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  • JQuery: How to AutoComplete "City, State" ?

    - by NickT
    Question: How can you use the JQuery Auto-Completion plugin to suggest a location ("City, State") for an input field? Meaning, someone wants to type in "Chicago, IL" ... so they begin typing "Chi" and it auto-suggestions "Chicago, IL". My biggest hurdles is finding a service that I can query to find out all US city+state names. I essentially want to do what the StackOverflow "Tags" input form works but form "City, State" auto completion.

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  • XSLT, JSTL e JSF

    - by Paulo S.
    I have a xml file which I want to transform in a jsf code page. To do that I've created a xsl file. xml: <?xml version='1.0' encoding='ISO-8859-1'?> <questionario xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance' xsi:noNamespaceSchemaLocation='Schema2.xsd'> <componente nome='input'> <id>input1</id> </componente> <componente nome='input'> <id>input2</id> </componente> </questionario> code: <%@ taglib uri="http://java.sun.com/jstl/core_rt" prefix="c" %> <%@ taglib uri="http://java.sun.com/jsp/jstl/xml" prefix="x" %> <c:set var="xml" value="${questionarioXSLBean.xml}"/> <c:set var="xsl"> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0" xmlns:f="http://java.sun.com/jsf/core" xmlns:h="http://java.sun.com/jsf/html" exclude-result-prefixes="f h"> <xsl:template match="/"> <xsl:for-each select="questionario/componente"> <xsl:if test="attribute::nome = 'input'"> <xsl:variable name="id"> <xsl:value-of select="id" /> </xsl:variable> <h:inputText id="{$id}"/> </xsl:if> </xsl:for-each> </xsl:template> </xsl:stylesheet> </c:set> <x:transform xml="${xml}" xslt="${xsl}" /> The problem is that nothing is shown in my screen because the generated code for <h:inputText id="input1"/> is <h:inputText id="input_1" xmlns:h="http://java.sun.com/jsf/html"/> how can I replace the xmlns:h="http://java.sun.com/jsf/html" or suppress it. Thanks! Update: Let me clarify what I want to do. I want to generate a jsf page dynamically depending on the attributes of a xml file, for instance, 2 input texts, 3 check boxes, etc. To make the transformation to jsf I thought in two approaches, one using jstl and another using xslt. The problem with the former is that I couldn't integrate jstl with jsf code (to set jsf components attributes using jstl variables) and with the last approach, I'm facing the problem described above.I wouldn't like to create components in java (UIComponents). Any suggestions?

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  • How to Get a Specific Column Value from a DataTable? - C#.NET Winforms

    - by peace
    I have a datatable. I need to fetch a certain column value based on the user input. For example, lets say the datatable has two columns CountryID and CountryName. I need to find CountryID in the datatable based on the user input country name. I could just open a connection with DB and run the query select countryID from Country where countryName = @userinput. Is there anyway i could do this on the datatable. Thanks

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  • Strange behaviour when posting CGEvent to PSN

