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  • iPhone MVC Question

    - by HM1
    Hi, I'm bit of a newbie and had a basic question regarding adhering to the MVC model in iPhone coding. How do I setup a Model class that holds my data and connect it to different controllers in the following setup: Using Interface Builder, I created a tab controller in which - Tab #1 has a Nav Controller and a hierarchy of View Controllers. - Tab #2 has a View Controller So with what I have now, the View Controller under Tab #1 alloc init's the model class and I know how to pass the model from one ViewController to the next in the Navigation Hierarchy where it can pass the data and/or be updated with new data. Question is how to pass it from Tab #1's View Controller to Tab #2 View Controller as there is no code linking the two??? Thanks in advance, Hiren.

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  • How can I order fields in Django ModelForm?

    - by joozek
    I have an 'order' Model: class Order(models.Model): date_time=models.DateTimeField() # other stuff And I'm using Django ModelForm class to render a form, but I want to display date and time widgets separately. I've came up with this: class Form(forms.ModelForm): class Meta: model = Order exclude = ('date_time',) date = forms.DateField() time = forms.TimeField() The problem is that I want to put these fields somewhere between 'other stuff'

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  • DJANGO complex modelling

    - by SledgehammerPL
    Hello. I have such model now: receipt contains components. component contain product. The difference between component and product is, that component has quantity and measure unit: eg. component is 100g sugar - sugar is a product. So I need to make lots of components to satisfy different recipes - 100g sugar is not equal 200g sugar I wonder if I can remodel it to kick off components - in pure sql it's rather easy, but I'm trying to USE django - not making workarounds. class Receipt(models.Model): name = models.CharField(max_length=128) (...) components = models.ManyToManyField(Component) class Component(models.Model): quantity = models.FloatField(max_length=9) unit = models.ForeignKey(Unit) product = models.ForeignKey(Product) class Product(models.Model): name = models.CharField(max_length = 128) TIA

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  • How to make item view render rich (html) text in PyQt?

    - by Giorgio Gelardi
    I'm trying to translate code from this thread in python: import sys from PyQt4.QtCore import * from PyQt4.QtGui import * __data__ = [ "Lorem ipsum dolor sit amet, consectetur adipisicing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua.", "Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo consequat.", "Duis aute irure dolor in reprehenderit in voluptate velit esse cillum dolore eu fugiat nulla pariatur.", "Excepteur sint occaecat cupidatat non proident, sunt in culpa qui officia deserunt mollit anim id est laborum." ] def get_html_box(text): return '''<table border="0" width="100%"><tr width="100%" valign="top"> <td width="1%"><img src="softwarecenter.png"/></td> <td><table border="0" width="100%" height="100%"> <tr><td><b><a href="http://www.google.com">titolo</a></b></td></tr> <tr><td>{0}</td></tr><tr><td align="right">88/88/8888, 88:88</td></tr> </table></td></tr></table>'''.format(text) class HTMLDelegate(QStyledItemDelegate): def paint(self, painter, option, index): model = index.model() record = model.listdata[index.row()] doc = QTextDocument(self) doc.setHtml(get_html_box(record)) doc.setTextWidth(option.rect.width()) painter.save() ctx = QAbstractTextDocumentLayout.PaintContext() ctx.clip = QRectF(0, option.rect.top(), option.rect.width(), option.rect.height()) dl = doc.documentLayout() dl.draw(painter, ctx) painter.restore() def sizeHint(self, option, index): model = index.model() record = model.listdata[index.row()] doc = QTextDocument(self) doc.setHtml(get_html_box(record)) doc.setTextWidth(option.rect.width()) return QSize(doc.idealWidth(), doc.size().height()) class MyListModel(QAbstractListModel): def __init__(self, parent=None, *args): super(MyListModel, self).__init__(parent, *args) self.listdata = __data__ def rowCount(self, parent=QModelIndex()): return len(self.listdata) def data(self, index, role=Qt.DisplayRole): return index.isValid() and QVariant(self.listdata[index.row()]) or QVariant() class MyWindow(QWidget): def __init__(self, *args): super(MyWindow, self).__init__(*args) # listview self.lv = QListView() self.lv.setModel(MyListModel(self)) self.lv.setItemDelegate(HTMLDelegate(self)) self.lv.setResizeMode(QListView.Adjust) # layout layout = QVBoxLayout() layout.addWidget(self.lv) self.setLayout(layout) if __name__ == "__main__": app = QApplication(sys.argv) w = MyWindow() w.show() sys.exit(app.exec_()) Element's size and position are not calculated correctly I guess, perhaps because I haven't understand at all the style related parts from original code. Can someone help me?

