Search Results

Search found 36719 results on 1469 pages for 'value chain'.

Page 665/1469 | < Previous Page | 661 662 663 664 665 666 667 668 669 670 671 672  | Next Page >

  • SortedDictionary and SortedList

    - by Simon Cooper
    Apart from Dictionary<TKey, TValue>, there's two other dictionaries in the BCL - SortedDictionary<TKey, TValue> and SortedList<TKey, TValue>. On the face of it, these two classes do the same thing - provide an IDictionary<TKey, TValue> interface where the iterator returns the items sorted by the key. So what's the difference between them, and when should you use one rather than the other? (as in my previous post, I'll assume you have some basic algorithm & datastructure knowledge) SortedDictionary We'll first cover SortedDictionary. This is implemented as a special sort of binary tree called a red-black tree. Essentially, it's a binary tree that uses various constraints on how the nodes of the tree can be arranged to ensure the tree is always roughly balanced (for more gory algorithmical details, see the wikipedia link above). What I'm concerned about in this post is how the .NET SortedDictionary is actually implemented. In .NET 4, behind the scenes, the actual implementation of the tree is delegated to a SortedSet<KeyValuePair<TKey, TValue>>. One example tree might look like this: Each node in the above tree is stored as a separate SortedSet<T>.Node object (remember, in a SortedDictionary, T is instantiated to KeyValuePair<TKey, TValue>): class Node { public bool IsRed; public T Item; public SortedSet<T>.Node Left; public SortedSet<T>.Node Right; } The SortedSet only stores a reference to the root node; all the data in the tree is accessed by traversing the Left and Right node references until you reach the node you're looking for. Each individual node can be physically stored anywhere in memory; what's important is the relationship between the nodes. This is also why there is no constructor to SortedDictionary or SortedSet that takes an integer representing the capacity; there are no internal arrays that need to be created and resized. This may seen trivial, but it's an important distinction between SortedDictionary and SortedList that I'll cover later on. And that's pretty much it; it's a standard red-black tree. Plenty of webpages and datastructure books cover the algorithms behind the tree itself far better than I could. What's interesting is the comparions between SortedDictionary and SortedList, which I'll cover at the end. As a side point, SortedDictionary has existed in the BCL ever since .NET 2. That means that, all through .NET 2, 3, and 3.5, there has been a bona-fide sorted set class in the BCL (called TreeSet). However, it was internal, so it couldn't be used outside System.dll. Only in .NET 4 was this class exposed as SortedSet. SortedList Whereas SortedDictionary didn't use any backing arrays, SortedList does. It is implemented just as the name suggests; two arrays, one containing the keys, and one the values (I've just used random letters for the values): The items in the keys array are always guarenteed to be stored in sorted order, and the value corresponding to each key is stored in the same index as the key in the values array. In this example, the value for key item 5 is 'z', and for key item 8 is 'm'. Whenever an item is inserted or removed from the SortedList, a binary search is run on the keys array to find the correct index, then all the items in the arrays are shifted to accomodate the new or removed item. For example, if the key 3 was removed, a binary search would be run to find the array index the item was at, then everything above that index would be moved down by one: and then if the key/value pair {7, 'f'} was added, a binary search would be run on the keys to find the index to insert the new item, and everything above that index would be moved up to accomodate the new item: If another item was then added, both arrays would be resized (to a length of 10) before the new item was added to the arrays. As you can see, any insertions or removals in the middle of the list require a proportion of the array contents to be moved; an O(n) operation. However, if the insertion or removal is at the end of the array (ie the largest key), then it's only O(log n); the cost of the binary search to determine it does actually need to be added to the end (excluding the occasional O(n) cost of resizing the arrays to fit more items). As a side effect of using backing arrays, SortedList offers IList Keys and Values views that simply use the backing keys or values arrays, as well as various methods utilising the array index of stored items, which SortedDictionary does not (and cannot) offer. The Comparison So, when should you use one and not the other? Well, here's the important differences: Memory usage SortedDictionary and SortedList have got very different memory profiles. SortedDictionary... has a memory overhead of one object instance, a bool, and two references per item. On 64-bit systems, this adds up to ~40 bytes, not including the stored item and the reference to it from the Node object. stores the items in separate objects that can be spread all over the heap. This helps to keep memory fragmentation low, as the individual node objects can be allocated wherever there's a spare 60 bytes. In contrast, SortedList... has no additional overhead per item (only the reference to it in the array entries), however the backing arrays can be significantly larger than you need; every time the arrays are resized they double in size. That means that if you add 513 items to a SortedList, the backing arrays will each have a length of 1024. To conteract this, the TrimExcess method resizes the arrays back down to the actual size needed, or you can simply assign list.Capacity = list.Count. stores its items in a continuous block in memory. If the list stores thousands of items, this can cause significant problems with Large Object Heap memory fragmentation as the array resizes, which SortedDictionary doesn't have. Performance Operations on a SortedDictionary always have O(log n) performance, regardless of where in the collection you're adding or removing items. In contrast, SortedList has O(n) performance when you're altering the middle of the collection. If you're adding or removing from the end (ie the largest item), then performance is O(log n), same as SortedDictionary (in practice, it will likely be slightly faster, due to the array items all being in the same area in memory, also called locality of reference). So, when should you use one and not the other? As always with these sort of things, there are no hard-and-fast rules. But generally, if you: need to access items using their index within the collection are populating the dictionary all at once from sorted data aren't adding or removing keys once it's populated then use a SortedList. But if you: don't know how many items are going to be in the dictionary are populating the dictionary from random, unsorted data are adding & removing items randomly then use a SortedDictionary. The default (again, there's no definite rules on these sort of things!) should be to use SortedDictionary, unless there's a good reason to use SortedList, due to the bad performance of SortedList when altering the middle of the collection.

    Read the article

  • How does a programmer who doesn't know how to program get a job ? [closed]

    - by A programmer
    I often read about this and I'm curious: if there programmers who can't program, how did they get a programming job in the first place? They must bring some value to the company they're working for, otherwise they would be fired. I don't think "programmers who don't know how to program" means "bad programmers" in this case ? Even if they are bad programmers, they still know (badly) how to write (bad) programs. So what defines programmers who can't program ?

