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  • Force gdm login screen to the primary monitor

    - by JIa3ep
    I have two monitors attached to my video card. Primary monitor has a resolution equal to 1280x1024 and second has 1920x1200. My gdm login screen always appears on the second monitor even if it is switched off. My question is how to force gdm to show login screen always on primary monitor with resolution 1280x1024? I use Ubuntu 10.04.

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  • Control margins of an automatically generated content presenter in Windows Phone Panorama Control

    - by Maxim V. Pavlov
    I am building an MVVM Panorama Windows Phone 7 application. At some point of Panorama Item's layout I get a bottom margin of a panorama header box, that moves my content too far down. Is there a way I can set a bottom margin of a ContentPresenter, that is generated to hold the controls, defined in the Panorama.HeaderTemplate? Here is my layout list in Silverlight Spy: In case the screen shot is not readable, here is a large version: http://bit.ly/rBvNp8 Something generates a 26 points bottom margin for a header box (probably the control's code, that handles a layout). How can I control this value? I need it to be set to 0.

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  • windows 2008 server login screen remote desktop

    - by Marki
    how can I access a GRAPHICAL login screen (like on earlier Windows versions, or like VNC) instead of the Username/Password prompt via RDP? I'm asking because we have several servers where we have no passwords but the shutdown/reboot option is given via group policy on the login screen. Thus, instead of having to go the hardware console I'd like to be able to perform reboot/shutdown actions via terminal services. Regards, Marki

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  • javax.security.auth.login.LoginException: Login failed

    - by abdeslam
    I'm trying to run a hadoop job (version 18.3) on my windows machine but I get the following error: Caused by: javax.security.auth.login.LoginException: Login failed: CreateProcess: bash -c groups error=2 at org.apache.hadoop.security.UnixUserGroupInformation.login(UnixUserGroupInformation.java:250) at org.apache.hadoop.security.UnixUserGroupInformation.login(UnixUserGroupInformation.java:275) at org.apache.hadoop.mapred.JobClient.configureCommandLineOptions(JobClient.java:557) ... 3 more The same job works fine in an another windows machine. Do I have may be something wrong in the settings variabls? How can I fix this problem?

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  • Survey: How do you manage the source code for your personal projects?

    - by Linchi Shea
    This seems to be the survey season. Andy’s post on source controlling T-SQL code triggered a question that I always wanted to ask. Do you version control the source code for your various personal projects (i.e. not projects of your customer or employer)? Do you use a computer at home for your source control repository, or do you use a hosting service such as ProjectLocker ? If you do it yourself at home, what version control software you use? If you use a hosting service, what’s your experience?...(read more)

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  • Is this PHP/MySQL login script secure?

    - by NightMICU
    Greetings, A site I designed was compromised today, working on damage control at the moment. Two user accounts, including the primary administrator, were accessed without authorization. Please take a look at the log-in script that was in use, any insight on security holes would be appreciated. I am not sure if this was an SQL injection or possibly breach on a computer that had been used to access this area in the past. Thanks <?php //Start session session_start(); //Include DB config require_once('config.php'); //Error message array $errmsg_arr = array(); $errflag = false; //Connect to mysql server $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } //Select database $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } //Function to sanitize values received from the form. Prevents SQL injection function clean($str) { $str = @trim($str); if(get_magic_quotes_gpc()) { $str = stripslashes($str); } return mysql_real_escape_string($str); } //Sanitize the POST values $login = clean($_POST['login']); $password = clean($_POST['password']); //Input Validations if($login == '') { $errmsg_arr[] = 'Login ID missing'; $errflag = true; } if($password == '') { $errmsg_arr[] = 'Password missing'; $errflag = true; } //If there are input validations, redirect back to the login form if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; session_write_close(); header("location: http://tapp-essexvfd.org/admin/index.php"); exit(); } //Create query $qry="SELECT * FROM user_control WHERE username='$login' AND password='".md5($_POST['password'])."'"; $result=mysql_query($qry); //Check whether the query was successful or not if($result) { if(mysql_num_rows($result) == 1) { //Login Successful session_regenerate_id(); //Collect details about user and assign session details $member = mysql_fetch_assoc($result); $_SESSION['SESS_MEMBER_ID'] = $member['user_id']; $_SESSION['SESS_USERNAME'] = $member['username']; $_SESSION['SESS_FIRST_NAME'] = $member['name_f']; $_SESSION['SESS_LAST_NAME'] = $member['name_l']; $_SESSION['SESS_STATUS'] = $member['status']; $_SESSION['SESS_LEVEL'] = $member['level']; //Get Last Login $_SESSION['SESS_LAST_LOGIN'] = $member['lastLogin']; //Set Last Login info $qry = "UPDATE user_control SET lastLogin = DATE_ADD(NOW(), INTERVAL 1 HOUR) WHERE user_id = $member[user_id]"; $login = mysql_query($qry) or die(mysql_error()); session_write_close(); if ($member['level'] != "3" || $member['status'] == "Suspended") { header("location: http://members.tapp-essexvfd.org"); //CHANGE!!! } else { header("location: http://tapp-essexvfd.org/admin/admin_main.php"); } exit(); }else { //Login failed header("location: http://tapp-essexvfd.org/admin/index.php"); exit(); } }else { die("Query failed"); } ?>

