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  • Join two list comparing their elements properties

    - by 100r
    public class Person() { int ID; string Name; DateTime ChangeDate } var list1 = new List<Person> { new Person { ID= 1, Name = "Peter", ChangeDate= "2011-10-21" }, new Person { ID= 2, Name = "John", ChangeDate= "2011-10-22" }, new Person { ID= 3, Name = "Mike", ChangeDate= "2011-10-23" }, new Person { ID= 4, Name = "Dave", ChangeDate= "2011-10-24" } }; var list2 = new List<Person> { new Person { ID= 1, Name = "Pete", ChangeDate= "2011-10-21" }, new Person { ID= 2, Name = "Johny", ChangeDate= "2011-10-20" }, new Person { ID= 3, Name = "Mikey", ChangeDate= "2011-10-24" }, new Person { ID= 5, Name = "Larry", ChangeDate= "2011-10-27" } }; As output I would like to have list1 + list2 = Person { ID= 1, Name = "Peter", ChangeDate= "2011-10-21" }, Person { ID= 2, Name = "John", ChangeDate= "2011-10-22" }, Person { ID= 3, Name = "Mikey", ChangeDate= "2011-10-24" }, Person { ID= 4, Name = "Dave", ChangeDate= "2011-10-24" } Person { ID= 5, Name = "Larry", ChangeDate= "2011-10-27" } And the Algorithm is like this. Join two list. If elements of lists have same ID, compare them by ChangeDate and take the ond with bigger date. If ChangeDate are equeal take any of them but not both. Maybe its easier to concat both lists and than to filter them with lambda. I tried, but always came out with some ugly code :/ Anyone have any idea?

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  • glibc detected ./.a.out: free(): invalid pointer

    - by ExtremeBlue
    typedef struct _PERSON { size_t age; unsigned char* name; }PERSON; int init(PERSON** person) { (* person) = (PERSON *) malloc(sizeof(struct _PERSON)); (* person)->age = 1; (* person)->name = (unsigned char *) malloc(sizeof(4)); (* person)->name = "NAME"; return 0; } void close(PERSON** person) { (* person)->age = 0; if((* person)->name != NULL) { free((* person)->name); } if((* person) != NULL) { free((* person)); } } int main(int argc, char* argv[]) { PERSON* p; init(&p); printf("%d\t%s\n", (int) p->age, p->name); close(&p); return 0; } 1 NAME *** glibc detected *** ./a.out: free(): invalid pointer: 0x000000000040079c *** ======= Backtrace: ========= /lib/libc.so.6(+0x774b6)[0x7fa9027054b6] /lib/libc.so.6(cfree+0x73)[0x7fa90270bc83] ./a.out(close+0x3d)[0x400651] ./a.out[0x40069f] /lib/libc.so.6(__libc_start_main+0xfe)[0x7fa9026acd8e] ./a.out[0x4004f9] ... 7fa8fc000000-7fa8fc021000 rw-p 00000000 00:00 0 7fa8fc021000-7fa900000000 ---p 00000000 00:00 0 7fa902478000-7fa90248d000 r-xp 00000000 08:12 23068732 /lib/libgcc_s.so.1 7fa90248d000-7fa90268c000 ---p 00015000 08:12 23068732 /lib/libgcc_s.so.1 7fa90268c000-7fa90268d000 r--p 00014000 08:12 23068732 /lib/libgcc_s.so.1 7fa90268d000-7fa90268e000 rw-p 00015000 08:12 23068732 /lib/libgcc_s.so.1 7fa90268e000-7fa902808000 r-xp 00000000 08:12 23068970 /lib/libc-2.12.1.so 7fa902808000-7fa902a07000 ---p 0017a000 08:12 23068970 /lib/libc-2.12.1.so 7fa902a07000-7fa902a0b000 r--p 00179000 08:12 23068970 /lib/libc-2.12.1.so 7fa902a0b000-7fa902a0c000 rw-p 0017d000 08:12 23068970 /lib/libc-2.12.1.so 7fa902a0c000-7fa902a11000 rw-p 00000000 00:00 0 7fa902a11000-7fa902a31000 r-xp 00000000 08:12 23068966 /lib/ld-2.12.1.so 7fa902c25000-7fa902c28000 rw-p 00000000 00:00 0 7fa902c2e000-7fa902c31000 rw-p 00000000 00:00 0 7fa902c31000-7fa902c32000 r--p 00020000 08:12 23068966 /lib/ld-2.12.1.so 7fa902c32000-7fa902c33000 rw-p 00021000 08:12 23068966 /lib/ld-2.12.1.so 7fa902c33000-7fa902c34000 rw-p 00000000 00:00 0 7fff442d5000-7fff442f6000 rw-p 00000000 00:00 0 [stack] 7fff44308000-7fff44309000 r-xp 00000000 00:00 0 [vdso] ffffffffff600000-ffffffffff601000 r-xp 00000000 00:00 0 [vsyscall] Aborted

