C# class can not disguise to be another class because GetType method cannot be override
- by zinking
there is a statement in the CLR via C# saying
in C#, one class cannot disguise to be another, because GetType is virutal and thus it cannot be override
but I think in C# we can still hide the parent implementation of GetType.
I must missed something
if I hide the base GetType implementation then I can disguise my class to be another class, is that correct?
The key here is not whether GetType is virutal or not, the question is can we disguise one class to be another in C#
Following is the NO.4 answer from the possible duplicate, so My question is more on this.
is this kind of disguise possible, if so, how can we say that we can prevent class type disguise in C# ? regardless of the GetType is virtual or not
While its true that you cannot override the object.GetType() method,
you can use "new" to overload it completely, thereby spoofing another
known type. This is interesting, however, I haven't figured out how to
create an instance of the "Type" object from scratch, so the example
below pretends to be another type.
public class NotAString {
private string m_RealString = string.Empty;
public new Type GetType()
{
return m_RealString.GetType();
} }
After creating an instance of this, (new NotAString()).GetType(), will indeed return the type for a string.
share|edit|flag answered Mar 15 at 18:39
Dr Snooze 213
By almost anything that looks at GetType has an instance of object, or at the very least some base type that they control or can
reason about. If you already have an instance of the most derived type
then there is no need to call GetType on it. The point is as long as
someone uses GetType on an object they can be sure it's the system's
implementation, not any other custom definition. – Servy Mar 15 at
18:54 add comment
