Search Results

Search found 8262 results on 331 pages for 'optimization algorithm'.

Page 63/331 | < Previous Page | 59 60 61 62 63 64 65 66 67 68 69 70  | Next Page >

  • How do I produce "enjoyably" random, as opposed to pseudo-random?

    - by Hilton Campbell
    I'm making a game which presents a number of different kinds of puzzles in sequence. I choose each puzzle with a pseudorandom number. For each puzzle, there are a number of variations. I choose the variation with another pseudorandom number. And so on. The thing is, while this produces near-true randomness, this isn't what the player really wants. The player typically wants what they perceive to be and identify as random, but only if it doesn't tend to repeat puzzles. So, not really random. Just unpredictable. Giving it some thought, I can imagine hacky ways of doing it. For example, temporarily eliminating the most recent N choices from the set of possibilities when selecting a new choice. Or assigning every choice an equal probability, reducing a choice's probability to zero on selection, and then increasing all probabilities slowly with each selection. I assume there's an established way of doing this, but I just don't know the terminology so I can't find it. Anyone know? Or has anyone solved this in a pleasing way?

    Read the article

  • Updating "Inactive" Chunks

    - by Conner Bryan
    In my game, the only chunks (4x4 areas of tiles) in memory are the ones that the player is in. However, chunks need to have updates applied to them over time. A (likely) well-known example would be MineCraft: even if the player isn't in a chunk, the wheat still needs to grow over time. My current solution is to call a method and pass in the time since the chunk was active.. but what if the chunk depends on nearby chunks for information, i.e. vines spreading or similar? Is there any reasonable solutions to this problem, or should I simply not depend on nearby chunks?

    Read the article

  • Search Engine Optimization Services For Your Business

    In the beginning of the internet, if you talked about Ninja Turtles, it was likely that you could be found on the internet with little or no worry. Imagine if you will; standing on top of a small tower and looking down over a large number of people in any given area. If for example, you were looking for a Ninja Turtle, then you might be able to play "Where's Waldo" and spot one within the masses.

    Read the article

  • What to Look Out For When Hiring a Search Engine Optimization Company

    Let's face it SEO isn't rocket science, once you know what you're doing it's pretty straight forward, but if it's not done properly then your competitors are getting all your customers. So investing in the services of an SEO Company can be a great return on your time and money. But not all SEO Companies are created equal so here's a quick checklist of things to look out for when hiring an SEO company.

    Read the article

  • how to calculate intersection time and place of multiple moving arcs

    - by user20733
    I have rocks orbiting moons, moons orbiting planets, planets orbiting suns, and suns orbiting black holes, and the current system could have many many layers of orbitage. the position of any object is a function of time and relative to the object it orbits. (so far so good). now I want to know for a given 2 objects(A,B), a start time and a speed, how can I work out the when and where to go. I can work out where A and B is given a time. so i just need. 1: direction to travel in from A to B(remember B is moving(not in a straight line)) 2: Time to get to b in a straight line. travel must be in a straight line with the shortest possible distance. as an extension to this question, how will i know if its better to wait, EG is it faster to stay on object A and wait for a hour when the objects may be closer, than to set off from A to B at the start. Cheers, it hurt my brain.

    Read the article

  • Search Engine Optimization (SEO) Enhancement in ASP.NET 4.0

    This article explains the MetaKeywords and MetaDescription properties related to SEO enhancement in ASP.NET 4.0....Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

    Read the article

  • Finding out which tile a mouse click landed in

    - by Shard
    I am working on an icometric grid based game and im having an issue trying to link a mouse click from the user to a tile. I have been able to split the problem into 2 parts which is first finding a rectangle that sourounds a tile, which I have been able to do but the second part of figuring out from the rectangle which tile the click landed in has got me stumped. Here is an example of a rectangle with tiles on the inside: The rectangle is 70px long and 30px high so if i use an input of say 30x(top)/20y(left) how would I go about determining which tile this fell into?

