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  • Ubuntu doesn't start and I can't login

    - by Meph00
    My ubuntu 13.04 doesn't boot anymore. Eternal black screen. If I press ALT+CTRL+F1 I see that it's stucked on "Checking battery state [OK]." I'd like to try to go with sudo apt-get install gdm but I can't login on terminal tty2, tty3 etc. They correctly ask for my nickname, then they make me wait a lot, ask for password and make me wait again. After a lot of time (... a lot) the best I could achieve was visualizing "Documentantion https://help.ubuntu.com". I can never reach the point where I can give commands. Plus, during the long pauses, every 2 minutes it gives a messagge like this: INFO: task XXX blocked for more than 120 seconds. Any suggestion? Sorry for my bad english and thanks everyone for the attention.

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  • I can't even login, black screen! [SOLVED]

    - by Elisa Velasco Lorenzo
    I wanted to fix something, and I followed the advice given by someone on the #ubuntu IRC chat. I don't think I did it properly, because now, I cannot even login and I have a black screen. Ii must be a Gdm / Lightdm issue... I am writing this from another computer. Is there a way I can solve this without formatting and losing all my files? All I have is the GRUB menu. I don't even have the recovery mode on the GRUB menu...

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  • No user/password boxes on login screen after updates today (June 30, 2012)

    - by Tony
    Just installed today's batch of updates, including new kernel 3.2.0-26 and rebooted. Now the screen just has a logo in the middle and "Ubuntu 12.04 LTS" in bottom left corner, but no box to choose which user to log in as, or to enter a password. CTRL-ALT-F1 gets me to a "login:" prompt, and I can log in - but I have no idea what to look at to find out what is wrong, or to fix this. Tried older kernels and recovery mode for current kernel - no joy, still no way to log into the graphics console.

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  • Hangs on Splash Screen after login (auto-login), how can I fix this?

    - by Davious
    Computer: Toshiba Terca A4 OS: Ubuntu Desktop 10.10 After installing 10.10, the splash screen hangs and the mouse pointer appears. Anyone know what I can do to fix this? ~/.xsession-errors has (nautilus:3190): GConf-CRITICAL **: gconf_value_free: assertion `value != NULL' failed btw, Safe-mode works: I do a Ctrl-Alt-F1 into a command prompt session and run ps aux | grep slave then sudo kill [id of gdm-simple-slave] That killed the session and allowed me to login in safe-mode. Safe-mode works. Then I open a terminal and run ps aux | grep nm- sudo kill -9 [id of nm-applet] nm-applet --sm-disable & to get my internet connection up.

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  • Gnome 3.10 doesn't show login, Ubuntu 13.10

    - by TheWebs
    I use gnome as default desktop. And I recently upgrade Ubuntu to 13.10 then upgraded gnome to 3.10. Upon restarting, it brings me to the gnome log in screen (GDM) and all I see is the top banner part so like your date, music volume, option to restart, suspend or shutdown. Hitting control+alt+delete tells me gnome display manager will log out - it does but still nothing. I am on the log in screen, but there is no user to select, like there normally is or was. I can boot into safe mode and drop down to shell but I am not sure what commands I would enter to get the login screen back. I am using the gnome PPA's and the "unstable" PPA, so I expected issues, but not this - ideas?

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  • BAM Data Control in multiple ADF Faces Components

    - by [email protected]
    As we know Oracle BAM data control instance sharing is not supported.When two or more ADF Faces components must display the same data, and are bound to the same Oracle BAM data control definition, we have to make sure that we wrap each ADF Faces component in an ADF task flow, and set the Data Control Scope to isolated. This blog will show a small sample to demonstrate this. In this sample we will create a Pie and Bar using same BAM DC, such that both components use same Data control but have isolated scope.This sample can be downloaded  fromSample1.zip Set-up: Create a BAM data control using employees DO (sample) Steps: Right click on View Controller project and select "New->ADF Task Flow" Check "Create Bounded Task Flow" and give some meaningful name (ex:EmpPieTF.xml ) to the TaskFlow(TF) and click on "OK"CreateTF.bmpFrom the "Components Palette", drag and drop "View" into the task flow diagram. Give a meaningful name to the view. Double Click and Click "Ok" for  "Create New JSF Page Fragment" From "Data Controls" drag and drop "Employees->Query"  into this jsff page as "Graph->Pie" (Pie: Sales_Number and Slices: Salesperson) Repeat step 1 through 4 for another Task Flow (ex: EmpBarTF). From "Data Controls" drag and drop "Employees->Query"  into this jsff page as "Graph->Bar" (Bars :Sales_Number and X-axis : Salesperson). Open the Taskflow created in step 2. In the Structure Pane, right click on "Task Flow Definition -EmpPieTF" Click "Insert inside Task Flow Definition - EmpPieTF -> ADF Task Flow -> Data Control Scope". Click "OK"TFDCScope.bmpFor the "Data Control Scope", In the Property Inspector ->General section, change data control scope from Shared to Isolated. Repeat step 8 through 11 for the 2nd Task flow created. Now create a new jspx page example: Main.jspxDrag and drop both the Task flows (ex: "EmpPieTF" and "EmpBarTF") as regions. Surround with panel components as needed.Run the page Main.jspxMainPage.bmpNow when the page runs although both components are created using same Data control the bindings are not shared and each component will have a separate instance of the data control.

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  • How to implement a no-login authentication system

    - by mrwooster
    I am looking to build a very loose authentication system that can track a user and link submitted data/comments to a specific user. The submissions are essentially anonymous, but a user may want to edit his submission/comment at a later date. I want the experience to be as smooth as possible so do not want to ask users to sign up for an account and then login each time. There is no point as their submissions are not in their name and to another user browsing the site, there is no way of linking a submission to a specific user (think anonymous comments on a blog post or pastie). However, the user should have the ability to edit (at least in the short term) the content they have posted. The way I imagine doing this would be to place a unique identifier in a cookie on the users machine. This would enable me to link a submission to a user, and while that cookie remained on the users machine, I would allow them to edit their content. Of course, if the cookie is lost, or the user accesses the site from a different browser, then they would not be able to edit their content, but this is not really an issue, they can always resubmit a new piece of content. Is there a better way of doing this? How can I implement this so that the user can edit their data for the longest possible amount of time.

