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  • Versioning code in two separate projects concurently with subverison

    - by Matt1776
    I have a need to create a library of Object Oriented PHP code that will see much reuse and aspires to be highly flexible and modular. Because of its independent nature I would like it to exist as its own SVN project. I would like to be able to create a new web project, save it in SVN as its own separate project, and include within it the library project code as well. During this process, while coding the web application code and making commits, I may need to add a class to the library. I would like to be able to do so and commit those changes back to the libraries project code. In light of all this I could manage the code in two ways Commit the changes to the library back to a branch of its original base project code and make the branch name relevant to the web project I was using it with Commit the changes to the library back to the original code, growing it in size regardless of any specific references that might exist. I have two questions How can I include this library project code into a new project yet not break the subversion functionality, i.e. allowing me to make changes to each project individually? How I can keep the code synchronized? If I choose the first method of managing the library code I may want to grab changes from another branch and pull it in for use in another.

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  • How to test if a user has SELECTED a file to upload ?

    - by Tristan
    Hello, on a page, i have : if (!empty($_FILES['logo']['name'])) { $dossier = 'upload/'; $fichier = basename($_FILES['logo']['name']); $taille_maxi = 100000; $taille = filesize($_FILES['logo']['tmp_name']); $extensions = array('.png', '.jpg', '.jpeg'); $extension = strrchr($_FILES['logo']['name'], '.'); if(!in_array($extension, $extensions)) { $erreur = 'ERROR you must upload the right type'; } if($taille>$taille_maxi) { $erreur = 'too heavy'; } if(!empty($erreur)) { ....................... } The problem is, if the users wants to edit information WITHOUT uploading a LOGO, it raises an error : 'error you must upload the right type' So, if a user didn't put anything in the inputbox in order to upload it, i don't want to enter in these conditions test. i tested : if (!empty($_FILES['logo']['name']) and if (isset($_FILES['logo']['name']) but both doesn't seems to work. Any ideas? edit : maybe i wasn't so clear, i don't want to test if he uploaded a logo, i want to test IF he selected a file to upload, because right now, if he doesn't select a file to upload, php raises an error telling he must upload with the right format. thanks.

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  • DOMNode reference doesn't work anymore after appending it to another element twice

    - by Robbie Groenewoudt
    Hi, I'm using the a wrapper around the PHP5-class DOMDocument to generate my HTML. This makes it easy to modify the HTML by using the DOM. An example is creating element #1 and adding it to the element #2 and still be able to modify element #1 directly. A problem arises however with the following: Element #1 is added to element #2 Element #2 is added to element #3 Element #1 is modified but no changes are visible in the DOM of element #3 (which contains #1 and #2) A simplified sample code: <?php $doc1 = new DOMDocument(); $el1 = $doc1->createElement('h1', 'Hello'); $doc1->appendChild($el1); $doc2 = new DOMDocument(); $el2 = $doc2->createElement('h2', 'World'); $doc2->appendChild($el2); $doc3 = new DOMDocument(); $el3 = $doc3->createElement('h3', 'Today'); $doc3->appendChild($el3); // Import el1 into el2 $el1 = $doc2->importNode($el1, true); $el2->appendChild( $el1 ); $doc1 = $doc2; // Import el2 into el3 $el2 = $doc3->importNode($el2, true); //$el1 = $doc3->importNode($el1, true); Necessary? $el3->appendChild($el2); $doc2 = $doc3; // Modify el1 $el1->nodeValue = "Boo"; // This doesn't work? //$el2->nodeValue = "Boo"; // Changing element2 or 3 works... // Display result echo $doc3->saveHTML(); ?>` Any idea's on why modifying $el1 won't work? (While $el2 works fine) Or an easy way to set $el1 to the right element?