    - by Ben Packard
    If I set up a loop that posts some keyboard events to a PSN, I find that it works fine except for when first launched. The event only seems to post when i do something with the mouse manually - even just moving it slightly. Here's the details, if they help. An external application has a list box of text lines, which I am reading by posting copy commands (and checking the pasteboard). Unfortunately this is my only way to get this text. Sometimes, the application pulls focus away from the list, which I can detect. When this happens, the most reliable way to return focus is by sending a mouse event to click on a text field directly above the list, then send a 'tab' keyboard event to shift the focus onto the list. So at launch, the loop runs fine, scrolling down the list and copying the text. When focus is shifted away, its is detected fine, and the events are sent to move focus back to the list. But nothing seems to happen. The loop continues detecting that focus has changed, but the events only work once I move the mouse. Or even just use the scroll wheel. Strange. Once this has happened the first time, it works fine - each time focus moves, the PSN events switch it back without me having to do anything at all. Here's the code that runs in the loop - verified as working: //copy to pasteboard - CMD-V e3 = CGEventCreateKeyboardEvent(NULL, (CGKeyCode)8, true); CGEventSetFlags(e3, kCGEventFlagMaskCommand); CGEventPostToPSN(&psn, e3); CFRelease(e3); e4 = CGEventCreateKeyboardEvent(NULL, (CGKeyCode)8, false); CGEventPostToPSN(&psn, e4); CFRelease(e4); //move cursor down e1 = CGEventCreateKeyboardEvent(NULL, (CGKeyCode)125, true); CGEventPostToPSN(&psn, e1); CFRelease(e1); e2 = CGEventCreateKeyboardEvent(NULL, (CGKeyCode)125, false); CGEventPostToPSN(&psn, e2); CFRelease(e2); And here's where I switch focus, also working (except when first required): //click in text input box - point is derived earlier e6 = CGEventCreateMouseEvent(NULL, kCGEventLeftMouseDown, point, 0); CGEventPostToPSN(&psn, e6); CFRelease(e6); e7 = CGEventCreateMouseEvent(NULL, kCGEventLeftMouseUp, point, 0); CGEventPostToPSN(&psn, e7); CFRelease(e7); //press tab key to move to chat log table CGEventRef e = CGEventCreateKeyboardEvent(NULL, (CGKeyCode)48, true); //CGEventPost(kCGSessionEventTap, e); CGEventPostToPSN(&psn, e); CFRelease(e); CGEventRef e11 = CGEventCreateKeyboardEvent(NULL, (CGKeyCode)48, false); CGEventPostToPSN(&psn, e11); CFRelease(e11);

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  • IE6 CSS tooltip not appearing

    - by Lauren
    I'm using a tooltip that works in FF, Chrome, and IE7-8, but in IE6 it doesn't appear. You can go to this page http://www.avaline.com/ Bags/ Eco-Friendly-Bags/R1500 and login with [email protected] password:test02, then hit the "add to cart" button and hover over the question marks to see (or not see) the tooltips. This is the relevant HTML and CSS: <DIV class=oewBox id=oewImpLocDiv style="BACKGROUND-IMAGE: url(/images/img/org4.gif)"> <A class=tooltip href="#"><SPAN class=""><STRONG>More than 2 imprint locations?</STRONG> Test </SPAN></A> </DIV> <style> /* Rule from element "style" attribute */ element.style { BACKGROUND-IMAGE: url(/images/img/org4.gif) } /* Rule N°8 from inline stylesheet */ .oewBox { PADDING-RIGHT: 8px; PADDING-LEFT: 40px; PADDING-BOTTOM: 16px; MARGIN: 0px 0px 6px; PADDING-TOP: 6px; BORDER-BOTTOM: #ff7c14 3px solid } /* Rule N°7 from inline stylesheet */ .oewBox { BACKGROUND-POSITION: 0px 0px; BACKGROUND-IMAGE: none; BACKGROUND-REPEAT: no-repeat } /* Rule N°11 from /site/av-files/mainstyles.css */ A:active { COLOR: #3b88c4; TEXT-DECORATION: none } /* Rule N°10 from /site/av-files/mainstyles.css */ A:hover { COLOR: #000; TEXT-DECORATION: none } /* Rule N°9 from /site/av-files/mainstyles.css */ A:visited { COLOR: #3b88c4; TEXT-DECORATION: underline } /* Rule N°8 from /site/av-files/mainstyles.css */ A:link { COLOR: #3b88c4; TEXT-DECORATION: underline } /* Rule N°7 from /site/av-files/mainstyles.css */ A { COLOR: #3b88c4; TEXT-DECORATION: underline } /* Rule N°52 from inline stylesheet */ A.tooltip { BACKGROUND: url(/images/img/question.gif) no-repeat; FLOAT: right; WIDTH: 19px; HEIGHT: 20px } /* Rule N°54 from inline stylesheet */ A.tooltip:hover SPAN { BORDER-RIGHT: #ff7c14 1px solid; BORDER-TOP: #ff7c14 1px solid; DISPLAY: inline; BACKGROUND: #ffffff; BORDER-LEFT: #ff7c14 1px solid; COLOR: #000; BORDER-BOTTOM: #ff7c14 1px solid; POSITION: absolute } /* Rule N°53 from inline stylesheet */ A.tooltip SPAN { PADDING-RIGHT: 3px; DISPLAY: none; PADDING-LEFT: 3px; FONT-WEIGHT: normal; FONT-SIZE: 11px; PADDING-BOTTOM: 2px; MARGIN-LEFT: -245px; WIDTH: 230px; PADDING-TOP: 2px } </style>

