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  • Stop output of image if no record - paperclip - Ruby on rails

    - by bgadoci
    I have just installed paperclip into my ruby on rails blog application. Everything is working great...too great. I am trying to figure out how to tell paperclip not to output anything if there is no record in the table so that I don't have broken image links everywhere. How, and where, do I do this? Here is my code: class Post < ActiveRecord::Base has_attached_file :photo, :styles => { :small => "150x150"} validates_presence_of :body, :title has_many :comments, :dependent => :destroy has_many :tags, :dependent => :destroy has_many :ugtags, :dependent => :destroy has_many :votes, :dependent => :destroy belongs_to :user after_create :self_vote def self_vote # I am assuming you have a user_id field in `posts` and `votes` table. self.votes.create(:user => self.user) end cattr_reader :per_page @@per_page = 10 end View <% div_for post do %> <div id="post-wrapper"> <div id="post-photo"> <%= image_tag post.photo.url(:small) %> </div> <h2><%= link_to_unless_current h(post.title), post %></h2> <div class="light-color"> <i>Posted <%= time_ago_in_words(post.created_at) %></i> ago </div> <%= simple_format truncate(post.body, :length => 600) %> <div id="post-options"> <%= link_to "Read More >>", post %> | <%= link_to "Comments (#{post.comments.count})", post %> | <%= link_to "Strings (#{post.tags.count})", post %> | <%= link_to "Contributions (#{post.ugtags.count})", post %> | <%= link_to "Likes (#{post.votes.count})", post %> </div> </div> <% end %>

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  • How can one extract rdf:about or rdf:ID properties from triples using SPARKQL?

    - by lennyks
    It seemed a trivial matter at the beginning but so far I had not managed to get unique identifier for a given resource using SPARKQL. What I mean is given, let say, rdf:Description rdf:about="http://..." and then some properties identifying this resource, what I want to do is to first find this very resource and then retrieve all the triples given some uri. I have tried naive approaches by writing statements in a WHERE clause such as ?x rdf:about ?y and ?x rdfs:about ?y. I hope I am being precise.

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  • Problem signing jars for web applet

    - by nuno_cruz
    keytool -genkey -keystore myKeyStore -alias me keytool -selfcert -keystore myKeyStore -alias me jarsigner -keystore myKeyStore jarfile.jar me I'm using this way to sign jars. I use my jar and a few more as libraries and all of them are signed this way, still, when I open the browser I get the warning that there is signed and unsigned code. So this is confusing me... :/ http://dl.dropbox.com/u/1430071/images/errormessage.png

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  • AWS free tier "sign up date" vs "credit card details submission date"

    - by Mayur Rokade
    I am worried about my account expiry date. I created an account on AWS in July 2013 and submitted my credit card details on 31st Oct 2013. I went in Billing Management Console/Bills section where when I click on Date, I can see months ranging from July 2013 to Nov 2013. From AWS FAQs I gathered When does the AWS free usage tier expire? The AWS free usage tier will expire 12 months from the date you sign up. So WHEN will my account expire, July 2014 (sign up date) or Oct 2014 (credit card details submission date) ?

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  • WCF Web/ServiceHost - Singletons and initialisation

    - by Kyle
    I have some Service class which is defined as InstanceContextMode.Single, and is well known in the hosting application. (The host creates an instance, and passes that to the WebServiceHost) Hosting app:WebServiceHost host = null; SomeService serviceInstance = new SomeService("text", "more text"); host = new WebServiceHost(serviceInstance, baseUri); Problem: When I go to use the variables initialised when the service is created (ie, when a call is made to the service), they are either null or empty... Am I wrong in assuming that as the instance being initialised in the hosting application is used for each request to the WebServiceHost? Any pointers here would be great.