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  • SugarmCRM REST API always returns "null"

    - by TuomasR
    I'm trying to test out the SugarCRM REST API, running latest version of CE (6.0.1). It seems that whenever I do a query, the API returns "null", nothing else. If I omit the parameters, then the API returns the API description (which the documentation says it should). I'm trying to perform a login, passing as parameter the method (login), input_type and response_type (json) and rest_data (JSON encoded parameters). The following code does the query: $api_target = "http://example.com/sugarcrm/service/v2/rest.php"; $parameters = json_encode(array( "user_auth" => array( "user_name" => "admin", "password" => md5("adminpassword"), ), "application_name" => "Test", "name_value_list" => array(), )); $postData = http_build_query(array( "method" => "login", "input_type" => "json", "response_type" => "json", "rest_data" => $parameters )); echo $parameters . "\n"; echo $postData . "\n"; echo file_get_contents($api_target, false, stream_context_create(array( "http" => array( "method" => "POST", "header" => "Content-Type: application/x-www-form-urlencoded\r\n", "content" => $postData ) ))) . "\n"; I've tried different variations of parameters and using username instead of user_name, and all provide the same result, just a response "null" and that's it.

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  • MySQL query returning mysql_error

    - by Sebastian
    This returns mysql_error: <?php $name = $_POST['inputName2']; $email = $_POST['inputEmail2']; $instruments = $_POST['instruments']; $city = $_POST['inputCity']; $country = $_POST['inputCountry']; $distance = $_POST['distance']; // ^^ These all echo properly ^^ // CONNECT TO DB $dbhost = "xxx"; $dbname = "xxx"; $dbuser = "xxx"; $dbpass = "xxx"; $con = mysqli_connect("$dbhost", "$dbuser", "$dbpass", "$dbname"); if (mysqli_connect_errno()) { echo "Failed to connect to MySQL: " . mysqli_connect_error(); } $query = "INSERT INTO depfinder (name, email, instrument1, instrument2, instrument3, instrument4, instrument5, city, country, max_distance) VALUES ($name, $email, $instruments[0], $instruments[1], $instruments[2], $instruments[3], $instruments[4], $city, $country, $max_distance)"; $result = mysqli_query($con, $query) or die(mysqli_error($con)); // script fails here if (!$result) { echo "There was a problem with the signup process. Please try again later."; } else { echo "Success"; } } ?> N.B. I'm not sure whether it's relevant, but the user may not choose five instruments so some $instrument[] array values may be empty. Bonus question: is my script secure enough or is there more I could do?

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  • How to send a future email using AT command.

    - by BHare
    I just need to send one email into the future, so I figured i'd be best at using at rather than using cron. This is what I have so far, its messy and ugly and not that great at escaping: <pre> <?php $out = array(); // Where is the email going? $email = "[email protected]"; // What is the body of the email (make sure to escape any double-quotes) $body = "This is what is actually emailed to me"; $body = escapeshellcmd($body); $body = str_replace('!', '\!', $body); // What is the subject of the email (make sure to escape any double-quotes) $subject = "It's alive!"; $subject = escapeshellcmd($subject); $subject = str_replace('!', '\!', $subject); // How long from now should this email be sent? IE: 1 minute, 32 days, 1 month 2 days. $when = "1 minute"; $command= <<<END echo " echo \"$body\" > /tmp/email; mail -s \"$subject\" $email < /tmp/email; rm /tmp/email; " | at now + $when; END; $ret = exec($command, $out); print_r($out); ?> </pre> The output should be something like warning: commands will be executed using /bin/sh job 60 at Thu Dec 30 19:39:00 2010 However I am doing something wrong with exec and not getting the result? The main thing is this seem very messy. Is there any alternative better methods for doing this? PS: I had to add apache's user (www-data for me) to /etc/at.allow ...Which I don't like, but I can live with it.

