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  • undefined reference

    - by rantravee
    Hi, I'm unfamiliar to working in c++ under linux so I have some issues, one of them is that after I write a class and try to instantiate an object of that class I get to following error : "undefined reference to Constructor_of_that_class" . This happens for every class that I write , and it happens no matter where I try to do the instantiating, even if the code compiles without any problems . What is going wrong here and what I have to do to get over this error ? Because the project that I'm working wasn't created by me I suspect that it has to do something with some settings but I don't know which.

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  • Zend Framework modular app, can't load models for each module, autoloading models?

    - by EricP
    Is there a way to have models for each module? I have 3 modules, one is a "contacts" module. I created a model for it in modules/contacts/models/Codes.php Codes Controller class Contacts_CodesController extends Zend_Controller_Action { public function init() { /* Initialize action controller here */ $this->view->messages = $this->_helper->flashMessenger->getMessages(); } public function indexAction() { $codesTable = new Contacts_Model_Codes(); } Codes Model: class Contacts_Model_Codes extends Zend_Db_Table { protected $_name = 'codes'; } The error I get: Fatal error: Class 'Contacts_Model_Codes' not found in /Applications/MAMP/htdocs/zf_site/application/modules/contacts/controllers/CodesController.php on line 26 thanks

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  • Hibernate Bi-Directional ManyToMany Updates with Second Level cache

    - by DD
    I have a bidirectional many-to-many class: public class A{ @ManyToMany(mappedBy="listA") private List<B> listB; } public class B{ @ManyToMany private List<A> listA; } Now I save a listA into B: b.setListA(listA); This all works fine until I turn on second-level caching on the collection a.ListB. Now, when I update the list in B, a.listB does not get updated and remains stale. How do you get around this? Thanks, Dwayne

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  • Exception while trying to deserialize JSON into EntityFramework using JavaScriptSerializer

    - by Barak
    I'm trying to deserialize JSON which I'm getting from an external source into an Entity Framework entity class using the following code: var serializer = new JavaScriptSerializer(); IList<Feature> obj = serializer.Deserialize<IList<Feature>>(json); The following exception is thrown: Object of type 'System.Collections.Generic.List1[JustTime.Task]' cannot be converted to type 'System.Data.Objects.DataClasses.EntityCollection1[JustTime.Task]'. My model is simple: The Feature class has a one-to-many relation to the Tasks class. The problem appears to be the deserializer is trying to create a generic List to hold the collection of tasks instead of an EntityCollection. I've tried implementing a JavaScriptConverted which would handle System.Collections.Generic.List but it didn't get called by the deserializer.

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  • Returning a collection of objects from a webmethod

    - by Narmatha Balasundaram
    How do I return a collection of objects from a webmethod? And can this collection of objects be of different types - say of these 3 classes, private class ClassA { int A1; int A2; } private class ClassB { int B1; } private class ClassC { int C1; } ClassA objA = new ClassA(...); ClassB objB = new ClassB(...); ClassC objC = new ClassC(...); How can I return the objects, objA, objB and objC from a method?

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  • Generic extension method returning IEnumerable<T> without using reflection

    - by roosteronacid
    Consider this snippet of code: public static class MatchCollectionExtensions { public static IEnumerable<T> AsEnumerable<T>(this MatchCollection mc) { return new T[mc.Count]; } } And this class: public class Ingredient { public String Name { get; set; } } Is there any way to magically transform a MatchCollection object to a collection of Ingredient? The use-case would look something like this: var matches = new Regex("([a-z])+,?").Matches("tomato,potato,carrot"); var ingredients = matches.AsEnumerable<Ingredient>();

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  • When a li is appended, does it not become a part of the ul "for real"?

    - by Noor
    I have right now this code: <ul><li class="listitem">text<li></ul> jQuery: $('.listitem').click(function() { $("#elname").text($(this).text()); $('#slists').css('visibility','hidden') $('#elname').css('visibility','visible') $('#elname').css('display','inline-block') }); This is supposed to hide a div and it does, but when I append items to the ul (with the class listitem) nothing happens with the appended item, the class it gets is correct, the title, and the value too. Can this have something to do with the code above being in the document ready function to do?

