Search Results

Search found 33205 results on 1329 pages for 'login config xml'.

Page 5/1329 | < Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >

  • Login speed varies over time

    - by Brock Dute
    I have a weird problem with my Ubuntu right now. My login speed is never consistent for months, sometimes it changes within weeks. What I mean is, for example, within 2 weeks, boot time is really fast and speedy but then say after that, boot time becomes noticeably slower. Usually, right after the ubuntu login sound plays, my desktop would've finished loading already but sometimes, the ubuntu login sound is already done playing and I'm still in this stage of the login -- image, exactly like that. Any reasons for this? Sometimes it slows down after updates (which I think is kind of normal?) After a few reboots, it becomes fast then randomly it becomes slow again.

    Read the article

  • Laptop works fine with ac adapter, hangs after login screen using battery

    - by tavoton
    I did an Ubuntu 10.10 Desktop Edition clean install (amd64 version) on a notebook Medion Akoya E1311. With AC adapter everything works fine, but using battery, it hangs after login screen. I can type login, password too, and I can press login button. But then I can see mouse cursor and lower task bar, not upper, and nothing works. The only thing I can do is login on a terminal with ctrl+alt+F1, this is ok. Nothing seems alive on Gnome except mouse cursor. The only thing I did after Ubuntu fresh install was donwloading driver for RTL8191SE from Realtek web, because WiFi didn't work, now works fine, with ac adapter of course. Hardware is a Notebook Medion Akoya E1311 AMD Sempron 210U 1 GB DDR2 ATI RS690M (Radeon X1200 Series) Western Digital 160GB wireless RTL8191SEvB ethernet RTL8101E/RTL8102E

    Read the article

  • Ubuntu 12.04LTS stuck at login mouse and keyboard not responding

    - by user169954
    I have Ubuntu 12.04LTS installed on a dual-booted machine (i5 dual core 8G ram) and it's been working fine, but today for some reason when I logged out and tried to log back in it is stuck at the login page, i.e. the mouse and the keyboard are not responding. The mouse is stuck at the top left corner of my screen, and I can do nothing but to turn the machine off. (I have been using logitech wireless mouse and keyboard.) I can not access the virtual console (Alt-F1 or Cntrl-Alt-F1) either! Here is what I have tried so far: Verified it is not a H/W problem since the mouse and keyboard work fine with windows7 Booted with ubuntu installation dvd and ran trial mode and mouse and keyboard worked fine. Tried bypassing the login screen by booting into recovery mode and editing tty1.conf, but to no avail. I moved .Xauthority .profile and .bashrc from my $HOME to another location so my login would proceed completely by system defaults. But this did not help From recovery mode commandline used to dpkg-reconfigure to switch between gdm and lightgdm. This did not help either. By the way, when in recovery mode as root from command line I mount the filesystem, all apps work fine. Python is Ok, octave is ok, vi is ok etc. I have a feeling if I could only bypass the login screen, and automatically get into the desktop, I will be ok. But I haven't been able to accomplish this either. I desperately need help please. Thank you in advance. Update: So I tried to switch to lightdm by dpkg-configure lightdm. This at least brings me up to the classical linux commandline login prompt but without a gui. Should I install startx? Should I install ubuntu-desktop?

    Read the article

  • Can't type my username and password, random freeze at login

    - by rakesh
    My netbook runs a dual OS(Windows7 & Ubuntu 12.04). After Ubuntu login screen appears, that’s it, it gets hanged, can't even move my cursor nor type my user name. I had to turn off my system and boot again. Still its not sure that it won't freeze out at login screen again, but this is the temporary solution I have to get into Ubuntu. This freezing at login screen doesn't happen every time, it happens randomly. It seems like I had to enter into Ubuntu purely based on my luck, which is quite irritating. I found many other types of login problem in Ubuntu when I googled, which were quite different from my case. So any1 kindly help me out.