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  • cURL cookie negative cookie expire

    - by Joe Doe
    I have problems with cookies with cURL. After problems I turned on verbose function and figured out cURL sets them negative expire date even if server sends positive date. Example: * Added cookie _c_sess=""test"" for domain test.com, path /, expire -1630024962 < Set-Cookie: _c_sess="test"; Domain=test.com; HttpOnly; expires=Mon, 26-Mar-2012 14:52:47 GMT; Max-Age=1332773567; Path=/ As you can see both expires and max-age are positive, but cURL sets expire to negative value. Somebody has idea? EDIT: Here is php code I use. $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, "http://site.com/"); curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/5.0 (Windows NT 6.1; rv:11.0) Gecko/20100101 Firefox/11.0'); curl_setopt($ch, CURLOPT_COOKIEJAR, $cookiepath); curl_setopt($ch, CURLOPT_COOKIEFILE, $cookiepath); curl_setopt($ch, CURLOPT_HEADER ,1); curl_setopt($ch, CURLOPT_VERBOSE ,1); curl_setopt($ch, CURLOPT_STDERR ,$f); curl_setopt($ch, CURLOPT_RETURNTRANSFER ,1); curl_setopt($ch, CURLOPT_FOLLOWLOCATION ,1); curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0); $data = curl_exec($ch); Data from cookie jar: #HttpOnly_.test.com TRUE / FALSE -1630016318 _test_sess "test"

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  • How to add Remember me function at custom login box ?

    - by morningglory
    In my theme, there's custom page for the login. Login function at functions.php is like this function log_in($username, $password) { $user = parse_user($username); $username = $username; $password = $password; if(isEmptyString($username)) return new WP_Error('username', 'required'); if(isEmptyString($password)) return new WP_Error('password', "required"); if(!wp_check_password( $password, $user->user_pass ) ) return new WP_Error('wrong_password', "wrong"); wp_set_auth_cookie($user->ID, $remember); wp_login($username, $password); redirect_profile(); } function parse_user($info = null, $return = 'object') { if ( is_null( $info ) ) { global $current_user; if ( empty( $current_user->ID ) ) return null; $info = get_userdata( $current_user->ID ); } elseif ( empty( $info ) ) { return null; } if( $return == 'ID' ) { if ( is_object( $info ) ) return $info->ID; if ( is_numeric( $info ) ) return $info; } elseif( $return == 'object' ) { if ( is_object( $info ) && $info->ID) return $info; if ( is_object( $info )) return get_userdata( $info->ID ); if ( is_numeric( $info ) ) return get_userdata( $info ); if ( is_string( $info ) ) return get_userdatabylogin( $info ); } else { return null; } } I want to add remember me checkbox for user to logged in all the time until they logout. How can i add this ? Please kindly help me out. Thank you.

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  • "for" loop inside another "for" loop

    - by jnkrois
    Hello everybody. I have quick question, and I'm sure some of you guys will be able to point out what I'm doing wrong. Basically, I want to create a table with (calendar), with the months and days of an entire year, and Im using php to do it, my code is doing something weird. What happens is that January is empty and the days for January are being put in february. My code so far is as follows: $months = 12; $monthsOfTheyear = array("Januany","February","March","April","May","June","July","August","September","October","November","December"); $currentMonth = date("n"); $currentYear = date("Y"); $daysOfTheMonth = cal_days_in_month(CAL_GREGORIAN, $currentMonth, $currentYear); for($i = 0; $i < $months; $i++){ echo " <tbody class='month'>"; echo " <tr> <td colspan='".$daysOfTheMonth."'> ".$monthsOfTheyear[$i]." </td> </tr> <tr> "; $daysOfEachMonth = cal_days_in_month(CAL_GREGORIAN, $i, $currentYear); for($d = 1; $d <= $daysOfEachMonth; $d++){ echo " <td> ".$d." </td> "; } echo " </tr> </tbody"; } I'm obviously doing something wrong, but I've been staring at the monitor for about an hour trying to figure it out. I'd appreciate any advice. Thanks

