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  • Submitting form with Ajax

    - by Sidetracking
    So I'm completely lost on how to submit a form with Ajax. I'm fairly new to Javascript and hopefully I'm not in over my head. When I click submit on my form, nothing happens on my page, not in my SQL database where the info should be stored (double checked process form too). Here's the code if anyone's willing to help Javascript: $(document).ready(function() { $('#form').submit(function() { $.ajax({ url: "../process.php", type: "post", data: $(this).serialize() }); }); } HTML: <form name="contact" method="post" action="" id="form"> <span id="input"> <input type="text" name="first" maxlength="50" size="30" title="First Name" class="textbox"> <input type="text" name="last" maxlength="80" size="30" title="Last Name" class="textbox"> <input type="text" name="email" maxlength="80" size="30" title="Email" class="textbox"> <textarea name="request" maxlength="1000" cols="25" rows="6" title="Request"></textarea> </span> <input type="submit" value="Submit" class="submit"> </form>

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  • How to use XML namespace prefixes without xmlns="..." everywhere? (.NET)

    - by LonelyPixel
    The subject is probably too short to explain it... I'm writing out XML files with no namespace stuff at all, for some application. That part I cannot change. But now I'm going to extend those files with my own application-defined element names, and I'd like to put them in a different namespace. For this, the result should look like this: <doc xmlns:x="urn:my-app-uri"> <a>existing element name</a> <x:addon>my additional element name</x:addon> </doc> I've used an XmlNamespaceManager and added my URI with the prefix "x" to it. I've also passed it to each CreateElement for my additional element names. But the nearest I can get is this: <doc> <a>existing element name</a> <addon xmlns="urn:my-app-uri">my additional element name</addon> </doc> Or maybe also <x:addon xmlns:x="urn:my-app-uri">my additional element name</x:addon> So the point is that my URI is written to every single of my additional elements, and no common prefix is written to the document element where I'd like to have it. How can I get the above XML result with .NET?

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  • Help with 'simple' jQuery question

    - by user318573
    I am trying to get a simple effect working in jQuery, and only have a few hours of experience with it, so have a lot to learn. I managed to get this code working: <script type="text/javascript" > $(document).ready(function() { lastBlock = $("#a1"); maxWidth = 415; minWidth = 75; $("ul li a").hover(function() { $(lastBlock).animate({ width: minWidth + "px" }, { queue: false, duration: 600 }); $(this).animate({ width: maxWidth + "px" }, { queue: false, duration: 600 }); lastBlock = this; }); }); </script> Which gives me exactly what I want, a 6 pane horizontal accordion effect. Each pane however has a 75x75 image on the upper left, which is always visible no matter which pane is active (and it is this image that when hovered over caused the pane to open) - what I want to do is for the image on the selected 'pane', I want to drop the top margin down 10px, and then put it back to 0px when a new one is selected, i.e. so the selected panes image is always 10px lower than the other 5 images. I suspect this should be easy, but not quite grasping the syntax yet. Thanks.

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  • CouchDB- basic grouping question

    - by dnolen
    I have a user document which has a group field. This field is an array of group ids. I would like to write a view that returns (groupid as key) - (array of user docs as val). This mapping operation seems like a good beginning. function(doc) { var type = doc.type; var groups = doc.groups; if(type == "user" && groups.length > 0) { for(var i = 0; i < groups.length; i++) { emit(groups[i], doc); } } } But there's obviously something very wrong with my attempt at a reduce: function(key, values, rereduce) { var set = []; var seen = []; for(var i = 0; i < values.length; i++) { var _id = values[i]._id; if(seen.indexOf(_id) == -1) { seen.push(_id); set.push(values[i]); } } return set; } I'm running CouchDB 0.10dev. Any help appreciated.

