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  • Moving from dedicated to shared cpanel - any scripts to do all / some of the install tasks ?

    - by mbbcat
    Hi, I have a few hundred phpld sites to move - each has its own cpanel, ( & the target may have shared cpanel) & I can do a full cpanel backup on the original server, but I don't have whm on the current host - the backups are fairly easy to organize but the installs so far means picking through files & setting up db's & mail etc by hand - I am thinking there ought to be an easier ie scripted way to do the installs or at least some parts - can anyone please suggest something ? I would like to migrate the stats at the same time Thanks M

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  • Relating categories with tags using SQL

    - by Pablo
    I want be able to find tags of items under the a certain category. Following is example of my database design: images +----------+-----+-------------+-----+ | image_id | ... | category_id | ... | +----------+-----+-------------+-----+ | 1 | ... | 11 | ... | +----------+-----+-------------+-----+ | 2 | ... | 12 | ... | +----------+-----+-------------+-----+ | 3 | ... | 11 | ... | +----------+-----+-------------+-----+ | 4 | ... | 11 | ... | +----------+-----+-------------+-----+ images_tags +----------+--------+ | image_id | tag_id | +----------+--------+ | 1 | 53 | +----------+--------+ | 3 | 54 | +----------+--------+ | 2 | 55 | +----------+--------+ | 1 | 56 | +----------+--------+ | 4 | 57 | +----------+--------+ tags and categories each have their own table relating the id to an actual name(text). So my question is how will i find out that images with category_id=11 have have the tag_id 53 54 55 56 57. In other words how to find the tags that images in certain category have?

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  • "slash before every quote" problem

    - by Camran
    I have a php page which contains a form. Sometimes this page is submitted to itself (like when pics are uploaded). I wouldn't want users to have to fill in every field again and again, so I use this as a value of a text-input inside the form: value="<?php echo htmlentities(@$_POST['annonsera_headline'],ENT_COMPAT,'UTF-8');?>"> This works, except it adds a "\" sign before every double-quote... For instance writing 19" wheels gives after page is submitted to itself: 19\" wheels And if I don't even use htmlentities then everything after the quotes dissappears. What is the problem here?

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  • Does UNIQ constraint mean also an index on that field(s)?

    - by Gremo
    As title, should i defined a separate index on email column (for searching purposes) or the index is "automatically" added along with UNIQ_EMAIL_USER constraint? CREATE TABLE IF NOT EXISTS `customer` ( `id` int(11) NOT NULL AUTO_INCREMENT, `user_id` int(11) NOT NULL, `first` varchar(255) NOT NULL, `last` varchar(255) NOT NULL, `slug` varchar(255) NOT NULL, `email` varchar(255) NOT NULL, `created_at` datetime NOT NULL, `updated_at` datetime NOT NULL, PRIMARY KEY (`id`), UNIQUE KEY `UNIQ_SLUG` (`slug`), UNIQUE KEY `UNIQ_EMAIL_USER` (`email`,`user_id`), KEY `IDX_USER` (`user_id`) ) ENGINE=InnoDB;

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  • duplicate record

    - by user349953
    Insert into Attendancemst ( emp_code , name, date , timetable , on_duty,out_duty,clockin , clockout, late, early, mis_in , mis_out , absent , halfday, total_time ) values (pemp_code,pname,pdate,ptimetable,pon_duty,pout_duty ,pclockin,pclockout,plate, pearly, pmis_in,pmis_out,pabsent,phalfday,ptotal_time )ON DUPLICATE KEY UPDATE emp_code=pemp_code and date = pdate;

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  • The best way to structure this database?

    - by James P
    At the moment I'm doing this: gems(id, name, colour, level, effects, source) id is the primary key and is not auto-increment. A typical row of data would look like this: id => 40153 name => Veiled Ametrine colour => Orange level => 80 effects => +12 sp, +10 hit source => Ametrine (Some of you gamers might see what I'm doing here :) ) But I realise this could be sorted a lot better. I have studied database relationships and secondary keys in my A-Level computing class but never got as far as to set one up properly. I just need help with how this database should be organised, like what tables should have what data with what secondary and foreign keys? I was thinking maybe 3 tables: gem, effects, source. Which then have relationships to each other? Can anyone shed some light on this? Is a complex way like I'm proposing really the way to go or should I just carry on with what I'm doing? Cheers.

