How to grep curl -I header information
- by Mint
Im trying to get the redirect link from a site by using curl -I then grep to "location" and then sed out the location text so that I am left with the URL.
But this doesn't work, it will outputs the URL to screen and doesn't put it
test=$(curl -I "http://www.redirectURL.com/" 2> /dev/null | grep "location" | sed -E 's/location:[ ]+//g')
echo "1..$test..2"
Which then outputs:
..2http://www.newURLfromRedirect.com/bla
Whats going on?
