Filter string in C
- by Paul Tarjan
How can I filter a string in c? I want to remove anything that isn't [a-z0-9_].
int main(int argc, char ** argv) {
char* name = argv[1];
// remove anything that isn't [a-z0-9_]
printf("%s", name);
}
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Search found 36490 results on 1460 pages for 'string replacement'.
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Best way to code this, string to map conversion in Groovy
- by Daxon
I have a string like def data = "session=234567893egshdjchasd&userId=12345673456&timeOut=1800000" I want to convert it to a map ["session", 234567893egshdjchasd] ["userId", 12345673456] ["timeout", 1800000] This is the current way I am doing it, def map = [:] data.splitEachLine("&"){ it.each{ x -> def object = x.split("=") map.put(object[0], object[1]) } } It works, but is there a more efficient way?Read the article
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increasing string size through loop
- by calccrypto
what's a simple way to increase the length of a string given an arbitrary integer x? like 'a' goes to 'z' and then goes to 'aa' to 'zz' to 'aaa', etc.Read the article
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String Parsing in C#
- by Betamoo
What is the most efficient way to parse a C# string in the form of "(params (abc 1.3)(sdc 2.0)....)" into a struct in the form struct Params { double abc,sdc....; } Thanks EDIT The structure always have the same parameters (number and names).. but the order is not granted..Read the article
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python - remove string from words in an array
- by tekknolagi
#!/usr/bin/python #this looks for words in dictionary that begin with 'in' and the suffix is a real word wordlist = [line.strip() for line in open('/usr/share/dict/words')] newlist = [] for word in wordlist: if word.startswith("in"): newlist.append(word) for word in newlist: word = word.split('in') print newlist how would I get the program to remove the string "in" from all the words that it starts with? right now it does not workRead the article
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finding and returning a string with a specified prefix
- by tipu
I am close but I am not sure what to do with the restuling match object. If I do p = re.search('[/@.* /]', str) I'll get any words that start with @ and end up with a space. This is what I want. However this returns a Match object that I dont' know what to do with. What's the most computationally efficient way of finding and returning a string which is prefixed with a @? For example, "Hi there @guy" After doing the proper calculations, I would be returned guyRead the article
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Split a long JSON string into lines in Ruby
- by David J.
First, the background: I'm writing a Ruby app that uses SendGrid to send mass emails. SendGrid uses a custom email header (in JSON format) to set recipients, values to substitute, etc. SendGrid's documentation recommends splitting up the header so that the lines are shorter than 1,000 bytes. My question, then, is this: given a long JSON string, how can I split it into lines < 1,000 so that lines are split at appropriate places (i.e., after a comma) rather than in the middle of a word? This is probably unnecessary, but here's an example of the sort of string I'd like to split: X-SMTPAPI: {"sub": {"pet": ["dog", "cat"]}, "to": ["[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]", "[email protected]"]} Thanks in advance for any help you can provide!Read the article
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String.IsNullOrWhiteSpace
- by Scott Dorman
An empty string is different than an unassigned string variable (which is null), and is a string containing no characters between the quotes (""). The .NET Framework provides String.Empty to represent an empty string, and there is no practical difference between ("") and String.Empty. One of the most common string comparisons to perform is to determine if a string variable is equal to an empty string. The fastest and simplest way to determine if a string is empty is to test if the Length property is equal to 0. However, since strings are reference types it is possible for a string variable to be null, which would result in a runtime error when you tried to access the Length property. Since testing to determine if a string is empty is such a common occurrence, the .NET Framework provides the static method String.IsNullOrEmpty method: public static bool IsNullOrEmpty(string value) { if (value != null) { return (value.Length == 0); } return true; } It is also very common to determine if a string is empty and contains more than just whitespace characters. For example, String.IsNullOrEmpty(" ") would return false, since this string is actually made up of three whitespace characters. In some cases, this may be acceptable, but in many others it is not. TO help simplify testing this scenario, the .NET Framework 4 introduces the String.IsNullOrWhiteSpace method: public static bool IsNullOrWhiteSpace(string value) { if (value != null) { for (int i = 0; i < value.Length; i++) { if (!char.IsWhiteSpace(value[i])) { return false; } } } return true; } Using either String.IsNullOrEmpty or String.IsNullOrWhiteSpace helps ensure correctness, readability, and consistency, so they should be used in all situations where you need to determine if a string is null, empty, or contains only whitespace characters. Technorati Tags: .NET,C# 4Read the article
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Responsive logo (image replacement) in html5boilerplate