    Read the article

  • Partner Webcast – More out of ODA with DB Options - 19 July 2012

    - by Thanos
    The Simple, Reliable, Affordable Path to High-Availability Databases Critical business data needs to be available 24/7 for users and customers, but it can be a struggle to find the time and resources to build a highly available database system that’s reliable and affordable. That’s why Oracle created the new Oracle Database Appliance—a complete package of software, server, storage, and networking. The Oracle Database Appliance integrates the world’s most popular database - Oracle Database 11g  - with system software, servers, storage and networking in a single box. Business gets the benefit of a reliable, secure and highly available database to support applications and maintain continuity – as well as groundbreaking ease of use. But that is not all, with the support for all Oracle Database Options, Oracle Database Appliance can be the ideal solution for many use cases. The benefits?   Unmatched performance, reliability & security for your data that’s there when you need it – which is all the time. Fast installation, simple deployment, easy management. Out of the box. Significant cost savings & reduced risk and complexity compared to integrating all the elements yourself. Ongoing lower total cost of ownership with multiple automated support, detection & correction functions that also save you time.   Discover the Oracle Database Appliance Value Proposition and learn how to position and combine it with database options to capture new business and easily roll out solutions safely and with maximum cost efficiency. Agenda: Oracle Database& Engineered Systems Innovation. What’s the Oracle Database Appliance ? Oracle Database Appliance Value Proposition. Oracle Database Appliance with Database Options Oracle Database Appliance Partners Business Delivery Format This FREE online LIVE eSeminar will be delivered over the Web. Registrations received less than 24hours prior to start time may not receive confirmation to attend. Duration: 1 hour Register Now! For any questions please contact us at partner.imc-AT-beehiveonline.oracle-DOT-com Visit regularly our ISV Migration Center blog Or Follow us @oracleimc to learn more on Oracle Technologies as well as upcoming partner webcasts and events.

    Read the article

  • Refactoring a Single Rails Model with large methods & long join queries trying to do everything