    Read the article

  • Login screen won't accept my password

    - by Raven H
    I recently upgraded to 12.04 from 11.10 and since upgrading have been unable to login to my user profile. The upgrade went okay and I can login to a guest session fine but whenever I try to login to my profile, after entering my password, I just return to the login screen. I've changed my password in Root (passwd 'username')and can log in to tty1 with no issues, it's just in GUI I'm having problems. I'm using a HP dv7 laptop, 32 bit Ubuntu install, Intel® Core™2 Duo CPU P7350 @ 2.00GHz × 2, Nvidia graphics. Any help would be appreciated.

    Read the article

  • "input not supported" at login screen after ati driver is installed

    - by squalo78
    I'm running ubuntu 11.10 and I installed the Ati driver from the oficial page. When i reboot, the grub and the splash screen are working (at lower resolution) but instead of the login screen, it shows "input not supported" message. If I use "Ctrl+Alt+ keypad +" I can see my login screen at 640x480 resolution and login. I don't know how to make login screen displays 1440x900@60, that is the resolution set on my session. I'm running Ubuntu 11.10 with ati hd4200 video card, a monitor acer aL1916w that supports the resolution 1440x900.

    Read the article

  • After install of kubuntu-full, no longer have access to Unity login

    - by ResidentBiscuit
    I installed Ubuntu 13.10 about a week ago. Just today I went ahead and installed kubuntu-full to get KDE and it's associated programs. I want to keep the Unity login screen though (default when you install Ubuntu). I can't seem to get this working. Doing a 'sudo dpkg-reconfigure gdm' or 'sudo dpkg-reconfigure lightdm' and choosing either one of those does not get me there. If I choose gdm, I just end up with a gnome login screen. If I pick lightdm, I end up with a KDE login screen. Doesn't seem to be an option for choosing the unity login screen (whatever it's called). Any assistance?

    Read the article

  • How often are comments used in XML documents?

    - by Jeffrey Sweeney
    I'm currently developing a web-based XML managing program for a client (though I may 'market' it for future clients). Currently, it reads an XML document, converts it into manageable Javascript objects, and ultimately spits out indented, easy to read XML code. Edit: The program would be used by clients that don't feel like learning XML to add items or tags, but I (or another XML developer) may use the raw data for quick changes without using an editor. I feel like fundamentally, its ready for release, but I'm wondering if I should go the extra mile and allow support for remembering (and perhaps making) comments before generating the resulting XML. Considering that these XML files will probably never be read without a program interpreting it, should I really bother adding support for comments? I'll probably be the only one looking at raw files, and I usually don't use comments for XML anyway. So, are comments common/important in most XML documents?

    Read the article

  • PHP Multiple User Login Form - Navigation to Different Pages Based on Login Credentials