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  • jQuery - Creating a dynamic content loader using $.get()

    - by Kenny Bones
    Hello everybody! (hello dr.Nick) :) So I posted a question yesterday about a content loader plugin for jQuery I thought I'd use, but didn't get it to work. http://stackoverflow.com/questions/2469291/jquery-could-use-a-little-help-with-a-content-loader Although it works now, I see some disadvantages to it. It requires heaploads of files where the content is in. Since the code essentially picks up the url in the href link and searches that file for a div called #content What I would really like to do is to collect all of these files into a single file and give each div/container it's unique ID and just pick up the content from those. So i won't need so many separate files laying around. Nick Craver thought I should use $.get()instead since it's got a descent callback. But I'm not that strong in js at all.. And I don't even know what this means. I'm basically used to Visual Basic and passing of arguments, storing in txt files etc. Which is really not suitable for this purpose. So what's the "normal" way of doing things like this? I'm pretty sure I'm not the only one who's thought of this right? I basically want to get content from a single php file that contains alot of divs with unique IDs. And without much hassle, fade out the existing content in my main page, pick up the contents from the other file and fade it into my main page.

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  • How to query multiple tables with multiple selects MySQL

    - by brybam
    I'm trying to write a php function that gets all the basic food data(this part works fine in my code) Then grabs all the ingredients related to the ids of the selected items from the query before. Anyone have have any idea why my second array keeps coming back as false? I should be getting 1 array with the list of foods (this works) Then, the second one should be an array with all the ingredients for all the foods that were previously selected...then in my code im planning to work with the array and sort them with the proper foods based on the ids. function getFood($start, $limit) { $one = mysql_query("SELECT a.id, a.name, a.type, AVG(b.r) AS fra, COUNT(b.id) as tvotes FROM `foods` a LEFT JOIN `foods_ratings` b ON a.id = b.id GROUP BY a.id ORDER BY fra DESC, tvotes DESC LIMIT $start, $limit;"); $row = mysql_fetch_array($one); $qry = ""; foreach ($row as &$value) { $fid = $value['id']; $qry = $qry . "SELECT ing, amount FROM foods_ing WHERE fid='$fid';"; } $two = mysql_query($qry); return array ($one, $two); }

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  • While loop in foreach loop not looping correctly

    - by tominated
    I'm trying to make a very basic php ORM as for a school project. I have got almost everything working, but I'm trying to map results to an array. Here's a snippet of code to hopefully assist my explanation. $results = array(); foreach($this->columns as $column){ $current = array(); while($row = mysql_fetch_array($this->results)){ $current[] = $row[$column]; print_r($current); echo '<br><br>'; } $results[$column] = $current; } print_r($results); return mysql_fetch_array($this->results); This works, but the while loop only works on the first column. The print_r($results); shows the following: Array ( [testID] => Array ( [0] => 1 [1] => 2 ) [testName] => Array ( ) [testData] => Array ( ) ) Can anybody shed some light? Thanks in advance!

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  • Parse error: syntax error, unexpected T_STRING in...

    - by rabidmachine9
    I' making this class to catch twitter posts but I get the error : Parse error: syntax error, unexpected T_STRING in /Applications/XAMPP/xamppfiles/htdocs/classTest/Twitter.php on line 29 I cant find what's wrong...any ideas? class TwitterGrub{ function twitterCapture($user = 'myUsername',$password = 'myPass') { $ch = curl_init("https://twitter.com/statuses/user_timeline.xml"); curl_setopt($ch, CURLOPT_HEADER, 1); curl_setopt($ch,CURLOPT_TIMEOUT, 30); curl_setopt($ch,CURLOPT_USERPWD,$user . ":" . $password); curl_setopt($ch,CURLOPT_RETURNTRANSFER,1); curl_setopt ($ch, CURLOPT_SSL_VERIFYPEER, 0); curl_setopt ($ch, CURLOPT_SSL_VERIFYHOST, 0); $result=curl_exec ($ch); $data = strstr($result, '<?'); $xml = new SimpleXMLElement($data); return $xml; } function twitterDisplay($twitNum){ $xml = this->twitterCapture(); for($i= 0; $i<$twitNum; $i++){ echo "<div class='curvebox'>".$xml->status[$i]->text."</div>"; } } }

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  • What characters are NOT escaped with a mysqli prepared statement?