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  • Saving multiple select form data in db

    - by fl00r
    Hi. I've got form for some model A, which has got few fields: tile description ... colors colors are selected from multiple select and options are ['red', 'green', 'blue', 'yellow']. User can choose colors as many as he wants. I don't think that making Color model and has_many relationship is good solution here to store colors data in model A. So question is: How to store multiple data in db for such multiple select forms?

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  • How can I keep the the logic to translate a ViewModel's values to a Where clause to apply to a linq query out of My Controller?

    - by Mr. Manager
    This same problem keeps cropping up. I have a viewModel that doesn't have any persistent backing. It is just a ViewModel to generate a search input form. I want to build a large where clause from the values the user entered. If the Action Accepts as a parameter SearchViewModel How do I do this without passing my viewModel to my service layer? Service shouldn't know about ViewModels right? Oh and if I serialize it, then it would be a big string and the key/values would be strongly typed. SearchViewModel this is just a snippet. [Display(Name="Address")] public string AddressKeywords { get; set; } /// <summary> /// Gets or sets the census. /// </summary> public string Census { get; set; } /// <summary> /// Gets or sets the lot block sub. /// </summary> public string LotBlockSub { get; set; } /// <summary> /// Gets or sets the owner keywords. /// </summary> [Display(Name="Owner")] public string OwnerKeywords { get; set; } In my controller action I was thinking of something like this. but I would think all this logic doesn't belong in my Controller. ActionResult GetSearchResults(SearchViewModel model){ var query = service.GetAllParcels(); if(model.Census != null){ query = query.Where(x=>x.Census == model.Census); } if (model.OwnerKeywords != null){ query = query.Where(x=>x.Owners == model.OwnerKeywords); } return View(query.ToList()); }

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  • Bind Child table data on View field- MVC ASP.Net

    - by Tassadaque
    I have two tables Contact and Addresses. Addresses is the child table of Contact. When i create view for Contact. i also want to get addresses for user as many as user wants. For contact table i bind the textbox and add validation like this <%= Html.TextBoxFor(model => model.ContactName) %> <%= Html.ValidationMessageFor(model => model.ContactName) %> Now my question is that how can i bind address field on create view screen. Regards Tassadaque

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  • Class name to view path

    - by Alexey Poimtsev
    Hi, I have a RoR application and model SomeModel. I have views for this model and I want to know - is there any method to get the view's path? Of course I can use for this model instance m = SomeModel.new v = m.class.class_name.pluralize.downcase It's working, but maybe you know a better way? :)

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  • Access: Expression too complex to be evaluated

    - by user2502964
    I'm trying to sort out values from a database by the weekending date. The script I'm using functions on 6 of my 7 databases (they are all constructed identically). The 7th database doesn't function. I get the expression too complex error. any help figuring out why?? Here is my code: SELECT UPC_Test.Type, UPC_Test.[Model No], UPC_Test.[Model Desc], UPC_Test.[Serial No], Format(DateValue([UPC_Test].[Test Date]+7-Weekday([UPC_Test].[Test Date],0)),"m/d/yyyy") AS [Test Date], UPC_Test.Parameter, UPC_Test.[Failure Symptom], UPC_Test.[Repair Action], UPC_Test.[Factory Select], UPC_Test.[Test Station] FROM UPC_Test GROUP BY UPC_Test.Type, UPC_Test.[Model No], UPC_Test.[Model Desc], UPC_Test.[Serial No], Format(DateValue([UPC_Test].[Test Date]+7-Weekday([UPC_Test].[Test Date],0)),"m/d/yyyy"), UPC_Test.Parameter, UPC_Test.[Failure Symptom], UPC_Test.[Repair Action], UPC_Test.[Factory Select], UPC_Test.[Test Station] HAVING (((UPC_Test.Type)="Production") AND ((Format(DateValue([UPC_Test].[Test Date]+7-Weekday([UPC_Test].[Test Date],0)),"m/d/yyyy"))=[Enter]) AND ((UPC_Test.[Failure Symptom])<>"") AND ((UPC_Test.[Repair Action])<>"") AND ((UPC_Test.[Test Station])="UPC RF Test")) ORDER BY Format(DateValue([UPC_Test].[Test Date]+7-Weekday([UPC_Test].[Test Date],0)),"m/d/yyyy");

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  • Accessing inter-schema tables and relations in hibernate

    - by nitesh
    There is a typical situation being faced where different tables are scattered through different schemas in Oracle database and they are related to each other (encompassing all different types of relations). How can they be represented in Hibernate using annotations as when a sessionfactory handle is created for one schema, tables in that schema can't access other related tables (foreign key relation to tables in other schema)? For a query like following, exception is thrown - "from table1 as model where model.table2Name.table2column = "+foo Exception comes as - org.hibernate.QueryException: could not resolve property: table2column of: com.test.table1 [from com.test.table1 as model where model.table2Name.table2column = 1] Here table1 and table2 are present in different schemas.

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  • django updating m2m field

    - by Marconi
    I have a model service and a ModelForm named Service which I use to add and update the service model. The model looks like this: class Service(models.Model): categories = models.ManyToManyField(Category) The categories field is displayed as a tag with that allows multiple selection. It works well when I'm adding a new record but when I'm updating it, only one service is showing up on the request.POST['categories'] even if I selected multiple categories. I tried dumping the request object and I can see that the categories is showing something like: u'categories': [u'3', u'4', u'2'] I tried calling the request._get_post() and it did return only 1 category, hence the request.POST['categories'] returns only 1. Anybody who knows what's happening and how to fix it?

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  • Controls on main window using Visual C++ designer?

    - by PatrickBateman
    Is is possible to draw controls using Visual C++ designer on the main window, in the same way you can design dialogs? I'd preferably like to be able to design the main window controls this way without using MFC, rather than creating them on WM_CREATE. EDIT: I don't want a dialog-based app, just to be able to design the main window graphically similar to what can be done using Windows Forms Designer in .NET?

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  • How to Generate the .Form file using .java file in swings

    - by vamshikpd
    Hi all, I am using SunJavaStudio Enterprise 8 and Swing frame work In swing, In My source folder, I have Demo.java and Demo.form file. Demo.form file is the Design file. If both files in the Source folder,java file shows source and design view in IDE. If I delete the Demo.form in source folder,The Design view doesn't show. I have only Demo.java file,How can i generate the Demo.form ? please can u help me urgent

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  • Entity framework: Need a easy going, clean database migration solution.

    - by user469652
    I'm using entity framework model first development, and I need to do database migration often, The EF database generation power pack doesn't help a lot, because that data migration never worked here. The database migration here I mean, change the model, and then I can update the existing database from the model, but creating a new one. Is there any free of charge tool here invented here yet? Or would this going to be a new feature of next EF release? PS: I love django's ORM.

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  • Teacher confused about MVC?

    - by Gideon
    I have an assignment to create a game in java using MVC as a pattern. The thing is that stuff I read about MVC aren't really what the teacher is telling me. What I read is that the Model are the information objects, they are manipulated by the controllers. So in a game the controller mutates the placement of the objects and check if there is any collision etc. What my teacher told me is that I should put everything that is universal to the platform in the models and the controllers should only tell the model which input is given. That means the game loop will be in a model class, but also collision checks etc. So what I get from his story is that the View is the screen, the Controller is the unput handeler, and the Model is the rest. Can someone point me in the right direction?

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  • Django admin - remove field if editing an object

    - by John McCollum
    I have a model which is accessible through the Django admin area, something like the following: # model class Foo(models.Model): field_a = models.CharField(max_length=100) field_b = models.CharField(max_length=100) # admin.py class FooAdmin(admin.ModelAdmin): pass Let's say that I want to show field_a and field_b if the user is adding an object, but only field_a if the user is editing an object. Is there a simple way to do this, perhaps using the fields attribute? If if comes to it, I could hack a JavaScript solution, but it doesn't feel right to do that at all!

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  • WPF StaticResource bound to subproperty

    - by mizipzor
    I have a class thats created as a resource: <Window.Resources> <Model:MyModel x:Key="model" /> </Window.Resources> The MyModel class has a cli property named Foo. I want the selected value in a combobox to be bound to this property. I thought I could do this but Im getting errors: <ComboBox SelectedItem="{Binding Source={StaticResource model.Foo}}" /> Heres the error: Cannot find resource named '{model.Foo}'. Where did I go wrong? What extra parameters do I need to specify to properly bind to a subproperty?

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  • MVC3 html.TextBox

    - by BigTommy79
    I have login view that takes a LoginPageViewModel: public class LoginPageViewModel : PageViewModel { public string ReturnUrl { get; set; } public bool PreviousLoginFailed { get; set; } public LoginFormViewModel EditForm { get; set; } } which is rendered in the view. When a user tries to log in I only want to post the LoginFormViewModel (Model.EditForm) to the controller: public ActionResult Login(LoginFormViewModel loginDetails) { //do stuff } Using Html.TextBox I can specify the name of the form field manually 'loginDetails.UserName' and post back to the controller and everything works. @model Web.Controllers.User.ViewModels.LoginPageViewModel @using (Html.BeginForm()){ @Html.Hidden("loginDetails.ReturnUrl", Model.ReturnUrl) @Html.LabelFor(x => x.EditForm.UserName, "User Name:") @Html.TextBox("loginDetails.UserName", Model.EditForm.UserName) @Html.ValidationMessageFor(x => x.EditForm.UserName) ..... But what I want to do is to use the staticaly typed helper, something like: @Html.TextBoxFor(x => x.EditForm.UserName) But I'm unable to get this to work. Are you only able to post back the same model when useing the strongly typed helpers? Is there something I'm missing on this? Intellisense doesn't seem to give any clues such as a form field string.

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  • ManyToManyField error when having recursive structure. How to solve it?

    - by luc
    Hello, I have the following table in the model with a recursive structure (a page can have children pages) class DynamicPage(models.Model): name = models.CharField("Titre",max_length=200) parent = models.ForeignKey('self',null=True,blank=True) I want to create another table with manytomany relation with this one: class UserMessage(models.Model): name = models.CharField("Nom", max_length=100) page = models.ManyToManyField(DynamicPage) The generated SQL creates the following constraint: ALTER TABLE `website_dynamicpage` ADD CONSTRAINT `parent_id_refs_id_29c58e1b` FOREIGN KEY (`parent_id`) REFERENCES `website_dynamicpage` (`id`); I would like to have the ManyToMany with the page itself (the id) and not with the parent field. How to modify the model to make the constraint using the id and not the parent? Thanks in advance

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  • How to create the automatic mass form submitter (javascript-ajax script) to be used on the 3rd part

    - by Daniel
    I need a script that can handle the following tasks. Take user data from my database and fill in and submit / post data to forms located on third part websites.: So I want to know if is it hard to create or do somebody knows if does exists some script for mass form submissions in PHP -Javascript-Ajax ? I run Dancers & Hostess & Model jobs website, I would like to find some script which allows the girls automaticly submit to hundreds websites forms (other 3rd part model agencies) with their similar model application form info on my website previously specified, 1).Firstly the girls will fill out my agency portfolio very detailed form , like this i will get all the model personal info from them , 2) Secondly i would like to allow for example models to submit to 100 and more other model agencies forms (I will find those websites before, and I will get their field names = values and thanks to some script would like to connect them with every girl data already created in my website to submit . I would like to implement it to my wordpress website where the girls has their portfolios instead of my pages . I would like to offer this service especially to models , it should work like some directory submitters , The script knows names - values and fill it out itself, but I want it online - browser side, where the girls should only fill out captcha if there is and click the button "submit".After succesful submit it should offer other form to submit. I would be very happy if you know the answer or if you can redirect me to some article

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  • Sharing the same file between different projects

    - by selsine
    Hi Everyone, For version control we currently use Visual Source Safe and are thinking of migrating to another version control system (SVN, Mercurial, Git). Currently we use Visual Source Safe's "Shared" file feature quite heavily. This allows us to share code between design and runtimes of a single product, and between multiple products as well. For example: **Product One** - Design Login.cpp Login.h Helper.cpp Helper.h - Runtime Login.cpp Login.h Helper.cpp Helper.h **Product Two** - Design Login.cpp Login.h - Launcher Login.cpp Login.h - Runtime Login.cpp Login.h In this example Login.cpp and Login.h contain common code that all of our projects need, Helper.cpp and Helper.h is only used in Product One. In Visual Source Safe they are shared between the specific projects, which means that whenever the files are updated in one project they are updated in any project they are shared with. This is a simple example but hopefully it explains why we use the shared feature: to reduce the amount of duplicated code and ensure that when a bug is fixed all projects automatically have access to the new fixed code. After researching alternatives to Visual Source Safe it seems that most version control systems do not have the idea of shared files, instead they seem to use the idea of sub repositories. (http://mercurial.selenic.com/wiki/subrepos http://svnbook.red-bean.com/en/1.0/ch07s03.html) My question (after all of that) is about what the best practices for achieving this are using other version control systems? Should we restructure our projects so that two copies of the files do not exist and an include directory is used instead? e.g. Product One Design Login.cpp Login.h Runtime Login.cpp Login.h Common Helper.cpp Helper.h This still leaves what to do with Login.cpp and Logon.h Should the shared files be moved to their own repository and then compiled into a lib or dll? This would make bug fixing more time consuming as the lib projects would have to be edited and then rebuilt. Should we use externals or sub repositories? Should we combine our projects (i.e. runtime, design, and launcher) into one large project? Any help would be appreciated. We have the feeling that our project design has evolved based on the tools that we used and now that we are thinking of switching tools it's difficult for us to see how we can best modify our practices. Or maybe we are the only people are there doing this...? Also, we use Visual Studio for all of our stuff. Thanks.

