Search Results

Search found 21501 results on 861 pages for 'slow connection'.

Page 538/861 | < Previous Page | 534 535 536 537 538 539 540 541 542 543 544 545  | Next Page >

  • How can I split mySQL query logs by database?

    - by barnaby
    I've been trying to implement a mySQL Proxy solution that can separate out the queries into per-database logs. Everything I've Googled has pointed to mySQL Proxy but I can only seem to capture the database a connection was opened to, not which the current query is being issued against. Is it even possible? Is there a different tool to use? Thanks for any suggestions.

    Read the article

  • Best way to return result from business layer to presentation layer when using LINQ-to-SQL

    - by samsur
    I have a business layer that has DTOs that are used in the presentation layer. This application uses entity framework. Here is an example of a class called RoleDTO: public class RoleDTO { public Guid RoleId { get; set; } public string RoleName { get; set; } public string RoleDescription { get; set; } public int? OrganizationId { get; set; } } In the BLL I want to have a method that returns a list of DTO. I would like to know which is the better approach: returning IQueryable or list of DTOs. Although I feel that returning IQueryable is not a good idea because the connection needs to be open. Here are the 2 different methods using the different approaches: First approach public class RoleBLL { private servicedeskEntities sde; public RoleBLL() { sde = new servicedeskEntities(); } public IQueryable<RoleDTO> GetAllRoles() { IQueryable<RoleDTO> role = from r in sde.Roles select new RoleDTO() { RoleId = r.RoleID, RoleName = r.RoleName, RoleDescription = r.RoleDescription, OrganizationId = r.OrganizationId }; return role; } Note: in the above method the DataContext is a private attribute and set in the constructor, so that the connection stays opened. Second approach public static List<RoleDTO> GetAllRoles() { List<RoleDTO> roleDTO = new List<RoleDTO>(); using (servicedeskEntities sde = new servicedeskEntities()) { var roles = from pri in sde.Roles select new { pri.RoleID, pri.RoleName, pri.RoleDescription }; //Add the role entites to the DTO list and return. This is necessary as anonymous types can be returned acrosss methods foreach (var item in roles) { RoleDTO roleItem = new RoleDTO(); roleItem.RoleId = item.RoleID; roleItem.RoleDescription = item.RoleDescription; roleItem.RoleName = item.RoleName; roleDTO.Add(roleItem); } return roleDTO; } } Please let me know, if there is a better approach.

    Read the article

  • SQL Invalid Object Name 'AddressType'