    - by Kelseydh
    I have a working Ruby on Rails Model that I suspect is inefficient, hard to maintain, and full of unnecessary SQL join queries. I want to optimize and refactor this Model (Quiz.rb) to comply with Rails best practices, but I'm not sure how I should do it. The Rails app is a game that has Missions with many Stages. Users complete Stages by answering Questions that have correct or incorrect Answers. When a User tries to complete a stage by answering questions, the User gets a Quiz entry with many Attempts. Each Attempt records an Answer submitted for that Question within the Stage. A user completes a stage or mission by getting every Attempt correct, and their progress is tracked by adding a new entry to the UserMission & UserStage join tables. All of these features work, but unfortunately the Quiz.rb Model has been twisted to handle almost all of it exclusively. The callbacks began at 'Quiz.rb', and because I wasn't sure how to leave the Quiz Model during a multi-model update, I resorted to using Rails Console to have the @quiz instance variable via self.some_method do all the heavy lifting to retrieve every data value for the game's business logic; resulting in large extended join queries that "dance" all around the Database schema. The Quiz.rb Model that Smells: class Quiz < ActiveRecord::Base belongs_to :user has_many :attempts, dependent: :destroy before_save :check_answer before_save :update_user_mission_and_stage accepts_nested_attributes_for :attempts, :reject_if => lambda { |a| a[:answer_id].blank? }, :allow_destroy => true #Checks every answer within each quiz, adding +1 for each correct answer #within a stage quiz, and -1 for each incorrect answer def check_answer stage_score = 0 self.attempts.each do |attempt| if attempt.answer.correct? == true stage_score += 1 elsif attempt.answer.correct == false stage_score - 1 end end stage_score end def winner return true end def update_user_mission_and_stage ####### #Step 1: Checks if UserMission exists, finds or creates one. #if no UserMission for the current mission exists, creates a new UserMission if self.user_has_mission? == false @user_mission = UserMission.new(user_id: self.user.id, mission_id: self.current_stage.mission_id, available: true) @user_mission.save else @user_mission = self.find_user_mission end ####### #Step 2: Checks if current UserStage exists, stops if true to prevent duplicate entry if self.user_has_stage? @user_mission.save return true else ####### ##Step 3: if step 2 returns false: ##Initiates UserStage creation instructions #checks for winner (winner actions need to be defined) if they complete last stage of last mission for a given orientation if self.passed? && self.is_last_stage? && self.is_last_mission? create_user_stage_and_update_user_mission self.winner #NOTE: The rest are the same, but specify conditions that are available to add badges or other actions upon those conditions occurring: ##if user completes first stage of a mission elsif self.passed? && self.is_first_stage? && self.is_first_mission? create_user_stage_and_update_user_mission #creates user badge for finishing first stage of first mission self.user.add_badge(5) self.user.activity_logs.create(description: "granted first-stage badge", type_event: "badge", value: "first-stage") #If user completes last stage of a given mission, creates a new UserMission elsif self.passed? && self.is_last_stage? && self.is_first_mission? create_user_stage_and_update_user_mission #creates user badge for finishing first mission self.user.add_badge(6) self.user.activity_logs.create(description: "granted first-mission badge", type_event: "badge", value: "first-mission") elsif self.passed? create_user_stage_and_update_user_mission else self.passed? == false return true end end end #Creates a new UserStage record in the database for a successful Quiz question passing def create_user_stage_and_update_user_mission @nu_stage = @user_mission.user_stages.new(user_id: self.user.id, stage_id: self.current_stage.id) @nu_stage.save @user_mission.save self.user.add_points(50) end #Boolean that defines passing a stage as answering every question in that stage correct def passed? self.check_answer >= self.number_of_questions end #Returns the number of questions asked for that stage's quiz def number_of_questions self.attempts.first.answer.question.stage.questions.count end #Returns the current_stage for the Quiz, routing through 1st attempt in that Quiz def current_stage self.attempts.first.answer.question.stage end #Gives back the position of the stage relative to its mission. def stage_position self.attempts.first.answer.question.stage.position end #will find the user_mission for the current user and stage if it exists def find_user_mission self.user.user_missions.find_by_mission_id(self.current_stage.mission_id) end #Returns true if quiz was for the last stage within that mission #helpful for triggering actions related to a user completing a mission def is_last_stage? self.stage_position == self.current_stage.mission.stages.last.position end #Returns true if quiz was for the first stage within that mission #helpful for triggering actions related to a user completing a mission def is_first_stage? self.stage_position == self.current_stage.mission.stages_ordered.first.position end #Returns true if current user has a UserMission for the current stage def user_has_mission? self.user.missions.ids.include?(self.current_stage.mission.id) end #Returns true if current user has a UserStage for the current stage def user_has_stage? self.user.stages.include?(self.current_stage) end #Returns true if current user is on the last mission based on position within a given orientation def is_first_mission? self.user.missions.first.orientation.missions.by_position.first.position == self.current_stage.mission.position end #Returns true if current user is on the first stage & mission of a given orientation def is_last_mission? self.user.missions.first.orientation.missions.by_position.last.position == self.current_stage.mission.position end end My Question Currently my Rails server takes roughly 500ms to 1 sec to process single @quiz.save action. I am confident that the slowness here is due to sloppy code, not bad Database ERD design. What does a better solution look like? And specifically: Should I use join queries to retrieve values like I did here, or is it better to instantiate new objects within the model instead? Or am I missing a better solution? How should update_user_mission_and_stage be refactored to follow best practices? Relevant Code for Reference: quizzes_controller.rb w/ Controller Route Initiating Callback: class QuizzesController < ApplicationController before_action :find_stage_and_mission before_action :find_orientation before_action :find_question def show end def create @user = current_user @quiz = current_user.quizzes.new(quiz_params) if @quiz.save if @quiz.passed? if @mission.next_mission.nil? && @stage.next_stage.nil? redirect_to root_path, notice: "Congratulations, you have finished the last mission!" elsif @stage.next_stage.nil? redirect_to [@mission.next_mission, @mission.first_stage], notice: "Correct! Time for Mission #{@mission.next_mission.position}", info: "Starting next mission" else redirect_to [@mission, @stage.next_stage], notice: "Answer Correct! You passed the stage!" end else redirect_to [@mission, @stage], alert: "You didn't get every question right, please try again." end else redirect_to [@mission, @stage], alert: "Sorry. We were unable to save your answer. Please contact the admministrator." end @questions = @stage.questions.all end private def find_stage_and_mission @stage = Stage.find(params[:stage_id]) @mission = @stage.mission end def find_question @question = @stage.questions.find_by_id params[:id] end def quiz_params params.require(:quiz).permit(:user_id, :attempt_id, {attempts_attributes: [:id, :quiz_id, :answer_id]}) end def find_orientation @orientation = @mission.orientation @missions = @orientation.missions.by_position end end Overview of Relevant ERD Database Relationships: Mission - Stage - Question - Answer - Attempt <- Quiz <- User Mission - UserMission <- User Stage - UserStage <- User Other Models: Mission.rb class Mission < ActiveRecord::Base belongs_to :orientation has_many :stages has_many :user_missions, dependent: :destroy has_many :users, through: :user_missions #SCOPES scope :by_position, -> {order(position: :asc)} def stages_ordered stages.order(:position) end def next_mission self.orientation.missions.find_by_position(self.position.next) end def first_stage next_mission.stages_ordered.first end end Stage.rb: class Stage < ActiveRecord::Base belongs_to :mission has_many :questions, dependent: :destroy has_many :user_stages, dependent: :destroy has_many :users, through: :user_stages accepts_nested_attributes_for :questions, reject_if: :all_blank, allow_destroy: true def next_stage self.mission.stages.find_by_position(self.position.next) end end Question.rb class Question < ActiveRecord::Base belongs_to :stage has_many :answers, dependent: :destroy accepts_nested_attributes_for :answers, :reject_if => lambda { |a| a[:body].blank? }, :allow_destroy => true end Answer.rb: class Answer < ActiveRecord::Base belongs_to :question has_many :attempts, dependent: :destroy end Attempt.rb: class Attempt < ActiveRecord::Base belongs_to :answer belongs_to :quiz end User.rb: class User < ActiveRecord::Base belongs_to :school has_many :activity_logs has_many :user_missions, dependent: :destroy has_many :missions, through: :user_missions has_many :user_stages, dependent: :destroy has_many :stages, through: :user_stages has_many :orientations, through: :school has_many :quizzes, dependent: :destroy has_many :attempts, through: :quizzes def latest_stage_position self.user_missions.last.user_stages.last.stage.position end end UserMission.rb class UserMission < ActiveRecord::Base belongs_to :user belongs_to :mission has_many :user_stages, dependent: :destroy end UserStage.rb class UserStage < ActiveRecord::Base belongs_to :user belongs_to :stage belongs_to :user_mission end

    Read the article

  • ASP.NET MVC in Action: The model in depth

    In this chapter, we’ll explore a model for a system that helps to manage a small conference, like a Code Camp. The model enables the application to provide an interesting service. Without the model, the application provides no value. We place great importance on creating a rich model with which our controllers can work. Presented By: NEC   Ads by Pheedo

    Read the article

  • New security configuration flag in UCM PS3

    - by kyle.hatlestad
    While the recent Patch Set 3 (PS3) release was mostly focused on bug fixes and such, a new configuration flag was added for security. In 10gR3 and prior versions, UCM had a component called Collaboration Manager which allowed for project folders to be created and groups of users assigned as members to collaborate on documents. With this component came access control lists (ACL) for content and folders. Users could assign specific security rights on each and every document and folder within a project. And it was possible to enable these ACL's without having the Collaboration Manager component enabled. But it took some special instructions (see technote# 603148.1) and added some extraneous pieces still related to Collaboration Manager. When 11g came out, Collaboration Manager was no longer available. But the configuration settings to turn on ACLs were still there. Well, in PS3 they've been cleaned up a bit and a new configuration flag has been added to simply turn on the ACL fields and none of the other collaboration bits. To enable ACLs: UseEntitySecurity=true Along with this configuration flag to turn ACLs on, you also need to define which Security Groups will honor the ACL fields. If an ACL is applied to a content item with a Security Group outside this list, it will be ignored. SpecialAuthGroups=HumanResources,Legal,Marketing Save the settings and restart the instance. Upon restart, two new metadata fields will be created: xClbraUserList, xClbraAliasList. If you are using OracleTextSearch as the search indexer, be sure to run a Fast Rebuild on the collection. On the Check In, Search, and Update pages, values are added by simply typing in the value and getting a type-ahead list of possible values. Select the value, click Add and then set the level of access (Read, Write, Delete, or Admin). If all of the fields are blank, then it simply falls back to just Security Group and Account access. As for how they are stored in the metadata fields, each entry starts with it's identifier: ampersand (&) symbol for users, "at" (@) symbol for groups, and colon (:) for roles. Following that is the entity name. And at the end is the level of access in paranthesis. e.g. (RWDA). And each entry is separated by a comma. So if you were populating values through batch loader or an external source, the values would be defined this way. Detailed information on Access Control Lists can be found in the Oracle Fusion Middleware System Administrator's Guide for Oracle Content Server.