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  • Laptop using 14.04 won't get past login GUI

    - by Dave M G
    My laptop was working perfectly yesterday, and now today I can't log in. At first, I was only getting a black screen. However, after following instructions in some questions here on AskUbuntu, I first reinstalled lightdm, and then I had to change the ownership of the file ~/.Xauthority to be my user name. Now, I get the log in GUI screen. However, once I enter my username, it flickers and then comes back to the login GUI. It does not matter if I use Gnome, Unity, or Gnome-Flashback. I don't know why lightdm needed to be reconfigured, or how ~/.Xauthority got changed, but in any case, what is still standing in my way, preventing me from logging in? Update: I have tried deleting the .Xauthority file, and the .profile files in my home directory. It has not changed anything. Logging in as guest also fails to work. The following commands did not work: mv ~/.config ~/.config.BAK mv ~/.cache ~/.cache.BAK Inside .xsession-errors in my home directory, it says: Gdk-CRITICAL: gdk_x11_display_get_xdisplay: assertion 'GDK_IS_DISPLAY (display)' failed

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  • Why does the login screen fail to appear?

    - by a different ben
    My system: Dell Precision T3500 nVidia Quadro NVS 295 Ubuntu 12.04 x86_64 (3.2.0-32) Essential problem: On boot my system won't get past the splash screen. I can switch to another virtual terminal and log in, I can also ssh from another system -- so it appears that the problem might be with the display manager. How can I diagnose and fix this problem? More info: From a VT I can issue sudo lightdm restart, and this will bring up the login screen and and I can continue from there. So I do have access to my system. Update-manager recently updated a number of packages, including a bunch of x11 and xorg packages, some nVidia drivers, rpcbind, etc etc. My boot log (if that is any guidance) says the following: fsck from util-linux 2.20.1 fsck from util-linux 2.20.1 fsck from util-linux 2.20.1 fsck from util-linux 2.20.1 rpcbind: Cannot open '/run/rpcbind/rpcbind.xdr' file for reading, errno 2 (No such file or directory) rpcbind: Cannot open '/run/rpcbind/portmap.xdr' file for reading, errno 2 (No such file or directory) /dev/sda1: clean, 597650/1525920 files, 3963433/6103296 blocks /dev/sda7: clean, 11/6406144 files, 450097/25608703 blocks /dev/sda5: clean, 158323/1525920 files, 1886918/6103296 blocks /dev/sda8: clean, 250089/107929600 files, 111088810/431689728 blocks Skipping profile in /etc/apparmor.d/disable: usr.bin.firefox Skipping profile in /etc/apparmor.d/disable: usr.sbin.rsyslogd * Starting AppArmor profiles [80G [74G[ OK ] Loading the saved-state of the serial devices... /dev/ttyS0 at 0x03f8 (irq = 4) is a 16550A * Starting ClamAV virus database updater freshclam [80G [74G[ OK ] * Starting Name Service Cache Daemon nscd [80G [74G[ OK ] * Starting modem connection manager[74G[ OK ] * Starting K Display Manager[74G[ OK ] * Starting mDNS/DNS-SD daemon[74G[ OK ] * Stopping GNOME Display Manager[74G[ OK ] * Stopping K Display Manager[74G[ OK ] * Starting bluetooth daemon[74G[ OK ] * Starting network connection manager[74G[ OK ] * Starting Postfix Mail Transport Agent postfix [80G [74G[ OK ] speech-dispatcher disabled; edit /etc/default/speech-dispatcher * Starting VirtualBox kernel modules [80G [74G[ OK ] * Starting the Winbind daemon winbind [80G [74G[ OK ] saned disabled; edit /etc/default/saned * Starting anac(h)ronistic cron[74G[ OK ] * Stopping anac(h)ronistic cron[74G[ OK ] * Checking battery state... [80G [74G[ OK ] nxsensor is disabled in '/usr/NX/etc/node.cfg' Trying to start NX server: NX 122 Service started. NX 999 Bye. Trying to start NX statistics: NX 723 Cannot start NX statistics: NX 709 NX statistics are disabled for this server. NX 999 Bye. * Stopping System V runlevel compatibility[74G[ OK ] * Starting Mount network filesystems[74G[ OK ] * Stopping Mount network filesystems[74G[ OK ] * Stopping regular background program processing daemon[74G[ OK ] * Starting regular background program processing daemon[74G[ OK ] * Starting anac(h)ronistic cron[74G[ OK ] * Stopping anac(h)ronistic cron[74G[ OK ]

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  • Login and Redirect

    - by xRobot
    This is my login views: def login(request): redirect_to = request.REQUEST.get("next") if request.method == 'POST': formL = LoginForm(data=request.POST) if formL.is_valid(): if not redirect_to or '//' in redirect_to or ' ' in redirect_to: redirect_to = "/blogs/" from django.contrib.auth import login login(request, formL.get_user()) if request.session.test_cookie_worked(): request.session.delete_test_cookie() return HttpResponseRedirect(redirect_to) else: formL = LoginForm(request) request.session.set_test_cookie() return render_to_response('blogs.html', { 'formL': formL, }, context_instance=RequestContext(request)) login = never_cache(login) When I go, for example, to example.com/myblog/ then I have been redirect to example.com/accounts/login/?next=/myblog/ but when I insert user and psw for login then I have been redirect to /blogs/ and not /myblog/ Why ?

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  • Creating a second login page that automatically logs in the user

    - by nsilva
    I have a login page as follows: <form action="?" method="post" id="frm-useracc-login" name="frm-useracc-login" > <div id="login-username-wrap" > <div class="login-input-item left"> <div class="div-search-label left"> <div id="div-leftheader-wrap"> <p class="a-topheader-infotext left"><strong>Username: </strong></p> </div> </div> <div class="login-input-content left div-subrow-style ui-corner-all"> <input type="text" tabindex="1" name="txt-username" id="txt-username" class="input-txt-med required addr-search-input txt-username left"> </div> </div> </div> <div id="login-password-wrap" > <div class="login-input-item left"> <div class="div-search-label left"> <div id="div-leftheader-wrap"> <p class="a-topheader-infotext left"><strong>Password: </strong></p> </div> </div> <div class="login-input-content left div-subrow-style ui-corner-all"> <input type="password" tabindex="1" name="txt-password" id="txt-password" class="input-txt-med required addr-search-input txt-password left"> </div> </div> </div> <div id="login-btn-bottom" class="centre-div"> <div id="login-btn-right"> <button name="btn-login" id="btn-login" class="btn-med ui-button ui-state-default ui-button-text-only ui-corner-all btn-hover-anim btn-row-wrapper left">Login</button> <button name="btn-cancel" id="btn-cancel" class="btn-med ui-button ui-state-default ui-button-text-only ui-corner-all btn-hover-anim btn-row-wrapper left">Cancel</button><br /><br /> </div> </div> </form> And here my session.controller.php file: Click Here Basically, what I want to do is create a second login page that automatically passes the value to the session controller and logs in. For example, if I go to login-guest.php, I would put the default values for username and password and then have a jquery click event that automatically logs them in using $("#btn-login").trigger('click'); The problem is that the session controller automatically goes back to login.php if the session has timed out and I'm not sure how I could go about achieving this. Any help would be much appreciated!

