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  • Undefined Variable? But I defined it...

    - by Rob
    Well before anyone claims that theres a duplicate question... (I've noticed that people who can't answer the question tend to run and look for a duplicate, and then report it.) Here is the duplicate you are looking for: http://stackoverflow.com/questions/2481382/php-claims-my-defined-variable-is-undefined However, this isn't quite a duplicate. It gives me a solution, but I'm not really looking for this particular solution. Here is my problem: Notice: Undefined variable: custom Now here is my code: $headers = apache_request_headers(); // Request the visitor's headers. $customheader = "Header: 7ddb6ffab28bb675215a7d6e31cfc759"; //This is what the header should be. foreach ($headers as $header => $value) { $custom .= "$header: $value"; } Clearly, $custom is defined. According to the other question, it's a global and should be marked as one. But how is it a global? And how can I make it a (non-global)? The script works fine, it still displays what its supposed to and acts correctly, but when I turn on error messages, it simply outputs that notice as well. I suppose its not currently necessary to fix it, but I'd like to anyway, as well as know why its doing this.

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  • Taking wrong database configuration array

    - by user309076
    Hi, I have one application in which i have used 2 database connections. In my database config file i have given two arrays as below. $active_group = ‘default’; $active_record = TRUE; FIRST ARRAY $db[‘default’][‘hostname’] = ‘hostname’; .............. .......... SECOND ARRAY $db[‘another_db’][‘hostname’] = ‘hostname’; .............. .......... this is working fine. Now, I copied the entire CI folder to develop another application in which only one database connection needed. So, now, in the database config file, i deleted the second configuration array. But, the db class is taking first application’s second array i.e. “another_db” and it is giving the below error. “You have specified an invalid database connection group.” When i change the default (only one) array name to “another_db” in configuration file. It is working fine. Can’t understand from where it is taking the group name as “another_db”. My application autoloads database library. I have debugged the ci_auto_loader in Loader.php class where it calls $this-database() function with no parameters. But in function database($params, $, $) {}, if I echo $params it shows “another_db”.

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  • Sample twitter App

    - by Jack
    I am now running my code on a web hosting service http://xtreemhost.com/ <?php function updateTwitter($status) { $username = 'xxxxxx'; $password = 'xxxx'; $url = 'http://twitter.com/statuses/update.xml'; $postargs = 'status='.urlencode($status); $responseInfo=array(); $ch = curl_init($url); curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 2); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt ($ch, CURLOPT_POST, true); // Give CURL the arguments in the POST curl_setopt ($ch, CURLOPT_POSTFIELDS, $postargs); // Set the username and password in the CURL call curl_setopt($ch, CURLOPT_USERPWD, $username.':'.$password); // Set some cur flags (not too important) $response = curl_exec($ch); if($response === false) { echo 'Curl error: ' . curl_error($ch); } else { echo 'Operation completed without any errors<br/>'; } // Get information about the response $responseInfo=curl_getinfo($ch); // Close the CURL connection curl_close($ch); // Make sure we received a response from Twitter if(intval($responseInfo['http_code'])==200){ // Display the response from Twitter echo $response; }else{ // Something went wrong echo "Error: " . $responseInfo['http_code']; } curl_close($ch); } updateTwitter("Just finished a sweet tutorial on http://brandontreb.com"); ?> I get the following error now Curl error: Couldn't resolve host 'api.twitter.com' Error: 0 Please somebody solve my problem

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  • unicode convertion problem

