Search Results

Search found 14506 results on 581 pages for 'document scanner'.

Page 520/581 | < Previous Page | 516 517 518 519 520 521 522 523 524 525 526 527  | Next Page >

• UnknownHostException again!

  - by Nitesh Panchal

  Hello, I posted one question previously and all of them answered that there is some problem with DNS but i changed my DNS to many addressed and now i have the most reliable, google DNS :- 8.8.8.8 Still i get the same UnknownHostException. What can be the problem? This is my code :- DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); DocumentBuilder db = dbf.newDocumentBuilder(); Document doc = db.parse("http://rss.news.yahoo.com/rss/india"); Infact if i pass address as something very common like :- http://google.com i still get the same error. Please help me :(. I have my submissions tomorrow. Thanks in advance :) EDIT : If i type the same address in my mozilla, it works great. So, i am sure that there is no DNS problem. 2nd EDIT :- I found this link http://www.ehow.com/how_4747553_fix-unknownhostexception-java-applications-ubuntu.html But when i run the command sudo apt-get install lib32nss-mdns i get package not found. Somebody even mentioned :- -Djava.net.preferIPv4Stack=true But where do i write this statement of Djava? I am using Netbeans 6.8 to run my web application

  Read the article

• What's wrong (or right) with this JS Object Pattern?

  - by unsane1

  Here's an example of the pattern I'm using in my javascript objects these days (this example relies on jQuery). http://pastie.org/private/ryn0m1gnjsxdos9onsyxg It works for me reasonably well, but I'm guessing there's something wrong, or at least sub-optimal about it, I'm just curious to get people's opinions. Here's a smaller, inline example of it: sample = function(attach) { // set internal reference to self var self = this; // public variable(s) self.iAmPublic = true; // private variable(s) var debug = false; var host = attach; var pane = { element: false, display: false } // public function(s) self.show = function() { if (!pane.display) { position(); $(pane.element).show('fast'); pane.display = true; } } self.hide = function() { if (pane.display) { $(pane.element).hide('fast'); pane.display = false; } } // private function(s) function init () { // do whatever stuff is needed on instantiation of this object // like perhaps positioning a hidden div pane.element = document.createElement('div'); return self; } function position() { var h = { 'h': $(host).outerHeight(), 'w': $(host).outerWidth(), 'pos': $(host).offset() }; var p = { 'w': $(pane.element).outerWidth() }; $(pane.element).css({ top: h.pos.top + (h.h-1), left: h.pos.left + ((h.w - p.w) / 2) }); } function log () { if (debug) { console.log(arguments); } } // on-instantiation let's set ourselves up return init(); } I'm really curious to get people's thoughts on this.

  Read the article

• How can I [simply] consume JSON Data to display to the page

  - by Atomiton

  I usually use JSON with jQuery to just return a string with html. However, I want to start to use Javascript objects in my code. What's the simplest way to get started using json objects on my page? Here's a sample Ajax call ( after $(document).ready( { ... }) of course: $('#btn').click(function(event) { event.preventDefault(); var out = $('#result'); $.ajax({ url: "CustomerServices.asmx/GetCustomersByInvoiceCount", success: function(msg) { // // Iterate through the json results and spit them out to a page? // }, data: "{ 'invoiceCount' : 100 }" }); }); My WebMethod: [WebMethod(Description="Gets customers with more than n invoices")] public List<Customer> GetCustomersByInvoiceCount(int? invoiceCount) { using (dbDataContext db = new dbDataContext()) { return db.Customers.Where(c => c.InvoiceCount >= invoiceCount); } } What gets returned: {"d":[{"__type":"Customer","Account":"1116317","Name":"SOME COMPANY","Address":"UNit 1 , 392 JOHN ST. ","LastTransaction":"\/Date(1268294400000)\/","HighestBalance":13922.34},{"__type":"Customer","Account":"1116318","Name":"ANOTHER COMPANY","Address":"UNIT #345 , 392 JOHN ST. ","LastTransaction":"\/Date(1265097600000)\/","HighestBalance":549.42}]} What I'd LIKE to know, is what are people generally doing with this returned json? Do you iterate through the properties and create an html table on the fly? Is there way to "bind" JSON data using a javascript version of reflection ( something like the .Net GridView Control ) Do you throw this returned data into a Javascript Object and then do something with it? An example of what I want to achieve is to have an plain ol' html page ( on a mobile device )with a list of a Salesperson's Customers. When one of those customers are clicked, the customer id gets sent to a webservice which retrieves the customer details that are relevant to a sales person. I know the SO talent pool is quite deep so I figured you all here would be able to guide in the right direction and give me a few ideas on the best way to approach this.

  Read the article

• jQuery, Ajax & PHP submit multiple forms dilemma

  - by user557563

  This is a very simple form that I have found on the web (as I am a jQuery beginner). <!-- this is my jquery --> <script> $(document).ready(function(){ $("form#submit_wall").submit(function() { var message_wall = $('#message_wall').attr('value'); var id = $('#id').attr('value'); $.ajax({ type: "POST", url: "index.php?leht=pildid", data:"message_wall="+ message_wall + "&id="+ id, cache: false, success: function(){ $("ul#wall").prepend(""+message_wall+"", ""+id+""); $("ul#wall li:first").fadeIn(); alert("Thank you for your comment!"); } }); return false; }); }); </script> <!-- this is my HTML+PHP --> some PHP ... while($row_pilt = mysql_fetch_assoc($select_pilt)){ print <form id="submit_wall"> <label for="message_wall">Share your message on the Wall</label> <input type="text" id="message_wall" /> <input type="hidden" id="id" value="'.(int)$row_pilt['id'].'"> <button type="submit">Post to wall</button> </form> and down below is my PHP script that writes to mySQL. It is a pretty straight forward script. However, it is getting little complicated when I submit it. Since I have more than one form on my page (per WHILE PHP LOOP), thus when I submit - only the FIRST form gets submitted. Furthermore, any other subsequent forms that I submit - data is being copied from the first form. Is there any jQuery functions that clear the data? - or is there a better solution. Thanks, Nick

  Read the article

• simple jQuery script not running

  - by romaer

  I just have copied a simple script from W3School and cannot get it running: Here it is: <!DOCTYPE html> <html> <head> <script type="text/javascript" src="http://Web Testing/js/jquery-1.8.0.min.js"> </script> <script> $(document).ready(function(){ $("p").click(function(){ $(this).hide(); }); }); </script> </head> <body> <p>If you click on me, I will disappear.</p> <p>Click me away!</p> <p>Click me too!</p> </body> </html> It works on their Tryit Editor with the following line but does not work even with this line on my Mac under BBEdit

  Read the article

• Use external inline script as local function

  - by Aidan

  Had this closed once as a duplicate, yet the so-called duplicate DID NOT actually address my whole question. I have found this script that, when run inline, returns your IP. <script type="text/javascript" src="http://l2.io/ip.js"></script> http://l2.io/ip.js Has nothing more than a line of code that says document.write('123.123.123.123'); (But obviously with the user's IP address) I want to use this IP address as a return string for a function DEFINED EXTERNALLY, BUT STILL ON MY DOMAIN. That is, I have a "scripts.js" that contains all the scripts I wish to use, and I would like to include it in that list as a local function that calls to the 12.io function, but javascript won't allow the < tags, so I am unsure as to how to do this. I.e. function getIP() { return (THAT SCRIPT'S OUTPUT); } This is the topic this was supposedly a duplicate of, and it is very similar. Get ip address with javascript However, this DOES NOT address defining as a forwarded script it in my own script file.