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  • Simple search engine issues

    - by user1184100
    Simple search engine issues.. I'm creating a simple search engine but i'm not able to figure out how to go about it. So here's what I have tried. I need to get the results based on first/last name.. JSFiddle : http://jsfiddle.net/WSPbP/ JS $(document).ready(function() { $('#sbutn').click(function() { $v = $('#searchbox').val(); console.log($('#myConnections >div').find("div:contains("+$v+")")); }); }); HTML <div id="searchelement"> <div class="search"><input type="text" name="search" id="searchbox" value="" /></div> <div class="searchbutton" id="sbutn"><button type="button">Search</button></div> </div> </br> <div id="myConnections"> <div class="left" style="width:100px; height:100px;"> <img style="width:70px; height:70px;" src="picture1.jpg" alt=""><br> person1_xyz </div> <div class="left" style="width:100px; height:100px;"> <img style="width:70px; height:70px;" src="picture2.jpg" alt=""><br> person2 abc </div> </div>

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  • xml parsing in php issue

    - by jan
    I have this code/function method as part of a class in php: function defaulthome(){ $fp = null; $err =''; $xml_parser = xml_parser_create(); $rss_parser = new Rssparser(); xml_set_object($xml_parser,&$rss_parser); xml_set_element_handler($xml_parser, "startElement", "endElement"); xml_set_character_data_handler($xml_parser, "characterData"); $fp = fopen("http://gulfnews.com/cmlink/business-rss-feed-1.446098?localLinksEnabled=false","r"); if(!$fp) $err = "Error reading RSS data."; else { $count = 0; while ($data = fread($fp, 4096) && $count<10) { xml_parse($xml_parser, $data, feof($fp)) or $err=xml_error_string(xml_get_error_code($xml_parser)); $count++; } } fclose($fp); xml_parser_free($xml_parser); $content_sect2 = $this->tnjn->render('forms/landlords_prompt.phtml'); $context = array('content1_title'=>'Welcome to my website','content1_article'=>"test article", 'feeds'=>$err); $output = $this->tnjn->render("default.phtml", $context); return $output; } I don't get results and the error i have is empty document! Does anyone know which part of the code is the problem? Thanks very much !!

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  • UITableView which has sections as alphabets and various rows within each section

    - by lifemoves
    Hello I have a database in which I am inserting data by parsing an XML document. Populating the data using Navigation bar control view. I have various NSObjects defined in a class and have populated the data using NSMutableArray. Using UITableview I have populated the data. My question is : I have populated the data with the sections defined in it as alphabets so I have total of 26 sections. Each section has data in form of name. Now when I use cellforrowatIndexpath it does not give me the correct index for row and section together. My code is : (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *CellIdentifier = @"Cell"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier]; if (cell == nil) { cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier] autorelease]; } /* Index names as in AB ....Z */ NSString *strIndexNames = [arrCharacters objectAtIndex:indexPath.section]; /* object sections has names in each section */ NSArray *arrIndexedCategories = [objSections objectForKey:strIndexNames]; NSString *strName = [arrIndexedCategories objectAtIndex:indexPath.row] ; cell.textLabel.text = strName; cell.accessoryType = UITableViewCellAccessoryDisclosureIndicator; cell.textLabel.font = [UIFont systemFontOfSize:16]; return cell; } Any help whatsoever will be really helpful. S

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  • Best strategies for reading J code

    - by estanford
    I've been using J for a few months now, and I find that reading unfamiliar code (e.g. that I didn't write myself) is one of the most challenging aspects of the language, particularly when it's in tacit. After a while, I came up with this strategy: 1) Copy the code segment into a word document 2) Take each operator from (1) and place it on a separate line, so that it reads vertically 3) Replace each operator with its verbal description in the Vocabulary page 4) Do a rough translation from J syntax into English grammar 5) Use the translation to identify conceptually related components and separate them with line breaks 6) Write a description of what each component from (5) is supposed to do, in plain English prose 7) Write a description of what the whole program is supposed to do, based on (6) 8) Write an explanation of why the code from (1) can be said to represent the design concept from (7). Although I learn a lot from this process, I find it to be rather arduous and time-consuming -- especially if someone designed their program using a concept I never encountered before. So I wonder: do other people in the J community have favorite ways to figure out obscure code? If so, what are the advantages and disadvantages of these methods?