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  • Google lance son outil Person Finder suite au tsunami japonais, pour aider les personnes concernées par le drame

    Google relance son outil Person Finder suite au tsunami japonais, la base de données devrait aider à prendre des nouvelles des personnes touchées par le drame Suite au terrible Tsunami qui a ravagé le Japon ce matin après un tremblement de terre de magnitude 8.9, Google a mis en place un service d'aide aux victimes et à leurs proches. Person Finder, une sorte de grande base de données participative, permettra de lancer un avis de recherche pour quelqu'un doit on souhaite avoir des nouvelles, mais aussi sera à la disposition des personnes touchées par la catastrophe pour publier des messages assurant qu'ils vont bien et donnant des informations sur la situation. Le service est accessible depuis Google.com et se prése...

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  • Plongée dans les entrailles de l'outil Person Finder de Google, une API open-source codée en Python

    Plongée dans les entrailles de l'outil Person Finder de Google, une API open-source codée en Python Mise à jour du 14.03.2011 par Katleen Comme indiqué dans la news précédente, Google a lancé son outil Person Finder à destination des personnes concernées par le drame survenu le 11.03.2011 au Japon (victimes et entourage de victimes). Ce service a déjà servi auparavant, lors des sinistres de Haiti ou de Christchurch par exemple. En fait, il est né à l'initiative de la firme comme projet sur Google.org, dans le cadre du secteur Google Crisis Response qui y a été lancé en janvier 2010 (séisme d'Haïti), en réponse ...

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  • How to convert an ORM to its subclass using Hibernate ?

    - by Gaaston
    Hi everybody, For example, I have two classes : Person and Employee (Employee is a subclass of Person). Person : has a lastname and a firstname. Employee : has also a salary. On the client-side, I have a single HTML form where i can fill the person informations (like lastname and firstname). I also have a "switch" between "Person" and "Employee", and if the switch is on Employee I can fill the salary field. On the server-side, Servlets receive informations from the client and use the Hibernate framework to create/update data to/from the database. The mapping i'm using is a single table for persons and employee, with a discriminator. I don't know how to convert a Person in an Employee. I firstly tried to : load the Person p from the database create an empty Employee e object copy values from p into e set the salary value save e into the database But i couldn't, as I also copy the ID, and so Hibernate told me they where two instanciated ORM with the same id. And I can't cast a Person into an Employee directly, as Person is Employee's superclass. There seems to be a dirty way : delete the person, and create an employee with the same informations, but I don't really like it.. So I'd appreciate any help on that :) Some precisions : The person class : public class Person { protected int id; protected String firstName; protected String lastName; // usual getters and setters } The employee class : public class Employee extends Person { // string for now protected String salary; // usual getters and setters } And in the servlet : // type is the "switch" if(request.getParameter("type").equals("Employee")) { Employee employee = daoPerson.getEmployee(Integer.valueOf(request.getParameter("ID"))); modifyPerson(employee, request); employee.setSalary(request.getParameter("salary")); daoPerson.save(employee ); } else { Person person = daoPerson.getPerson(Integer.valueOf(request.getParameter("ID"))); modifyPerson(employee, request); daoPerson.save(person); } And finally, the loading (in the dao) : public Contact getPerson(int ID){ Session session = HibernateSessionFactory.getSession(); Person p = (Person) session.load(Person.class, new Integer(ID)); return p; } public Contact getEmployee(int ID){ Session session = HibernateSessionFactory.getSession(); Employee = (Employee) session.load(Employee.class, new Integer(ID)); return p; } With this, i'm getting a ClassCastException when trying to load a Person using getEmployee. XML Hibernate mapping : <class name="domain.Person" table="PERSON" discriminator-value="P"> <id name="id" type="int"> <column name="ID" /> <generator class="native" /> </id> <discriminator column="type" type="character"/> <property name="firstName" type="java.lang.String"> <column name="FIRSTNAME" /> </property> <property name="lastName" type="java.lang.String"> <column name="LASTNAME" /> </property> <subclass name="domain.Employee" discriminator-value="E"> <property name="salary" column="SALARY" type="java.lang.String" /> </subclass> </class> Is it clear enough ? :-/