    - by Zulu Irminger
    I am trying to create a login page that will send the user to a different index.php page based on their login credentials. For example, should a user with the "IT Technician" role log in, they will be sent to "index.php", and if a user with the "Student" role log in, they will be sent to the "student/index.php" page. I can't see what's wrong with my code, but it's not working... I'm getting the "wrong login credentials" message every time I press the login button. My code for the user login page is here: <?php session_start(); if (isset($_SESSION["manager"])) { header("location: http://www.zuluirminger.com/SchoolAdmin/index.php"); exit(); } ?> <?php if (isset($_POST["username"]) && isset($_POST["password"]) && isset($_POST["role"])) { $manager = preg_replace('#[^A-Za-z0-9]#i', '', $_POST["username"]); $password = preg_replace('#[^A-Za-z0-9]#i', '', $_POST["password"]); $role = preg_replace('#[^A-Za-z0-9]#i', '', $_POST["role"]); include "adminscripts/connect_to_mysql.php"; $sql = mysql_query("SELECT id FROM Users WHERE username='$manager' AND password='$password' AND role='$role' LIMIT 1"); $existCount = mysql_num_rows($sql); if (($existCount == 1) && ($role == 'IT Technician')) { while ($row = mysql_fetch_array($sql)) { $id = $row["id"]; } $_SESSION["id"] = $id; $_SESSION["manager"] = $manager; $_SESSION["password"] = $password; $_SESSION["role"] = $role; header("location: http://www.zuluirminger.com/SchoolAdmin/index.php"); } else { echo 'Your login details were incorrect. Please try again <a href="http://www.zuluirminger.com/SchoolAdmin/index.php">here</a>'; exit(); } } ?> <?php if (isset($_POST["username"]) && isset($_POST["password"]) && isset($_POST["role"])) { $manager = preg_replace('#[^A-Za-z0-9]#i', '', $_POST["username"]); $password = preg_replace('#[^A-Za-z0-9]#i', '', $_POST["password"]); $role = preg_replace('#[^A-Za-z0-9]#i', '', $_POST["role"]); include "adminscripts/connect_to_mysql.php"; $sql = mysql_query("SELECT id FROM Users WHERE username='$manager' AND password='$password' AND role='$role' LIMIT 1"); $existCount = mysql_num_rows($sql); if (($existCount == 1) && ($role == 'Student')) { while ($row = mysql_fetch_array($sql)) { $id = $row["id"]; } $_SESSION["id"] = $id; $_SESSION["manager"] = $manager; $_SESSION["password"] = $password; $_SESSION["role"] = $role; header("location: http://www.zuluirminger.com/SchoolAdmin/student/index.php"); } else { echo 'Your login details were incorrect. Please try again <a href="http://www.zuluirminger.com/SchoolAdmin/index.php">here</a>'; exit(); } } ?> And the form that the data is pulled from is shown here: <form id="LoginForm" name="LoginForm" method="post" action="http://www.zuluirminger.com/SchoolAdmin/user_login.php"> User Name:<br /> <input type="text" name="username" id="username" size="50" /><br /> <br /> Password:<br /> <input type="password" name="password" id="password" size="50" /><br /> <br /> Log in as: <select name="role" id="role"> <option value="">...</option> <option value="Head">Head</option> <option value="Deputy Head">Deputy Head</option> <option value="IT Technician">IT Technician</option> <option value="Pastoral Care">Pastoral Care</option> <option value="Bursar">Bursar</option> <option value="Secretary">Secretary</option> <option value="Housemaster">Housemaster</option> <option value="Teacher">Teacher</option> <option value="Tutor">Tutor</option> <option value="Sanatorium Staff">Sanatorium Staff</option> <option value="Kitchen Staff">Kitchen Staff</option> <option value="Parent">Parent</option> <option value="Student">Student</option> </select><br /> <br /> <input type="submit" name = "button" id="button" value="Log In" onclick="javascript:return validateLoginForm();" /> </h3> </form> Once logged in (and should the correct page be loaded, the validation code I have at the top of the script looks like this: <?php session_start(); if (!isset($_SESSION["manager"])) { header("location: http://www.zuluirminger.com/SchoolAdmin/user_login.php"); exit(); } $managerID = preg_replace('#[^0-9]#i', '', $_SESSION["id"]); $manager = preg_replace('#[^A-Za-z0-9]#i', '', $_SESSION["manager"]); $password = preg_replace('#[^A-Za-z0-9]#i', '', $_SESSION["password"]); $role = preg_replace('#[^A-Za-z0-9]#i', '', $_SESSION["role"]); include "adminscripts/connect_to_mysql.php"; $sql = mysql_query("SELECT id FROM Users WHERE username='$manager' AND password='$password' AND role='$role' LIMIT 1"); $existCount = mysql_num_rows($sql); if ($existCount == 0) { header("location: http://www.zuluirminger.com/SchoolAdmin/index.php"); exit(); } ?> Just so you're aware, the database table has the following fields: id, username, password and role. Any help would be greatly appreciated! Many thanks, Zulu

    Read the article

  • App.Config Transformation for Visual Studio 2010?

    - by Amitabh
    For Visual Studio 2010 Web based application we have Config Transformation features by which we can maintain multiple configuration files for different environments. But the same feature is not available for App.Config files for Windows Services/WinForms or Console Application. There is a workaround available as suggested on the following link. http://vishaljoshi.blogspot.com/2010/05/applying-xdt-magic-to-appconfig.html However it is not straightforward and requires no of steps. Is there an easier way to achieve the same for App.Config files?

