Search Results

Search found 49860 results on 1995 pages for 'reference type'.

Page 62/1995 | < Previous Page | 58 59 60 61 62 63 64 65 66 67 68 69  | Next Page >

  • How to set up my belongs_to and has_many reference

    - by dagda1
    Hi, I have an ExpenseType object that I have created with the following migration: class CreateExpenseTypes < ActiveRecord::Migration def self.up create_table :expense_types do |t| t.column :name, :string, :null => false t.timestamps end end I can see the table name is the pluralised expense_types. My question is, how do I reference this type in a belongs_to relationship? Is it: belongs_to :expensetype or is it belongs_to :expense_type I do not seem able to set it up correctly. Cheers

    Read the article

  • Error loading SQL_VARIANT data type using Python

    - by Brett D
    I am using Python and SQLAlchemy to query a database that I did not create. I have run into a problem querying a table that contains the SQL_VARIANT data type. I get the error: sqlalchemy.exc.DBAPIError: (Error) ('ODBC data type -150 is not supported. Cannot read column Value.', 'HY000') I confirmed with the database creator that the "Value" column is of type SQL_VARIANT. Does anyone know a way to load this data type using Python? I am currently using mssql with pyodbc. Thank you for any help you can offer! Versions: Python 2.7, SQLAlchemy 0.7.8

    Read the article

  • WPF reference style in resource dictionary and use triggers

    - by Taylor
    I have a style defined in a resource dictionary that applies to all ComboBox controls. Within the ComboBox control, I reference the style like so: Style="{DynamicResource MyComboBoxStyle}" This works ok. I want to be able to add some triggers to some of the ComboBox controls. What is a good way to use the style referenced as a dynamic resource yet still be able to add triggers to some of the ComboBox controls?

    Read the article

  • BLL returning the right Type of an instance

    - by Younes
    I have a class "Artikel" and there i write some Business Logic. I also have a class "tArtikel" which is a type. In my class "Artikel" I work with "tArtikel" and returns are of that type. Now when i instantiate an "Artikel" i want it to be of type "tArtikel", so what i tried in my code is: public tArtikel Artikel() { tArtikel artikel = new tArtikel(); } Which results in: "'Artikel' member names cannot be the same as their enclosing type". How would i set this up correctly?

    Read the article

  • Problem compiling c++ in CodeGear

    - by Carlos
    I have written a C++ program for a University assignment. I used Netbeans 6.8 running on my Mac and the code runs smoothly, no warnings, errors or problems/bugs. However when compiling and running on a Windows computer using CodeGear RAD Studio 2009 (C++ Builder) am getting several errors. [BCC32 Error] main.cpp(51): E2094 'operator<<' not implemented in type 'ostream' for arguments of type 'string' [BCC32 Error] main.cpp(62): E2093 'operator==' not implemented in type 'string' for arguments of the same type [BCC32 Error] main.cpp(67): E2093 'operator==' not implemented in type 'string' for arguments of the same type [BCC32 Error] main.cpp(112): E2093 'operator==' not implemented in type 'string' for arguments of the same type [BCC32 Error] main.cpp(121): E2094 'operator<<' not implemented in type 'ostream' for arguments of type 'string' [BCC32 Error] main.cpp(130): E2093 'operator==' not implemented in type 'string' for arguments of the same type [BCC32 Error] main.cpp(133): E2094 'operator<<' not implemented in type 'ostream' for arguments of type 'string' [BCC32 Error] main.cpp(139): E2094 'operator<<' not implemented in type 'ostream' for arguments of type 'string' [BCC32 Error] main.cpp(153): E2094 'operator<<' not implemented in type 'fstream' for arguments of type 'string' [BCC32 Error] main.cpp(199): E2094 'operator>>' not implemented in type 'fstream' for arguments of type 'string' [BCC32 Error] main.cpp(219): E2094 'operator>>' not implemented in type 'istream' for arguments of type 'string' [BCC32 Error] main.cpp(231): E2094 'operator>>' not implemented in type 'istream' for arguments of type 'string' [BCC32 Error] main.cpp(240): E2094 'operator>>' not implemented in type 'istream' for arguments of type 'string' [BCC32 Error] main.cpp(262): E2094 'operator>>' not implemented in type 'istream' for arguments of type 'string' [BCC32 Error] main.cpp(264): E2094 'operator>>' not implemented in type 'istream' for arguments of type 'string' These are the header files am using #include <iostream> #include <fstream> #include <cmath> #include <stdio> #include <windows> //I added this one just to check and still does not work (I didnt have it on Netbeans/Mac) using namespace std; Any ideas what is producing the errors and how can I fix it?

