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  • PHP getting blank pages after submit a form + signal Segmentation fault (11)

    - by Ole Media
    I few days ago I update my macbook pro to snow leopard, and since then some php files are not showing. This is what happens: I created a php form, when going to 'http://localhost/webform.php' I can see the form just fine. Then, once I submit the form, I just get a blank page. I enable error and warnings reporting under php.ini to make sure I'm not missing something, but still I'm not getting anything, just the blank page. Then I checked under apache log files, and what I notice is that every time I submit the form I see the following line coming up under the apache logs: [Wed Apr 07 21:40:28 2010] [notice] child pid 70223 exit signal Segmentation fault (11) I'm clueless on this one. Any ideas on how to fix it?

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  • Organize array in PHP from mysql

    - by Matthew Carter
    Hi i have a social networking website. what i want it to do is pull out my friends status updates. basically what it does is i have a mysql query that pulls out all of my friends and in that while loop there is another mysql query that pulls out the status's from my friends. i want it to be in order of date but since its one while loop in another what it does is pull out all status's from friend 1 then 2 then 3 and not in order by date. i even tried ORDER BY DATE but that just ordered it by date within the friend.. my thought is that i could putt it all in an array and friends is one thing and the values is the stats. then just sort by values would this work and how could i do it. THANKS SO MUCH

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  • INET_ATON() and INET_NTOA() in PHP?

    - by blerh
    I want to store IP addresses in my database, but I also need to use them throughout my application. I read about using INET_ATON() and INET_NTOA() in my MySQL queries to get a 32-bit unsigned integer out of an IP address, which is exactly what I want as it will make searching through the database faster than using char(15). The thing is, I can't find a function that does the same sort of thing in PHP. The only thing I came across is: http://php.net/manual/en/function.ip2long.php So I tested it: $ip = $_SERVER['REMOTE_ADDR']; echo ip2long($ip); And it outputs nothing. In the example they gave it seems to work, but then again I'm not exactly sure if ip2long() does the same thing as INET_ATON(). Does someone know a PHP function that will do this? Or even a completely new solution to storing an IP address in a database? Thanks.

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  • PHP database selection issue

    - by Citroenfris
    I'm in a bit of a pickle with freshening up my PHP a bit, it's been about 3 years since I last coded in PHP. Any insights are welcomed! I'll give you as much information as I possibly can to resolve this error so here goes! Files config.php database.php news.php BLnews.php index.php Includes config.php - news.php database.php - news.php news.php - BLnews.php BLnews.php - index.php Now the problem with my current code is that the database connection is being made but my database refuses to be selected. The query I have should work but due to my database not getting selected it's kind of annoying to get any data exchange going! database.php <?php class Database { //------------------------------------------- // Connects to the database //------------------------------------------- function connect() { if (isset($dbhost) && isset($dbuser) && isset($dbpass)) { $con = mysql_connect($dbhost, $dbuser, $dbpass) or die("Could not connect: " . mysql_error()); } }// end function connect function selectDB() { if (isset($dbname) && isset($con)) { $selected_db = mysql_select_db($dbname, $con) or die("Could not select test DB"); } } } // end class Database ?> News.php <?php // include the config file and database class include 'config.php'; include 'database.php'; ... ?> BLnews.php <?php // include the news class include 'news.php'; // create an instance of the Database class and call it $db $db = new Database; $db -> connect(); $db->selectDB(); class BLnews { function getNews() { $sql = "SELECT * FROM news"; if (isset($sql)) { $result = mysql_query($sql) or die("Could not execute query. Reason: " .mysql_error()); } return $result; } ?> index.php <?php ... include 'includes/BLnews.php'; $blNews = new BLnews(); $news = $blNews->getNews(); ?> ... <?php while($row = mysql_fetch_array($news)) { echo '<div class="post">'; echo '<h2><a href="#"> ' . $row["title"] .'</a></h2>'; echo '<p class="post-info">Posted by <a href="#"> </a> | <span class="date"> Posted on <a href="#">' . $row["date"] . '</a></span></p>'; echo $row["content"]; echo '</div>'; } ?> Well this is pretty much everything that should get the information going however due to the mysql_error in $result = mysql_query($sql) or die("Could not execute query. Reason: " .mysql_error()); I can see the error and it says: Could not execute query. Reason: No database selected I honestly have no idea why it would not work and I've been fiddling with it for quite some time now. Help is most welcomed and I thank you in advance! Greets Lemon

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  • MySQL insert at end of table

    - by Theopile
    Hello, I am using MySQL and PHP. I am having a problem with inserting a new item at the end of my table. When I insert the new item appears after the last created item, but I want it to be entered at the bottom of the table. Suppose that I have a table id=int,Primary Key and album=string and the table is: Wrath Crack The Skye Enter Shikari What would the MySQL query be if php variable $album=myAlbum was to be inserted next, at the end of the table, and with the appropriate id? Thanks

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  • Unix timestamp and mysql date: birthdate

    - by Mikk
    Hi, I have a really basic question concerning unix timestamp and mysql date. I'm trying to build a small website where users can register and fill in their birthdate. Problem is that unix starts with Jan 01 1970. Now if i calculate age for users, form dates like date('m.d.Y', $unix_from_db) and so on it will fail with users older that 40 years, right? So what would be the rigth way for doing this. Sorry, for basic question like this, but I'm inexperienced with php and mysql.

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  • PHP: MySQL query duplicating update for no reason

    - by ThinkingInBits
    The code below is first the client code, then the class file. For some reason the 'deductTokens()' method is calling twice, thus charging an account double. I've been programming all night, so I may just need a second pair of eyes: if ($action == 'place_order') { if ($_REQUEST['unlimited'] == 200) { $license = 'extended'; } else { $license = 'standard'; } if ($photograph->isValidPhotographSize($photograph_id, $_REQUEST['size_radio'])) { $token_cost = $photograph->getTokenCost($_REQUEST['size_radio'], $_REQUEST['unlimited']); $order = new ImageOrder($_SESSION['user']['id'], $_REQUEST['size_radio'], $license, $token_cost); $order->saveOrder(); $order->deductTokens(); header('location: account.php'); } else { die("Please go back and select a valid photograph size"); } } ######CLASS CODE####### <?php include_once('database_classes.php'); class Order { protected $account_id; protected $cost; protected $license; public function __construct($account_id, $license, $cost) { $this->account_id = $account_id; $this->cost = $cost; $this->license = $license; } } class ImageOrder extends Order { protected $size; public function __construct($account_id, $size, $license, $cost) { $this->size = $size; parent::__construct($account_id, $license, $cost); } public function saveOrder() { //$db = Connect::connect(); //$account_id = $db->real_escape_string($this->account_id); //$size = $db->real_escape_string($this->size); //$license = $db->real_escape_string($this->license); //$cost = $db->real_escape_string($this->cost); } public function deductTokens() { $db = Connect::connect(); $account_id = $db->real_escape_string($this->account_id); $cost = $db->real_escape_string($this->cost); $query = "UPDATE accounts set tokens=tokens-$cost WHERE id=$account_id"; $result = $db->query($query); } } ?> When I die("$query"); directly after the query, it's printing the proper statement, and when I run that query within MySQL it works perfectly.

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  • Question about Radio button/PHP/MySQL

    - by Marcelo
    Hi, I'm an engineering student and I'm developing a simple software based on HTML, PHP and mysql. I learned this topics on w3schools. I know only the basics. I tried to search about this in this website but I found questions about PHP, MySQL and HTML radio buttons which were much more complex than I need and that I could understand. Sorry for the English. (Q1) Ex: $email=$_REQUEST['email'] , in this case the input is text, if it where like a radio button for ex: sex: male or female, how would it be? (Q2) what would be the type of this field (for exemple sex in question 1) in the database: text, int, varchar ? Thanks for the attention

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  • MySQL IDE recommendation?

    - by Maxim Veksler
    Hello, I've been wondering what you guys are using to write,debug,test your SQL queries there days? The requirements are quite simple: Auto-complete Syntax Highlighting SQL Hisotry Good UI There are some tools which are common for this task, each with his own problems. To name a few Mysql Query Browser MySQL Workbench (GA?, Beta?) Eclipse Database development perspective Oracle SQL Developer with Connector/J I won't go into why none of them is perfect, trust me they all have their problems. So, what are you guys using?

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  • Selecting two field in MySQL with PHP

    - by Crays
    Hi guys, i'm relatively new to php and mysql and would like to know how to select two value in mysql with php. What i have is $query = sprintf("SELECT COUNT(id) FROM table WHERE UPPER(username) = UPPER('%s') AND password='%s'"... in this case, i'm only selecting and count if the id exist and i use list($count) = mysql_fetch_row($result); if($count == 1) and by using cookies, i would like to retrieve two value from the database, namely user (the user's name) and power (which has value of 1,2 or 3, indicating the menu they would be able to see) basically it is to differentiate if you're admin or normal user, but i wonder if i could do SELECT COUNT(id) AND power FROM table WHERE ... is this possible? or is there any other way? Please guide me, thanks.