    Read the article

  • perl xml parser get xml content within xml

    - by user391986
    How can I use XMLParser to get the item-@url, item-@replace and item-"value inside" for the content as a string of the node where item-@cone="one"? <cstep> <item cone="one" url="http://google.com/{ccc}/cthree" replace="{ccc}"> <itemsub conesub="conesub"> <itemsubsub conesubsub="conesubsub" /> </itemsub> </item> <item cone="two" url="http://google.com/{ccc}/cthree" replace="{ccc}"> <itemsub conesub="conesub"> <itemsubsub conesubsub="conesubsub" /> </itemsub> </item> </cstep>

    Read the article

  • storing user info/pass in web.config authentication

    - by Tomaszewski
    Hello, I am trying to write a simple internal app with some simple authentication. I'm also trying to make this quick and learn about the forms authentication via web.config. So i have my authentication working if I hard code my 'user name' and 'password' into C# code and do a simple conditional. However, I'm having a tough time storing the a user/pass to be checked against in the web.config file. The MSDN manual says to put this into the web.config: <authentication mode="Forms"> <forms loginUrl="login.aspx"> <credentials passwordFormat="SHA1"> <user name="user1" password="27CE4CA7FBF00685AF2F617E3F5BBCAFF7B7403C" /> <user name="user2" password="D108F80936F78DFDD333141EBC985B0233A30C7A" /> <user name="user3" password="7BDB09781A3F23885CD43177C0508B375CB1B7E9"/> </credentials> </forms> </authentication> However, the minute I add 'credentials' into the 'authentication' section, I get this error: Server Error in '/' Application. Configuration Error Description: An error occurred during the processing of a configuration file required to service this request. Please review the specific error details below and modify your configuration file appropriately. Parser Error Message: Unrecognized element 'credentials'. Source Error: Line 44: <authentication mode="Forms"> Line 45: <forms loginUrl="login.aspx" /> Line 46: <credentials> Line 47: Line 48: </credentials> Source File: C:\inetpub\wwwroot\asp\projects\passwordCatalog\passwordCatalog\web.config Line: 46 So my question is, how and where would I add the following in the web.config file? <credentials passwordFormat="SHA1"> <user name="johndoe" password="mypass123" /> </credentials>

    Read the article

  • Get the file path of current application's config file

    - by dummy
    The reason I asked this question is that I wanted to create a helper class for Remoting instantiation, and wanted to pass the appropriate app.exe.config (or web.config) file path to the RemotingConfiguration.Configure method, depending on the caller. Is there a way I could get the name of the config file for both Win and Web apps without checking if the application is Web or WinForms?

    Read the article

  • Copied App.config to (Assembly).exe.config but from folder debug application doesn't run

    - by uugan
    Gives error: "The specified named connection is either not found in the configuration, not intended to be used with the EntityClient provider, or not valid" App.config looks like and it's same as (Assembly.exe.config) config file for output: <?xml version="1.0" encoding="utf-8"?> <configuration> <connectionStrings> <add name="Entities1" connectionString="metadata=res://*/;provider=System.Data.SqlClient;provider connection string='data source=localhost;initial catalog=DatabaseName;integrated security=True;multipleactiveresultsets=True;App=EntityFramework'" providerName="System.Data.EntityClient" /> </connectionStrings> </configuration> How to run exe with it's configuration file? I tried to change '' to quot but nothing has changed.

    Read the article

  • How to implement a good system for login/out into a webapp

    - by Brandon Wang
    I am one of the developers at PassPad, a secure password generator and username storage system. We're still working on it, but I have a few questions on the best way to implement a secure login/out system. Right now, what we plan on doing is to have the login system save a cookie with the username and a session key, and that's all that serves as authentication. The server verifies the two to match. Upon login/out a new key is created. This is a security-related webapp and while we don't actually store any information that might make the user queasy, because it is security-oriented it makes it a necessity for us to at least appear secure in a way that the user would be happy with. Is there a better way to implement a login/out system in PHP? Preferably it won't take too much coding time or server resources. Is there anything else I need to implement, like brute-force protection, etc? How would I go about that?

