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• Is there a programming language with not a tree but tags idea behind OOP?

  - by kolupaev

  I'm thinking about tree structures, and I feel that I don't like them. It's like when you have a shop, then you try to put all products to tree-like catalog, and then you need to place one product to multiple categories, now you have multiple routing, bla-bla. I don't feel like everything in the world could be put to a tree. Instead, I like idea of tags. I would like to store everything with tags. With tags I could do much more. I can even simulate trees if I want. I want to have tag-based filesystem! But hey - modern OOP paradigm with inheritance is based on tree. I want to see how it is when you don't have such basement. Closest thing I found is mixins in some languages. Do you know what else is also about this ideas?

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• Directory error when trying to create a new user

  - by Tom Brossman

  I added a second user 'shirley' in Settings - User Accounts, and set a password. The account type is Standard. In 11.04, this worked and I logged in and had a functioning desktop for this user. How is this done in 11.10? When I try to log in as this user I have this error: Nautilus could not create the required folder "/home/shirley/.config/nautilus". Before running Nautilus, please create the following folder, or set permissions such that Nautilus can create it. The only option then is to click OK, this dumps me out to full-screen Nautilus, like this: There is no launcher or visible way to start any programs. Print screen doesn't take a screengrab. The desktop is similar to this question but I get no terminal when I press CTRL+ALT+T. I have to press CTRL+ALT+F2 and restart from the terminal to get out of this. This answer is to install gnome-system-tools. Shouldn't I be able to add a second user with the default install? EDIT: I tried the deluser+adduser suggestion, there was no change after trying it. Here is what I got: tom@desktop:~$ sudo deluser shirley [sudo] password for tom: Removing user `shirley' ... Warning: group `shirley' has no more members. Done tom@desktop:~$ sudo adduser shirley Adding user `shirley' ... Adding new group `shirley' (1001) Adding new user shirley' (1001) with groupshirley' The home directory '/home/shirley' already exists. Not copying from `/etc/skel'. Enter new UNIX password: Retype new UNIX password: passwd: password updated successfully Changing user information for shirley Enter the new value, or press ENTER for the default Full Name []: Room Number []: Work Phone []: Home Phone []: Other []: Is the information correct? [Y/n] y What has gone so wrong with simply adding a second user? Am I the only one having this problem? I'd reinstall if that fixed things, but this is a fresh install only a few days old.

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• Why create a Huffman tree per character instead of a Node?

  - by Omega

  For a school assignment we're supposed to make a Java implementation of a compressor/decompresser using Huffman's algorithm. I've been reading a bit about it, specially this C++ tutorial: http://www.cprogramming.com/tutorial/computersciencetheory/huffman.html In my program, I've been thinking about having Nodes that have the following properties: Total Frequency Character (if a leaf) Right child (if any) Left child (if any) Parent (if any) So when building the Huffman tree, it is just a matter of linking a node to others, etc. However, I'm a bit confused with the following quote (emphasis mine): First, every letter starts off as part of its own tree and the trees are ordered by the frequency of the letters in the original string. Then the two least-frequently used letters are combined into a single tree, and the frequency of that tree is set to be the combined frequency of the two trees that it links together. My question: why should I create a tree per letter, instead of just a node per letter and then do the linking later? I have not begun coding, I'm just studying the algorithm first, so I guess I'm missing an important detail. What is it?

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• Why don't we store the syntax tree instead of the source code?

  - by Calmarius

  We have a lot of programming languages. Every language is parsed and syntax checked before translated into code so an abstract syntax tree is built. We have this abstract syntax tree, why don't we store this syntax tree instead of the source code (or next to the source code)? By using an AST instead of the source code. Every programmer in a team can serialize this tree to any language, they want (with the appropriate context free grammar) and parse back to AST when they finished. So this would eliminate the debate about the coding style questions (where to put the { and }, where to put whitespace, indentation, etc.) What are the pros and cons of this approach?

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• Java+DOM: How do I convert a DOM tree without namespaces to a namespace-aware DOM tree?

