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  • Criticise/Recommendations for my code

    - by aLk
    Before i go any further it would be nice to know if there is any major design flaws in my program so far. Is there anything worth changing before i continue? Model package model; import java.sql.*; import java.util.*; public class MovieDatabase { @SuppressWarnings({ "rawtypes", "unchecked" }) public List queryMovies() throws SQLException { Connection connection = null; java.sql.Statement statement = null; ResultSet rs = null; List results = new ArrayList(); try { DriverManager.registerDriver(new com.mysql.jdbc.Driver()); connection = DriverManager.getConnection("jdbc:mysql://localhost:3306/test", "root", "password"); statement = connection.createStatement(); String query = "SELECT * FROM movie"; rs = statement.executeQuery(query); while(rs.next()) { MovieBean bean = new MovieBean(); bean.setMovieId(rs.getInt(1)); bean.setTitle(rs.getString(2)); bean.setYear(rs.getInt(3)); bean.setRating(rs.getInt(4)); results.add(bean); } } catch(SQLException e) { } return results; } } Servlet public class Service extends HttpServlet { @SuppressWarnings("rawtypes") protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { response.setContentType("text/html"); PrintWriter out = response.getWriter(); out.println("Movies!"); MovieDatabase movies = new MovieDatabase(); try { List results = movies.queryMovies(); Iterator it = results.iterator(); while(it.hasNext()) { MovieBean movie = new MovieBean(); movie = (MovieBean)it.next(); out.println(movie.getYear()); } } catch(SQLException e) { } } } Bean package model; @SuppressWarnings("serial") public class MovieBean implements java.io.Serializable { protected int movieid; protected int rating; protected int year; protected String title; public MovieBean() { } public void setMovieId(int movieidVal) { movieid = movieidVal; } public void setRating(int ratingVal) { rating = ratingVal; } public void setYear(int yearVal) { year = yearVal; } public void setTitle(String titleVal) { title = titleVal; } public int getMovieId() { return movieid; } public int getRating() { return rating; } public int getYear() { return year; } public String getTitle() { return title; } }

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  • How can you remove a Criterion from a criteria?

    - by ChuckM
    Hello, For instance if I do something like: Criteria c = session.createCriteria(Book.class) .add(Expression.ge("release",reDate); .add(Expression.ge("price",price); .addOrder( Order.asc("date") ) .setFirstResult(0) .setMaxResults(10); c.list(); How can I use the same criteria instance, but remove (for example) the second criterion? I'm trying to build a dynamic query in which I'd like to let the user remove a filter, without the backend having to reconstruct the criteria from scratch. Thank you

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  • How can you tell which columns are unused in ALL_TAB_COLS?

    - by thecoop
    When you query the ALL_TAB_COLS view on Oracle 9i, it lists columns marked as UNUSED as well as the 'active' table columns. There doesn't seem to be a field that explicitly says whether a column is UNUSED, or any view I can join to that lists the unused columns in a table. How can I easily find out which are the unused columns, so I can filter them out of ALL_TAB_COLS?

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  • Not Inserted into database in PHP script

    - by Aruna
    Hi, i am having an form for uploading an excel file like <form enctype="multipart/form-data" action="http://localhost/joomla/Joomla_1.5.7/index.php?option=com_jumi&fileid=7" method="POST"> Please choose a file: <input name="file" type="file" id="file" /><br /> <input type="submit" value="Upload" /> </form> And in the FIle http://localhost/joomla/Joomla_1.5.7/index.php?option=com_jumi&fileid=7 i have retrived the uploaded file contents by <?php echo "Name". $_FILES['file']['name'] . "<br />"; echo "Type: " . $_FILES["file"]["type"] . "<br />"; echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />"; echo "Stored in: " . $_FILES["file"]["tmp_name"] . "<br />"; $string = file_get_contents( $_FILES["file"]["tmp_name"] ); foreach ( explode( "\n", $string ) as $userString ) { $userString = trim( $userString ); echo $userString; $array = explode( ';', $userString ); $userdata = array ( 'cf_id'=>trim( $array[0] ), 'text_0'=>trim( $array[1] ), 'text_1'=>trim( $array[2] ), 'text_2'=>trim( $array[3] ), 'text_3'=>trim($array[4]), 'text_6'=>trim($array[5]), 'text_7'=>trim($array[6]), 'text_9'=>trim($array[7]), 'text_12'=>trim($array[8])); global $db; $db =& JFactory::getDBO(); $query = 'INSERT INTO #__chronoforms_UploadAuthor VALUES ("'.$userdata['cf_id'].'","'.$userdata['text_0'].'","'.$userdata['text_1'].'","'.$userdata['text_2'].'","'.$userdata['text_3'].'","'.$userdata['text_6'].'","'.$userdata['text_7'].'","'.$userdata['text_9'].'")'; $db->Execute($query); echo "<br>"; } i am trying to insert the contents into the table #__chronoforms_UploadAuthor in Joomla database . it doent shows any error but it is not inserted into the database.. Please help me.. Y the contents are not inserted into the database...And how to make it inserted into the database..