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  • A free standing ASP.NET Pager Web Control

    - by Rick Strahl
    Paging in ASP.NET has been relatively easy with stock controls supporting basic paging functionality. However, recently I built an MVC application and one of the things I ran into was that I HAD TO build manual paging support into a few of my pages. Dealing with list controls and rendering markup is easy enough, but doing paging is a little more involved. I ended up with a small but flexible component that can be dropped anywhere. As it turns out the task of creating a semi-generic Pager control for MVC was fairly easily. Now I’m back to working in Web Forms and thought to myself that the way I created the pager in MVC actually would also work in ASP.NET – in fact quite a bit easier since the whole thing can be conveniently wrapped up into an easily reusable control. A standalone pager would provider easier reuse in various pages and a more consistent pager display regardless of what kind of 'control’ the pager is associated with. Why a Pager Control? At first blush it might sound silly to create a new pager control – after all Web Forms has pretty decent paging support, doesn’t it? Well, sort of. Yes the GridView control has automatic paging built in and the ListView control has the related DataPager control. The built in ASP.NET paging has several issues though: Postback and JavaScript requirements If you look at paging links in ASP.NET they are always postback links with javascript:__doPostback() calls that go back to the server. While that works fine and actually has some benefit like the fact that paging saves changes to the page and post them back, it’s not very SEO friendly. Basically if you use javascript based navigation nosearch engine will follow the paging links which effectively cuts off list content on the first page. The DataPager control does support GET based links via the QueryStringParameter property, but the control is effectively tied to the ListView control (which is the only control that implements IPageableItemContainer). DataSource Controls required for Efficient Data Paging Retrieval The only way you can get paging to work efficiently where only the few records you display on the page are queried for and retrieved from the database you have to use a DataSource control - only the Linq and Entity DataSource controls  support this natively. While you can retrieve this data yourself manually, there’s no way to just assign the page number and render the pager based on this custom subset. Other than that default paging requires a full resultset for ASP.NET to filter the data and display only a subset which can be very resource intensive and wasteful if you’re dealing with largish resultsets (although I’m a firm believer in returning actually usable sets :-}). If you use your own business layer that doesn’t fit an ObjectDataSource you’re SOL. That’s a real shame too because with LINQ based querying it’s real easy to retrieve a subset of data that is just the data you want to display but the native Pager functionality doesn’t support just setting properties to display just the subset AFAIK. DataPager is not Free Standing The DataPager control is the closest thing to a decent Pager implementation that ASP.NET has, but alas it’s not a free standing component – it works off a related control and the only one that it effectively supports from the stock ASP.NET controls is the ListView control. This means you can’t use the same data pager formatting for a grid and a list view or vice versa and you’re always tied to the control. Paging Events In order to handle paging you have to deal with paging events. The events fire at specific time instances in the page pipeline and because of this you often have to handle data binding in a way to work around the paging events or else end up double binding your data sources based on paging. Yuk. Styling The GridView pager is a royal pain to beat into submission for styled rendering. The DataPager control has many more options and template layout and it renders somewhat cleaner, but it too is not exactly easy to get a decent display for. Not a Generic Solution The problem with the ASP.NET controls too is that it’s not generic. GridView, DataGrid use their own internal paging, ListView can use a DataPager and if you want to manually create data layout – well you’re on your own. IOW, depending on what you use you likely have very different looking Paging experiences. So, I figured I’ve struggled with this once too many and finally sat down and built a Pager control. The Pager Control My goal was to create a totally free standing control that has no dependencies on other controls and certainly no requirements for using DataSource controls. The idea is that you should be able to use this pager control without any sort of data requirements at all – you should just be able to set properties and be able to display a pager. The Pager control I ended up with has the following features: Completely free standing Pager control – no control or data dependencies Complete manual control – Pager can render without any data dependency Easy to use: Only need to set PageSize, ActivePage and TotalItems Supports optional filtering of IQueryable for efficient queries and Pager rendering Supports optional full set filtering of IEnumerable<T> and DataTable Page links are plain HTTP GET href Links Control automatically picks up Page links on the URL and assigns them (automatic page detection no page index changing events to hookup) Full CSS Styling support On the downside there’s no templating support for the control so the layout of the pager is relatively fixed. All elements however are stylable and there are options to control the text, and layout options such as whether to display first and last pages and the previous/next buttons and so on. To give you an idea what the pager looks like, here are two differently styled examples (all via CSS):   The markup for these two pagers looks like this: <ww:Pager runat="server" id="ItemPager" PageSize="5" PageLinkCssClass="gridpagerbutton" SelectedPageCssClass="gridpagerbutton-selected" PagesTextCssClass="gridpagertext" CssClass="gridpager" RenderContainerDiv="true" ContainerDivCssClass="gridpagercontainer" MaxPagesToDisplay="6" PagesText="Item Pages:" NextText="next" PreviousText="previous" /> <ww:Pager runat="server" id="ItemPager2" PageSize="5" RenderContainerDiv="true" MaxPagesToDisplay="6" /> The latter example uses default style settings so it there’s not much to set. The first example on the other hand explicitly assigns custom styles and overrides a few of the formatting options. Styling The styling is based on a number of CSS classes of which the the main pager, pagerbutton and pagerbutton-selected classes are the important ones. Other styles like pagerbutton-next/prev/first/last are based on the pagerbutton style. The default styling shown for the red outlined pager looks like this: .pagercontainer { margin: 20px 0; background: whitesmoke; padding: 5px; } .pager { float: right; font-size: 10pt; text-align: left; } .pagerbutton,.pagerbutton-selected,.pagertext { display: block; float: left; text-align: center; border: solid 2px maroon; min-width: 18px; margin-left: 3px; text-decoration: none; padding: 4px; } .pagerbutton-selected { font-size: 130%; font-weight: bold; color: maroon; border-width: 0px; background: khaki; } .pagerbutton-first { margin-right: 12px; } .pagerbutton-last,.pagerbutton-prev { margin-left: 12px; } .pagertext { border: none; margin-left: 30px; font-weight: bold; } .pagerbutton a { text-decoration: none; } .pagerbutton:hover { background-color: maroon; color: cornsilk; } .pagerbutton-prev { background-image: url(images/prev.png); background-position: 2px center; background-repeat: no-repeat; width: 35px; padding-left: 20px; } .pagerbutton-next { background-image: url(images/next.png); background-position: 40px center; background-repeat: no-repeat; width: 35px; padding-right: 20px; margin-right: 0px; } Yup that’s a lot of styling settings although not all of them are required. The key ones are