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  • Problem in Fetching Table contents when adding rows in same table

    - by jasmine
    Im trying to write a function for adding category: function addCategory() { $cname = mysql_fix_string($_POST['cname']); $kabst = mysql_fix_string($_POST['kabst']); $kselect = $_POST['kselect']; $kradio = $_POST['kradio']; $ksubmit = $_POST['ksubmit']; $id = $_POST['id']; if($ksubmit){ $query = "INSERT INTO category VALUES (' ', '{$cname}', '{$kabst}', {$kselect}, {$kradio}, ' ') "; $result = mysql_query($query); if ($result) { echo "ok"; } else{ echo $query ; } } $text .= '<div class="form"> <h2>ADD new category</h2> <form action="?page=addCategory" method="post"> <ul> <li><label>Category</label></li> <li><input name="cname" type="text" class="inp" /></li> <li><label>Description</label></li> <li><textarea name="kabst" cols="40" rows="10" class="inx"></textarea></li> <li>Published:</li> <li> <select name="kselect" class="ins"> <option value="1">Active</option> <option value="0">Passive</option> </select> </li> <li>Show in home page:</li> <li> <input type="radio" name="kradio" value="1" /> yes <input type="radio" name="kradio" value="0" /> no </li> <li>Subcategory of</li> <li> <select>'; while ($row = mysql_fetch_assoc(mysql_query("SELECT * FROM category"))){ $text .= '<option>'.$row['name'].'</option>'; } $text .= '</select> </li> <li><input name="ksubmit" type="submit" value="ekle" class="int"/></li> </ul> </form> '; return $text;} And the error: Fatal error: Maximum execution time of 30 seconds exceeded What is wrong in my function?

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  • Issues adding search to iPhone app

    - by Graeme
    Hi, Basically I'm trying to add a search function to my iPhone app, but I'm not having much luck at the moment. I've downloaded the Apple provided Table Search app, and have copied across the code to mine. It builds OK, but here's the problem. Unlike the Apple example, all my data is stored in an array, that is accessed by calling [ciParser.currentArray]. Any ideas on how to change the code to suit my needs? I'm getting an error "Terminating app due to uncaught exception 'NSRangeException', reason: '* -[NSCFArray objectAtIndex:]: index (0) beyond bounds (0)'" whenever I click on the search bar and the app exits. Below is the code in particular that the debugger highlights as being troublesome. Apparently this error means the database trying to be searched is empty, but I could be wrong. FYI my app downloads and parsers an RSS feed using a class which is referenced by ciParser - which in turn stores the downloaded content in an array that I need to search. // Customize the appearance of table view cells. - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *CellIdentifier = @"Cell"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier]; if (cell == nil) { cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier] autorelease]; } /* If the requesting table view is the search display controller's table view, configure the cell using the filtered content, otherwise use the main list. */ CurrentItem * nextCurrentItem=[ciParser.currentArray objectAtIndex:indexPath.row]; if (tableView == self.searchDisplayController.searchResultsTableView) { (Code which debugger points to as being wrong) nextCurrentItem = [self.filteredListContent objectAtIndex:indexPath.row]; } else { nextCurrentItem = [ciParser.currentArray objectAtIndex:indexPath.row]; } NSString*settingValue = [[NSUserDefaults standardUserDefaults]stringForKey:@"state"]; if ([settingValue isEqualToString:@"New South Wales"]) { cell.textLabel.text=nextCurrentItem.title; } else if ([settingValue isEqualToString:@"Western Australia"]) { cell.textLabel.text=@"The FESA does not provide any Current Incident reports."; } else if ([settingValue isEqualToString:@"Victoria"]) { cell.textLabel.text=nextCurrentItem.title; } else if ([settingValue isEqualToString:@"South Australia"]) { cell.textLabel.text=nextCurrentItem.title; } else if ([settingValue isEqualToString:@"Tasmania"]) { cell.textLabel.text=nextCurrentItem.title; } // Set up the cell... [cell setAccessoryType:UITableViewCellAccessoryDisclosureIndicator]; return cell; }