    Read the article

  • To Reference A Generic Method With A Lambda Expression

    - by SDReyes
    It is possible to reference a generic method using a Lambda Expression Object? For example, having: TheObject: public abstract class LambdaExpression : Expression TheMethod (an extension method of LINQ): public static TSource Last<TSource>( this IEnumerable<TSource> source ) I'm trying to create an instance of TheObject, that references to TheMethod. How do you do such thing?

    Read the article

  • std::map default value for build-in type

    - by Qifa Zhao
    Recently, I was confused by the std::map operator[] function. In the MSDN library, it says: "If the argument key value is not found, then it is inserted along with the default value of the data type." I tryed to search much more exactly explanation for this issue. For example here: std::map default value In this page, Michael Anderson said that "the default value is constructed by the default constructor(zero parameter constructor)". Now my quest comes to this:"what the default value for the build-in type?". Was it compiler related? Or is there a standard for this issue by the c++ stardard committee? I did a test on visual studio 2008 for the "int" type, and found the "int" type is construted with the value 0.

    Read the article

  • F# return type coercion

    - by Alex
    Hi, In F# I have a function that returns System.Linq.Expression instances: and System.Object with member this.ToExpression() = match this with | :? System.Int32 -> Expression.Constant(this) :> Expression | :? System.Boolean -> Expression.Constant(this) :> Expression | :? Tml.Runtime.Seq as s -> s.ToExpression() | _ -> failwith "bad expression" If I omit the type coercions on the return values F# will infer the return type of the function to ConstantExpression. My first thought was to explicitly mark the return type as being : #Expression, but that didn't work. Is there a more elegant way of doing this that doesn't involve manually casting return types to the most generic type? Thanks.

    Read the article

  • Make Visual Studios "Add Service Reference" Feature use an existing Class

    - by gencha
    When I add a service reference to my Visual Studio 2010 C# project, a new class for one of the types defined in the WSDL will be generated. A de-facto equivalent definition of that type already exists in our solution in a different assembly. When adding the SoapTypeAttribute to the existing class and replacing the references to the generated class in the generated code, everything runs perfectly and as expected. How would I tell Visual Studio to use the existing class in the generated code?

    Read the article

  • jQuery: get the file name selected from <input type="file" />

    - by ConNen
    This code should work in IE (don't even test it in Firefox), but it doesn't. What I want is to display the name of the attached file. Any help? <html> <head> <title>example</title> <script type="text/javascript" src="../js/jquery.js"></script> <script type="text/javascript"> $(document).ready( function(){ $("#attach").after("<input id='fakeAttach' type='button' value='attach a file' />"); $("#fakeAttach").click(function() { $("#attach").click(); $("#maxSize").after("<div id='temporary'><span id='attachedFile'></span><input id='remove' type='button' value='remove' /></div>"); $('#attach').change(function(){ $("#fakeAttach").attr("disabled","disabled"); $("#attachedFile").html($(this).val()); }); $("#remove").click(function(e){ e.preventDefault(); $("#attach").replaceWith($("#attach").clone()); $("#fakeAttach").attr("disabled",""); $("#temporary").remove(); }); }) }); </script> </head> <body> <input id="attach" type="file" /><span id="maxSize">(less than 1MB)</span> </body> </html>

    Read the article

  • MYSQL join - reference external field from nested select?

    - by PHP thinker
    Is it allowed to reference external field from nested select? E.g. SELECT FROM ext1 LEFT JOIN (SELECT * FROM int2 WHERE int2.id = ext1.some_id ) as x ON 1=1 in this case, this is referencing ext1.some_id in nested select. I am getting errors in this case that field ext1.some_id is unknow. Is it possible? Is there some other way?

    Read the article

  • Haskell Type error

    - by Jon
    I am getting a Couldn't match expected type error on this code and am not sure why. Would appreciate it if someone could point me in the right direction as to fixing it. import qualified Data.ByteString.Lazy as S import Data.Binary.Get import Data.Word getBinary :: Get Word16 getBinary = do a <- getWord16be "Test.class" return (a) main :: IO () main = do contents <- S.getContents print getBinary contents Specifically it cannot match expected type 'S.ByteString - IO ()' to inferred type 'IO ()'