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  • How to let one external stylsheet selectively overrule the other

    - by Ferdy
    I'm stunned by a simple thing that I want to accomplish but does not work. I have a website and I want it to support themes, which are a named set of CSS + images. No matter which theme is selected, I always include the main CSS file, which is the default theme. On top of that I'm loading a second stylesheet, the one that is theme-specific, like so: <link rel="stylesheet" type="text/css" href="css/main.css" title=main" media="screen" /> <link rel="stylesheet" type="text/css" href="themes/<?= $style ?>/css/<?= $style ?>.css" title="<?= $style ?>" media="screen" /> My idea is that the theme specific css should not be a full copy of the main css file. Instead, it should only contain CSS rules that overrule those of the main.css file. This makes themes much smaller and easier to maintain. I thought I could simply load two external stylesheets after each other and that for conflicting rules it will always use the theme specific css, the second file. However, it does not seem to work. If I make a dramatic styling change in the theme file then it has no effect. If I then comment the main CSS file, the theme CSS does have effect. Was I too naive in expecting this to work like this? I know I can use inline styles to overrule anything, but I prefer a setup like this if possible.

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  • Website: Make printable version with footnotes?

    - by DavidR
    I have a website that uses editable divs so that a user can modify or make notes to a text. Is there a way I can have the website generate a pdf or some printable document with footnotes, such that if a user has this: <div class="text" id="text_1"> <div class="bodyTest">This is the body text</div> <div class="notes">These are the notes</div> </div> <div class="text" id="text_2"> <div class="bodyTest">This is the body text</div> <div class="notes">These are the notes</div> </div> the website will generate a printable version (or document) in such a way thatdiv.notes will appear as a footnote on the same page on which div#text_1 appears? I don't need a full answer, just a shove in the general direction will be amazing. Thanks.

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  • getting web page data as json object?

    - by encryptor
    I have a url, the data of which page i need as a json object. I ve tried xmlhttprequest and ajaxobject both but doesnt work. It doesnt even give a responseText when I give it as an alert Ill post both the code snippets here. url = http://mydomain.com:port/a/b/c AJAX : var ajaxRequest = new ajaxObject(URL); ajaxRequest.callback = function (responseText,responseStatus) { alert(responseStatus); JSONData = responseText.parseJSON(); processData(JSONData); } USING xmlhttprequest: var client = new XMLHttpRequest(); client.open('GET',URL,true ); data = JSON.parse(client.responseText); alert(data.links.length); can someone please help me out with this. I understand cross scripting may be an issue, but how to come over it? and shouldn't then too it should give the alerts as zero or null

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  • DIV with text over an image on hover.

    - by Dylan Taylor
    OKay first off this is really really similiar to the http://dribbble.com homepage. In the simplest form possible. I have an image, and i'm trying to CSS it so that when i hover over the image, a DIV shows up with some text and a partially transparent background color. I have no idea how to do this..

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  • Connecting to a web server over HTTP, code snippet

    - by Emanuil
    I'v got the following piece of code: try { HttpClient httpClient = new DefaultHttpClient(); HttpPost httpPost = new HttpPost("http://www.flashstall.com/json.txt"); HttpResponse httpResponse = httpClient.execute(httpPost); } catch (Exception e) { Log.e("m40", "Error in http connection " + e.toString()); } When I run it it logs "Error in http connection java.net.UnkownHostException: www.flashstall.com". What am I doing wrong?

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  • How do I modify this jQuery :submit selector example?

    - by Tommy
    Looking at this jQuery example, how can I modify the code so that it only changes the color of the cell if the value of the submit button in that cell is a certain value. i.e.- var submitEl = $("td :submit") //Only do the below if the submit buttons value is "XYZ" .parent('td') .css({background:"yellow", border:"3px red solid"})

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  • require_owner code to limit controller actions not recognizing current user as owner