pagerbutton, pager and pager selection. The others (which are implicitly created by the control based on the pagerbutton style) are for custom markup of the ‘special’ buttons. In my apps I tend to have two kinds of pages: Those that are associated with typical ‘grid’ displays that display purely tabular data and those that have a more looser list like layout. The two pagers shown above represent these two views and the pager and gridpager styles in my standard style sheet reflect these two styles. Configuring the Pager with Code Finally lets look at what it takes to hook up the pager. As mentioned in the highlights the Pager control is completely independent of other controls so if you just want to display a pager on its own it’s as simple as dropping the control and assigning the PageSize, ActivePage and either TotalPages or TotalItems. So for this markup: <ww:Pager runat="server" id="ItemPagerManual" PageSize="5" MaxPagesToDisplay="6" /> I can use code as simple as: ItemPagerManual.PageSize = 3; ItemPagerManual.ActivePage = 4;ItemPagerManual.TotalItems = 20; Note that ActivePage is not required - it will automatically use any Page=x query string value and assign it, although you can override it as I did above. TotalItems can be any value that you retrieve from a result set or manually assign as I did above. A more realistic scenario based on a LINQ to SQL IQueryable result is even easier. In this example, I have a UserControl that contains a ListView control that renders IQueryable data. I use a User Control here because there are different views the user can choose from with each view being a different user control. This incidentally also highlights one of the nice features of the pager: Because the pager is independent of the control I can put the pager on the host page instead of into each of the user controls. IOW, there’s only one Pager control, but there are potentially many user controls/listviews that hold the actual display data. The following code demonstrates how to use the Pager with an IQueryable that loads only the records it displays: protected voidPage_Load(objectsender, EventArgs e) {     Category = Request.Params["Category"] ?? string.Empty;     IQueryable<wws_Item> ItemList = ItemRepository.GetItemsByCategory(Category);     // Update the page and filter the list down     ItemList = ItemPager.FilterIQueryable<wws_Item>(ItemList); // Render user control with a list view Control ulItemList = LoadControl("~/usercontrols/" + App.Configuration.ItemListType + ".ascx"); ((IInventoryItemListControl)ulItemList).InventoryItemList = ItemList; phItemList.Controls.Add(ulItemList); // placeholder } The code uses a business object to retrieve Items by category as an IQueryable which means that the result is only an expression tree that hasn’t execute SQL yet and can be further filtered. I then pass this IQueryable to the FilterIQueryable() helper method of the control which does two main things: Filters the IQueryable to retrieve only the data displayed on the active page Sets the Totaltems property and calculates TotalPages on the Pager and that’s it! When the Pager renders it uses those values, plus the PageSize and ActivePage properties to render the Pager. In addition to IQueryable there are also filter methods for IEnumerable<T> and DataTable, but these versions just filter the data by removing rows/items from the entire already retrieved data. Output Generated and Paging Links The output generated creates pager links as plain href links. Here’s what the output looks like: <div id="ItemPager" class="pagercontainer"> <div class="pager"> <span class="pagertext">Pages: </span><a href="http://localhost/WestWindWebStore/itemlist.aspx?Page=1" class="pagerbutton" />1</a> <a href="http://localhost/WestWindWebStore/itemlist.aspx?Page=2" class="pagerbutton" />2</a> <a href="http://localhost/WestWindWebStore/itemlist.aspx?Page=3" class="pagerbutton" />3</a> <span class="pagerbutton-selected">4</span> <a href="http://localhost/WestWindWebStore/itemlist.aspx?Page=5" class="pagerbutton" />5</a> <a href="http://localhost/WestWindWebStore/itemlist.aspx?Page=6" class="pagerbutton" />6</a> <a href="http://localhost/WestWindWebStore/itemlist.aspx?Page=20" class="pagerbutton pagerbutton-last" />20</a>&nbsp;<a href="http://localhost/WestWindWebStore/itemlist.aspx?Page=3" class="pagerbutton pagerbutton-prev" />Prev</a>&nbsp;<a href="http://localhost/WestWindWebStore/itemlist.aspx?Page=5" class="pagerbutton pagerbutton-next" />Next</a></div> <br clear="all" /> </div> </div> The links point back to the current page and simply append a Page= page link into the page. When the page gets reloaded with the new page number the pager automatically detects the page number and automatically assigns the ActivePage property which results in the appropriate page to be displayed. The code shown in the previous section is all that’s needed to handle paging. Note that HTTP GET based paging is different than the Postback paging ASP.NET uses by default. Postback paging preserves modified page content when clicking on pager buttons, but this control will simply load a new page – no page preservation at this time. The advantage of not using Postback paging is that the URLs generated are plain HTML links that a search engine can follow where __doPostback() links are not. Pager with a Grid The pager also works in combination with grid controls so it’s easy to bypass the grid control’s paging features if desired. In the following example I use a gridView control and binds it to a DataTable result which is also filterable by the Pager control. The very basic plain vanilla ASP.NET grid markup looks like this: <div style="width: 600px; margin: 0 auto;padding: 20px; "> <asp:DataGrid runat="server" AutoGenerateColumns="True" ID="gdItems" CssClass="blackborder" style="width: 600px;"> <AlternatingItemStyle CssClass="gridalternate" /> <HeaderStyle CssClass="gridheader" /> </asp:DataGrid> <ww:Pager runat="server" ID="Pager" CssClass="gridpager" ContainerDivCssClass="gridpagercontainer" PageLinkCssClass="gridpagerbutton" SelectedPageCssClass="gridpagerbutton-selected" PageSize="8" RenderContainerDiv="true" MaxPagesToDisplay="6" /> </div> and looks like this when rendered: using custom set of CSS styles. The code behind for this code is also very simple: protected void Page_Load(object sender, EventArgs e) { string category = Request.Params["category"] ?? ""; busItem itemRep = WebStoreFactory.GetItem(); var items = itemRep.GetItemsByCategory(category) .Select(itm => new {Sku = itm.Sku, Description = itm.Description}); // run query into a DataTable for demonstration DataTable dt = itemRep.Converter.ToDataTable(items,"TItems"); // Remove all items not on the current page dt = Pager.FilterDataTable(dt,0); // bind and display gdItems.DataSource = dt; gdItems.DataBind(); } A little contrived I suppose since the list could already be bound from the list of elements, but this is to demonstrate that you can also bind against a DataTable if your business layer returns those. Unfortunately there’s no way to filter a DataReader as it’s a one way forward only reader and the reader is required by the DataSource to perform the bindings.  