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  • Dropdown menu not showing when using position: absolute;

    - by Xiy
    I've just turned my website into a responsive layout and along the way I've somehow managed to make my dropdown menus not work. When hovering over 'Drop-downs' they don't display unless I'm using position: relative. They worked before using position: absolute - but it seems they only work with position relative now. When using relative it uses the width which messes up the navigation bar. Using relative: http://d.pr/i/tp5R Using absolute: http://d.pr/i/j7r1 CSS for my sub-menu div.left_first_header ul.sub-menu { width: 125px; top: 14px; z-index: 2; height: 100%; position: absolute; -webkit-border-radius: 0px 0px 4px 4px; -moz-border-radius: 0px 0px 4px 4px; background: url(images/drop_down_bg.jpg); padding-left: 15px; padding-right: 15px; background-repeat: repeat; } jQuery for the drop down functionality jQuery(document).ready(function ($) { jQuery("ul.dropdown li").hover(function() { $('ul:first',this).css('visibility', 'visible'); }, function() { jQuery(this).removeClass("hover"); jQuery('ul:first',this).css('visibility', 'hidden'); }); }); My website http://wpvault.com/kahlam/ Considering it's 4am I've probably made a really stupid simple mistake. I apologise if I've missed anything.

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  • div on other div

    - by Gisinior
    i have: <script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.6.1/jquery.min.js"></script> <style type="text/css"> #ONE { background-color: #888; width: 500px; height: 500px; } #TWO { background-color: blue; width: 50px; height: 50px; } #THREE { background-color: yellow; width: 200px; height: 200px; display: none; } #four { background-color: red; width: 200px; height: 200px; } </style> <script type="text/javascript"> $(document).ready( function() { $("#TWO").click( function() { $("#THREE").toggle(); }); }); </script> <div id="ONE"><div id="TWO"></div><div id="four"></div><div id="THREE"></div></div> default click for blue div how can i it make? best with transparent :)

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  • jQuery: Is it possible to assign a DOM element to a variable for later use?

    - by Braxo
    I'm working on a project that is using jQuery, which I'm much more familiar with Mootools. I'll start with my code first. var customNamespace = { status: 'closed', popup: $('#popup'), showPopup: function() { // ... } } $(document).ready(function(){ console.log($('#popup')); console.log(customNamespace.popup); console.log($(customNamespace.popup)); $('#popup').fadeIn('slow'); (customNamespace.popup).fadeIn('slow'); $(customNamespace.popup).fadeIn('slow'); }); My goal is to not have jQuery traverse the DOM everytime I want to do something with the #popup div, so I wanted to save it to a variable to use it throughout my script. When the page loads, the console prints out the object 3 times as I would expect, so I assumed that for each method, the fadeIn would just work. But it doesn't, only $('#popup').fadeIn('slow'); Actually fades in the div. Even if I remove my namespace hash, and just save the object to a global variable, and do a var globalVariable = $('#popup'); . . . globalVariable.fadeIn('slow'); Also does not work as I thought it would. Can jQuery do what I am trying to do?

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  • mcsCustomscrollbar append new content not working

