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  • scrolling in both directions at the same time...like in many games

    - by Angel
    Hi, I want to create a game which has a grid view...like 1 2 3 4 5 6 7 8 9 1 2 3 4 5 6 7 8 9 1 5 6 7 8 9 3 1 3 2 4 6 7 8 9 1 4 6 3 1 5 6 8 9 1 4 6 4 4 7 8 1 5 7 8 8 what i want to do is on my screen it should display only a part of it that is 1 2 3 4 1 2 3 4 1 5 6 7 Rest all should be hidden and scrollable in both the directions at the same time (diagonally) Please give inputs.. Should i use canvas and over it gridView or simply a grid view.. . If yes then how? Thanks

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  • Only first word of two strings gets added to db

    - by dkgeld
    When trying to add words to a database via php, only the first word of both strings gets added. I send the text via this code: public void sendTextToDB() { valcom = editText1.getText().toString(); valnm = editText2.getText().toString(); t = new Thread() { public void run() { try { url = new URL("http://10.0.2.2/HB/hikebuddy.php?function=setcomm&comment="+valcom+"&name="+valnm); h = (HttpURLConnection)url.openConnection(); if( h.getResponseCode() == HttpURLConnection.HTTP_OK){ is = h.getInputStream(); }else{ is = h.getErrorStream(); } h.disconnect(); } catch (Exception e) { // TODO Auto-generated catch block e.printStackTrace(); Log.d("Test", "CONNECTION FAILED 1"); } } }; t.start(); } When tested with spaces and commas etc. in a browser, the php function adds all text. The strings also return the full value when inserted into a dialog. How do I fix this? Thank you.

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  • Customizing Sipdroid

    - by Seshu Vinay
    I have a Voip based app. So i thought of customizing SipDroid open source project. As the starting phase i have changed all the package names, Class names etc. It perfectly works on my Samsung Galaxy Y. But i tried with many other mobiles, Voice is not audible. Call is being initialized but could not hear voice. In Samsung galaxy young, voice is clearly audible for both incoming and outgoing calls. But in all the other phones i have tested i can hear only beep sounds. What could be the problem? I tried calling the other mobile(that has Sip Droid) with my Samsung Galaxy Young(customized app) I could hear voice in my app but could not hear in Sipdroid. But when i tried calling Sipdroid to Sipdroid, it works fine in all the mobiles.

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  • How to differenciate two tables

    - by Nemat
    Hi friends.... I have two tables.I want to get all records from one table that are different from the records in second table. For eg. if we have four records in first table like A,B,C,D and three records in second table thats A,B,C then the answer of query should be D. I have tried "EXCEPT" operator but it doesnt work fine.Kindly help me in writing correct query for the given problem. Any help is appreciated.... Thanks in Advance Nemat

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  • Why activity result code is diffrent then I expected

    - by Fisher
    I have 2 activities. In child activity i have put something like that in onPause(): if (isFinishing()) { final Intent intent = new Intent(); intent.putExtra(SOME_DATA, value); setResult(RESULT_OK, intent); Log.i("test", "Result set to RESULT_OK"); } In parent activity i check resultCode when child activity is destroyed, and this is what i have noticed: If i destroy child activity by some action (in some condition i invoke finish()), then resultCode is RESULT_OK But when i destroy by pressing return key (i works only in emulator so its ESC) who kills activity, then resultCode read in parent onActivityResult method equals 0 (RESULT_CANCELD). "test" log read in each case is the same.

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  • Can't remove a view included using a include tag

    - by Julio Rodrigues
    Removing a view that was included using a <include> tag seems to have no effect. ViewGroup currentPersonContainer = (ViewGroup) root.findViewById(R.id.propria_pessoa_container); if (dto.occupation!= null) { . . . } else { root.removeView(currentPersonContainer); } After the root.removeView(currentPersonContainer); I can still find it in root and the view is still visible. How can I remove a view included in a xml layout resource file?

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  • when do we have a virtual memory problem using Fastmm4?

    - by JD
    Hi, We have an application whose virtual memory rises and keep going for over a day. After two days it has climbed to about 500MB. I have tried profiling the applications which hits a database as well as makes lots of http and soap requests but I Fastmm4 shows there are no leaks. I am not sure how or when memory is claimed and if there is a problem here with the rising virtual memory? JD

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  • Problem with setProgressDrawable

    - by Martin
    I am having problem with setting a new Drawable to my ProgressBar. If I use the setProgressDrawable() inside onCreate() method it works great. But when I try to call the same method inside a Handler post callback it doesn't work and the progressbar disapears. Can someone explain this behaviour? How can I solve this problem?