    Read the article

  • How to minimize a window using mouse in PCManFM?

    - by Mithun P
    How can I minimize a window using mouse in PCManFM? I'm using Elementary Desktop Environment in Ubuntu 12.04 Update I tried to bring the minimize button back by opening gconf-editor and change the value of /apps/metacity/general/button_layout from close:maximize to close,minimize:maximize. Then I logged out and back in, but that change was simply ignored. Update Again Screenshot And the System settings

    Read the article

  • Overwrite previous output in Bash instead of appending it

    - by NES
    For a bash timer i use this code: #!/bin/bash sek=60 echo "60 Seconds Wait!" echo -n "One Moment please " while [ $sek -ge 1 ] do echo -n "$sek " sleep 1 sek=$[$sek-1] done echo echo "ready!" That gives me something like that One Moment please: 60 59 58 57 56 55 ... Is there a possibility to replace the last value of second by the most recent so that the output doesn't generate a large trail but the seconds countdown like a real time at one position? (Hope you understand what i mean :))

    Read the article

  • Test interface implementation

    - by Michael
    I have a interface in our code base that I would like to be able to mock out for unit testing. I am writing a test implementation to allow the individual tests to be able to override the specific methods they are concerned with rather than implementing every method. I've run into a quandary over how the test implementation should behave if the test fails to override a method used by the method under test. Should I return a "non-value" (0, null) in the test implementation or throw a UnsupportedOperationException to explicitly fail the test?

