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  • List files with two dots in their names using java regular expressions

    - by Nivas
    I was trying to match files in a directory that had two dots in their name, something like theme.default.properties I thought the pattern .\\..\\.. should be the required pattern [. matches any character and \. matches a dot] but it matches both oneTwo.txt and theme.default.properties I tried the following: [resources/themes has two files oneTwo.txt and theme.default.properties] 1. public static void loadThemes() { File themeDirectory = new File("resources/themes"); if(themeDirectory.exists()) { File[] themeFiles = themeDirectory.listFiles(); for(File themeFile : themeFiles) { if(themeFile.getName().matches(".\\..\\..")); { System.out.println(themeFile.getName()); } } } } This prints nothing and the following File[] themeFiles = themeDirectory.listFiles(new FilenameFilter() { public boolean accept(File dir, String name) { return name.matches(".\\..\\.."); } }); for (File file : themeFiles) { System.out.println(file.getName()); } prints both oneTwo.txt theme.default.properties I am unable to find why these two give different results and which pattern I should be using to match two dots... Can someone help?

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  • How do I make this nested for loop, testing sums of cubes, more efficient?

    - by Brian J. Fink
    I'm trying to iterate through all the combinations of pairs of positive long integers in Java and testing the sum of their cubes to discover if it's a Fibonacci number. I'm currently doing this by using the value of the outer loop variable as the inner loop's upper limit, with the effect being that the outer loop runs a little slower each time. Initially it appeared to run very quickly--I was up to 10 digits within minutes. But now after 2 full days of continuous execution, I'm only somewhere in the middle range of 15 digits. At this rate it may end up taking a whole year just to finish running this program. The code for the program is below: import java.lang.*; import java.math.*; public class FindFib { public static void main(String args[]) { long uLimit=9223372036854775807L; //long maximum value BigDecimal PHI=new BigDecimal(1D+Math.sqrt(5D)/2D); //Golden Ratio for(long a=1;a<=uLimit;a++) //Outer Loop, 1 to maximum for(long b=1;b<=a;b++) //Inner Loop, 1 to current outer { //Cube the numbers and add BigDecimal c=BigDecimal.valueOf(a).pow(3).add(BigDecimal.valueOf(b).pow(3)); System.out.print(c+" "); //Output result //Upper and lower limits of interval for Mobius test: [c*PHI-1/c,c*PHI+1/c] BigDecimal d=c.multiply(PHI).subtract(BigDecimal.ONE.divide(c,BigDecimal.ROUND_HALF_UP)), e=c.multiply(PHI).add(BigDecimal.ONE.divide(c,BigDecimal.ROUND_HALF_UP)); //Mobius test: if integer in interval (floor values unequal) Fibonacci number! if (d.toBigInteger().compareTo(e.toBigInteger())!=0) System.out.println(); //Line feed else System.out.print("\r"); //Carriage return instead } //Display final message System.out.println("\rDone. "); } } Now the use of BigDecimal and BigInteger was delibrate; I need them to get the necessary precision. Is there anything other than my variable types that I could change to gain better efficiency?

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  • Problem in getting response from server in jquery

    - by Alvin
    Hello, I'm using $.ajax(options) method to pass the request to server based on username and password, but whenever I try to print the response by XMLHttpRequest object when response gets successful, I'm getting an empty value. $(document).ready(function(){ $("#form").submit(function(){ $.ajax({url:"Chat.jsp",type:"POST",data:$("#form").serialize(),success:function(request) { alert(request.responseText); //This is displaying nothing },error:function(){document.write("YOU can't");}}); }); }); This is what I'm doing in my servlets code after executing query: try { String user = request.getParameter("j_username"); String password = request.getParameter("j_password"); if(user != null && password != null) { String query = "Select * from users where user_name="+"\'"+user+"\'"+"&& user_pass="+"\""+password+"\""; DBCheck db= new DBCheck(); boolean b = db.doExecuteQuery(con.createStatement(),query); response.setHeader("Cache-Control", "no-cache"); if(b) { response.getWriter().println("Username already exits"); } else { response.getWriter().println("Username doesn't exit"); } } } catch(SQLException ex) { ex.printStackTrace(); } } May I know the problem, and how can I fix it?

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  • Problem with loading a PNG image in JApplet.

    - by Bruce
    Hi there, I'm trying to load a PNG image from JAR file when running JApplet. The file is, I think, loaded properly - there are no errors. However it is not displayed. img.png is placed in the same directory as MainClass.java file. Here is the code: InputStream imageURL = this.getClass().getResourceAsStream("img.png" ); byte[] bytes = null; try {bytes = new byte[imageURL.available()]; System.out.println(imageURL.available()); imageURL.read(bytes);} catch(Exception e) {System.out.println("bleah");} Image image = Toolkit.getDefaultToolkit().createImage(bytes); Image imageScaled = me.getScaledInstance( 100, 150, Image.SCALE_SMOOTH ); jLabel6 = new javax.swing.JLabel( new ImageIcon( imageScaled) ); and the HTML exerpt: <APPLET codebase="classes" code="myapplet/MainClass.class" archive ="LittleApplet.jar" width=700 height=500> The image, as I wrote, is probably read, but not displayed in JLabel. What am I missing/doing wrong? Thanks in advance for the reply!