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  • Why eclipse + pydev print() output look strange with two strings?

    - by srisar
    hay all, I just did the following: a = input("give a word: ") b = input("give another word: ") c = a + " " + b print("result is", c) and get the output as follows: give a word: name give another word: word result is name word my question is why the output on pydev or eclipse console in two lines? i expected to output as follows: give a word: name give another word: word result is name word how and why this happens to me? on cmd its looking fine??!!

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  • Match Regex across newlines?

    - by Jörg Battermann
    I have a regex ( "(&lt;lof&lt;).*?(&gt;&gt;)" ) that works and matches perfectly on single line input. However, if the input contains newlines between the two () parts it does not match at all. What's the best way to ignore any newlines at all in that case?

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  • how to solve the errors of this program

    - by hussein abdullah
    include using std::cout; using std::cin; using std::endl; include void initialize(char[],int*); void input(const char[] ,int&); void print ( const char*,const int); void growOlder (const char [], int* ); bool comparePeople(const char* ,const int*,const char*,const int*); int main(){ char name1[25]; char name2[25]; int age1; int age2; initialize (name1,&age1); initialize (name2,&age2); print(name1,*age1); print(name2,*age2); input(name1,age1); input(name2,age2); print(&name1,&age1); print(&name2,&age2); growOlder(name2,age2); if(comparePeople(name1,&age1,name2,&age2)) cout<<"Both People have the same name and age "<<endl; return 0; } void input(const char name[],int &age) { cout<<"Enter a name :"; cinname ; cout<<"Enter an age:"; cin>>age; cout<<endl; } void initialize ( char name[],int *age) { name=""; age=0; } void print ( const char name[],const int age ) { cout<<"The Value stored in variable name is :" < void growOlder(const char name[],int *age) { cout<< name <<" has grown one year older\n\n"; *age++; } bool comparePeople (const char *name1,const int *age1, const char *name2,const int *age2) { return(age1==age2 &&strcmp(name1,name2)); }

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  • Code-Golf: Modulus Divide

    - by thyrgle
    Challenge: Without using the modulus divide operator provided already by your language, write a program that will take two integer inputs from a user and then displays the result of the first number modulus divided number by the second number. Example: Input of first number:2 Input of second number:2 Result:0 Who wins: In case you don't know how Code Golf the winner is the person who writes this program in the least amount of characters.

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  • did you know some good web site about 'iphone css layouts' ,and can you help me to improve my code..

    - by zjm1126
    i want to create a webpage on iphone , but i can't complete it in a simple way, this is my code: <!DOCTYPE html PUBLIC "-//WAPFORUM//DTD XHTML Mobile 1.0//EN" "http://www.wapforum.org/DTD/xhtml-mobile10.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" > <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <meta name="viewport" content="width=device-width,minimum-scale=1.0,maximum-scale=5.0,user-scalable=yes"> </head> <body onorientationchange="updateOrientation();" onload=updateOrientation()> <div id="a"> <input id='ab' type="button" value="button" /> </div> <div id=b style="display: none">sssadwq dwqdqw</div> <style type="text/css"> *{ margin:0; padding:0; } /* Reposition on orientation change */ body.landscape{ height: 268px; } body.landscape #a{ height:134px; line-height:134px; } body.landscape #b{ height:114px; width:470px; } body{ height: 416px; } #a{ line-height:208px; height:208px; text-align:center; } #b{ height:198px; width:310px; background:red; border:5px solid black; } </style> <script src="jquery-1.4.2.js" type="text/javascript"></script> <script type="text/javascript"> function updateOrientation() { var orientation = window.orientation; switch (orientation) { // If we're horizontal case 90: case -90: // Set orient to landscape $(document.body).addClass("landscape"); break; // If we're vertical default: // Set orient to portrait $(document.body).removeClass("landscape"); break; } } $('#ab').click(function(){ if($('#b').css('display')=='none')$('#b').css('display','block') else $('#b').css('display','none') }) </script> </body> </html> it use much more fixed number,this is not the best way ,i think the best way is to use the percentage more and more, can you do it fo me ,, thanks