    Read the article

  • Oracle Database 12 c New Partition Maintenance Features by Gwen Lazenby

    - by hamsun
    One of my favourite new features in Oracle Database 12c is the ability to perform partition maintenance operations on multiple partitions. This means we can now add, drop, truncate and merge multiple partitions in one operation, and can split a single partition into more than two partitions also in just one command. This would certainly have made my life slightly easier had it been available when I administered a data warehouse at Oracle 9i. To demonstrate this new functionality and syntax, I am going to create two tables, ORDERS and ORDERS_ITEMS which have a parent-child relationship. ORDERS is to be partitioned using range partitioning on the ORDER_DATE column, and ORDER_ITEMS is going to partitioned using reference partitioning and its foreign key relationship with the ORDERS table. This form of partitioning was a new feature in 11g and means that any partition maintenance operations performed on the ORDERS table will also take place on the ORDER_ITEMS table as well. First create the ORDERS table - SQL CREATE TABLE orders ( order_id NUMBER(12), order_date TIMESTAMP, order_mode VARCHAR2(8), customer_id NUMBER(6), order_status NUMBER(2), order_total NUMBER(8,2), sales_rep_id NUMBER(6), promotion_id NUMBER(6), CONSTRAINT orders_pk PRIMARY KEY(order_id) ) PARTITION BY RANGE(order_date) (PARTITION Q1_2007 VALUES LESS THAN (TO_DATE('01-APR-2007','DD-MON-YYYY')), PARTITION Q2_2007 VALUES LESS THAN (TO_DATE('01-JUL-2007','DD-MON-YYYY')), PARTITION Q3_2007 VALUES LESS THAN (TO_DATE('01-OCT-2007','DD-MON-YYYY')), PARTITION Q4_2007 VALUES LESS THAN (TO_DATE('01-JAN-2008','DD-MON-YYYY')) ); Table created. Now the ORDER_ITEMS table SQL CREATE TABLE order_items ( order_id NUMBER(12) NOT NULL, line_item_id NUMBER(3) NOT NULL, product_id NUMBER(6) NOT NULL, unit_price NUMBER(8,2), quantity NUMBER(8), CONSTRAINT order_items_fk FOREIGN KEY(order_id) REFERENCES orders(order_id) on delete cascade) PARTITION BY REFERENCE(order_items_fk) tablespace example; Table created. Now look at DBA_TAB_PARTITIONS to get details of what partitions we have in the two tables – SQL select table_name,partition_name, partition_position position, high_value from dba_tab_partitions where table_owner='SH' and table_name like 'ORDER_%' order by partition_position, table_name; TABLE_NAME PARTITION_NAME POSITION HIGH_VALUE -------------- --------------- -------- ------------------------- ORDERS Q1_2007 1 TIMESTAMP' 2007-04-01 00:00:00' ORDER_ITEMS Q1_2007 1 ORDERS Q2_2007 2 TIMESTAMP' 2007-07-01 00:00:00' ORDER_ITEMS Q2_2007 2 ORDERS Q3_2007 3 TIMESTAMP' 2007-10-01 00:00:00' ORDER_ITEMS Q3_2007 3 ORDERS Q4_2007 4 TIMESTAMP' 2008-01-01 00:00:00' ORDER_ITEMS Q4_2007 4 Just as an aside it is also now possible in 12c to use interval partitioning on reference partitioned tables. In 11g it was not possible to combine these two new partitioning features. For our first example of the new 12cfunctionality, let us add all the partitions necessary for 2008 to the tables using one command. Notice that the partition specification part of the add command is identical in format to the partition specification part of the create command as shown above - SQL alter table orders add PARTITION Q1_2008 VALUES LESS THAN (TO_DATE('01-APR-2008','DD-MON-YYYY')), PARTITION Q2_2008 VALUES LESS THAN (TO_DATE('01-JUL-2008','DD-MON-YYYY')), PARTITION Q3_2008 VALUES LESS THAN (TO_DATE('01-OCT-2008','DD-MON-YYYY')), PARTITION Q4_2008 VALUES LESS THAN (TO_DATE('01-JAN-2009','DD-MON-YYYY')); Table altered. Now look at DBA_TAB_PARTITIONS and we can see that the 4 new partitions have been added to both tables – SQL select table_name,partition_name, partition_position position, high_value from dba_tab_partitions where table_owner='SH' and table_name like 'ORDER_%' order by partition_position, table_name; TABLE_NAME PARTITION_NAME POSITION HIGH_VALUE -------------- --------------- -------- ------------------------- ORDERS Q1_2007 1 TIMESTAMP' 2007-04-01 00:00:00' ORDER_ITEMS Q1_2007 1 ORDERS Q2_2007 2 TIMESTAMP' 2007-07-01 00:00:00' ORDER_ITEMS Q2_2007 2 ORDERS Q3_2007 3 TIMESTAMP' 2007-10-01 00:00:00' ORDER_ITEMS Q3_2007 3 ORDERS Q4_2007 4 TIMESTAMP' 2008-01-01 00:00:00' ORDER_ITEMS Q4_2007 4 ORDERS Q1_2008 5 TIMESTAMP' 2008-04-01 00:00:00' ORDER_ITEMS Q1_2008 5 ORDERS Q2_2008 6 TIMESTAMP' 2008-07-01 00:00:00' ORDER_ITEM Q2_2008 6 ORDERS Q3_2008 7 TIMESTAMP' 2008-10-01 00:00:00' ORDER_ITEMS Q3_2008 7 ORDERS Q4_2008 8 TIMESTAMP' 2009-01-01 00:00:00' ORDER_ITEMS Q4_2008 8 Next, we can drop or truncate multiple partitions by giving a comma separated list in the alter table command. Note the use of the plural ‘partitions’ in the command as opposed to the singular ‘partition’ prior to 12c– SQL alter table orders drop partitions Q3_2008,Q2_2008,Q1_2008; Table altered. Now look at DBA_TAB_PARTITIONS and we can see that the 3 partitions have been dropped in both the two tables – TABLE_NAME PARTITION_NAME POSITION HIGH_VALUE -------------- --------------- -------- ------------------------- ORDERS Q1_2007 1 TIMESTAMP' 2007-04-01 00:00:00' ORDER_ITEMS Q1_2007 1 ORDERS Q2_2007 2 TIMESTAMP' 2007-07-01 00:00:00' ORDER_ITEMS Q2_2007 2 ORDERS Q3_2007 3 TIMESTAMP' 2007-10-01 00:00:00' ORDER_ITEMS Q3_2007 3 ORDERS Q4_2007 4 TIMESTAMP' 2008-01-01 00:00:00' ORDER_ITEMS Q4_2007 4 ORDERS Q4_2008 5 TIMESTAMP' 2009-01-01 00:00:00' ORDER_ITEMS Q4_2008 5 Now let us merge all the 2007 partitions together to form one single partition – SQL alter table orders merge partitions Q1_2005, Q2_2005, Q3_2005, Q4_2005 into partition Y_2007; Table altered. TABLE_NAME PARTITION_NAME POSITION HIGH_VALUE -------------- --------------- -------- ------------------------- ORDERS Y_2007 1 TIMESTAMP' 2008-01-01 00:00:00' ORDER_ITEMS Y_2007 1 ORDERS Q4_2008 2 TIMESTAMP' 2009-01-01 00:00:00' ORDER_ITEMS Q4_2008 2 Splitting partitions is a slightly more involved. In the case of range partitioning one of the new partitions must have no high value defined, and in list partitioning one of the new partitions must have no list of values defined. I call these partitions the ‘everything else’ partitions, and will contain any rows contained in the original partition that are not contained in the any of the other new partitions. For example, let us split the Y_2007 partition back into 4 quarterly partitions – SQL alter table orders split partition Y_2007 into (PARTITION Q1_2007 VALUES LESS THAN (TO_DATE('01-APR-2007','DD-MON-YYYY')), PARTITION Q2_2007 VALUES LESS THAN (TO_DATE('01-JUL-2007','DD-MON-YYYY')), PARTITION Q3_2007 VALUES LESS THAN (TO_DATE('01-OCT-2007','DD-MON-YYYY')), PARTITION Q4_2007); Now look at DBA_TAB_PARTITIONS to get details of the new partitions – TABLE_NAME PARTITION_NAME POSITION HIGH_VALUE -------------- --------------- -------- ------------------------- ORDERS Q1_2007 1 TIMESTAMP' 2007-04-01 00:00:00' ORDER_ITEMS Q1_2007 1 ORDERS Q2_2007 2 TIMESTAMP' 2007-07-01 00:00:00' ORDER_ITEMS Q2_2007 2 ORDERS Q3_2007 3 TIMESTAMP' 2007-10-01 00:00:00' ORDER_ITEMS Q3_2007 3 ORDERS Q4_2007 4 TIMESTAMP' 2008-01-01 00:00:00' ORDER_ITEMS Q4_2007 4 ORDERS Q4_2008 5 TIMESTAMP' 2009-01-01 00:00:00' ORDER_ITEMS Q4_2008 5 Partition Q4_2007 has a high value equal to the high value of the original Y_2007 partition, and so has inherited its upper boundary from the partition that was split. As for a list partitioning example let look at the following another table, SALES_PAR_LIST, which has 2 partitions, Americas and Europe and a partitioning key of country_name. SQL select table_name,partition_name, high_value from dba_tab_partitions where table_owner='SH' and table_name = 'SALES_PAR_LIST'; TABLE_NAME PARTITION_NAME HIGH_VALUE -------------- --------------- ----------------------------- SALES_PAR_LIST AMERICAS 'Argentina', 'Canada', 'Peru', 'USA', 'Honduras', 'Brazil', 'Nicaragua' SALES_PAR_LIST EUROPE 'France', 'Spain', 'Ireland', 'Germany', 'Belgium', 'Portugal', 'Denmark' Now split the Americas partition into 3 partitions – SQL alter table sales_par_list split partition americas into (partition south_america values ('Argentina','Peru','Brazil'), partition north_america values('Canada','USA'), partition central_america); Table altered. Note that no list of values was given for the ‘Central America’ partition. However it should have inherited any values in the original ‘Americas’ partition that were not assigned to either the ‘North America’ or ‘South America’ partitions. We can confirm this by looking at the DBA_TAB_PARTITIONS view. SQL select table_name,partition_name, high_value from dba_tab_partitions where table_owner='SH' and table_name = 'SALES_PAR_LIST'; TABLE_NAME PARTITION_NAME HIGH_VALUE --------------- --------------- -------------------------------- SALES_PAR_LIST SOUTH_AMERICA 'Argentina', 'Peru', 'Brazil' SALES_PAR_LIST NORTH_AMERICA 'Canada', 'USA' SALES_PAR_LIST CENTRAL_AMERICA 'Honduras', 'Nicaragua' SALES_PAR_LIST EUROPE 'France', 'Spain', 'Ireland', 'Germany', 'Belgium', 'Portugal', 'Denmark' In conclusion, I hope that DBA’s whose work involves maintaining partitions will find the operations a bit more straight forward to carry out once they have upgraded to Oracle Database 12c. Gwen Lazenby is a Principal Training Consultant at Oracle. She is part of Oracle University's Core Technology delivery team based in the UK, teaching Database Administration and Linux courses. Her specialist topics include using Oracle Partitioning and Parallelism in Data Warehouse environments, as well as Oracle Spatial and RMAN.

