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  • Monitoring for postbacks with PHP?

    - by Rebecca
    Hi, I have a PHP page with content that my users can view. When this page receives a POST request from a certain external URL, I'd like to redirect the user to another page. The problems I'm' having are: How can I monitor the page for requests being sent in an efficient way? How can I actually redirect them since header() doesn't work. Thanks.

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  • Extract Address Information from a Web Page

    - by Brian Boatright
    I need to take a web page and extract the address information from the page. Some are easier than others. I'm looking for a firefox plugin, windows app, or VB.NET code that will help me get this done. Ideally I would like to have a web page on our admin (ASP.NET/VB.NET) where you enter a URL and it scraps the page and returns a Dataset that I can put in a Grid.

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  • How to get the list in second image ?

    - by rajesh
    Hi, actually i have 2 images ,when we click on one image it generates pop window containing n no of list. if i click on any link 2 parameters are passed to function one for url and other image path and now i have another image ,what i want to do is if i click on that image it will generate a list which has a content of first image after clicking any link of first image means if i click image1 image2 1 2 3 now if i click 1 then result must be like this image1 image2 1 1 2 3 Please help thanks.

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  • [JS] How to workaround same origin problem

    - by Ricky
    Hi guys: The following JS will fail if the URL in mainFrame from a.abc.com to b.abc.com. top.frames["mainFrame"].location.href = "/Users/xuenn.aspx?backUrl=" + top.frames["mainFrame"].location.href.split("?")[0]; This is the error message: Permission denied for http://a.abc.com to get property Location.href from http://b.abc.com. Anybody knows how could I workaround this or think of other solutions?

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  • HTTP triggers for Postgres

    - by HeineyBehinds
    I'm trying to write a Postgres trigger such that when a configuration table is updated, a backend component is notified and can handle the change. I know that Oracle has the concept of a web/HTTP trigger, where you can execute an HTTP GET from the Oracle instance itself to a URL that can then handle the request at the application layer. I'm wondering if Postgres (v. 9.0.5) has the same feature, or comes with anything similar (and, subsequently, how to set it up/configure it)?

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  • JQuery AJAX syntax

    - by Nick
    I am trying to find the correct syntax to pass a varible to my JQuery Post. var id = empid; $.ajax({ type: "POST", url: "../Webservices/EmployeeService.asmx/GetEmployeeOrders", data: "{empid: empid}", contentType: "application/json; charset=utf-8", dataType: "json", success: function(result) { alert(result.d); } I don't think the data: value is quite right. Someone set me straight? Thanks!

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  • Using XMLHttpRequest ??

    - by Rohan
    Hey I'd like to know how to use XMLHttpRequest to load the content of a remote URL and have the HTML of the accessed site stored in a JS variable. Say, if I wanted to load and alert() the HTML of http://foo.com/bar.php, how would I do that? Thanks!

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  • Deploying solr in Jboss

    - by Azhar
    I want to deploy the solr.war to jboss server. Please provide me the steps for this. Also after deploying what url i should use to access the solr/data/index directory? Thanks!!

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  • what is other option for HTTP_REFERER in php?

    - by user251336
    Hi all, I want to know is there any option/work sround for $_SERVER['HTTP_REFERER']. Because 'HTTP_REFERER' can not be trusted. Then What is other way to know that from which url the request has came from?. Here is the situation - http:// abc.com/one.htmlwill have an iframe having src=http:// xyz.com/giv.php?param=1. How giv.php on xyz.com will know that request is coming from http:// abc.com/one.html?

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  • Upload & Link an Image with php

    - by Jason
    I know this should be really simple, but im having trouble getting this to work right, basically i want to have an image upload box that uploads an image and then puts the new url into a mysql database. Anyone have any advice on how to do this, as i may be having developer block but im over complicating it in my head :P Thanks

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  • jquery pass dynamic variable name

    - by Alessandro
    hi function liveUpdate(fld,value,id) { $.ajax({ type: 'POST', url: 'myurl.html', data: { fld:value, 'id': id }, success: function(data){//console.log(data); } }); } i want fld to be posted as fld's value not the variable name fld? i've tried to wrap around with eval but no luck any ideas? thanks

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  • terminating index process for search engine

    - by Sadegh
    hi, i am working on a small search-engine app with asp.net 4.0. the indexing process can index each URL founded in each document and this recursively performed for each other. now how i can terminate this process when i want or when user clicked on stop browser button?