  - by java.is.for.desktop

  Hello, everyone! I receive a Document (DOM tree) from a certain API (not in JDK). Sadly, this Document is not namespace-aware. As far as I know DOM, once generated, namespace-awareness can't be "added" afterwards. When converting this Document using a Transformer to a string, the XML is correct. Elements have xmlns:... attributes and name prefixes. But from the DOM point of view, there are no namespaces and no prefixes. I need to be able to convert this Document into a new Document which is namespace-aware. Yes, I could do this by just converting it to a string and back to DOM with namespaces enabled. But: nodes of the original tree have user-objects set. Converting to string and back would make a mapping of these user-objects to the new Document very complicated, if not impossible. So I really need a way to convert non-namespace DOM to namespace DOM. Are there any more-or-less straightforward solutions for this? Worst case (what I'm hoping to avoid) would be to manually iterate through old Document tree and create new namespace-aware Node for each old Node. Doing so, one had to manually "parse" namespace prefixes, watch out for xmlns-attributes, and maintain a mapping between prefixes and namespace-URIs. Lots of things to go wrong.

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• ACL actions tag cause 'roles resource tree' draw incorrectly in admin/system/permissions/roles

  - by latvian

  Hi, We created new action similar to 'hold', 'ship' and others in the 'sales_order/view' admin section that can be triggered by clicking at the button. Afterward, we added our new action to the ACL with the following code in config.xml: <acl> <resources> <admin> <children> <sales> <children> <order> <children> <actions translate="title"> <title>Actions</title> <children> <shipNew translate="title"><title>Ship Ups</title></shipNew> </children> </actions> </children> <sort_order>10</sort_order> </order> </children> </sales> </children> </admin> </resources> </acl> ACL functionality works, however, in the 'Resources Tree'(System/Permissions/Roles/Role Resources) our new action does never show up as selected(checked) even thou it is allowed for particular Role. I can see that from table 'admin_rule' with resource id for our new action that it is allowed, so it needs to be selected, but it is not. When trying to solve this issue i looked into the template(permissions/rolesedit.phtml) and I found that the 'resource tree' is draw with Javascript...thats where i got stock due to my limited knowledge in Javascript. Why the resource tree does not display our new ACL entry correctly, that is the check box is never checked? Thank You for helping margots

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• Realizing program with decision tree logics

  - by Vytas999

  The system realizes a game “Think animal”. Main use case is: 1. System offers user to think about any animal and the system will try to guess it 2. The system starts asking questions from the start of decision tree. Ex., “Question: It has fur?”, and provides possible answers – yes or no. 3. If the user answers Yes, the system proceeds to these steps: a. System tries to guess animal that has that feature, ex. “My guess: Is it bear?” and provides with possible answers – yes or no. b. If the user answer is Yes, the system offers to think off another animal 4. If the user answers is No, the system moves to No node in decision tree and moves to 2 step (and starts from asking from new node). 5. If system runs out of nodes (i.e., empty yes or no node was reached): a. the system announces that it has given up, and ask user to enter: i. What animal he had in mind ii. What is his characteristic feature b. User enters requested data c. The system creates a new node and links it to yes or no of last active node. Where i can get some information and some examples, when implementing decision tree logics in MS SQL Server and C#..? Any information will be usefull. Thanks

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• converting a Tree to newick format. java

  - by Esmond

  I'm having problems converting a binary rooted tree to newick format. The full explanation for such a format can be found: http://code.google.com/p/mrsrf/wiki/NewickTree An example of a newick format would be as follows: for a tree T such as http://www.cs.mcgill.ca/~cs251/OldCourses/1997/topic8/images/completetreetwo.gif the newick representation would be: (((8,9),(10,11)),((12,13),(14,15))) the internal node will become the commas while the leaves will be retained. such trees have internal nodes which will always have 2 children. I have a problem using recursion to come out with this newick format. The output contains far too many nodes and braces. Any comments to resolve this problem is appreciated or even an iterative algorithm would be welcomed import java.util.Stack; public class Tree { .... public String inOrderNewick(Node root, String output) throws ItemNotFoundException { if (root.hasChild()) { output += "("; output += inOrderNewick(root.child1, output); output += ","; output += inOrderNewick(root.child2, output); output += ")"; return output; } else { output += root.getSeq(); return output; } } }

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• Parse a CSV file using python (to make a decision tree later)