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  • How can i fetch the large image from url

    - by Kutbi
    i used below code to fetch the image from url.but its not working for large image.. i missing something to add for that type of image to fetch. imgView = (ImageView)findViewById(R.id.ImageView01); imgView.setImageBitmap(loadBitmap("http://www.360technosoft.com/mx4.jpg")); //imgView.setImageBitmap(loadBitmap("http://sugardaddydiaries.com/wp-content/uploads/2010/12/how_do_i_get_sugar_daddy.jpg")); //setImageDrawable("http://sugardaddydiaries.com/wp-content/uploads/2010/12/holding-money-copy.jpg"); //Drawable drawable = LoadImageFromWebOperations("http://www.androidpeople.com/wp-content/uploads/2010/03/android.png"); //imgView.setImageDrawable(drawable); /* try { ImageView i = (ImageView)findViewById(R.id.ImageView01); Bitmap bitmap = BitmapFactory.decodeStream((InputStream)new URL("http://sugardaddydiaries.com/wp-content/uploads/2010/12/holding-money-copy.jpg").getContent()); i.setImageBitmap(bitmap); } catch (MalformedURLException e) { System.out.println("hello"); } catch (IOException e) { System.out.println("hello"); }*/ } protected Drawable ImageOperations(Context context, String string, String string2) { // TODO Auto-generated method stub try { InputStream is = (InputStream) this.fetch(string); Drawable d = Drawable.createFromStream(is, "src"); return d; } catch (MalformedURLException e) { e.printStackTrace(); return null; } catch (IOException e) { e.printStackTrace(); return null; } }

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  • static variable lose its value

    - by user542719
    I have helper class with this static variable that is used for passing data between two classes. public class Helper{ public static String paramDriveMod;//this is the static variable in first calss } this variable is used in following second class mathod public void USB_HandleMessage(char []USB_RXBuffer){ int type=USB_RXBuffer[2]; MESSAGES ms=MESSAGES.values()[type]; switch(ms) { case READ_PARAMETER_VALUE: // read parameter values switch(prm){ case PARAMETER_DRIVE_MODE: // paramet drive mode Helper.paramDriveMod =(Integer.toString(((USB_RXBuffer[4]<< 8)&0xff00))); System.out.println(Helper.paramDriveMod+"drive mode is selectd ");//here it shows the value that I need. ..........}}//let say end switch and method and the following is an third class method use the above class method public void buttonSwitch(int value) throws InterruptedException{ boolean bool=true; int c=0; int delay=(int) Math.random(); while(bool){ int param=3; PARAMETERS prm=PARAMETERS.values()[param]; switch(value){ case 0: value=1; while(c<5){ Thread.sleep(delay); protocol.onSending(3,prm.PARAMETER_DRIVE_MODE.ordinal(),dataToRead,dataToRead.length);//read drive mode System.out.println(Helper.paramDriveMod+" drive mode is ..........in wile loop");//here it shows null value }}//let say end switch and method what is the reason that this variable lose its value?

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  • Create static instances of a class inside said class in Python

    - by Samir Talwar
    Apologies if I've got the terminology wrong here—I can't think what this particular idiom would be called. I've been trying to create a Python 3 class that statically declares instances of itself inside itself—sort of like an enum would work. Here's a simplified version of the code I wrote: class Test: A = Test("A") B = Test("B") def __init__(self, value): self.value = value def __str__(self): return "Test: " + self.value print(str(Test.A)) print(str(Test.B)) Writing this, I got an exception on line 2 (A = Test("A")). I assume line 3 would also error if it had made it that far. Using __class__ instead of Test gives the same error. File "<stdin>", line 1, in <module> File "<stdin>", line 2, in Test NameError: name 'Test' is not defined Is there any way to refer to the current class in a static context in Python? I could declare these particular variables outside the class or in a separate class, but for clarity's sake, I'd rather not if I can help it. To better demonstrate what I'm trying to do, here's the same example in Java: public class Test { private static final Test A = new Test("A"); private static final Test B = new Test("B"); private final String value; public Test(String value) { this.value = value; } public String toString() { return "Test: " + value; } public static void main(String[] args) { System.out.println(A); System.out.println(B); } } This works as you would expect: it prints: Test: A Test: B How can I do the same thing in Python?