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  • Handling Model Inheritance in ASP.NET MVC2

    - by enth
    I've gotten myself stuck on how to handle inheritance in my model when it comes to my controllers/views. Basic Model: public class Procedure : Entity { public Procedure() { } public int Id { get; set; } public DateTime ProcedureDate { get; set; } public ProcedureType Type { get; set; } } public ProcedureA : Procedure { public double VariableA { get; set; } public int VariableB { get; set; } public int Total { get; set; } } public ProcedureB : Procedure { public int Score { get; set; } } etc... many of different procedures eventually. So, I do things like list all the procedures: public class ProcedureController : Controller { public virtual ActionResult List() { IEnumerable<Procedure> procedures = _repository.GetAll(); return View(procedures); } } but now I'm kinda stuck. Basically, from the list page, I need to link to pages where the specific subclass details can be viewed/edited and I'm not sure what the best strategy is. I thought I could add an action on the ProcedureController that would conjure up the right subclass by dynamically figuring out what repository to use and loading the subclass to pass to the view. I had to store the class in the ProcedureType object. I had to create/implement a non-generic IRepository since I can't dynamically cast to a generic one. public virtual ActionResult Details(int procedureID) { Procedure procedure = _repository.GetById(procedureID, false); string className = procedure.Type.Class; Type type = Type.GetType(className, true); Type repositoryType = typeof (IRepository<>).MakeGenericType(type); var repository = (IRepository)DependencyRegistrar.Resolve(repositoryType); Entity procedure = repository.GetById(procedureID, false); return View(procedure); } I haven't even started sorting out how the view is going to determine which partial to load to display the subclass details. I'm wondering if this is a good approach? This makes determining the URL easy. It makes reusing the Procedure display code easy. Another approach is specific controllers for each subclass. It simplifies the controller code, but also means many simple controllers for the many procedure subclasses. Can work out the shared Procedure details with a partial view. How to get to construct the URL to get to the controller/action in the first place? Time to not think about it. Hopefully someone can show me the light. Thanks in advance.

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  • WCF service: how to open and read from TCP/HTTP stream?

    - by Ole Jak
    So I need my WCF service to be capable of starting TCP stream on HTTP request (like sockets do) and be capable of reading if any one is sending TCP respons to it while reciving stream. I need my service to have acsessable to Internet browsers url like example.com/myTCPStreamingWCFService.svc?id=999 for reading from or riting to it. How to do such thing?

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  • android activity callback

    - by sanju
    Hii'm begginer in android. i'm doing small apllication,i have mainscreen and calling next screen by main screen.in nextscreen by selecting image in gallery i wanted to go back main screen by getting image url how can do this please help me its urgent.

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  • Avoid closing Jquery's FancyBox

    - by user309745
    Hi I am using fanxybox 1.2.6 but it's getting closed despite of mentionig onContentClick:false Here is the code: $("#"+vari).fancybox({'hideOnContentClick':false }).trigger('click'); Kindly help me out p.s: The window is loading content from other URL(via Iframe)

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  • is it possible to store server returned json data in jqgrid to display columnnames models data dynamically for every request?

    - by user1768246
    is it possible to store server returned json data in jqgrid to display columnnames models data dynamically for every request ? $("#grid").jqGrid({ type: "GET", url: "", var columnNames = $("#grid")[0].p.colNames, var columnModel = $("#grid")[0].p.colNames, var columnData = $("#grid")[0].p.colNames, datatype: 'jsonstring', datastr: columnData, colModel: columnModel, jsonReader: { root: 'innerWrapper.rows', page: "result.gridData.outerWrapper.page", total: "result.gridData.outerWrapper.total", records: "result.gridData.outerWrapper.total", repeatitems: false, }, gridview: true, pager: "pager", height: "auto", rowNum: 10, width:"auto", height:"auto", rowList: [10, 20, 30,40], viewrecords: true, caption:"Graph Data", rownumbers: true, });

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  • How do i create multiple URLs with /controller/action/ format?

    - by Angela
    I have several controller/actions where no :id needs to be passed. what I did with the first two was make a custom route defining the controller and action. I thought that the default would allow me to create controller/action.xml by using respond_to in the controller, but that doesn't appear to be the right way. How can I create controller/action URL's (some are .xml) without creating a special route with map.connect?

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  • Any php code to make embed code of video ?

    - by Tom
    Hi, I Want a php code to turn a youtube/dailymotion/vimeo/metacafe... URL into an EMBEDABLE code so i can show it using echo , it is really hard to read the API of every website, so i'm wondering if there is a class or code to do this. Note: if there isn't anyone, then maybe a jQuery facebox alternative who supports more than youtube. Thanks

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