  - by Margaret

  First off, full disclosure: This is going towards a uni assignment, so I don't want to receive code. :). I'm more looking for approaches; I'm very new to python, having read a book but not yet written any code. The entire task is to import the contents of a CSV file, create a decision tree from the contents of the CSV file (using the ID3 algorithm), and then parse a second CSV file to run against the tree. There's a big (understandable) preference to have it capable of dealing with different CSV files (I asked if we were allowed to hard code the column names, mostly to eliminate it as a possibility, and the answer was no). The CSV files are in a fairly standard format; the header row is marked with a # then the column names are displayed, and every row after that is a simple series of values. Example: # Column1, Column2, Column3, Column4 Value01, Value02, Value03, Value04 Value11, Value12, Value13, Value14 At the moment, I'm trying to work out the first part: parsing the CSV. To make the decisions for the decision tree, a dictionary structure seems like it's going to be the most logical; so I was thinking of doing something along these lines: Read in each line, character by character If the character is not a comma or a space Append character to temporary string If the character is a comma Append the temporary string to a list Empty string Once a line has been read Create a dictionary using the header row as the key (somehow!) Append that dictionary to a list However, if I do things that way, I'm not sure how to make a mapping between the keys and the values. I'm also wondering whether there is some way to perform an action on every dictionary in a list, since I'll need to be doing things to the effect of "Everyone return their values for columns Column1 and Column4, so I can count up who has what!" - I assume that there is some mechanism, but I don't think I know how to do it. Is a dictionary the best way to do it? Would I be better off doing things using some other data structure? If so, what?

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• Makefile; mirroring a growing tree through a process

  - by Martineau

  I would like to periodically mirror a growing tree, say, from $in to $out, doing a process in between (saving the only file header). As; #!/bin/bash in=./segd out=./db for f in `find $in -name "*.segd"`;do # Deduct output (dir + name) d=`dirname $f|perl -pe 's!'$in'!'$out'!'` n=`basename $f|perl -pe 's!$!_hdr!'` if [ ! -e $d/$n ]; then [ ! -d $d ] && mkdir -p $d; printf "From %s now build %s\n" $f "$d/$n" # Do something, whathever. For example e.g; dd if=$f bs=32 count=1 conv=swab 2>/dev/null|od -x > $d/$n fi done That is about fair. However; to be more robust, for a better synchronization (say if a source file did change or whatever), I would like to use a Makefile, as in; HDR := $(patsubst ./segd/%.segd,./db/%.segd_hdr,$(wildcard ./segd/*.segd)) all: ${HDR} db/%.segd_hdr: ./segd/%.segd echo "Doing" dd if=$< bs=32 count=1 conv=swab 2>/dev/null|od -x > $@ My problem; I cannot code this Makefile to "dive" more deeply within the source ./segd tree. How can we do it and is there a way ? Many thanks for your kind recommendations. PS: The idea will be to later rsync the (smaller) destination tree over a sat connection.

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• Bidirectional real-time sync of large file tree between two distant linux servers

  - by dlo

  By large file tree I mean about 200k files, and growing all the time. A relatively small number of files are being changed in any given hour though. By bidirectional I mean that changes may occur on either server and need to be pushed to the other, so rsync doesn't seem appropriate. By distant I mean that the servers are both in data centers, but geographically remote from each other. Currently there are only 2 servers, but that may expand over time. By real-time, it's ok for there to be a little latency between syncing, but running a cron every 1-2 minutes doesn't seem right, since a very small fraction of files may change in any given hour, let alone minute. EDIT: This is running on VPS's so I might be limited on the kinds of kernel-level stuff I can do. Also, the VPS's are not resource-rich, so I'd shy away from solutions that require lots of ram (like Gluster?). What's the best / most "accepted" approach to get this done? This seems like it would be a common need, but I haven't been able to find a generally accepted approach yet, which was surprising. (I'm seeking the safety of the masses. :) I've come across lsyncd to trigger a sync at the filesystem change level. That seems clever though not super common, and I'm a bit confused by the various lsyncd approaches. There's just using lsyncd with rsync, but it seems this could be fragile for bidirectionality since rsync doesn't have a notion of memory (eg- to know whether a deleted file on A should be deleted on B or whether it's a new file on B that should be copied to A). lipsync appears to be just a lsyncd+rsync implementation, right? Then there's using lsyncd with csync2, like this: http://www.axivo.com/community/threads/lightning-fast-synchronization-with-csync2-and-lsyncd.121/ ... I'm leaning towards this approach, but csync2 is a little quirky, though I did do a successful test of it. I'm mostly concerned that I haven't been able to find a lot of community confirmation of this method. People on here seem to like Unison a lot, but it seems that it is no longer under active development and it's not clear that it has an automatic trigger like lsyncd. I've seen Gluster mentioned, but maybe overkill for what I need? UPDATE: fyi- I ended up going with the original solution I mentioned: lsyncd+csync2. It seems to work quite well, and I like the architectural approach of having the servers be very loosely joined, so that each server can operate indefinitely on its own regardless of the link quality between them.

