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  • How to know if the website being scraped has changed?

    - by Lost_in_code
    I'm using PHP to scrape a website and collect some data. It's all done without using regex. I'm using php's explode() method to find particular HTML tags instead. It is possible that if the structure of the website changes (CSS, HTML), then wrong data may be collected by the scraper. So the question is - how do I know if the HTML structure has changed? How to identify this before storing any data to my database to avoid wrong data being stored.

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  • Getting Null value with JSON from MySQL, how to retrive data from MySQL to JSON correctly?

    - by sky
    I'm using following code but cannot return data from MySQL. This is the output: <script type="text/javascript"> var somethings= [null,null,null]; </script> It does have three post, but I couldn't get the title(message) output. EDIT: this is the code I'm using: <?php $session = mysql_connect('localhost','name','pass'); mysql_select_db('dbname', $session); $result= mysql_query('SELECT * FROM posts', $session); $somethings= array(); while ($row= mysql_fetch_assoc($result)) { $somethings[]= $row['something']; } ?> <script type="text/javascript"> var somethings= <?php echo json_encode($somethings); ?>; </script> This is the table: message Try iPhone post! Welcome to Yo~ :) ??!

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  • Error in header function

    - by user1178695
    I'm using the php header function for the redirection but it is not working.I'm using the following code. $sql=mysql_query("select * from password where username='$email' and password1 = '$pwd'"); //echo "selct * from password where username='$email' and password = '$pwd'"; $row=mysql_fetch_row($sql); $fieldset=mysql_num_rows($sql); $host=$_SERVER['HTTP_HOST']."/beta/"; if($fieldset>0 && $conEmail !="") { $_SESSION['email']=$email; $_SESSION['Email']=$email; $_SESSION['memberID']=$id; $_SESSION['status']='Admin'; header("location:http://".$host."member.php"); }

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  • Apache crashes after installing mysqli

    - by Marco P.
    System: Apache 2.2 running on Windows 2008 Server with PHP 5.2.17 VC6 Thread-Safe as a Module and MySQL 5.5.17 - all working fine. After installing mysqli using the php package, Apache won't start anymore. There is no error message in the log. What I have tried: Make sure Windows PATH points to libmysql.dll: Yes, done. Make sure extension_dir points to the right point: Yes. Other extensions load fine. Try without mysqli: Yes, Apache loads fine then. Try without mysql: Yes, does not help. Test mysql itself: Restarts server! Overwrite libmysql: Yes, does not help. It seems to me that there is some general problem with MySql, but the DB server seems to be running fine. I'm really out of ideas of things I could try, so I'm desperate for any hints or tricks.

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  • which one consume less resources? opening text file or make an sql query,both a thousand times ?

    - by imin
    hi I've a php website which displays recipes www.trymasak.my, to be exact. The recipes being displayed at the index page is updated about once a day. To get the latest recipes, I just use a mysql query which is something like "select recipe_name, page_views, image from table order by last_updated". So if I got 10000 visitors a day, obviously the query would be made 10000 times a day. A friend told me a better way (in terms of reducing server load) is when I update the recipes, I just put in the latest recipe details (names,images etc) into a text file, and make my page instead of querying a same query for 10,000 times, just get the data from the text file. Is his suggestion really better? If yes, which is the best php command should I use to open, read and close the text file? thanks

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  • Need help with regular expressions - URL redirection

    - by paperless
    Hello everyone. I'm trying to redirect an easy to remember url to a php file but I'm having some trouble with the regex. Here's what I have at the moment: RewriteRule ^tcb/([a-zA-Z0-9]{1,})/([a-zA-Z0-9]{1,})/([a-zA-Z0-9]{1,}) /tcb/lerbd.php?autocarro=$1&tipo=$2&dsd=$3 It is working but only if I supply all 3 arguments. I want the last two arguments to be optional so it either works with only the first or all three. I'm hoping you can help me with this. Thank you very much.

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  • Is there any way to use imagegrabwindow() with Firefox or Chrome?

    - by patternsofchaos
    I'm trying to generate website thumbnails programatically in PHP. To do this, I'm using imagegrabwindow() with a COM object: $browser = new COM("InternetExplorer.Application"); $handle = $browser->HWND; $browser->Visible = true; $browser->Navigate($pre.$URL); while ($browser->Busy) { com_message_pump(4000); } $img = imagegrabwindow($handle); What I'm wondering is if there is any way to do the same thing with Firefox or Chrome? Can I invoke either of them with PHP COM?

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  • How can I store and access SQLite databases from a central location?