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  • Cannot login to ISCSI Target - hangs after sending login details

    - by Frank
    I have an ISCSI target volume, to which i am trying to connect using CentOS Linux server. Everything works fine, but cannot its stuck at login. Here are the steps i am performing: [root@neon ~]# iscsiadm -m node -l iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session20 iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session21 iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session22 iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session23 iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session30 iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session31 iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session78 iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session79 iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session80 iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session81 Logging in to [iface: eql.eth2, target: iqn.2001-05.com.equallogic:0-8a0906-ab4764e0b-55ed2ef5cf350a66-neon105, portal: 10.10.1.1,3260] (multiple) After this step, its stucks, waits for some time and then gives this output: Logging in to [iface: iface1, target: iqn.2001-05.com.equallogic:0-8a0906-ab4764e0b-55ed2ef5cf350a66-neon105, portal: 10.10.1.1,3260] (multiple) iscsiadm: Could not login to [iface: eql.eth2, target: iqn.2001-05.com.equallogic:0-8a0906-ab4764e0b-55ed2ef5cf350a66-neon105, portal: 10.10.1.1,3260]. My iscsi.conf is this: node.startup = automatic node.session.timeo.replacement_timeout = 15 # default 120; RedHat recommended node.conn[0].timeo.login_timeout = 15 node.conn[0].timeo.logout_timeout = 15 node.conn[0].timeo.noop_out_interval = 5 node.conn[0].timeo.noop_out_timeout = 5 node.session.err_timeo.abort_timeout = 15 node.session.err_timeo.lu_reset_timeout = 20 node.session.initial_login_retry_max = 8 # default 8; Dell recommended node.session.cmds_max = 1024 # default 128; Equallogic recommended node.session.queue_depth = 32 # default 32; Equallogic recommended node.session.iscsi.InitialR2T = No node.session.iscsi.ImmediateData = Yes node.session.iscsi.FirstBurstLength = 262144 node.session.iscsi.MaxBurstLength = 16776192 node.conn[0].iscsi.MaxRecvDataSegmentLength = 262144 discovery.sendtargets.iscsi.MaxRecvDataSegmentLength = 32768 node.conn[0].iscsi.HeaderDigest = None node.session.iscsi.FastAbort = Yes Also, in access control, i have given full access to Any IP, Any CHAP user and fixed iscsi initiator name. With same access level, all other volumes on rest of servers are working, except this one.

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  • What is Inversion of control and why we need it?

    - by Jalpesh P. Vadgama
    Most of programmer need inversion of control pattern in today’s complex real time application world. So I have decided to write a blog post about it. This blog post will explain what is Inversion of control and why we need it. We are going to take a real world example so it would be better to understand. The problem- Why we need inversion of control? Before giving definition of Inversion of control let’s take a simple real word example to see why we need inversion of control. Please have look on the following code. public class class1 { private class2 _class2; public class1() { _class2=new class2(); } } public class class2 { //Some implementation of class2 } I have two classes “Class1” and “Class2”.  If you see the code in that I have created a instance of class2 class in the class1 class constructor. So the “class1” class is dependent on “class2”. I think that is the biggest issue in real world scenario as if we change the “class2” class then we might need to change the “class1” class also. Here there is one type of dependency between this two classes that is called Tight Coupling. Tight coupling will have lots of problem in real world applications as things are tends to be change in future so we have to change all the tight couple classes that are dependent of each other. To avoid this kind of issue we need Inversion of control. What is Inversion of Control? According to the wikipedia following is a definition of Inversion of control. “In software engineering, Inversion of Control (IoC) is an object-oriented programming practice where the object coupling is bound at run time by an assembler object and is typically not known at compile time using static analysis.” So if you read the it carefully it says that we should have object coupling at run time not compile time where it know what object it will create, what method it will call or what feature it will going to use for that. We need to use same classes in such way so that it will not tight couple with each other. There are multiple way to implement Inversion of control. You can refer wikipedia link for knowing multiple ways of implementing Inversion of control. In future posts we are going to see all the different way of implementing Inversion of control.

