1; break; } if (optind + 1 != argc) { fprintf (stderr, "\tWrong arguments!\n") ; return -1 ; } FILE * fd = fopen (argv[optind], "r"); printf("am deschis fisierul %s ",argv[optind]); if (fd == NULL) { printf("FISIER NULL asdasdasdasdasd"); return 1; } char line[1025]; int line_count = 1; while (!feof(fd)) { fgets(line, 1025, fd); printf("sunt in while :> %s",line); int len = strlen(line); if (line[len - 1] == '\n') { if(len - 2 >= 0) { if(line[len - 2] == '\r') { line[len - 2] = '\0'; len -= 2; } else { line[len - 1] = '\0'; len -= 1; } } else { line[len - 1] = '\0'; len -= 1; } } if (squeeze == 1 && len == 0) continue; if (number == 1) { fprintf (stdout, "%4d ", line_count); line_count++; } else if (number == 2) { if (len > 0) { fprintf (stdout, "%4d ", line_count); line_count++; } else fprintf (stdout, " "); } fprintf(stdout, "%s", line); if (marker == 1) fprintf(stdout, "$"); fprintf(stdout, "\n"); } fclose (fd); return 0 ; }

  Read the article

• Recursion inside while loop, How does it work ?

  - by M.H

  Can you please tell me how does this java code work? : public class Main { public static void main (String[] args) { Strangemethod(5); } public static void Strangemethod(int len) { while(len > 1){ System.out.println(len-1); Strangemethod(len - 1); } } } I tried to debug it and follow the code step by step but I didn't understand it.

  Read the article

< Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >