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  • PHP from database and query

    - by Kyle R
    I have a table: id, affiliate Each time somebody clicks a link, a new row is inserted, ID being the ID of the page, and affiliate being the ID of the affiliate. For example: Page ID: 9 Affiliate ID: 1 Page ID: 9 Affiliate ID: 2 Page ID: 9 Affiliate ID: 3 I only have 3 affiliates. I want to select this information, and group them by affiliate, for the ID. I have tried this query: SELECT COUNT(*) FROM table WHERE id = '9' GROUP BY affiliate It works fine when I do it in php my admin, how do I get the info in PHP? I have tried: $q = mysql_query("SELECT COUNT(*) FROM table WHERE id = '" . $id . "' GROUP BY affiliate"); $r = mysql_fetch_array($q); When trying to print the data onto the page, I am only getting one result. Do I need to use a foreach/while loop to get all 3? How would I go about doing this? Thank you!

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  • How can I Create a CMS using php where end user doesn't have to know anything about database. Is that possible

    - by cryptex_vinci
    In genera sense if I create a CMS using php .Where I created and named the database in my localhost. Now if I or my clent upload the CMS in any server how will it work. because there is no database in that server. And in my php code I wrote to create database. Now how can i create a CMS which can automatically create database and tables where client doesn't have to know about anything besides uploading the CMS.

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  • Working with sets of rows in (My)SQL and comparing values

    - by Pep.
    Hello, I am trying to figure out the SQL for doing some relatively simple operations on sets of records in a table but I am stuck. Consider a table with multiple rows per item, all identified by a common key. For example: serial model color XX1 A blue XX2 A blue XX3 A green XX5 B red XX6 B blue XX1 B blue What I would for example want to do is: Assuming that all model A rows must have the same color, find the rows which dont. (for example, XX3 is green). Assuming that a given serial number can only point to a single type of model, find out the rows which that does not occur (for example XX1 points both to A and B) These are all simple logically things to do. To abstract it, I want to know how to group things by using a single key (or combination of keys) and then compare the values of those records. Should I use a join on the same table? should i use some sort of array or similar? thanks for your help

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  • Persisting Serializable Objects in Hibernate

    - by VeeArr
    I am attempting to persist objects that contain some large Serializable types. I want Hibernate to automatically generate my DDL (using Hibernate annotations). For the most part, this works, but the default database column type used by Hibernate when persisting these types is tinyblob. Unfortunately, this causes crashes when attempting to persist my class, because these types will not fit within the length of tinyblob. However, if I manually set the type (using @Column(columnDefinition="longblob")), it works fine. Is there any way to make the default binary type longblob instead of tinyblob, so that I don't need to manually specify the @Column annotation on each field?

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  • Retrieve Specific Data/Value From Database 1 Line PHP

    - by Belgin Fish
    Hi, I'm just wondering how I can retrieve a specific value (only 1 thing will be returned) from a database using php. My query is mysql_query("SELECT balance FROM users WHERE username = '". $this->username . "'") I'm just looking for it to retrieve the data from that row so I can save it directory into a variable.

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  • Select products with users

    - by Ploppe
    I have not worked with SQL for quite a long time, and I need some help for a basic query. I have the three following tables: users (id, name) products (id, name) owners (userid, productid, date) One product can be sold by user A to user B and then back to A. Now, I want the list of all products currently owned by every single user with the date of transaction. Currently, my query is this one, but I'm stuck with old data (first association of one product to one user, and not the newest one): SELECT users.name, products.name, date FROM products JOIN owners ON products.id = owners.id JOIN users ON owners.id = user.id GROUP BY product.id Do you have some hints? Thanks

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  • adding count( ) column on each row

    - by Arsenal
    I'm not sure if this is even a good question or not. I have a complex query with lot's of unions that searches multiple tables for a certain keyword (user input). All tables in which there is searched are related to the table book. There is paging on the resultset using LIMIT, so there's always a maximum of 10 results that get withdrawn. I want an extra column in the resultset displaying the total amount of results found however. I do not want to do this using a seperate query. Is it possible to add a count() column to the resultset that counts every result found? the output would look like this: ID Title Author Count(...) 1 book_1 auth_1 23 2 book_2 auth_2 23 4 book_4 auth_.. 23 ... Thanks!

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  • Obtaining a timestamp every minute from a database

    - by soumen
    This is my table structure: +------------+-----------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +------------+-----------+------+-----+---------+-------+ | uid | char(255) | NO | MUL | NULL | | | cid | char(255) | NO | MUL | NULL | | | ip_address | char(15) | NO | | NULL | | | user_agent | char(255) | YES | | NULL | | | open_date | datetime | NO | MUL | NULL | | | referrer | char(255) | YES | | NULL | | | environ | text | YES | | NULL | | | country | char(255) | NO | MUL | NULL | | +------------+-----------+------+-----+---------+-------+ I want to get a timestamp every minute within a range. select DATE_ADD(open_date,interval 1 minute) as m from open_track.camp_open where open_date between "2009-05-13 00:00:00" and "2009-05-13 23:59:59" limit 10; outputs +---------------------+ | m | +---------------------+ | 2009-05-13 00:01:01 | | 2009-05-13 00:01:02 | | 2009-05-13 00:01:03 | | 2009-05-13 00:01:03 | | 2009-05-13 00:01:04 | | 2009-05-13 00:01:05 | | 2009-05-13 00:01:06 | | 2009-05-13 00:01:08 | | 2009-05-13 00:01:08 | | 2009-05-13 00:01:09 | +---------------------+ Please advise me.

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  • CodeIgniter - numbers in sql query are masked with ``

    - by Checkson
    Hello, i'm using CodeIgniter for developing a community board. As I'm using nested sets to get a nested forum hierarchy, I have to run a lot of queries such as: SELECT `id` FROM `forums` WHERE 1 BETWEEN `lft` AND `rgt` My problem: CodeIgniter is replacing the "1" by "`1`" because the "1" is recognized as a column name. Of course, the query does not work any more. Is there a way to get it working? thx in advance

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  • Thumbnailing and then Saving as a Blob with PHP in Wordpress

    - by Parris
    The below code seems like it should work; however, the blob in the database only contains 0 after the function is run. Does the below code look accurate? If not how can I fix it? $tmpName = $_FILES['picture']['tmp_name']; $fp = fopen($tmpName, 'r'); $binary = fread($fp, filesize($tmpName)); fclose($fp); $originalImage = imagecreatefromstring($binary); $tempImage = imagecreate(100,100); imagecopyresized($tempImage,$originalImage,0,0,0,0,100,100); ob_start(); imageJPEG($tempImage); $thumbnail = ob_get_contents(); ob_end_clean(); $wpdb->query("UPDATE ".$wpdb->prefix."items SET picture = $thumbnail WHERE id=$id'"); Thank :)!

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  • Error including errno.h

    - by TechWiz
    Every time I try to compile a project that includes errno.h in linux, I get issues using the error codes. GCC spits out errors saying the error codes aren't declared and I get the same issue with 3rd party projects that are, of course, known to compile. I have the Linux headers for my kernel installed. Any suggestions as to what else it could be? edit: Snippet at error code: if ((res != 0) && (errno == EEXIST)) Snippet of includes: ... #include <dirent.h> #include <errno.h> #include <stdarg.h> ... as is with no ifdef edit: Well I'm convinced my system's Linux headers are hosed somehow... that, or I'm missing some environment vars.

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  • Does it make sense to replace sub-queries by join?

    - by Roman
    For example I have a query like that. select col1 from t1 where col2>0 and col1 in (select col1 from t2 where col2>0) As far as I understand, I can replace it by the following query: select t1.col1 from t1 join (select col1 from t2 where col2>0) as t2 on t1.col1=t2.col1 where t1.col2>0 ADDED In some answers I see join in other inner join. Are both right? Or they are even identical?

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  • Where to store users visited pages?

    - by kofto4ka
    Hi there. I have a project, where I have posts for example. The task is next: I must show to user his last posts visit. This is my solution: every time user visits new (for him) topic, I create a new record in table visits. Table visits has next structure: id, user_id, post_id, last_visit. Now my tables visits has ~14,000,000 records and its still growing every day.. May be my solution isnt optimal and exists another way how to store users visits? Its important to save every visit as standalone record, because I also have feature to select and use users visits. And I cant purge this table, because data could be needed later month, year. How I could optimize this situation?

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  • limiting a query to a specific item

    - by Dev-Ria
    I have a db with thousands of domains and data. I want to list only 100 rows of each domain. i can't use LIMIT 100 cause that only limits 100 records but I want dom1 to list 100 dom2 to list 100 dom3 to list 100 all in one query. This is what I have so far. SELECT domain COUNT(Key) AS DomCount FROM table_domain GROUP BY user,location ORDER BY domain,DomCount DESC Could I use a CASE?

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  • Update all but one result?

    - by Jack M.
    I'm trying to update a table to remove all but the first instance of a group. Basically, I have a table with vehicle data related to an insurance policy. Each policy should only have one power_unit. Everything else should be a towed unit. Unfortunately, a bug has been duplicating power units, and now I need to clean this up. There are ~10k records in the database, and ~4k of them have doubled up power units. The important bits of my table (call it test1 for now) are: +------------+---------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +------------+---------+------+-----+---------+----------------+ | id | int(10) | NO | PRI | NULL | auto_increment | | policy_id | int(10) | NO | | NULL | | | power_unit | int(1) | NO | | 0 | | +------------+---------+------+-----+---------+----------------+ And some sample data: +----+-----------+------------+ | id | policy_id | power_unit | +----+-----------+------------+ | 1 | 1 | 1 | | 2 | 1 | 1 | | 3 | 1 | 1 | | 4 | 2 | 1 | | 5 | 2 | 1 | | 6 | 2 | 1 | | 7 | 4 | 1 | | 8 | 4 | 1 | | 9 | 4 | 1 | | 10 | 5 | 1 | | 11 | 5 | 1 | | 12 | 6 | 1 | +----+-----------+------------+ Basically I'd like to end up where policy_id 1 has only one power_unit=1. Same for policy_id 2, 3, 4, etc. For policy_id 6, nothing should change (there is only one entry, and it is a power_unit already). I don't know if this is possible, but it was an intriguing problem for me, so I thought you guys might find it the same.

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  • Best way to update record X when Y is inserted

    - by Saif Bechan
    I have a huge table that is mainly used for backup and administrative purposes. The only records that matters is the last inserted record. On every hit to order by time inserted is just too slow. I want keep a separate table with the last inserted id. In PHP I now insert, get last inserted id, and update the other table. Is there a more efficient way to do this.

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  • Online Hotel Booking System, Simultaneous Booking?

    - by KiiroSora09
    I'm asked to create an online booking system with online payment and I'm wondering what to do in the case when 2 customers booked for the same room(s) at the same time. For Example: At the same time: Customer1 and Customer2 booked for a standard room which only has 1 room available. (The Room availability will display that there is still 1 room available). And then they hit the 'confirm' button at the same time.

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