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  • Distributed Development Tools -- (Version control and Project Management)

    - by Macy Abbey
    Hello, I've recently become responsible for choosing which source control and project management software to use for a company that employs me. Currently it uses Jira (project management) and Subversion (version control). I know there are many other options out there -- the ones I know about are all in this article http://mashable.com/2010/07/14/distributed-developer-teams/ . I'm leaning towards recommending they just stay with what they have as it seems workable and any change would have to be worth the cost of switching to say github/basecamp or some other solution. Some details on the team: It's a distributed development shop. Meetings of the whole team in one room are rare. It's currently a very small development team (three developers). The project management software is used by developers and a product manager or two. What are you experiences with version control and project management web applications? Are there any you would recommend and you think are worth the switching cost of time to learn new services / implementing the change? Edit: After educating myself further on the options it appears DVCS offer powerful benefits that may be worth investing in now as opposed to later in the company's lifetime when the switching cost is higher: I'm a Subversion geek, why I should consider or not consider Mercurial or Git or any other DVCS?

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  • How to Remote View and Control Your Android Phone

    - by Jason Fitzpatrick
    If you’ve ever wished you could see your Android phone’s screen on your desktop or remote control it using your mouse and keyboard we’ll show you how in this simple guide to gaining remote access to your Android device. Why would you want to gain access? When you’re done with this tutorial you’ll be able to view your phone’s screen on your computer monitor which is great for: putting your Android notifications right along side other notification boxes on your monitor, using it like an on-monitor caller ID, and taking screenshots and screencasts. Also if your phone is rooted (and it should be! rooting unlocks so many great features) you’ll gain the ability to use your computer’s keyboard and mouse to control your Android phone. Remote keyboard/mouse control is great for inputting data on the tiny screen without needing to peck at the on-screen keyboard. Latest Features How-To Geek ETC RGB? CMYK? Alpha? What Are Image Channels and What Do They Mean? How to Recover that Photo, Picture or File You Deleted Accidentally How To Colorize Black and White Vintage Photographs in Photoshop How To Get SSH Command-Line Access to Windows 7 Using Cygwin The How-To Geek Video Guide to Using Windows 7 Speech Recognition How To Create Your Own Custom ASCII Art from Any Image Google Cloud Print Extension Lets You Print Doc/PDF/Txt Files from Web Sites Hack a $10 Flashlight into an Ultra-bright Premium One Firefox Personas Arrive on Firefox Mobile Focus Booster Is a Sleek and Free Productivity Timer What is the Internet? From the Today Show January 1994 [Historical Video] Take Screenshots and Edit Them in Chrome and Iron Using Aviary Screen Capture

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  • Simple ADF page using BAM Data Control

    - by [email protected]
    var gaJsHost = (("https:" == document.location.protocol) ? "https://ssl." : "http://www."); document.write(unescape("%3Cscript src='" + gaJsHost + "google-analytics.com/ga.js' type='text/javascript'%3E%3C/script%3E")); try { var pageTracker = _gat._getTracker("UA-15829414-1"); pageTracker._trackPageview(); } catch(err) {} Purpose : In this blog I will walk you through very simple steps to create an ADF page using BAM data control connection.Details : Create the projectOpen JDeveloper (make sure you have installed the SOA extension for JDev)Create new Application using "Generic Application" template.Click on "Next"Shuttle  "ADF Faces" to right pane for the project technology.Click "Finish"Create a BAM connectionIn the resource palette click on "Folder->New Connection -> BAM"Enter the connection name and click "Next"Enter Connection details Click on "Test connection" and "Finish"Create the BAM Data Control Open the IDE connection created in above step.Drag and drop "Employees" to "Data controls" palette.Select "Flat Query" and Click "Finish".Create the View Create a new JSF page.From Data control Panel drag and drop "Employees->Query->ADF Read Only table"Right click and Run the page.