- by Barbara
I'm using the responsive version of html5 boilerplate via initializr.com. My site uses a custom logo so i added the .ir class to h1 .ir { background-color: transparent; border: 0; overflow: hidden; *text-indent: -9999px; } like this <h1 class="title ir">h1.title</h1> The documentation says Add the .ir class to any element you are applying image-replacement to. When replacing an element's content with an image, make sure to also set a specific background-image: url(pathtoimage.png);, width, and height so that your replacement image appears. So I added to the code these lines .ir { background-image: url(http://i.imgur.com/yYnyJ.jpg); background-size: 100% auto; width:450px; height:450px } The problem are the specific width and height. I can't get rid of them but the logo is not responsive this way. Ideas? Here's the fiddle. http://jsfiddle.net/qeW3e/Read the article
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How do I concatenate 2 strings in NSIS
- by Apoc
How do I concatenate 2 strings in NSIS?Read the article
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how to create a string literal as a function argument via string concatenation in c
- by Reed Debaets
I need to pass a string literal to a function myfunction("arg1" CONSTANT "arg1"); now part of that constructed string literal needs to be a function return stmp = createString(); myfunction("arg1" stmp "arg2"); is there any way to do this in one line? myfunction("arg1" createString() "arg2"); //doesn't work ... why not? what instead? NOTE: C only please.Read the article
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Transforming a string to a valid PDO_MYSQL DSN
- by Alix Axel
What is the most concise way to transform a string in the following format: mysql:[/[/]][user[:pass]@]host[:port]/db[/] Into a usuable PDO connection/instance (using the PDO_MYSQL DSN), some possible examples: $conn = new PDO('mysql:host=host;dbname=db'); $conn = new PDO('mysql:host=host;port=3307;dbname=db'); $conn = new PDO('mysql:host=host;port=3307;dbname=db', 'user'); $conn = new PDO('mysql:host=host;port=3307;dbname=db', 'user', 'pass'); I've been trying some regular expressions (preg_[match|split|replace]) but they either don't work or are too complex, my gut tells me this is not the way to go but nothing else comes to my mind. Any suggestions?Read the article
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PHP String tokenizer not working correctly
- by asdadas
I have no clue why strtok decided to break on me. Here is my code. I am tokenizing a string by dollar symbol $. echo 'Tokenizing this by $: ',$aliases,PHP_EOL; if(strlen($aliases) > 0) { //aliases check $token = strtok($aliases, '$'); while($token != NULL) { echo 'Found a token: ',$token,PHP_EOL; if(!isGoodLookup($token)) { echo 'ERROR: Invalid alias found.',PHP_EOL; stop($db); } $goodAliasesList[] = $token; $token = strtok('$'); } if($token == NULL) echo 'Found null token, moving on',PHP_EOL; } And this is my output: Tokenizing this by $: getaways$aaa Found a token: getaways Found null token, moving on str tok is not supposed to do this!! where is my aaa token!!Read the article
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Finding multiple values in a string Jquery / Javascript
- by user257503
I have a three strings of categories "SharePoint,Azure,IT"; "BizTalk,Finance"; "SharePoint,Finance"; I need to find a way to check if a string contains for example "SharePoint" and "IT", or "BizTalk" and "Finance". The tests are individual strings themselces. How would i loop through all the category strings (1 - 3) and only return the ones which have ALL instances of the souce. i have tried the following function doesExist(source, filterArray) { var substr = filterArray.split(" "); jQuery.each(substr, function() { var filterTest = this; if(source.indexOf(filterTest) != -1 ) { alert("true"); return true; }else { alert("false"); return false; } }); } with little success...the code above checks one at a time rather than both so the results returned are incorrect. Any help would be great. Thanks Chris UPDATE: here is a link to a work in progress version..http://www.invisiblewebdesign.co.uk/temp/filter/#Read the article
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Search for string allowing for one mismatches in any location of the string, Python
- by Vincent
I am working with DNA sequences of length 25 (see examples below). I have a list of 230,000 and need to look for each sequence in the entire genome (toxoplasma gondii parasite) I am not sure how large the genome is but much more that 230,000 sequences. I need to look for each of my sequences of 25 characters example(AGCCTCCCATGATTGAACAGATCAT). The genome is formatted as a continuous string ie (CATGGGAGGCTTGCGGAGCCTGAGGGCGGAGCCTGAGGTGGGAGGCTTGCGGAGTGCGGAGCCTGAGCCTGAGGGCGGAGCCTGAGGTGGGAGGCTT.........) I don't care where or how many times it is found, just yes or no. This is simple I think, str.find(AGCCTCCCATGATTGAACAGATCAT) But I also what to find a close match defined as wrong(mismatched) at any location but only 1 location and record the location in the sequnce. I am not sure how do do this. The only thing I can think of is using a wildcard and performing the search with a wildcard in each position. ie search 25 times. For example AGCCTCCCATGATTGAACAGATCAT AGCCTCCCATGATAGAACAGATCAT close match with a miss-match at position 13 Speed is not a big issue I am only doing it 3 times. i hope but it would be nice it was fast. The are programs that do this find matches and partial matches but I am looking for a type of partial match that is not available with these applications. Here is a similar post for pearl but they are only comparing sequnces not searching a continuous string Related postRead the article
