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  • Accessing mySQL from two ports: Problems with iptables

    - by marekventur
    Hi! I'm trying to make my mySQL-server (running on Ubuntu) listen on port 3306 and 110, because I would like to access it from a network with very few open ports. So far I've found this answer telling me to do iptables -t nat -A PREROUTING -i eth0 -p tcp --dport 110 -j REDIRECT --to-port 3306 but all I got is: # mysql -h mydomain.com -P 3306 -u username --password=xyz Welcome to the MySQL monitor. Commands end with ; or \g. Your MySQL connection id is 68863 Server version: 5.0.75-0ubuntu10.5 (Ubuntu) Type 'help;' or '\h' for help. Type '\c' to clear the buffer. mysql> exit Bye # mysql -h mydomain.com -P 110 -u username --password=xyz ERROR 2003 (HY000): Can't connect to MySQL server on 'mydomain.com' (111) I'm not an expert with iptables, so I not sure where to look for the problem. I'm googling around for quite some time, but haven't found anything to help me yet. This is what iptable tells me: # iptables -t nat -L -n -v Chain PREROUTING (policy ACCEPT 32M packets, 1674M bytes) pkts bytes target prot opt in out source destination 0 0 REDIRECT tcp -- eth0 * 0.0.0.0/0 0.0.0.0/0 tcp dpt:110 redir ports 3306 Chain POSTROUTING (policy ACCEPT 855K packets, 55M bytes) pkts bytes target prot opt in out source destination Chain OUTPUT (policy ACCEPT 837K packets, 54M bytes) pkts bytes target prot opt in out source destination # iptables -L -n -v Chain INPUT (policy DROP 7 packets, 340 bytes) pkts bytes target prot opt in out source destination 107K 5390K LOG all -- * * 0.0.0.0/0 0.0.0.0/0 state INVALID limit: avg 2/sec burst 5 LOG flags 0 level 4 prefix `INPUT INVALID ' 131K 6614K DROP all -- * * 0.0.0.0/0 0.0.0.0/0 state INVALID 0 0 MY_DROP tcp -- * * 0.0.0.0/0 0.0.0.0/0 tcp flags:0x3F/0x00 0 0 MY_DROP tcp -- * * 0.0.0.0/0 0.0.0.0/0 tcp flags:0x03/0x03 0 0 MY_DROP tcp -- * * 0.0.0.0/0 0.0.0.0/0 tcp flags:0x06/0x06 0 0 MY_DROP tcp -- * * 0.0.0.0/0 0.0.0.0/0 tcp flags:0x05/0x05 0 0 MY_DROP tcp -- * * 0.0.0.0/0 0.0.0.0/0 tcp flags:0x11/0x01 0 0 MY_DROP tcp -- * * 0.0.0.0/0 0.0.0.0/0 tcp flags:0x18/0x08 0 0 MY_DROP tcp -- * * 0.0.0.0/0 0.0.0.0/0 tcp flags:0x30/0x20 6948K 12G ACCEPT all -- lo * 0.0.0.0/0 0.0.0.0/0 151M 34G ACCEPT all -- * * 0.0.0.0/0 0.0.0.0/0 state RELATED,ESTABLISHED 32M 1666M ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:80 1833 106K ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:443 603 29392 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:25 1 60 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:465 24 1180 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:110 1 60 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:995 7919 400K ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:143 1 60 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:993 0 0 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:119 1 60 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:53 7 517 ACCEPT udp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW udp dpt:53 1110 65364 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:21 139K 8313K ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:22 10176 499K ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:3306 2 80 ACCEPT udp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW udp dpt:123 0 0 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:6060 4 176 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:6667 20987 1179K MY_REJECT all -- * * 0.0.0.0/0 0.0.0.0/0 Chain FORWARD (policy DROP 0 packets, 0 bytes) pkts bytes target prot opt in out source destination Chain OUTPUT (policy DROP 0 packets, 0 bytes) pkts bytes target prot opt in out source destination 2159 284K LOG all -- * * 0.0.0.0/0 0.0.0.0/0 state INVALID limit: avg 2/sec burst 5 LOG flags 0 level 4 prefix `OUTPUT INVALID ' 2630 304K DROP all -- * * 0.0.0.0/0 0.0.0.0/0 state INVALID 6948K 12G ACCEPT all -- * lo 0.0.0.0/0 0.0.0.0/0 181M 34G ACCEPT all -- * * 0.0.0.0/0 0.0.0.0/0 state NEW,RELATED,ESTABLISHED 0 0 MY_REJECT all -- * * 0.0.0.0/0 0.0.0.0/0 Chain MY_DROP (7 references) pkts bytes target prot opt in out source destination 0 0 LOG all -- * * 0.0.0.0/0 0.0.0.0/0 limit: avg 2/sec burst 5 LOG flags 0 level 4 prefix `PORTSCAN DROP ' 0 0 DROP all -- * * 0.0.0.0/0 0.0.0.0/0 Chain MY_REJECT (2 references) pkts bytes target prot opt in out source destination 13806 652K LOG tcp -- * * 0.0.0.0/0 0.0.0.0/0 limit: avg 2/sec burst 5 LOG flags 0 level 4 prefix `REJECT TCP ' 18171 830K REJECT tcp -- * * 0.0.0.0/0 0.0.0.0/0 reject-with tcp-reset 912 242K LOG udp -- * * 0.0.0.0/0 0.0.0.0/0 limit: avg 2/sec burst 5 LOG flags 0 level 4 prefix `REJECT UDP ' 912 242K REJECT udp -- * * 0.0.0.0/0 0.0.0.0/0 reject-with icmp-port-unreachable 1904 107K LOG icmp -- * * 0.0.0.0/0 0.0.0.0/0 limit: avg 2/sec burst 5 LOG flags 0 level 4 prefix `DROP ICMP ' 1904 107K DROP icmp -- * * 0.0.0.0/0 0.0.0.0/0 0 0 LOG all -- * * 0.0.0.0/0 0.0.0.0/0 limit: avg 2/sec burst 5 LOG flags 0 level 4 prefix `REJECT OTHER ' 0 0 REJECT all -- * * 0.0.0.0/0 0.0.0.0/0 reject-with icmp-proto-unreachable Is there anyone who can give ma a hint where to look for the problem? Thank you!