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  • cakePHP: Filter selected list by variable

    - by gonzela2006
    I'm on cakePHP 2. I have a problem and I need your help. Here is some code of my controller(StudentsController.php) specifically "edit" function: $students = $this -> Student -> find('list', array( 'order' => 'Student.name ASC' )); $this -> set('students', $students); How can I filter the list by the current student's class?? so the list will contain all students that has the same student's class I need some code like this $students = $this -> Student -> find('list', array( 'conditions' => array('Student.class_id' => CURRENT-STUDENT'S-CLASS), 'order' => 'Student.name ASC' )); $this -> set('students', $students); Please Advise Thanks, gonzela2006

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  • NoClassDefFound error - Spring JDBC

    - by glowcoder
    Right now, I'm compiling my .class files in eclipse and moving them over to my %tomcat_home%\webapps\myapp\WEB-INF\classes directory. They compile just fine. I also have in the ...\classes directory a org.springframework.jdbc-3.0.2.RELEASE.jar which I have verified has the org.springframework.jdbc.datasource.DriverManagerDataSource class inside it. However, I get a NoClassDefFound error when I run my class and it tries to DriverManagerDataSource source = new DriverManagerDataSource(); I don't understand why it wouldn't be finding that jar. Any help is appreciated!

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  • c#, Internal, and Reflection

    - by cyberconte
    Duplicate of: Accessing internal members via System.Reflection? Is there a way to execute "internal" code via reflection? Here is an example program: using System; using System.Reflection; namespace ReflectionInternalTest { class Program { static void Main(string[] args) { Assembly asm = Assembly.GetExecutingAssembly(); // Call normally new TestClass(); // Call with Reflection asm.CreateInstance("ReflectionInternalTest.TestClass", false, BindingFlags.Default | BindingFlags.CreateInstance, null, null, null, null); // Pause Console.ReadLine(); } } class TestClass { internal TestClass() { Console.WriteLine("Test class instantiated"); } } } Creating a testclass normally works perfectly, however when i try to create an instance via reflection, I get a missingMethodException error saying it can't find the Constructor (which is what would happen if you tried calling it from outside the assembly). Is this impossible, or is there some workaround i can do?

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  • Where is BuildConfig.DEBUG?

    - by Ollie C
    My project doesn't seem to be aware of this new constant that's apparently auto-generated in Android Tools r17 builds: "Added a feature that allows you to run some code only in debug mode. Builds now generate a class called BuildConfig containing a DEBUG constant that is automatically set according to your build type. You can check the (BuildConfig.DEBUG) constant in your code to run debug-only functions such as outputting debug logs." I've confirmed that this class is not being auto-generated anywhere in my project by the new tools. I deleted all project outputs (including all gen folders) and rebuilt, and only R.java classes are being generated. Why are the tools not generating the BuildConfig class? It may be relevant that I'm using IntelliJ.

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  • How can I dispose of an object (say a Bitmap) when it becomes orphaned ?

    - by Jelly Amma
    I have a class A providing Bitmaps to other classes B, C, etc. Now class A holds its bitmaps in a ring queue so after a while it will lose reference to the bitmap. While it's still in the queue, the same Bitmap can be checked out by several classes so that, say, B and C can both hold a reference to this same Bitmap. But it can also happen that only one of them checked out the Bitmap or even none of them. I would like to dispose of the bitmap when it's not being needed any more by either A, B or C. I suppose I have to make B and C responsible for somehow signaling when they're finished using it but I'm not sure about the overall logic. Should it be a call to something like DisposeIfNowOrphan() that would be called : 1 - when the Bitmap gets kicked out of the queue in class A 2 - when B is finished with it 3 - when C is finished with it If that's the best strategy, how can I evaluate the orphan state ? Any advice would be most welcome.