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  • repaint problem

    - by user357816
    I have a problem with my repaint in the method move. I dont know what to doo, the code is below import java.awt.*; import java.io.*; import java.text.*; import java.util.*; import javax.sound.sampled.*; import javax.swing.*; import javax.swing.Timer; import java.awt.event.*; import java.lang.*; public class bbb extends JPanel { public Stack<Integer> stacks[]; public JButton auto,jugar,nojugar; public JButton ok,ok2; public JLabel info=new JLabel("Numero de Discos: "); public JLabel instruc=new JLabel("Presiona la base de las torres para mover las fichas"); public JLabel instruc2=new JLabel("No puedes poner una pieza grande sobre una pequenia!"); public JComboBox numeros=new JComboBox(); public JComboBox velocidad=new JComboBox(); public boolean seguir=false,parar=false,primera=true; public int n1,n2,n3; public int click1=0; public int opcion=1,tiempo=50; public int op=1,continuar=0,cont=0; public int piezas=0; public int posx,posy; public int no; public bbb() throws IOException { stacks = new Stack[3]; stacks[0]=new Stack<Integer>(); stacks[1]=new Stack<Integer>(); stacks[2]=new Stack<Integer>(); setPreferredSize(new Dimension(1366,768)); ok=new JButton("OK"); ok.setBounds(new Rectangle(270,50,70,25)); ok.addActionListener(new okiz()); ok2=new JButton("OK"); ok2.setBounds(new Rectangle(270,50,70,25)); ok2.addActionListener(new vel()); add(ok2);ok2.setVisible(false); auto=new JButton("Automatico"); auto.setBounds(new Rectangle(50,80,100,25)); auto.addActionListener(new a()); jugar=new JButton("PLAY"); jugar.setBounds(new Rectangle(100,100,70,25)); jugar.addActionListener(new play()); nojugar=new JButton("PAUSE"); nojugar.setBounds(new Rectangle(100,150,70,25)); nojugar.addActionListener(new stop()); setLayout(null); info.setBounds(new Rectangle(50,50,170,25)); info.setForeground(Color.white); instruc.setBounds(new Rectangle(970,50,570,25)); instruc.setForeground(Color.white); instruc2.setBounds(new Rectangle(970,70,570,25)); instruc2.setForeground(Color.white); add(instruc);add(instruc2); add(jugar);add(nojugar);jugar.setVisible(false);nojugar.setVisible(false); add(info); info.setVisible(false); add(ok); ok.setVisible(false); add(auto); numeros.setBounds(new Rectangle(210,50,50,25)); numeros.addItem(1);numeros.addItem(2);numeros.addItem(3);numeros.addItem(4);numeros.addItem(5); numeros.addItem(6);numeros.addItem(7);numeros.addItem(8);numeros.addItem(9);numeros.addItem(10); add(numeros); numeros.setVisible(false); velocidad.setBounds(new Rectangle(150,50,100,25)); velocidad.addItem("Lenta"); velocidad.addItem("Intermedia"); velocidad.addItem("Rapida"); add(velocidad); velocidad.setVisible(false); } public void Mover(int origen, int destino) { for (int i=0;i<3;i++) { System.out.print("stack "+i+": "); for(int n : stacks[i]) System.out.print(n+";"); System.out.println(""); } System.out.println("de <"+origen+"> a <"+destino+">"); stacks[destino].push(stacks[origen].pop()); System.out.println(""); this.validate(); this.repaint( ); } public void hanoi(int origen, int destino, int cuantas) { while (parar) {} if (cuantas <= 1) Mover(origen,destino); else { hanoi(origen,3 - (origen+destino),cuantas-1); Mover(origen,destino); hanoi(3 - (origen+destino),destino,cuantas-1); } } public void paintComponent(Graphics g) { ImageIcon fondo= new ImageIcon("fondo.jpg"); g.drawImage(fondo.getImage(),0, 0,1366,768,null); g.setColor(new Color((int)(Math.random() * 254), (int)(Math.random() *255), (int)(Math.random() * 255))); g.fillRect(0,0,100,100); g.setColor(Color.white); g.fillRect(150,600,250,25); g.fillRect(550,600,250,25); g.fillRect(950,600,250,25); g.setColor(Color.red); g.fillRect(270,325,10,275); g.fillRect(270+400,325,10,275); g.fillRect(270+800,325,10,275); int x, y,top=0; g.setColor(Color.yellow); x=150;y=580; for(int ii:stacks[0]) { g.fillRect(x+((ii*125)/10),y-(((ii)*250)/10),((10-ii)*250)/10,20);} x=550;y=580; for(int ii:stacks[1]) {g.fillRect(x+((ii*125)/10),y-(((ii)*250)/10),((10-ii)*250)/10,20);} x=950;y=580; for(int ii:stacks[2]) {g.fillRect(x+((ii*125)/10),y-(((ii)*250)/10),((10-ii)*250)/10,20);} System.out.println("ENTRO"); setOpaque(false); } private class play implements ActionListener //manual { public void actionPerformed(ActionEvent algo) { parar=false; if(primera=true) { hanoi(0,2,no); primera=false; } } } private class stop implements ActionListener //manual { public void actionPerformed(ActionEvent algo) { parar=true; } } private class vel implements ActionListener //manual { public void actionPerformed(ActionEvent algo) { if (velocidad.getSelectedItem()=="Lenta") {tiempo=150;} else if (velocidad.getSelectedItem()=="Intermedia") {tiempo=75;} else tiempo=50; ok2.setVisible(false); jugar.setVisible(true); nojugar.setVisible(true); } } private class a implements ActionListener //auto { public void actionPerformed(ActionEvent algo) { auto.setVisible(false); info.setVisible(true); numeros.setVisible(true); ok.setVisible(true); op=3; } } private class okiz implements ActionListener //ok { public void actionPerformed(ActionEvent algo) { no=Integer.parseInt(numeros.getSelectedItem().toString()); piezas=no; if (no>0 && no<11) { info.setVisible(false); numeros.setVisible(false); ok.setVisible(false); for (int i=no;i>0;i--) stacks[0].push(i); opcion=2; if (op==3) { info.setText("Velocidad: ");info.setVisible(true); velocidad.setVisible(true); ok2.setVisible(true); } } else { } repaint(); } } } the code of the other class that calls the one up is below: import java.awt.*; import java.io.*; import java.net.URL; import javax.imageio.*; import javax.swing.*; import javax.swing.border.*; import java.lang.*; import java.awt.event.*; public class aaa extends JPanel { private ImageIcon Background; private JLabel fondo; public static void main(String[] args) throws IOException { JFrame.setDefaultLookAndFeelDecorated(true); final JPanel cp = new JPanel(new BorderLayout()); JFrame frame = new JFrame ("Torres de Hanoi"); frame.setDefaultCloseOperation (JFrame.EXIT_ON_CLOSE); frame.setSize(550,550); frame.setVisible(true); bbb panel = new bbb(); frame.getContentPane().add(panel); frame.pack(); frame.setVisible(true); } }