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  • How to make paging start from 1 instead of 0 in ASP.NET MVC

    - by ssx
    I used the paging example of the Nerddinner tutorial. But I also wanted to add page Numbers, somehting like that: <<< 1 2 3 4 5 6 The code below works if i start my paging from 0, but not from 1. How can I fix this ? Here is my code: PaginatedList.cs public class PaginatedList<T> : List<T> { public int PageIndex { get; private set; } public int PageSize { get; private set; } public int TotalCount { get; private set; } public int TotalPages { get; private set; } public PaginatedList(IQueryable<T> source, int pageIndex, int pageSize) { PageIndex = pageIndex; PageSize = pageSize; TotalCount = source.Count(); TotalPages = (int) Math.Ceiling(TotalCount / (double)PageSize); this.AddRange(source.Skip(PageIndex * PageSize).Take(PageSize)); } public bool HasPreviousPage { get { return (PageIndex > 0); } } public bool HasNextPage { get { return (PageIndex+1 < TotalPages); } } } UserController.cs public ActionResult List(int? page) { const int pageSize = 20; IUserRepository userRepository = new UserRepository(); IQueryable<User> listUsers = userRepository.GetAll(); PaginatedList<User> paginatedUsers = new PaginatedList<User>(listUsers, page ?? 0, pageSize); return View(paginatedUsers); } List.cshtml @if (Model.HasPreviousPage) { @Html.RouteLink(" Previous ", "PaginatedUsers", new { page = (Model.PageIndex - 1) }) } @for (int i = 1; i <= Model.TotalPages; i++) { @Html.RouteLink(@i.ToString(), "PaginatedUsers", new { page = (@i ) }) } @if (Model.HasNextPage) { @Html.RouteLink(" Next ", "PaginatedUsers", new { page = (Model.PageIndex + 1) }) }

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  • MVC Validator.TryValidateObject does not validate custom atrribute, validateAllProperties = true

    - by nealsu
    When calling Validator.TryValidateObject with validateAllProperties = true my custom validation attribute does not get triggered. The ValidationResult does not contain an entry for my erroneous property value. Below is the model, attribute and code used to test this. //Model public class Model { [AmountGreaterThanZero] public int? Amount { get; set; } } //Attribute public sealed class AmountGreaterThanZero: ValidationAttribute { private const string errorMessage = "Amount should be greater than zero."; public AmountGreaterThanZero() : base(errorMessage) { } public override string FormatErrorMessage(string name) { return errorMessage; } protected override ValidationResult IsValid(object value, ValidationContext validationContext) { if (value != null) { if ((int)value <= 0) { var message = FormatErrorMessage(validationContext.DisplayName); return new ValidationResult(message); } } return null; } } //Validation Code var container = new Container(); container.ModelList = new List<Model>() { new Model() { Amount = -5 } }; var validationContext = new ValidationContext(container, null, null); var validationResults = new List<ValidationResult>(); var modelIsValid = Validator.TryValidateObject(container, validationContext, validationResults, true); Note: That the validation works fine and ValidationResult returns with correct error message if I use the TryValidateProperty method.

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  • Where do I put constants file for Codeigniter (PHP)?

    - by wag2639
    I have a list of constants (I'm using them as an enum), some are define statements, and some are just global variables. Where am I suppose to put them in the MVC framework so I can use them for both my model and my controller that needs to reference it? I'd rather not stick it into config/constants.php since they shouldn't be called except for by this model and the controllers that use it. Edit 1: Clarification To be more specific, I have my message_model model and it has a bunch of constants that I need that are stored in message_model_constants.php. Where should I put message_model_constants.php and is there a way to have it automatically included by the controller that loads message_model when message_model is not (and I don't want it to be) auto-loaded. Edit 2: I really don't want to have the constants auto-loaded except for when I use the model

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