    - by Dariel Pratama
    i have this script in my website. $(document).ready(function(){ var comment = $('textarea[name=comment_text]').val(); var vid = $('input[name=video_id]').val(); $('#add_comment').on('click', function(){ $.post('<?php echo site_url('comment/addcomments'); ?>', $('#comment-form').serialize(), function(data){ data = JSON.parse(data); if(data.userdata){ var date = new Date(data.userdata.comment_create_time * 1000); var picture = data.userdata.user_image.length > 0 ? 'fileupload/'+data.userdata.user_image:'images/no_pic.gif'; var newComment = '<div class="row">\ <div class="col-md-4">\ <img src="<?php echo base_url(); ?>'+picture+'" class="profile-pic margin-top-15" />\ </div>\ <div class="col-md-8 no-pade">\ <p id="comment-user" class="margin-top-15">'+data.userdata.user_firstname+' '+data.userdata.user_lastname+'</p>\ <p id="comment-time">'+date.getTime()+'</p>\ </div>\ <div class="clearfix"></div>\ <div class="col-md-12 margin-top-15" id="comment-text">'+data.userdata.comment_text +'</div>\ <div class="col-md-12">\ <div class="hr-grey margin-top-15"></div>\ </div>\ </div>'; $('#comment-scroll').append($(newComment)); $('#comment').modal('hide'); } }); }); }); what i expect when a comment added to the DB and the PHP page give JSON response, the new comment will be added to the last line of $('#comment-scroll'). #comment-scroll is also have custom scroll bar by mcsCustomscrollbar. the above script also hiding the modal dialog when comment saved and it's working fine which is mean data.userdata is not empty, but why the append() isnt?

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  • Drupal 7 - I can't pass post data in module function

    - by user2603290
    I can't pass post data in my custom module. filenames: mymodule.info mymodule.mod .info name = My Module description = My custom module. package = DEV version = 1.0 core = 7.x .module <?php function mymodule_menu() { $items = array(); $items['getcountries'] = array( 'title' => 'Get Countries', 'page callback' => 'getcountries', 'access arguments' => array('access content'), 'type' => MENU_CALLBACK, ); $items['getstates'] = array( 'title' => 'Get States', 'page callback' => 'getstates', 'access arguments' => array('access content'), 'type' => MENU_CALLBACK, ); return $items; } function getcountries() { $result = db_query("select distinct(country) from region"); $jsonarray = Array(); foreach ($result as $record) { $jsonarray[] = array( 'item' => $record->country, 'value' => $record->country ); } $json = json_encode($jsonarray); echo $json; } function getstates() { echo $_POST["test"]; } Ajax call $(document).ready(function(){ $.ajax({ url: '/getstates', type: 'POST', data: '{"test":"1"}', success : function () { alert('ok'); }, error : function (jqXHR, textStatus, errorThrown) { alert('error'); } }); }); The first item "getcountries" is working fine however the second one is not. I can browse to http://mysite.com/getstates ok but when I call this function using ajax it is not passing the value of "test" which is "1" to $_POST["test"]. I am new to Drupal so I am positive that I miss something here. I thought I need a new set of eyes.

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  • jquery .siblings do not work

    - by Mango
    Hi i want when the one #box is open the others #box close. Html: <div id="main"> <div id="link">click</div><!--/*div*/--> <div id="box">content1</div><!--/*div*/--> </div><!--/*div*/--> <div id="main"> <div id="link">click2</div><!--/*div*/--> <div id="box">content2</div><!--/*div*/--> </div><!--/*div*/--> <div id="main"> <div id="link">click3</div><!--/*div*/--> <div id="box">content3</div><!--/*div*/--> </div><!--/*div*/--> Jquery: <script type="text/javascript"> $(document).ready(function(){ $('#main #box').css('display', 'none') $('#main #link').click(function() { $(this).next('#main #box').slideToggle('slow') .siblings('#main #box:visible').css('display', 'none'); }); }); </script> Thanks!

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  • JQuery ajax success help