However, you can still use a DataReader as long as your business logic filters the data prior to rendering and provides a total item count (most likely as a second query). Control Creation The control itself is a pretty brute force ASP.NET control. Nothing clever about this other than some basic rendering logic and some simple calculations and update routines to determine which buttons need to be shown. You can take a look at the full code from the West Wind Web Toolkit’s Repository (note there are a few dependencies). To give you an idea how the control works here is the Render() method: /// <summary> /// overridden to handle custom pager rendering for runtime and design time /// </summary> /// <param name="writer"></param> protected override void Render(HtmlTextWriter writer) { base.Render(writer); if (TotalPages == 0 && TotalItems > 0) TotalPages = CalculateTotalPagesFromTotalItems(); if (DesignMode) TotalPages = 10; // don't render pager if there's only one page if (TotalPages < 2) return; if (RenderContainerDiv) { if (!string.IsNullOrEmpty(ContainerDivCssClass)) writer.AddAttribute("class", ContainerDivCssClass); writer.RenderBeginTag("div"); } // main pager wrapper writer.WriteBeginTag("div"); writer.AddAttribute("id", this.ClientID); if (!string.IsNullOrEmpty(CssClass)) writer.WriteAttribute("class", this.CssClass); writer.Write(HtmlTextWriter.TagRightChar + "\r\n"); // Pages Text writer.WriteBeginTag("span"); if (!string.IsNullOrEmpty(PagesTextCssClass)) writer.WriteAttribute("class", PagesTextCssClass); writer.Write(HtmlTextWriter.TagRightChar); writer.Write(this.PagesText); writer.WriteEndTag("span"); // if the base url is empty use the current URL FixupBaseUrl(); // set _startPage and _endPage ConfigurePagesToRender(); // write out first page link if (ShowFirstAndLastPageLinks && _startPage != 1) { writer.WriteBeginTag("a"); string pageUrl = StringUtils.SetUrlEncodedKey(BaseUrl, QueryStringPageField, (1).ToString()); writer.WriteAttribute("href", pageUrl); if (!string.IsNullOrEmpty(PageLinkCssClass)) writer.WriteAttribute("class", PageLinkCssClass + " " + PageLinkCssClass + "-first"); writer.Write(HtmlTextWriter.SelfClosingTagEnd); writer.Write("1"); writer.WriteEndTag("a"); writer.Write("&nbsp;"); } // write out all the page links for (int i = _startPage; i < _endPage + 1; i++) { if (i == ActivePage) { writer.WriteBeginTag("span"); if (!string.IsNullOrEmpty(SelectedPageCssClass)) writer.WriteAttribute("class", SelectedPageCssClass); writer.Write(HtmlTextWriter.TagRightChar); writer.Write(i.ToString()); writer.WriteEndTag("span"); } else { writer.WriteBeginTag("a"); string pageUrl = StringUtils.SetUrlEncodedKey(BaseUrl, QueryStringPageField, i.ToString()).TrimEnd('&'); writer.WriteAttribute("href", pageUrl); if (!string.IsNullOrEmpty(PageLinkCssClass)) writer.WriteAttribute("class", PageLinkCssClass); writer.Write(HtmlTextWriter.SelfClosingTagEnd); writer.Write(i.ToString()); writer.WriteEndTag("a"); } writer.Write("\r\n"); } // write out last page link if (ShowFirstAndLastPageLinks && _endPage < TotalPages) { writer.WriteBeginTag("a"); string pageUrl = StringUtils.SetUrlEncodedKey(BaseUrl, QueryStringPageField, TotalPages.ToString()); writer.WriteAttribute("href", pageUrl); if (!string.IsNullOrEmpty(PageLinkCssClass)) writer.WriteAttribute("class", PageLinkCssClass + " " + PageLinkCssClass + "-last"); writer.Write(HtmlTextWriter.SelfClosingTagEnd); writer.Write(TotalPages.ToString()); writer.WriteEndTag("a"); } // Previous link if (ShowPreviousNextLinks && !string.IsNullOrEmpty(PreviousText) && ActivePage > 1) { writer.Write("&nbsp;"); writer.WriteBeginTag("a"); string pageUrl = StringUtils.SetUrlEncodedKey(BaseUrl, QueryStringPageField, (ActivePage - 1).ToString()); writer.WriteAttribute("href", pageUrl); if (!string.IsNullOrEmpty(PageLinkCssClass)) writer.WriteAttribute("class", PageLinkCssClass + " " + PageLinkCssClass + "-prev"); writer.Write(HtmlTextWriter.SelfClosingTagEnd); writer.Write(PreviousText); writer.WriteEndTag("a"); } // Next link if (ShowPreviousNextLinks && !string.IsNullOrEmpty(NextText) && ActivePage < TotalPages) { writer.Write("&nbsp;"); writer.WriteBeginTag("a"); string pageUrl = StringUtils.SetUrlEncodedKey(BaseUrl, QueryStringPageField, (ActivePage + 1).ToString()); writer.WriteAttribute("href", pageUrl); if (!string.IsNullOrEmpty(PageLinkCssClass)) writer.WriteAttribute("class", PageLinkCssClass + " " + PageLinkCssClass + "-next"); writer.Write(HtmlTextWriter.SelfClosingTagEnd); writer.Write(NextText); writer.WriteEndTag("a"); } writer.WriteEndTag("div"); if (RenderContainerDiv) { if (RenderContainerDivBreak) writer.Write("<br clear=\"all\" />\r\n"); writer.WriteEndTag("div"); } } As I said pretty much brute force rendering based on the control’s property settings of which there are quite a few: You can also see the pager in the designer above. unfortunately the VS designer (both 2010 and 2008) fails to render the float: left CSS styles properly and starts wrapping after margins are applied in the special buttons. Not a big deal since VS does at least respect the spacing (the floated elements overlay). Then again I’m not using the designer anyway :-}. Filtering Data What makes the Pager easy to use is the filter methods built into the control. While this functionality is clearly not the most politically correct design choice as it violates separation of concerns, it’s very useful for typical pager operation. While I actually have filter methods that do something similar in my business layer, having it exposed on the control makes the control a lot more useful for typical databinding scenarios. Of course these methods are optional – if you have a business layer that can provide filtered page queries for you can use that instead and assign the TotalItems property manually. There are three filter method types available for IQueryable, IEnumerable and for DataTable which tend to be the most common use cases in my apps old and new. The IQueryable version is pretty simple as it can simply rely on on .Skip() and .Take() with LINQ: /// <summary> /// <summary> /// Queries the database for the ActivePage applied manually /// or from the Request["page"] variable. This routine /// figures out and sets TotalPages, ActivePage and /// returns a filtered subset IQueryable that contains /// only the items from the ActivePage. /// </summary> /// <param name="query"></param> /// <param name="activePage"> /// The page you want to display. Sets the ActivePage property when passed. /// Pass 0 or smaller to use ActivePage setting. /// </param> /// <returns></returns> public IQueryable<T> FilterIQueryable<T>(IQueryable<T> query, int activePage) where T : class, new() { ActivePage = activePage < 1 ? ActivePage : activePage; if (ActivePage < 1) ActivePage = 1; TotalItems = query.Count(); if (TotalItems <= PageSize) { ActivePage = 1; TotalPages = 1; return query; } int skip = ActivePage - 1; if (skip > 0) query = query.Skip(skip * PageSize); _TotalPages = CalculateTotalPagesFromTotalItems(); return query.Take(PageSize); } The IEnumerable<T> version simply  converts the IEnumerable to an IQuerable and calls back into this method for filtering. The DataTable version requires a little more work to manually parse and filter records (I didn’t want to add the Linq DataSetExtensions assembly just for this): /// <summary> /// Filters a data table for an ActivePage. /// /// Note: Modifies the data set permanently by remove DataRows /// </summary> /// <param name="dt">Full result DataTable</param> /// <param name="activePage">Page to display. 0 to use ActivePage property </param> /// <returns></returns> public DataTable FilterDataTable(DataTable dt, int activePage) { ActivePage = activePage < 1 ? ActivePage : activePage; if (ActivePage < 1) ActivePage = 1; TotalItems = dt.Rows.Count; if (TotalItems <= PageSize) { ActivePage = 1; TotalPages = 1; return dt; } int skip = ActivePage - 1; if (skip > 0) { for (int i = 0; i < skip * PageSize; i++ ) dt.Rows.RemoveAt(0); } while(dt.Rows.Count > PageSize) dt.Rows.RemoveAt(PageSize); return dt; } Using the Pager Control The pager as it is is a first cut I built a couple of weeks ago and since then have been tweaking a little as part of an internal project I’m working on. I’ve replaced a bunch of pagers on various older pages with this pager without any issues and have what now feels like a more consistent user interface where paging looks and feels the same across different controls. As a bonus I’m only loading the data from the database that I need to display a single page. With the preset class tags applied too adding a pager is now as easy as dropping the control and adding the style sheet for styling to be consistent – no fuss, no muss. Schweet. Hopefully some of you may find this as useful as I have or at least as a baseline to build ontop of… Resources The Pager is part of the West Wind Web & Ajax Toolkit Pager.cs Source Code (some toolkit dependencies) Westwind.css base stylesheet with .pager and .gridpager styles Pager Example Page © Rick Strahl, West Wind Technologies, 2005-2010Posted in ASP.NET  