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  • morethan one between clause

    - by tismon
    hi how can i use more than one 'between' clause in mysql query ? like if i want to select students having height between 20 and 25 and weight between 50 and 70.. thanks in advance tismon

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  • login not working when changing from mysql to mysqli

    - by user1438647
    I have a code below where it logs a teacher in by matching it's username and password in the database, if correct, then log in, if incorrect, then display a message. <?php session_start(); $username="xxx"; $password="xxx"; $database="mobile_app"; $link = mysqli_connect('localhost',$username,$password); mysqli_select_db($link, $database) or die( "Unable to select database"); foreach (array('teacherusername','teacherpassword') as $varname) { $$varname = (isset($_POST[$varname])) ? $_POST[$varname] : ''; } ?> <form action="<?php echo htmlentities($_SERVER['PHP_SELF']); ?>" method="post" id="teachLoginForm"> <p>Username</p><p><input type="text" name="teacherusername" /></p> <!-- Enter Teacher Username--> <p>Password</p><p><input type="password" name="teacherpassword" /></p> <!-- Enter Teacher Password--> <p><input id="loginSubmit" type="submit" value="Login" name="submit" /></p> </form> <?php if (isset($_POST['submit'])) { $query = " SELECT * FROM Teacher t WHERE (t.TeacherUsername = '".mysqli_real_escape_string($teacherusername)."') AND (t.TeacherPassword = '".mysqli_real_escape_string($teacherpassword)."') "; $result = mysqli_query($link, $query); $num = mysqli_num_rows($result); $loged = false; while($row = mysqli_fetch_array($result)) { if ($_POST['teacherusername'] == ($row['TeacherUsername']) && $_POST['teacherpassword'] == ($row['TeacherPassword'])) { $loged = true; } $_SESSION['teacherforename'] = $row['TeacherForename']; $_SESSION['teachersurname'] = $row['TeacherSurname']; $_SESSION['teacherusername'] = $row['TeacherUsername']; } if ($loged == true){ header( 'Location: menu.php' ) ; }else{ echo "The Username or Password that you Entered is not Valid. Try Entering it Again."; } mysqli_close($link); } ?> Now the problem is that even if the teacher has entered in the correct username and password, it still doesn't let the teacher log in. When the code above was the old mysql() code, it worked fine as teacher was able to login when username and password match, but when trying to change the code into mysqli then it causes login to not work even though username and password match. What am I doing wrong?

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  • Database design for business numbers

    - by Rob Morris
    I'm in need of some help, I need to store the information below into a database, what would the relational database structure be for this: Then I need to create a dropdown for the insurance company followed by another dropdown depending on what the first dropdown selected value was, then once both selects have been chosen display the relevant telephone number. I guess i need to query the database, then display the dropdowns using javascript(jquery) or Ajax?

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  • ruby yaml ypath like xpath ?

    - by gurpal2000
    Hi i have a yaml file like so --- data: - date: "2004-06-11" description: First description - date: "2008-01-12" description: Another descripion How can i do a "ypath" query similar to xpath for xml ? Something like "get the description where the date is 2004-06-11" YAML.parse_file('myfile.yml').select('/data/*/date == 2004-06-11') How do you do it, and if that's possible how can i similarly edit the description by 'ypath' ? Thanks

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  • Error with characters in a html iframe

    - by dinero beta
    excuse my English I speak Spanish I'm trying to display multiple php and mysql registration, after that the show in an iframe the problem is that apparently in the iframe shows me errors accents and other characters for example: for example (?D?nde cuesta menos y se consume m?s?") this is what shows (?) In the original query or first does not show me that, but in the iframe shows me that error and probe with http-equiv = "content-type" and I worked What else I can do? What should I do? regards

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  • How do I create links in the cells of a PHP generated table?

    - by typoknig
    I have a table generated from some PHP code that lists a SMALL amount of important information for employees. I want to make it so each row, or at least one element in each row can be clicked on so the user will be redirected to ALL of the information (pulled from MySQL database) related to the employee who was clicked on. I am not sure how would be the best way to go about this, but I am open to suggestions. I would like to stick to PHP and/or JavaScript. Below is the code for my table: <table> <tr> <td id="content_heading" width="25px">ID</td> <td id="content_heading" width="150px">Last Name</td> <td id="content_heading" width="150px">First Name</td> <td id="content_heading" width="75px">SSN</td> </tr> <?php $user = 'user'; $pass = 'pass'; $server = 'localhost'; $link = mysql_connect($server, $user, $pass); if (!$link){ die('Could not connect to database!' . mysql_error()); } mysql_select_db('mydb', $link); $query = "SELECT * FROM employees"; $result = mysql_query($query); mysql_close($link); $num = mysql_num_rows($result); for ($i = 0; $i < $num; $i++){ $row = mysql_fetch_array($result); $class = (($i % 2) == 0) ? "table_odd_row" : "table_even_row"; echo "<tr class=".$class.">"; echo "<td>".$row[id]."</td>"; echo "<td>".$row[l_name]."</td>"; echo "<td>".$row[f_name]."</td>"; echo "<td>".$row[ssn]."</td>"; echo "</tr>"; } ?> </table>