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  • IIS cache control header settings

    - by a_m0d
    I'm currently working on a website that is accessed over https. We have recently come across a problem where we are unable to view .pdf files or any other type of file that is sent as an attachment (Content-Disposition:attachment). According to Microsoft Knowledge Base this is due to the fact that Cache-Control is set to no-cache. However, we have a requirement that all pages be fully reloaded every time they are visited, so we have disabled caching on all pages (through our ASP code, not through IIS settings). However, I have made a special case of this one page that shows the attachment, and it now returns a header with Cache-Control:private and the expiry set to 1 minute in the future. This works fine when I test it on my local machine, using https. However, when I deploy it to our test server and try it, the response headers still return Cache-Control:no-cache. There is no firewall or anything between me and the server, so IIS itself must be adding these headers and replacing mine. I have no idea why it would do this, and it doesn't really make any sense, but it seems to be the only option at the moment (I haven't yet found any other place in the code that will change the cache headers). Can anyone point me to a possible place where IIS might be setting these header values?

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  • Distributed Development Tools -- (Version control and Project Management)

    - by Macy Abbey
    I've recently become responsible for choosing which source control and project management software to use for a company that employs me. Currently it uses Jira (project management) and Subversion (version control). I know there are many other options out there -- the ones I know about are all in this article http://mashable.com/2010/07/14/distributed-developer-teams/ . I'm leaning towards recommending they just stay with what they have as it seems workable and any change would have to be worth the cost of switching to say github/basecamp or some other solution. Some details on the team: It's a distributed development shop. Meetings of the whole team in one room are rare. It's currently a very small development team (three developers). The project management software is used by developers and a product manager or two. What are you experiences with version control and project management web applications? Are there any you would recommend and you think are worth the switching cost of time to learn new services / implementing the change? Edit: After educating myself further on the options it appears DVCS offer powerful benefits that may be worth investing in now as opposed to later in the company's lifetime when the switching cost is higher: I'm a Subversion geek, why I should consider or not consider Mercurial or Git or any other DVCS?

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  • How to wake from screensaver directly to the login screen in Ubuntu

    - by torbengb
    (a.k.a. How to switch users without entering password, part II) (see part I) I've got Ubuntu 9.10 with a user account for my wife, and one for myself. "Wake-from-screensaver" should result in "choose user" without having to enter any password. I know how to do that in Windows, but I'm not good with Linux (yet). Part of this was answered in my earlier question which helped me get past the login screen without passwords (after booting, and after choosing "switch user"), but once the screensaver kicks in and I wake it up again, the system does not present the "choose user" screen. Instead, it either turns off the screensaver and presents the desktop of the most recent user, or (if the screensaver is set to lock the screen) prompt for the user's password (which can be handily surpassed by clicking the "switch user" button and choosing the same user again). So, the login ("choose user") screen has been dealt with. How do I make the (any) screensaver return to the login screen at wake, rather than to the current user's desktop? Windows can do this, I'm sure Linux can too - but how?

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  • login form whith java/sqlite