  Read the article

• slidepanel/hover help

  - by Josh

  I'm trying to create a menu navigation system from the top of the page. I want it so when I hover over the link, it drops down (the link drops down; so it'd be as if there was a whole field being hidden beyond the 0px mark) with the related field. I've gotten it to work, somehow but it still isn't right. A few issues are: when I hover over .drop_slide and then if I choose to close it by hovering back over the .drop_slide it does as it's told, which is "slide, slide". I'm interested in rectifying this issue so it doesn't do that, however I just don't know how. The idea is to have multiple links in the .slide, so I need it to be constantly open while the user mouses over the other links. Should this be created in one field? If so, how would I do that with a drop down in mind? Am I approaching this completely wrong? Lol. Should I be researching into .animate? I've been looking at it actually, but I can't get anything to grow negatively. Say; marginTop: -85px or something. ANY help is appreciated, thanks! $(document).ready(function(){ function slide() { $("#panel").slideToggle("slow"); } $(".drop_slide").hover(slide, stop); $("#panel").hover(stop, slide); });

  Read the article

• Ajax to read from form

  - by Edwin

  Hello, I'm writing a store system for my game, it worked quite well until I found out that it only takes the amount of first entered Item. function pbuy(buyitem) { var amountc = "amount-"+buyitem, var amount = $("#"+amountc+"").val(); $.ajax({ type: "POST", url: "store2.php", data: "buyitem="+ buyitem+"&amount="+amount, success: function(resp){ document.getElementById('ajaxDiv').innerHTML = resp; }, error: function(e){ alert('Error: ' + e); } }); } I'm trying to give it it the Id of the form like so: function pbuy(buyitem) { var amountc = "amount-"+buyitem, var amount = $("#"+amountc+"").val(); But nothing happens. The code the creation of the forms is: <tr> <td class='items' width='80%' align='center' valign='top'><?PHP echo $itemstore->itemname;?> </td> <td width="20%"> Price:<?PHP echo $itemstore->newprice;?> <form method="post"> <input type='text' id='amount-<?PHP echo $row;?>)' /> <input name="itembid" type="button" onclick="pbuy(<?PHP echo $row;?>)" value="Buy" /></form></td> </tr> If I hardcode the amount in the ajax function it all runs fine like it should.

  Read the article

• What goes into the "Controller" in "MVC"?

  - by P72endragon

  I think I understand the basic concepts of MVC - the Model contains the data and behaviour of the application, the View is responsible for displaying it to the user and the Controller deals with user input. What I'm uncertain about is exactly what goes in the Controller. Lets say for example I have a fairly simple application (I'm specifically thinking Java, but I suppose the same principles apply elsewhere). I organise my code into 3 packages called app.model, app.view and app.controller. Within the app.model package, I have a few classes that reflect the actual behaviour of the application. These extends Observable and use setChanged() and notifyObservers() to trigger the views to update when appropriate. The app.view package has a class (or several classes for different types of display) that uses javax.swing components to handle the display. Some of these components need to feed back into the Model. If I understand correctly, the View shouldn't have anything to do with the feedback - that should be dealt with by the Controller. So what do I actually put in the Controller? Do I put the public void actionPerformed(ActionEvent e) in the View with just a call to a method in the Controller? If so, should any validation etc be done in the Controller? If so, how do I feedback error messages back to the View - should that go through the Model again, or should the Controller just send it straight back to View? If the validation is done in the View, what do I put in the Controller? Sorry for the long question, I just wanted to document my understanding of the process and hopefully someone can clarify this issue for me!