    - by salvationishere
    I am getting the above error in my VS 2008 C# method when I try to invoke the SQL getColumnNames stored procedure from VS. This SP accepts one input parameter, the table name, and works successfully from SSMS. Currently I am selecting the AdventureWorks AddressType table for it to pull the column names from this table. I can see teh AdventureWorks table available in VS from my Server Explorer / Data Connection. And I see both the AddressType table and getColumnNames SP showing in Server Explorer. But I am still getting this error listed above. Here is the C# code snippet I use to execute this: public static DataTable DisplayTableColumns(string tt) { SqlDataReader dr = null; string TableName = tt; string connString = "Data Source=.;AttachDbFilename=\"C:\Program Files\Microsoft SQL Server\MSSQL10.MSSQLSERVER\MSSQL\DATA\AdventureWorks_Data.mdf\";Initial Catalog=AdventureWorks;Integrated Security=True;Connect Timeout=30;User Instance=False"; string errorMsg; SqlConnection conn2 = new SqlConnection(connString); SqlCommand cmd = conn2.CreateCommand(); try { cmd.CommandText = "dbo.getColumnNames"; cmd.CommandType = CommandType.StoredProcedure; cmd.Connection = conn2; SqlParameter parm = new SqlParameter("@TableName", SqlDbType.VarChar); parm.Value = TableName; parm.Direction = ParameterDirection.Input; cmd.Parameters.Add(parm); conn2.Open(); dr = cmd.ExecuteReader(); } catch (Exception ex) { errorMsg = ex.Message; } And when I examine the errorMsg it says the following: " at System.Data.SqlClient.SqlConnection.OnError(SqlException exception, Boolean breakConnection)\r\n at System.Data.SqlClient.SqlInternalConnection.OnError(SqlException exception, Boolean breakConnection)\r\n at System.Data.SqlClient.TdsParser.ThrowExceptionAndWarning(TdsParserStateObject stateObj)\r\n at System.Data.SqlClient.TdsParser.Run(RunBehavior runBehavior, SqlCommand cmdHandler, SqlDataReader dataStream, BulkCopySimpleResultSet bulkCopyHandler, TdsParserStateObject stateObj)\r\n at System.Data.SqlClient.SqlDataReader.ConsumeMetaData()\r\n at System.Data.SqlClient.SqlDataReader.get_MetaData()\r\n at System.Data.SqlClient.SqlCommand.FinishExecuteReader(SqlDataReader ds, RunBehavior runBehavior, String resetOptionsString)\r\n at System.Data.SqlClient.SqlCommand.RunExecuteReaderTds(CommandBehavior cmdBehavior, RunBehavior runBehavior, Boolean returnStream, Boolean async)\r\n at System.Data.SqlClient.SqlCommand.RunExecuteReader(CommandBehavior cmdBehavior, RunBehavior runBehavior, Boolean returnStream, String method, DbAsyncResult result)\r\n at System.Data.SqlClient.SqlCommand.RunExecuteReader(CommandBehavior cmdBehavior, RunBehavior runBehavior, Boolean returnStream, String method)\r\n at System.Data.SqlClient.SqlCommand.ExecuteReader(CommandBehavior behavior, String method)\r\n at System.Data.SqlClient.SqlCommand.ExecuteReader()\r\n at ADONET_namespace.ADONET_methods.DisplayTableColumns(String tt) in C:\Documents and Settings\Admin\My Documents\Visual Studio 2008\Projects\AddFileToSQL\AddFileToSQL\ADONET methods.cs:line 35" Where line 35 is dr = cmd.ExecuteReader();

    Read the article

  • Invalid authorization specification error with Classic ASP accessing MSSQL DB

    - by Scott
    Hi, I am getting the following error: Invalid authorization specification I've narrowed down the error to my connection string. I have verified the server name, database, user & password are correct. Here is the string: "Provider=SQLOLEDB;Server=xxxxx.db.12345.hostedresource.com;Database=foo;UID=fooUser;PWD=fooPW" The SQL server is hosted on Godaddy so I don't have access to its settings. Please help, I've scoured the internet for a solution!

    Read the article

  • Default MVC Web Application Database

    - by wows
    When setting up a new ASP.NET MVC Web Application, the default connection string inside Web.Config is something like this: connectionString="data source=.\SQLEXPRESS;Integrated Security=SSPI;AttachDBFilename=|DataDirectory|aspnetdb.mdf;User Instance=true" I'm just wanting to play around with logging in and registering, etc but when I run the app it obviously can't find a SQL database. What database with what tables do I need to setup to do this? I have SQL Server 2005 Standard installed on my system, is that enough? Thanks.

    Read the article

  • iphone sqlite app startup issues

    - by Futur
    Hi All, I have 4 database catalogues in my app, i will be switching the four catalogues. When i start the app, i read the NSUserDefaults and try to load the default catalogue in the memory, but in the first time this doesnt happen. Instead i get null values returned first time just because the DB connection is not successful for some unknown reason, the debugger is unable to go there too. But the app starts up the next time, the values are fetched successfully. Please help

    Read the article

  • QueryTables error

    - by ktm5124
    I have the following VBA code inside an Excel macro: With ActiveSheet.QueryTables.Add( _ Connection:=ConnStr, _ Destination:=ActiveSheet.Range("A1"), _ Sql:=SqlStr) .Refresh End With And yet I am getting the error: "Run-time error '1004': Application-defined or object-defined error." The debugger points to this code as the source of error. Assuming that my ConnStr and SqlStr are correct, why am I getting this error? I am using Excel 2007 and I am querying an Oracle database.