    Read the article

  • Config file (App.config) does not update on new installation

    - by Muhammad Kashif Nadeem
    I am creating setup of my project using Visula Studio 2008. I am facing problem in setup installation. If I uninstall old setup (application) and install the new one then config file (App.config) updates the attributes (surely it is new file) of config file but if I install new setup without uninstalling the old one then config file does not update. from config file I mean MyProject.exe.config Why is this behavior of config file. Should it not be updated on installation of the new setup Is this possible to delete and copy the config file of new setup? Is there a way to update only config file forcefully during installation. Thanks for your help!

    Read the article

  • capture login screen-not sucssecful

    - by yinon
    I'm using Ubuntu 12.04 . If more information is needed, please tell me. I Tried some guides to cature my login screen: How can I take a screenshot of the login screen? http://www.howtoforge.com/how-to-take-a-screenshot-of-your-login-screen I tried the first one, but after running: $ sudo bash /tmp/shot.sh >/tmp/shot.xwd I'm getting this: No protocol specified No protocol specified xwd unable to open display ':0' and i'm getting an xwd file in my tmp folder. running the other commands giving errors. tried the second one, after running: chvt 8; sleep 5; XAUTHORITY=/var/gdm/:0.Xauth DISPLAY=:0.0 import -window root /tmp/gdm-login-shot.png I got: No protocol specified No protocol specified import: unable to open X server ':0.0' @ error/import.c/ImportImageCommand/366 Many Thanks for helping (: EDIT to vine_user: here the output from the terminal-I cacked it from within the system while I'm looged in: ubuntu@PrecisePangolin:~$ echo 'sleep 5; DISPLAY=:0 XAUTHORITY=/var/run/lightdm/root/$DISPLAYDISPLAY xwd -root' > /tmp/shot.sh ubuntu@PrecisePangolin:~$ sudo bash /tmp/shot.sh >/tmp/shot.xwd bash: /tmp/shot.xwd: Permission denied ubuntu@PrecisePangolin:~$ sudo su root@PrecisePangolin:/home/ubuntu# sudo bash /tmp/shot.sh >/tmp/shot.xwd No protocol specified No protocol specified xwd: unable to open display ':0' root@PrecisePangolin:/home/ubuntu# EDIT 2!: HERE IT IS!: just uploading-this uploadong site is better than other iuset to use (: :

    Read the article

  • Parsing xml files locally from assets folder using XmlPullParser

    - by Randolphg
    Im trying to parse a local xml file that I place in my assets folder. I've been trying to do this for almost a week now. Here is my test xml file Test1 Test2 Test3 Test4 Test5 I keep getting the same error: W/System.err(22458): org.xmlpull.v1.XmlPullParserException: unexpected type (position:TEXT Code: public void xmlParser() throws XmlPullParserException, IOException, ParserConfigurationException, SAXException { Log.d("tag", "xmlParsing...."); Arithmetic arthm = new Arithmetic(); XmlPullParserFactory xmlPF = XmlPullParserFactory.newInstance(); xmlPF.setValidating(false); XmlPullParser xml = xmlPF.newPullParser(); InputStream raw = getApplication().getAssets().open("menu.xml"); xml.setInput(raw, null); xml.nextTag(); Log.d("tag", "start parsing...."); String elementText = null; String elemName = null; int nofTags = 0; while (xml.getEventType() != XmlPullParser.END_DOCUMENT) { Log.d("tag", "while(xml.next)..."); switch (xml.getEventType()) { case XmlPullParser.START_DOCUMENT: Log.d("tag", "while (xml.getEventType() != XmlPullParser.END_DOCUMENT)"); break; case XmlPullParser.START_TAG: Log.d("tag", " case XmlPullParser.START_TAG"); elementText = xml.getName(); Log.d("tag", "elementText = " + elementText); if (xml.getEventType() != XmlPullParser.END_TAG) { xml.nextTag(); } break; case XmlPullParser.TEXT: Log.d("tag", "case TEXT"); if (elementText.equals("menu") && xml.isWhitespace()) { Log.d("tag", "<" + elementText + ">"); arthm.menu_name = xml.getText(); Log.d("tag", "value " + xml.getText() + " added"); } else if (elementText.equals("item")) { arthm.description = xml.getText(); Log.d("tag", "value " + xml.getText() + " added"); } else if (elementText.equals("SUBCATEGORY NAME")) { arthm.subcategoryDesc.add(xml.getText()); Log.d("tag", "value " + xml.getText() + " added"); } else if (elementText.equals("SUBCATEGORY DESC")) { arthm.subcategoryName.add(xml.getText()); Log.d("tag", "value " + xml.getText() + " added"); } break; case XmlPullParser.END_TAG: Log.d("tag", "case END_TAG"); nofTags += 1; String tags = Integer.toString(nofTags); Log.d("tags", elementText + " number of tags" + tags); if (xml.nextTag() != XmlPullParser.START_TAG) { xml.next(); } break; case XmlPullParser.END_DOCUMENT: Log.d("tag", "case END_DOCUMENT"); break; default: break; } } Log.d("tag", "Success!"); } Thanks in advance.