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  • Randomize table guests in Excel

    - by Jo Voud
    I have a list of people: Column A: person A, person A guest, person B, person C, person C guest, ... Column B: 1, 1, 2, 3, 3, ... So in column A there is the person's name, column B gives a person a unique ID (the same id for their guest so we know that they are together). Now pretend we have a list of 100 people (also note that not all persons have guests) and we have to seat them. We have a list of tables (for example 10 * 4 person table and 10*6 person tables). We have to randomize that each person is assigned to a table and the guest is seated on the same table. What is the best way to do this? (it is also needed that I can generate this 4 times in a row without the same results, so when during the 4 courses of the diner the person are switching tables but not losing their guest).

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  • How to use Object Type Converter

    - by arun.x.sridharan(at)oracle.com
    UseCase Description A person form where in user will enter String which has to be converted to Number while persisting. From the User Interface we might be getting a String value which has to be persisted in the database as a number in that scenario we can use converters to map the java object which is of type String to its database value which is a Number. For example , there is a 'Person' table in database which is used to store the user details passed from the User Interface. It has a 'Status' column which is of the value  Number. But from the User Interface String values (Active/InActive) are passed . For persisting the user details we can use Object type converter and provide the mappings for status column corresponding to the String values. Object type converter can be used if you wanted to have a mapping for a field for example when departmentName on the entity was of String value and mapped to dept_name field on the database table which is of the value NUMBER.   Implementation steps Sample EJB API for setting the value of status on Person Entity as a String     public void createPerson(String status,String firstName,String lastName) {                Person person = new Person();                // status will be set as a String value received from the User Interface         person.setStatus(status);                person.setFirstname(firstName);        person.setLastname(lastName);                persistPerson(person);         } In the sample code shown above status is passed as a String, this has to be converted to Number. The String value obtained will be set on Person object and persistPerson API will be called for creating a new person from the values passed from the User Interface.  Steps to configure Object type converter: 1. Navigate to Person Entity from persistence.xml and navigate to status field2. Click on Conversion tab and select Converted check box3. Select Object Type Converter radio button and set the Data Type Class to      java.math.BigDecimal and Object Type Class to java.lang.String4. Specify the conversion values for all the values that can be passed from the user interface  as shown below5. Set the Default Object value

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  • Does a 77 Year Old Person Like To Use iPhone Siri? Of course!

    - by Gopinath
    When Apple releases any product, they just work irrespective of age, capability and ability of the users. It’s in the DNA of Steve Jobs and his colleagues at Apple to build products that just work with out any learning curve. The recent iPhone is loaded with Siri, an intelligent personal assistant. But can a 77 year old person quickly learn to use Siri for his day to day activities? Lets hear from a son who trained his 77 year old dad to use Siri on iPhone He caught on much faster than I thought he might. I was feeling proud of him and believed Siri would be a real productivity help in his life — seeing that, at 77, my dad still works full time as a realtor. I was encouraged that he really liked and would use his new personal assistant. Or at least I was until my mom called later that night. "Your father and I were just practicing with his new phone," Sigh. Well Siri will be great for my dad…if and when he remembers how to find her. Apple products are not for just techies like Android mobiles, they are for everyone. You can read the full story over here This article titled,Does a 77 Year Old Person Like To Use iPhone Siri? Of course!, was originally published at Tech Dreams. Grab our rss feed or fan us on Facebook to get updates from us.