    - by bgadoci
    I am trying to restrict access to certain actions using a before_filter which seems easy enough. Somehow the ApplicationController is not recognizing that the current_user is the owner of the user edit action. When I take the filter off the controller correctly routes the current_user to their edit view information. Here is the code. Link to call edit action from user controller (views/questions/index.html.erb): <%= link_to "Edit Profile", edit_user_path(:current) %> ApplicationController (I am only posting the code that I think is affecting this but can post the whole thing if needed). class ApplicationController < ActionController::Base def require_owner obj = instance_variable_get("@#{controller_name.singularize.camelize.underscore}") # LineItem becomes @line_item return true if current_user_is_owner?(obj) render_error_message("You must be the #{controller_name.singularize.camelize} owner to access this page", root_url) return false end end and the before_filter class UsersController < ApplicationController before_filter :require_owner, :only => [:edit, :update, :destroy] #... end I simply get the rendering of the error message from the ApplicationController#require_owner action.

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  • Standalone jQuery "touch" method?

    - by dclowd9901
    So, I'm looking to implement the ability for a plugin I wrote to read a touch "swipe" from a touch-capable internet device, like an iPhone, iPad or android. Is there anything out there? I'm not looking for something as full as jQtouch, though was considering reverse engineering the code I would need out of it. Any suggestions on the best way to approach this? A snippet of code already available? Addendum: I realize in hindsight the solution won't strictly be jQuery, as I'm pretty sure there aren't any built-in methods to handle this. I would expect standard Javascript to find itself in the answer.

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  • Cross-browser method for hiding page elements until all content is loaded to prevent layout from appearing broken during load?

    - by Ryan
    I have an issue where due to some elements loading faster than others, the page looks broken for a few seconds at the start. An example is the CSS Pie behavior that allows me to do curved corners in IE, it appears before it becomes curved which looks bad. What would be ideal would be it somehow knowing when everything is loaded and then appear all at once, possibly including some kind of elegant visual way of not making the user feel impatient... any ideas or common tricks for doing this?

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  • Has anybody developed an auto part ecommerce site?

    - by Sam Kong
    Hi, I need to develop an e-Commerce site that sells auto parts. For that, I need a database that has year/make/model information that each part is applicable to. As far as I know, we need to purchase the database and subscribe updates. Is there any database available for free? (I may not need updates) Thanks. Sam

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  • Use .js files for caching large dropdown lists.

    - by ProfK
    I would like to keep the contents of large UI lists cached on the client, and updated according to criterial or regularly. Client side code can then just fill the dropdowns locally, avoiding long page download times. How can I go about this? I mean, what patterns and strategies would be suitable for this?

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  • How to output multicolumn html without "widows"?

    - by user314850
    I need to output to HTML a list of categorized links in exactly three columns of text. They must be displayed similar to columns in a newspaper or magazine. So, for example, if there are 20 lines total the first and second columns would contain 7 lines and the last column would contain 6. The list must be dynamic; it will be regularly changed. The tricky part is that the links are categorized with a title and this title cannot be a "widow". If you have a page layout background you'll know that this means the titles cannot be displayed at the bottom of the column -- they must have at least one link underneath them, otherwise they should bump to the next column (I know, technically it should be two lines if I were actually doing page layout, but in this case one is acceptable). I'm having a difficult time figuring out how to get this done. Here's an example of what I mean: Shopping Link 3 Link1 Link 1 Link 4 Link2 Link 2 Link 3 Link 3 Cars Link 1 Music Games Link 2 Link 1 Link 1 Link 2 News As you can see, the "News" title is at the bottom of the middle column, and so is a "widow". This is unacceptable. I could bump it to the next column, but that would create an unnecessarily large amount of white space at the bottom of the second column. What needs to happen instead is that the entire list needs to be re-balanced. I'm wondering if anyone has any tips for how to accomplish this, or perhaps source code or a plug in. Python is preferable, but any language is fine. I'm just trying to get the general concept down.

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  • Disable printing in adobe Flex

    - by Ankur Chauhan
    I am building my website in adobe flex(i am n00b). I have some photographs which I would like to make sure that people cannot print. I do understand that it is not possible to completely stop users from printing. But atleast disable the context menu or just the print option and the copy option. Any and all things about this is helpful

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