    - by bhoomi-nature
    Hai frnds i am bhoomi new to php,i am having having below problem in my coding please can you help anyone 1.first i want to open one word document which is having content and i wann to edit it 2.for that i am opening word document from the server and at that time its opening with garbage value(i thing its not converting to utf8 format) 3.wen i delete that garbage value and insert something from textarea to that file it is going to insert and next time onwords its its getting open properly. 4.actually i wann that doc file should open with english words wats there in that doc instead of garbage value..first time opening only its giving problem. i am using below code for that please do the needful $filename = 'test.doc'; if(isset($_REQUEST['Submit'])){ $somecontent = stripslashes($_POST['somecontent']); // Let's make sure the file exists and is writable first. if (is_writable($filename)) { // In our example we're opening $filename in append mode. // The file pointer is at the bottom of the file hence // that's where $somecontent will go when we fwrite() it. if (!$handle = fopen($filename, 'w')) { echo "Cannot open file ($filename)"; exit; } // Write $somecontent to our opened file. if (fwrite($handle, $somecontent) === FALSE) { echo "Cannot write to file ($filename)"; exit; } echo "Success, wrote ($somecontent) to file ($filename) - Continue - "; fclose($handle); } else { echo "The file $filename is not writable"; } } else{ // get contents of a file into a string $handle = fopen($filename, 'r'); $somecontent = fread($handle, filesize($filename)); ? Edit file

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  • How to search within an xml data set?

    - by user187580
    Hi, I have some xml data and I am trying to keyword search data. For example, if I search "some" for the following data it returns me the <id> and <title>. <resource> <id>101</id> <title>Test Environment</title> <description><b>Some</b> description. </description> <type>classroom</type> </resource> <resource> <id>102</id> <title>ABC Test Environment</title> <description><b>Some</b> another description. </description> <type>classroom</type> </resource> ... I had a look on on xpath e.g. $xml->xpath('//title') but looks for elements only. Basically what I need to do is to create a functionality where users can keyword search within the above data set which I receive from third party api in the above format. Any ideas how I can achieve this? using PHP/ Javascript etc. Thanks.

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  • Is it possible to limit outside connections to a subdomain with .htaccess or similar?

    - by digidave0205
    I host a web application. This application serves static html pages that are refreshed at various intervals. Some as often as every 30 secs. At this time I have about 300 unique pages that are accessed via 300 unique subdomains. Some clients have at most 50 visitors to their unique page and it refreshes every 30 secs, no problem. Other clients have up to 1000 or more visitors to their page. These clients are killing my server. There was no predefined limit upon signup but now I have to impose such a limit to remain afloat financially. I would like to define a finite number of connections allowed for each individual subdomain in my hosting account. Connections attempted out of range of this finite value would either be rejected or redirected. I have access to .htaccess and php.ini. Is something of this nature possible? Oh, I have a dedicated/managed server at 1and1.

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  • Converting json data to an HTML table

    - by dnaluz
    I have an array of data in php and I need to display this data in a HTML table. Here is what an example data set looks like. Array( Array ( [comparisonFeatureId] => 1182 [comparisonFeatureType] => Category [comparisonValues] => Array ( [0] => Not Available [1] => Standard [2] => Not Available [3] => Not Available ) [featureDescription] => Rear Seat Heat Ducts ),) The dataset is a comparison of 3 items (shown in the comparisonValues index of the array) In the end I need the row to look similar to this <tr class="alt2 section_1"> <td><strong>$record['featureDescription']</strong></td> <td>$record['comparisonValues'][0]</td> <td>$record['comparisonValues'][1]</td> <td>$record['comparisonValues'][2]</td> <td>$record['comparisonValues'][3]</td> </tr> The problem I am coming across is how to best do this. Should I create the entire table HTML on the server side pass it over an ajax call and just dump pre-rendered HTML data into a div or pass the json data and render the table client side. Any elegant suggestions? Thanks in advanced.

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  • [Concept] How does unlink() find the file to delete?

