How can I print the argument value that caused Exception in Java?
- by Sanoj
I am writing a parser for csv-files, and sometimes I get NumberFormatException. Is there an easy way to print the argument value that caused the exception?
For the moment do I have many try-catch blocks that look like this:
String ean;
String price;
try {
builder.ean(Long.parseLong(ean));
} catch (NumberFormatException e) {
System.out.println("EAN: " + ean);
e.printStackTrace();
}
try {
builder.price(new BigDecimal(price));
} catch (NumberFormatException e) {
System.out.println("Price: " + price);
e.printStackTrace();
}
I would like to be able to write something like:
try {
builder.ean(Long.parseLong(ean));
} catch (NumberFormatException e) {
e.printMethod(); // Long.parseLong()
e.printArgument(); // should print the string ean "99013241.23"
e.printStackTrace();
}
Is there any way that I at least can improve my code? And do this kind of printing/logging more programmatically?
