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  • which one consume less resources? opening text file or make an sql query,both a thousand times ?

    - by imin
    hi I've a php website which displays recipes www.trymasak.my, to be exact. The recipes being displayed at the index page is updated about once a day. To get the latest recipes, I just use a mysql query which is something like "select recipe_name, page_views, image from table order by last_updated". So if I got 10000 visitors a day, obviously the query would be made 10000 times a day. A friend told me a better way (in terms of reducing server load) is when I update the recipes, I just put in the latest recipe details (names,images etc) into a text file, and make my page instead of querying a same query for 10,000 times, just get the data from the text file. Is his suggestion really better? If yes, which is the best php command should I use to open, read and close the text file? thanks

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  • 'An error occurred. Please try later' message on Facebook authentication dialog

    - by Eugene Zhuang
    I am a newbie who is trying to create a Facebook app using PHP and Facebook's PHP SDK. The app is hosted on Heroku, and the sample app that they provided is working fine. However, I am now trying to get the sample app to work on Apache 2.2, and I have encountered a lot of problems along the way. Well, straight to the point, my latest problem will be trying to do Facebook login on localhost, but the 'An error occurred. Please try later' appears on the popup dialog. This does not happen on Heroku. Will someone please enlighten me on if there's any steps that I can take to overcome this error? I don't think it got to do with any coding error since I am just following the provided sample app. Thanks!

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  • My rewrite rule is not working

    - by DijkeMark
    I need to make a rewrite rule for a page, but it does not work. I do have mod_rewrite for apache enabled This is my .htacces file: <IfModule mod_rewrite.c> RewriteEngine on RewriteRule ^gameofthrones/(full|house|characters)\.(all|Stark|Lannister)\.(html|xml|json)$ index.php?output=$3&house=$2&info=$1 </IfModule> But when I enter this url: localhost/school/str-webservices/eindopdracht/index.php?output=html&house=all&info=full It stays that way, but it should be something like: localhost/school/str-webservices/eindopdracht/gameofthrones/full/all/html What am I doing wrong? Thanks in advance, Mark

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  • ajax how to read out $_post variable

    - by alex
    Hi, I am trying to filter/search a database with ajax $.ajax({ type: "POST", url: "filterSearch.php", queryString: qry, success: function(data){ alert( "Data Saved: " + data ); $('#searchResult').html(data); // Fill the search results box } }); Now in filterSearch.php i have the following test codes if(isset($_POST['queryString'])) { echo "TEST"; } if($_POST['runquery']==1) { $sql = "SELECT * FROM fs_vacatures WHERE here-the-like-query?"; $msg = $sql; echo $msg; die(); } die(); But nor TEST or the $sql is return in the alert??

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  • weird problem..the exact xml work in one host and not working in another...