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• Explode all folders

  - by sam

  Ive got a folder with about a hundred sub folders and again each ones of those has between 10 and 20 sub folders, so all in all a pretty large folder tree. Is there a simple way i can explode or export all of the files in the tree to a new folder which will just be one folder contain the files (no folders, no trees). Im running OSX 10.8, although ive also got Parallels so if there is a windows solution i could just run that as its not something i need to do everyday.

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• sshfs mounted directory becomes unresponsive

  - by gms8994

  I've mounted a directory via sshfs: sshfs <user>@<host>:/var/www <host>/ However, after a few hours, the "something" happens, and I can no longer use the mounted directory. Symptoms are similar to when an nfsmounted server becomes unavailable: ls fails, cd fails, etc. I've attempted sshfs -o reconnect <user>@<host>:/var/www <host>/ but that never responded. Does anyone know how I can either unmount the directory, and remount it, or force sshfs to reconnect to the server?

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• Cannot create file in directory even though it's writable by a group I belong to

  - by Alan Berndt

  I have a directory structure owned by a certain group, and I am a member of the group that owns these directories. I am able to create files in one directory, but not in another, even though the permissions are the same. alan@bricky:/mnt/storage/media$ stat Music Music\ \(Lossy\)/ File: `Music' Size: 34 Blocks: 8 IO Block: 4096 directory Device: fb00h/64256d Inode: 4215424 Links: 3 Access: (2775/drwxrwsr-x) Uid: ( 1001/ media) Gid: ( 1001/ media) Access: 2011-08-19 11:45:03.182586898 -0700 Modify: 2011-08-19 11:44:01.412840027 -0700 Change: 2011-08-19 11:45:02.734603240 -0700 File: `Music (Lossy)/' Size: 6 Blocks: 8 IO Block: 4096 directory Device: fb00h/64256d Inode: 1512056832 Links: 2 Access: (2775/drwxrwsr-x) Uid: ( 1001/ media) Gid: ( 1001/ media) Access: 2011-08-19 11:45:03.190586606 -0700 Modify: 2011-08-19 10:34:46.526530313 -0700 Change: 2011-08-19 11:45:02.738603094 -0700 alan@bricky:/mnt/storage/media$ touch Music/test alan@bricky:/mnt/storage/media$ touch Music\ \(Lossy\)/test touch: cannot touch `Music (Lossy)/test': Permission denied

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• Loading the 'pktgen' module on Ubuntu Server

  - by StackedCrooked

  I would like to enable and use the pktgen module on Ubuntu Server. I have enabed the module by adding a line containing 'pktgen' to the /etc/modules file. After rebooting it seems that the module is successfully loaded because the directory /proc/net/pktgen exists. However when trying to run the first sample I get these errors: root@ubuntu:~# bash ./pktgen.conf-1-1 Removing all devices Adding eth4 Setting max_before_softirq 10000 Configuring /proc/net/pktgen/eth4 ./pktgen.conf-1-1: line 9: /proc/net/pktgen/eth4: No such file or directory cat: /proc/net/pktgen/eth4: No such file or directory cat: /proc/net/pktgen/eth4: No such file or directory ./pktgen.conf-1-1: line 9: /proc/net/pktgen/eth4: No such file or directory cat: /proc/net/pktgen/eth4: No such file or directory cat: /proc/net/pktgen/eth4: No such file or directory ./pktgen.conf-1-1: line 9: /proc/net/pktgen/eth4: No such file or directory cat: /proc/net/pktgen/eth4: No such file or directory cat: /proc/net/pktgen/eth4: No such file or directory ./pktgen.conf-1-1: line 9: /proc/net/pktgen/eth4: No such file or directory cat: /proc/net/pktgen/eth4: No such file or directory cat: /proc/net/pktgen/eth4: No such file or directory ./pktgen.conf-1-1: line 9: /proc/net/pktgen/eth4: No such file or directory cat: /proc/net/pktgen/eth4: No such file or directory cat: /proc/net/pktgen/eth4: No such file or directory ./pktgen.conf-1-1: line 9: /proc/net/pktgen/eth4: No such file or directory cat: /proc/net/pktgen/eth4: No such file or directory cat: /proc/net/pktgen/eth4: No such file or directory Running... ctrl^C to stop Done It turns out the script simply unable to write a file to the /proc/net/pktgen directory. When I try this manually it fails as well: root@ubuntu:~# cd /proc/net/pktgen/ root@ubuntu:/proc/net/pktgen# touch eth4 touch: cannot touch `eth4': No such file or directory Can anyone help me make it work? I'm using Ubuntu version: 2.6.32-21-server. Fixed I apologize for keeping this post not up to date. I was able to fix it. If I remember well the cause of the error was that eth4 did not exist, or did not have the 'online' status. Anyway, it is fixed now.