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  • How do managers know if a person is a good or a bad programmer?

    - by Pavel Shved
    In most companies that do programming teams and divisions consist of programmers who design and write code and managers who... well, do the management stuff. Aside from just not writing code, managers usually do not even look at the code the team develops, and may even have no proper IDE installed on their work machines. Still, the managers are to judge if a person works well, if he or she should be put in charge of something, or if particular developer should be assigned to a task of the most importance and responsibility. And last, but not least: the managers usually assign the quarterly bonuses! To do the above effectively, a manager should know if a person is a good programmer—among other traits, of course. The question is, how do they do it? They don't even look at the code people write, they can't directly assess the quality of the components programmers develop... but their estimates of who is a good coder, and who is "not as good" are nevertheless correct in most cases! What is the secret?

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  • Is it bad to be the only person supporting software you have developed?

    - by trpt4him
    My employer has a need for a web-based application to manage and share data within the department, with approximately 50-75 possible users. I feel I have the ability to write it for them. I would likely use Python/Django with a MySQL database, so it would be open source. However, I'm the only IT person in my department (our larger organization has a separate IT support staff with which I often work, but not for web development). I want to develop this application, but if I leave in 1-2 years, and someone else has to come in after me and support it, will this be seen as a bad decision? This is assuming all the obvious points -- I will write documentation, I will comment my code, and I will strive to follow good application design principles. But will that be enough? In principle, is it acceptable for one person to develop and support an entire web application? Is this a "do first, then show and ask" kind of situation, or should I be certain it will be adopted by everyone involved first?

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  • How can I get my first-person character in Unity to move to a ledge with an animation?

    - by BallzOfSteel
    I'm trying to get this to happen: The character walks up to a large crate, the player presses a button, and an animation starts playing where the character climbs up on to the crate. (all in first person view). So far I tried this with normal "First Person Controller" Prefab in Unity. My code so far: function OnTriggerStay(other : Collider){ if(other.tag == "GrabZone"){ if(Input.GetKeyDown("e")){ animation.Play("JumpToLedge"); } } } However when i use this on The FPC it will always play from the position the animation is created on. I also tried to create an empty game object, placing the FPC in there. Gives same effect. I also tried just animating the graphics of the FPC alone. This seems to work but since the Character Controller itself is not animated that stays onthe ground. So the whole FPC wont work anymore. Is there anyway i could let this animation play on the local position the player is on at that time? Or can you think of any other logical solution for a grab and climb?

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  • With Eclipselink/JPA, can I have a Foreign Composite Key that shares a field with a Primary Composit

    - by user107924
    My database has two entities; Company and Person. A Company can have many People, but a Person must have only one Company. The table structure looks as follows. COMPANY ---------- owner PK comp_id PK c_name PERSON ---------------- owner PK, FK1 personid PK comp_id FK1 p_fname p_sname It has occurred to me that I could remove PERSON.OWNER and derive it through the foreign key; however, I can't make this change without affecting legacy code. I have modeled these as JPA-annotated classes; @Entity @Table(name = "PERSON") @IdClass(PersonPK.class) public class Person implements Serializable { @Id private String owner; @Id private String personid; @ManyToOne @JoinColumns( {@JoinColumn(name = "owner", referencedColumnName = "OWNER", insertable = false, updatable = false), @JoinColumn(name = "comp_id", referencedColumnName = "COMP_ID", insertable = true, updatable = true)}) private Company company; private String p_fname; private String p_sname; ...and standard getters/setters... } @Entity @Table(name = "COMPANY") @IdClass(CompanyPK.class) public class Company implements Serializable { @Id private String owner; @Id private String comp_id; private String c_name; @OneToMany(mappedBy = "company", cascade=CascadeType.ALL) private List people; ...and standard getters/setters... } My PersonPK and CompanyPK classes are nothing special, they just serve as a struct holding owner and the ID field, and override hashCode and equals(o). So far so good. I come across a problem, however, when trying to deal with associations. It seems if I have an existing Company, and create a Person, and associate to the Person to the Company and persist the company, the association is not saved when the Person is inserted. For example, my main code looks like this: EntityManager em = emf.createEntityManager(); em.getTransaction().begin(); CompanyPK companyPK = new CompanyPK(); companyPK.owner="USA"; companyPK.comp_id="1102F3"; Company company = em.find(Company.class, companyPK); Person person = new Person(); person.setOwner("USA"); person.setPersonid("5116628123"); //some number that doesn't exist yet person.setP_fname("Hannah"); person.setP_sname("Montana"); person.setCompany(company); em.persist(person); This completes without error; however in the database I find that the Person record was inserted with a null in the COMP_ID field. With EclipseLink debug logging set to FINE, the SQL query is shown as: INSERT INTO PERSON (PERSONID,OWNER,P_SNAME,P_FNAME) VALUES (?,?,?,?) bind = [5116628123,USA,Montana,Hannah,] I would have expected this to be saved, and the query to be equivalent to INSERT INTO PERSON (PERSONID,OWNER,COMP_ID,P_SNAME,P_FNAME) VALUES (?,?,?,?,?) bind = [5116628123,USA,1102F3,Montana,Hannah,] What gives? Is it incorrect to say updatable/insertable=true for one half of a composite key and =false for the other half? If I have updatable/insertable=true for both parts of the foreign key, then Eclipselink fails to startup saying that I can not use the column twice without having one set to readonly by specifying these options.

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  • Grails checkbox

    - by Tomáš
    Hi gurus I have trouble with binding Boolean property in association classes. Property is set to true if I check checkbox (good), but is null if checbox is not checked. I know the problem with HTML checkbox. I know why is send "_fieldName" in params, but this "_fieldName" dont set my boolean property to false. class Person{ String title List<Group> groups = new ArrayList() static hasMany = [groups: Groups] } class Group{ String title Boolean isHidden static belongTo = Person } class PersonController{ def form = { def person = new Person() person.groups.add( new Group() ) return ["person": person] } def handleForm = { def person = new Person( params ) println person.groups[0] } } If I check checkbox: [isHidden:on, title:a, _isHidden:] println person.groups[0] //true If I don check checkbox: [title:a, _isHidden:] println person.groups[0] //null Thank a lot for help Tom I am sorry, I searched this web, but did not get actual info for my trouble.

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  • Can someone here explain constructors and destructors in python - simple explanation required - new

    - by rgolwalkar
    i will try to see if it makes sense :- class Person: '''Represnts a person ''' population = 0 def __init__(self,name): //some statements and population += 1 def __del__(self): //some statements and population -= 1 def sayHi(self): '''grettings from person''' print 'Hi My name is %s' % self.name def howMany(self): '''Prints the current population''' if Person.population == 1: print 'i am the only one here' else: print 'There are still %d guyz left ' % Person.population rohan = Person('Rohan') rohan.sayHi() rohan.howMany() sanju = Person('Sanjivi') sanju.howMany() del rohan # am i doing this correctly --- ? i need to get an explanation for this del - destructor O/P:- Initializing person data ****************************************** Initializing Rohan ****************************************** Population now is: 1 Hi My name is Rohan i am the only one here Initializing person data ****************************************** Initializing Sanjivi ****************************************** Population now is: 2 In case Person dies: ****************************************** Sanjivi Bye Bye world there are still 1 people left i am the only one here In case Person dies: ****************************************** Rohan Bye Bye world i am the last person on earth Population now is: 0 If required i can paste the whole lesson as well --- learning from :- http://www.ibiblio.org/swaroopch/byteofpython/read/

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  • python __getattr__ help

    - by Stefanos Tux Zacharakis
    Reading a Book, i came across this code... # module person.py class Person: def __init__(self, name, job=None, pay=0): self.name = name self.job = job self.pay = pay def lastName(self): return self.name.split()[-1] def giveRaise(self, percent): self.pay = int(self.pay *(1 + percent)) def __str__(self): return "[Person: %s, %s]" % (self.name,self.pay) class Manager(): def __init__(self, name, pay): self.person = Person(name, "mgr", pay) def giveRaise(self, percent, bonus=.10): self.person.giveRaise(percent + bonus) def __getattr__(self, attr): return getattr(self.person, attr) def __str__(self): return str(self.person) It does what I want it to do, but i do not understand the __getattr__ function in the Manager class. I know that it Delegates all other attributes from Person class. but I do not understand the way it works. for example why from Person class? as I do not explicitly tell it to. person(module is different than Person(class) Any help is highly appreciated :)