    Read the article

  • Reading xml document in firefox

    - by Searock
    I am trying to read customers.xml using javascript. My professor has taught us to read xml using `ActiveXObjectand he has given us an assignment to create a sample login page which checks username and password by reading customers.xml. I am trying to use DOMParser so that it works with firefox. But when I click on Login button I get this error. Error: syntax error Source File: file:///C:/Users/Searock/Desktop/home/project/project/login.html Line: 1, Column: 1 Source Code: customers.xml Here's my code. login.js var xmlDoc = 0; function checkUser() { var user = document.login.txtLogin.value; var pass = document.login.txtPass.value; //xmlDoc = new ActiveXObject("Microsoft.XMLDOM"); /* xmlDoc = document.implementation.createDocument("","",null); xmlDoc.async = "false"; xmlDoc.onreadystatechange = redirectUser; xmlDoc.load("customers.xml"); */ var parser = new DOMParser(); xmlDoc = parser.parseFromString("customers.xml", "text/xml"); alert(xmlDoc.documentElement.nodeName); xmlDoc.async = "false"; xmlDoc.onreadystatechange = redirectUser; } function redirectUser() { alert(''); var user = document.login.txtLogin.value; var pass = document.login.txtPass.value; var log = 0; if(xmlDoc.readyState == 4) { xmlObj = xmlDoc.documentElement; var len = xmlObj.childNodes.length; for(i = 0; i < len; i++) { var nodeElement = xmlObj.childNodes[i]; var userXml = nodeElement.childNodes[0].firstChild.nodeValue; var passXml = nodeElement.childNodes[1].firstChild.nodeValue; var idXML = nodeElement.attributes[0].value if(userXml == user && passXml == pass) { log = 1; document.cookie = escape(idXML); document.login.submit(); } } } if(log == 0) { var divErr = document.getElementById('Error'); divErr.innerHTML = "<b>Login Failed</b>"; } } customers.xml <?xml version="1.0" encoding="UTF-8"?> <customers> <customer custid="CU101"> <user>jack</user> <pwd>PW101</pwd> <email>[email protected]</email> </customer> <customer custid="CU102"> <user>jill</user> <pwd>PW102</pwd> <email>[email protected]</email> </customer> <customer custid="CU103"> <user>john</user> <pwd>PW103</pwd> <email>[email protected]</email> </customer> <customer custid="CU104"> <user>jeff</user> <pwd>PW104</pwd> <email>[email protected]</email> </customer> </customers> I get parsererror message on line alert(xmlDoc.documentElement.nodeName); I don't know what's wrong with my code. Can some one point me in a right direction? Edit : Ok, I found a solution. var xmlDoc = 0; var xhttp = 0; function checkUser() { var user = document.login.txtLogin.value; var pass = document.login.txtPass.value; var err = ""; if(user == "" || pass == "") { if(user == "") { alert("Enter user name"); } if(pass == "") { alert("Enter Password"); } return; } if (window.XMLHttpRequest) { xhttp=new XMLHttpRequest(); } else // IE 5/6 { xhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xhttp.onreadystatechange = redirectUser; xhttp.open("GET","customers.xml",true); xhttp.send(); } function redirectUser() { var log = 2; var user = document.login.txtLogin.value; var pass = document.login.txtPass.value; if (xhttp.readyState == 4) { log = 0; xmlDoc = xhttp.responseXML; var xmlUsers = xmlDoc.getElementsByTagName('user'); var xmlPasswords = xmlDoc.getElementsByTagName('pwd'); var userLen = xmlDoc.getElementsByTagName('customer').length; var xmlCustomers = xmlDoc.getElementsByTagName('customer'); for (var i = 0; i < userLen; i++) { var xmlUser = xmlUsers[i].childNodes[0].nodeValue; var xmlPass = xmlPasswords[i].childNodes[0].nodeValue; var xmlId = xmlCustomers.item(i).attributes[0].nodeValue; if(xmlUser == user && xmlPass == pass) { log = 1; document.cookie = xmlId; document.login.submit(); break; } } } if(log == 0) { alert("Login failed"); } } Thanks.