    Read the article

  • Web reference problem on WCF

    - by kaivalya
    I have a WCF service which I am able to connect to from my web application and get data. I now added a web reference to this wcf project to a wsdl file that a shipping company provides. Intention is to get shipping quotes.. I am able to access the objects that are generated from this wsdl file but when I call service.Authenticate("DEMO"); method almost nothing happens. I debug and see the debugger continue to the next lines but there is no change on service parameters and service.isauthorized is null.. Can you lead me to how I should debug this further and things I should check, or if there are additional steps that I need to ensure to have a web reference working on wcf app Thanks using System; using System.Collections.Generic; using System.Linq; using System.Runtime.Serialization; using System.ServiceModel; using System.Text; using ShippingCalculator.com.freight.api; namespace ShippingCalculator { public class ShippingService : IShippingService { freight_service service = new freight_service(); public string GetData(int value) { service.setConnectionType(".net"); service.Authenticate("DEMO"); OriginRequest origin = new OriginRequest(); origin.zip = "60101"; DestinationRequest destination = new DestinationRequest(); destination.zip = "10001"; PackageRequest package = new PackageRequest(); package.weight = "10"; ShipmentInfoRequest shipmentInfo = new ShipmentInfoRequest(); shipmentInfo.ship_date = DateTime.Now.AddDays(5); service.setOrigin(origin); service.setDestination(destination); service.setPackage(package); service.setShipmentInfo(shipmentInfo); Quote quote = service.getQuote(); return string.Format("Quote Number: {0}<br /> ", quote.QuoteNumber); } } } using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.Mvc; using ShippingTestApp.ShippingServiceReference; namespace ShippingTestApp.Controllers { [HandleError] public class HomeController : Controller { public ActionResult Index() { ShippingServiceClient shipClient = new ShippingServiceClient(); shipClient.GetData(0); ViewData["Message"] = shipClient.GetData(0); return View(); } } }

    Read the article

  • Samsung Galaxy S2 ROM compilation error?

    - by Bashir
    I'm running Ubuntu 12.04 X64 and have installed all the tools(Toolchain: arm-2010q1 and Samsung Galaxy S2 source as given Here) to compile a ROM. When I run make Command I'm getting this error: kernel/built-in.o: In function `cpufreq_table_show': cpu_pm.c:(.text+0x39b64): undefined reference to `cpufreq_frequency_get_table' kernel/built-in.o: In function `cpufreq_max_limit_store': cpu_pm.c:(.text+0x39cd4): undefined reference to `omap_cpufreq_max_limit' cpu_pm.c:(.text+0x39d04): undefined reference to `omap_cpufreq_max_limit_free' cpu_pm.c:(.text+0x39d24): undefined reference to `omap_cpufreq_max_limit_free' kernel/built-in.o: In function `cpufreq_min_limit_store': cpu_pm.c:(.text+0x39dd4): undefined reference to `omap_cpufreq_min_limit' cpu_pm.c:(.text+0x39e04): undefined reference to `omap_cpufreq_min_limit_free' cpu_pm.c:(.text+0x39e24): undefined reference to `omap_cpufreq_min_limit_free' make: *** [.tmp_vmlinux1] Error 1

    Read the article

  • Type patterns and generic classes in Haskell

    - by finnsson
    I'm trying to understand type patterns and generic classes in Haskell but can't seem to get it. Could someone explain it in laymen's terms? In [1] I've read that "To apply functions generically to all data types, we view data types in a uniform manner: except for basic predefined types such as Float, IO, and ?, every Haskell data type can be viewed as a labeled sum of possibly labeled products." and then Unit, :*: and :+: are mentioned. Are all data types in Haskell automatically versions of the above mentioned and if so how do I figure out how a specific data type is represented in terms of :*:, etc? The users guide for generic classes (ch. 7.16) at haskell.org doesn't mention the predefined types but shouldn't they be handled in every function if the type patterns should be exhaustive? [1] Comparing Approaches to Generic Programming in Haskell, Ralf Hinze, Johan Jeuring, and Andres Löh

    Read the article

  • 'Lexical' scoping of type parameters in C#

    - by leppie
    I have 2 scenarios. This fails: class F<X> { public X X { get; set; } } error CS0102: The type 'F' already contains a definition for 'X' This works: class F<X> { class G { public X X { get; set; } } } The only logical explanation is that in the second snippet the type parameter X is out of scope, which is not true... Why should a type parameter affect my definitions in a type? IMO, for consistency, either both should work or neither should work. Any other ideas? PS: I call it 'lexical', but it probably is not not the correct term.

    Read the article

< Previous Page | 58 59 60 61 62 63 64 65 66 67 68 69  | Next Page >