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  • Problem writing HTML content to Word document in ASP.NET

    - by saran
    I am trying to export the HTML page contents to Word. My Html display page is: What is your favourite color? NA List the top three school ? one National two Devs three PS And a button for click event. The button click event will open MS word and paste the page contents in word. The word page contains the table property of html design page. It occurs only in Word 2003. But in word 2007 the word document contains the text with out table property. How can I remove this table property in word 2003. I am not able to add the snapshots. Else i will make you clear. I am designing the web page by aspx. I am exporting the web page content by the following code. protected void Button1_Click(object sender, EventArgs e) { Response.ContentEncoding = System.Text.Encoding.UTF7; System.Text.StringBuilder SB = new System.Text.StringBuilder(); System.IO.StringWriter SW = new System.IO.StringWriter(); System.Web.UI.HtmlTextWriter htmlTW = new System.Web.UI.HtmlTextWriter(SW); tbl.RenderControl(htmlTW); string strBody = "<html>" + "<body>" + "<div><b>" + htmlTW.InnerWriter.ToString() + "</b></div>" + "</body>" + "</html>"; Response.AppendHeader("Content-Type", "application/msword"); Response.AppendHeader("Content-disposition", "attachment; filename=" + fileName); Response.ContentEncoding = System.Text.Encoding.UTF7; string fileName1 = "C://Temp/Excel" + DateTime.Now.Millisecond.ToString(); BinaryWriter writer = new BinaryWriter(File.Open(fileName1, FileMode.Create)); writer.Write(strBody); writer.Close(); FileStream fs = new FileStream(fileName1, FileMode.Open, FileAccess.Read); byte[] renderedBytes; // Create a byte array of file stream length renderedBytes = new byte[fs.Length]; //Read block of bytes from stream into the byte array fs.Read(renderedBytes, 0, System.Convert.ToInt32(fs.Length)); //Close the File Stream fs.Close(); FileInfo TheFile = new FileInfo(fileName1); if (TheFile.Exists) { File.Delete(fileName1); } Response.BinaryWrite(renderedBytes); Response.Flush(); Response.End(); }

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  • How do I use an Entity Framework 4 model without a real database?

    - by Ivan
    I don't need any data to be stored. I'd like an application to start, create an Entity Framework entities container based on the model I've designed but having no data records in it, then generate some data (from user input and other input sources), work with it and discard all the data on close, without propagating any data operations made with EF contect to a real database hosted on server or in a file. How do I implement such a pattern? I use Entity Framework 4 and Visual Studio 2010.

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  • How to access string[] in xhtml page

    - by Kalpana
    I am having a simple string array in my bean as public String[] colors = new String[]{"red", "blue", "green"}; and trying to display these colors from my xhtml as but I am getting a java.lang.NumberFormatException: For input string: "colors" java.lang.NumberFormatException: For input string: "colors" at java.lang.NumberFormatException.forInputString(NumberFormatException. java:48) at java.lang.Integer.parseInt(Integer.java:447) at java.lang.Integer.parseInt(Integer.java:497) at javax.el.ListELResolver.coerce(ListELResolver.java:166) at javax.el.ListELResolver.getValue(ListELResolver.java:51) at javax.el.CompositeELResolver.getValue(CompositeELResolver.java:54)

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  • Prolog - generate correct bracketing

    - by Henrik Bak
    I'd like to get some help in the following exam problem, i have no idea how to do this: Input: a list of numbers, eg.: [1,2,3,4] Output: every possible correct bracketing. Eg.: (in case of input [1,2,3,4]): ((1 2) (3 4)) ((1 (2 3)) 4) (1 ((2 3) 4)) (1 (2 (3 4))) (((1 2) 3) 4) Bracketing here is like a method with two arguments, for example multiplication - then the output is the possible multiplication orders. Please help, i'm stuck with this one. Any help is appreciated, thanks!