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  • Trying to understand MVC Models, Advice?

    - by Tyler
    I am writing my own MVC for the purpose of learning it. I have pretty much everything "down-pat" and my main stuff written besides models due to some trouble understanding them and lack of viable examples. Now, I've been told a model should reprecent a single row, someone told me, your model class should on update/insert and delete rows, anything that involves fetching a single or multiple rows - a "finder" class should be used. So... a) what is a finder class, b) how do I implement it in a useage example, c) Is what I've been told about models correct or is there a better way than "finders"? Advice is much appricated :)

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  • Building a wiki like data model in rails question.

    - by lillq
    I have a data model in which I would like to have an item that has a description that can be edited. I would like to also keep track of all edits to the item. I am running into issues with my current strategy, which is: class Item < ActiveRecord::Base has_one :current_edit, :class_name => "Edit", :foreign_key => "current_edit_id" has_many :edits end class Edit < ActiveRecord::Base belongs_to :item end Can the Item have multiple associations to the same class like this? I was thinking that I should switch to keeping track of the edit version in the Edit object and then just sorting the has_many relationship base on this version.

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  • Is it possible to group validation?

    - by lambdabutz
    I am using a lot of my own validation methods to compare the data from one association to the other. I've noticed that I'm constantly checking that my associations aren't nil before trying to call anything on them, but I am also validating their presence, and so I feel that my nil checks are redundant. Here's an example: class House < ActiveRecord::Base has_one :enterance, :class => Door has_one :exit, :class => Door validates_presence_of :enterance, :exit validate :not_a_fire_hazard def not_a_fire_hazard if enterance && exit && enterance.location != exit.location errors.add_to_base('If there is a fire you will most likely die') return false end end end I feel like I am repeating myself by checking the existence of enterance and exit within my own validation. Is there a more "The Rails Way" to do this?

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  • Remapping design issue

    - by Sirupsen
    Hello, I'm currently developing a Ruby Gem and I'm a bit lost on the design currently. Basically, I'm remapping some APIs, so my skeleton is something like this: module MyApp module SomeApi class Function > Base::Function ... end class Function2 > Base::Function2 ... end ... end module SomeApi2 ... end class RemappedFunction def initalize # set some values and stuf ... end def remapped_method # Problem: # How would I know, if I should take contact to # SomeApi, or SomeApi2? end end def interact_with(api) # What would be the best way of letting RemappedFunction # know which API to use? end end someapi2 = MyApp.interact_with(:someapi2) someapi2.remapped_method Any ideas?

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  • Ruby on Rails: how to render a string as HTML?

    - by Tim
    I have @str = "<b>Hi</b>" and in my erb view: <%= @str > What will display on the page is: <b>Hi</b> when what I really want is Hi. What's the ruby way to "interpret" a string as HTML markup? Edit: the case where @str = "<span class=\"classname\">hello</span>" If in my view I do <%raw @str %> The HTML source code is <span class=\"classname\">hello</span where what I really want is <span class="classname">hello</span> (without the backslashes that were escaping the double quotes). What's the best way to "unescape" those double quotes?

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  • Acts as Tree with Multiple Models

    - by Joe
    I've got several models that I'd like to relate together hierarchically. For simplicity's sake, let's say I've got these three: class Group < ActiveRecord::Base acts_as_tree has_many :users end class User < ActiveRecord::Base acts_as_tree belongs_to :group has_many :posts end class Post < ActiveRecord::Base acts_as_tree belongs_to :user end Under the current acts_as_tree, each node can individually can relate hierarchically to other nodes provided they are of the same type. What I'd like is to remove this restriction on type identity, so that SomePost.parent could have a User or a Post as its' parent, and that SomeUser.parent could have another user or a group as its parent. Any thoughts?