    - by Ofear
    hi all! i search alot for this but can't find an aswer... I have made a working xml parser using php. till today i host my files on a free web host, and everything works just fine. today i got access to my college server and i host my files there. now for some reason.. i can't make the parser work as i was in the free host... look on those files please: working site: xml file: [http://ofear.onlinewebshop.net/asce/calendar.xml] working parser is this: [http://ofear.onlinewebshop.net/asce/calendar.php] (the lower table is the xml,it's hebrew) not working site: xml file: [http://apps.sce.ac.il/agoda/calendar.xml] not working parser is this: [http://apps.sce.ac.il/agoda/calendar.php] anyone have idea why it's not working.. those are the same files and they should work. maybe it a server problem? calendar.xml: <?xml version="1.0" encoding="UTF-8" ?> <events> <record> <event>??? ???? ????? ???? ???</event> <eventDate>30/12/2010</eventDate> <desc>?????? ?? ????</desc> </record> <record> <event>??? ???? ??????? - 2 : ???? ??? ???? ??????</event> <eventDate>22/12/2010</eventDate> <desc>????? ???? ??????? ?????? ??? ???? ??????? ?????? ????? ?????? ?? ??? ???? ??????? 2 ??????? ????? ???????? 22-23 ?????? 2010. ???? ????? ???? ????? "?????? ????"</desc> </record> <record> <event>????? ???? ?????? ?????? - ?? ????</event> <eventDate>5/12/2010</eventDate> <desc>??? ????? 17:30-20:45</desc> </record> </events> parser: <?php $doc = new DOMDocument(); $doc->load( 'calendar.xml' ); $events = $doc->getElementsByTagName( "record" ); foreach( $events as $record ) { $events = $record->getElementsByTagName( "event" ); $event = $events->item(0)->nodeValue; $eventDates= $record->getElementsByTagName( "eventDate" ); $eventDate= $eventDates->item(0)->nodeValue; $descs = $record->getElementsByTagName( "desc" ); $desc = $descs->item(0)->nodeValue; echo "<tr><td>$event</td><td>$eventDate</td><td>$desc</td></tr>"; } ?> after a little debugging i saw that it's stop here: $doc = new DOMDocument(); and it's not doing anything after that. i think that the line above is the cos

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  • How to know if the website being scraped has changed?

    - by Lost_in_code
    I'm using PHP to scrape a website and collect some data. It's all done without using regex. I'm using php's explode() method to find particular HTML tags instead. It is possible that if the structure of the website changes (CSS, HTML), then wrong data may be collected by the scraper. So the question is - how do I know if the HTML structure has changed? How to identify this before storing any data to my database to avoid wrong data being stored.

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  • Is there any way to use imagegrabwindow() with Firefox or Chrome?

    - by patternsofchaos
    I'm trying to generate website thumbnails programatically in PHP. To do this, I'm using imagegrabwindow() with a COM object: $browser = new COM("InternetExplorer.Application"); $handle = $browser->HWND; $browser->Visible = true; $browser->Navigate($pre.$URL); while ($browser->Busy) { com_message_pump(4000); } $img = imagegrabwindow($handle); What I'm wondering is if there is any way to do the same thing with Firefox or Chrome? Can I invoke either of them with PHP COM?

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  • How to access constant defined in child class?

    - by kavoir.com
    I saw this example from php.net: <?php class MyClass { const MY_CONST = "yonder"; public function __construct() { $c = get_class( $this ); echo $c::MY_CONST; } } class ChildClass extends MyClass { const MY_CONST = "bar"; } $x = new ChildClass(); // prints 'bar' $y = new MyClass(); // prints 'yonder' ?> But $c::MY_CONST is only recognized in version 5.3.0 or later. The class I'm writing may be distributed a lot. Basically, I have defined a constant in ChildClass and one of the functions in MyClass (father class) needs to use the constant. Any idea?

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  • How can I store and access SQLite databases from a central location?

    - by Brian Ramsay
    I have installed SQLite on my UNIX system, and am planning on accessing it from PHP. However, the database is created in the directory I initialize it in, and if a script runs in a different directory a new database is created in the same directory. Is there an option for SQLite (or the PHP wrappers) to create the databases in one location, and have those databases accessible just by name outside of that directory? Ideally, I'd like to be able to do something like $db=new SQLiteDatabase("db.test"); in any directory and have it reference the same database, if that makes sense.

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  • array_count_values for javascript instead

    - by user626342
    Hi, I have the following php-script, now I need to do the same thing in javascript. Is there a funcion in javascript that works similar to the php function, I have been searching for days but cannot find anything similar? What I want to do is to count the number of times a certain word is beeing used in an array. $interfaceA = array($interfaceA_1,$interfaceA_2,$interfaceA_3,$interfaceA_4,$interfaceA_5,$interfaceA_6,$interfaceA_7,$interfaceA_8); $interfaceA_array=array_count_values($interfaceA); $knappsatsA = $interfaceA_array[gui_knappsats]; $touchpanelA = $interfaceA_array[gui_touchpanel]; Many thanks linda

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  • Add a custom class name to Wordpress body tag?

    - by Scott B
    I'd like to place a directive in my theme's functions.php file which appends a classname to the wordpress body tag. Is there a built-in API method for this? For example, my body tag code is... <body <?php if(function_exists("body_class") && !is_404()){body_class();} else echo 'class="page default"'?>> And it results in the following being written to the body tag (depending on the context in which the page is presented (page, post, logged-in, etc) <body class="home blog logged-in"> Depending on the child theme I'm using at the time, I want it to be... <body class="home blog logged-in mychildthemename">

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  • Seeking assistance with Escaping Data for MySQL queries

    - by JM4
    Please don't send me a link to php.net referencing mysql_real_escape_string as the only response. I have read through the page and while I understand the general concepts, I am having some trouble based on how my INSERT statement is currently built. Today, I am using the following: $sql = "INSERT INTO tablename VALUES ('', '$_SESSION['Member1FirstName'], '$_SESSION['Member1LastName'], '$_SESSION['Member1ID'], '$_SESSION['Member2FirstName'], '$_SESSION['Member2LastName'], '$_SESSION['Member2ID'] .... and the list goes on for 20+ members with some other values entered. It seems most people in the examples already have all their data stored in an array. On my site, I accept form inputs, action="" is set to self, php validation takes place and if validation passes, data is stored into SESSION variables on page 2 then redirected to the next page in the process (page 3) (approximately 8-10 pages in the whole process). thanks!

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  • Include a repetitive chunk of HTML

    - by user146780
    I basically have a div on my site that always has the same stuff. However, this div is not present on all pages which is why I won't use the dynamic web template. I was wondering if it was possible for PHP to get the code from a document on the server and put in into the div? Ex: <div id="section... then my text file contains <p>hello</p> Basically I want PHP to put it into the div when the user sees it. If theres a smarter way of acheiving this I'd be open to it as well. Thanks

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  • How to handle un-assigned records

    - by Mico
    I have this PHP page where the user can select and un-select items. The interface looks like this: Now I'm using these code, when the user hit the save changes button: foreach( $value as $al_id ){ //al_id is actually location id //check if a record exists //if location were assigned and leave it as is $assigned_count = $this->AssignedLoc->checkIfAssigned( $tab_user_id, $al_id ); if( $assigned_count == 0 ){ //else if not, insert this new record $this->insertAssigned( $tab_user_id, $company_id, $al_id ); } } Now my question is, how do I delete the un assigned locations? For example in the screenshot above, there are 4 assigned locations, if I'm gonna remove (or unassign) "Mercury Morong" and "GP Hagonoy" from the assigned locations, only two must remain. What are the possible solutions using PHP? Thanks for any help!

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  • Apache crashes after installing mysqli

    - by Marco P.
    System: Apache 2.2 running on Windows 2008 Server with PHP 5.2.17 VC6 Thread-Safe as a Module and MySQL 5.5.17 - all working fine. After installing mysqli using the php package, Apache won't start anymore. There is no error message in the log. What I have tried: Make sure Windows PATH points to libmysql.dll: Yes, done. Make sure extension_dir points to the right point: Yes. Other extensions load fine. Try without mysqli: Yes, Apache loads fine then. Try without mysql: Yes, does not help. Test mysql itself: Restarts server! Overwrite libmysql: Yes, does not help. It seems to me that there is some general problem with MySql, but the DB server seems to be running fine. I'm really out of ideas of things I could try, so I'm desperate for any hints or tricks.

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  • Keeping some files private

    - by user490895
    Hi, I was trying to create a directory of private files that could only be accessed when a user logs in. To do this, I used a folder outside the web directory, and then php to access it, if allowed. Here's an example: function display_movie($file){ printf("<video id='movie' width='960' height='416' controls='controls' onerror='fix()'> <source src='movie.php?file=%s' type='video/ogg; codecs=\"theora, vorbis\"'> </video>", rawurlencode($file)); } This works great for images, but breaks the media player. Also, I've only tested this locally on a Linux machine. Any ideas? Thanks.

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  • Problem with onsubmit ID

    - by Liso22
    I need an onsubmit to return false if what's written on the first field is a certain PHP value however the field has a strange id format and I'm not quite sure how to add it in the onsubmit. This is the form, I didn't add the element ID to it: <form class="questionform" name="questionform-0" id="questionform-0" onsubmit="if (document.getElementById('').value == '<?php echo $casi; ?>') return false;" > <textarea class="question-box" style="width:97%;" cols="20" rows="4" id="question-box-' . $questionformid . '" name="title" type="text" maxlength="80" size="28" value=""></textarea> I tried many times but couldn't add it. How should I do it? Thanks

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  • CakePHP accessing other controllers

    - by James
    CakePHP Newbie :) I am having trouble accessing another controller and passing that data to a view in one of my controllers: In controllers/landings_controller.php: var $uses = 'User'; function home() { $userdata = $this->User->read(); $this->set(compact('userdata')); } In views/landings/home.ctp: <?php echo $this->userdata; ?> When accessing /landings/home I get the following error: Notice (8): Undefined property: View::$userdata [APP/views/landings/home.ctp, line 38] I don't know what I am doing wrong. Any help? Thanks!

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  • 1054 - Unknown column 'apa_calda' in 'where clause'

    - by sebastian
    Hi, I keep getting this error in mysql. Here is the query: SELECT user_id FROM detalii_contor WHERE tip_contor=apa_calda i want to use this query in a php file but it doesn't give any result. so i tried to write it in the sql command prompt. here is what i tried in the php file: $Q = "SELECT id_contor, den_contor FROM detalii_contor WHERE tip_contor='".$contor."'"; $Q = "SELECT id_contor, den_contor FROM detalii_contor WHERE tip_contor='$contor'"; even without "" or without '' i wanted to get $contor from a form, i also tried with $_POST['util'] and {$_POST['util']} i've also tried to set $contor the value i need, but no result. please help. thanks, Sebastian

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  • Getting Null value with JSON from MySQL, how to retrive data from MySQL to JSON correctly?

    - by sky
    I'm using following code but cannot return data from MySQL. This is the output: <script type="text/javascript"> var somethings= [null,null,null]; </script> It does have three post, but I couldn't get the title(message) output. EDIT: this is the code I'm using: <?php $session = mysql_connect('localhost','name','pass'); mysql_select_db('dbname', $session); $result= mysql_query('SELECT * FROM posts', $session); $somethings= array(); while ($row= mysql_fetch_assoc($result)) { $somethings[]= $row['something']; } ?> <script type="text/javascript"> var somethings= <?php echo json_encode($somethings); ?>; </script> This is the table: message Try iPhone post! Welcome to Yo~ :) ??!

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  • Stopping users posting more than once

    - by user342391
    Before posting my form I am checking the database to see if there are any previous posts from the user. If there are previous posts then the script will kick back a message saying you have already posted. The problem is that what I am trying to achieve isn't working it all goes wrong after my else statement. It is also probable that there is an sql injection vulnerability too. Can you help??4 <?php include '../login/dbc.php'; page_protect(); $customerid = $_SESSION['user_id']; $checkid = "SELECT customerid FROM content WHERE customerid = $customerid"; if ($checkid = $customerid) {echo 'You cannot post any more entries, you have already created one';} else $sql="INSERT INTO content (customerid, weburl, title, description) VALUES ('$_POST[customerid]','$_POST[webaddress]','$_POST[pagetitle]','$_POST[pagedescription]')"; if (!mysql_query($sql)) { die('Error: ' . mysql_error()); } echo "1 record added"; ?>

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