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  • Qt static build with static mysql plugin confusion

    - by bdiloreto
    I have built a Qt application which uses the MySQL library, but I am confused by the documentation on static versus shared builds. From the Qt documentation at http://doc.qt.nokia.com/4.7/deployment-windows.html it says: To deploy plugin-based applications we should use the shared library approach. And on http://doc.qt.nokia.com/4.7/deployment.html, it says: Static linking results in a stand-alone executable. The advantage is that you will only have a few files to deploy. The disadvantages are that the executables are large and with no flexibility and that you cannot deploy plugins. To deploy plugin-based applications, you can use the shared library approach. But on http://doc.qt.nokia.com/latest/plugins-howto.html, it seems to say the opposite, giving directions on how to use static plugins: Plugins can be linked statically against your application. If you build the static version of Qt, this is the only option for including Qt's predefined plugins. Using static plugins makes the deployment less error-prone, but has the disadvantage that no functionality from plugins can be added without a complete rebuild and redistribution of the application. ... To link statically against those plugins, you need to use the Q_IMPORT_PLUGIN() macro in your application and you need to add the required plugins to your build using QTPLUGIN. I want to build the Qt libraries statically (for easy deployment) and then use the static MySQL plugin. To do this, I did NOT use the binary distrubtion for Windows. Instead, I've started with the source qt-everywhere-opensource-src-4.7.4 Is the following the correct way to do a static build so that i can use the static MySql plugin? configure -static -debug-and-release -opensource -platform win32-msvc2010 -no-qt3support -no-webkit -no-script -plugin-sql-mysql -I C:\MySQL\include -L C:\MySQL\lib This should build the Qt libraries statically AND the static plugin to be linked at run-time, correct? I would NOT need to build the Mysql Plugin from source separately, correct? If I was to subtitute "-qt-sql-mysql" for "-plugin-sql-mysql" in above, it would include the MySQL driver directly in the QT static libraries, in which case I would NOT need to use the plugin at all, correct? Thanks for making me unconfused!