    Read the article

  • .NET datetime issue with SQL stored procedure

    - by DanO
    I am getting the below error when executing my application on a Windows XP machine with .NET 2.0 installed. On my computer Windows 7 .NET 2.0 - 3.5 I am not having any issues. The target SQL server version is 2005. This error started occurring when I added the datetime to the stored procedure. I have been reading alot about using .NET datetime with SQL datetime and I still have not figured this out. If someone can point me in the right direction I would appreciate it. Here is the where I believe the error is coming from. private static void InsertRecon(string computerName, int EncryptState, TimeSpan FindTime, Int64 EncryptSize, DateTime timeWritten) { SqlConnection DBC = new SqlConnection("server=server;UID=InventoryServer;Password=pass;database=Inventory;connection timeout=30"); SqlCommand CMD = new SqlCommand(); try { CMD.Connection = DBC; CMD.CommandType = CommandType.StoredProcedure; CMD.CommandText = "InsertReconData"; CMD.Parameters.Add("@CNAME", SqlDbType.NVarChar); CMD.Parameters.Add("@ENCRYPTEXIST", SqlDbType.Int); CMD.Parameters.Add("@RUNTIME", SqlDbType.Time); CMD.Parameters.Add("@ENCRYPTSIZE", SqlDbType.BigInt); CMD.Parameters.Add("@TIMEWRITTEN", SqlDbType.DateTime); CMD.Parameters["@CNAME"].Value = computerName; CMD.Parameters["@ENCRYPTEXIST"].Value = EncryptState; CMD.Parameters["@RUNTIME"].Value = FindTime; CMD.Parameters["@ENCRYPTSIZE"].Value = EncryptSize; CMD.Parameters["@TIMEWRITTEN"].Value = timeWritten; DBC.Open(); CMD.ExecuteNonQuery(); } catch (System.Data.SqlClient.SqlException e) { PostMessage(e.Message); } finally { DBC.Close(); CMD.Dispose(); DBC.Dispose(); } } Unhandled Exception: System.ArgumentOutOfRangeException: The SqlDbType enumeration value, 32, is invalid. Parameter name: SqlDbType at System.Data.SqlClient.MetaType.GetMetaTypeFromSqlDbType(SqlDbType target) at System.Data.SqlClient.SqlParameter.set_SqlDbType(SqlDbType value) at System.Data.SqlClient.SqlParameter..ctor(String parameterName, SqlDbType dbType) at System.Data.SqlClient.SqlParameterCollection.Add(String parameterName, SqlDbType sqlDbType) at ReconHelper.getFilesInfo.InsertRecon(String computerName, Int32 EncryptState, TimeSpan FindTime, Int64 EncryptSize, DateTime timeWritten) at ReconHelper.getFilesInfo.Main(String[] args)

    Read the article

  • How to connect laptop with telephone using WI-FI? (ethernet)

    - by rmaster
    What I did: 1)added new wireless network in wireless network settings and gave it SSID 2)gave laptop the IP like 192.168.0.1, mask: 255.255.255.0, gateway: 192.168.0.2 3)gave the telephone with wifi the same mask but IP and gateway rewersed But telephone can not find my new wireless network(it can find all other networks), computer also can not find it. where is error? how to make it visible and working? if my steps are wrong tell me correct way to establish this connection via wi-fi

    Read the article

  • I cnn't use Database in SQL Azure!

    - by Nahid
    Hi, I am trying to use a Database in SQL AZURE. I have installed SQL Server 2008. I can Login SQL Azure and can use master Database. But I can't use other Database and I can't see any things in my object explorer. Its Show Error: "USE statement is not supported to switch between databases. Use a new connection to connect to a different Database." How can I use other database?

    Read the article

  • I have problems with adding rows to data-binded DataGridView in desktop app.