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  • spring mvc forward to jsp

    - by jerluc
    I currently have my web.xml configured to catch 404s and send them to my spring controller which will perform a search given the original URL request. The functionality is all there as far as the catch and search go, however the trouble begins to arise when I try to return a view. <bean class="org.springframework.web.servlet.view.ContentNegotiatingViewResolver" p:order="1"> <property name="mediaTypes"> <map> <entry key="json" value="application/json" /> <entry key="jsp" value="text/html" /> </map> </property> <property name="defaultContentType" value="application/json" /> <property name="favorPathExtension" value="true" /> <property name="viewResolvers"> <list> <bean class="org.springframework.web.servlet.view.BeanNameViewResolver" /> <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="prefix" value="/WEB-INF/jsp/" /> <property name="suffix" value="" /> </bean> </list> </property> <property name="defaultViews"> <list> <bean class="org.springframework.web.servlet.view.json.MappingJacksonJsonView" /> </list> </property> <property name="ignoreAcceptHeader" value="true" /> </bean> This is a snippet from my MVC config file. The problem lies in resolving the view's path to the /WEB-INF/jsp/ directory. Using a logger in my JBoss setup, I can see that when I test this search controller by going to a non-existent page, the following occurs: Server can't find the request Request is sent to 404 error page (in this case my search controller) Search controller performs search Search controller returns view name (for this illustration, we'll assume test.jsp is returned) Based off of server logger, I can see that org.springframework.web.servlet.view.JstlView is initialized once my search controller returns the view name (so I can assume it is being picked up correctly by the InternalResourceViewResolver) Server attempts to return content to browser resulting in a 404! A couple things confuse me about this: I'm not 100% sure why this isn't resolving when test.jsp clearly exists under the /WEB-INF/jsp/ directory. Even if there was some other problem, why would this result in a 404? Shouldn't a 404 error page that results in another 404 theoretically create an infinite loop? Thanks for any help or pointers! Controller class [incomplete]: @Controller public class SiteMapController { //-------------------------------------------------------------------------------------- @Autowired(required=true) private SearchService search; @Autowired(required=true) private CatalogService catalog; //-------------------------------------------------------------------------------------- @RequestMapping(value = "/sitemap", method = RequestMethod.GET) public String sitemap (HttpServletRequest request, HttpServletResponse response) { String forwardPath = ""; try { long startTime = System.nanoTime() / 1000000; String pathQuery = (String) request.getAttribute("javax.servlet.error.request_uri"); Scanner pathScanner = new Scanner(pathQuery).useDelimiter("\\/"); String context = pathScanner.next(); List<ProductLightDTO> results = new ArrayList<ProductLightDTO>(); StringBuilder query = new StringBuilder(); String currentValue; while (pathScanner.hasNext()) { currentValue = pathScanner.next().toLowerCase(); System.out.println(currentValue); if (query.length() > 0) query.append(" AND "); if (currentValue.contains("-")) { query.append("\""); query.append(currentValue.replace("-", " ")); query.append("\""); } else { query.append(currentValue + "*"); } } //results.addAll(this.doSearch(query.toString())); System.out.println("Request: " + pathQuery); System.out.println("Built Query:" + query.toString()); //System.out.println("Result size: " + results.size()); long totalTime = (System.nanoTime() / 1000000) - startTime; System.out.println("Total TTP: " + totalTime + "ms"); if (results == null || results.size() == 0) { forwardPath = "home.jsp"; } else if (results.size() == 1) { forwardPath = "product.jsp"; } else { forwardPath = "category.jsp"; } } catch (Exception ex) { System.err.println(ex); } System.out.println("Returning view: " + forwardPath); return forwardPath; } }

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  • Query multiple models with one value

    - by swoei
    I have multiple models which all have a FK to the same model. All I know is the FK how can I determine which of the models has the FK attached? Below an example to clearify: class ModelA(models.Model): title = models.CharField("title", max_length=80) class ModelB(models.Model): fk = models.ForeignKey(ModelA) class ModelC(models.Model): fk = models.ForeignKey(ModelA) How can I figure out without using a try/except on each model whether B or C has the FK? (The FK can only be in one of them, for the record in this case I only added two models but in the real world app there are multiple possible x amount of models which have the FK to modelA)