    Read the article

  • Turn off keyboard back-light Sony (VAIO SVF1521DCXW)

    - by KasiyA
    I have a Sony laptop and I want to turn keyboard back-light off. It doesn't have a shortcut function key for doing this on the keyboard . I can turn off it with VAIO Control Center in Windows but I don't know how can I turn it off in Ubuntu 14.04. There isn't available to me: /sys/devices/platform/sony-laptop/kbd_backlight doesn't exist on my machine. I have this folder /sys/devices/platform/sony-laptop/ and there is three folder one power folder and two shortcut-ed folder driver , subsystem and five file contains battery_care_health , battery_care_limiter , modalias , touchpad and event This is the output of running sudo modinfo sony-laptop: filename: /lib/modules/3.13.0-34-generic/kernel/drivers/platform/x86/sony-laptop.ko version: 0.6 license: GPL description: Sony laptop extras driver (SPIC and SNC ACPI device) author: Stelian Pop, Mattia Dongili srcversion: 5C6E050349475558A231C59 alias: acpi*:SNY6001:* alias: acpi*:SNY5001:* depends: intree: Y vermagic: 3.13.0-34-generic SMP mod_unload modversions signer: Magrathea: Glacier signing key sig_key: 50:0B:C5:C8:7D:4B:11:5C:F3:C1:50:4F:7A:92:E2:33:C6:14:3D:58 sig_hashalgo: sha512 parm: debug:set this to 1 (and RTFM) if you want to help the development of this driver (int) parm: no_spic:set this if you don't want to enable the SPIC device (int) parm: compat:set this if you want to enable backward compatibility mode (int) parm: mask:set this to the mask of event you want to enable (see doc) (ulong) parm: camera:set this to 1 to enable Motion Eye camera controls (only use it if you have a C1VE or C1VN model) (int) parm: minor:minor number of the misc device for the SPIC compatibility code, default is -1 (automatic) (int) parm: kbd_backlight:set this to 0 to disable keyboard backlight, 1 to enable it (default: no change from current value) (int) parm: kbd_backlight_timeout:meaningful values vary from 0 to 3 and their meaning depends on the model (default: no change from current value) (int) With the suggested command: sudo modprobe -r sony_laptop sudo modprobe -v sony_laptop kbd_backlight=0 Output was: insmod /lib/modules/3.13.0-34-generic/kernel/drivers/platform/x86/sony-laptop.ko kbd_backlight=0 It doesn't seem to affect the keyboard backlight. And also trying this command: sudo modprobe -v sony_laptop kbd_backlight_timeout=3 kbd_backlight=0 and doesn't seem to effect the keyboard backlight I also test it after restart laptop, And I didn't see any effect too. Important : By default, keyboard backlight is off; when I press a key it turns on and after 15 seconds it turns off again. It's the same result on battery and AC power I followed also http://ubuntuforums.org/showthread.php?t=2139597 and Keyboard backlighting not working on a Vaio VPCSB11FX but didn't work so.

    Read the article

  • Oracle Solaris 11 Best Platform for Oracle Database 12c!

    - by uwes
    Sharpen your knowledge about Oracle Solaris 11 and Oracle Database 12c. Oracle Solaris Product Management has developed a host of content supporting the value of Oracle Database 12c on Oracle Solaris and Oracle Solaris on SPARC. OTN-Web Pages Oracle Solaris 11 and SPARC Oracle Solaris 11 Best Platform for Oracle Database Collateral Updated datasheet: Oracle Solaris Optimizations for the Oracle Stack Article: How Oracle Solaris Makes Oracle Database Fast Screen Cast: Analyzing Oracle Database I/O Outliers Blog: Oracle Solaris Blog OTN Garage Blog

    Read the article

  • Tile-based 2D collision detection problems

    - by Vee
    I'm trying to follow this tutorial http://www.tonypa.pri.ee/tbw/tut05.html to implement real-time collisions in a tile-based world. I find the center coordinates of my entities thanks to these properties: public float CenterX { get { return X + Width / 2f; } set { X = value - Width / 2f; } } public float CenterY { get { return Y + Height / 2f; } set { Y = value - Height / 2f; } } Then in my update method, in the player class, which is called every frame, I have this code: public override void Update() { base.Update(); int downY = (int)Math.Floor((CenterY + Height / 2f - 1) / 16f); int upY = (int)Math.Floor((CenterY - Height / 2f) / 16f); int leftX = (int)Math.Floor((CenterX + Speed * NextX - Width / 2f) / 16f); int rightX = (int)Math.Floor((CenterX + Speed * NextX + Width / 2f - 1) / 16f); bool upleft = Game.CurrentMap[leftX, upY] != 1; bool downleft = Game.CurrentMap[leftX, downY] != 1; bool upright = Game.CurrentMap[rightX, upY] != 1; bool downright = Game.CurrentMap[rightX, downY] != 1; if(NextX == 1) { if (upright && downright) CenterX += Speed; else CenterX = (Game.GetCellX(CenterX) + 1)*16 - Width / 2f; } } downY, upY, leftX and rightX should respectively find the lowest Y position, the highest Y position, the leftmost X position and the rightmost X position. I add + Speed * NextX because in the tutorial the getMyCorners function is called with these parameters: getMyCorners (ob.x+ob.speed*dirx, ob.y, ob); The GetCellX and GetCellY methods: public int GetCellX(float mX) { return (int)Math.Floor(mX / SGame.Camera.TileSize); } public int GetCellY(float mY) { return (int)Math.Floor(mY / SGame.Camera.TileSize); } The problem is that the player "flickers" while hitting a wall, and the corner detection doesn't even work correctly since it can overlap walls that only hit one of the corners. I do not understand what is wrong. In the tutorial the ob.x and ob.y fields should be the same as my CenterX and CenterY properties, and the ob.width and ob.height should be the same as Width / 2f and Height / 2f. However it still doesn't work. Thanks for your help.