    - by Prasad
    My app has a 'Photo' field to store URL. It uses sfWidgetFormInputFileEditable for the widget schema. To delete the old image when a new image is uploaded, I use unlink before setting the value in the over-ridden setter and it works!!! if (file_exists($this->_get('photo'))) unlink($this->_get('photo')); Photos are stored in uploads/photos and when saving 'Photo' only the file name xxx-yyy.zzz is saved (and not the full path). However, I wish to know how symfony/php knows the full path of the file to be deleted? Part 2: I am using sfThumbnailPlugin to generate thumbnails. So the actual code looks like this: public function setPhoto($value) { if(!empty($value)) { Contact::generateThumbnail($value); // delete current Photo & create thumbnail $this->_set('photo',$value); // setting new value after deleting old one } } public function generateThumbnail($value) { $uploadDir = sfConfig::get('app_photo_upload'); // path to upload folder if (file_exists($this->_get('photo'))) { unlink($this->_get('photo')); // delete full-size image // path to thumbnail $thumbpath = $uploadDir.'/thumbnails/'.$this->get('photo'); // read a blog, tried setting dir manually, doesn't work :( //chdir('/thumbnails/'); // tried closing the file too, doesn't work! :( //fclose($thumbpath) or die("can't close file"); //unlink($this->_get('photo')); // doesn't work; no error :( unlink($thumbpath); // doesn't work, no error :( } $thumbnail = new sfThumbnail(150, 150); $thumbnail->loadFile($uploadDir.'/'.$value); $thumbnail->save($uploadDir.'/thumbnails/'.$value, 'image/png'); } Why can't the thumbnail be deleted using unlink()? is the sequence of ops incorrect? Is it because the old thumbnail is displayed in the sfWidgetFormInputFileEditable widget? I've spent hours trying to figure this out, but unable to nail down the real cause. Thanks in advance.

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  • Problem with using Jquery.ajax over .load on Zend

    - by Matthew
    Right now, what i'm trying to do is to replace a label on the front page with a block of html. Right now, the page basically has: <label id="replace"></label> the js currently has: $(document).ready(function(){ $("#replace").load('/test'); }); the Zend class function has: public function indexAction(){ $this->_helper->layout()->disableLayout(); $this->_view->message = "This is from TestController index"; } and finally the index.phtml template simply has: <?php echo $this->message;?> Right now, I want to change the code around so that instead of just replacing that label with the same message, it would do a POST where the function will pull out a parameter, do something (like for instance, go to the database and pull something out with the POST parameter) and then return the message. I've tried editing the js so that it would look like: $.post('/test', {param : "test_param"}, function(data) {$("#replace").html(data);}); or $.ajax({ type: 'POST', url: '/test', data: "{param:test_param}", contentType: "application/json; charset=utf-8", dataType: "json", success: function(data) {$("#replace").html(data);} }); and neither worked. I took a step back and tried to replicate the .load functionality and do: $.ajax({ url: '/test', success: function(data) { $('#replace').html(data); alert('Load was performed.'); } }); and it doesn't work either. Anyone have any tips on how to go about doing this?

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  • Logging in with sha1() encryption.

    - by Samir Ghobril
    Hey guys, I added this to my sign up code : $password=mysql_real_escape_string(sha1($_POST['password'])); and now it inserts the password into the database while its encrypted. But signing in doesn't seem to work anymore. Here is the login code. function checklogin($username, $password){ global $mysqli; $password=sha1($password); $result = $mysqli->prepare("SELECT * FROM users WHERE username = ? and password=?"); $result->bind_param("ss", $username, $password); $result->execute(); if($result != false){ $dbArray=$result->fetch(); if(!$dbArray){ echo '<p class="statusmsg">The username or password you entered is incorrect, or you haven\'t yet activated your account. Please try again.</p><br/><input class="submitButton" type="button" value="Retry" onClick="location.href='."'login.php'\">"; return; } $_SESSION['username']=$username; if(isset($_POST['remember'])){ setcookie("jmuser",$username,time()+60*60*24*356); setcookie("jmpass",$password ,time()+60*60*24*356); } redirect(); }

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  • MySQL COUNT() total posts within a specific criteria?