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  • How can i see if dealloc is being called on a uikit object, or any object not created by myself

    - by Gyozo Kudor
    I think i have an UIImage that has a higher retain count than it should have and i am probably leaking memory. I use this image as a thumbnail, to set a custom background to a uibutton. So the uibutton is holding a reference to it and so do i. But instead of 2, the retainCount is 3. Do i have to create a custom UIImage derived class and override dealloc if I want to place a log message there and then change the class used from UIImage to my class, or is there an easier way. Thanks in advance.

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  • Anyone using ASP.NET MembershipProvider with Nhibernate?

    - by JLago
    Hi, I'm trying to implement Membership controls in a mvc 2 application and i'm having trouble dealing with the MembershipUser class. I have my own data store (in Postgresql) and I'm using Nhibernate to deal with it from C#. The thing is, I have my own user class, but I can't use it with any provider I found that implements Membership, because all the functions return the predefined MembershipUser class and cannot return my own. I'm losing my mind here, is there any way i can work with this, or should I implement everything myself? thanks in advance!

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  • C# Using singleton instead of a global static instance

    - by Farstucker
    I ran into a problem today and a friend recommended I use a global static instance or more elegantly a singleton pattern. I spent a few hours reading about singletons but a few things still escape me. Background: What Im trying to accomplish is creating an instance of an API and use this one instance in all my classes (as opposed to making a new connection, etc). There seems to be about 100 ways of creating a singleton but with some help from yoda I found some thread safe examples. ..so given the following code: public sealed class Singleton { public static Singleton Instance { get; private set; } static Singleton() { Instance = new Singleton(); } } How/Where would you instantiate the this new class and how should it be called from a separate class? Thanks for your help.

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  • Overriding fetch in multiple spine models

    - by Adam Charnock
    I need to override Spine's @fetch() method in all of my Spine models. Currently I have code duplication as follows: TastypieEndpointMixin = fromJSON: (data) -> return unless data return Spine.Model.fromJSON(data.objects) class App.models.Position extends Spine.Model @configure 'Position', 'code', 'name' @extend Spine.Model.Ajax @extend TastypieEndpointMixin @url: '/api/v1/position/?format=json' validate: -> 'code is required' unless @code @fetch: -> defer = $.Deferred() @one "refresh", -> defer.resolve() super return defer class App.models.Player extends Spine.Model @configure 'Player', 'first_name', 'last_name', ... @extend Spine.Model.Ajax @extend TastypieEndpointMixin @url: '/api/v1/player/?format=json' @fetch: -> defer = $.Deferred() @one "refresh", -> defer.resolve() super return defer My question is: How can I create some form of parent class which contains @fetch()? I know this should be a simple problem to solve. I have tried many options (including extending Spine.Model and Spine.Model.Ajax), but nothing works and I cannot seem to get my head around it.

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  • ActionScript/Flex: Augment MouseEvents with extra information

    - by David Wolever
    I've got a business class, Spam and the corresponding view class, SpamView. How can I augment MouseEvents coming out of SpamView so the MouseEvents which come out of it contain a reference to the instance of Spam which the SpamView is displaying? Here's how I'd like to use it: class ViewContainer { ... for each (spam in spams) { addChild(new SpamView(spam)); ... function handleMouseMove(event:MouseEvent) { if (event is SpamViewMouseEvent) trace("The mouse is being moved over spam:", spam) } } Thanks! Things I've considered which don't work: Adding event listeners to each SpamView: the book keeping (making sure that they are added/removed properly) is a pain. Using event.target: the event's target may be a child of the SpamView (which isn't very useful) Listening for a MouseEvent, creating a new SpamViewMouseEvent, copying all the fields over, then dispatching that: copying all the fields manually is also a pain.

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