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  • HOw to make image stay inside the div box on scrolling

    - by Mirage
    I have the image position fixed inside div and code is gven below #content{ margin-top:100px; width:900px; color:#009; border:1px solid red; overflow:hidden; display:block; } img { float:left; position:fixed; top:140px; padding:50px; } #text{ display:block; border:1px solid green; width:500px; height:1200px; float:right; overflow:scroll; } #footer{ clear:both; width:600px; height:300px; border:2x solid blue; color:#939; } HTML is <div id="content" > <img src="bar.jpg" width="46" height="639" /> <div id="text"> ggggggggggggggggggfgdfgdfgdgdfgdgdfgdf </div> </div> <div id="footer"> Footer text </div> </body> Now when i scroll down then image comes out of the content div box. IS there any way so that even if i scroll the image bar should stay inside the div box. The screen shot shows my problem First Screen is ok without scrolling But when i scroll the text full then it covers my footer as well

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  • How to get the root path in JavaScript?

    - by Axel
    I am using mod_rewrite to remap the URLs in my website in the following format: http://www.mydomain.com/health/54856 http://www.mydomain.com/economy/strategy/911025/ http://www.mydomain.com/tags/obama/new The problem is that I am making AJAX calls to a file: http://www.mydomain.com/login.php And I don't want to write the FULL url or even use the ../ trick because there isn't a fixed level of folders. So, what i want is something to access the login.php from the root, whatever the domain name is: $.ajax({ type: "POST", url: "http://www.mydomain.com/login.php" });

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  • How do I get only two form fields to show instead of all 5 on initial page load? CSS

    - by marcamillion
    Here is the implementation: http://jsfiddle.net/AdQfB/2/ If you notice, when you click 'Login' or 'Register' before entering anything, you should see a few fields disappear and re-appear respectively. I would like for this page to display the view of just the two fields on the first load (rather than the current 5 it shows on first load), then when the user clicks the 'register' link, it shows the other 3 - for a total of 5. How do I do that? Thanks

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  • Javascript IN operator compatibility

    - by jAndy
    Hi Folks, Can someone tell me since which ECMA version the IN operator is available and which browsers (versions) support it ? Explanation: The IN-operator can be used like the following: var myObject = { Firstname: 'Foo', Lastname: 'Bar' }; if('Lastname' in myObject){ // Lastname is an attribute of myObject }

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  • jQueryt Search for Text in a Variable?

    - by thatryan
    I have a variable that contains some text, some html, basically can be a string. I need to search the variable for a specific string to process that variable differently if it is contained. Here is a snippet of what I am trying to do, does not work obviously :) $.each(data.results, function(i, results) { var text = this.text var pattern = new RegExp("^[SEARCHTERM]$"); if(pattern.test( text ) ) alert(text); //was hoping this would alert the SEARCHTERM if found...

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  • Remove or hide div on runtime

    - by Xulfee
    following code remove div on runtime. I have written code perfectly but it did not delete or hide the div. $(document).ready(function() { $("#metainfo > input").live('click', function() { $("#div" + this.id).fadeOut("slow"); }); });

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  • Can a Client Link to My JavaScript, Hosted on a Different Domain?

    - by DaveDev
    Is it possible for me to supply a client with a snippet of HTML which contains a reference to a javascript file that I host? They want to paste this HTML into their CMS, so that when their page loads, it'll load our content. I was under the impression that there was cross domain security preventing this from being possible. What if, instead of linking to the JavaScript, I gave them the snippet of HTML with the JavaScript already included so instead of <div> <!-- link to js --> </div> I gave them <div> $.get(/*url to my content*/); </div> Would that work?

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  • Jsonp cross-domain ajax

    - by Guillaume le Floch
    I'm working on an application which use ajax call to get html from the server. When I run it on the server, everything works fine. But when I'm running on a localhost, I've a 'Access-Control-Allow-Origin' error. I looked arround and it seems like using jsonp could be the solution. So, my ajax call looks like that: $.ajax({ url: url, dataType: 'jsonp', crossDomain: true, type: 'GET', success: function(data){ // should put the data in a div }, error: function(){ //do some stuff with errors } }); I get html from the server, but I always have this error: Uncaught SyntaxError: Unexpected token < Is there a way to wrap the jsonp response in html? Thanks!