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  • Fatal error: Call to undefined function mysqli_connect()

    - by Jack
    I have installed WAMP. I am using Tomcat 6 to run my PHP scripts. I am also using JavaBridge.war and I have copied my php scripts into \webapp\JavaBridge\project. I have removed the semicolon from php.ini file before the statements extension=php_mysqli.dll extension=php_mysql.dll I have added C:\wamp\bin into my PATH env variable. I have copied all dll's from C:\wamp\bin\php\php5.3.0\ext into C:\windows\system32 I am still getting this error. Fatal error: Call to undefined function mysqli_connect() in C:\Program Files\apache-tomcat-6.0.26\webapps\JavaBridge\project\pf_query.php on line 534 Note - I dont get this error when I run my PHP script from Apache 2.2.11 of the WAMP package.

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  • Beginner having difficulty with SQL query

    - by Vulcanizer
    Hi, I've been studying SQL for 2 weeks now and I'm preparing for an SQL test. Anyway I'm trying to do this question: For the table: 1 create table data { 2 id int, 3 n1 int not null, 4 n2 int not null, 5 n3 int not null, 6 n4 int not null, 7 primary key (id) 8 } I need to return the relation with tuples (n1, n2, n3) where all the corresponding values for n4 are 0. The problem asks me to solve it WITHOUT using subqueries(nested selects/views) It also gives me an example table and the expected output from my query: 01 insert into data (id, n1, n2, n3, n4) 02 values (1, 2,4,7,0), 03 (2, 2,4,7,0), 04 (3, 3,6,9,8), 05 (4, 1,1,2,1), 06 (5, 1,1,2,0), 07 (6, 1,1,2,0), 08 (7, 5,3,8,0), 09 (8, 5,3,8,0), 10 (9, 5,3,8,0); expects (2,4,7) (5,3,8) and not (1,1,2) since that has a 1 in n4 in one of the cases. The best I could come up with was: 1 SELECT DISTINCT n1, n2, n3 2 FROM data a, data b 3 WHERE a.ID <> b.ID 4 AND a.n1 = b.n1 5 AND a.n2 = b.n2 6 AND a.n3 = b.n3 7 AND a.n4 = b.n4 8 AND a.n4 = 0 but I found out that also prints (1,1,2) since in the example (1,1,2,0) happens twice from IDs 5 and 6. Any suggestions would be really appreciated.

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  • A logical problem with two tables

    - by Luke
    Hey guys, I created a list for fixtures. $result = mysql_query("SELECT date FROM ".TBL_FIXTURES." WHERE compname = '$comp_name' GROUP BY date"); $i = 1; $d = "Start"; while ($row = mysql_fetch_assoc($result)) { $odate = $row['date']; $date=date("F j Y", $row['date']); echo "<p>Fixture $i - $d to $date</p>"; } As you can see from the query, the date is displayed from the fixtures table. The way my system works is that when a fixture is "played", it is removed from this table. Therefore when the entire round of fixtures are complete, there wont be any dates for that round in this table. They will be in another table. Is there anyway I can run an other query for dates at the same time, and display only dates from the fixtures table if there isnt a date in the results table? "SELECT * FROM ".TBL_CONF_RESULTS." WHERE compid = '$_GET[id]' && type2 = '2' ORDER BY date" That would be the second query!