    - by tuxou
    hi I would like to create a login form for my application with the possibility to add or remove users for an sqlite database, i have created the table users(nam, pass) but i can't unclud it in my login form, it someone could help me this is my login code: import java.awt.*; import java.awt.event.*; import javax.swing.*; public class login extends JFrame { // Variables declaration private JLabel jLabel1; private JLabel jLabel2; private JTextField jTextField1; private JPasswordField jPasswordField1; private JButton jButton1; private JPanel contentPane; // End of variables declaration public login() { super(); create(); this.setVisible(true); } private void create() { jLabel1 = new JLabel(); jLabel2 = new JLabel(); jTextField1 = new JTextField(); jPasswordField1 = new JPasswordField(); jButton1 = new JButton(); contentPane = (JPanel)this.getContentPane(); // // jLabel1 // jLabel1.setHorizontalAlignment(SwingConstants.LEFT); jLabel1.setForeground(new Color(0, 0, 255)); jLabel1.setText("username:"); // // jLabel2 // jLabel2.setHorizontalAlignment(SwingConstants.LEFT); jLabel2.setForeground(new Color(0, 0, 255)); jLabel2.setText("password:"); // // jTextField1 // jTextField1.setForeground(new Color(0, 0, 255)); jTextField1.setSelectedTextColor(new Color(0, 0, 255)); jTextField1.setToolTipText("Enter your username"); jTextField1.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent e) { jTextField1_actionPerformed(e); } }); // // jPasswordField1 // jPasswordField1.setForeground(new Color(0, 0, 255)); jPasswordField1.setToolTipText("Enter your password"); jPasswordField1.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent e) { jPasswordField1_actionPerformed(e); } }); // // jButton1 // jButton1.setBackground(new Color(204, 204, 204)); jButton1.setForeground(new Color(0, 0, 255)); jButton1.setText("Login"); jButton1.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent e) { jButton1_actionPerformed(e); } }); // // contentPane // contentPane.setLayout(null); contentPane.setBorder(BorderFactory.createEtchedBorder()); contentPane.setBackground(new Color(204, 204, 204)); addComponent(contentPane, jLabel1, 5,10,106,18); addComponent(contentPane, jLabel2, 5,47,97,18); addComponent(contentPane, jTextField1, 110,10,183,22); addComponent(contentPane, jPasswordField1, 110,45,183,22); addComponent(contentPane, jButton1, 150,75,83,28); // // login // this.setTitle("Login To Members Area"); this.setLocation(new Point(76, 182)); this.setSize(new Dimension(335, 141)); this.setDefaultCloseOperation(WindowConstants.EXIT_ON_CLOSE); this.setResizable(false); } /** Add Component Without a Layout Manager (Absolute Positioning) */ private void addComponent(Container container,Component c,int x,int y,int width,int height) { c.setBounds(x,y,width,height); container.add(c); } private void jTextField1_actionPerformed(ActionEvent e) { } private void jPasswordField1_actionPerformed(ActionEvent e) { } private void jButton1_actionPerformed(ActionEvent e) { System.out.println("\njButton1_actionPerformed(ActionEvent e) called."); String username = new String(jTextField1.getText()); String password = new String(jPasswordField1.getText()); if(username.equals("") || password.equals("")) // If password and username is empty Do this { jButton1.setEnabled(false); JLabel errorFields = new JLabel("You must enter a username and password to login."); JOptionPane.showMessageDialog(null,errorFields); jTextField1.setText(""); jPasswordField1.setText(""); jButton1.setEnabled(true); this.setVisible(true); } else { JLabel optionLabel = new JLabel("You entered "+username+" as your username. Is this correct?"); int confirm =JOptionPane.showConfirmDialog(null,optionLabel); switch(confirm){ // Switch Case case JOptionPane.YES_OPTION: // Attempt to Login user jButton1.setEnabled(false); // Set button enable to false to prevent 2 login attempts break; case JOptionPane.NO_OPTION: // No Case.(Go back. Set text to 0) jButton1.setEnabled(false); jTextField1.setText(""); jPasswordField1.setText(""); jButton1.setEnabled(true); break; case JOptionPane.CANCEL_OPTION: // Cancel Case.(Go back. Set text to 0) jButton1.setEnabled(false); jTextField1.setText(""); jPasswordField1.setText(""); jButton1.setEnabled(true); break; } // End Switch Case } } public static void main(String[] args) { JFrame.setDefaultLookAndFeelDecorated(true); JDialog.setDefaultLookAndFeelDecorated(true); try { UIManager.setLookAndFeel("com.sun.java.swing.plaf.windows.WindowsLookAndFeel"); } catch (Exception ex) { System.out.println("Failed loading L&F: "); System.out.println(ex); } new login(); }; }

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  • How to set up source control in VS2010

    - by Jouke van der Maas
    Hi, I want to set up source control for my project, but it seems like I need a server for this. I've never done this before, and I couldn't find anything helpfull yet. Is there any way to host a server locally so Visual studio can use it? Or do you know any online (free) servers I can use? By the way, if source control is not actually what i should use for keeping track of changes in my files, please suggest a better option. Thanks in advance.