    - by Jason
    Hi all, I am implementing a "Quick delete" function into a page I am creating. The way it works is like this: 1: You click the "delete" button in the table row for the record that you want to delete. 2: The page sends a request to the ajax page and return a successfully message of "yes" or a failure message of "no". My issue is that if I get a successful message of "yes" I want to hide the row for that record. I am having issue "finding" the row using JQuery. Here is my jquery code: $(document).ready(function(){ $(".pane .btn-delete").click(function(){ var element = $(this); var del_id = element.attr("id"); var dataString = 'action=del&cid=' + del_id; if(confirm("Are you sure you want to delete this content block?")) { $("#msgbox").addClass('ajaxmsg').text('Checking permissions....').fadeIn(1000); $.ajax({ type: "get", url: "ajax/admArticles_ajax.php", data: dataString, success: function(data){ switch(data) { case "yes": $("#msgbox").addClass('ajaxmsg').text('Deleting content block....').fadeIn(1000); $(this).parents(".pane").animate({ backgroundColor: "#fbc7c7" }, "fast") .animate({ opacity: "hide" }, "slow") break case "no": $("#msgbox").removeClass().addClass('error').text('You do not have the correct permissions to delete this content....').fadeIn(1000); break default: }; } }); } return false; }); }); This is the lines of code I am using to hide the row however it is not working because I don't think $(this).parents(".pane") finds the element. $(this).parents(".pane").animate({ backgroundColor: "#fbc7c7" }, "fast") .animate({ opacity: "hide" }, "slow") Any help would be greatly appreciated. Thanks...

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  • Allowing user to type only one "."

    - by Tartar
    I am trying to implement a simple javascript-html calculator. What i want to do is,typing only one '.' by the user. How can i control this ? Here is the code that i tried. I can already find the number of '.' but i'am confused now also this replaceAll function is not replacing '.' with empty string. String.prototype.replaceAll = function(search, replace) { //if replace is null, return original string otherwise it will //replace search string with 'undefined'. if(!replace) return this; return this.replace(new RegExp('[' + search + ']', 'g'), replace); }; function calculate(){ var value = document.calculator.text.value; var valueArray = value.split(""); var arrayLenght = valueArray.length; var character = "."; var charCount = 0; for(i=0;i<arrayLenght;i++){ if (valueArray[i]===character) { charCount += 1; } } if(charCount>1){ var newValue=value.replaceAll(".",""); alert(newValue); } }

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  • Problem with jQuery array

    - by user236106
    <html> <head> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.3/jquery.min.js" type="text/javascript"></script> <script type="text/jscript"> $('document').ready(function (){ var clickNo=0; $('div#pics>img').hide() $('div#pics>input').click(function(event){ $('div#pics>img')[0].show('slow'); }) }); </script> </head> <body> <div id="pics"> <input type="button" value="next" /> <--a bunch of img tags .I had to resort to this comment because the system won't let me include the img tag in the code--> </div> </body> </html> I can't understand why the line $('div#pics>img')[0].show('slow'); is not working.

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  • Eclipc java,writting a program [closed]

    - by ghassar
    I have an important exercise for that i found in the internet please i need help in using eclipc java thanks i have to design, implement, test and document a Java program (a set of classes) for one of the following problem specifications: Problem 1 – Jubilee Estate Agency Property Management System A local Estate Agent would like a prototype system to keep track of properties that are offered for sale. The Estate Agent sells domestic and commercial properties. You will need to define classes that represent the Estate Agency System. You should design your system and the classes that you will need before starting coding. Your system must have a graphical user interface and be designed and developed using the object-oriented principles of the MVC architecture design pattern i.e. the user interface class must be separate from the other classes. The initial basic requirements for the system are as follows: • Include a list of domestic properties for sale that include details of: address, description, selling price, and number of rooms • Include a list of commercial properties for sale that include details of: address, description, selling price, and area in square metres • Enable the properties that are for sale to be viewed on the screen • Allow the customer to select one or more properties to be placed on a ‘viewing list’ so that the properties can be visited in person • Display on the screen the viewing list that shows the details of the properties chosen • Provide a basic search facility to find properties that are for sale in a particular price band and display the results • Enable a property to be marked as sold

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  • how to filter selected objects then hide objects not selected.

