Search Results

Search found 92550 results on 3702 pages for 'server variables'.

Page 564/3702 | < Previous Page | 560 561 562 563 564 565 566 567 568 569 570 571  | Next Page >

  • Why is fulltextsearch for phrase ignored in SQL Server?

    - by cpt.oneeye
    I am executing the following SQL statement on an indexed SQL Server 2008 R2 database. SELECT * FROM mydatabase WHERE (CONTAINS(ColumnA,'"The Apple is red"')) The problem is that it returns too many entries. It also returns entries where 'ColumnA' contains only one of the words ('Apple' or 'is' or 'red'...) and not only the entries which contains the exact phrase. According to MSDN this should be the way to search for a phrase. Thanks cpt.oneeye

    Read the article

  • Variable type for Application on Time Events [on hold]

    - by user2931226
    Been Trying to figure out how to go about setting a Variable for some Application On Time events, But still not confident to do it. These events (Macro's) get called by another Macro then they wait for 10 - 20 minutes, then they don't Run. So have read that (EarliestTime argument) should be assigned to a variable to store it other wise it looses it when other things are running Help appreciated Thanks Sub settimers() Application.OnTime TimeValue(Range("$X$9").Text), "StartBlink" Application.OnTime TimeValue(Range("$W$11").Text), "StopBlink" End Sub

    Read the article

  • Adding extra data to a Variable

    - by DogPooOnYourShoe
    Right now, my code plucks out only one value using Mysql. So I thought I might aswell add each found result to a variable, however I dont know how to do this. This must be a very basic question, but I cant find a answer for it echo '<table border="1">'; echo "<tr><td><b>Surname</b></td><td><b>Title/Name</b></td><td><b>Numbers</b></td><td><b>Telephone</b></td><td><b>Edit</b></td><td><b>Del</b></td></tr>\n"; while ($row= mysql_fetch_array($result)) { $Surname = $row["Surname"]; $Title = $row["TitleName"]; $Email = $row["Email"]; $Telephone = $row["Telephone"]; $id = $row["id"]; $MooringNumbers = $row['Number']; $Assignedto['AssignedTo']; } $MooringQuery = "select * FROM mooring WHERE AssignedTo='$id'"; $MooringResult = mysql_query($MooringQuery) or die("Couldn't execute query"); while ($row1= mysql_fetch_array($MooringResult)) { $AssignedTo = $row1["AssignedTo"]; $MooringNumbers = $row1["Number"]; echo '<tr><td>' .$Surname.'</td><td>'.$Title.'</td><td>'.$MooringNumbers . '</td><td>'.$Telephone.'</td><td>' . '<a href="rlayCustomerUpdtForm.php?id='.$id.'">[EDIT]</a></td>'.'<td>'. '<a href="deleteCustomer.php?id='.$id.'">[x]</a></td>'. '</tr>'; }

    Read the article

  • Variable not accessible within an if statment

    - by Chris
    I have a variable which holds a score for a game. My variable is accessible and correct outside of an if statement but not inside as shown below score is declared at the top of the main.cpp and calculated in the display function which also contains the code below cout << score << endl; //works if(!justFinished){ cout << score << endl; // doesn't work prints a large negative number endTime = time(NULL); ifstream highscoreFile; highscoreFile.open("highscores.txt"); if(highscoreFile.good()){ highscoreFile.close(); }else{ std::ofstream outfile ("highscores.txt"); cout << score << endl; outfile << score << std::endl; outfile.close(); } justFinished = true; } cout << score << endl;//works

    Read the article

  • xargs command works on ubuntu, but not mac

    - by Corey Hart
    I have the following line of code that I use to update my personal date variable in my projects to todays current date. This line works in Ubuntu's terminal, but the Mac terminal seems to be far behind. Unfortunately, I copied this snippet from some site, so I'm not sure how it exactly works. Suggestions? grep -ilr --exclude=revar.sh --exclude=README.md "[DATE]" * | grep -v .git | xargs -i@ sed -i "s/\[DATE\]/${today}/g" @

    Read the article

  • DOS Batch file - Copy file based on filename elements

    - by user1848356
    I need to sort alot of files based on their filename. I would like to use a batch file to do it. I do know what I want but I am not sure of the correct syntax. Example of filenames I work with: (They are all in the same directory originally) 2012_W34_Sales_Store001.pdf 2012_W34_Sales_Store002.pdf 2012_W34_Sales_Store003.pdf 2012_November_Sales_Store001.pdf 2012_November_Sales_Store002.pdf 2012_November_Sales_Store003.pdf I would like to extract the information that are located between the "_" signs and put them into a different variable each time. The lenght of the informations contained between the _ signs will be different everytime. Example: var1="2012" var2="W34" (or November) var3="Sales" var4="001" If I am able to do this, I could then copy the files to the appropriate directory using move %var1%_%var2%_%var3%_%var4%.pdf z:\%var3%\%var4%\%var1%\%var2% It would need to loop because I have Store001 to Store050. Also, there are not only Sales report, many others are available. I hope I am clear. Please help me realize this batchfile!