    - by newbtophp
    Hey, I've been losing my hair trying to figure out what I'm doing wrong, let me explain abit about my MySQL structure (so you get a better understanding) before I go straight to the question. I have a simple PHP forum and I have a column in both tables (for posts and topics) named 'deleted' if it equals 0 that means its displayed (considered not deleted/exists) or if it equals 1 it hidden (considered deleted/doesn't exist) - bool/lean. Now, the 'specific criteria' I'm on about...I'm wanting to get a total post count within a specific forum using its id (forum_id), ensuring it only counts posts which are not deleted (deleted = 0) and their parent topics are not deleted either (deleted = 0). The column/table names are self explanatory (see my efforts below for them - if needed). I've tried the following (using a 'simple' JOIN): SELECT COUNT(t1.post_id) FROM forum_posts AS t1, forum_topics AS t2 WHERE t1.forum_id = '{$forum_id}' AND t1.deleted = 0 AND t1.topic_id = t2.topic_id AND t2.deleted = 0 LIMIT 1 I've also tried this (using a Subquery): SELECT COUNT(t1.post_id) FROM forum_posts AS t1 WHERE t1.forum_id = '{$forum_id}' AND t1.deleted = 0 AND (SELECT deleted FROM forum_topics WHERE topic_id = t1.topic_id) = 0 LIMIT 1 But both don't comply with the specific criteria. Appreciate all help! :)

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  • jQuery not working as expected on HTTPS Internet explorer

    - by jat
    When I try to run my code on any other webbrowsers apart from the Internet explorer it works fine. But when I try to run the code on Internet explorer I do get an alert box saying HERE along with an Ok button. but the problem is when I click on that OK button I do not get anything. Ideally I should be getting another alert box. <!DOCTYPE html> <html> <head> <script src="js/jquery-1.4.2.min.js"></script> <script type="text/javascript"> $(document).ready(function(){ $("#submit").click(function(event) { alert("here"); $.post('process.php', {name:'test1',email:'test.com'}, function(data) { $('#results').html(data); alert(data); }); }); }); </script> </head> <body> <form name="myform" id="myform" action="" method="POST"> <label for="name" id="name_label">Name</label> <input type="text" name="name" id="name" size="30" value=""/> <br> <label for="email" id="email_label">Email</label> <input type="text" name="email" id="email" size="30" value=""/> <br> <input type="button" name="submit" id="submit" value="Submit"> </form> <div id="results"><div> </body> </html> Any help on this is very much appreciated. Edit: I found out that Internet Explorer which has HTTP works perfectly fine but not on Internet Explorer which uses HTTPS.

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  • why my image and first name disappears in this code?

    - by udaya
    Hi This is my foreach function <? foreach($Selected as $row) $value = $row['dPath']; $imgp = base_url()."images"."/".$value; {?> <td> <?=$row['dFrindName'].'</br>';?> <?php */?> <img src="<?=$imgp ?>" name="b1" width="90" height="80" border="0"/> </td> <? }}?> Print_r($Selected); results in `Array ( [0] => Array ( [dFrindName] => chandruCP [dPath] => m11on.gif ) [1] => Array ( [dFrindName] => udaya [dPath] => logo.jpg ) )` but only my last value of the array is displayed on image I can get the name udaya and logo.jpg on the screen But i cant get chandruCP and m11on.gif why it is so how can i get all the values and image on scrren

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  • Link my tag on other website search

    - by kresna kurdang
    This is my search code <div id="search"> <form method="get" action="http://www.other-website.com/search"> <input type="hidden" name="f" value=""> <input type="text" placeholder="Temukan informasi, komunitas & produk yang kamu cari disini" accesskey="s" name="q"> <input type="submit" value="Search"> </form> </div> This is the tag code (display only text "do not link") <?php $posttags = get_the_tags(); if ($posttags) { foreach($posttags as $tag) { echo $tag->name . ' '; } } ?> The code can apply well on the website, but I have to enter text to the search. I just want to place my tag on that search text so my question is How to make fixed word(my tag) automatically placed on search or where I must place the tag code, the search result is mytag linked on @www.other-website.com/search so user do not have to type? I want to search my tag on other website search

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  • Is a server side script necessary to process a form?

    - by jitendra
    Is a server side script necessary to send a form to email? For example, suppose I want to submit this form. Is it only possible with php asp.net etc. or it can be done with javascript only? <HTML> <HEAD> <TITLE>HTML form tutorial example</TITLE> </HEAD> <BODY> <H1>HTML form tutorial example</H1> <FORM> Name: <INPUT TYPE="TEXT" NAME="Name" VALUE="" SIZE="25" MAXLENGTH="50"> <BR> Email: <INPUT TYPE="TEXT" NAME="Email" VALUE="" SIZE="25" MAXLENGTH="50"><BR> <INPUT TYPE="SUBMIT" NAME="submit" VALUE="Sign Me Up!"> </FORM> </BODY> </HTML>

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  • How to open a file and remove the last line?