    - by barfoon
    Hey everyone, I'm trying to harden some of my PHP code and use mysqli prepared statements to better validate user input and prevent injection attacks. I switched away from mysqli_real_escape_string as it does not escape % and _. However, when I create my query as a mysqli prepared statement, the same flaw is still present. The query pulls a users salt value based on their username. I'd do something similar for passwords and other lookups. Code: $db = new sitedatalayer(); if ($stmt = $db->_conn->prepare("SELECT `salt` FROM admins WHERE `username` LIKE ? LIMIT 1")) { $stmt->bind_param('s', $username); $stmt->execute(); $stmt->bind_result($salt); while ($stmt->fetch()) { printf("%s\n", $salt); } $stmt->close(); } else return false; Am I composing the statement correctly? If I am what other characters need to be examined? What other flaws are there? What is best practice for doing these types of selects? Thanks,

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  • Error with MySQL Query

    - by Ken
    Okay, I must be an idiot, because this is my 3rd question for today. Here's my code: date_default_timezone_set("America/Los_Angeles"); include("mainmenu.php"); $con = mysql_connect("localhost", "root", "********"); if(!$con){ die(mysql_error()); } $usrname = $_POST['usrname']; $fname = $_POST['fname']; $lname = $_POST['lname']; $password = $_POST['password']; $email = $_POST['email']; mysql_select_db("`users`, $con) or die(mysql_error()"); $query = ("INSERT INTO `users`.`data` (`id`, `usrname`, `fname`, `lname`, `email`, `password`) VALUES (NULL, '$usrname', '$fname', '$lname', '$email', 'password'))"); mysql_query('$query') or die(mysql_error()); mysql_close($con); echo("Thank you for registering!"); I always get the error returned as: "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '$query' at line 1. Help a newbie. I'm about to stab my monitor.

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  • SQL query error while trying to put a file in the database

    - by DaGhostman Dimitrov
    Hey Guys I have a big problem that I have no Idea why.. I have few forms that upload files to the database, all of them work fine except one.. I use the same query in all(simple insert). I think that it has something to do with the files i am trying to upload but I am not sure. Here is the code: if ($_POST['action'] == 'hndlDocs') { $ref = $_POST['reference']; // Numeric value of $doc = file_get_contents($_FILES['doc']['tmp_name']); $link = mysqli_connect('localhost','XXXXX','XXXXX','documents'); mysqli_query($link,"SET autocommit = 0"); $query = "INSERT INTO documents ({$ref}, '{$doc}', '{$_FILES['doc']['type']}') ;"; mysqli_query($link,$query); if (mysqli_error($link)) { var_dump(mysqli_error($link)); mysqli_rollback($link); } else { print("<script> window.history.back(); </script>"); mysqli_commit($link); } } The database has only these fields: DATABASE documents ( reference INT(5) NOT NULL, //it is unsigned zerofill doc LONGBLOB NOT NULL, //this should contain the binary data mime_type TEXT NOT NULL // the mime type of the file php allows only application/pdf and image/jpeg ); And the error I get is : You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '00001, '????' at line 1 I will appreciate every help. Cheers!