    Read the article

  • using key/value collection in session

    - by jumpdart
    Question: What is a good datatype to keep in session for a large collection of keys and values to frequently reference and update? Application: Updating an old .NET web app with a million pages and grids to have all the grids maintain their sort. They currently access helper code to format themselves graphically on load and on sort. I figured I could add to that code to check for a key based on the page and grid id in a collection in session to see if it has a previous expression on load. and the on sort update/add its appropriate item in the collection. Thoughts? Dictionary vs NameValueCollection

    Read the article

  • Exporting an Environment Variable in Ruby

    - by wilhelmtell
    How do I export an environment variable from within a Ruby script to the parent shell? For example, implementing a naïve implementation of the /usr/bin/read utility: #!/usr/bin/ruby varname = ARGV[0] ENV[varname] = STDIN.gets # but have varname exported to the parent process

    Read the article

  • C++ Beginner - Trouble using structs and constants!

    - by Francisco P.
    Hello everyone! I am currently working on a simple Scrabble implementation for a college project. I can't get a part of it to work, though! Check this out: My board.h: http://pastebin.com/J9t8VvvB The subroutine where the error lies: //Following snippet contained in board.cpp //I believe the function is self-explanatory... //Pos is a struct containing a char, y, a int, x and an orientation, o, which is not //used in this particular case void Board::showBoard() { Pos temp; temp.o = 0; for (temp.y = 'A'; temp.y < (65 + TOTAL_COLUMNS); ++temp.y) { for (temp.x = 1; temp-x < (1 + TOTAL_ROWS); ++temp.x) { cout << _matrix[temp].getContents(); } cout << endl; } } The errors returned on compile time: http://pastebin.com/bZv7fggq How come the error states that I am trying to compare two Pos when I am comparing chars and ints? I also really can't place these other errors... Thanks for your time!

    Read the article

  • define global in a python module from C api

    - by wiso
    Sorry for the trivial question, but I can't find this infomation from the manual. I am developping a module for python using C api; how can I create a variabile that is seen as global from python? For example if my module is module I want to create a variable g that do this job: import module print module.g in particular g is an integer. Solution from Alex Martelli PyObject *m = Py_InitModule("mymodule", mymoduleMethods); PyObject *v = PyLong_FromLong((long) 23); PyObject_SetAttrString(m, "L", v); Py_DECREF(v);

    Read the article

  • is there a way to add a variable/property to a DOM element (eg, an element returned by a jQuery sele

    - by bt
    Hi there, I am looking for an alternative to using an object/variable in global scope -- I would like to associate key/value pairs with specific DOM elements (eg, a DIV), so that I can use them as input for logic that processes other elements (eg, child elements of said DIV). I tried something naive like: $('[foo=bar]').key='value' , and $('[foo=bar]')[key]='value', but it puked. Doing something like: var foobar = $('[foo=bar]'); foobar.key = 'value' -- works, but the new property/value only affects the new object (ie, foobar, not $('[foo=bar]')) Most likely there's something terribly basic I am overlooking. Any help is appreciated, thanks!

    Read the article

  • odd behavior setting timeouts inside a function with global references in javascript

    - by Pablo
    Here is the the function and the globals: $note_instance = Array(); $note_count = 0; function create(text){ count = $note_count++; time = 5000; $note_instance[count] = $notifications.notify("create", text); setTimeout(function(){ $note_instance[count].close() }, time); } The function simply opens a notification, a sets a timeout to close it in 5 seconds. so if i call this create("Good Note 1"); create("Good Note 2"); create("Good Note 3"); Ecah note should close 5 seconds from their creation, however always and only the last note closes, in this case "Good Note 3". Each note object has its own entry in the the $note_instance global array so the timeouts should no be overwriting themselves. What am i missing here folks? Thanks in advance

    Read the article

  • How to set result of function as global variable.