    - by sologhost
    I am looking to open up a file, grab the last line in the file where the line = "?", which is the closing tag for a php document. Than I am wanting to append data into it and add back in the "?" to the very last line. I've been trying a few approaches, but I'm not having any luck. Here's what I got so far, as I am reading from a zip file. Though I know this is all wrong, just needing some help with this please... // Open for reading is all we can do with zips and is all we need. if (zip_entry_open($zipOpen, $zipFile, "r")) { $fstream = zip_entry_read($zipFile, zip_entry_filesize($zipFile)); $fp = fopen($curr_lang_file, 'r+b'); while (!feof($fp)) { $output = fgets($fp, 16384); if (trim($output) == '?>') break; fwrite($fp, $output); } fclose($fp); file_put_contents($curr_lang_file, $fstream, FILE_APPEND); } $curr_lang_file is a filepath string to the actual file that needs to have the fstream appended to it, but after we remove the last line that equals '?'

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  • Which of these methods provides for the fastest page loading?

    - by chromedude
    I am building a database in MySQL that will be accessed by PHP scripts. I have a table that is the activity stream. This includes everything that goes on on the website (following of many different things, liking, upvoting etc.). From this activity stream I am going to run an algorithm for each user depending on their activity and display relevant activity. Should I create another table that stores the activity for each user once the algorithm has been run on the activity or should I run the algorithm on the activity table every time the user accesses the site? UPDATE:(this is what is above except rephrased hopefully in an easier to understand way) I have a database table called activity. This table creates a new row every time an action is performed by a user on the website. Every time a user logs in I am going to run an algorithm on the new rows (since the users last login) in the table (activity) that apply to them. For example if the user is following a user who upvoted a post in the activity stream that post will be displayed when the user logs in. I want the ability for the user to be able to access previous content applying to them. Would it be easiest to create another table that saved the rows that have already been run over with the algorithm except attached to individual users names? (a row can apply to multiple different users)

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  • HELP A NEWB (AGAIN) PLZ

    - by Ken
    Okay, I must be an idiot, because this is my 3rd question for today. Here's my code: date_default_timezone_set("America/Los_Angeles"); include("mainmenu.php"); $con = mysql_connect("localhost", "root", "********"); if(!$con){ die(mysql_error()); } $usrname = $_POST['usrname']; $fname = $_POST['fname']; $lname = $_POST['lname']; $password = $_POST['password']; $email = $_POST['email']; mysql_select_db("`users`, $con) or die(mysql_error()"); $query = ("INSERT INTO `users`.`data` (`id`, `usrname`, `fname`, `lname`, `email`, `password`) VALUES (NULL, '$usrname', '$fname', '$lname', '$email', 'password'))"); mysql_query('$query') or die(mysql_error()); mysql_close($con); echo("Thank you for registering!"); I always get the error returned as: "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '$query' at line 1. Help a newbie. I'm about to stab my monitor.