    - by Mishko
    DataTable table1 = new DataTable(); double brutoUkupno1 = 0; double porezUkupno1 = 0; double doprinosUkupno1 = 0; double netoUkupno1 = 0; double doprinosTeretUkupno1 = 0; double topliObrokUkupno1 = 0; double regresUkupno1 = 0; Connection con = new Connection(); table1 = con.boundTable(month, Convert.ToInt32(year)); //This is method which returns DataTable table1.Rows.Add(null, null, null, null, null, null, null, null, null, null, null, null, null, null); table1.Rows.Add(null, null, null, null, null, null, null, null, null, null, null, null, null, null); dgv2.Visible = true; dgv2.DataSource = table1; for (int i = 0; i < dgv2.RowCount - 2; i++) { topliObrokUkupno1 += Convert.ToDouble(dgv2.Rows[i].Cells[7].Value); regresUkupno1 += Convert.ToDouble(dgv2.Rows[i].Cells[8].Value); brutoUkupno1 += Convert.ToDouble(dgv2.Rows[i].Cells[9].Value); porezUkupno1 += Convert.ToDouble(dgv2.Rows[i].Cells[10].Value); doprinosUkupno1 += Convert.ToDouble(dgv2.Rows[i].Cells[11].Value); netoUkupno1 += Convert.ToDouble(dgv2.Rows[i].Cells[12].Value); doprinosTeretUkupno1 += Convert.ToDouble(dgv2.Rows[i].Cells[13].Value); //Now I am having problems with this below, putting things above to dgv2 : } dgv2.Rows[dgv2.Rows.Count - 1].Cells[0].Value = "Ukupno"; dgv2.Rows[dgv2.Rows.Count - 1].Cells[3].Value = month.ToString(); dgv2.Rows[dgv2.Rows.Count - 1].Cells[4].Value = year.ToString(); dgv2.Rows[dgv2.Rows.Count - 1].Cells[7].Value = topliObrokUkupno1.ToString(); dgv2.Rows[dgv2.Rows.Count - 1].Cells[8].Value = regresUkupno1.ToString(); dgv2.Rows[dgv2.Rows.Count - 1].Cells[9].Value = brutoUkupno1.ToString(); dgv2.Rows[dgv2.Rows.Count - 1].Cells[10].Value = porezUkupno1.ToString(); dgv2.Rows[dgv2.Rows.Count - 1].Cells[11].Value = doprinosUkupno1.ToString(); dgv2.Rows[dgv2.Rows.Count - 1].Cells[12].Value = netoUkupno1.ToString(); dgv2.Rows[dgv2.Rows.Count - 1].Cells[13].Value = doprinosTeretUkupno1.ToString(); dgv2.Rows[dgv2.RowCount - 2].Height = 3; dgv2.Rows[dgv2.RowCount - 2].DefaultCellStyle.BackColor = Color.Black;

    Read the article

  • cannot access sql server after publishing site in iis7

    - by vinu
    I am created a website using visual studio 2010. On the time of the development of website I am able to access the database.. but after publishing the site using IIS7..i was unable to access the database..the exception occured during that time was "the connection is in the closed state".in IIS7 When I changed the application pool identity to localsystem, it worked. Data base is installed in the same machine. and server is SQL SERVER 2008 R2

    Read the article

  • Add subview to another view

    - by Martol1ni
    With two ViewControllers, MyView 1 and MyView 2, is there possible to add a subview to MyView2 from MyView1.m? I have tried: MyView2 * screen = [[MyView2 alloc]initWithNibName:nil bundle:nil]; [screen.view addSubView:mySubView]; But my new instance of MyView 2 has no connection to the 'visible' ViewController on MyView2, right? To clarify, the ViewController that is showing, is MyView1. I want MyView1 to be able to add a subview to the MyView2 view. Thanks

    Read the article

  • PHP syntax error “unexpected $end”