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  • question about counting sort

    - by davit-datuashvili
    hi i have write following code which prints elements in sorted order only one big problem is that it use two additional array here is my code public class occurance{ public static final int n=5; public static void main(String[]args){ // n is maximum possible value what it should be in array suppose n=5 then array may be int a[]=new int[]{3,4,4,2,1,3,5};// as u see all elements are less or equal to n //create array a.length*n int b[]=new int[a.length*n]; int c[]=new int[b.length]; for (int i=0;i<b.length;i++){ b[i]=0; c[i]=0; } for (int i=0;i<a.length;i++){ if (b[a[i]]==1){ c[a[i]]=1; } else{ b[a[i]]=1; } } for (int i=0;i<b.length;i++){ if (b[i]==1) { System.out.println(i); } if (c[i]==1){ System.out.println(i); } } } } // 1 2 3 3 4 4 5 1.i have two question what is complexity of this algorithm?i mean running time 2. how put this elements into other array with sorted order? thanks

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  • how to send image to remote server using web services in android

    - by Aswan
    get image from sdcard and store that image to remote server. i am getting the image from sdcard and i converterd that image to bytearray by using bitmap .but what's the problem if i oberver byte array it is showing some different values it is not matching with .net image byte array conversion. can u pl help if you have any solution it is very urgent to me following is the code i am using can u pl suggest me FileInputStream fin = new FileInputStream(new File("/sdcard/pictures/1.jpg")); BufferedInputStream bis = new BufferedInputStream(fin,3000); byte[] data = new byte[bis.available()]; bis.read(data, 0, data.length); byte[] data1=new byte[data.length]; for (int i = 0; i < data.length; i++) { System.out.print(data[i]); data1[i]=data[i]; } System.out.println("5..................."+data1); Bitmap bitmap = BitmapFactory.decodeByteArray(data1,0,data1.length); System.out.println("6..................."+data1.length); Log.v("hgfjohfjghjdfhgj",""+bitmap); if(bitmap!=null) image.setImageBitmap(bitmap); else Log.e("Bitmap "," Not Created");

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  • Java Function Analysis

    - by khan
    Okay..I am a total Python guy and have very rarely worked with Java and its methods. The condition is that I have a got a Java function that I have to explain to my instructor and I have got no clue about how to do so..so if one of you can read this properly, kindly help me out in breaking it down and explaining it. Also, i need to find out any flaw in its operation (i.e. usage of loops, etc.) if there is any. Finally, what is the difference between 'string' and 'string[]' types? public static void search(String findfrom, String[] thething){ if(thething.length > 5){ System.err.println("The thing is quite long"); } else{ int[] rescount = new int[thething.length]; for(int i = 0; i < thething.length; i++){ String[] characs = findfrom.split("[ \"\'\t\n\b\f\r]", 0); for(int j = 0; j < characs.length; j++){ if(characs[j].compareTo(thething[i]) == 0){ rescount[i]++; } } } for (int j = 0; j < thething.length; j++) { System.out.println(thething[j] + ": " + rescount[j]); } } }