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  • A non-ugly way to persist dialog contents across orientation changes?

    - by alex
    So I have a managed AlertDialog with a number of EditTexts & separate portrait + landscape layouts. The user opens the dialog in portrait mode, enters some text and then all of a sudden decides to pop out the keyboard. Now, I need to remove the dialog and recreate it for the changed layout persisting the text entered. What I can think of is getting references to the EdiTexts in onPrepareDialog(..), then getting the actual text in onConfigurationChanged(..), then removing the dialog, then showing it again, then populating it. Rather ugly, huh? Are there any better options?

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  • BitmapFactory.decodeFile out of memory with images 2400x2400

    - by alasarr
    I need to send an image from a file to a server. The server request the image in a resolution of 2400x2400. What I'm trying to do is: 1) Get a Bitmap using BitmapFactory.decodeFile using the correct inSampleSize. 2) Compress the image in JPEG with a quality of 40% 3) Encode the image in base64 4) Sent to the server I cannot achieve the first step, it throws an out of memory exception. I'm sure the inSampleSize is correct but I suppose even with inSampleSize the Bitmap is huge (around 30 MB in DDMS). Any ideas how can do it? Can I do these steps without created a bitmap object? I mean doing it on filesystem instead of RAM memory. This is the current code: // The following function calculate the correct inSampleSize Bitmap image = Util.decodeSampledBitmapFromFile(imagePath, width,height); // compressing the image ByteArrayOutputStream baos = new ByteArrayOutputStream(); image.compress(Bitmap.CompressFormat.JPEG, 40, baos); // encode image String encodedImage = Base64.encodeToString(baos.toByteArray(),Base64.DEFAULT));

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  • How to set message when I get Exception

    - by user1748932
    public class XMLParser { // constructor public XMLParser() { } public String getXmlFromUrl(String url) { String responseBody = null; getset d1 = new getset(); String d = d1.getData(); // text String y = d1.getYear(); // year String c = d1.getCircular(); String p = d1.getPage(); List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(); nameValuePairs.add(new BasicNameValuePair("YearID", y)); nameValuePairs.add(new BasicNameValuePair("CircularNo", c)); nameValuePairs.add(new BasicNameValuePair("SearchText", d)); nameValuePairs.add(new BasicNameValuePair("pagenumber", p)); try { HttpClient httpclient = new DefaultHttpClient(); HttpPost httppost = new HttpPost(url); httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); HttpResponse response = httpclient.execute(httppost); HttpEntity entity = response.getEntity(); responseBody = EntityUtils.toString(entity); } catch (UnsupportedEncodingException e) { e.printStackTrace(); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } // return XML return responseBody; } public Document getDomElement(String xml) { Document doc = null; DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); try { DocumentBuilder db = dbf.newDocumentBuilder(); InputSource is = new InputSource(); is.setCharacterStream(new StringReader(xml)); doc = db.parse(is); } catch (ParserConfigurationException e) { Log.e("Error: ", e.getMessage()); return null; } catch (SAXException e) { Log.e("Error: ", e.getMessage()); // i m getting Exception here return null; } catch (IOException e) { Log.e("Error: ", e.getMessage()); return null; } return doc; } /** * Getting node value * * @param elem * element */ public final String getElementValue(Node elem) { Node child; if (elem != null) { if (elem.hasChildNodes()) { for (child = elem.getFirstChild(); child != null; child = child .getNextSibling()) { if (child.getNodeType() == Node.TEXT_NODE) { return child.getNodeValue(); } } } } return ""; } /** * Getting node value * * @param Element * node * @param key * string * */ public String getValue(Element item, String str) { NodeList n = item.getElementsByTagName(str); return this.getElementValue(n.item(0)); } } I am getting Exception in this class for parsing data. I want print this message in another class which extends from Activity. Can you please tell me how? I tried much but not able to do.. public class AndroidXMLParsingActivity extends Activity { public int currentPage = 1; public ListView lisView1; static final String KEY_ITEM = "docdetails"; static final String KEY_NAME = "heading"; public Button btnNext; public Button btnPre; public static String url = "http://dev.taxmann.com/TaxmannService/TaxmannService.asmx/GetNotificationList"; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); // listView1 lisView1 = (ListView) findViewById(R.id.listView1); // Next btnNext = (Button) findViewById(R.id.btnNext); // Perform action on click btnNext.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { currentPage = currentPage + 1; ShowData(); } }); // Previous btnPre = (Button) findViewById(R.id.btnPre); // Perform action on click btnPre.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { currentPage = currentPage - 1; ShowData(); } }); ShowData(); } public void ShowData() { XMLParser parser = new XMLParser(); String xml = parser.getXmlFromUrl(url); // getting XML Document doc = parser.getDomElement(xml); // getting DOM element NodeList nl = doc.getElementsByTagName(KEY_ITEM); int displayPerPage = 5; // Per Page int TotalRows = nl.getLength(); int indexRowStart = ((displayPerPage * currentPage) - displayPerPage); int TotalPage = 0; if (TotalRows <= displayPerPage) { TotalPage = 1; } else if ((TotalRows % displayPerPage) == 0) { TotalPage = (TotalRows / displayPerPage); } else { TotalPage = (TotalRows / displayPerPage) + 1; // 7 TotalPage = (int) TotalPage; // 7 } int indexRowEnd = displayPerPage * currentPage; // 5 if (indexRowEnd > TotalRows) { indexRowEnd = TotalRows; } // Disabled Button Next if (currentPage >= TotalPage) { btnNext.setEnabled(false); } else { btnNext.setEnabled(true); } // Disabled Button Previos if (currentPage <= 1) { btnPre.setEnabled(false); } else { btnPre.setEnabled(true); } // Load Data from Index int RowID = 1; ArrayList<HashMap<String, String>> menuItems = new ArrayList<HashMap<String, String>>(); HashMap<String, String> map; // RowID if (currentPage > 1) { RowID = (displayPerPage * (currentPage - 1)) + 1; } for (int i = indexRowStart; i < indexRowEnd; i++) { Element e = (Element) nl.item(i); // adding each child node to HashMap key => value map = new HashMap<String, String>(); map.put("RowID", String.valueOf(RowID)); map.put(KEY_NAME, parser.getValue(e, KEY_NAME)); // adding HashList to ArrayList menuItems.add(map); RowID = RowID + 1; } SimpleAdapter sAdap; sAdap = new SimpleAdapter(AndroidXMLParsingActivity.this, menuItems, R.layout.list_item, new String[] { "RowID", KEY_NAME }, new int[] { R.id.ColRowID, R.id.ColName }); lisView1.setAdapter(sAdap); } } This my class where I want to Print that message