    - by Jacksta
    I have 3 files 1) show_createtable.html 2) do_showfielddef.php 3) do_showtble.php 1) First file is for creating a new table for a data base, it is a fom with 2 inputs, Table Name and Number of Fields. THIS WORKS FINE! <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <h1>Step 1: Name and Number</h1> <form method="post" action="do_showfielddef.php" /> <p><strong>Table Name:</strong><br /> <input type="text" name="table_name" size="30" /></p> <p><strong>Number of fields:</strong><br /> <input type="text" name="num_fields" size="30" /></p> <p><input type="submit" name="submit" value="go to step2" /></p> </form> </body> </html> 2) this script validates fields and createa another form to enter all the table rows. This for also WORKS FINE! <?php //validate important input if ((!$_POST[table_name]) || (!$_POST[num_fields])) { header( "location: show_createtable.html"); exit; } //begin creating form for display $form_block = " <form action=\"do_createtable.php\" method=\"post\"> <input name=\"table_name\" type=\"hidden\" value=\"$_POST[table_name]\"> <table cellspacing=\"5\" cellpadding=\"5\"> <tr> <th>Field Name</th><th>Field Type</th><th>Table Length</th> </tr>"; //count from 0 until you reach the number fo fields for ($i = 0; $i <$_POST[num_fields]; $i++) { $form_block .=" <tr> <td align=center><input type=\"texr\" name=\"field name[]\" size=\"30\"></td> <td align=center> <select name=\"field_type[]\"> <option value=\"char\">char</option> <option value=\"date\">date</option> <option value=\"float\">float</option> <option value=\"int\">int</option> <option value=\"text\">text</option> <option value=\"varchar\">varchar</option> </select> </td> <td align=center><input type=\"text\" name=\"field_length[]\" size=\"5\"> </td> </tr>"; } //finish up the form $form_block .= " <tr> <td align=center colspan=3><input type =\"submit\" value=\"create table\"> </td> </tr> </table> </form>"; ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create a database table: Step 2</title> </head> <body> <h1>defnie fields for <? echo "$_POST[table_name]"; ?> </h1> <? echo "$form_block"; ?> </body> </html> Problem is here 3) this form creates the tables and enteres them into the database. I am getting an error on line 37 "Parse error: syntax error, unexpected $end in /home/admin/domains/domaina.com.au/public_html/do_createtable.php on line 37" <? $db_name = "testDB"; $connection = @mysql_connect("localhost", "admin_user", "pass") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $sql = "CREATE TABLE $_POST[table_name]("; for ($i = 0; $i < count($_POST[field_name]); $i++) { $sql .= $_POST[field_name][$i]." ".$_POST[field_type][$i]; if ($_POST[field_length][$i] !="") { $sql .=" (".$_POST[field_length][$i]."),"; } else { $sql .=","; } $sql = substr($sql, 0, -1); $sql .= ")"; $result = mysql_query($sql, $connection) or die(mysql_error()); if ($result) { $msg = "<p>" .$_POST[table_name]." has been created!</p>"; ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create A Database Table: Step 3</title> </head> <body> <h1>Adding table to <? echo "$db_name"; ?>...</h1> <? echo "$msg"; ?> </body> </html>