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  • Tomcat does not pick up the class file - the JSP file is not displayed

    - by blueSky
    I have a Java code which is a controller for a jsp page, called: HomeController.java. Code is as follows: @Controller public class HomeController { protected final transient Log log = LogFactory.getLog(getClass()); @RequestMapping(value = "/mypage") public String home() { System.out.println("HomeController: Passing through..."); return "home"; } } There is nothing especial in the jsp page: home.jsp. If I go to this url: http://localhost:8080/adcopyqueue/mypage I can view mypage and everything works fine. Also in the tomcat Dos page I can see the comment: HomeController: Passing through... As expected. Now under the same directory that I have HomeController.java, I've created another file called: LoginController.java. Following is the code: @Controller public class LoginController { protected final transient Log log = LogFactory.getLog(getClass()); @RequestMapping(value = "/loginpage") public String login() { System.out.println("LoginController: Passing through..."); return "login"; } } And under the same place which I have home.jsp, I've created login.jsp. Also under tomcat folders, LoginController.class exists under the same folder that HomeController.class exists and login.jsp exists under the same folder which home.jsp exists. But when I go to this url: http://localhost:8080/adcopyqueue/loginpage Nothing is displayed! I think tomcat does not pick up LoginController.class b/c on the tomcat Dos window, I do NOT see this comment: LoginController: Passing through... Instead I see following which I do not know what do they mean? [ INFO] [http-8080-1 01:43:45] (AppInfo.java:populateAppInfo:34) got manifest [ INFO] [http-8080-1 01:43:45] (AppInfo.java:populateAppInfo:36) manifest entrie s 8 The structure and the code for HomeController.java and LoginController.java plus the jsp files match. I have no idea why tomcat sees one of the files and not the other? Clean build did not help. Does anybody have any idea? Any help is greatly appraciated.

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  • final transient fields and serialization

    - by doublep
    Is it possible to have final transient fields that are set to any non-default value after serialization in Java? My usecase is a cache variable — that's why it is transient. I also have a habit of making Map fields that won't be changed (i.e. contents of the map is changed, but object itself remains the same) final. However, these attributes seem to be contradictory — while compiler allows such a combination, I cannot have the field set to anything but null after unserialization. I tried the following, without success: simple field initialization (shown in the example): this is what I normally do, but the initialization doesn't seem to happen after unserialization; initialization in constructor (I believe this is semantically the same as above though); assigning the field in readObject() — cannot be done since the field is final. In the example cache is public only for testing. import java.io.*; import java.util.*; public class test { public static void main (String[] args) throws Exception { X x = new X (); System.out.println (x + " " + x.cache); ByteArrayOutputStream buffer = new ByteArrayOutputStream (); new ObjectOutputStream (buffer).writeObject (x); x = (X) new ObjectInputStream (new ByteArrayInputStream (buffer.toByteArray ())).readObject (); System.out.println (x + " " + x.cache); } public static class X implements Serializable { public final transient Map <Object, Object> cache = new HashMap <Object, Object> (); } } Output: test$X@1a46e30 {} test$X@190d11 null

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  • When should EntityManagerFactory instance be created/opened ?

    - by masato-san
    Ok, I read bunch of articles/examples how to write Entity Manager Factory in singleton. One of them easiest for me to understand a bit: http://javanotepad.blogspot.com/2007/05/jpa-entitymanagerfactory-in-web.html I learned that EntityManagerFactory (EMF) should only be created once preferably in application scope. And also make sure to close the EMF once it's used (?) So I wrote EMF helper class for business methods to use: public class EmProvider { private static final String DB_PU = "KogaAlphaPU"; public static final boolean DEBUG = true; private static final EmProvider singleton = new EmProvider(); private EntityManagerFactory emf; private EmProvider() {} public static EmProvider getInstance() { return singleton; } public EntityManagerFactory getEntityManagerFactory() { if(emf == null) { emf = Persistence.createEntityManagerFactory(DB_PU); } if(DEBUG) { System.out.println("factory created on: " + new Date()); } return emf; } public void closeEmf() { if(emf.isOpen() || emf != null) { emf.close(); } emf = null; if(DEBUG) { System.out.println("EMF closed at: " + new Date()); } } }//end class And my method using EmProvider: public String foo() { EntityManager em = null; List<Object[]> out = null; try { em = EmProvider.getInstance().getEntityManagerFactory().createEntityManager(); Query query = em.createNativeQuery(JPQL_JOIN); //just some random query out = query.getResultList(); } catch(Exception e) { //handle error.... } finally { if(em != null) { em.close(); //make sure to close EntityManager } } I made sure to close EntityManager (em) within method level as suggested. But when should EntityManagerFactory be closed then? And why EMF has to be singleton so bad??? I read about concurrency issues but as I am not experienced multi-thread-grammer, I can't really be clear on this idea.