    Read the article

  • Login to OS X Server User Account from Local Computer

    - by Brod Wilkinson
    I have OS X Server installed on a mac mini. I've created several User accounts, one of which is Account Name: Bob Password: abc123 From the Mac Mini's login screen I can choose "Server" (main account) "Bob" (Bobs account) and "Other..." OS X Server Accounts, from "Other..." if I input Bobs credentials it will log me in. I also have a macbook air, I would like to be able to select from the Login Screen "Other..." input Bobs credentials and have it login to Bobs account, or any other User Account for that matter. My Server is setup as private with the server address: server.network.private Following some googled instructions as well as apples very own instructions I have: Setup an Open Directory with Username: diradmin Password: abc123 Then on the macbook air gone into System Preferences > Users & Groups > Login Options and clicked Join next to Network Account Server, input my server (server.network.private) with diradmin credentials and its connected. Great. I've also ticked Allow Network Users to Login and Login Window and selected All Users. I was assuming this would allow my macbook air to login to the "Bob" account by selecting "Other..." from the login window although there is no "Other..." option. I then setup a VPN, basic credentials, logged into it on the macbook air and still not much has changed. I am able to share screens with the "Bob" account form my macbook air by logging in by clicking Share Screen... from the Finder under Shared > Network Server and then clicking Login In but this obviously requires the macbook air to already be logged into an account before it can share screens which is not suitable. Is there any way to simply login to the OS X Server User Account from the macbook air's login screen via the "Other..." like it does on the mac mini's login screen? Thanks in advance. Operating System: OS X 10.9 Mavericks OS X Server: Version 3

    Read the article

  • VS 2010 SP1 BETA – App.config XML Transformation Fix

    - by João Angelo
    The current version for App.config XML tranformations as described in a previous post does not support the SP1 BETA version of Visual Studio. I did some quick tests and decided to provide a different version with a compatibility fix for those already experimenting with the beta release of the service pack. This is a quick workaround to the build errors I found when using the transformations in SP1 beta and is pretty much untested since I’ll wait for the final release of the service pack to take a closer look to any possible problems. But for now, those that already installed SP1 beta can use the following transformations: VS 2010 SP1 BETA – App.config XML Transformation And those with the RTM release of Visual Studio can continue to use the original version of the transformations available from: VS 2010 RTM – App.config XML Transformation

    Read the article

  • Can we replace XML with JSON entirely?

    - by Saeed Neamati
    I'm sure lots of developers are familiar with XML and JSON, and they've used both of them. Thus no point in explaining what they are, and what is their purpose, even in brief. If we try to map their concepts, we can say (correct me if I'm wrong): XML tags are equivalent to JSON {} XML attributes are equivalent to JSON properties XML tag collection is equivalent to JSON [] The only thing I can think of, which doesn't exist in JSON, is XML Namespaces. The question is, considering this mapping, and considering that JSON is highly lighter in this mapping, can we see a world in future (or at least theoretically think of a world) without XML, but with JSON doing everything XML does? Can we use JSON everywhere XML is used? PS: Please note that I've seen this question. It's something entirely different from what I'm asking here. Thus please don't mention duplicate.

    Read the article

< Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >