How do I open a file with a program via a shortcut from the cmd prompt
- by PassByReference0
Here's my predicament:
When I add a program's location to my PATH, I can do the following in cmd prompt to open a file in my current directory:
notepad++ open_me.txt
And this opens open_me.txt in notepad++.
However, I don't want to have to add every single program I want to run to my path. What I want is to add a folder called C:\Users\Me\Documents\Programs to my path and just drop shortcuts to various programs into that folder and have them function the same as adding them to my path.
So I dropped a link to notepad++.exe named "np" in my folder, and what I got was this:
I have to run it with start np (instead of just np)
But more importantly, if I try start np open_me.txt, it opens notepad++.exe but looks for open_me.txt in notepad++'s directory.
How can I do this properly? (Also, I'd like to be opening notepad++.exe with the shortened name of np)
