Search Results

Search found 3076 results on 124 pages for 'beginner'.

Page 60/124 | < Previous Page | 56 57 58 59 60 61 62 63 64 65 66 67  | Next Page >

  • Java queue and multi-dimension array

    - by javaLearner.java
    First of all, this is my code (just started learning java): Queue<String> qe = new LinkedList<String>(); qe.add("b"); qe.add("a"); qe.add("c"); qe.add("d"); qe.add("e"); My question: Is it possible to add element to the queue with two values, like: qe.add("a","1"); // where 1 is integer So, that I know element "a" have value 1. If I want to add a number let say "2" to element a, I will have like a = 3. If this cant be done, what else in java classes that can handle this? I tried to use multi-dimention array, but its kinda hard to do the queue, like pop, push etc. (Maybe I am wrong) How to call specific element in the queue? Like, call element a, to check its value. [Note] Please don't give me links that ask me to read java docs. I was reading, and I still dont get it. The reason why I ask here is because, I know I can find the answer faster and easier.

    Read the article

  • iPhone Developer account with someone elses credit card

    - by HappYCrappY
    Hi I wanted to enroll in Apples iPhone developer program the problem is I myself don't own a credit card is it Ok if I use some one else's credit card to sign up... I mean will Apple pay the guy whose credit card I have used or can I specify my Account details for any future transactions & just use this credit card for paying Apple. (& yes I cannot get a credit card, I am currently jobless never ever had a credit card before in my life & credit card companies are very skeptical to give me one.) Thank you

    Read the article

  • memset on array of structures in C++

    - by garry
    I have another memset question. It appears as if the code I am editing may have some issues (or it's not done the same way in different files) A::LRM las[9]; //A and LRM are both structures with BOOLS and INTS memset(&las, 0, sizeof(las)); typedef Sec SecArray[16]; SecArray rad_array; memset(rad_array, 0, sizeof(SecArray)); The second example appears to be correct because rad_array is the same as the first position in the array. Then the sizeof(SecArray)) would make sense. The first one doesn't seem correct to me. All structs are just BOOLs and INTS nothing dynamic in them. My understanding from my other post about memset was that it followed this format. memset("pointer to object", "what to set it to", "size of object") Can anyone tell me what exactly is going on here if I am incorrect with my theory.

    Read the article

  • django accessing class variables in a view

    - by dana
    hello, i want to make a notification function, and i need fields from 2 different models. how can i access those fields? in my notification view i wrote this data = Notices.objects.filter(last_login<date_follow) where last_login belongs to the model class User , and date_follow to Follow but it is not a proper and correct way of accessing those variables. How can i access them? I need to compare the two dates for realising the notifications that one did not see since his last login. Thanks!

    Read the article

  • Hex to bin after logical operations

    - by user355926
    I want: 111 || 100 ---> 111, not 1 100 && 100 ---> 100, not 1 101 && 010 ---> 000, not 0 Broken code #include <stdio.h> main(void){ string hexa = 0xff; strig hexa2 = 0xf1; // CONVERT TO INT??? cast int hexa3 = hexa || hexa2; int hexa4 = hexa && hexa2; puts(hexa3); puts(hexa4); }

    Read the article

  • Perl : In splice() type of arg1 must be array, cannot be scalar dereference. How to fix?

    - by Michael Mao
    I am trying to comprehend the reference/dereference system in Perl. What I am trying to do is to remove an element by using reference: my $ref= \@{$collection{$_[0]}}; # delete($$ref[$i]); # delete works, I've tested that already splice($$ref, $i, 1); # this wouldn't do. I first tried the delete() subroutine, it works; however, it doesn't shift the index after the removed elements forward by 1, so I cannot continue working on other stuff. I then Googled and found the splice() subroutine which does delete and shift in one go. But the error feedback tells me that "Type of arg 1 to splice must be array (not scalar dereference)..." I then tried something like this: splice(@{$$ref}, $i, 1); That resulted in another error like this: "Not a SCALAR reference at...(pointing at that line)" So I am a bit puzzled, how could I handle this issue? I prefer not using any CPAN or additional library for the solution, if possible.

    Read the article

  • Java: one-liner to list Dirs in a directory?

    - by Heoa
    One-Liner to list TXT-files. import java.io.File; import java.io.FilenameFilter; ... files = dir.listFiles(new FilenameFilter() { public boolean accept(File dir, String name) { return name.toLowerCase().endsWith(".txt"); } } ); Source. Is there an one-liner to list dirs in a dir?

    Read the article

  • display format for gridview

    - by peter
    I have a grid named 'GridView1' contains two columns 'Date' and 'Session Deatils' i am displaying like this way only <asp:GridView ID="GridView1" OnRowCommand="ScheduleGridView_RowCommand" runat="server" AutoGenerateColumns="False" Height="60px" Style="text-align: center" Width="869px" EnableViewState="False"> <Columns> <asp:BoundField HeaderText="Date" DataField="Date"><HeaderStyle Width="80px" /></asp:BoundField> <asp:BoundField DataField="" HeaderText="Session Detais" /> </Columns> But here i need to display 3 column sections downside Session details without any column borders for each dates,,how can i achive like this wasy Date SessionDetails 06-04-2010 Time-(value from database) Topic-(value from database) Head-(value from database) ------- ------------------ ------------------- ----------------------

    Read the article

  • Writing a file shredder in python or ruby?