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  • How to disable form submit if the username is not available

    - by Rajasekar
    I have checked the user name availability. The problem is, even if the username is not available, the form is posting. Edited Code: <SCRIPT type="text/javascript"> $(document).ready(function(){ $("#emailch").change(function() { var usr = $("#emailch").val(); if(usr.length >= 3) { $("#status").html('<img src="images/loader.gif" align="absmiddle">&nbsp;Checking availability...'); $.ajax({ type: "POST", url: "includes/check.php", data: "username="+ usr, success: function(msg){ $("#status").ajaxComplete(function(event, request, settings){ if(msg == 'OK') { $("#username").removeClass('object_error'); // if necessary $("#username").addClass("object_ok"); $(this).html('&nbsp;<img src="images/tick.gif" align="absmiddle">'); } else { $("#username").removeClass('object_ok'); // if necessary $("#username").addClass("object_error"); $(this).html(msg); } }); } }); } else { $("#status").html('<font color="red">The username should have at least <strong>3</strong> characters.</font>'); $("#username").removeClass('object_ok'); // if necessary $("#username").addClass("object_error"); } }); }); </SCRIPT> What I want is that, the form should not be posted if the user name is not available. I have tried by using return false; in IF CONDITION but it fails. Please suggest any alternate method. Any help will be appreciated.

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  • #1146 - Table 'phpmyadmin.pma_recent' doesn't exist

    - by Mumin Ali
    Solution Guys... FYI i am using xampp to use phpmyadmin. and this error happens during the process of creating a database on localhost. Below is the code for config.inc file under phpmyadmin directory: <?php /* * This is needed for cookie based authentication to encrypt password in * cookie */ $cfg['blowfish_secret'] = 'xampp'; /* YOU SHOULD CHANGE THIS FOR A MORE SECURE COOKIE AUTH! */ /* * Servers configuration */ $i = 0; /* * First server */ $i++; /* Authentication type and info */ $cfg['Servers'][$i]['auth_type'] = 'HTTP'; $cfg['Servers'][$i]['user'] = 'root'; $cfg['Servers'][$i]['password'] = 'password'; $cfg['Servers'][$i]['extension'] = 'mysql'; $cfg['Servers'][$i]['AllowNoPassword'] = true; $cfg['Lang'] = ''; /* Bind to the localhost ipv4 address and tcp */ $cfg['Servers'][$i]['host'] = 'localhost'; $cfg['Servers'][$i]['connect_type'] = 'tcp'; /* User for advanced features */ $cfg['Servers'][$i]['controluser'] = 'pma'; $cfg['Servers'][$i]['controlpass'] = ''; /* Advanced phpMyAdmin features */ $cfg['Servers'][$i]['pmadb'] = 'phpmyadmin'; $cfg['Servers'][$i]['bookmarktable'] = 'pma_bookmark'; $cfg['Servers'][$i]['relation'] = 'pma_relation'; $cfg['Servers'][$i]['table_info'] = 'pma_table_info'; $cfg['Servers'][$i]['table_coords'] = 'pma_table_coords'; $cfg['Servers'][$i]['pdf_pages'] = 'pma_pdf_pages'; $cfg['Servers'][$i]['column_info'] = 'pma_column_info'; $cfg['Servers'][$i]['history'] = 'pma_history'; $cfg['Servers'][$i]['designer_coords'] = 'pma_designer_coords'; $cfg['Servers'][$i]['tracking'] = 'pma_tracking'; $cfg['Servers'][$i]['userconfig'] = 'pma_userconfig'; $cfg['Servers'][$i]['recent'] = 'pma_recent'; $cfg['Servers'][$i]['table_uiprefs'] = 'pma_table_uiprefs'; /* * End of servers configuration */ ?>

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  • CakePHP: Need help using saveField to update a fields in a belongsTo model