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  • AJAX filter MySQL results using checkboxes

    - by keepitnang
    I'm attempting to get to grips with displaying filterable MySQL data within a PHP page based on user checkbox selections. I have a database of domain names and the dates on which these will require renewal as per Nominet DAC information and I can get unfiltered data to display, but filtering results by domain extensions is proving tricky for me to accomplish. I should point out at this stage that I am a serious newcomer to many of the ideas I am trying to learn to work with here, so please be gentle. I have tried following some other articles on here also, but no dice. I have the following so far: HTML <input type="checkbox" class="extensions" name="extensions" value=".co.uk">.co.uk</input> <input type="checkbox" class="extensions" name="extensions" value=".org.uk">.org.uk</input> Script $('.extensions').live('click', function() { var all_boxes = $('.extensions'); var all_boxes_values = []; var i = 0; for (var i; i < all_boxes.length; i++) { if (all_boxes[i].checked) { all_boxes_values.push(all_boxes[i].value) } } var all_boxes_values_clean = all_boxes_values.join(", "); console.log(all_boxes_values_clean); $.get("sql-test.php", {q: all_boxes_values_clean}, function(result) { $("div#output").html(result); } )}); PHP $g = $_GET['q']; $extensionsql=""; $extension=1; if(isset($g)) { $extension=1; $param = "" . str_replace(",", "','", $_GET['q']) . ""; } And that's as far as I have gotten with my limited ability. What I would like to do next is search the column domainName for a string match and return the appropriate results to the user. Something to mimic something like the following but I'm not sure how to achieve it. Any help would be much appreciated: SELECT * FROM `refresh` WHERE `domainName` LIKE '%.co.uk%' AND renewalDate LIKE '%2012-06-30%' ORDER BY `domainName` ASC Thanks

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  • Integrating Incoming Email Into a php/mysql App

    - by phirschybar
    I am looking to create an incoming email daemon switchboard that I can integrate with various remote php/mysql apps. Ideally I want to check the 'to' address to see if it is in a mysql database and if it is, have the email parsed and posted via CURL to a target destination as well as have attachments saved somewhere locally. I will likely set up a rackspace cloud server dedicated to this task (just accepting emails and posting to 3rd party APIs). However, I do not know where to start. Which server platform / distribution should I go with? Which software needs to be customized, etc?

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  • SQL Server instead of MYSQL in WAMP

    - by Vish
    Hi, We have an application which uses WAMP server. Now, there is a new requirement from a customer who wants to use MS SQL Server instead of MySQL. How easy is it to port to SQL Server from MySQL. Also it has to retain this configuration. Apache-PHP-SQL Server on windows. How can I connect from Apache to SQL Server. Hope PHP works well with SQL server. Please advise. Thanks, Vish

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  • MySQL Locks: order of unblocked threads

    - by teehoo
    I have a MySQL ISAM table being accessed my multiple php instances. Right now I'm using a WRITE lock to serialize access to this table. My question is how do I ensure that the PHP instances get served on a First-Come-First-Serve basis? Or is this the default behaviour? The official MySQL documentation doesn't mention anything about the blocked thread order for threads of the same lock type (ie multiple threads attempting a WRITE LOCK). It only mentions that a WRITER will jump to the front of the waiting queue if READERS are waiting.

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  • Mysql retrieve polygon data

    - by dskanth
    Hi, i have been developing a site that stores spatial data in mysql database, like that of buildings, gardens, etc. in the form of polygons (latitudes and longitudes). I want to know how to retrieve polygon data in mysql. I have seen this sample query to insert a polygon data: http://amper.110mb.com/SPAT/mysql_initgeometry2.htm But now i want to know how to retrieve data from the table, based on certain constraints like: "where latitude < 9.33 and longitude > 22.4" Also how do i find whether a point lies inside or outside of a polygon

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  • Beginner PHP: I can't insert data into MYSQL database

    - by Victor
    I'm learning PHP right now and I'm trying to insert data into a MySQL database called "pumpl2" The table is set up like this. create table product ( productid int unsigned not null auto_increment primary key, price int(9) not null, value int(9) not null, description text ); I have a form and want to insert the fields from the form in the database. Here is what the php file looks like. <?php // create short variable names $price = $_POST['price']; $value = $_POST['value']; $description = $_POST['description']; if (!$price || !$value || !$description) { echo "You have not entered all the required details.<br />" ."Please go back and try again."; exit; } @ $db = new mysqli('localhost', 'pumpl', '********', 'pumpl2'); if (mysqli_connect_errno()) { echo "Error: Could not connect to database. Please try again later."; exit; } $query = "insert into pumpl2 values ('".$price."', '".$value."', '".$description."')"; $result = $db->query($query); if ($result) { echo $db->affected_rows." product inserted into database."; } else { echo "An error has occurred. The item was not added."; } $db->close(); ?> When I submit the form, I get an error message "An error has occurred. The item was not added." Does anyone know what the problem is? Thank you!