  Read the article

• The page at [ Page URL ] could not be reached. (Urgent)

  - by Danial Sabagh

  I want to add the like button on my website, but it does not work because whenever I click on Like button it says: The page at could not be reached. You can also check the url to see the error: My Facebook page Here is what I did to use the code: <html xmlns="http://www.w3.org/1999/xhtml" xmlns:fb="http://ogp.me/ns/fb#"> <head> <meta property="og:title" content="ALEXA BEAUTY" /> <meta property="og:type" content="company" /> <meta property="og:url" content="http://alexasalon.co.uk/" /> <meta property="og:image" content="http://alexasalon.co.uk/images/logo.png" /> <meta property="og:site_name" content="ALEXA BEAUTY" /> <meta property="fb:admins" content="100002556535323" /> </head> <body> <div id="fb-root"></div> <script>(function(d, s, id) { var js, fjs = d.getElementsByTagName(s)[0]; if (d.getElementById(id)) {return;} js = d.createElement(s); js.id = id; js.src = "//connect.facebook.net/en_US/all.js#xfbml=1&appId=220687968005095"; fjs.parentNode.insertBefore(js, fjs); }(document, 'script', 'facebook-jssdk'));</script> <div> <fb:like href="http://www.facebook.com/pages/Alexa-Beauty/205401152839187" send="true" width="450" show_faces="false" font="lucida grande"></fb:like> </div> Is the code wrong? Is the page URL correct? I checked the website on Object Debugger and seems there is no error, check link please. I really do not know what is wrong? Does anyone know?!

  Read the article

• How to use scrollTop in jQuery when scrolling within a div?

  - by sharataka

  I am trying to get the scrollTop using jQuery to work when the content I am trying to scroll to is located in within a div. The current implementation doesn't do anything javascript <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.5.1/jquery.min.js"></script> <script> $(document).ready(function (){ //$(this).animate(function(){ $('html, body').animate({ scrollTop: $("#test4").offset().top }, 2000); //}); }); </script> html <div class="row"> <div class = "span12"> <div class = "row"> <div class = "span2"> <div style="height:480px;font:12px Georgia, Garamond, Serif;overflow:auto;"> <div id = "test1">Test1</div> <div id = "test2">Test2</div> <div id = "test3">Test3</div> <div id = "test4">Test4</div> </div> </div> <div class = "row"> <div class = "span8"> Other content on the page </div> </div> </div> </div> </div>

  Read the article

• I can't find the homepage for my ASP.NET MVC site :(

  - by Pure.Krome

  Hi folks, really simple question here. when I remove the default route, I returns an empty page to the browser :- routes.MapRoute( "Default", // Route name "{controller}/{action}/{id}", // URL with parameters new { controller = "Home", action = "Index", id = UrlParameter.Optional } ); Now before everyone starts shouting "that's because that's the default route to access all action methods, etc.." .. i know that. My question is - what code / routes does the default framework try and call .. which makes that Default Route get used/kick in? Why? I don't wish to make that my default route regex (don't ask why - this is some R&D) but I still need the main home page .. ie. Home/Index . If i try and just add that route, it doesn't get called and an empty page is returned. So -- what does the framework try and call when a user doesn't provide any urls? It's like there's some secret default document stuff set up? Cheers :)

  Read the article

• JQuery:bind.blur() is not working

  - by user198880

  Hello, I need to add a row to a table.I am using jQuery to add the row.But i my Add() function everyhing is working fine except that the blur function for the input fild "txtQuantity" is not getting triggered for the newly added row.Here is my function, function Add() { var rowPart = $('#trPart0').clone(true).show().insertAfter('#tblPart tbody>tr:last'); var index = document.getElementById("hdnMaxPartId").value; $("#tblPart tbody>tr:last").attr("id", "trPart" + index); $("td:eq(0) img", rowPart).attr("id", "imgPartDelete" + index).attr("onclick", ""); $("td:eq(1) input:eq(0)", rowPart).attr("id", "hdnWODefPartId" + index); $("td:eq(1) input:eq(1)", rowPart).attr("id", "hdnPartCost" + index); $("td:eq(1) input:eq(3)", rowPart).attr("id", "txtPart" + index).attr("name", "txtPart" + index).attr("onkeyup", ""); $("td:eq(2) input", rowPart).attr("id", "txtQuantity" + index).attr("onblur", ""); $("td:eq(3) div", rowPart).attr("id", "divPartCost" + index); $("td:eq(4) div", rowPart).attr("id", "divPartUnit" + index); $("#imgPartDelete" + index).unbind().bind('click', function() { DeletePart(index); } ); $("#txtPart" + index).unbind().bind('keyup', function() { ajax_showOptions(this,"getPartForAC",event,2,"replace","div_part_list"+index); } ); $("#txtQuantity" + index).unbind().bind('blur', function() { ChangeClassForObject(this,"clsSpText_blur"); CalculateCost(index,this,"divPartCost"+index); } ); }