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  • Send SOAP via curl

    - by danrichardson
    Hi. This has been bugging me for days, i'm trying to send a SOAP post via curl but i just keep getting a 'couldn't connect to host' error but i really cant see how. I have an asp version which works fine with the same url and data, i think it's just a php/curl thing...? I currently have the following code (the CURLOPT_POSTFIELDS data is a valid soap envelope string) $soap_do = curl_init(); curl_setopt($soap_do, CURLOPT_URL, "https://xxx.yyy.com:517/zzz.asmx" ); curl_setopt($soap_do, CURLOPT_CONNECTTIMEOUT, 10); curl_setopt($soap_do, CURLOPT_TIMEOUT, 10); curl_setopt($soap_do, CURLOPT_RETURNTRANSFER, true ); curl_setopt($soap_do, CURLOPT_SSL_VERIFYPEER, false); curl_setopt($soap_do, CURLOPT_SSL_VERIFYHOST, false); curl_setopt($soap_do, CURLOPT_POST, true ); curl_setopt($soap_do, CURLOPT_POSTFIELDS, '<soap:Envelope>...</soap:Envelope>'); curl_setopt($soap_do, CURLOPT_HTTPHEADER, array('Content-Type: text/xml; charset=utf-8', 'Content-Length: '.strlen('<soap:Envelope>...</soap:Envelope>') )); if(curl_exec($soap_do) === false) { $err = 'Curl error: ' . curl_error($soap_do); curl_close($soap_do); return $err; } else { curl_close($soap_do); return 'Operation completed without any errors'; } So any ideas why it just errors all the time? The asp version works fine! The code is; Set xmlhttp = server.Createobject("MSXML2.ServerXMLHTTP") xmlhttp.Open "POST","https://xxx.yyy.com:517/zzz.asmx" xmlhttp.setRequestHeader "Content-Type", "text/xml; charset=utf-8" xmlhttp.Send('<soap:Envelope>...</soap:Envelope>')

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  • syntax for MySQL INSERT with an array of columns

    - by Mike_Laird
    I'm new to PHP and MySQL query construction. I have a processor for a large form. A few fields are required, most fields are user optional. In my case, the HTML ids and the MySQL column names are identical. I've found tutorials about using arrays to convert $_POST into the fields and values for INSERT INTO, but I can't get them working - after many hours. I've stepped back to make a very simple INSERT using arrays and variables, but I'm still stumped. The following line works and INSERTs 5 items into a database with over 100 columns. The first 4 items are strings, the 5th item, monthlyRental is an integer. $query = "INSERT INTO `$table` (country, stateProvince, city3, city3Geocode, monthlyRental) VALUES ( '$country', '$stateProvince', '$city3', '$city3Geocode', '$monthlyRental')"; When I make an array for the fields and use it, as follows: $colsx = array('country,', 'stateProvince,', 'city3,', 'city3Geocode,', 'monthlyRental'); $query = "INSERT INTO `$table` ('$colsx') VALUES ( '$country', '$stateProvince', '$city3', '$city3Geocode', '$monthlyRental')"; I get a MySQL error - check the manual that corresponds to your MySQL server version for the right syntax to use near ''Array') VALUES ( 'US', 'New York', 'Fairport, Monroe County, New York', '(43.09)' at line 1. I get this error whether the array items have commas inside the single quotes or not. I've done a lot of reading and tried many combinations and I can't get it. I want to see the proper syntax on a small scale before I go back to foreach expressions to process $_POST and both the fields and values are arrays. And yes, I know I should use mysql_real_escape_string, but that is an easy later step in the foreach. Lastly, some clues about the syntax for an array of values would be helpful, particularly if it is different from the fields array. I know I need to add a null as the first array item to trigger the MySQL autoincrement id. What else? I'm pretty new, so please be specific.

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  • formmail to email in database

    - by aarontb
    Here's what I need to setup...and I am not well versed in PHP/SQL...but this is what I'm trying to do. On the New User database, I will have a section where they can have information sent to their phone using the provider's default e-mail to text msg (i.e. [email protected].) New User: Input number: ______________(2225551212 format, no hyphens, etc.) Select Provider: (Drop-down menu with proper @provider.ext...) Then the formmail, when sent, if for specific user will get ($phone".@."$provider); or something like that and send a preset message like: $user."requested information on ".$product."on".$date." at ".$time."."; Is this possible? The $user, $product, $date, $time all are generated directly from the most recent input page for a database. Is this possible? Please help!

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  • md5_file() not working with IP addresses?