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• Prefix files with the current directory name using Powershell

  - by XST

  I have folders with images (*.png and *.jpg) >C:\Directory\Folder1 01.png 02.png 03.jpg 04.jpg 05.png And I want to rename all the files like this using powershell: >C:\Directory\Folder1 Folder1 - 01.png Folder1 - 02.png Folder1 - 03.jpg Folder1 - 04.jpg Folder1 - 05.png So I came up with this simple line: Get-ChildItem | Where-Object { $_.Extension -eq ".jpg" -or $_.Extension -eq ".png"} | rename-item -newname {$_.Directory.Name +" - " + $_.Name} If I have 35 or less files in the folder, I will have the wanted result, but if there is 36 or more files, I will end up with this: >C:\Directory\Folder1 Folder1Folder1Folder1 - 01.png Folder1Folder1Folder1 - 02.png Folder1Folder1Folder1 - 03.jpg Folder1Folder1Folder1 - 04.jpg Folder1Folder1Folder1 - 05.png The loop stops when the file's name exceeds 248 characters. Any ideas why it's looping?

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• SFTP: file symlinks in a jailed (chrooted) directory

  - by Kevin Duke

  I'm trying to set up sftp so that a few trusted people can access/edit/create some files. I have jailed a user into their home directory (/home/name) but have run into a problem. I want for them to also be able to access other parts of the VPS because it is also a game server, webhost, etc, and I want for them to be able to have full control of files outside their jailed directory. I tried making a symlink (ln -s) to the desired directory but it does not work, as expected. I tried (cp -rl) to the files that I wanted to give access and it worked -- they can edit the files in their directory and it changes the one stored outside of jail. BUT they cannot create new files (they can but it won't update outside of jail). I know I'm probably not doing this the "right way" but what can I do to do what I want?

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• proftpd: copying uploaded files to an additional directory

  - by Matthew Iselin

  Using proftpd, is there a good way to automatically synchronise uploaded files from the upload directory to some other directory? Our layout ends up a bit like this: ~/ftp/some/path <-- Files are uploaded here ~/some/other/path/not/accessible/via/ftp <-- But also need to be here after uploading Is there a good way to do this automatically, or do I have to tell anyone uploading files to upload twice, and open up an additional directory (containing data we cannot redistribute)?

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• Unable to install bin files.(No such file or directory error)

  - by rogerstone

  I wanted to install adobe reader on my ubuntu 10.10(Maverick Meerkat).I have downloaded the file and copied it on my desktop.I had then browsed to the desktop directory through command line terminal. I had tried all the possible combinations of the commands but still i get a "file or directory does not exist error" roger@ubuntu:~/Desktop$ chmod a+x AdbeRdr9.4-1_i486linux_enu.bin roger@ubuntu:~/Desktop$ sudo ./AdbeRdr9.4-1_i486linux_enu.bin sudo: unable to execute ./AdbeRdr9.4-1_i486linux_enu.bin: No such file or directory I tried without the sudo and this is what i get roger@ubuntu:~/Desktop$ chmod a+x AdbeRdr9.4-1_i486linux_enu.bin roger@ubuntu:~/Desktop$ ./AdbeRdr9.4-1_i486linux_enu.bin bash: ./AdbeRdr9.4-1_i486linux_enu.bin: No such file or directory The file is present in the desktop.Where am i going wrong? P.S:This is not a duplicate of the question Cannot install .bin package on Ubuntu

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• Setting default working directory/drive in Emacs shell on Windows

  - by Victor K.