    - by George
    I'm sure this is really simple and I'm drawing a giant blank, but how do you set the result of a function as a global variable? Example, I want to set the first "color" in array "colors" as global variable "color" (I know the example doesn't make much practical sense, but it's just to illustrate my question): var color = ""; function selectColor () { var colors = ["blue","red","green","yellow"]; var color = colors[0]; return color; } window.onload = function () { selectColor (); alert(color); }

    Read the article

  • jQuery ajax return value

    - by Jordan Pagaduan
    How can I return the value "pinNumber" from jquery ajax so I can append it outside of the ajax. Here is my code var x = pinLast + 1; for(i=x;i<=pinMany;i++) { var i = x++; var cardNumber = i.toPrecision(8).split('.').reverse().join(''); var pinNumber = ''; jQuery.ajax({ type: "POST", url: "data.php", data: "request_type=generator", async: false, success: function(msg){ var pinNumber = msg; return pinNumber; //pin number should return } }); jQuery('.pin_generated_table').append(cardNumber+' = '+pinNumber+''); // the variable pinNumber should be able to go here } Please ask me if you don't understand.. ^^ thanks

    Read the article

  • python objects confusion

    - by james
    wow i thought i knew python untill tonight.. what is the correct way to do something like this.. heres my code a = ["one", "two", "three"] b = a #here i want a complete copy that when b is changed, has absolutely no effect on a b.append["four"] print a #a now has "four" in it.. so basically i want to know, instead of the b = a step, how would i correctly make a copy of a list or dictionary so that when b is changed a does not change along with it.. thanks guys

    Read the article

  • How can I use a value of JSP in Javascript code?

    - by novellino
    Hello, I have a list of elements, each of them appeared in my page through jsp. So I have this: <div id="title"><%= list.get(ind).getTitle() %></div> When I display the elements, as this tag is in for loop, I get everything right. Now I what to place a button for deleting each of this elements. What I have done is: <input type="submit" name="submit" onclick="deleteNewsFunction();" id="submit_btn"/> In the deleteNewsFunction() I just want to print the data. <script> function deleteNewsFunction(){ var item = $('#title').val(); alert(item); } </script> The problem is that the title var gets always the first item even if I am clicking on the button of the second item. I was thinking that maybe a solution is to add the "list.get(ind).getTitle()" as a parameter in the function like deleteNewsFunction(<%=list.get(ind).getTitle()%) but then it did not work at all. Does anyone know how to help me? Thanks a lot!

    Read the article

  • How can I draw a line with a variable of width?

    - by user1729944
    #include <iostream> #include <cmath> #include "graph1.h" using namespace std; int main() { int diameter = 0; int height = 0; double rate = 0; char repeat = 'y'; int obj_num = 0; displayGraphics(); obj_num = drawRect(0,0,50,400); setColor(obj_num,200,200,200); obj_num = drawRect(0,400,640,79); setColor(obj_num,71,35,35); obj_num = drawLine(50,50,150,50,5); setColor(obj_num,80,80,80); displayBMP("faucet.bmp",150,12); do { do { cout << "Enter the diamater of the cylinder <in inches > 0 but <= 300: "; cin >> diameter; if((diameter<0) || (diameter>300)) { cout << "Incorrect diamater entered; value must be between 1 and 300" << endl; } }while((diameter<0) || (diameter>300)); do { cout << "Enter the height of the cylinder <in inches > 0 but <= 325: "; cin >> height; if((height<0) || (height>325)) { cout << "Incorrect height entered; value must be between 1 and 325" << endl; } }while((height<0) || (height>325)); do { cout << "Enter the facet water's rate: <gallons/minute> "; cin >> rate; if((rate<0) || (rate>100)) { cout << "Incorrect rate entered; value must be between 1 and 100" << endl; } }while((rate<0) || (rate>100)); //I need to draw the lines here. The graphics window has a faucet that is supposed to fill //up a cylinder made out of 3 lines. I don't know how to make the lines vary from the users //input since lines are hard coded with points and all i am receiving is the width for the //bottom line and the height for the left and right lines. cout << "Repeat program? (y/n): "; cin >> repeat; clearGraphics(); }while ( (repeat == 'y') || (repeat == 'Y') ); return 0; } Here is a screenshot for reference:

    Read the article

  • Rails - undefined method `name' for nil:NilClass

    - by sscirrus
    Hi guys, Quick question. Here is my code: #routes map.resources :customers, :has_many => [:addresses, :matchings] map.connect ":controller/:action/:id" #url path: http://127.0.0.1:3000/customers/index/3 #customers controller def index @customer = Customer.find(params[:id]) end #customers view/index.html.erb ... <%= @customer.name %> ... Error: undefined method `name' for nil:NilClass. Here's my reasoning. The parameter :id is coming from my url path (i.e. we're looking for customer #3 in the above path). @customer should find that array easily, then @customer.name should produce the name, but apparently @customer is blank. Why? I assume the problem is that I'm not producing an array in my controller?

    Read the article

< Previous Page | 560 561 562 563 564 565 566 567 568 569 570 571  | Next Page >