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  • Problems with MySQL OR clause

    - by Simon
    I have a problem with AND and OR clause in SQL. Here is my query: SELECT `act1`.`name`, `act1`.`surname`, `act2`.`name`, `act2`.`surname`, `act3`.`name`, `act3`.`surname` FROM `videos`, `actors` AS act1, `actors` AS act2, `actors` AS act3 WHERE `videos`.`ident` = 'somethink' AND ( `act1`.`id` = `videos`.`id_actor1` OR `act2`.`id` = `videos`.`id_actor2` OR `act3`.`id` = `videos`.`id_actor3` ) It returns me all variations of {name, surname}, but I want the name and surname of first exactly, second and thirth, if they exist.

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  • How to test if table was updated in Zend Framework?

    - by AD
    When user opens a form to modify a record, but instead of changing information, he just clicks the Update button. Which causes the update() function to return 0. However, I consider this case a valid update task. How would I test it, so I can assign a success message? Is update() returns -1 when SQL query failed or also 0? Method: Zend_Db_Table_Abstract::update() Any ideas? Thanks

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  • How to test if a table is empty, using Hibernate

    - by landon9720
    Using Hibernate, what is the most efficient way to determine if a table is empty or non-empty? In other words, does the table have 0, or more than 0 rows? I could execute the HQL query select count(*) from tablename and then check if result is 0 or non-0, but this isn't optimal as I would be asking the database for more detail than I really need.

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  • ado.net-data-services filer using composite

    - by Thurein
    Hi, I am having a problem filter a query. I have Contact and Tag entities. Actually in the database, they are 3 different tables, Contacts, Tags and ContactTag table. I would like to filter contacts using the Tag name. I was trying this filter but it did not work. http://localhost:50143/ContactDataService.svc/Contacts?$filter=Tags/TagName eq 'Tag1' Am I missing any thing ? Thanks Thurein

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  • How to syncronize merge subscription in Sql Compact DB (on a Mobile device emulator)

    - by Bero
    Using SQL ManagementStudio 2008 I created SQL 3.5 Compact DB (TestCompact.sdf) and I have created subscription to existing Publication. Using SQL Management Studio it is working. I have transfered TestCompact.sdf to Windows Mobile 5 emulator device and with QueryAnalyzer for Mobile I could query existing tables in TestCompact.sdf. I don't know how to start replication synchronization on that mobile device. Do I need to write some C# code or it is possible do it more simple?

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  • SELECT table name that is inside UNION

    - by LexRema
    I have two same tables. I need to union them in such way: SELECT f1,f2, xxx FROM (SELECT * FROM tbl1 UNION ALL SELECT * FROM tbl2) where xxx would query for a table name, where f1 and f2 fields are taken from. Example output: 123 345 'tbl1' -- this rows are from the first table 121 345 'tbl1' 121 345 'tbl1' 123 345 'tbl1' 124 345 'tbl1' 125 345 'tbl2' -- this rows are from the second table 127 345 'tbl2' Thank you in advance.

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  • Passing variables from Model to Model in codeigniter

    - by Craig Ward
    Hi, I need to pass a variable to model, that model needs to send another back and use that variable to query a different model. EG: I have a product_ID which I send to the product model, From that I find out the supplier_ID. I want to grab that supplier_ID to the supplier model to get the supplier name. How do you implement this in codeigniter?

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  • Three-way full outer join in SQLite

    - by Vince
    I have three tables with a common key field, and I need to join them on this key. Given SQLite doesn't have full outer or right joins, I've used the full outer join without right join technique on Wikipedia with much success. But I'm curious, how would one use this technique to join three tables by a common key? What are the efficiency impacts of this (the current query takes about ten minutes)? Thanks!

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  • Browser removing + from request parameter

    - by Marquinio
    Hello everyone, I'm trying to pass an SQL query string from a Java Applet to Servlet as a parameter. Problem is that in Applet I have something say: sql=select * from p where(+p=1) The resulting sql parameter in the Servlet is sql=select * from p where(+p=1). So anyone knows how to prevent the browser from removing the + character from parameters? Is there a escape character? Thank you.

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