    - by Rob
    Here is my code relating to the question: $theurl = trim($_POST['url']); $md5file = md5_file($theurl); if ($md5file != '96a0cec80eb773687ca28840ecc67ca1') { echo 'Hash doesn\'t match. Incorrect file. Reupload it and try again'; When I run this script, it doesn't even output an error. It just stops. It loads for a bit, and then it just stops. Further down the script I implement it again, and it fails here, too: while($row=mysql_fetch_array($execquery, MYSQL_ASSOC)){ $hash = @md5_file($row['url']); $url = $row['url']; mysql_query("UPDATE urls SET hash='" . $hash . "' WHERE url='" . $url . "'") or die("MYSQL is indeed gay: ".mysql_error()); if ($hash != '96a0cec80eb773687ca28840ecc67ca1'){ $status = 'down'; }else{ $status = 'up'; } mysql_query("UPDATE urls SET status='" . $status . "' WHERE url='" . $url . "'") or die("MYSQL is indeed gay: ".mysql_error()); } And it checks all the URL's just fine, until it gets to one with an IP instead of a domain, such as: http://188.72.215.195/config.php In which, again, the script then just loads for a bit, and then stops. Any help would be much appreciated, if you need any more information just ask.

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  • Good Hosting Providers With Zend Framework Support

    - by manyxcxi
    I currently use ixwebhosting for my hosting services. They're cheap and work (most of the time). The databases are horribly slow, the servers are horribly slow, and their support (though usually prompt) is tough to deal with. That being said, they're cheap, I've got like 20 domains hosted in my account, none of them are high volume, and they work JUST good enough- until today. This isn't meant to be a condemnation of ixwh though. Their prices are very low for what they do offer and most things work just fine, most of the time. I need to be able to host web apps written with Zend Framework in a fairly easy fashion. The server performance can't be worse than what I've already had (a pretty low hurdle to clear), and I don't want to spend $30/mo. These are not money making websites- they're projects. My requirements are PHP 5.3, ZF support, MySQL databases, multiple domains- not much. Who should I look at, and who should I look out for? Also- I put this on SO instead of SF because of the Zend Framework specific requirement. If I'm wrong, do as you wish.

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  • Password protect user image album

    - by Poland Rocks
    Hi Im making i photo sharint site I want to give the ability for my users to prevent the public to acces their albums with a password. Then they can give the password to the ones they want to be able to see it. To password protect their albums. Im thinking something like this, cant test it on this computer, should work ok. but as im a php/mysql beginner i wanna hear what you experts think if theres a better way/approach Albums id name owner password (if it isnt null the album is considered password protected) The code $id = isset($_GET['albumID']) ? intval($_GET['albumID']) : 0; $result = mysql_query("SELECT * FROM albums WHERE id = $id"); $row = mysql_fetch_object($result); // IS it password protected? if ($row->password != NULL) { echo "This album is password protected."; // User pressed "Enter" if (!empty($_POST['password'])) { $result = mysql_query("SELECT password FROM albums WHERE password = '".mysql_real_escape_string($_POST['password'])."'"); // Was It right password? if (mysql_num_rows($result) == 1) { $authed=1; } echo << <form method="post"> <input type="text" name="password" /> EOT; exit; } else $authed=1; if $authed==1 { // render albumimages etc }

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  • Zend Framework - How do make a hierarchy without it being a module?

    - by Josh
    Here is my specific issue. I want to make an api level which then under that you can select which method you will use. For example: test.com/api/rest test.com/api/xmlprc Currently I have api mapping to a module directory. I then setup a route to make it a rest route. test.com/api is a rest route, but I would rather have it be test.com/api/rest. This would allow me later to add others. In Bootstrap.php: $front = Zend_Controller_Front::getInstance(); $router = $front->getRouter(); $route = new Zend_Controller_Router_Route( 'api/:module/:controller/:id/*', array('module' =>'default') ); $router-addRoute('api', $route); $restRoute = new Zend_Rest_Route($front, array(), array( 'rest' )); $router-addRoute('rest', $restRoute); return $router; In application.ini: resources.frontController.moduleDirectory = APPLICATION_PATH "/modules" I know it will involve routes, but sometimes I find the Zend Framework documentation to be a little hard to follow. When I go to test.com/rest/controller/ it works how it should, but if I go to test.com/api/rest/ it tells me that my module is api and controller is rest.

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