    - by ussteele
    following up from yesterday... This portion of the code does work. $(document).ready(function(){ $('#listMenu a').click(function (selected) { var getPage = $(this).attr('id'); var getName = $(this).attr('name'); //console.log(getPage); //console.log(getName); $(function() { $("#" + getName ).show(); var getColor = $('#' + getName ).css('background-color'); $('#header' ).css('background', getColor); $('#slideshow' ).css('background', getColor); $('span').css('background', getColor); $('#menuContainer').css('background', getColor); }); $('li.listMenu ul').hide(); }); }); I am able to get what I wanted selected; based on vars getPage and getName, now I need to hide what is not selected. I have tried this: $(function() { var notSelected = $('div').filter(selected).attr('id', 'name'); $(this).hide(); console.log(notSelected); }); placed just above: $('li.listMenu ul').hide(); but it's not correct, remember I am really a newbie. what I see on screen is the new selected items on top of what should be hidden. again any help is appreciated. -sjs

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  • Get real height of div plus css generated content (if possible)

    - by qp2wd
    I'm trying to use javascript to give three divs a negative top position equal to their height. I've got it working, sort of (thanks to help from here!) but instead of calculating the height of each div and calculating the top position accordingly, each div is being assigned a negative top position of -367px: <script type="text/javascript"> $(document).ready(function() { //Get height of footer popup var pHeight = $('footer ul li > ul').outerHeight(); //Calculate new top position based on footer popup height var nHeight = pHeight + "px"; $('footer ul li > ul').css({ //Change top position to equal height of footer popup 'top' : "-" + nHeight }); }); </script> I've tried this using .height, .outerheight, and even .getheight which someone mentioned on the Jquery documentation for .height. I also tried using an each statement, though it didn't seem to work; I may have written it incorrectly. In addition (if possible), I'd like the negative position to take into account the height of a content being generated using the css :after psuedo-property, though I can always manually add that in to the calculation if javascript has no way to access that. EDIT: Added a test page link. It's the bottom divs I'm trying to target with JS, but if anyone has an idea regarding how to fix the problem with the top divs I'd be much obliged as well. http://www.qualityprinters2.com/test/float-tab-test.html

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  • Javascript in php

    - by user506539
    I have a form where user enters category, it gets inserted into db and it has to go to other page to select an image, after selection image id has to get into category table. I am doing some thing like this <?php error_reporting(E_ALL ^ E_NOTICE); $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("mydocair", $con); $ThirdPartyCategoryName =$_POST['ThirdPartyCategoryName']; $checkformembers = mysql_query("SELECT * FROM thirdpartycategorymaster WHERE ThirdPartyCategoryName = '$ThirdPartyCategoryName'"); if(mysql_num_rows($checkformembers) != 0) { header('location:newcat.php?msg=category exists'); } else { $sql="INSERT INTO thirdpartycategorymaster (ThirdPartyCategoryID, ThirdPartyCategoryName) VALUES ('$_POST[ThirdPartyCategoryID]', '$_POST[ThirdPartyCategoryName]' )"; } if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } mysql_close($con); ?> <?php $res = mysql_query("SELECT ThirdPartyCategoryID FROM thirdpartycategorymaster"); while($row = mysql_fetch_array($res)) { "<script type='text/javascript'> if(window.confirm("Do you want to insert image for category?")) { document.location = "imgcat.php?id="<?php echo row2['ThirdPartyCategoryID']; ?>"" } </script>"; } ?>

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  • How to get jquery to append output immediately after each ajax call in a loop

    - by david_nash
    I'd like to append to an element and have it update immediately. console.log() shows the data as expected but append() does nothing until the for loop has finished and then writes it all at once. index.html: ... <body> <p>Page loaded.</p> <p>Data:</p> <div id="Data"></div> </body> test.js: $(document).ready(function() { for( var i=0; i<5; i++ ) { $.ajax({ async: false, url: 'server.php', success: function(r) { console.log(r); //this works $('#Data').append(r); //this happens all at once } }); } }); server.php: <?php sleep(1); echo time()."<br />"; ?> The page doesn't even render until after the for loop is complete. Shouldn't it at least render the HTML first before running the javascript?