    - by afrisch
    I am trying to update a password into two different models/tables in CakePHP. I can update it fine in the parent model, but not the second model. Models: Users (hasOne GameProfile) PK=id Gameprofiles (belongsTo User) FK=user_id Here is a stripped down version of my function in the Users_controller.php: function updatepass() { if (!empty($this->data)) { $this->User->id = $this->Auth->user('id'); $this->User->saveField('sha1password', $this->Auth->password($this->data['User']['newpass'])); $this->User->Gameprofile->saveField('plainpassword', $this->data['User']['newpass']); } } When I execute the function, the users table is updated fine. But the gameprofile table is not updated, rather Cake does an insert. SQL Query Log: 1195 Query UPDATE `users` SET `sha1password` = 'e9443e9f5e1a07832aad1b2f84de1a666daf89b5' WHERE `users`.`id` = 30 1195 Query INSERT INTO `gameprofiles` (`plainpassword`) VALUES ('abc') Is there a way to get CakePHP to do an update using saveField on a model with a belongsTo attribute? I've tried various ways to refer to user_id before executing the second saveField, but just can't seem to find the winning combination. Any help is greatly appreciated!

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  • Incrementing value by one over a lot of rows

    - by Andy Gee
    Edit: I think the answer to my question lies in the ability to set user defined variables in MySQL through PHP - the answer by Multifarious has pointed me in this direction Currently I have a script to cycle over 10M records, it's very slow and it goes like this: I first get a block of 1000 results in an array similar to this: $matches[] = array('quality_rank'=>46732, 'db_id'=>5532); $matches[] = array('quality_rank'=>12324, 'db_id'=>1234); $matches[] = array('quality_rank'=>45235, 'db_id'=>8345); $matches[] = array('quality_rank'=>75543, 'db_id'=>2562); I then cycle through them one by one and update the record $mult = count($matches)*2; foreach($matches as $m) { $rank++; $score = (($m[quality_rank] + $rank)/($mult))*100; $s = "UPDATE `packages_sorted` SET `price_rank` = '".$rank."', `deal_score` = '".$score."' WHERE `db_id` = '".$m[db_id]."' LIMIT 1"; } It seems like this is a very slow way of doing it but I can't find another way to increment the field price_rank by one each time. Can anyone suggest a better method. Note: Although I wouldn't usually store this kind of value in a database I really do need on this occasion for comparison search queries later on in the project. Any help would be kindly appreciated :)

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  • For business people to manage, keep binary images in MySQL or just the urls?

    - by Michael Mao
    Hello everyone: I am working on a task to enable image uploading and auto-scaling(from full sized to thumbnail) by jQuery & PHP. I can naturally come up with two approaches : First, store both images as binary objects directly into MySQL; Second, store only urls to the images and keep the images somewhere on server. The images are for everyone to view, so there are no security restrictions, as far as I know. Personally I don't have any preference, however, at the end of the day, it is the business people that are going to manage the images as part of the system(CRUD). So I am wondering which seems to be a bit better for them? Of course I am building a easy-to-use, visualize web interface for the staff to control the process, but I am not sure if that is enough. Lessons told me that if I don't think for the future and seek the most flexible approach, the I will probably screw myself sooner or later. PS. The following link is what I've found so far, which is pretty cool, no flash involved :) Andrew Valum's ajax image upload jQuery plugin

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  • Extend DOMElement object

    - by Comma
    How could I exdend objects provided with Document Object Model? Seems that there is no way according to this [issue][2]. class Application_Model_XmlSchema extends DOMElement { const ELEMENT_NAME = 'schema'; /** * @var DOMElement */ private $_schema; /** * @param DOMDocument $document * @return void */ public function __construct(DOMDocument $document) { $this->setSchema($document->getElementsByTagName(self::ELEMENT_NAME)->item(0)); } /** * @param DOMElement $schema * @return void */ public function setSchema(DOMElement $schema){ $this->_schema = $schema; } /** * @return DOMElement */ public function getSchema(){ return $this->_schema; } /** * @param string $name * @param array $arguments * @return mixed */ public function __call($name, $arguments) { if (method_exists($this->_schema, $name)) { return call_user_func_array( array($this->_schema, $name), $arguments ); } } } $version = $this->getRequest()->getParam('version', null); $encoding = $this->getRequest()->getParam('encoding', null); $source = 'http://www.w3.org/2001/XMLSchema.xsd'; $document = new DOMDocument($version, $encoding); $document->load($source); $xmlSchema = new Application_Model_XmlSchema($document); $xmlSchema->getAttribute('version'); I got an error: Warning: DOMElement::getAttribute(): Couldn't fetch Application_Model_XmlSchema in C:\Nevermind.php on line newvermind

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  • How to do word wrapping.