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  • Using a constructor for return.

    - by Fecal Brunch
    Hi, Just a quick question. I've written some code that returns a custom class Command, and the code I've written seems to work fine. I was wondering if there are any reasons that I shouldn't be doing it this way. It's something like this: Command Behavior::getCommand () { char input = 'x'; return Command (input, -1, -1); } Anyway, I read that constructors aren't meant to have a return value, but this works in g++. Thanks for any advice, Rhys

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  • How do display checked value in checkbox on Google plus style popup box?

    - by user946742
    After reading this post on Stackoverflow Google plus popup box when hovering over thumbnail? I was inspirted to add it on my site. I managed to do so and the script adds the contacts to my database. So far awesome! However, my problem (and also appears in the example) is it does not display the "checked" value... so the user will never know if they already added them to their list or not. Is the correct way to display checked values with PHP? Here is my html code: <ul style="list-style: none;padding:2px;"> <li style="padding:5px 2px;"> <input type="checkbox" id="Friends" name="circles" value="Friends" '.$checked1.'/> Friends </li> <li style="padding:5px 2px;"> <input type="checkbox" id="Following" name="circles" value="Following" '.$checked2.'/>Following </li> <li style="padding:5px 2px;"> <input type="checkbox" id="Family" name="circles" value="Family" '.$checked3.'/> Family </li> <li style="padding:5px 2px;"> <input type="checkbox" id="Acquaintances" name="circles" value="Acquaintances" '.$checked4.'/> Acquaintances </li> </ul> And my PHP code is: if($circle_check_friends>0) { $ckecked1='checked=""'; } else if ($circle_check_following>0) { $ckecked2='checked=""'; } else if ($circle_check_family>0) { $ckecked3='checked=""'; } else if ($circle_check_acquaintances>0) { $ckecked4='checked=""'; } else if ($circle_check_friends=0) { $ckecked1=''; } else if ($circle_check_following=0) { $ckecked2=''; } else if ($circle_check_family=0) { $ckecked3=''; } else if ($circle_check_acquaintances=0) { $ckecked4=''; } Im lost because this is not giving me the result I want... i.e. for the checked values to be displayed according to the users choice. Your help is highly appreciated Thank you all in advance George

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  • How to set header font style as bold for the header of the table in a pdf file, in jsf

    - by Radhika
    Hi I have used PdfPTable to convert table data into a pdf file using com.itextpdf.text.pdf.PdfPTable. Table is displaying, but table data and the header are in same style. To make difference i have to set the header font style to bold. can anybody help me out in this, I have attached my code here.. Thanks in advance import java.awt.Color; import java.util.ArrayList; import java.util.List; import javax.faces.model.ListDataModel; import com.mypackage.core.filter.domainobject.FilterResultDO; import com.itextpdf.text.Font; import com.itextpdf.text.FontFactory; import com.itextpdf.text.Phrase; import com.itextpdf.text.pdf.PdfPTable; public class PDFGenerator { //This method will generate PDF for Filter Result Screen (only DataTable level) @SuppressWarnings("unchecked") public static PdfPTable generatePDF(PdfPTable table,List filterResultDOList ,List filterResultHeaderList ) { //Initialize the table with number of columns required for the Datatable header int numberOfFilterLabelCols = filterResultHeaderList.size(); //PDF Table Frame table = new PdfPTable(numberOfFilterLabelCols); //Getting Filter Detail Table Heading for(int i = 0 ; i < numberOfFilterLabelCols; i++) { ColumnHeader commandHeaderObj = filterResultHeaderList.get(i); table.addCell(commandHeaderObj.getLabel()); } //Getting Filter Detail Data (Rows X Cols) FilterResultDO filterResultDOObj = filterResultDOList.get(0); List filterResultDataList = filterResultDOObj.getFilterResultLst(); int numberOfFilterDataRows = filterResultDataList.size(); //each row iteration for(int row = 0; row < numberOfFilterDataRows; row++) { List filterResultCols = filterResultDataList.get(row); int numberOfFilterDataCols = filterResultCols.size(); //columns iteration of each row for(int col = 0; col < numberOfFilterDataCols ; col++) { String filterColumnsValues = (String) filterResultCols.get(col); table.addCell(filterColumnsValues); } } return table; }//generatePDF }