    Read the article

  • Mistakes in Implementing Website Optimization

    What are some of the mistakes these SEO companies have done in the implementation of SEO strategies? Outlined in this article are some of the important things SEO expert and companies implementing SEO strategies will take most into consideration.

    Read the article

  • A* algorithm very slow

    - by Amaranth
    I have an programming a RTS game (I use XNA with C#). The pathfinding is working fine, except that when it has a lot of node to search in, there is a lag period of one or two seconds, it happens mainly when there is no path to the target destination, since it that situation there is more nodes to explore. I have the same problem when the path is shorter but selected more than 3 units (can't take the same path since the selected units can be in different part of the map). private List<NodeInfo> FindPath(Unit u, NodeInfo start, NodeInfo end) { Map map = GameInfo.GetInstance().GameMap; _nearestToTarget = start; start.MoveCost = 0; Vector2 endPosition = map.getTileByPos(end.X, end.Y).Position; //getTileByPos simply gets the tile in a 2D array with the X and Y indexes start.EstimatedRemainingCost = (int)(endPosition - map.getTileByPos(start.X, start.Y).Position).Length(); start.Parent = null; List<NodeInfo> openedNodes = new List<NodeInfo>(); ; List<NodeInfo> closedNodes = new List<NodeInfo>(); Point[] movements = GetMovements(u.UnitType); openedNodes.Add(start); while (!closedNodes.Contains(end) && openedNodes.Count > 0) { //Loop in nodes to find lowest cost NodeInfo currentNode = FindLowestCostOpenedNode(openedNodes); openedNodes.Remove(currentNode); closedNodes.Add(currentNode); Vector2 previousMouvement; if (currentNode.Parent == null) { previousMouvement = ConvertRotationToDirectionVector(u.Rotation); } else { previousMouvement = map.getTileByPos(currentNode.X, currentNode.Y).Position - map.getTileByPos(currentNode.Parent.X, currentNode.Parent.Y).Position; previousMouvement.Normalize(); } //For each neighbor foreach (Point movement in movements) { Point exploredGridPos = new Point(currentNode.X + movement.X, currentNode.Y + movement.Y); //Checks if valid move and checks if not if closed nodes list if (ValidNavigableNode(u.UnitType, new Point(currentNode.X, currentNode.Y), exploredGridPos) && !closedNodes.Contains(_gridMap[exploredGridPos.Y, exploredGridPos.X])) { NodeInfo exploredNode = _gridMap[exploredGridPos.Y, exploredGridPos.X]; Tile.TileType exploredTerrain = map.getTileByPos(exploredGridPos.X, exploredGridPos.Y).TerrainType; if(openedNodes.Contains(exploredNode)) { int newCost = currentNode.MoveCost + GetMoveCost(previousMouvement, movement, exploredTerrain); if (newCost < exploredNode.MoveCost) { exploredNode.Parent = currentNode; exploredNode.MoveCost = newCost; //Find nearest tile to the target (in case doesn't find path to target) //Only compares the node to the current nearest FindNearest(exploredNode); } } else { exploredNode.Parent = currentNode; exploredNode.MoveCost = currentNode.MoveCost + GetMoveCost(previousMouvement, movement, exploredTerrain); Vector2 exploredNodeWorldPos = map.getTileByPos(exploredGridPos.X, exploredGridPos.Y).Position; exploredNode.EstimatedRemainingCost = (int)(endPosition - exploredNodeWorldPos).Length(); //Find nearest tile to the target (in case doesn't find path to target) //Only compares the node to the current nearest FindNearest(exploredNode); openedNodes.Add(exploredNode); } } } } return closedNodes; } After that, I simply check if the end node is contained in the returned nodes. If so, I add the end node and each parent until I reach the start. If not, I add the nearestToTarget and each parent until I reach the start. I added a condition before calling FindPath so that only one unit can call a find path each frame (60 frame per second), but it makes no difference. I thought maybe I could solve this by allowing the find path to run in background while the game continues to run correctly, even if it takes a few frame (it is currently sequential sonce it is called in the update() of the unit if there's a target location but no path), but I don't really know how... I also though about sorting my opened nodes list by cost so I don't have to loop them, but I don't know if that would have an effect on the performance... Would there be other solutions? P.S. In the code, when I get the Move Cost, I check if the unit has to turn to perform the move, and the terrain type, nothing hard to do.