  Read the article

• How to make jquery pop up box responsive

  - by user2375896

  i have jquery pop up responsive , it works but when i change the size of the page , it stays on the right side . <link rel="stylesheet" type="text/css" href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.7.1/themes/base/jquery-ui.css"> <style type="text/css"> .ui-widget-header { background: white; border: 0px; color:black; } #ui-dialog-title-dialog { background-color: black; } .ui-widget-overlay { background: none repeat-x scroll 0 0 black; opacity: 0.7; }</style> and function side is here : <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.7.1/jquery-ui.min.js"></script> <script type="text/javascript"> $(document).ready(function () { var $dialog = $('<div stye="float:left;" width:auto;"></div>') .html('<p>Lütfen kisi veya kisileri hedef alan haberler yazmayiniz.</p><p>Gerçegi yansitmayan haberler paylasmayiniz. </p><ul><li>Eklediginiz haberler Admin tarafindan onaylandiktan sonra yayinlanacaktir.</li><li>Boyabat.net sitesini kullandiginiz için tesekkür ederiz...</li></ul><table style="margin-right:auto; margin-left:auto;"></table>') .dialog({ autoOpen: true, resizable: true, draggable: true, width: 'auto', // overcomes width:'auto' and maxWidth bug height: 300, maxWidth: 600, modal: true, title: 'Haber Ekleme Kurallari' }); }); </script it works fine but when i run my responsive template and changeit is size to iphone , it is not appera in the screen. I juust need a solution on that . An help appriciate..Thanks

  Read the article

• Why can't I overwrite the prototype of `Array` (`Array.prototype`)?

  - by user828896

  I set the prototype of Array as an instance of my, I think book.aa will display "aa", but it displays "undefined", why? Thanks! <html> <head> <title>Array Properties</title> <h2>Array Properties</h2> <script type="text/javascript"> function my() { this.aa = 'aa'; } Array.prototype = new my(); Array.prototype.bb = "bb"; var book = new Array(); book[0] = "War and Peace"; </script> </head> <body bgcolor="lightblue"> <script type="text/javascript"> document.write(book.aa+book.bb); </script> </body> </html>

  Read the article

• (JQuery) How to call a custom function before following link

  - by morpheous

  I want to achieve the following behavior in a page link. When the link is clicked, I want to: First, send (POST) some data back to the server Second, allow the browser to navigate to the url that the link was pointing to. I am relatively new to JQuery, and here is my first attempt below. I will be grateful to any jQuery gurus in here to fillin the blanks (and maybe point out how the snippet below may be improved). <html> <head>test page</head> <body> <div><a id="hotlink" href="http://www.example.com">Clik and see</a></div> </body> <script type="text/javascript"> $(document).ready(function(){ $('hotlink').click(function(){ //AJAX Post data here ... //follow the link url (i.e. navigate/browse to the link) ... }); }); </script> </html>

  Read the article

• Google Chrome && (cache || memory leaks).