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  • Ajax Control Toolkit December 2013 Release

    - by Stephen.Walther
    Today, we released a new version of the Ajax Control Toolkit that contains several important bug fixes and new features. The new release contains a new Tabs control that has been entirely rewritten in jQuery. You can download the December 2013 release of the Ajax Control Toolkit at http://Ajax.CodePlex.com. Alternatively, you can install the latest version directly from NuGet: The Ajax Control Toolkit and jQuery The Ajax Control Toolkit now contains two controls written with jQuery: the ToggleButton control and the Tabs control.  The goal is to rewrite the Ajax Control Toolkit to use jQuery instead of the Microsoft Ajax Library gradually over time. The motivation for rewriting the controls in the Ajax Control Toolkit to use jQuery is to modernize the toolkit. We want to continue to accept new controls written for the Ajax Control Toolkit contributed by the community. The community wants to use jQuery. We want to make it easy for the community to submit bug fixes. The community understands jQuery. Using the Ajax Control Toolkit with a Website that Already uses jQuery But what if you are already using jQuery in your website?  Will adding the Ajax Control Toolkit to your website break your existing website?  No, and here is why. The Ajax Control Toolkit uses jQuery.noConflict() to avoid conflicting with an existing version of jQuery in a page.  The version of jQuery that the Ajax Control Toolkit uses is represented by a variable named actJQuery.  You can use actJQuery side-by-side with an existing version of jQuery in a page without conflict.Imagine, for example, that you add jQuery to an ASP.NET page using a <script> tag like this: <%@ Page Language="C#" AutoEventWireup="true" CodeBehind="WebForm1.aspx.cs" Inherits="TestACTDec2013.WebForm1" %> <!DOCTYPE html> <html > <head runat="server"> <title></title> </head> <body> <form id="form1" runat="server"> <div> <script src="Scripts/jquery-2.0.3.min.js"></script> <ajaxToolkit:ToolkitScriptManager runat="server" /> <ajaxToolkit:TabContainer runat="server"> <ajaxToolkit:TabPanel runat="server"> <HeaderTemplate> Tab 1 </HeaderTemplate> <ContentTemplate> <h1>First Tab</h1> </ContentTemplate> </ajaxToolkit:TabPanel> <ajaxToolkit:TabPanel runat="server"> <HeaderTemplate> Tab 2 </HeaderTemplate> <ContentTemplate> <h1>Second Tab</h1> </ContentTemplate> </ajaxToolkit:TabPanel> </ajaxToolkit:TabContainer> </div> </form> </body> </html> The page above uses the Ajax Control Toolkit Tabs control (TabContainer and TabPanel controls).  The Tabs control uses the version of jQuery that is currently bundled with the Ajax Control Toolkit (jQuery version 1.9.1). The page above also includes a <script> tag that references jQuery version 2.0.3.  You might need that particular version of jQuery, for example, to use a particular jQuery plugin. The two versions of jQuery in the page do not create a conflict. This fact can be demonstrated by entering the following two commands in the JavaScript console window: actJQuery.fn.jquery $.fn.jquery Typing actJQuery.fn.jquery will display the version of jQuery used by the Ajax Control Toolkit and typing $.fn.jquery (or jQuery.fn.jquery) will show the version of jQuery used by other jQuery plugins in the page.      Preventing jQuery from Loading Twice So by default, the Ajax Control Toolkit will not conflict with any existing version of jQuery used in your application. However, this does mean that if you are already using jQuery in your application then jQuery will be loaded twice. For performance reasons, you might want to avoid loading the jQuery library twice. By taking advantage of the <remove> element in the AjaxControlToolkit.config file, you can prevent the Ajax Control Toolkit from loading its version of jQuery. <ajaxControlToolkit> <scripts> <remove name="jQuery.jQuery.js" /> </scripts> <controlBundles> <controlBundle> <control name="TabContainer" /> <control name="TabPanel" /> </controlBundle> </controlBundles> </ajaxControlToolkit> Be careful here:  the name of the script being removed – jQuery.jQuery.js – is case-sensitive. If you remove jQuery then it is your responsibility to add the exact same version of jQuery back into your application.  You can add jQuery back using a <script> tag like this: <script src="Scripts/jquery-1.9.1.min.js"></script>     Make sure that you add the <script> tag before the server-side <form> tag or the Ajax Control Toolkit won’t detect the presence of jQuery. Alternatively, you can use the ToolkitScriptManager like this: <ajaxToolkit:ToolkitScriptManager runat="server"> <Scripts> <asp:ScriptReference Name="jQuery.jQuery.js" /> </Scripts> </ajaxToolkit:ToolkitScriptManager> The Ajax Control Toolkit is tested against the particular version of jQuery that is bundled with the Ajax Control Toolkit. Currently, the Ajax Control Toolkit uses jQuery version 1.9.1. If you attempt to use a different version of jQuery with the Ajax Control Toolkit then you will get the exception jQuery 1.9.1 is required in your JavaScript console window: If you need to use a different version of jQuery in the same page as the Ajax Control Toolkit then you should not use the <remove> element. Instead, allow the Ajax Control Toolkit to load its version of jQuery side-by-side with the other version of jQuery. Lots of Bug Fixes As usual, we implemented several important bug fixes with this release. The bug fixes concerned the following three controls: Tabs control – In the course of rewriting the Tabs control to use jQuery, we fixed several bugs related to the Tabs control. AjaxFileUpload control – We resolved an issue concerning the AjaxFileUpload and the TMP directory. HTMLEditor control – We updated the HTMLEditor control to use the new Ajax Control Toolkit bundling and minification framework. Summary I would like to thank the Superexpert team for their hard work on this release. Many long hours of coding and testing went into making this release possible.