    Read the article

  • Script to create a table and fields in SQL wont work

    - by Jacksta
    Warning this is lenghty! attack if you knowledagble. well at least more then a newb beginner like me. This script uses three files as detailed below. It is suppoed to create the database and fields from the form input. It gets to the end and shows my_contacts has been created!. But when i go into phpMyadmin the table has not been created. I have a file named show_createtable.html which is used to create a table in MySQL <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <h1>Step 1: Name and Number</h1> <form method="post" action="do_showfielddef.php" /> <p><strong>Table Name:</strong><br /> <input type="text" name="table_name" size="30" /></p> <p><strong>Number of fields:</strong><br /> <input type="text" name="num_fields" size="30" /></p> <p><input type="submit" name="submit" value="go to step2" /></p> </form> </body> </html> This Form Posts to do_showfielddef.php <?php //validate important input if ((!$_POST[table_name]) || (!$_POST[num_fields])) { header( "location: show_createtable.html"); exit; } //begin creating form for display $form_block = " <form action=\"do_createtable.php\" method=\"post\"> <input name=\"table_name\" type=\"hidden\" value=\"$_POST[table_name]\"> <table cellspacing=\"5\" cellpadding=\"5\"> <tr> <th>Field Name</th><th>Field Type</th><th>Table Length</th><th>Primary Key?</th><th>Auto-Increment?</th> </tr>"; //count from 0 until you reach the number fo fields for ($i = 0; $i <$_POST[num_fields]; $i++) { $form_block .=" <tr> <td align=center><input type=\"texr\" name=\"field name[]\" size=\"30\"></td> <td align=center> <select name=\"field_type[]\"> <option value=\"char\">char</option> <option value=\"date\">date</option> <option value=\"float\">float</option> <option value=\"int\">int</option> <option value=\"text\">text</option> <option value=\"varchar\">varchar</option> </select> </td> <td align=center><input type=\"text\" name=\"field_length[]\" size=\"5\"></td> <td aligh=center><input type=\"checkbox\" name=\"primary[]\" value=\"Y\"></td> <td aligh=center><input type=\"checkbox\" name=\"auto_increment[]\" value=\"Y\"></td> </tr>"; } //finish up the form $form_block .= " <tr> <td align=center colspan=3><input type =\"submit\" value=\"create table\"> </td> </tr> </table> </form>"; ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create a database table: Step 2</title> </head> <body> <h1>defnie fields for <? echo "$_POST[table_name]"; ?> </h1> <? echo "$form_block"; ?> </body> </html> Which in turn creates the table and fields with this file do_showfielddef.php //connect to database $connection = @mysql_connect("localhost", "user", "pass") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); //start creating the SQL statement $sql = "CREATE TABLE $_POST[table_name]("; //continue the SQL statement for each new field for ($i = 0; $i < count($_POST[field_name]); $i++) { $sql .= $_POST[field_name][$i]." ".$_POST[field_type][$i]; if ($_POST[auto_increment][$i] =="Y") { $additional = "NOT NULL auto_increment"; } else { $additional = ""; } if ($_POST[primary][$i] =="Y") { $additional .= ", primary key (".$_POST[field_name][$i].")"; } else { $additional = ""; } if ($_POST[field_length][$i] !="") { $sql .= " (".$_POST[field_length][$i].") $additional ,"; } else { $sql .=" $additional ,"; } } //clean up the end of the string $sql = substr($sql, 0, -1); $sql .= ")"; //execute the query $result = mysql_query($sql, $connection) or die(mysql_error()); //get a giid message for display upon success if ($result) { $msg = "<p>" .$_POST[table_name]." has been created!</p>"; } ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create A Database Table: Step 3</title> </head> <body> <h1>Adding table to <? echo "$db_name"; ?>...</h1> <? echo "$msg"; ?> </body> </html>

    Read the article

  • Integration Services Throws an Error Reading Access 2007 Table

    - by Eric Flamm
    [Participant Table [1994]] Error: SSIS Error Code DTS_E_CANNOTACQUIRECONNECTIONFROMCONNECTIONMANAGER. The AcquireConnection method call to the connection manager "I:\My Documents\Flamm Consulting\Migrations.accdb" failed with error code 0xC0209303. There may be error messages posted before this with more information on why the AcquireConnection method call failed. Frankly, I'm confused about how SSIS should connect to Access 2007 - the UI just isn't very friendly - there's no file browser, for example. I'm wondering if there's something wrong with my install - missing drivers, etc.

    Read the article

  • Definition of Connect, Processing, Waiting in apache bench.

    - by rpatel
    When I run apache bench I get results like: Command: abs.exe -v 3 -n 10 -c 1 https://mysite Connection Times (ms) min mean[+/-sd] median max Connect: 203 213 8.1 219 219 Processing: 78 177 88.1 172 359 Waiting: 78 169 84.6 156 344 Total: 281 389 86.7 391 563 I can't seem to find the definition of Connect, Processing and Waiting. What do those numbers mean?

    Read the article

  • Read some content of a resource on internet

    - by Andreas Johannessen
    Hi For my iPhone application I need to read some content of a plain html file on the web. It's just some text within a pre-tag. However I don't want to download the whole file and then get the line I need. The format is: TextTextTextTextTextTextTextText TextTextTextTextTextTextTextText TextTextTextTextTextTextTextText TextTextTextTextTextTextTextText I only need the first line and then close the connection to that resource. Thanks in advance.

    Read the article

  • Unable to get project info and source control from a particular machine

    - by Gerard
    From one particular machine, accounts are unable to get tfs project info and source control via the visual studio tfs client. The connection with the tfs server is made but the project content remains empty. Web access is possible from this machine. Note: from all other machines everything works normally, so it must be a local machine issue. What might be misconfigured on this machine? Otherwise there seem to be no problems on this XP machine.

    Read the article

< Previous Page | 534 535 536 537 538 539 540 541 542 543 544 545  | Next Page >