  - by Alexey Ogarkov

  Hello All, I have a big problem with Google Chrome and its memory. My app is displaying to user several image charts and reloads them every 10s. In the interval i have code like that var image = new Image(); var src = 'myurl/image'+new Date().getTime(); image.onload = function() { document.getElementById('myimage').src = src; image.onload = image.onabort = image.onerror = null; } image.src = src; So i have no memory leaks in Firefox and IE. Here the response headers for images Server Apache-Coyote/1.1 Vary * Cache-Control no-store (// I try no-cache, must-revalidate and so on here) Content-Type image/png Content-Length 11131 Date Mon, 31 May 2010 14:00:28 GMT Vary * taken from here In about:cache page there is no my cached images. If i enable purge-memory-button for chrome (--purge-memory-button parameter) it`s not help. Images is in PNG24. So i think that the problem is not in cache. May be Google Chrome is not releasing memory for old images. Please help. Any suggestions. Thanks.

  Read the article

• jQuery variable and object caching

  - by niksy

  This is something that has been bugging me some time and every time I found myself using different solution for this. So, I have link in my document which on click creates new element with some ID. <a href="#" id="test-link">Link</a> For the purpose of easier reusing, I would like to store that new elements ID in a variable which is jQuery object var test = $('#test'); On click I append that new element on body, new element is DIV $('body').append('<div id="test"/>'); And here goes the main "problem" - if I test this new elements length with test.length it first returns 0 and later 1. But, when I test it with $('#test').length it returns 1 from the start. I suppose it is some caching mechanism and I was wondering is there better, all-around solution which will allow to store elements in variables in the start for later repurpose and in the same time work with dynamically created elements. Live, delegate, something else? What I do sometimes is create string and add it to jQuery object but I think this is just avoiding the real issue. Also, using .find() inside another jQuery object. Thanks in advance.

  Read the article

• Zoom in on a point (using scale and translate)

  - by csiz

  I want to be able to zoom in on the point under the mouse in canvas with the mouse whell, like when zooming on maps.google. I'd like straight code as I've been working on this for 5h+ Something to start with: <canvas id="canvas" width="800" height="600"></canvas> <script type="text/javascript"> var canvas = document.getElementById("canvas"); var context = canvas.getContext("2d"); var scale = 1; var originx = 0; var originy = 0; function draw(){ context.fillStyle = "white"; context.fillRect(originx,originy,800/scale,600/scale); context.fillStyle = "black"; context.fillRect(50,50,100,100); } setInterval(draw,100); canvas.onmousewheel = function (event){ var mousex = event.clientX - canvas.offsetLeft; var mousey = event.clientY - canvas.offsetTop; var wheel = event.wheelDelta/120;//n or -n var zoom = 1 + wheel/2; scale *= zoom; originx += 0;//??? originy += 0;//??? context.scale(zoom,zoom); context.translate(0,0);//??? } </script>

  Read the article

• Issue in alternate Row color using each() method of JQuery

  - by user1323981

  I have a table as under <table > <tr> <th scope="col">EmpId</th><th scope="col">EmpName</th> </tr> <tr> <td>1</td><td>ABC</td> </tr> <tr> <td>2</td><td>DEF</td> </tr> </table> I want to set the alternate row color of only the "td" elements of the table and not "th" by using only each() function. I have tried with <style type="text/css"> tr.even { background-color: green; } tr.odd { background-color: yellow; } </style> $(document).ready(function () { $('table > tbody').each(function () { $('tr:odd', this).addClass('odd').removeClass('even'); $('tr:even', this).addClass('even').removeClass('odd'); }); }); Though this works but it accepts also "th" element. How to avoid that? Please help Thanks

  Read the article

• jquery to toggle a label

  - by Juan Almonte

  How can I get the label to toggle show/hide? Below is my code and currently it is also displaying show. I would like it to toggle from show to hide and from hide back to show. when show is displayed the div will be hidden but when show is clicked the label will switch to hide and the div will be displayed and when hide is clicked the label will go back to show and the div will be hidden <html> <head> <title>jQuery test page</title> <script type="text/javascript" src="../scripts/jquery-1.4.2.js"></script> <script type="text/javascript"> $(document).ready(function() { $("#clickMe").click(function() { $("#textBox").toggle(); }); }); </script> </head> <body> <label id="clickMe">Show</label> <br /> <div id="textBox" style="display: none">This text will be toggled</div> </body> </html>