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  • Use where clause with Like in codeigniter

    - by user2524013
    I am working on a project. I am implementing the Search functionality in my System. I will have to show the search record from two tables base on the current use login. I have tried the following code: function searchActivity($limit,$offset,$keyword1,$keyword2,$recruiter_id) { $q=$this->db->select('*')->from('tbl_activity')->limit($limit,$offset); $this->db->join('tbl_job', 'tbl_job.job_id = tbl_activity.job_id_fk', 'left outer'); $this->db->order_by("activity_id", "ASC"); $this->db->like('job_title',$keyword1,'both'); $this->db->or_like('job_title',$keyword2,'both'); $this->db->or_like('activity_subject',$keyword1,'both'); $this->db->or_like('activity_subject',$keyword2,'both'); $this->db->or_like('activity_details',$keyword1,'both'); $this->db->or_like('activity_details',$keyword2,'both'); $this->db->where('tbl_activity.recruiter_id_fk',$recruiter_id); $ret['rows']=$q->get()->result(); return $ret; } I want to show search results based on the current user id, which is currently store in $recruiter. Thanks in advance.

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  • How to find and update the next record in a linking table

    - by someoneinomaha
    I have a classifieds system I'm working on. People are able to add photos to a classified, but I only display one when displaying the list of classifieds. To do that, I have a linking table between classifieds and photos that has a "is_main" boolean field. When someone deletes one of their classified photos, I want to: 1) See if there is more than that photo tied to the classified. 2) If there is, update the next photo and set that "is_main" field to TRUE. Just trying to find out the most efficient way to do this.

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  • restoring with mysqldump, but where is the data?

    - by Ole Media
    Ok, so I'm in need to restore a table and I do: mysqldump --opt database table_name < table_name.sql I hit enter and Done! Well, not really, when I go to see if there is anything on the table it show 0 records. I have look into the table_name.sql and I see two records. What am I doing wrong?

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  • Generating SQL for website

    - by Ethan
    I am working on a webapplication How can i create SQL for the following Database Information User information Username - String Password - String Admin or Client - boolean Last login – Date/Time LogItem typeLogItem – String (Page name?) hitCount – int View PageURL UserID Transaction User – String DateTimeStamp SKU – int Purchase-boolean TransactionID-int Inventory information Sku number - int Item description - String Price to customer - double Count - in

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  • inserting facebook app users details to database

    - by fusion
    i'm trying to insert user details, who authorize the app, into the database, but nothing seems to be happening. the data is null and no record is being inserted. is there something wrong with the code? function insertUser($user_id,$sk,$conn) { //$info = $facebook->api_client->users_getInfo($user_id, 'first_name, last_name', 'name', 'sex'); $info = $facebook->api_client->fql_query("SELECT uid, first_name, last_name, name, sex FROM user WHERE uid = $user_id"); for ($i=0; $i < count($info); $i++) { $record = $info[$i]; $first_name=$record['first_name']; $last_name=$record['last_name']; $full_name=$record['name']; $gender=$record['sex']; } $data= mysql_query("select uid from users where uid='{$user_id}'",$conn); if(mysql_num_rows($data)==0) { $sql = "INSERT INTO users (uid,sessionkey, active, fname, lname, full_name, gender) VALUES('{$user_id}','{$sk}','1', '{$first_name}', '{$last_name}', '{$full_name}', '{$gender}')"; mysql_query($sql,$conn); return true; } return false; }

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  • Select multiple records by one query

    - by kofto4ka
    Hello there. Please, give me advice, how to construct select query. I have table table with fields type and obj_id. I want to select all records in concordance with next array: $arr = array( 0 => array('type' => 1, 'obj_id' => 5), 1 => array('type' => 3, 'obj_id' => 15), 2 => array('type' => 4, 'obj_id' => 14), 3 => array('type' => 12, 'obj_id' => 17), ); I want to select needed rows by one query, is it real? Smth like select * from `table` where type in (1,3,4,12) and obj_id in (5,15,14,17) But this query returns also records with type = 3 and obj_id = 14, and for example type = 1 and obj_id = 17. p.s. moderators, please fix my title, I dont know how to describe my question.

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  • What SQL query should I perform to get the result set expected?