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  • Magento set Store Id - customer login - but still logged out

    - by user3564050
    I've got an overridden AccountController in which i set the current store to an other as currently running (example: Customer is in website default and store default, going to login page, click login, my loginPostAction sets the store to id "2" (on website 2) and then executes the parent code loginPostAction. The store is set, of course, but after the login and the redirect to home, the customer is not logged in anymore... Customer-sendlogindata-myaccountcontroller sets store-original account controller logs in without errors (cause $session customer is set)-redirect to home-customer is not logged in anymore... i set the store with Mage::app()-setCurrentStore($id); . And in index.php i've got an extra where the store is set to the right id (2) too and this works... but the customer is not logged in anymore.. is that an issue with the session cause different websites ? I don't want to globally share customer.. each website has his own customers, but every customer has to be able to login on default store. AccountController.php overridden: public $Website_Ids = array( array("code" => "gerstore", "id" => "3", "website" => "ger"), array("code" => "ukstore", "id" => "2", "website" => "uk"), array("code" => "esstore", "id" => "4", "website" => "es"), array("code" => "frstore", "id" => "5", "website" => "fr") ); public function loginPostAction() { $login = $this->getRequest()->get('login'); if(isset($login['username'])) { $found = null; foreach($this->Website_Ids as $WebsiteId) { $customer = Mage::getModel('customer/customer'); $customer->setWebsiteId($WebsiteId['id']); $customer->loadByEmail($login['username']); if(count($customer->getData()) > 0) { $found = $WebsiteId; } } if($found != null && Mage::app()->getStore()->getId() != $found['id']) { /* found, so set currentstore to id */ Mage::app()->setCurrentStore($found['id']); $_SESSION['current_store_b2b'] = $found; } /* not found, doesn't matter cause mage login exception handling */ } parent::loginPostAction(); } Index.php : session_start(); $session = $_SESSION['current_store_b2b']; if($session != null || $session != "") { Mage::app()->setCurrentStore($session['id']); Mage::run($session['code'], 'store'); } else { /* Store or website code */ $mageRunCode = isset($_SERVER['MAGE_RUN_CODE']) ? $_SERVER['MAGE_RUN_CODE'] : ''; /* Run store or run website */ $mageRunType = isset($_SERVER['MAGE_RUN_TYPE']) ? $_SERVER['MAGE_RUN_TYPE'] : 'store'; Mage::run($mageRunCode, $mageRunType); } Whats the matter ? Thanks.

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  • Android: prevent user from coming back to login page after logging in

    - by user522559
    Hi all, I have a login page in my android app. I want to prevent the user after logging in to come back to the login page. Also, when the user reopens the app, if he has logged in before, I want to go directly to the main page without having to go to the login page. What the best way of doing that? One idea I thought of is to save the login parameters in a cookie, and then, when the app is reopens, if the cookie contains some login information, I inflate the main page, otherwise, I inflate the login page. Is this the best way of doing it? Thanks,

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  • Skip new Windows 7 user selection and go to login prompt

    - by Doltknuckle
    We've begun our migration to windows 7 and we ran into an interesting issue. When we hit "CTRL+ALT+DEL" we are brought to the "User selection Screen". Normally, this screen will have an icon for every local user for the machine. These machines are Domain members with "Fast User Switch" disabled so no user names are listed only the "Other User" option. If you click "Other User" or hit enter, the system moves on to the normal login screen where it prompts for user name and password. Here's the issue: We want to find a way to skip over the part where a user selects "Other User". We essentially want the system to always assume that we always want "Other User" and to go directly to the login screen when a user hits "CTRL+ALT+DEL". What I find odd is that the "Other User" doesn't show up until we've had more than one domain user log in. Right after we re-image the machine, the login process goes directly to the user credential prompt. Anyone have any ideas?

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  • Login or Register (Ruby on rails)