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  • MySQL my.cnf file not being read, Ubuntu 10.04 64bit

    - by reallyordinary
    I've been researching this for a few hours with no luck. Basically it looks like my server's my.cnf file isn't being read at all. I've searched my server, and there's only one my.cnf file on it, located at /etc/mysql/my.cnf. Its ownership is root:root. I'm running Ubuntu 10.04 64bit on a Linode.com server. I have the latest versions of MySQL and PHP installed. I've edited the my.cnf file, commented out "skip-innodb", and have set innodb to be the default storage engine using default-storage-engine = innodb And then restarted mysql. But when I do show engines, MyISAM is still coming up as the default engine. Also - none of the innodb settings I've added to the my.cnf file are being read. For example, I have this in my.cnf: innodb_buffer_pool_size=4G But in phpmyadmin, InnoDB is showing as having a buffer pool size of 8,192 KiB. Similarly, I have this in the my.cnf: innodb_data-file_path = ibdata1:500M:autoextend But in phpmyadmin, it's reading as ibdata1:10M:autoextend. It doesn't look like MyISAM info is being read from the my.cnf file either. The my.cnf file has skip-external-locking queried out, but it's showing as "on" in phpmyadmin. So - yeah, it looks like nothing in the my.cnf file is being read at all. But the server still works. I'm running a Drupal site on it and it seems to operate fine. So mysql seems to be drawing default settings from... some mysterious secret location. Any idea how I can make mysql see and use this my.cnf file? Actually, wait - it looks like it may be being read, not sure. I checked the error.log and found this: 101128 4:28:52 [ERROR] Cannot find or open table databasename/cache_apachesolr from the internal data dictionary of InnoDB though the .frm file for the table exists. Maybe you have deleted and recreated InnoDB data files but have forgotten to delete the corresponding .frm files of InnoDB tables, or you have moved .frm files to another database? or, the table contains indexes that this version of the engine doesn't support. See http://dev.mysql.com/doc/refman/5.1/en/innodb-troubleshooting.html how you can resolve the problem. InnoDB: Error: auto-extending data file ./ibdata1 is of a different size InnoDB: 640 pages (rounded down to MB) than specified in the .cnf file: InnoDB: initial 32000 pages, max 0 (relevant if non-zero) pages! InnoDB: Could not open or create data files. InnoDB: If you tried to add new data files, and it failed here, InnoDB: you should now edit innodb_data_file_path in my.cnf back InnoDB: to what it was, and remove the new ibdata files InnoDB created InnoDB: in this failed attempt. InnoDB only wrote those files full of InnoDB: zeros, but did not yet use them in any way. But be careful: do not InnoDB: remove old data files which contain your precious data! 101128 4:28:52 [ERROR] Plugin 'InnoDB' init function returned error. 101128 4:28:52 [ERROR] Plugin 'InnoDB' registration as a STORAGE ENGINE failed. 101128 4:28:52 [ERROR] /usr/sbin/mysqld: unknown variable 'innodb_lock_wait_timout=50' 101128 4:28:52 [ERROR] Aborting 101128 4:28:52 [Note] /usr/sbin/mysqld: Shutdown complete

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  • After writing SQL statements in MySQL, how to measure the speed / performance of them?

    - by Jian Lin
    I saw something from an "execution plan" article: 10 rows fetched in 0.0003s (0.7344s) How come there are 2 durations shown? What if I don't have large data set yet. For example, if I have only 20, 50, or even just 100 records, I can't really measure how faster 2 different SQL statements compare in term of speed in real life situation? In other words, there needs to be at least hundreds of thousands of records, or even a million records to accurately compares the performance of 2 different SQL statements?

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  • Top 10 collection completion - a monster in-query formula in MySQL?

    - by Andrew Heath
    I've got the following tables: User Basic Data (unique) [userid] [name] [etc] User Collection (one to one) [userid] [game] User Recorded Plays (many to many) [userid] [game] [scenario] [etc] Game Basic Data (unique) [game] [total_scenarios] I would like to output a table that shows the collection play completion percentage for the Top 10 users in descending order of %: Output Table [userid] [collection_completion] 3 95% 1 81% 24 68% etc etc In my mind, the calculation sequence for ONE USER is: grab user's total owned scenarios from User Collection joined with Game Basic Data and COUNT(gbd.total_scenarios) grab all recorded plays by COUNT(DISTINCT scenario) for that user Divide all recorded plays by total owned scenarios So that's 2 queries and a little PHP massage at the end. For a list of users sorted by completion percentage things get a little more complicated. I figure I could grab all users' collection totals in one query, and all users recorded plays in another, and then do the calcs and sort the final array in PHP, but it seems like overkill to potentially be doing all that for 1000+ users when I only ever want the Top 10. Is there a wicked monster query in MySQL that could do all that and LIMIT 10? Or is sticking with PHP handling the bulk of the work the way to go in this case?