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  • Executing Password Change over Ruby Net-SSH

    - by tesmar
    Hi all, I am looking to execute a password change over Net-ssh and this code seems to hang: Net::SSH.start(server_ip, "user", :verbose => :debug ) do |session| session.process.popen3("ls") do |input, output, error| ["old_pass","test", "test"].each do |x| input.puts x end end end I know the connection works because using a simple exec I can get the output from ls on the remote server, but this hangs. Any ideas? The last message from debug is that the public key succeeded.

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  • Reading POST data from html form sent to serversocket.

    - by user32167
    i try to write simplest possible server app in Java, displaying html form with textarea input, which after submitting gives me possibility to parse xml typed in that textarea. For now i build simple serversocket based server like that: import java.io.BufferedReader; import java.io.InputStreamReader; import java.io.PrintWriter; import java.net.ServerSocket; import java.net.Socket; public class WebServer { protected void start() { ServerSocket s; String gets = ""; System.out.println("Start on port 80"); try { // create the main server socket s = new ServerSocket(80); } catch (Exception e) { System.out.println("Error: " + e); return; } System.out.println("Waiting for connection"); for (;;) { try { // wait for a connection Socket remote = s.accept(); // remote is now the connected socket System.out.println("Connection, sending data."); BufferedReader in = new BufferedReader(new InputStreamReader( remote.getInputStream())); PrintWriter out = new PrintWriter(remote.getOutputStream()); String str = "."; while (!str.equals("")) { str = in.readLine(); if (str.contains("GET")){ gets = str; break; } } out.println("HTTP/1.0 200 OK"); out.println("Content-Type: text/html"); out.println(""); // Send the HTML page String method = "get"; out.print("<html><form method="+method+">"); out.print("<textarea name=we></textarea></br>"); out.print("<input type=text name=a><input type=submit></form></html>"); out.println(gets); out.flush(); remote.close(); } catch (Exception e) { System.out.println("Error: " + e); } } } public static void main(String args[]) { WebServer ws = new WebServer(); ws.start(); } } After form (textarea with xml and one additional text input) is submitted in 'gets' String-type variable I have Urlencoded values of my variables (also displayed on the screen, it looks like that: gets = GET /?we=%3Cnetwork+ip_addr%3D%2210.0.0.0%2F8%22+save_ip%3D%22true%22%3E%0D%0A%3Csubnet+interf_used%3D%22200%22+name%3D%22lan1%22+%2F%3E%0D%0A%3Csubnet+interf_used%3D%22254%22+name%3D%22lan2%22+%2F%3E%0D%0A%3C%2Fnetwork%3E&a=fooBar HTTP/1.1 What can i do to change GET to POST method (if i simply change it in form and than put " if (str.contains("POST")){" it gives me string like gets = POST / HTTP/1.1 with no variables. And after that, how i can use xml from my textarea field (called 'we')?

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  • Ruby: output not saved to file

    - by Sophie
    I'm trying to give a file as input, have it changed within the program, and save the result to a file that is output. But the output file is the same as the input file. :/ Total n00b question, but what am I doing wrong?: puts "Reading Celsius temperature value from data file..." num = File.read("temperature.dat") celsius = num.to_i farenheit = (celsius * 9/5) + 32 puts "Saving result to output file 'faren_temp.out'" fh = File.new("faren_temp.out", "w") fh.puts farenheit fh.close

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