  Read the article

• Simple Jquery function won't work

  - by stijn26

  I have following jQuery code $(document).ready(function() { for(var i=1;i<4;i++) { var img= ".img"+i; var p= ".p"+i; $(img).on("click", function(){ $(p).hide(); }); } }); Applied on the following html: <div> <article> <h1>Over mezelf <img src='images/plus.png' class='img1'/></h1> <p class='p1'>Test</p> </article> <article> <h1>Contact <img src='images/plus.png' class='img2'/></h1> <p class='p2'>Test</p> </article> <article> <h1>Website <img src='images/plus.png' class='img3'/></h1> <p class='p3'>Test</p> </article> </div> When I click on the images, the last <p> disappears, it doesn't work on the other ones.

  Read the article

• PHP Deleting a file 24 hours after being uploaded

  - by user3742063

  I've made a simple script that allows users to upload html files to a web directory on my server. However, I'd like it so each file is deleted after 24 hours of being on my server. 24 hours for each file, not 24 hours for the entire directory. Here is my code so far... Thank you for your help. :) <?php $target = "users/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target) && ($_FILES["uploaded"]["type"] == "html")) { echo "File: " . $_FILES["uploaded"]["name"] . "<br />"; echo "Type: " . $_FILES["uploaded"]["type"] . "<br />"; echo "Size: " . ($_FILES["uploaded"]["size"] / 1024) . " Kb<br />"; echo "Location: /users/" . $_FILES["uploaded"]["name"]; } else { echo "Sorry, " . $_FILES["uploaded"]["name"] . " is not a valid HTML document. Please try again."; unlink . $_FILES["uploaded"]["name"]; } ?>

  Read the article

• Javascript onchange event doesn't change div content

  - by Eli_jun

  I want to replace the content of my <div id="score_here">10</div> when I selecta value from my dropdown <select id="ansRate" onchange="javascript:add_score(this);">. I have setup my javascript function shown below but it doesn't work, what is the problem with this? Thanks for the help. Here are my codes. <div> <select id="ansRate" onchange="javascript:add_score(this);"> <option value="0">Answer Rate</option> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> <option value="4">4</option> <option value="5">5</option> <option value="6">6</option> <option value="7">7</option> <option value="8">8</option> <option value="9">9</option> <option value="10">10</option> </select> </div> <div id="score_here" style="width:100px;height:100px;background-color:yellow;"> 81 </div> <script type="text/javascript"> function add_score(a){ var string = $("#questionScore").text(); var thenum = string.replace( /^\D+/g, ''); var add = $(a).val(); var total = parseInt(thenum) + parseInt(add); document.getElementByID('score_here').innerHTML = total; } </script>

  Read the article

• Submitting form with Ajax

  - by Sidetracking

  So I'm completely lost on how to submit a form with Ajax. I'm fairly new to Javascript and hopefully I'm not in over my head. When I click submit on my form, nothing happens on my page, not in my SQL database where the info should be stored (double checked process form too). Here's the code if anyone's willing to help Javascript: $(document).ready(function() { $('#form').submit(function() { $.ajax({ url: "../process.php", type: "post", data: $(this).serialize() }); }); } HTML: <form name="contact" method="post" action="" id="form"> <span id="input"> <input type="text" name="first" maxlength="50" size="30" title="First Name" class="textbox"> <input type="text" name="last" maxlength="80" size="30" title="Last Name" class="textbox"> <input type="text" name="email" maxlength="80" size="30" title="Email" class="textbox"> <textarea name="request" maxlength="1000" cols="25" rows="6" title="Request"></textarea> </span> <input type="submit" value="Submit" class="submit"> </form>

  Read the article

< Previous Page | 516 517 518 519 520 521 522 523 524 525 526 527  | Next Page >