    Read the article

  • Search Engine Optimization - The Five Factors Search Engines Use to Rank Websites

    At the end of the day, SEO requires a lot of extremely specialized knowledge, time, and attention - on an ongoing basis. But because a SEO effort can give a website's rankings a dramatic boost in the search results - and there is a significant connection between search engine ranking and search referral traffic - it is well worth doing whatever it takes to develop the knowledge and to be able to invest the time and attention.

    Read the article

  • Search Engine Optimization - The Five Factors Search Engines Use to Rank Websites

    At the end of the day, SEO requires a lot of extremely specialized knowledge, time, and attention - on an ongoing basis. But because a SEO effort can give a website's rankings a dramatic boost in the search results - and there is a significant connection between search engine ranking and search referral traffic - it is well worth doing whatever it takes to develop the knowledge and to be able to invest the time and attention.

    Read the article

  • Can GJK be used with the same "direction finding method" every time?

    - by the_Seppi
    In my deliberations on GJK (after watching http://mollyrocket.com/849) I came up with the idea that it ins not neccessary to use different methods for getting the new direction in the doSimplex function. E.g. if the point A is closest to the origin, the video author uses the negative position vector AO as the direction in which the next point is searched. If an edge (with A as an endpoint) is closest, he creates a normal vector to this edge, lying in the plane the edge and AO form. If a face is the feature closest to the origin, he uses even another method (which I can't recite from memory right now) However, while thinking about the implementation of GJK in my current came, I noticed that the negative direction vector of the newest simplex point would always make a good direction vector. Of course, the next vertex found by the support function could form a simplex that less likely encases the origin, but I assume it would still work. Since I'm currently experiencing problems with my (yet unfinished) implementation, I wanted to ask whether this method of forming the direction vector is usable or not.

    Read the article

  • Search Engine Optimization Basics - Know Your Keywords

    I laugh to myself when I hear everyone in SEO talking about how the most important thing to improve your website's position in Google is backlinks. Now don't get me wrong, I definitely agree that building backlinks to your pages is important, but there is something that I consider much more important - and that is keyword research.

    Read the article

  • How should I compress a file with multiple bytes that are the same with Huffman coding?

    - by Omega
    On my great quest for compressing/decompressing files with a Java implementation of Huffman coding (http://en.wikipedia.org/wiki/Huffman_coding) for a school assignment, I am now at the point of building a list of prefix codes. Such codes are used when decompressing a file. Basically, the code is made of zeroes and ones, that are used to follow a path in a Huffman tree (left or right) for, ultimately, finding a byte. In this Wikipedia image, to reach the character m the prefix code would be 0111 The idea is that when you compress the file, you will basically convert all the bytes of the file into prefix codes instead (they tend to be smaller than 8 bits, so there's some gain). So every time the character m appears in a file (which in binary is actually 1101101), it will be replaced by 0111 (if we used the tree above). Therefore, 1101101110110111011011101101 becomes 0111011101110111 in the compressed file. I'm okay with that. But what if the following happens: In the file to be compressed there exists only one unique byte, say 1101101. There are 1000 of such byte. Technically, the prefix code of such byte would be... none, because there is no path to follow, right? I mean, there is only one unique byte anyway, so the tree has just one node. Therefore, if the prefix code is none, I would not be able to write the prefix code in the compressed file, because, well, there is nothing to write. Which brings this problem: how would I compress/decompress such file if it is impossible to write a prefix code when compressing? (using Huffman coding, due to the school assignment's rules) This tutorial seems to explain a bit better about prefix codes: http://www.cprogramming.com/tutorial/computersciencetheory/huffman.html but doesn't seem to address this issue either.