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C# collection/string .Contains vs collection/string.IndexOf
- by Daniel
Is there a reason to use .Contains on a string/list instead of .IndexOf? Most code that I would write using .Contains would shortly after need the index of the item and therefore would have to do both statements. But why not both in one? if ((index = blah.IndexOf(something) = 0) // i know that Contains is true and i also have the indexRead the article
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Making a string out of a string and an integer in Python
- by Waterfox
I get this error when trying to take an integer and prepend "b" to it, converting it into a string: File "program.py", line 19, in getname name = "b" + num TypeError: Can't convert 'int' object to str implicitly That's related to this function: num = random.randint(1,25) name = "b" + numRead the article
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Findind string in another string in PHP
- by Mamadou
Hi everybody I got a string like this : $str1 = "mod 1 + mode 2 + comp 1 + toto" I would like to test even " mod 1" is in $str1. I used strpos but this function dosen't help Pliz can anyone give an idea to fix this problem thank u.Read the article
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Finding substring of a word found in joining a string from another string
- by 2er0
Given a list of words, L, that are all the same length, and a string, S, find the starting position of the substring of S that is a concatenation of each word in L exactly once and without any intervening characters. This substring will occur exactly once in S. Example: L: "fooo", "barr", "wing", "ding", "wing" S: "lingmindraboofooowingdingbarrwingmonkeypoundcake" Word found in joining L and also found in S: "fooowingdingbarrwing" Answer: 13 L: "mon", "key" S: "monkey Word found in joining L and also found in S: "monkey Answer: 0 L: "a", "b", "c", "d", "e" S: "abcdfecdba" Word found in joining L and also found in S: "ecdba Answer: 5Read the article
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Ruby string compare regardless of string case
- by Steven
Hi I need to check for "Apple" = "Apple" TRUE "Apple" = "APPLE" TRUE "Apple" = "Apple1" FALSE in ruby I need a string comparison but for the check to not be case sensitive. thksRead the article
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Remove characters after specific character in string, then remove substring?
- by sah302
I feel kind of dumb posting this when this seems kind of simple and there are tons of questions on strings/characters/regex, but I couldn't find quite what I needed (except in another language: http://stackoverflow.com/questions/2176544/remove-all-text-after-certain-point). I've got the following code: [Test] public void stringManipulation() { String filename = "testpage.aspx"; String currentFullUrl = "http://localhost:2000/somefolder/myrep/test.aspx?q=qvalue"; String fullUrlWithoutQueryString = currentFullUrl.Replace("?.*", ""); String urlWithoutPageName = fullUrlWithoutQueryString.Remove(fullUrlWithoutQueryString.Length - filename.Length); String expected = "http://localhost:2000/somefolder/myrep/"; String actual = urlWithoutPageName; Assert.AreEqual(expected, actual); } I tried the solution in the question above (hoping the syntax would be the same!) but nope. I want to first remove the queryString which could be any variable length, then remove the page name, which again could be any length. How can I get the remove the query string from the full URL such that this test passes?Read the article
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How to extract specific variables from a string?
- by David
Hi, let's say i have the following: $vars="name=david&age=26&sport=soccer&birth=1984"; I want to turn this into real php variables but not everything. By example, the functions that i need : $thename=getvar($vars,"name"); $theage=getvar($vars,"age"); $newvars=cleanup($vars,"name,age"); // Output $vars="name=david&age=26" How can i get only the variables that i need . And how i clean up the $vars from the other variables if possible? ThanksRead the article
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String formatting error
- by wrongusername
Using the code print('{0} is not'.format('That that is not')) in Python 3.1.1, I get the following error: AttributeError: 'str' object has no attribute 'format' when I delete the line Netbeans automatically inserted at the beginning: from distutils.command.bdist_dumb import format which itself causes an error of ImportError: cannot import name format What am I doing wrong here?Read the article
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How to replace round bracket tag in javascript string
- by tomaszs
I have trouble with changing round bracket tag in Javascript. I try to do this: var K = 1; var Text = "This a value for letter K: {ValueOfLetterK}"; Text = Text.replace("{ValueOfLetterK}", K); and after that I get: Text = "This a value for letter K: {ValueOfLetterK}" What can be done to make this work? When I remove round brackets it works fine.Read the article
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Use FlurryAgent.onEvent(String eventId, Map<String, String> parameters)
- by Shalini Singh
hello, Please anybody tell how to use FlurryAgent.onEvent(String eventId, Map parameters) in an android activity to track events with flurry ?Read the article