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  • mysql connection error 1045 on windows vista

    - by Namrata
    Environment mysql-essential-5.1 mysql-workbench-oss-5.1.18a windows vista asmin account, UAC off windows firewall exception- add port- mysql 3306 tcp is set I unstalled mysql from installer remove option which delete all related folder and reinstalled it I need to connect mysql from nebeans 6.8 All good tutorials, blogs not really helping much can anybody help me.

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  • Why can I query with an int but not a string here? PHP MySQL Datatypes

    - by CT
    I am working on an Asset Database problem. I receive $id from $_GET["id"]; I then query the database and display the results. This works if my id is an integer like "93650" but if it has other characters like "wci1001", it displays this MySQL error: Unknown column 'text' in 'where clause' All fields in tables are of type: VARCHAR(50) What would I need to do to be able to use this query to search by id that includes other characters? Thank you. <?php <?php /* * ASSET DB FUNCTIONS SCRIPT * */ # connect to database function ConnectDB(){ mysql_connect("localhost", "asset_db", "asset_db") or die(mysql_error()); mysql_select_db("asset_db") or die(mysql_error()); } # find asset type returns $type function GetAssetType($id){ $sql = "SELECT asset.type From asset WHERE asset.id = $id"; $result = mysql_query($sql) or die(mysql_error()); $row = mysql_fetch_assoc($result); $type = $row['type']; return $type; } # query server returns $result (sql query array) function QueryServer($id){ $sql = " SELECT asset.id ,asset.company ,asset.location ,asset.purchaseDate ,asset.purchaseOrder ,asset.value ,asset.type ,asset.notes ,server.manufacturer ,server.model ,server.serialNumber ,server.esc ,server.warranty ,server.user ,server.prevUser ,server.cpu ,server.memory ,server.hardDrive FROM asset LEFT JOIN server ON server.id = asset.id WHERE asset.id = $id "; $result = mysql_query($sql); return $result; } # get server data returns $serverArray function GetServerData($result){ while($row = mysql_fetch_assoc($result)) { $id = $row['id']; $company = $row['company']; $location = $row['location']; $purchaseDate = $row['purchaseDate']; $purchaseOrder = $row['purchaseOrder']; $value = $row['value']; $type = $row['type']; $notes = $row['notes']; $manufacturer = $row['manufacturer']; $model = $row['model']; $serialNumber = $row['serialNumber']; $esc = $row['esc']; $warranty = $row['warranty']; $user = $row['user']; $prevUser = $row['prevUser']; $cpu = $row['cpu']; $memory = $row['memory']; $hardDrive = $row['hardDrive']; $serverArray = array($id, $company, $location, $purchaseDate, $purchaseOrder, $value, $type, $notes, $manufacturer, $model, $serialNumber, $esc, $warranty, $user, $prevUser, $cpu, $memory, $hardDrive); } return $serverArray; } # print server table function PrintServerTable($serverArray){ $id = $serverArray[0]; $company = $serverArray[1]; $location = $serverArray[2]; $purchaseDate = $serverArray[3]; $purchaseOrder = $serverArray[4]; $value = $serverArray[5]; $type = $serverArray[6]; $notes = $serverArray[7]; $manufacturer = $serverArray[8]; $model = $serverArray[9]; $serialNumber = $serverArray[10]; $esc = $serverArray[11]; $warranty = $serverArray[12]; $user = $serverArray[13]; $prevUser = $serverArray[14]; $cpu = $serverArray[15]; $memory = $serverArray[16]; $hardDrive = $serverArray[17]; echo "<table width=\"100%\" border=\"0\"><tr><td style=\"vertical-align:top\"><table width=\"100%\" border=\"0\"><tr><td colspan=\"2\"><h2>General Info</h2></td></tr><tr id=\"hightlight\"><td>Asset ID:</td><td>"; echo $id; echo "</td></tr><tr><td>Company:</td><td>"; echo $company; echo "</td></tr><tr id=\"hightlight\"><td>Location:</td><td>"; echo $location; echo "</td></tr><tr><td>Purchase Date:</td><td>"; echo $purchaseDate; echo "</td></tr><tr id=\"hightlight\"><td>Purchase Order #:</td><td>"; echo $purchaseOrder; echo "</td></tr><tr><td>Value:</td><td>"; echo $value; echo "</td></tr><tr id=\"hightlight\"><td>Type:</td><td>"; echo $type; echo "</td></tr><tr><td>Notes:</td><td>"; echo $notes; echo "</td></tr></table></td><td style=\"vertical-align:top\"><table width=\"100%\" border=\"0\"><tr><td colspan=\"2\"><h2>Server Info</h2></td></tr><tr id=\"hightlight\"><td>Manufacturer:</td><td>"; echo $manufacturer; echo "</td></tr><tr><td>Model:</td><td>"; echo $model; echo "</td></tr><tr id=\"hightlight\"><td>Serial Number:</td><td>"; echo $serialNumber; echo "</td></tr><tr><td>ESC:</td><td>"; echo $esc; echo "</td></tr><tr id=\"hightlight\"><td>Warranty:</td><td>"; echo $warranty; echo "</td></tr><tr><td colspan=\"2\">&nbsp;</td></tr><tr><td colspan=\"2\"><h2>User Info</h2></td></tr><tr id=\"hightlight\"><td>User:</td><td>"; echo $user; echo "</td></tr><tr><td>Previous User:</td><td>"; echo $prevUser; echo "</td></tr></table></td><td style=\"vertical-align:top\"><table width=\"100%\" border=\"0\"><tr><td colspan=\"2\"><h2>Specs</h2></td></tr><tr id=\"hightlight\"><td>CPU:</td><td>"; echo $cpu; echo "</td></tr><tr><td>Memory:</td><td>"; echo $memory; echo "</td></tr><tr id=\"hightlight\"><td>Hard Drive:</td><td>"; echo $hardDrive; echo "</td></tr><tr><td colspan=\"2\">&nbsp;</td></tr><tr><td colspan=\"2\">&nbsp;</td></tr><tr><td colspan=\"2\"><h2>Options</h2></td></tr><tr><td colspan=\"2\"><a href=\"#\">Edit Asset</a></td></tr><tr><td colspan=\"2\"><a href=\"#\">Delete Asset</a></td></tr></table></td></tr></table>"; } ?> __ /* * View Asset * */ # include functions script include "functions.php"; $id = $_GET["id"]; if (empty($id)):$id="000"; endif; ConnectDB(); $type = GetAssetType($id); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <link rel="stylesheet" type="text/css" href="style.css" /> <title>Wagman IT Asset</title> </head> <body> <div id="page"> <div id="header"> <img src="images/logo.png" /> </div> </div> <div id="content"> <div id="container"> <div id="main"> <div id="menu"> <ul> <table width="100%" border="0"> <tr> <td width="15%"></td> <td width="30%%"><li><a href="index.php">Search Assets</a></li></td> <td width="30%"><li><a href="addAsset.php">Add Asset</a></li></td> <td width="25%"></td> </tr> </table> </ul> </div> <div id="text"> <ul> <li> <h1>View Asset</h1> </li> </ul> <?php if (empty($type)):echo "<ul><li><h2>Asset ID does not match any database entries.</h2></li></ul>"; else: switch ($type){ case "Server": $result = QueryServer($id); $ServerArray = GetServerData($result); PrintServerTable($ServerArray); break; case "Desktop"; break; case "Laptop"; break; } endif; ?> </div> </div> </div> <div class="clear"></div> <div id="footer" align="center"> <p>&nbsp;</p> </div> </div> <div id="tagline"> Wagman Construction - Bridging Generations since 1902 </div> </body> </html>

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  • How do I filter one of the columns in a SQL Server SQL Query