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  • php database image show problem

    - by Termedi
    here is the code <?php session_start(); if(!isset($_SESSION['user_name'])) { header('Location: login.php'); } $conn = mysql_connect("localhost", "root", "") or die("Can no connect to Database Server"); ?> <html> <head> </head> <body> <center> <div id="ser"> <form action="" method="post"> <label for="file">Card No:</label> <input type="text" name="card_no" id="card_no" class="fil" onKeyUp="CardNoLength()" onKeyDown="CardNoLength()" onKeyPress="CardNoLength()"/> <input type="submit" name="search" value="Search" class="btn" onClick="return CardNoLengthMIN()"/> </form> </div> </center> <br/><hr style="border: 1px solid #606060 ;" /> <center><a href="index.php">Home</a></center> <br/> <center> <?php if(isset($_POST['card_no'])) { if($conn) { if(mysql_select_db("img_mgmt", $conn)) { $sql = "select * from temp_images where card_no='".trim($_POST['card_no'])."'"; $result = mysql_query($sql); $image = mysql_fetch_array($result); if(isset($image['card_no'])) { //echo "<img src=\"".$image['file_path']."\" alt=\"".$image['card_no']."\" width=\"250\" height=\"280\"/>"; header("Content-type: image/jpeg"); echo $image['img_content']; } else { echo "<p style=\"color:red;\">Sorry, Your search came with no results ! <br/> Try with different card number"; } } else { echo "Database selection error: ".mysql_error(); } } else { echo "Could not connect: ".mysql_error(); } } ?> </center> </body> </html> But it after executing the script it shows: Cannot modify header information - headers already sent by (output started at C:\xampp\htdocs\img\search.php:61) in C:\xampp\htdocs\img\search.php on line 77

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  • PHP MySQL Zend-ACL - Find all inherited items (Children / Parents)

    - by Scoobler
    I have one MySQL DB table like the following, the resources table: id | name | type 1 | guest | user 2 | member | user 3 | moderator | user 4 | owner | user 5 | admin | user 6 | index | controller Onto the next table, the rules table: id | user_id | rule | resource_id | extras 1 | 2 | 3 | 1 | null 2 | 3 | 3 | 2 | null 3 | 4 | 3 | 3 | null 4 | 5 | 3 | 4 | null 5 | 6 | 1 | 1 | index,login,register 6 | 6 | 2 | 2 | login,register 7 | 6 | 1 | 2 | logout OK, sorry for the length, but I am trying to give a full picture of what I am trying to do. So the way it works, a role (aka user) can be granted (rule: 1) access to a controller, a role can inherit (rule: 3) access from another role or a role and be denied (rule: 2) access to a controller. (A user is a resource and a controller is a resource) Access to actions are granted / denied using the extras column. This all works, its not a problem with setting up the ACL within zend. What I am now trying to do is show the relationships; to do that I need to find the lowest level a role is granted access to a controller stopping if it has explicitly been removed. I plan on listing the roles. When I click a role, I want it to show all the controllers that role has access to. Then clicking on a controller shows the actions the role is allowed to do. So in the example above, a guest is allowed to view the index action of the index controller along with the login action. A member inherits the same access, but is then denied access to the login action and register action. A moderator inherits the rules of a member. So if I were to select the role moderator. I want to see the controller index listed. If I click on the controller, it should show the allowed actions as being action: index. (which was originally granted to the guest, but hasn't since been dissallowed) Is there any examples to doing this. I am obviously working with the Zend MVC (PHP) and MySQL. Even just a persudo code example would be a helpful starting point - this is one of the last parts of the jigsaw I am putting together. P.S. Obviously I have the ACL object - is it going to be easier to interigate that or is it better to do it my self via PHP/MySQL? The aim will be, show what a role can access which will then allow me to add or edit a role, controller and action in a GUI style (that is somewhat the easy bit) - currently I am updating the DB manually as I have been building the site.