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  • Static variables in Java for a test oObject creator

    - by stevebot
    Hey, I have something like the following TestObjectCreator{ private static Person person; private static Company company; static { person = new Person() person.setName("Joe"); company = new Company(); company.setName("Apple"); } public Person createTestPerson(){ return person; } public Person createTestCompany(){ return company; } } By applying static{} what am I gaining? I assume the objects are singletons as a result. However, if I did the following: Person person = TestObjectCreator.createTestPerson(); person.setName("Jill"); Person person2 = TestObjectCreator.createTestPerson(); would person2 be named Jill or Joe?

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  • How to optimise MySQL query containing a subquery?

    - by aidan
    I have two tables, House and Person. For any row in House, there can be 0, 1 or many corresponding rows in Person. But, of those people, a maximum of one will have a status of "ACTIVE", the others will all have a status of "CANCELLED". e.g. SELECT * FROM House LEFT JOIN Person ON House.ID = Person.HouseID House.ID | Person.ID | Person.Status 1 | 1 | CANCELLED 1 | 2 | CANCELLED 1 | 3 | ACTIVE 2 | 1 | ACTIVE 3 | NULL | NULL 4 | 4 | CANCELLED I want to filter out the cancelled rows, and get something like this: House.ID | Person.ID | Person.Status 1 | 3 | ACTIVE 2 | 1 | ACTIVE 3 | NULL | NULL 4 | NULL | NULL I've achieved this with the following sub select: SELECT * FROM House LEFT JOIN ( SELECT * FROM Person WHERE Person.Status != "CANCELLED" ) Person ON House.ID = Person.HouseID ...which works, but breaks all the indexes. Is there a better solution that doesn't? I'm using MySQL and all relevant columns are indexed. EXPLAIN lists nothing in possible_keys. Thanks.

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  • How to write two-dimensional array to xml in Scala 2.8.0

    - by Shadowlands
    The following code (copied from a question from about a year ago) works fine under Scala 2.7.7, but does not behave correctly under Scala 2.8.0 (Beta 1, RC8). import scala.xml class Person(name : String, age : Int) { def toXml(): xml.Elem = <person><name>{ name }</name><age>{ age }</age></person> } def peopleToXml(people: Array[Person]): xml.Elem = { <people>{ for {person <- people} yield person.toXml }</people> } val data = Array(new Person("joe",40), new Person("mary", 35)) println(peopleToXml(data)) The output (according to 2.7.7) should be: <people><person><name>joe</name><age>40</age></person><person><name>mary</name><age>35</age></person></people> but instead comes out as: <people>\[Lscala.xml.Elem;@17821782</people> How do I get this to behave as it did in 2.7.x?

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  • inheritance problem OOP extend

    - by hsmit
    If a Father is a Parent and a Parent is a Person and a Person has a Father I create the following: class Person{ Father father; } class Parent extends Person{} class Father extends Parent{} Instances: Person p1 = new Person(); Person p2 = new Person(); p1.father = p2; //father is of the type Father This doesn't work... Now try casting:: Person p1 = new Person(); Person p2 = new Person(); p1.father = (Father)p2; This doesn't work either. What does work for this case?