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  • Run simple bash script to start applications at login

    - by ganjan
    I want to run a simple bash script automatically when I log in. For example #!/bin/bash echo "start spotify" gnome-terminal -e spotify --title spotify When I run this command, one gnome-terminal shows up and spotify show up. I also want the gnome-terminal to popup "hidden" in a different virtual desktop. (one of the other four virtual desktops you can choose from taskbar) I tried to add this to /home/me/.bash_login or something, but that didn't work..

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  • Purple/Pink lines on screen after login on Ubuntu Desktop 13.04

    - by Thomas May
    I downloaded Ubuntu 13.04 and I loaded up the live system. It loaded up fine but when I clicked on the Ubuntu logo purple and pink lines appeared on screen and they didn't go away so I thought that if I installed the OS it would be fine so I installed the OS, logged in and lo and behold the purple and pink lines where back. My video card is nVidia N force (I think) Anyone having the same problem???

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  • Ubuntu GUI crash when LightDM enters, unable to login

    - by Cesar
    This issue happened spounteniously, i don´t know what could have cause it as i wasn´t using the PC when it happened. I ruled out any messing around with the setting as the user doesn´t know how to enter the BIOS, doesn´t have the sudo password and was only using firefox and libreoffice when it happened. After the plymouth sequence i get this error. https://www.dropbox.com/s/uf1xdkqkw9alvcu/IMAG0252.jpg And this option: https://www.dropbox.com/s/tpivkgjkx2spa3v/IMAG0253.jpg I follow each option and nothing happens after that. The issue persist after rebooting. I choose the other options to see if anything happens, i either get back to option 1 or doesn´t show anything anormal. (I have pictures i someone wants to know) What i found weird is that event though the error is possitioned in the chip, however ubuntu 10.04 and 12.04 run fine in a live CD I saw that some people are having issues when LightDM has a non default wallpaper, but i use a default one. Thanks in advance.

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  • How to change login wallpaper?

    - by Mochan
    So, say my wallpaper is a picture of my family or something, or a picture of a flower. But, when I log in, I don't want my family/flower to show on the log in screen but instead be something separate. Is there a possible way to do this? Like, say, this is my desktop image: But for my log in screen, I would have to have this (but I want the flower, and then the woven speaker thing for the log in screen?): Thanks in advance,

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  • Login - check database if user exists... (c#)

    - by SAMIR BHOGAYTA
    I have managed to do the following... string connectionString = "datasource=localhost;username=xxx;password=xxx;database=xxx"; MySqlConnection mySqlConnection = new MySqlConnection(connectionString); string selectString = "SELECT username, password " + "FROM forum_members " + "WHERE username = '" + frmUsername.Text + "' AND password = '" + frmPassword.Text + "'"; MySqlCommand mySqlCommand = new MySqlCommand(selectString, mySqlConnection); mySqlConnection.Open(); String strResult = String.Empty; strResult = (String)mySqlCommand.ExecuteScalar(); mySqlConnection.Close(); if (strResult.Length == 0) { Label1.Text = "INCORRECT USER/PASS!" //could redirect to register page } else { Label1.Text = "YOU ARE LOGGED IN!"; //set loggin in sessions variables }

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  • Dual booted Windows 7 freezes after login screen

    - by Cathal
    First-time Linux user, using a Packard Bell Easy Note TS laptop. My problem arose after I dual boot installed Ubuntu 12.04 on Windows 7 via WUBI. I backed up all my data, and reinstalled Windows from factory settings on the recovery partition. When I first tried to install Ubuntu I mistakenly closed the lid at the start of the installation, stopping it. After that I rebooted, and my second installation attempt went without a hitch. Ubuntu works perfectly, the data on the partitions seem to be fine. My problem is I can't log back in to Windows 7. After selecting it in GRUB, and then in the Windows 7/ WUBI choice on boot, it loads up perfectly til the user log in screen. After the password is inputted, it stalls on the "Welcome" busy screen. This happens in Safe mode as well. Startup repair can't find a problem and neither can CHKDSK. System restore and Last known good config have no effect either. If anyone could help me out, I'd be real grateful. edit in response to the question below, since I don't know how to comment: Windows was installed first and its partitions are the first on the list. Should I move the windows partitions to after the Linux ones on the disk? Thanks for your help.