    - by Brian Ramsay
    I have installed SQLite on my UNIX system, and am planning on accessing it from PHP. However, the database is created in the directory I initialize it in, and if a script runs in a different directory a new database is created in the same directory. Is there an option for SQLite (or the PHP wrappers) to create the databases in one location, and have those databases accessible just by name outside of that directory? Ideally, I'd like to be able to do something like $db=new SQLiteDatabase("db.test"); in any directory and have it reference the same database, if that makes sense.

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  • Include a repetitive chunk of HTML

    - by user146780
    I basically have a div on my site that always has the same stuff. However, this div is not present on all pages which is why I won't use the dynamic web template. I was wondering if it was possible for PHP to get the code from a document on the server and put in into the div? Ex: <div id="section... then my text file contains <p>hello</p> Basically I want PHP to put it into the div when the user sees it. If theres a smarter way of acheiving this I'd be open to it as well. Thanks

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  • Injecting single-use object into class

    - by moteutsch
    I have the following code: <?php class X { public function do($url) { $httpRequest = new \HttpRequest\Curl($url, $this->getOptions()); $httpRequest->fire(); // etc. } // ... } In order to be able to unit test this class, I'd like to inject a mocked HttpRequest class. One way to do this would be as follows: <?php class X { private $httpRequestClass; public function __construct($httpRequestClass = '\HttpRequest\Curl') { $this->httpRequestClass = $httpRequestClass; } public function do($url) { $httpRequest = new $this->httpRequestClass($url, $this->getOptions()); $httpRequest->fire(); // etc. } // ... } But this doesn't seem right. Any other ideas?

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  • PDOException “could not find driver”

    - by Mike
    I have just installed Debian Lenny with Apache, MySQL, and PHP and I am receiving a PDOException could not find driver. This is the specific line of code it is referring to: $dbh = new PDO('mysql:host=' . DB_HOST . ';dbname=' . DB_NAME, DB_USER, DB_PASS) DB_HOST, DB_NAME, DB_USER, and DB_PASS are constants that I have defined. It works fine on the production server (and on my previous Ubuntu Server setup). Is this something to do with my PHP installation? Searching the internet has not helped, all I get is experts-exchange and examples, but no solutions.

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  • CakePHP accessing other controllers

    - by James
    CakePHP Newbie :) I am having trouble accessing another controller and passing that data to a view in one of my controllers: In controllers/landings_controller.php: var $uses = 'User'; function home() { $userdata = $this->User->read(); $this->set(compact('userdata')); } In views/landings/home.ctp: <?php echo $this->userdata; ?> When accessing /landings/home I get the following error: Notice (8): Undefined property: View::$userdata [APP/views/landings/home.ctp, line 38] I don't know what I am doing wrong. Any help? Thanks!

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  • Uploading files wont work on production server

    - by Camran
    I have a php script which uploads images to a temporary folder on the server. This works on my local computer with the local (virtual) server. (wampserver). However, on the production server (linux) I cant get it working. Everything is loading as it should, except for that the file doesn't show up on the server. My Q is, is there anything I should think about when moving to a production server with uploading images or files? I have set permissions on the folder where the images are supposed to go to 777 and also the php-code which uploads them to 777. Thanks

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  • ajax how to read out $_post variable

    - by alex
    Hi, I am trying to filter/search a database with ajax $.ajax({ type: "POST", url: "filterSearch.php", queryString: qry, success: function(data){ alert( "Data Saved: " + data ); $('#searchResult').html(data); // Fill the search results box } }); Now in filterSearch.php i have the following test codes if(isset($_POST['queryString'])) { echo "TEST"; } if($_POST['runquery']==1) { $sql = "SELECT * FROM fs_vacatures WHERE here-the-like-query?"; $msg = $sql; echo $msg; die(); } die(); But nor TEST or the $sql is return in the alert??

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  • Error - Trying to get property of non-object

    - by Patrick Lanfranco
    I am currently getting this error on one of my files: /var/www/vhosts/httpdocs/generator/index.php on line 6 Line 6 would be resulting in: echo $results->GetBookCodesResult->BookCodes->BookInfo->ServiceCode; My code: <?php $config['soap_url'] = "http://myservice.com?WSDL"; if(isset($_REQUEST['codes'])) { $results = request_Data(explode("\n",$_REQUEST['codes'])); echo $results->GetBookCodesResult->BookCodes->BookInfo->ServiceCode; } .... What is the best method to have this fixed? Some advice would be appreciated.