  Hello, how can I change a default working directory/drive for shell in Emacs (on Windows)? Normally, shell starts in the same directory as the file in current buffer. However, when my current file is on D: drive, it starts in c:. Manually changing drive to D: in shell brings me to my directory of course, but I want to avoid this extra step. Is it possible?

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• How to simply remove everything from a directory on Linux

  - by Tometzky

  How to simply remove everything from a current or specified directory on Linux? Several approaches: rm -fr * rm -fr dirname/* Does not work — it will leave hidden files — the one's that start with a dot, and files starting with a dash in current dir, and will not work with too many files rm -fr -- * rm -fr -- dirname/* Does not work — it will leave hidden files and will not work with too many files rm -fr -- * .* rm -fr -- dirname/* dirname/.* Don't try this — it will also remove a parent directory, because ".." also starts with a "." rm -fr * .??* rm -fr dirname/* dirname/.??* Does not work — it will leave files like ".a", ".b" etc., and will not work with too many files find -mindepth 1 -maxdepth 1 -print0 | xargs -0 rm -fr find dirname -mindepth 1 -maxdepth 1 -print0 | xargs -0 rm -fr As far as I know correct but not simple. find -delete find dirname -delete AFAIK correct for current directory, but used with specified directory will delete that directory also. find -mindepth 1 -delete find dirname -mindeph 1 -delete AFAIK correct, but is it the simplest way?

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• Unable to delete a directory from NTFS drive: "Access is denied"

  - by Evgeny

  I'm running Windows XP Pro x64 SP2. I have a directory on an NTFS drive that was created by a Maven build. A subsequent build attempted to delete this directory and failed. I now get the error "Access is denied" whenever I try to do anything with that directory: change to it, delete it, rename it. This happens both in Windows Explorer and from a command prompt. The properties dialog in Windows Explorer doesn't even contain the Security tab. I created the directory, so I don't think this is truly a permissions issue. I've occasionally had this error happen in the past is well. I believe the error is misleading, but the question is: what is the real problem and how do I fix it?

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• What is a vim "runtime directory"?

  - by Andres Jaan Tack

  I'm trying to get started with things like FuzzyFinder, but I am stuck at the point where it says: INSTALLATION fuf-installation Put all files into your runtime directory. If you have the zip file, extract it to your runtime directory. You should place the files as follows: your_runtime_directory/plugin/fuf.vim ... What is my "runtime directory"? How do I know if I have one? Why does it matter how I put things into it?

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• Filezilla client unable to get directory listing from Filezilla Server (Windows)

  - by sestocker

  I've set up a self signed certificate in FileZilla server and enabled FTP over SSL/TPS. When I connect from the client FileZilla, I am able to authenticate but cannot get a directory listing: Status: Connecting to MY_SERVER_IP:21... Status: Connection established, waiting for welcome message... Response: 220-FileZilla Server version 0.9.39 beta Response: 220-written by Tim Kosse ([email protected]) Response: 220 Please visit http://sourceforge.net/projects/filezilla/ Command: AUTH TLS Response: 234 Using authentication type TLS Status: Initializing TLS... Status: Verifying certificate... Command: USER MYUSER Status: TLS/SSL connection established. Response: 331 Password required for MYUSER Command: PASS ******** Response: 230 Logged on Command: PBSZ 0 Response: 200 PBSZ=0 Command: PROT P Response: 200 Protection level set to P Status: Connected Status: Retrieving directory listing... Command: PWD Response: 257 "/" is current directory. Command: TYPE I Response: 200 Type set to I Command: PORT 10,10,25,85,219,172 Response: 200 Port command successful Command: MLSD Response: 150 Opening data channel for directory list. Response: 425 Can't open data connection. Error: Failed to retrieve directory listing I have ports 21 and 50001 through 50005 open on the firewall. We are migrating servers - the 50001 - 50005 is one of the things that helped get FTPS working on the old server. I'm not sure this installation would use the same ports? What else could be the problem?

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• RewriteRules targeting a directory result in a gratuitous redirect [closed]

  - by MapDot

  I have a standard CMS-like RewriteRule set up in my .htaccess: RewriteRule ^(.+)$ index.php?slug=$1 Let's say I have a directory called "foo" in the root directory. For some reason, if you hit the page it causes a redirect: http://www.mysite.com/foo -- http://www.mysite.com/foo?slug=foo Removing the directory fixes the problem, but unfortunately, it's not an option. Does anyone know of a workaround?

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