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  • Functioning of Intent.action_pick_activity??

    - by chris
    Hello everybody!! Here is I would like to set up in my application, the function of sharing (facebook, twitter, e-mail) as that of YouTube for example but I get lost little. By looking I saw that apparently it would be necessary to use Intent.action_pick_activity but I do not manage to see how using it on my case. What is that somebody has already implemented this kind of thing? Either what is what somebody knows where I can find examples?? Thanks to all!

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  • How to customize preferences screen theme to look like that ?

    - by Alex
    Ok, I have a Preferences activity set with an XML layout. Here I have a couple of Preferences that open some dialogs. On these preferences I want to have an arrow on the right of them like in the screenshot. How I do this, is something related to the theme ? First screenshot is how I want to look, second is what I have now. http://img545.imageshack.us/i/screenshot1zlk.png/ http://img405.imageshack.us/i/tsc3.png/

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  • Issues with start activity for result

    - by rodkarom
    I have written an Activity using Theme.Holo.Dialog so that it works as an AlertDialog as a login/password notice. I've started this activity with startActivityForResult(...) using a request code I defined. The thing is, whenever I start the activity ´onActivityResult(...)´ is triggered immediately, the buttons get loaded and everything, but once I press them, even though I know the Activity is working because login does happen, there is no result sent back to the first Activity and I am calling setResult(...) and finish() after the buttons are pressed. Thanks in advance, first time using startActivityForResult so I'm sure I must be missing something.

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  • troubles reading other apps config files

    - by Aivlis
    Hi guys, I have a problem. I have to access to the data folder of other applications from my application to read configuration's file and so on but it seems it's possible only to read data from the sdcard and my application's data folder. Can you suggest me how to solve this problem?

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  • how can I enter character "<" in strings.xml?

    - by yrajabi
    I want to enter string " -< " in strings.xml file, the string has character < and I couldn't add it to xml file without error! I even tried to escaping by \ character: <string name="search_target_arrow"> -\< </string> or enclosing it between "" as below: <string name="search_target_arrow">" -< "</string> but none worked. Maybe I'm very amateur at this and the answer is not hard for you. so please tell me how you add such special chars in strings.xml?

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