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  • Saving data in custom class via AppDelegate

    - by redspike
    I can't seem to save data to a custom instance object in my AppDelegate. My custom class is very simple and is as follows: Person.h ... @interface Person : NSObject { int _age; } - (void) setAge: (int) age; - (int) age; @end Person.m #import "Person.h" @implementation Person - (void) setAge:(int) age { _age = age; } - (int) age { return _age; } @end I then create an instance of Person in the AppDelegate class: AppDelegate.h @class Person; @interface AccuTaxAppDelegate : NSObject <UIApplicationDelegate> { ... Person *person; } ... @property (nonatomic, retain) Person *person; @end AppDelegate.m ... #import "Person.h" @implementation AccuTaxAppDelegate ... @synthesize person; - (void)applicationDidFinishLaunching:(UIApplication *)application { // Override point for customization after app launch [window addSubview:[navigationController view]]; [window makeKeyAndVisible]; } - (void)applicationWillTerminate:(UIApplication *)application { // Save data if appropriate } #pragma mark - #pragma mark Memory management - (void)dealloc { [navigationController release]; [window release]; [person release]; [super dealloc]; } @end Finally, in my ViewController code I grab a handle on AppDelegate and then grab the person instance, but when I try to save the age it doesn't seem to work: MyViewController ... - (void)textFieldDidEndEditing:(UITextField *)textField { NSString *textAge = [textField text]; int age = [textAge intValue]; NSLog(@"Age from text field::%i", age); AppDelegate *appDelegate = (AppDelegate *)[UIApplication sharedApplication].delegate; Person *myPerson = (Person *)[appDelegate person]; NSLog(@"Age before setting: %i", [myPerson age]); [myPerson setAge:age]; NSLog(@"Age after setting: %i", [myPerson age]); [textAge release]; } ... The output of the above NSLogs are: [Session started at 2010-05-04 18:29:22 +0100.] 2010-05-04 18:29:28.260 AccuTax[16235:207] Age in text field:25 2010-05-04 18:29:28.262 AccuTax[16235:207] Age before setting: 0 2010-05-04 18:29:28.263 AccuTax[16235:207] Age after setting: 0 Any ideas why 'age' isn't being stored? I'm relatively new to Obj-C so please forgive me if I'm missing something very simple!

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  • How do you explain refactoring to a non-technical person?

    - by Benjol
    (This question was inspired by the most-voted answer here) How do you go about explaining refactoring (and technical debt) to a non-technical person (typically a PHB or customer)? ("What, it's going to cost me a month of your work with no visible difference?!") UPDATE Thanks for all the answers so far, I think this list will provide several useful analogies to which we can point the appropriate people (though editing out references to PHBs may be wise!)

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  • How do you explain refactoring to a non-technical person?

    - by Benjol
    (This question was inspired by the most-voted answer here) How do you go about explaining refactoring (and technical debt) to a non-technical person (typically a PHB or customer)? ("What, it's going to cost me a month of your work with no visible difference?!") UPDATE Thanks for all the answers so far, I think this list will provide several useful analogies to which we can point the appropriate people (though editing out references to PHBs may be wise!)

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  • getting record from CoreData ?