    - by texai
    What SQL query should I perform to get the result set expected, giving the first element of the chain (2) as input data, or any of them ? table name: changes +----+---------------+---------------+ | id | new_record_id | old_record_id | +----+---------------+---------------+ | 1| 4| 2| | -- non relevant data -- | | 6| 7| 4| | -- non relevant data -- | | 11| 13| 7| | 12| 14| 13| | -- non relevant data -- | | 31| 20| 14| +----+---------------+---------------+ Result set expected: +--+ | 2| | 4| | 7| |13| |14| |20| +--+ I know I should consider change my data model, but: What if I couldn't? Thank you in advance!

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  • detection of 'flush tables with read lock' in php

    - by theduke0
    I would like to know from my application if a myisam table can accept writes (i.e. not locked). If an exception is thrown, everything is fine as I can catch this and log the failed statement to a file. However, if a 'flush tables with read lock' command has been issued (possibly for backup), the query I send will pretty much hang out forever. If one table is locked at a time, insert delayed works well. But when this global lock is applied, my query just waits. The query I run is an insert statement. If this statement fails or hangs, user experience is degraded. I need a way to send the query to the server and forget about it (pretty much). Does anyone have any suggestions on how to deal with this? -set a query timeout? -run asyncronous request and allow for the lock to expire while application continues? -fork my php process? Please let me know if I can provide and clarification or details.

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  • retrieve value from db in php

    - by wangdoo
    I have a db in which 1 column value will be always null.I want it to pass to next page but it is passing all values of other column except this null value column. This is my code $row=mysql_query("SELECT * FROM `thirdpartycategorymaster` WHERE ISNULL(`delete`)"); while($row1=mysql_fetch_array($row)) { <td><b><a href="catdel.php?head1=<?php echo $row1['ThirdPartyCategoryName'] . '&&msg1=' . $row1['ThirdPartyCategoryID'] . '&&ctdel=' . $row1['delete']; ?> ">Delete</a></b></td> This my db table ThirdPartyCategoryID ThirdPartyCategoryName delete 29 ecommerce NULL

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  • Autopopulate from Select box from database

    - by Chris Spalton
    hope you can help, please forgive any poor coding or anytihng, I'm new to this and just hacking my way through to get things to work. That said, on one of my projects I have this code, which successfully populates the dropdown from a database when the page is loaded: <select name="Region" id="Region"> <option value="">-- Select Region --</option> <?php $region=$POST['Region']; if ($region); { $regionquery = "SELECT DISTINCT REGION FROM Sales_Execs "; $regionresult = mysql_query($regionquery); while($row = mysql_fetch_array($regionresult)) { echo "<option value=\"".$row['REGION']."\">".$row['REGION']."</option>\n "; } } ?> <script type="text/javascript"> document.getElementById('Region').value = <?php echo json_encode(trim($_POST['Region']));?>; </script> </select> On my next project that I'm working on now, I need to do the same thing, so I copied the above code amended, and placed in my new project: <select name="Sales_Exec" id="Sales_Exec"> <option value="">-- Select SE --</option> <?php $salesexec=$POST['Sales_Exec']; if ($salesexec); { $salesexecquery = "SELECT DISTINCT Assigned FROM Data "; $salesexecresult = mysql_query($salesexecquery); while($row = mysql_fetch_array($salesexecresult)) { echo "<option value=\"".$row['ASSIGNED']."\">".$row['ASSIGNED']."</option>\n "; } } ?> <script type="text/javascript"> document.getElementById('Sales_Exec').value = <?php echo json_encode(trim($_POST['Sales_Exec']));?>; </script> </select> This second chunk of code doesn't work... and I can't work out why as it seems I've copied it all and amended all the neccersary parts, can anyone spot what is wrong? Thankyou!

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  • Database design for business numbers

    - by Rob Morris
    I'm in need of some help, I need to store the information below into a database, what would the relational database structure be for this: Then I need to create a dropdown for the insurance company followed by another dropdown depending on what the first dropdown selected value was, then once both selects have been chosen display the relevant telephone number. I guess i need to query the database, then display the dropdowns using javascript(jquery) or Ajax?

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