    Read the article

  • Help with timebased scoring algorithm

    - by Dave
    Im trying to devise an appropriate scoring system for my game. The game in essense has a finite number of tasks to complete (say 20) and the quicker you complete these task, the more points you get. I had devised a basic way of doing this using bands of time multiplied by a score for that band multiplied by the number of tasks solved within that time band i.e. (Time Band) = (Points) 1-5 sec = 15, 5-10 secs = 10, 10-20 secs = 5, 20-30 secs = 3, 40 secs onwards = 1, So for example if I did 3 tasks in the 1-5sec band i'd get 15*3=45points, if i found 10 in the 20-30sec band i'd get 3*10=30 points. Im sure there is a more mathematical way of doing this using powers of some kind but I just can't think how and hoping someone has already done something smilar.. Many thanks in advance

    Read the article

  • Search Engine Optimization - Article Authors Area

    When you think of starting a new online business make the authors area a frequent place to visit. Writing your own original content will brand your business. Submit your one of a kind article to only one directory and then write a new one to submit to another directory. Branding your business products and or services will create a structure of trust, when others see that you understand what you are doing.

    Read the article

  • Keeping the meshes "thickness" the same when scaling an object

    - by user1806687
    I've been bashing my head for the past couple of weeks trying to find a way to help me accomplish, on first look very easy task. So, I got this one object currently made out of 5 cuboids (2 sides, 1 top, 1 bottom, 1 back), this is just for an example, later on there will be whole range of different set ups. Now, the thing is when the user chooses to scale the whole object this is what should happen: X scale: top and bottom cuboids should get scaled by a scale factor, sides should get moved so they are positioned just like they were before(in this case at both ends of top and bottom cuboids), back should get scaled so it fits like before(if I simply scale it by a scale factor it will leave gaps on each side). Y scale: sides should get scaled by a scale factor, top and bottom cuboid should get moved, and back should also get scaled. Z scale: sides, top and bottom cuboids should get scaled, back should get moved. Hope you can help, EDIT: So, I've decided to explain the situation once more, this time more detailed(hopefully). I've also made some pictures of how the scaling should look like, where is the problem and the wrong way of scaling. I this example I will be using a thick walled box, with one face missing, where each wall is made by a cuboid(but later on there will be diffrent shapes of objects, where a one of the face might be roundish, or triangle or even under some angle), scaling will be 2x on X axis. 1.This is how the default object without any scaling applied looks like: http://img856.imageshack.us/img856/4293/defaulttz.png 2.If I scale the whole object(all of the meshes) by some scale factor, the problem becomes that the "thickness" of the object walls also change(which I do not want): http://img822.imageshack.us/img822/9073/wrongwaytoscale.png 3.This is how the correct scaling should look like. Appropriate faces gets caled in this case where the scale is on X axis(top, bottom, back): http://imageshack.us/photo/my-images/163/rightwayxscale1.png/ 4.But the scale factor might not be the same for all object all of the times. In this case the back has to get scaled a bit more or it leaves gaps: http://imageshack.us/photo/my-images/9/problemwhenscaling.png/ 5.If everything goes well this is how the final object should look like: http://imageshack.us/photo/my-images/856/rightwayxscale2.png/ So, as you have might noticed there are quite a bit of things to look out when scaling. I am asking you, if any of you have any idea on how to accomplish this scaling. I have tried whole bunch of things, from scaling all of the object by the same scale factor, to subtracting and adding sizes to get the right size. But nothing I tried worked, if one mesh got scaled correctly then others didnt. Donwload the example object. English is not my first language, so I am really sorry if its hard to understand what I am saying.

    Read the article

< Previous Page | 59 60 61 62 63 64 65 66 67 68 69 70  | Next Page >