    Read the article

  • Allocating Entities within an Entity System

    - by miguel.martin
    I'm quite unsure how I should allocate/resemble my entities within my entity system. I have various options, but most of them seem to have cons associated with them. In all cases entities are resembled by an ID (integer), and possibly has a wrapper class associated with it. This wrapper class has methods to add/remove components to/from the entity. Before I mention the options, here is the basic structure of my entity system: Entity An object that describes an object within the game Component Used to store data for the entity System Contains entities with specific components Used to update entities with specific components World Contains entities and systems for the entity system Can create/destroy entites and have systems added/removed from/to it Here are my options, that I have thought of: Option 1: Do not store the Entity wrapper classes, and just store the next ID/deleted IDs. In other words, entities will be returned by value, like so: Entity entity = world.createEntity(); This is much like entityx, except I see some flaws in this design. Cons There can be duplicate entity wrapper classes (as the copy-ctor has to be implemented, and systems need to contain entities) If an Entity is destroyed, the duplicate entity wrapper classes will not have an updated value Option 2: Store the entity wrapper classes within an object pool. i.e. Entities will be return by pointer/reference, like so: Entity& e = world.createEntity(); Cons If there is duplicate entities, then when an entity is destroyed, the same entity object may be re-used to allocate another entity. Option 3: Use raw IDs, and forget about the wrapper entity classes. The downfall to this, I think, is the syntax that will be required for it. I'm thinking about doing thisas it seems the most simple & easy to implement it. I'm quite unsure about it, because of the syntax. i.e. To add a component with this design, it would look like: Entity e = world.createEntity(); world.addComponent<Position>(e, 0, 3); As apposed to this: Entity e = world.createEntity(); e.addComponent<Position>(0, 3); Cons Syntax Duplicate IDs

    Read the article

  • BizTalk 360 Alarms, How do you configure yours?

    - by Michael Stephenson
    Originally posted on: http://geekswithblogs.net/michaelstephenson/archive/2013/06/18/153157.aspxIve recently written a guest post for BizTalk 360 on their blog about how customers may configure BizTalk 360 Alarms to optimize getting the right information to the right type of support people.This is my thoughts on how users of BTS 360 can get the best value out of BizTalk 360 alarmshttp://blogs.biztalk360.com/what-are-the-different-types-of-alarms-alerts-you-should-configure-in-biztalk360/

    Read the article

  • Questions about Microsoft's new Cloud certification

    - by makerofthings7
    I'm evaluating taking the cloud certification exams from Microsoft, and have a few questions How highly do you think employers will value this exam? What job roles would require this cert? In your personal experience, how would this certification be weighed against other factors such as real world experience, other certifications, and having a Bachelors degree? If you mention that other certifications are more valued, which ones are they?

    Read the article

  • Setup Guide for updating local system and the repository with the incremental Solaris 11.1 SRU

    - by Gurubalan
    This guide covers the steps to implement the following setup. I. Updating the local system from Solaris 11.1 to Solaris 11.1 SRU 16.5II. Setting up local system as an IPS Repository Server (HTTP interface)III. Updating the local repository with the incremental Solaris 11.1 SRU 16.5I. Updating the local system from Solaris 11.1 to Solaris 11.1 SRU 16.5We assume that the local system is currently installed with Solaris 11.1 GA and the system doesn't have internet connectivity.What I have:1. Two parts of full repo iso files downloaded from http://www.oracle.com/technetwork/server-storage/solaris11/downloads/index.html. Both files are concatenated to a single file using the following command. $ cat sol-11_1-repo-full.iso-a sol-11_1-repo-full.iso-b > sol-11_1-repo-full.iso I suggest to verify the downloaded file against its md5checksum value [http://download.oracle.com/otn/solaris/11_1/md5sum.txt] using the following command digest -a md5 <file-name>  // the output of this command should match the original checksum value for that file.2. Incremental repo sol-11_1_16_5_0-incr-repo.iso downloaded from MOS [Patch 18269379: ORACLE SOLARIS 11.1.16.5.0 REPO ISO IMAGE (SPARC/X86 (64-BIT)]. You can get the checksum value of incremental repo iso by clicking the check box "show digest details" when you download the file.3. The local system IP is 192.168.10.10 & port 81 is reserved for repo serverPlease note that this repo file (either full or incremental) is common for both SPARC and X86(64BIT).Steps to update the local system: 1. #mounting s11.1 full repo iso to mnt        $ mount -F hsfs /soft/sol-11_1-repo-full.iso /mnt 2. Setting the pkg publisher to full repo source         $ pkg set-publisher -g file:///mnt/repo solaris 3. Perform the update of the packages.        $ pkg updateII. Setting up local system (Oracle Solaris 11.1) as an IPS Repository Server(HTTP interface):Please note that we have already mounted the full repo iso at /mnt    1. # copying /mnt permanently to the disk location at /s11.1        #zfs create -o atime=off -o mountpoint=/s11.1 rpool/s11.1        #rsync -aP /mnt/* /s11.1     2. #unmounting mnt         #umount /mnt3. To allow clients to access the local repository via HTTP, enable the application/pkg/server Service Management Facility (SMF) service.        svccfg -s application/pkg/server setprop pkg/inst_root=<data_source>/repo        eg: $svccfg -s application/pkg/server setprop pkg/inst_root=/s11.1/repo4. Setting port# to 81      svccfg -s application/pkg/server setprop pkg/port=<port_number>      eg: svccfg -s application/pkg/server setprop pkg/port="81"5a. Enable the pkg/server service (if the service is disabled)     $svcs pkg/server     STATE          STIME    FMRI     disabled        19:55:03 svc:/application/pkg/server:default      $svcadm enable pkg/server5b. Refresh/Restart the service, if it is already online       $svcadm refresh application/pkg/server       $svcadm restart application/pkg/server6. Setting pkg publisher on repo server and repo clients:      pkg set-publisher -G '*' -g http://<ip>:<port> solaris      eg: $pkg set-publisher -G '*' -g 'http://192.168.10.10:81' solaris7. Verify the Solaris 11.1 version from the repository         $pkgrepo list -s http://192.168.10.10:81 | grep entire         solaris   entire     0.5.11,5.11-0.175.1.0.0.24.2:20120919T190135Z You will have multiple row entries if the repository is setup with incremental SRUs.III. Updating the local repository with the incremental Solaris 11.1 SRU 16.51. #mounting s11.1 incremental SRU repo iso to mnt        $ mount -F hsfs <full_path_to>/sol-11_1_sruN_bldnum_respinnum-incr-repo.iso  /mnt        $ mount -F hsfs /soft/sol-11_1_16_5_0-incr-repo.iso /mnt2. Updating the local repository        $pkgrecv -s  /mnt/repo -d /s11.1/repo '*'3. Building a Search Index    $pkgrepo -s /s11.1/repo refresh     Initiating repository refresh.4. Refresh/Restart the service       $svcadm refresh svc:/application/pkg/server       $svcadm restart svc:/application/pkg/server5. Verify the repo has the incremental SRU as well.       # pkgrepo list -s http://192.168.10.10:81 | grep entire        solaris   entire      0.5.11,5.11-0.175.1.16.0.5.0:20140218T165248Z       solaris   entire      0.5.11,5.11-0.175.1.0.0.24.2:20120919T190135Z