    - by pmilb21
    In the effort to learn python and/or ruby, I was wondering how a file shredder would be implemented? I would like it to take in a file as an argument and then employ an algorithm to make that file unrecoverable. Would possibly add the support for multiple files or even whole directories later.

    Read the article

  • jquery specific show buttons on hover

    - by bob
    I have an application creating a bunch of divs through a loop. Each div has the class "product" so it looks like <div class="product"> !.....stuff here ....! <div class="show_on_hover">...buttons here... </div> </div> so there are about 12 of these same divs per page. I would like to hover over a specific one and show the specific "show_on_hover" div which is initially set to display:none. $('.product').hover(function() { $(.show_on_hover).show(); }, function () { $(.show_on_hover).hide(); } ); That is what I have so far but it will show ALL of the .show_on_hovers on the page so I am wondering how to get only the specific one you have moused over to show. This effect is seen on youtube when you mouseover any of the comments, and some comment tools pop up. Thanks!

    Read the article

  • [Python] Tips for making a fraction calculator code more optimized (faster and using less memory)

    - by Logic Named Joe
    Hello Everyone, Basicly, what I need for the program to do is to act a as simple fraction calculator (for addition, subtraction, multiplication and division) for the a single line of input, for example: -input: 1/7 + 3/5 -output: 26/35 My initial code: import sys def euclid(numA, numB): while numB != 0: numRem = numA % numB numA = numB numB = numRem return numA for wejscie in sys.stdin: wyjscie = wejscie.split(' ') a, b = [int(x) for x in wyjscie[0].split("/")] c, d = [int(x) for x in wyjscie[2].split("/")] if wyjscie[1] == '+': licz = a * d + b * c mian= b * d nwd = euclid(licz, mian) konA = licz/nwd konB = mian/nwd wynik = str(konA) + '/' + str(konB) print(wynik) elif wyjscie[1] == '-': licz= a * d - b * c mian= b * d nwd = euclid(licz, mian) konA = licz/nwd konB = mian/nwd wynik = str(konA) + '/' + str(konB) print(wynik) elif wyjscie[1] == '*': licz= a * c mian= b * d nwd = euclid(licz, mian) konA = licz/nwd konB = mian/nwd wynik = str(konA) + '/' + str(konB) print(wynik) else: licz= a * d mian= b * c nwd = euclid(licz, mian) konA = licz/nwd konB = mian/nwd wynik = str(konA) + '/' + str(konB) print(wynik) Which I reduced to: import sys def euclid(numA, numB): while numB != 0: numRem = numA % numB numA = numB numB = numRem return numA for wejscie in sys.stdin: wyjscie = wejscie.split(' ') a, b = [int(x) for x in wyjscie[0].split("/")] c, d = [int(x) for x in wyjscie[2].split("/")] if wyjscie[1] == '+': print("/".join([str((a * d + b * c)/euclid(a * d + b * c, b * d)),str((b * d)/euclid(a * d + b * c, b * d))])) elif wyjscie[1] == '-': print("/".join([str((a * d - b * c)/euclid(a * d - b * c, b * d)),str((b * d)/euclid(a * d - b * c, b * d))])) elif wyjscie[1] == '*': print("/".join([str((a * c)/euclid(a * c, b * d)),str((b * d)/euclid(a * c, b * d))])) else: print("/".join([str((a * d)/euclid(a * d, b * c)),str((b * c)/euclid(a * d, b * c))])) Any advice on how to improve this futher is welcome. Edit: one more thing that I forgot to mention - the code can not make use of any libraries apart from sys.

    Read the article

  • In Python, how do I search a flat file for the closest match to a particular numeric value?

    - by kaushik
    have file data of format 3.343445 1 3.54564 1 4.345535 1 2.453454 1 and so on upto 1000 lines and i have number given such as a=2.44443 for the given file i need to find the row number of the numbers in file which is most close to the given number "a" how can i do this i am presently doing by loading whole file into list and comparing each element and finding the closest one any other better faster method? my code:i need to ru this for different file each time around 20000 times so want a fast method p=os.path.join("c:/begpython/wavnk/",str(str(str(save_a[1]).replace('phone','text'))+'.pm')) x=open(p , 'r') for i in range(6): x.readline() j=0 o=[] for line in x: oj=str(str(line).rstrip('\n')).split(' ') o=o+[oj] j=j+1 temp=long(1232332) end_time=save_a[4] for i in range((j-1)): diff=float(o[i][0])-float(end_time) if diff<0: diff=diff*(-1) if temp>diff: temp=diff pm_row=i

    Read the article

< Previous Page | 56 57 58 59 60 61 62 63 64 65 66 67  | Next Page >