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  • Algorithm complexity question

    - by Itsik
    During a recent job interview, I was asked to give a solution to the following problem: Given a string s (without spaces) and a dictionary, return the words in the dictionary that compose the string. For example, s= peachpie, dic= {peach, pie}, result={peach, pie}. I will ask the the decision variation of this problem: if s can be composed of words in the dictionary return yes, otherwise return no. My solution to this was in backtracking (written in Java) public static boolean words(String s, Set<String> dictionary) { if ("".equals(s)) return true; for (int i=0; i <= s.length(); i++) { String pre = prefix(s,i); // returns s[0..i-1] String suf = suffix(s,i); // returns s[i..s.len] if (dictionary.contains(pre) && words(suf, dictionary)) return true; } return false; } public static void main(String[] args) { Set<String> dic = new HashSet<String>(); dic.add("peach"); dic.add("pie"); dic.add("1"); System.out.println(words("peachpie1", dic)); // true System.out.println(words("peachpie2", dic)); // false } What is the time complexity of this solution? I'm calling recursively in the for loop, but only for the prefix's that are in the dictionary. Any idea's?

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  • Java reading xml element without prefix but within the scope of a namespace

    - by wsxedc
    Functionally, the two blocks should be the same <soapenv:Body> <ns1:login xmlns:ns1="urn:soap.sof.com"> <userInfo> <username>superuser</username> <password>qapass</password> </userInfo> </ns1:login> </soapenv:Body> ----------------------- <soapenv:Body> <ns1:login xmlns:ns1="urn:soap.sof.com"> <ns1:userInfo> <ns1:username>superuser</ns1:username> <ns1:password>qapass</ns1:password> </ns1:userInfo> </ns1:login> </soapenv:Body> However, how when I read using AXIS2 and I have tested it with java6 as well, I am having a problem. MessageFactory factory = MessageFactory.newInstance(); SOAPMessage soapMsg = factory.createMessage(new MimeHeaders(), SimpleTest.class.getResourceAsStream("LoginSoap.xml")); SOAPBody body = soapMsg.getSOAPBody(); NodeList nodeList = body.getElementsByTagNameNS("urn:soap.sof.com", "login"); System.out.println("Try to get login element" + nodeList.getLength()); // I can get the login element Node item = nodeList.item(0); NodeList elementsByTagNameNS = ((Element)item).getElementsByTagNameNS("urn:soap.sof.com", "username"); System.out.println("try to get username element " + elementsByTagNameNS.getLength()); So if I replace the 2nd getElementsByTagNameNS with ((Element)item).getElementsByTagName("username");, I am able to get the username element. Doesn't username have ns1 namespace even though it doesn't have the prefix? Am I suppose to keep track of the namespace scope to read an element? Wouldn't it became nasty if my xml elements are many level deep? Is there a workaround where I can read the element in ns1 namespace without knowing whether a prefix is defined?

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  • JSF, writeAttribute("value", str, null) fails with strings obtained through ValueExpression.getValue

    - by Roma
    Hello, I'm having a somewhat weird problem with custom JSF component. Here's my renderer code: public class Test extends Renderer { public void encodeBegin(final FacesContext context, final UIComponent component) throws IOException { ResponseWriter writer = context.getResponseWriter(); writer.startElement("textarea", component); String clientId = component.getClientId(context); if (clientId != null) writer.writeAttribute("name", clientId, null); ValueExpression exp = component.getValueExpression("value"); if (exp != null && exp.getValue(context.getELContext()) != null) { String val = (String) exp.getValue(context.getELContext()); System.out.println("Value: " + val); writer.writeAttribute("value", val, null); } writer.endElement("textarea"); writer.flush(); } } The code generates: <textarea name="j_id2:j_id12:j_id19" value=""></textarea> Property binding contains "test" and as it should be, "Value: test" is successfully printed to console. Now, if I change the code to: public void encodeBegin(final FacesContext context, final UIComponent component) throws IOException { ResponseWriter writer = context.getResponseWriter(); writer.startElement("textarea", component); String clientId = component.getClientId(context); if (clientId != null) writer.writeAttribute("name", clientId, null); ValueExpression exp = component.getValueExpression("value"); if (exp != null && exp.getValue(context.getELContext()) != null) { String val = (String) exp.getValue(context.getELContext()); String str = "new string"; System.out.println("Value1: " + val + ", Value2: " + str); writer.writeAttribute("value", str, null); } writer.endElement("textarea"); writer.flush(); } generated html is: <textarea name="j_id2:j_id12:j_id19" value="new string"></textarea> and console output is "Value1: test, Value2: new string" What's going on here? This doesn't make sense. Why would writeAttribute differentiate between the two strings? Additional info: The component extends UIComponentBase I am using it with facelets

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  • Issues regarding playing audio files in a JME midlet.