    Read the article

  • SOA Management in 3 minutes - Video explainer

    - by J Swaroop
    Today’s CIOs and IT executives face challenges that take valuable time away from more strategic business objectives. They have to keep their systems running 24/7, manage increasingly complex applications, and more as part of their SOA environment. Watch this quick 3 minute video explainer to learn how Oracle EM Management Pack Plus for SOA is engineered to deliver value right out of the box with a fully centralized management console - with a rich set of service and system level dashboards, administrators can view service levels for key business processes and SOA infrastructure components from a central location. Watch the 3 minute video explainer

    Read the article

  • What's the best Open Source code you've ever seen?

    - by Andrew Theken
    Part of the value of Open Source is to provide great example code to people getting started with a new platform or language. What's the best Open Source code you've encountered, and why do you like your choice? Any language will do, but I'm particularly interested in the best examples of Objective-C you can point out. Obviously this is an open-ended question, so I'll leave the question open for a while and see what kinds of answers we get. Thanks!

    Read the article

  • How to get current connection settings

    - by Peter Larsson
    SELECT name AS Setting,         CASE             WHEN @@OPTIONS & number = number THEN 'ON'             ELSE 'OFF'         END AS Value FROM    master..spt_values WHERE   type= 'SOP'         AND number > 0

    Read the article

  • The Social Business Thought Leaders - Ray Wang

    - by kellsey.ruppel
    It seems both consumers and businesses are at the peak of the social hype. Overwhelmed by social media channels, platforms, and processes both in their private and professional life, many early adopters are starting to feel the social fatigue. Mirroring what happened with email and web sites during the late 1990's - early 2000's, more and more managers are looking to move from ubiquitous social media tactics to the most appropriate business use case and processes. This step becomes even more important considering the year over year contraction in IT budgets and the consequent need to maximize return on every dollar spent in new technologies. Ray Wang, CEO and Principal Analyst at Constellation Research, suggests engagement through collaborative technologies both as a conceptual model and a transformational tool for enterprises to reap business value. Without participation - the reasoning goes - there is no value and good technology alone is not enough to guarantee employee and customer adoption. Enterprise gamification is a new lever to succeed with Social Business by directing a critical mass of participation towards desired outcomes. What kind of outcomes? A recent study from Constellation Research (see 2012 Q1 Gamification Early Adopters Best Practices) highlights how Marketing, Customer Service and HR are leading the pack with gamification in processes such as: Sustaining long term customer loyalty (76.4%) Improving response in campaign to lead (74.5%) Right channeling incidents for resolution in social media (67.3%) Growing the number service and support incidents resolved by the community (63.6%) Improving employee referral rates and effective recruiting (43.6%) Driving on-boarding success with new hires (20%) More than simply adding badges, points and leaderboards to existing processes, enterprise gamification should be holistically embedded into employee and customer experience to stimulate specific behaviors. According to Ray Wang this can be done at three core levels: Measurable actions. The behaviors we want to facilitate consist of granular actions (i.e likes, comments, posts, recommendations, etc) and more complex actions (i.e projects, initiatives, programmes) attributed to individuals, groups and/or external actors  Reputation. The reputation an individual has earned through his actions is a key factor in building motivation among others and it is determined by its identity, social standing status and competitiveness Incentives or the intrinsic and extrinsic rewards that motivate behaviors and drive actions Listen to Ray Wang's video-interview to learn more about the dynamics that are shaping the future of collaboration and how gamification can help organizations attain new levels of engagement.

    Read the article

  • Shadow Mapping and Transparent Quads

    - by CiscoIPPhone
    Shadow mapping uses the depth buffer to calculate where shadows should be drawn. My problem is that I'd like some semi transparent textured quads to cast shadows - for example billboarded trees. As the depth value will be set across all of the quad and not just the visible parts it will cast a quad shadow, which is not what I want. How can I make my transparent quads cast correct shadows using shadow mapping?

    Read the article

  • How to determine character's foot contact point on a uniform triangle mesh terrain?

    - by xenon
    For a terrain that is modelled by a heightmap with a uniform triangle mesh, what are some techniques I could use to determine the contact point of the foot of a character standing on the terrain? Since the terrain's Y values are altered by the heightmap, they won't be flat any more. As the character moves on the terrain, it has to know at which values of Y-value its foot should be. Conceptually, what are some methods and techniques to determine the contact point of the character's foot standing on the terrain?

    Read the article

< Previous Page | 661 662 663 664 665 666 667 668 669 670 671 672  | Next Page >