    - by Talha Bin Shakir
    Hi, I have created a table in PHP but the cells size is not fixed it expends when the input is long. Here is the Code. echo "<div style=\"overflow-y: scroll; white-space: nowrap; height: 190px;\">\n"; echo "<table cellspacing=\"1\" cellpadding=\"1\" align=\"center\" width=\"100%\" id=\"clients\">\n"; echo "<tr bgcolor=\"2b2d5d\">\n"; echo "<th align=\"left\" style=\"color: FFFFFF; font-size: 12px; font-weight: normal; font-family: Arial; padding: 5\">&nbsp;</th>\n"; echo "<th align=\"left\" style=\"color: FFFFFF; font-size: 12px; font-weight: normal; font-family: Arial; padding: 5\">Name</th>\n"; echo "<th align=\"left\" style=\"color: FFFFFF; font-size: 12px; font-weight: normal; font-family: Arial; padding: 5\">Address</th>\n"; echo "<th align=\"left\" style=\"color: FFFFFF; font-size: 12px; font-weight: normal; font-family: Arial; padding: 5\">Phone</th>\n"; echo "<th align=\"left\" style=\"color: FFFFFF; font-size: 12px; font-weight: normal; font-family: Arial; padding: 5\">Fax</th>\n"; I want to fixed the cells width please need help. Thanks

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  • How can I send GET data to multiple URLs at the same time using cURL?

    - by Rob
    My apologies, I've actually asked this question multiple times, but never quite understood the answers. Here is my current code: while($resultSet = mysql_fetch_array($SQL)){ $ch = curl_init($resultSet['url'] . $fullcurl); //load the urls and send GET data curl_setopt($ch, CURLOPT_TIMEOUT, 2); //Only load it for two seconds (Long enough to send the data) curl_exec($ch); //Execute the cURL curl_close($ch); //Close it off } //end while loop What I'm doing here, is taking URLs from a MySQL Database ($resultSet['url']), appending some extra variables to it, just some GET data ($fullcurl), and simply requesting the pages. This starts the script running on those pages, and that's all that this script needs to do, is start those scripts. It doesn't need to return any output. Just the load the page long enough for the script to start. However, currently it's loading each URL (currently 11) one at a time. I need to load all of them simultaneously. I understand I need to use curl_multi_*, but I haven't the slightest idea on how cURL functions work, so I don't know how to change my code to use curl_multi_* in a while loop. So my questions are: How can I change this code to load all of the URLs simultaneously? Please explain it and not just give me code. I want to know what each individual function does exactly. Will curl_multi_exec even work in a while loop, since the while loop is just sending each row one at a time? And of course, any references, guides, tutorials about cURL functions would be nice, as well. Preferably not so much from php.net, as while it does a good job of giving me the syntax, its just a little dry and not so good with the explanations.

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  • Create Dynamically table at runtime & save it in database

    - by user1548245
    I have written a code for creating table. It displays table structure on GUI form, but what I want is, when I enter values into table it should be stored in database table too. My code: <?php function display($column,$rows) { echo "<table border='1' align='center'>"; for ($iii = 0;$iii <$_POST['column'];$iii++) { echo "<tr>".$jjj."</tr>"; //display no. of <tr> for ($jjj = 0; $jjj <$_POST['rows'];$jjj++) { echo "<td>" ."<input type=\"text\" name='$iii'>"."</td>"; } } echo "</table>"; } ?>

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