    - by Kent S. Clarkson
    I have a table (that relates to a number of other tables) where I would like to filter ONE of the columns (RequesterID) - that column will be a combobox where only people that are not sales people should be selectable. Here is the "unfiltered" query, lets call it QUERY 1: SELECT RequestsID, RequesterID, ProductsID FROM dbo.Requests If using a separate query, lets call it QUERY 2, to filter RequesterID (which is a People related column, connected to People.PeopleID), it would look like this: SELECT People.PeopleID FROM People INNER JOIN Roles ON People.RolesID = Roles.RolesID INNER JOIN Requests ON People.PeopleID = Requests.RequesterID WHERE (Roles.Role <> N'SalesGuy') ORDER BY Requests.RequestsID Now, is there a way of "merging" the QUERY 2 into QUERY 1? (dbo.Requests in QUERY 1 has RequesterID populated as a Foreign Key from dbo.People, so no problem there... The connections are all right, just not know how to write the SQL query!)

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  • Should I use two queries, or is there a way to JOIN this in MySQL/PHP?

    - by Jack W-H
    Morning y'all! Basically, I'm using a table to store my main data - called 'Code' - a table called 'Tags' to store the tags for each code entry, and a table called 'code_tags' to intersect it. There's also a table called 'users' which stores information about the users who submitted each bit of code. On my homepage, I want 5 results returned from the database. Each returned result needs to list the code's title, summary, and then fetch the author's firstname based on the ID of the person who submitted it. I've managed to achieve this much so far (woot!). My problem lies when I try to collect all the tags as well. At the moment this is a pretty big query and it's scaring me a little. Here's my problematic query: SELECT code.*, code_tags.*, tags.*, users.firstname AS authorname, users.id AS authorid FROM code, code_tags, tags, users WHERE users.id = code.author AND code_tags.code_id = code.id AND tags.id = code_tags.tag_id ORDER BY date DESC LIMIT 0, 5 What it returns is correct looking data, but several repeated rows for each tag. So for example if a Code entry has 3 tags, it will return an identical row 3 times - except in each of the three returned rows, the tag changes. Does that make sense? How would I go about changing this? Thanks! Jack

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  • MySQL Error 2013

    - by kova
    I am facing connection failure to MySQL problem when I run my program for more than couple of days.MySQL Error Code is 2013 while connecting to Database. MySQL server and client programs are both on same machine. I am using FC5 as my OS and MySQL version is 5.0.18. Can anybody throw some light on this? I am getting mysql error 2013 while calling mysql_real_connect()... Any help is appreciated. Thanks in Advance k o v a

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  • Access denied for user 'root@localhost' (using password:NO)

    - by Nasser Hajloo
    I'm new to mysql, I'm trying to run Wordpress inmy windows desktop and it need Mysql. I install everything with Web Platform Installer which provided by microsoft. I never seta root password for mysql and in final step of installing wordpressit askfor root password of mysql. What is the default password for root (if there is one) and how to change it? I try mysql -u root password '123' but it show me Access denied for user 'root@localhost' (using password:NO) after this I try mysql -u root -p but it ask for a password which I don't have Thank you in advance

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  • PHP - get MySQL query results as their native data type?

    - by redidas
    I've tried fetching MySQL query results using mysql_fetch_row() mysql_result() and numeric values are being returned as strings. Is there any way to fetch the data as its datatype stored in the table? The application will be querying many different queries so I will be unable to cast the values as the intended datatype on a 1 by 1 basis.

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  • connect to mysql using c++

    - by hero
    is it possible to connect to an mysql database and issue queries using c++? i found some sample code from the internet but they all use mysql! so u need to install mysql first on the computer. what i want is to use a program from different locations where i don't have mysql installed to access a remote mysql database. is this possible?

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  • Mysql without installer is not working

    - by yyy i 777
    I have downloaded MYSQL without installer suppourt in my windows 64 bit machine . I have followed the guidelines mentioned in this website http://dev.mysql.com/doc/refman/5.0/en/windows-install-archive.html i have installed it inside c: mysql directory . As first step i navigated to c:\mysql\binmysqld , as shown in picture below . This started the Database Then i opened another command Prompt Window and navigated to c:\mysql\bin and typed show databases; With this it it showing an Error in Command Prompt saying

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