XSLT Global count of grouped items
- by Chris
Hi there,
I have a set of items which i am grouping using the muenchian method using keys. This is working great however when i try to do things with the first x number of items it is doing it on the x number of items in each group rather than across the whole set of results. How would i get the individual position of each item accross the whole collection?
<xsl:key name="pictures-by-productid" match="/dsQueryResponse/Rows/Row" use="@ProductId" />
<xsl:template match="/">
<div style="border:1px solid red; float:left;">
<xsl:apply-templates select="/" mode="sub">
</xsl:apply-templates>
</div>
</xsl:template>
and the second template
<xsl:template match="/" mode="sub"> <xsl:for-each select="/dsQueryResponse/Rows/Row[count(. | key('pictures-by-productid', @ProductId)[1]) = 1]">
<xsl:for-each select="key('pictures-by-productid', @ProductId)">
<xsl:sort select="@PictureType" />
<div style="float:left; margin:2px;">
<img src="{@ThumbNailUrl}" width="58" /> <br />
Download
<xsl:number value="position()" format="1. " />
<xsl:value-of select="." />
</div>
</xsl:for-each>
</xsl:for-each>
</xsl:template>
Thanks
Chris