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  • JSON Array Created in PHP/MySQL incorrectly decoded using JQuery

    - by Zak
    I am attempting to make an AJAX call to a very small PHP script that should return me an array that could be echo'd and decoded using JQuery. Here is what I have: My PHP page called to by AJAX: $web_q=mysql_query("select * from sec_u_g where uid='$id' "); $rs = array(); while($rs[] = mysql_fetch_assoc($web_q)) { } print_r(json_encode($rs)); This outputs: [{"id":"3","uid":"39","gid":"16"},{"id":"4","uid":"39","gid":"4"},{"id":"5","uid":"39","gid":"5"},{"id":"6","uid":"39","gid":"6"},{"id":"7","uid":"39","gid":"7"},{"id":"8","uid":"39","gid":"8"},{"id":"9","uid":"39","gid":"9"},false] I don't understand the "false" at the end for one .. But then I send to to JQuery and use: $.each(json.result, function(i, object) { $.each(object, function(property, value) { alert(property + "=" + value); }); }); This just fails. I try to alert "result" by itself which is set by: $.post("get_ug.php",{id:txt},function(result){ }); My output alerts are as follows: 1) The key is '0' and the value is '[' 2) The key is '1' and the value is 'f' 3) The key is '2' and the value is 'a' 4) The key is '3' and the value is 'l' 5) The key is '4' and the value is 's' 6) The key is '5' and the value is 'e' 7) The key is '6' and the value is ']' 8) The key is '7' and the value is ' ' (<-- Yes the line break is there in the alert) I am exhausted from trying different ideas and scripts. Other than setting a delimiter myself and concatenating my own array and decoding it with a custom script, does anyone have any ideas?? Thank you!!

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  • As3 & PHP URLEncoding problem!

    - by Jk_
    Hi everyone, I'm stuck with a stupid problem of encoding. My problem is that all my accentuated characters are displayed as weird iso characters. Example : é is displayed %E9 I send a string to my php file : XMLLoader.load(new URLRequest(online+"/query.php?Query=" + q)); XMLLoader.addEventListener(Event.COMPLETE,XMLLoaded); When I trace q, I get : "INSERT INTO hello_world (message) values('éàaà');" The GOOD query My php file look like this : <?php include("conection.php");//Conectiong to database $Q = $_GET['Query']; $query = $Q; $resultID = mysql_query($query) or die("Could not execute or probably SQL statement malformed (error): ". mysql_error()); $xml_output = "<?xml version=\"1.0\"?>\n"; // XML header $xml_output .= "<answers>\n"; $xml_output .= "<lastID id=".'"'.mysql_insert_id().'"'." />\n"; $xml_output .= "<query string=".'"'.$query.'"'." />\n"; $xml_output .= "</answers>"; echo $xml_output;//Output the XML ?> When I get back my XML into flash the $query looks like this : "INSERT INTO hello_world (message) values('%E9%E0a%E0');" And these values are then displayed into my DB which is annoying. Any help would be appreciated! Cheers. Jk_

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  • Creating a session user login php

    - by user2419393
    I'm stuck on how to create a session for a user who logs in. I got the part of checking to make sure the log in information corresponds with the database information, but is stuck on how to take the email address and store into a session. Here is my php code below. <?php include '../View/header.php'; session_start(); require('../model/database.php'); $email = $_POST['username']; $password = $_POST['password']; $sql = "SELECT emailAddress FROM customers WHERE emailAddress ='$email' AND password = '$password'"; $result = mysql_query($sql, $db); if (!$result) { echo "DB Error, could not query the database\n"; echo 'MySQL Error: ' . mysql_error(); exit; } while ($row = mysql_fetch_assoc($result)) { echo $row['emailAddress']; } mysql_free_result($result); ?>

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  • Working with PHP and MySQL - need a good and secure design with OO design

    - by Andrew
    I am new to PHP- first time developer. I am working on my web application and it is nearly done; nevertheless, most of my sql was done directly via code using direct mysql requests. This is the way I approached it: In classes_db.php I declared the db settings and created methods that I use to open and close DB connections. I declare those objects on my regular pages: class classes_db { public $dbserver = 'server; public $dbusername = 'user'; public $dbpassword = 'pass'; public $dbname = 'db'; function openDb() { $dbhandle = mysql_connect($this->dbserver, $this->dbusername, $this->dbpassword); if (!$dbhandle) { die('Could not connect: ' . mysql_error()); } $selected = mysql_select_db($this->dbname, $dbhandle) or die("Could not select the database"); return $dbhandle; } function closeDb($con) { mysql_close($con); } } On my regular page, I do this: <?php require 'classes_db.php'; session_start(); //create instance of the DB class $db = new classes_db(); //get dbhandle $dbhandle = $db->openDb(); //process query $result = mysql_query("update user set username = '" . $usernameFromForm . "' where iduser= " . $_SESSION['user']->iduser); //close the connection if (isset($dbhandle)) { $db->closeDb($dbhandle); } ?> My questions is: how to do it right and make it OO and secure? I know that I need incorporate prepared queries- how to do it the best way? Please provide some code

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