    - by Meko
    Hi. I am trying to add value to CoreData from .plist and get from coreData and show them on UITable. I made take from .plist and send them to CoreData .But I cant take them from CoreData entity and set to some NSMutable array.. Here my codes Edit : SOLVED NSString *path = [[NSBundle mainBundle] pathForResource:@"FakeData" ofType:@"plist"]; NSArray *myArray=[[NSArray alloc] initWithContentsOfFile:path]; FlickrFetcher *flickrfetcher =[FlickrFetcher sharedInstance]; managedObjectContext =[flickrfetcher managedObjectContext]; for(NSDictionary *dict in myArray){ Photo *newPhoto = (Photo *)[NSEntityDescription insertNewObjectForEntityForName:@"Photo" inManagedObjectContext:managedObjectContext]; // set the attributes for the photo NSLog(@"Creating Photo: %@", [dict objectForKey:@"name"]); [newPhoto setName:[dict objectForKey:@"name"]]; [newPhoto setPath:[dict objectForKey:@"path"]]; NSLog(@"Person is: %@", [dict objectForKey:@"user"]); NSPredicate *predicate = [NSPredicate predicateWithFormat:@"name ==%@",[dict objectForKey:@"user"]]; NSMutableArray *peopleArray = (NSMutableArray *)[flickrfetcher fetchManagedObjectsForEntity:@"Person" withPredicate:predicate]; NSEnumerator *enumerator = [peopleArray objectEnumerator]; Person *person; BOOL exists = FALSE; while (person = [enumerator nextObject]) { NSLog(@" Person is: %@ ", person.name); if([person.name isEqualToString:[dict objectForKey:@"user"]]) { exists = TRUE; NSLog(@"-- Person Exists : %@--", person.name); [newPhoto setPerson:person]; } } // if person does not already exist then add the person if (!exists) { Person *newPerson = (Person *)[NSEntityDescription insertNewObjectForEntityForName:@"Person" inManagedObjectContext:managedObjectContext]; // create the person [newPerson setName:[dict objectForKey:@"user"]]; NSLog(@"-- Person Created : %@--", newPerson.name); // associate the person with the photo [newPhoto setPerson:newPerson]; } //THis IS myArray that I want to save value in it and them show them in UITABLE personList=[[NSMutableArray alloc]init]; NSLog(@"lllll %@",[personList objectAtIndex:0]); // save the data NSError *error; if (![managedObjectContext save:&error]) { // Handle the error. NSLog(@"Unresolved error %@, %@", error, [error userInfo]); exit(-1); } } //To access core data objects you can try the following: // setup our fetchedResultsController fetchedResultsController = [flickrfetcher fetchedResultsControllerForEntity:@"Person" withPredicate:nil]; // execute the fetch NSError *error; BOOL success = [fetchedResultsController performFetch:&error]; if (!success) { // Handle the error. NSLog(@"Unresolved error %@, %@", error, [error userInfo]); exit(-1); } // save our data //HERE PROBLEM THAT I DONW KNOW WHERE IT IS SAVING //[personList addObject:(NSMutableArray *)[fetchedResultsController fetchedObjects]]; [self setPersonList:(NSMutableArray *)[fetchedResultsController fetchedObjects]]; } Here my tableview function - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { NSLog(@"ss %d",[personList count]); static NSString *CellIdentifier = @"Cell"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier]; if (cell == nil) { cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier] autorelease]; } cell.textLabel.text=[personList objectAtIndex:indexPath.row]; // Set up the cell... return cell; }

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  • Before and After the Programmer Life [closed]

    - by Gio Borje
    How were people before and after becoming programmers through a black box? In a black box, the implementation is irrelevant; therefore, we focus on the input and output: High School Nerd -> becomeProgrammer() -> Manager (Person Before) -> (Person as Programmer) -> (New Person) (Person Before) -> (Person as Programmer) How are the typical lives of people before they became programmers? Why do people pursue life as a programmer? (Person as Programmer) -> (New Person) How has becoming a programmer changed people afterwards? Why quit being a programmer? Anecdotes would be nice. If many programmers have similar backgrounds and fates, do you think that there is some sort of stereotypical person that are destined to become programmers?

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  • Why does DataContractJsonSerializer not include generic like JavaScriptSerializer?

    - by Patrick Magee
    So the JavaScriptSerializer was deprecated in favor of the DataContractJsonSerializer. var client = new WebClient(); var json = await client.DownloadStringTaskAsync(url); // http://example.com/api/people/1 // Deprecated, but clean looking and generally fits in nicely with // other code in my app domain that makes use of generics var serializer = new JavaScriptSerializer(); Person p = serializer.Deserialize<Person>(json); // Now have to make use of ugly typeof to get the Type when I // already know the Type at compile type. Why no Generic type T? var serializer = new DataContractJsonSerializer(typeof(Person)); Person p = serializer.ReadObject(json) as Person; The JavaScriptSerializer is nice and allows you to deserialize using a type of T generic in the function name. Understandably, it's been deprecated for good reason, with the DataContractJsonSerializer, you can decorate your Type to be deserialized with various things so it isn't so brittle like the JavaScriptSerializer, for example [DataMember(name = "personName")] public string Name { get; set; } Is there a particular reason why they decided to only allow users to pass in the Type? Type type = typeof(Person); var serializer = new DataContractJsonSerializer(type); Person p = serializer.ReadObject(json) as Person; Why not this? var serializer = new DataContractJsonSerializer(); Person p = serializer.ReadObject<Person>(json); They can still use reflection with the DataContract decorated attributes based on the T that I've specified on the .ReadObject<T>(json)

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