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  • facebook connect error

    - by coure06
    I am getting error but empty statusText, here is my code var ajaxUrl = 'https://graph.facebook.com/me?access_token=' + accessToken $.ajax({ url: ajaxUrl, dataType: 'json', success: function(user){ alert('h'); }, error: function(xhr, ajaxOptions, thrownError){ alert(xhr.statusText); } });

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  • Closest previous element with certain ID (with prev())?

    - by mathon12
    I have a big div wit a lot of smaller divs within it. Say, <div id="parent"> <div id="child1"> </div> <div id="child1"> </div> <div id="child2"> </div> <div id="child1"> </div> <div id="child1"> </div> </div> If I'm currently at the last 'child1', how dow I get to the top most child1 with prev()? For me it breaks when it reaches 'child2'.

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  • Basic javascript function

    - by McDan Garrett
    I have this function working <script type="text/javascript"> $(window).scroll(function() { if ($(window).scrollTop() == $(document).height() - $(window).height()) { $('div#loadmoreajaxloader').show(); $.ajax({ url: "loadmore.php?wall=<?php echo $wall; ?>&lastid=" + $(".postitem:last").attr("id"), success: function(html) { if (html) { $("#postswrapper").append(html); $('div#loadmoreajaxloader').hide(); } else { $('div#loadmoreajaxloader').html('<center><font color="white">No more posts to show.</font></center>'); } } }); } }); </script> But I need to have the same stuff happening (on IOS Devices), but instead of it happening when the browser reaches the loadmoreajaxeloader div, I simply need it to happen on an onclick event on a link. Thanks heaps. Tried to add code but didn't format so here it is http://pastebin.com/p2VUqZff

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  • It is only uploading first row's file input

    - by user1304328
    I have a application which you can access here. If you open the application please click on the "Add" button a couple of times. This will add a new row into a table below. In each table row there is an AJAX file uploader. Now the problem is that if I click on the "Upload" button in any row except the first row, then the uploading only happens in the first row so it is only uploading the first file input only. Why is it doing this and how can I get it so that when then the user clicks the "Upload" button, the file input within that row of the "Upload" button is uploaded and not the first row being uploaded? Below is the full code where it appends the file AJAX file uploaded in each table row: function insertQuestion(form) { var $tbody = $('#qandatbl > tbody'); var $tr = $("<tr class='optionAndAnswer' align='center'></tr>"); var $image = $("<td class='image'></td>"); var $fileImage = $("<form action='upload.php' method='post' enctype='multipart/form-data' target='upload_target' onsubmit='startUpload();' >" + "<p id='f1_upload_process' align='center'>Loading...<br/><img src='Images/loader.gif' /><br/></p><p id='f1_upload_form' align='center'><br/><label>" + "File: <input name='fileImage' type='file' class='fileImage' /></label><br/><label><input type='submit' name='submitBtn' class='sbtn' value='Upload' /></label>" + "</p> <iframe id='upload_target' name='upload_target' src='#' style='width:0;height:0;border:0px solid #fff;'></iframe></form>"); $image.append($fileImage); $tr.append($image); $tbody.append($tr); } function startUpload(){ document.getElementById('f1_upload_process').style.visibility = 'visible'; document.getElementById('f1_upload_form').style.visibility = 'hidden'; return true; } function stopUpload(success){ var result = ''; if (success == 1){ result = '<span class="msg">The file was uploaded successfully!<\/span><br/><br/>'; } else { result = '<span class="emsg">There was an error during file upload!<\/span><br/><br/>'; } document.getElementById('f1_upload_process').style.visibility = 'hidden'; document.getElementById('f1_upload_form').innerHTML = result + '<label>File: <input name="fileImage" type="file"/><\/label><label><input type="submit" name="submitBtn" class="sbtn" value="Upload" /><\/label>'; document.getElementById('f1_upload_form').style.visibility = 'visible'; return true; }

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  • how to facebook shoutbox open , with clicked friendname

    - by Surendra Singh
    Hey everyone i need source code for shotbox open with clicked friend name like facebook i tried it but ... it is opening with only one friend name .... i want it will open with the name of friend whom name or image is clicked My code is something like this <tr data-name="<?php echo $online_user_name; ?>"> <td> <div <?php echo $online_user_id; ?>"> <img src="../../social_users/<?php echo $online_user_gender; ?>/<?php echo $online_user_Email; ?>/Profile/<?php echo $online_user_pic; ?>" height="30" width="30" style="border-radius: 20px; border: 2px solid #fff;" onclick="shoutbox_open();"> </div> </td> <td style="color:#ffffff;"> <div <?php echo $online_user_id; ?> style="text-transform:capitalize; text-decoration:none; color:#6A7480;" onclick="shoutbox_open();"> <?php echo $online_user_name; ?> </div> &nbsp; </td> <td> <img src="background_file/background_icons/online_symbol.png" /> </td> </tr> <div id="shout_box"> <div id="header" > <span> <?php echo $online_user_name; ?> </span> <div id="close_btn" onclick="shoutbox_close();"> &nbsp; </div> </div> <div id="toggle_chat"> <div id="message_box"> </div> <div id="user_info"> <input name="shout_username" id="shout_username" type="text" placeholder="Your Name" value="" maxlength="15" /> <input name="shout_message" id="shout_message" type="text" placeholder="Type Message Hit Enter" maxlength="100" /> </div> </div> </div>

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  • Parsing XML in Javascript getElementsByTagName not working

    - by Probocop
    Hi, I am trying to parse the following XML with javascript: <?xml version='1.0' encoding='UTF-8'?> <ResultSet> <Result> <URL>www.asd.com</URL> <Value>10500</Value> </Result> </ResultSet> The XML is generated by a PHP script to get how many pages are indexed in Bing. My javascript function is as follows: function bingIndexedPages() { ws_url = "http://archreport.epiphanydev2.co.uk/worker.php?query=bingindexed&domain="+$('#hidden_the_domain').val(); $.ajax({ type: "GET", url: ws_url, dataType: "xml", success: function(xmlIn){ alert('success'); result = xmlIn.getElementsByTagName("Result"); $('#tb_actualvsindexedbing_indexed').val($(result.getElementsByTagName("Value")).text()); $('#img_actualvsindexedbing_worked').attr("src","/images/worked.jpg"); }, error: function() {$('#img_actualvsindexedbing_worked').attr("src","/images/failed.jpg");} }); } The problem I'm having is firebug is saying: 'result.getElementsByTagName is not a function' Can you see what is going wrong? Thanks

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  • Livevalidation: only validate when default value is changed

    - by usr122212
    Hello there! I am validating my html form with livevalidation and everything works great except for one feature. I have a input field with a default value age, I only want the livevalidation to validate when it says something other than "age". so maybe the user will type in 20 then the validation will fire checking its things but if left as "age" it won't check it all. But as of now, it just checks everything with a validation script and this is a problem for me as I have lots of fields in my form and some of them are optional so when I hit submit, the livevalidation checks the age field as well even if the user didnt touch it to begin with. Would this be possible with livevalidation ? Thanks for the help.

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  • How to change src (ajax ref in options (events: 'href') when calling refetchEvents

    - by Martin Glynn
    My site is for listing theatrical productions (http://theaterOnline.com) I want to use a drop down list to enable users to filter the listings by location or genre. The following code refreshes the screen: $("#cfilter").change(function() { $('#calendar').fullCalendar('refetchEvents' ) }) but I need to be able to change SRC in the ajax call below: $.ajax({ url: src, dataType: 'json', data: params, cache: options.cacheParam || false, success: reportEventsAndPop}) which is a passed parameter from eventSources[1] TIA for anyone who can help!

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  • Form submits but by passing the form validation when button.click is used

    - by Cuty Pie
    I am using form validation plugin as well as html5 attribute=recquired with input type=button or submit and fancybox.when button is clicked ,both validation proceedures work(notification of empty inputs appeare),but instead of this notification ,form is submitted. If I dont use button.click function but use simple submit.then validation works perfectly plugin==http://validatious.org/ javascript function $(document).ready(function() { $('#send').click(function() { $(this).attr("value", 'Applying...'); var id = getParam('ID'); $.ajax({ type:'POST', url:"send.php", data:{option:'catapply', tittle:$('#tittle').val(), aud:aud, con:con, adv:adv, mid:$('#mid').val(), aud2:aud, cid:$('#cid').val(), scid:$('#scname option[selected="saa"]').val(), gtt:$('input[name=gt]:radio:checked').val(), sr:$(":input").serialize() + '&aud=' + aud}, success:function(jd) { $('#' + id).fadeOut("fast", function() { $(this).before("<strong>Success! Your form has been submitted, thanks :)</strong>"); setTimeout("$.fancybox.close()", 1000); }); } }); }); }); AND Html is here <form id="form2" class="validate" style="display: none" > <input type='submit' value='Apply' id="send" class="sendaf validate_any" name="jobforming"/>

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  • Mouseup not working after mousemove on img

    - by leyou
    I'm trying to do a simple drag script. The idea is to save the position when the mouse is down, update the view while the mouse is moving, and stop when mouse is up. Problem, mouseup event isn't working properly. See the code: var target = $('a') var pos = 0; var dragging = false; $(document).mousedown(function(e) { pos=e.pageX; dragging = true }) $(document).mouseup(function() { dragging = false }) $(document).mousemove(function(e) { if(dragging){ target.css('left', e.pageX-pos); } }) ? Why mouseup works with a "a" tag: http://jsfiddle.net/leyou/c3TrG/1/ And why mouseup doesn't work with a "img" tag: http://jsfiddle.net/leyou/eNwzv/ Just try to drag them horizontally. Same probleme on ie9, ff and chrome.

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  • ProgressBar while transferring data from Excel sheet to SQL database table

    - by Sagar patel
    Can anyone tell me how to show animated progress bar while the data from an Excel sheet to a SQL database table is being transfered? I have a form in .aspx page. In that form, there is one FileUpload control that uploads an Excel file. While uploading that file and saving it on the server at the same time I'm transferring the data from the Excel sheet to a SQL table. During this transfer, I want to show a ProgressBar and after transferring all data it will be removed automatically.. Is there something I can do to achieve this?

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  • Inherit all methods of object (including "constructor"), but modify some of them.

    - by Kirzilla
    Hello, Let's imagine that we have object Animal $.Animal = function(options) { this.defaults = { name : null } this.options = $.extend(this.defaults, options); } $.Animal.prototype.saySomething = function() { alert("I'm animal!"); } Now I'd like to create Cat object. It is absolutely similar to $.Annimal, but method saySomething() will look like this one... $.Cat.prototype.saySomething = function() { alert("I'm cat!"); } How can I inherit from Animal to create new object Cat and redefine saySomething() method? Thank you.

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  • Using Uploadify, I'm renaming uploaded files via uploadify.php, how do I get the check script to now check for this renamed file??

    - by Rob Macintosh
    I've modified my uploadify.php file to rename my uploaded files, i'm appending them with my clients company name. As you can see i'm using scriptData to set the company name, so that uploadify.php can use it. documents.php 'scriptData': { 'PHPSESSID': '<?php echo session_id();?>', 'client_company': '<?php echo $_SESSION['company'] . "-";?>' }, This all works great - but now it breaks my check.php. I'm using the default check script, but now it simply thinks the file doesn't exist, so it overwrites it. I've tried appending the client_company POST variable to the file check; check.php $fileArray = array(); foreach ($_POST as $key => $value) { if ($key != 'folder') { if (file_exists($_SERVER['DOCUMENT_ROOT'] . $_POST['folder'] . '/' . $_POST['client_company'] . $value)) { $fileArray[$key] = $value; } } } echo json_encode($fileArray); But it doesn't work :( Can anyone help?

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  • How to write this in a simpler less ridiculous way

    - by Richard Knop
    This just seems absurd to me. Should I use array instead or is there some other better solution? $('.hoursRange').change(function() { if ('0' == $(this).val()) { $(this).val('00'); return false; } if ('1' == $(this).val()) { $(this).val('01'); return false; } if ('2' == $(this).val()) { $(this).val('02'); return false; } if ('3' == $(this).val()) { $(this).val('03'); return false; } if ('4' == $(this).val()) { $(this).val('04'); return false; } if ('5' == $(this).val()) { $(this).val('05'); return false; } if ('6' == $(this).val()) { $(this).val('06'); return false; } if ('7' == $(this).val()) { $(this).val('07'); return false; } });

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