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  • jquery plugin: creation

    - by user1542535
    The output am expecting is an unordered list which am creating with jquery...which takes in put from a json file (which works fine when i dont create it as a plugin). Am very new with the concept of building a plugin. i've tried to create one which doesnt output my unordered list json file structure { "Categories": [ { "cat_id":"1", "name":"Main Menu1", "sub_categories":[ { "cat_id":"10", "name":" Sub Menu11", "sub_level_one_link":"http:\/\/one.com" }, my js file //create plugin jQuery.fn.emrMenu= function (options) { myoptions = jQuery.extend ({ url: "error" }, options); if (myoptions.url=="error") { alert("Error:No data recieved"); return false; } $(this).html (myoptions.url); return this.each (function () { //alert(myoptions.url+this.id); $.getJSON(myoptions.url, function(data) { $.each(data.Categories, function(i, category) { alert("test1"); //get all sub menu items in list indexes var submenudata=''; $.each(category.sub_categories, function(i, sub_categories) { submenudata += "<li><a href='"+sub_categories.sub_level_one_link+"' <span>"+sub_categories.name+"</span></a></li>"; }); var menudata ="<li id='"+category.cat_id+"' class='has-sub '><a href='#'><span>"+category.name+"</span></a><ul>"+submenudata+"</ul></li>"; //stringify unordered list and bind to div var menu="<ul>"+menudata+"</ul>"; // $(menu).appendTo("#"this.id); }); }); //alert (this.id); }); } and am calling the plugin: <script> $(document).ready(function() { $('#menu_n').emrMenu ({ url: "menu_data.json"}); }); </script> I'am pretty confused at this point any help is greatly appreciated cheers!

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  • what this json must work?

    - by user1772630
    hi i search alot for get a respone from php back and if that respone is ok do someting and if its false do something else(!!!!!!!! WHENE I HAVE OTHER OUTPUT FROM THAT PHP !!!!!!) this is my index file <head> <script src="jquery-1.7.2.js" type="text/javascript"></script> <script src="js.js" type="text/javascript"></script> </head> <body> <p> click </p> <input type="text" id="who"> <br> <input type="text" id="why"> <div id="bg" align="center"> </div> </body> this is my JS file $(document).ready(function(){ $('p').click(function(){ var who = $('input#who').val(); var why = $('input#why').val(); $.post('file.php',{who:who,why:why},function(data) { if(data.success){ alert(data.message); } else{ alert('ERROR:' + data.message); } }); }); }); and this is my file.php <?php $response = array('success' => 'true', 'code' => "jQuery('#bg').html('\"Javascript\", \"json\", \"PHP\"');"); echo json_encode($response); ?> my question : 1- why this is not work i get alert (error:undifined) 2- how i can get some result from that php file when its have other output like this: <?php echo "1"; echo "2"; echo "3"; and now echo that json ?> thanks :(

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  • Receive Ajax and display output in a Photo?

    - by user1709469
    how to Receive Ajax and display output in a Photo? Images should be displayed inside the div tag After each of Bayer text, change the text to change the photo content The photos displayed are written in the form Thanks this code <script> function AjaxRequest() { var xmlhttp = null; if (window.XMLHttpRequest) { // code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp = new XMLHttpRequest(); } // else // code for IE6, IE5 return xmlhttp; } function ajaxAction() { var font_category = document.getElementById("ajaxField").value; var xmlHttp = AjaxRequest(); xmlHttp.open("POST" , "ajax.php?message=" + message , true); xmlHttp.onreadystatechange = function() { if(xmlHttp.readyState == 1) response.innerHTML = "Loading..."; if (xmlHttp.readyState == 4 && xmlHttp.status == 200) response.innerHTML = xmlHttp.responseText; } xmlHttp.send(null); } </script> <textarea id="ajaxField12" name="message" rows="2" cols="20" value="Send" onchange="javascript:ajaxAction();"> </textarea> <div id="ajaxResponse" height="42" width="42"> </div>

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