    - by DanielZ
    Hello stackoverflow, I'm working on an Ruby on Rails application (2.3.x) and i want to make a form that lets the user login or register. I want to do this in the same form. I have a JS function that replaces the form elements like this: Login form: <% form_for @user do |f| %> <div id="form"> <%= f.label :email, "E-mail" %> <%= f.text_field :email %> <%= f.label :password, "Password" %> <%= f.password_field :password %> <%= link_to "I don't have an account, "#", :id => "changeForm"%> <%= f.submit "Login" %> </div> <% end %> The id "changeForm" triggers a JS function that changes the form elements. So if you press the url the html looks like this: <% form_for @user do |f| %> <div id="form"> <%= f.label :name, "Name" %> <%= f.text_field :name %> <%= f.label :email, "E-mail" %> <%= f.text_field :email %> <%= f.label :password, "Password" %> <%= f.password_field :password %> <%= f.label :password_confirmation, "Password confirmation" %> <%= f.password_field :password_confirmation %> <%= link_to "I do have an account, "#", :id => "changeForm"%> <%= f.submit "Register" %> </div> <% end %> I added the neccesary validations to my user model: class User < ActiveRecord::Base attr_reader :password validates_presence_of :name, :email, :password validates_format_of :email, :with => /\A([^@\s]+)@((?:[-a-z0-9]+\.)+[a-z]{2,})\Z/i validates_confirmation_of :password But what happens when you fill in the email / password you get the errors that the name is missing and that the password fields aren't confirmed. So i could do some nasty programming in my user model like this: #if password_conf or the name are present the user has tried to register... if params[:user][:password_confirmation].present? || params[:user][:name].present? #so we'll try to save the user if @user.save #if the user is saved authenticate the user current_session.user = User.authenticate(params[:user]) #if the user is logged in? if current_session.user.present? flash[:notice] = "succesvully logged redirect_to some_routes_path else #not logged in... flash[:notice] = "Not logged in" render :action => "new" end else #user not saved render :action => "new" end else #So if the params[:user][:password_confirmation] or [:user][:name] weren't present we geuss the user wants to login... current_session.user = User.authenticate(params[:user]) #are we logged_in? if current_session.user.present? flash[:notice] = "Succesvully logged in" redirect_to some_routes_path else #errors toevoegen @user.errors.add(:email, "The combination of email/password isn't valid") @user.errors.add(:password," ") render :action => "new" end end end Without validations this (imho dirty code and should not be in the controller) works. But i want to use the validates_presence_of methods and i don't want to slap the "conventions over configurations" in the face. So another thing i have tried is adding a hidden field to the form: #login form <%= f.hidden_field :login, :value => true %> # and ofcourse set it to false if we want to register. And then i wanted to use the method: before_validation before_validation_on_create do |user| if params[:user].login == true #throws an error i know... validates_presence_of :email, :password validates_format_of :email, :with => /\A([^@\s]+)@((?:[-a-z0-9]+\.)+[a-z]{2,})\Z/i else validates_presence_of :name, :email, :password validates_format_of :email, :with => /\A([^@\s]+)@((?:[-a-z0-9]+\.)+[a-z]{2,})\Z/i validates_confirmation_of :password end end But this doesn't work because i can't access the params. And login isn't a attribute for the user object. But i thought that in this way i could validate the email and password params if the user wants to login. And all the other attrs if the user want to register. So all i could think of doesn't work how i want it to work. So my main goal is this: 1 form for login/register with the use of the validation methods in the user model. So if we want to login but don't fill in any information = give validation errors. And if the user wants to login but the email/password combination doens't match give the "@user.errors.add(:email, "the combination wasn't found in the db...")". And the same goes for user register... Thanks in advance!

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  • Can't login after upgrading to Windows 8.1

    - by flatline
    This afternoon, I upgraded my work laptop from Windows 8 to Windows 8.1. I had previously had a local account, but after the upgrade, it prompted me to enter my windows account credentials, which I had set up beforehand at some point. I entered my password and clicked next, went through another screen or two, grew tired with the process, and clicked whatever the equivalent button to "skip this step" that I was presented with. Now I can't log in. Not with my (previous) local account password, and not with my windows account password. It's a Dell with biometric identification, which I had set up previously, so I put my finger on the reader and it complained that I couldn't use that fingerprint because I had changed my password. But, I hadn't wittingly changed my password at all. I assume that what happened is that, by entering my credentials, my local account was tied to the Windows account, but because I cancelled the process partway through, something went wrong and I cannot log in. A few questions: 1) How do I log in with my windows account credentials? Should LOCALMACHINENAME\username, which was my previous login method, still work for the Windows account? When I booted to safemode it prompted me with WindowsAccount\myemailaddress, which allowed me to login there, but the regular login doesn't accept the '@' symbol. 2) Is there any way to make that account local-only again? I can't find any way of doing it. 3) I managed to enable the local administrator account and get back into the box; failing all else, is there a quick way to migrate my old profile over to a new user?