    - by Northernen
    I am making a midlet which is to be used to play out local audio files. It is obviously not working. I am getting a null reference on the "is" variable, in the code snippet shown below. 1. try{ 2. System.out.println("path: " + this.getClass()); 3. InputStream is = this.getClass().getResourceAsStream("res/01Track.wav"); 4. p1=Manager.createPlayer(is, "audio"); 5. p1.realize(); 6. p1.prefetch(); 7. p1.start(); 8. } 9. catch(Exception e){ 10. System.out.println(e.getMessage()); 11. } I assume there is something wrong with the "this.getClass().getResourceAsStream("res/01Track.wav")" bit, but I can not for the life of me figure out why, and I have tried referring to the file in 20 different ways. If I printline "this.getClass()" it gives me "path: class Mp3spiller". The absolute path to "01Track.wav" is "E:\Mine dokumenter\Dokumenter\workspace_mobiljava\Mp3spiller\res\01Track.wav". Am I completely wrong in thinking that I should refer relatively to "E:\Mine dokumenter\Dokumenter\workspace_mobiljava\Mp3spiller"? If anyone could point out what I am doing wrong, I would be grateful. I have basically stolen the code from a tutorial I found online, so I would have thought it would be working.

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  • Java NullPointerException In the constructor's class

    - by AndreaF
    I have made a Java class where I have defined a constructor and some methods but I get a NullPointer Exception, and I don't know how I could fix It. public class Job { String idJob; int time; int timeRun; Job j1; List<Job> startBeforeStart; List<Job> restricted; Job(String idJob, int time){ this.idJob=idJob; this.time=time; } public boolean isRestricted() { return restricted.size() != 0; } public void startsBeforeStartOf(Job job){ startBeforeStart.add(job); job.restricted.add(this); } public void startsAfterStartOf(Job job){ job.startsBeforeStartOf(this); } public void checkRestrictions(){ if (!isRestricted()){ System.out.println("+\n"); } else{ Iterator<Job> itR = restricted.iterator(); while(itR.hasNext()){ Job j1 = itR.next(); if(time>timeRun){ System.out.println("-\n"); time--; } else { restricted.remove(j1); } } } } @Override public boolean equals(Object obj) { return obj instanceof Job && ((Job) obj).idJob.equals(idJob); } public void run() { timeRun++; } } PS Looking in a forum a user says that to fix the error I should make an ArrayList inside the constructor (without modify the received parameters that should remain String id and int time), but I haven't understand what He mean.

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  • interface variables are final and static by default and methods are public and abstract

    - by sap
    The question is why it's been decided to have variable as final and static and methods as public and abstract by default. Is there any particular reason for making them implicit,variable as final and static and methods as public and abstract. Why they are not allowing static method but allowing static variable? We have interface to have feature of multiple inheritance in Java and to avoid diamond problem. But how it solves diamond problem,since it does not allow static methods. In the following program, both interfaces have method with the same name..but while implementing only one we implement...is this how diamond problem is solved? interface testInt{ int m = 0; void testMethod(); } interface testInt1{ int m = 10; void testMethod(); } public class interfaceCheck implements testInt, testInt1{ public void testMethod(){ System . out . println ( "m is"+ testInt.m ); System . out . println ( "Hi World!" ); } }

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  • JSP - Beginner question , Bypass the if..statement on page load?

    - by TatMing
    i am new in JSP,i have some problem with the following code : <%@ page contentType="text/html;charset=Big5" %> <html> <head> <title></title> </head> <body> <form method="post" action="InsertStudent.jsp"> <input type="text" size="20" name="txtName" /> <input type="text" size="20" name="txtDob" /> <input type="text" size="20" name="txtProStudied" /> <input type="submit" name="B1" value="Submit" /> </form> <% if (request.getParameter("txtName") !="" && request.getParameter("txtDob") != "" && request.getParameter("txtProStudied") != "" ) { out.println("...bypass the if....statement"); } %> </body> </html> If run this code, the out.println will fire even the 3 input box have value or not..

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  • How do I alias the scala setter method 'myvar_$(myval)' to something more pleasing when in java?