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  • Administrator user session only shows a terminal

    - by Saariko
    Weird problem: After upgrading to 11.10 (and I am sure that I worked with it for couple of days). We had a power failure, and now, when open the computer, what I get is a screen, with a scrollable list of users (administrator is one of them). When I select the administrator user, and login, I get on the top left a terminal window. That's it ! I don't see my regular ubuntu desktop. What's wrong? I have tried some of the issues mentioned here: Delete the .Xauthority sudo apt-get update *I had some DNS errors, so had to fic my /etc/resolv.config (works now) please advise.

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  • cannot unlock login screen 14.04

    - by LittleNooby
    When my computer boots, entering the correct password won't start my session. I found out the problem is /home/user/.Xauthority ownership. root owns this folder and giving the ownership to the user will solve the problem... for a while. I don't know how or when, but the ownership will go back to root pretty often; It can happen just after one boot or ten. Is there a definitive solution to this problem?

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  • 12.4 LTS after update fails to login

    - by user111839
    An update today (30-11-2012) on 12.4 lead to failure to log in. The system gets through its boot process then presents the logins, on choosing any of these immediately returned to log-in screen with no error. Machine is an AMD FX 64 on an Asus MB using the built-in graphics. If no one knows what this might be, what's the alternative distro to Ubuntu? It's the second time something like this has happened after an update in three months, kudos to the Ubuntu team but I need more reliability. Cheers, thanks to all.

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  • Control to Control Binding in WPF/Silverlight

    - by psheriff
    In the past if you had two controls that you needed to work together, you would have to write code. For example, if you want a label control to display any text a user typed into a text box you would write code to do that. If you want turn off a set of controls when a user checks a check box, you would also have to write code. However, with XAML, these operations become very easy to do. Bind Text Box to Text Block As a basic example of this functionality, let’s bind a TextBlock control to a TextBox. When the user types into a TextBox the value typed in will show up in the TextBlock control as well. To try this out, create a new Silverlight or WPF application in Visual Studio. On the main window or user control type in the following XAML. <StackPanel>  <TextBox Margin="10" x:Name="txtData" />  <TextBlock Margin="10"              Text="{Binding ElementName=txtData,                             Path=Text}" /></StackPanel> Now run the application and type into the TextBox control. As you type you will see the data you type also appear in the TextBlock control. The {Binding} markup extension is responsible for this behavior. You set the ElementName attribute of the Binding markup to the name of the control that you wish to bind to. You then set the Path attribute to the name of the property of that control you wish to bind to. That’s all there is to it! Bind the IsEnabled Property Now let’s apply this concept to something that you might use in a business application. Consider the following two screen shots. The idea is that if the Add Benefits check box is un-checked, then the IsEnabled property of the three “Benefits” check boxes will be set to false (Figure 1). If the Add Benefits check box is checked, then the IsEnabled property of the “Benefits” check boxes will be set to true (Figure 2). Figure 1: Uncheck Add Benefits and the Benefits will be disabled. Figure 2: Check Add Benefits and the Benefits will be enabled. To accomplish this, you would write XAML to bind to each of the check boxes in the “Benefits To Add” section to the check box named chkBenefits. Below is a fragment of the XAML code that would be used. <CheckBox x:Name="chkBenefits" /> <CheckBox Content="401k"           IsEnabled="{Binding ElementName=chkBenefits,                               Path=IsChecked}" /> Since the IsEnabled property is a boolean type and the IsChecked property is also a boolean type, you can bind these two together. If they were different types, or if you needed them to set the IsEnabled property to the inverse of the IsChecked property then you would need to use a ValueConverter class. SummaryOnce you understand the basics of data binding in XAML, you can eliminate a lot code. Connecting controls together is as easy as just setting the ElementName and Path properties of the Binding markup extension. NOTE: You can download the complete sample code at my website. http://www.pdsa.com/downloads. Choose Tips & Tricks, then "SL – Basic Control Binding" from the drop-down. Good Luck with your Coding,Paul Sheriff ** SPECIAL OFFER FOR MY BLOG READERS **Visit http://www.pdsa.com/Event/Blog for a free eBook on "Fundamentals of N-Tier".

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  • Making it Easier for Older Users to Login to Multiple Accounts

    - by Mike Hagstrom
    I currently do consulting for a small business that has multiple applications that they need to login too. I'm trying to get them to start using Basecamp and Zendesk to make all of our lives easier when it comes to collaboration on big projects and quick helpdesk ticket items. However, I have recently been informed that it is difficult for them to remember all of these websites etc... to login too. However the login information is the same. Right now they have to login to: Windows Login Gmail I want them additionally to login to Basecamp Zendesk This is just a generation or two gap between myself and them, so I'm wondering what others do to solve these problems. Is there some way we could configure USB thumbdrives that somehow have Lastpass or something on that when plugged into the computer automatically log them into their Windows account, then when they were to say visit the Basecamp account would automatically log them into that? I think the security risk (of a list thumbdrive) is well worth the ability to use these extra applications. Unless anyone else has any other ways for making it easier for users to login to multiple sites.

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  • Immediate logout after login with PAM, Kerberos, and LDAP

    - by Dylan Klomparens
    I've set up remote login on a computer using Kerberos and LDAP. I've also configured NFS to mount onto /home so that the user's home directory is the same wherever they login. Kerberos authentication seems to work fine. I can get a ticket using kinit user1 (assuming user1 is a remote user) and see the ticket with klist. I'm pretty sure LDAP is working because I see the proper output from getent passwd, which lists all the remote users. The contents of /home are present when I list the files. The problem is: when I try to login as a remote user the session is immediately ended. Why is it not letting me stay logged in? Here is the output from /var/log/messages after a login attempt: # /var/log/messages: Oct 9 10:57:53 tophat login[6472]: pam_krb5[6472]: authentication succeeds for 'user1' ([email protected]) Oct 9 10:57:53 tophat login[6472]: pam_krb5[6472]: pam_setcred (establish credential) called Oct 9 10:57:53 tophat login[6472]: pam_krb5[6472]: pam_setcred (delete credential) called EDIT: The distro is openSUSE. Here are the common-* files in /etc/pam.d:   # /etc/pam.d/common-account account required pam_unix.so   # /etc/pam.d/common-auth auth sufficient pam_krb5.so minimum_uid=1000 auth required pam_unix.so nullok_secure try_first_pass   # /etc/pam.d/common-session session optional pam_umask.so umask=002 session sufficient pam_krb5.so minimum_uid=1000 session required pam_unix.so There doesn't appear to be a /var/log/auth.log file nor a /var/log/secure file.

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