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  • Users Password does not reset after successful login at the console but works fine with SSH

    - by jnbbender
    The title says it all. I have my unsuccessful login attempts set to three. I purposefully fail logging in 2x, then when I SSH into the box successfully the 3rd time my count drops back to zero; exactly what should happen. But at the console I get failed login attempts EVEN for my successful login attempts. I am using RHEL 5.6 and no I am not able to upgrade. Here is my system-auth file: auth required pam_env.so auth required pam_tally.so onerr=fail deny=3 per_user auth sufficient pam_unix.so nullok try_first_pass auth requisite pam_succeed_if.so uid >= 500 quiet auth required pam_deny.so account required pam_unix.so account required pam_tally.so account sufficient pam_succeed_if.so uid < 500 quiet account required pam_permit.so password requisite pam_cracklib.so try_first_pass retry=3 password sufficient pam_unix.so md5 shadow nullok try_first_pass use_authtok password required pam_deny.so session optional pam_keyinit.co revoke session required pam_limits.so session [success=1 default=ignore] pam_succeed_if.so service in crond quiet use_uid session required pam_unix.so I have tried adding reset after and in place of per_user in the auth required pam_tally.so field. Nothing seems to work and I don't know why SSH is working just fine. Any ideas?

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  • Fb.Login() does not popup OAuth Dialog?

    - by cnz81
    I'm study fb api recently and I use fb api to do login, however, when I use Fb.Login() method, and scope the permission that I needed. I found the problem that when I use account ( this account is also the fb app admin ) to login, everything is be work including login dialog and oauth dialog , but when I use another account ( General account ) the login dialog is work but OAuth Dialog is not work . I've tried another account ( General account ), it had the same situation, Only when I use the account which is also the fb app owner account would be work. Any Ideas ? Below is the code... FB.login(function (response) { if (response.authResponse) { alert('success !') ; } else { alert(' faild ! '); } }, { scope: "publish_actions" });

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  • 13.10 Saucy login issues; black screen, loop, and freeze

    - by user135598
    Once upgraded to I 13.10 I was not able to get past the login screen. I had the black screen. Also; I can not log on with low graphics mode from recovery either. It makes no difference if I try default graphics driver or not. Then after running sudo install -f from recovery root prompt I got a login loop. I have purged fglrx, fglrx-legacy, and nvidia-current. I updated my repository with xorg-edgers and reinstalled nvidia-current. Now it semi-freezes at the login screen when I try to log on as my normal user. I say 'semi' because I can still use my mouse to click on the upper right hand Ubuntu logo and Shut Down or Restart the PC. I still cannot log on with my user name, but I can through the Guest login. While logged in as Guest I added a new user account with administrative privileges. I CAN log into this account without problem and from here am able to see that my .dmrc file in my original account reads: [Desktop] Session=XBMC I have changed 'Session=XBMC' to 'Session=ubuntu' and rebooted, but to no avail. The file resets itself and makes a backup of my changes. Any help would be greatly appreciated.

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  • Version control a content management system?

    - by Mike
    I have the following directory structure in the CMS application we have written: /application /modules /cms /filemanager /block /pages /sitemap /youtube /rss /skin /backend /default /css /js /images /frontend /default /css /js /images Application contains code specific to the current CMS implementation, i.e code for this specific cms. Modules contain reusable portions of code that we share across projects, such as libraries to work with youtube or rss feeds. We include these as git submodules, so that we can update the module in any website and push the changes back across all other projects. It makes it really easy to apply a change to our code and distribute it. We wanted to turn the CMS into a module so we get the same benefit - we can run the entire project under source control, then update the cms as required through a git-submodule. We have run into a problem however: the cms requires javascript/images/css in order for it to work correctly. Things we have thought about: We could create 2 submodules, one for cms-skin and one for cms, but this means you cannot "git pull" one version without having some idea of which versions of skin work with which versions of cms. i.e version 1.2.2 CMS might have issues with 1.0.3 CMS-Skin We could add the skin to the cms module but this has the following problems: Skin should be available on the document root, module code shouldn't be, and if it is it should probably be secured via .htaccess It doesn't seem to make any sense bundling assets with php code We could create a symlink between /skin/backend/ to go to /modules/cms/skin but does this cause any security problems, and do we want to require something like a symlink for the application to work? We could create a hook for git or a shell script that copies files from modules/cms/skin to skin/backend when an update occurs, but this means we lose the ability to edit CMS core files in a project then push them back How is this typically done in large scale cms's? How is it possible to get the source code for a cms under version control, work on the application for a client, then update the sourcecode as releases and given by the vendor? How do applications like Magento or Drupal do this?

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