    - by feydr
    I've been converting some code from java to scala lately trying to tech myself the language. Suppose we have this scala class: class Person() { var name:String = "joebob" } Now I want to access it from java so I can't use dot-notation like I would if I was in scala. So I can get my var's contents by issuing: person = Person.new(); System.out.println(person.name()); and set it via: person = Person.new(); person.name_$eq("sallysue"); System.out.println(person.name()); This holds true cause our Person Class looks like this in javap: Compiled from "Person.scala" public class Person extends java.lang.Object implements scala.ScalaObject{ public Person(); public void name_$eq(java.lang.String); public java.lang.String name(); public int $tag() throws java.rmi.RemoteException; } Yes, I could write my own getters/setters but I hate filling classes up with that and it doesn't make a ton of sense considering I already have them -- I just want to alias the _$eq method better. (This actually gets worse when you are dealing with stuff like antlr because then you have to escape it and it ends up looking like person.name_\$eq("newname"); Note: I'd much rather have to put up with this rather than fill my classes with more setter methods. So what would you do in this situation?

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  • SWIG: From Plain C++ to working Wrapper

    - by duckworthd
    Hi everyone. I've been trying to create a SWIG wrapper for this tiny little C++ class for the better part of 3 hours with no success, so I was hoping one of you out there could lend me a small hand. I have the following class: #include <stdio.h> class Example { public: Example(); ~Example(); int test(); }; #include "example.h" Along with the implementation: Example::Example() { printf("Example constructor called\n"); } Example::~Example() { printf("Example destructor called\n"); } int Example::test() { printf("Holy shit, I work!\n"); return 42; } I've read through the introduction page ( www.swig.org/Doc1.3/Java.html ) a few times without gaining a whole lot of insight into the situation. My steps were Create an example.i file Compile original alongside example_wrap.cxx (no linking) link resulting object files together Create a little java test file (see below) javac all .java files there and run Well steps 4 and 5 have created a host of problems for me, starting with the basic ( library 'example' not found due to not being in java's path ) to the weird ( library not found even unless LD_LIBRARY_PATH is set to something, even if it's nothing at all). I've included my little testing code below public class test2 { static { String libpath = System.getProperty("java.library.path"); String currentDir = System.getProperty("user.dir"); System.setProperty("java.library.path", currentDir + ":" + libpath); System.out.println(System.getProperty("java.library.path")); System.loadLibrary("example"); } public static void main(String[] args){ System.out.println("It loads!"); } } Well, if anyone has navigated these murky waters of wrapping, I could not be happier than if you could light the way, particularly if you could provide the example.i and bash commands to go along with it.

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  • how to add data to ARRAYLIST

    - by Chamal
    try { ArrayList ar=new ArrayList(); PRIvariable pri=new PRIvariable(); BufferedReader reader = new BufferedReader(new InputStreamReader(new FileInputStream("C:/cdr2.csv"))); while (reader.ready()) { String line = reader.readLine(); String[] values = line.split(","); pri.dateText=values[2]+" "+values[4]; pri.count=pri.count+1; pri.sum = pri.sum+Integer.parseInt(values[7]); System.out.println(pri.dateText+" "+pri.sum+" "+pri.count); ar.add(pri); } String[] columnNames={"Date","TOTAL","COUNTS"}; String[][] cells=new String[ar.size()][3]; for(int i=0;i<ar.size();i++){ cells[i][0]=((PRIvariable)ar.get(i)).dateText; cells[i][1]=""+((PRIvariable)ar.get(i)).sum; cells[i][2]=""+((PRIvariable)ar.get(i)).count; } table = new JTable(cells,columnNames); table.setSize(400,400); table.setVisible(true); JScrollPane js=new JScrollPane(); js.setViewportView(table); js.setSize(400,400); js.setVisible(true); add(js,java.awt.BorderLayout.CENTER); } catch (Exception e) { System.out.println(e); } This is my code. Here i want to Read text file and put that data to Jtable. But in this code it shows every row of the Jtable filled with same data that contain in arraylist(ar) last row. ( i think there is problem in my arraylist). How can i solve this......

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  • Timeout Exceptions

    - by Raihan Jamal
    This is my below code, I am confuse why this thing is happening. In this code getLocationByIpTimeout is a method in which I am passing two things- one is the ip address and second is the timeout. So I will get the timeout exception if the response is not getting back in under 5 ms. So when I ran this below code, I am getting few timeout exceptions but the most important thing that I am confuse is if I am getting timeout exceptions (time taken to get the response is greater than 5 ms) then why the program is entering in that if loop in which I am having difference 5. What can be the possible reason for this? It is because of catch block?? Any suggestions will be appreciated. long runs =10000; long difference = 0; while(runs > 0) { String ipAddress = generateIPAddress(); long start_time = System.nanoTime(); try { resp = PersonalizationGeoLocationServiceClientHelper.getLocationByIpTimeout(ipAddress, 5); } catch (TimeoutException e) { System.out.println("Timeout Exception"); } long end_time = System.nanoTime(); if(resp == null || (resp.getLocation() == null)) { difference = 0; } else if(resp.getLocation() != null) { difference = (end_time - start_time)/1000000; } if(difference> 5) { System.out.println("Debug"); } }

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