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  • Problem with onsubmit ID

    - by Liso22
    I need an onsubmit to return false if what's written on the first field is a certain PHP value however the field has a strange id format and I'm not quite sure how to add it in the onsubmit. This is the form, I didn't add the element ID to it: <form class="questionform" name="questionform-0" id="questionform-0" onsubmit="if (document.getElementById('').value == '<?php echo $casi; ?>') return false;" > <textarea class="question-box" style="width:97%;" cols="20" rows="4" id="question-box-' . $questionformid . '" name="title" type="text" maxlength="80" size="28" value=""></textarea> I tried many times but couldn't add it. How should I do it? Thanks

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  • How to access constant defined in child class from parent class functions?

    - by kavoir.com
    I saw this example from php.net: <?php class MyClass { const MY_CONST = "yonder"; public function __construct() { $c = get_class( $this ); echo $c::MY_CONST; } } class ChildClass extends MyClass { const MY_CONST = "bar"; } $x = new ChildClass(); // prints 'bar' $y = new MyClass(); // prints 'yonder' ?> But $c::MY_CONST is only recognized in version 5.3.0 or later. The class I'm writing may be distributed a lot. Basically, I have defined a constant in ChildClass and one of the functions in MyClass (father class) needs to use the constant. Any idea?

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  • how to list out the submited data in same page where form submitted?

    - by OM The Eternity
    I have a form with 3 text values and one image.. I want to save these values such that i can display these records in the list below.. how can i do that... I am using osCommerce For example: <form method="post" id="fm-form" action ="" enctype="multipart/form-data"> <label>Name:</label> <input type="text" id="fm-name" name="fm-name" value="" /> <label>Email:</label> <input type="text" id="fm-email" name="fm-email" value="" /> <label>Birthdate:</label> <input type="text" id="fm-birthdate" name="fm-birthdate" value="" /> <input type="file" id="fm-image" name="fm-image"/> <input type="submit" id="fm-submit" value="Save it"> </form> <table width="100%" border="0" cellspacing="0" cellpadding="0"> <tr > <td align="center" class="productListing-heading">Product(s)</td> <td align="center" class="productListing-heading">Edit</td> <td align="center" class="productListing-heading">Delete</td> </tr> <?php for($i=0;$i<$count_image;$i++){?> <tr> <td align="left" class="productListing-data1"> <?php echo tep_image(DIR_WS_IMAGES . $file_realname, $save_image[$i], '110', '110');?> </td> <td align="center" class="productListing-data1">Edit</td> <td align="center" class="productListing-data1">Delete</td> </tr> <tr><td>&nbsp;</td></tr> <?php }?> </table> In the above format as the form is submitted the image has to be stored in a count_image array variable... and the on its count, the list below the form is displayed.. but i cannot get it worked.. could u pls help in doing this...

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  • 1054 - Unknown column 'apa_calda' in 'where clause'

    - by sebastian
    Hi, I keep getting this error in mysql. Here is the query: SELECT user_id FROM detalii_contor WHERE tip_contor=apa_calda i want to use this query in a php file but it doesn't give any result. so i tried to write it in the sql command prompt. here is what i tried in the php file: $Q = "SELECT id_contor, den_contor FROM detalii_contor WHERE tip_contor='".$contor."'"; $Q = "SELECT id_contor, den_contor FROM detalii_contor WHERE tip_contor='$contor'"; even without "" or without '' i wanted to get $contor from a form, i also tried with $_POST['util'] and {$_POST['util']} i've also tried to set $contor the value i need, but no result. please help. thanks, Sebastian

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  • Stopping users posting more than once

    - by user342391
    Before posting my form I am checking the database to see if there are any previous posts from the user. If there are previous posts then the script will kick back a message saying you have already posted. The problem is that what I am trying to achieve isn't working it all goes wrong after my else statement. It is also probable that there is an sql injection vulnerability too. Can you help??4 <?php include '../login/dbc.php'; page_protect(); $customerid = $_SESSION['user_id']; $checkid = "SELECT customerid FROM content WHERE customerid = $customerid"; if ($checkid = $customerid) {echo 'You cannot post any more entries, you have already created one';} else $sql="INSERT INTO content (customerid, weburl, title, description) VALUES ('$_POST[customerid]','$_POST[webaddress]','$_POST[pagetitle]','$_POST[pagedescription]')"; if (!mysql_query($sql)) { die('Error: ' . mysql_error()); } echo "1 record added"; ?>

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  • How is this problem usually solved without using sever-side scripting?

    - by cyggi
    Simple problem I have so far always solved via PHP: You have a site with header, menu, footer and content field. Header, menu and footer are usually the same for each page. How do you, without PHP or any other server-side language, have the header, menu and footer data exist only in one file? So that for example you don't have ten sites (like home.html, products.html, about.html, ..) all having a copy of the static header and menu in their html files. Now if you want to change the header you have to change ten files. I hope I made my question clear enough, if not please leave a comment :)

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